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  • Looking for a free SMTP server program

    - by Richard
    Hello all, I am looking for a free SMTP server. I am currently using Free SMTP Server http://www.softstack.com/freesmtp.html This software works great other than the fact that it can only send 10 messages a day. This is a bit of a problem seeing that the software I am writing needs to send a message every half hour. Anyone knows of a good piece of software that does the same thing, but does not limit the amount of messages that can be sent in a day? I am using Windows XP, so software must be Windows friendly

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  • Windows shows incorrect free space on Raid 10 volume

    - by Adenverd
    I have 4 1TB hard drives in RAID 1+0 configuration. Theoretically, I should have ~2TB of available space. Windows says the drive has a total size of 1.81 TB, which I'm fine with. As far as files on the volume go, I used WinDirStat to determine that I have 552.8GB of files on the volume. This means that I should have somewhere around 1.3TB minimum of free space. Yet Windows shows the drive as only having 492GB of free space. Are there hidden files somewhere that I can't see (I have show hidden files/folders turned on)? Does Windows not recognize that old files have been deleted? Is there any way to correct this problem?

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  • Hosting ESXI (free edition) [closed]

    - by Peter Adss
    We currently have one physical server running the free version of VMWare ESXi that virtualizes a Win SBS 2003 server and a Citrix server. We need to collocate the server and are investigating our options. Are there places that will host our virtual servers and save us the expense of shipping the physical server out for collocation. In my mind we'd copy the Vms to disk and ship them out. Does the fact that we're using the free version of ESXi create a barrier to this idea? Thanks for the help, I realize this is a stupid question.

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  • Code Golf: Code 39 Bar Code

    - by gwell
    The challenge The shortest code by character count to draw an ASCII representation of a Code 39 bar code. Wikipedia article about Code 39: http://en.wikipedia.org/wiki/Code_39 Input The input will be a string of legal characters for Code 39 bar codes. This means 43 characters are valid: 0-9 A-Z (space) and -.$/+%. The * character will not appear in the input as it is used as the start and stop characters. Output Each character encoded in Code 39 bar codes have nine elements, five bars and four spaces. Bars will be represented with # characters, and spaces will be represented with the space character. Three of the nine elements will be wide. The narrow elements will be one character wide, and the wide elements will be three characters wide. A inter-character space of a single space should be added between each character pattern. The pattern should be repeated so that the height of the bar code is eight characters high. The start/stop character * (bWbwBwBwb) would be represented like this: # # ### ### # # # ### ### # # # ### ### # # # ### ### # # # ### ### # # # ### ### # # # ### ### # # # ### ### # ^ ^ ^^ ^ ^ ^ ^^^ | | || | | | ||| narrow bar -+ | || | | | ||| wide space ---+ || | | | ||| narrow bar -----+| | | | ||| narrow space ------+ | | | ||| wide bar --------+ | | ||| narrow space ----------+ | ||| wide bar ------------+ ||| narrow space --------------+|| narrow bar ---------------+| inter-character space ----------------+ The start and stop character * will need to be output at the start and end of the bar code. No quiet space will need to be included before or after the bar code. No check digit will need to be calculated. Full ASCII Code39 encoding is not required, just the standard 43 characters. No text needs to be printed below the ASCII bar code representation to identify the output contents. The character # can be replaced with another character of higher density if wanted. Using the full block character U+2588, would allow the bar code to actually scan when printed. Test cases Input: ABC Output: # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # Input: 1/3 Output: # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # Input: - $ (minus space dollar) Output: # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # Code count includes input/output (full program).

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  • Code Golf: Collatz Conjecture

    - by Earlz
    Inspired by http://xkcd.com/710/ here is a code golf for it. The Challenge Given a positive integer greater than 0, print out the hailstone sequence for that number. The Hailstone Sequence See Wikipedia for more detail.. If the number is even, divide it by two. If the number is odd, triple it and add one. Repeat this with the number produced until it reaches 1. (if it continues after 1, it will go in an infinite loop of 1 -> 4 -> 2 -> 1...) Sometimes code is the best way to explain, so here is some from Wikipedia function collatz(n) show n if n > 1 if n is odd call collatz(3n + 1) else call collatz(n / 2) This code works, but I am adding on an extra challenge. The program must not be vulnerable to stack overflows. So it must either use iteration or tail recursion. Also, bonus points for if it can calculate big numbers and the language does not already have it implemented. (or if you reimplement big number support using fixed-length integers) Test case Number: 21 Results: 21 -> 64 -> 32 -> 16 -> 8 -> 4 -> 2 -> 1 Number: 3 Results: 3 -> 10 -> 5 -> 16 -> 8 -> 4 -> 2 -> 1 Also, the code golf must include full user input and output.

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  • Code Golf: 1x1 black pixel

    - by Joey Adams
    Recently, I used my favorite image editor to make a 1x1 black pixel (which can come in handy when you want to draw solid boxes in HTML cheaply). Even though I made it a monochrome PNG, it came out to be 120 bytes! I mean, that's kind of steep. 120 bytes. For one pixel. I then converted it to a GIF, which dropped the size down to 43 bytes. Much better, but still... Challenge The shortest image file or program that is or generates a 1x1 black pixel. A submission may be: An image file that represents a 1x1 black pixel. The format chosen must be able to represent larger images than 1x1, and cannot be ad-hoc (that is, it can't be an image format you just made up for code golf). Image files will be ranked by byte count. A program that generates such an image file. Programs will be ranked by character count, as usual in code golf. As long as an answer falls into one of these two categories, anything is fair game.

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  • Code Golf: Leibniz formula for Pi

    - by Greg Beech
    I recently posted one of my favourite interview whiteboard coding questions in "What's your more controversial programming opinion", which is to write a function that computes Pi using the Leibniz formula. It can be approached in a number of different ways, and the exit condition takes a bit of thought, so I thought it might make an interesting code golf question. Shortest code wins! Given that Pi can be estimated using the function 4 * (1 - 1/3 + 1/5 - 1/7 + ...) with more terms giving greater accuracy, write a function that calculates Pi to within 0.00001. Edit: 3 Jan 2008 As suggested in the comments I changed the exit condition to be within 0.00001 as that's what I really meant (an accuracy 5 decimal places is much harder due to rounding and so I wouldn't want to ask that in an interview, whereas within 0.00001 is an easier to understand and implement exit condition). Also, to answer the comments, I guess my intention was that the solution should compute the number of iterations, or check when it had done enough, but there's nothing to prevent you from pre-computing the number of iterations and using that number. I really asked the question out of interest to see what people would come up with.

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  • Code Golf - p day

    - by gnibbler
    The Challenge The shortest code by character count to display a representation of a circle of radius R using the *character, followed by an approximation of p. Input is a single number, R. Since most computers seem to have almost 2:1 ratio you should only output lines where y is odd. The approximation of p is given by dividing twice the number of * characters by R². The approximation should be correct to at least 6 significant digits. Leading or trailing zeros are permitted, so for example any of 3, 3.000000, 003 is accepted for the inputs of 2 and 4. Code count includes input/output (i.e., full program). Test Cases Input 2 Output *** *** 3.0 Input 4 Output ***** ******* ******* ***** 3.0 Input 8 Output ******* ************* *************** *************** *************** *************** ************* ******* 3.125 Input 10 Output ********* *************** ***************** ******************* ******************* ******************* ******************* ***************** *************** ********* 3.16

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  • Code Golf - PI day

    - by gnibbler
    The Challenge The shortest code by character count to display a representation of a circle of radius R using the *character. Followed by an approximation of pi Input is a single number, R Since most computers seem to have almost 2:1 ratio you should only output lines where y is odd. The approximation of pi is given by dividing the twice the number of * characters by R squared. The approximation should be correct to at least 6 significant digits. Leading or trailing zeros are permitted, so for example any of 3,3.000000,003 is accepted for the inputs of 2 and 4 Code count includes input/output (i.e full program). Test Cases Input 2 Output *** *** 3.0 Input 4 Output ***** ******* ******* ***** 3.0 Input 8 Output ******* ************* *************** *************** *************** *************** ************* ******* 3.125 Input 10 Output ********* *************** ***************** ******************* ******************* ******************* ******************* ***************** *************** ********* 3.16

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  • Selecting by observation in R table

    - by Stedy
    I was working through the Rosetta Code example of the knapsack problem in R and I came up with four solutions. What is the best way to output only one of the solutions based on the observation number give in the table? > values[values$value==max(values$value),] I II III value weight volume 2067 9 0 11 54500 25 25 2119 6 5 11 54500 25 25 2171 3 10 11 54500 25 25 2223 0 15 11 54500 25 25 My initial idea was to save this output to a new variable, then query the new variable such as: > newvariable <- values[values$value==max(values$value),] > newvariable2 <- newvariable[2,] > newvariable2 I II III value weight volume 2119 6 5 11 54500 25 25 This gives me the desired output but is there a cleaner way to do it?

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  • Code Golf: MSM Random Number Generator

    - by Vivin Paliath
    The challenge The shortest code by character count that will generate (pseudo)random numbers using the Middle-Square Method. The Middle-Square Method of (pseudo)random number generation was first suggested by John Von Neumann in 1946 and is defined as follows: Rn+1 = mid((Rn)2, m) For example: 34562 = 11943936 mid(11943936) = 9439 94392 = 89094721 mid(89094721) = 0947 9472 = 896809 mid(896809) = 9680 96802 = 93702400 mid(93702400) = 7024 Test cases: A seed of 8653 should give the following numbers (first 10): 8744, 4575, 9306, 6016, 1922, 6940, 1636, 6764, 7516, 4902

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  • Rewriting UNIX cal(1)

    - by dharmatech
    Hello, Today I was testing out SRFI 19 and wrote a simple version of the UNIX cal(1) command. Here's a version in R6RS Scheme which runs in Ikarus and Ypsilon. A few example runs. Schemers: How would you write it? Use your favorite implementation. Ruby and Python: I'm guessing that y'all have elegant date and time libraries. I'm sure you can put the Schemers to shame. ;-) Let's see what ya got. I'd also like to see Haskell and golfed versions. Is there a Stack Overflow tag for re-implementations of UNIX commands? :-) Ed

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  • Code Golf - Banner Generation

    - by Claudiu
    When thanking someone, you don't want to just send them an e-mail saying "Thanks!", you want to have something FLASHY: Input: THANKS!! Output: TTT H H AAA N N K K SSS !!! !!! T H H A A NNN K K S !!! !!! T HHH AAA NNN KK SSS !!! !!! T H H A A N N K K S T H H A A N N K K SSS !!! !!! Write a program to generate a banner. You only have to generate upper-case A-Z along with spaces and exclamation points (what is a banner without an exclamation point?). All characters are made up of a 3x5 grid of the same character (so the S is a 3x5 grid made of S). All output should be on one row (so no newlines). Here are all the letters you need: Input: ABCDEFGHIJKL Output: AAA BBB CCC DD EEE FFF GGG H H III JJJ K K L A A B B C D D E F G H H I J K K L AAA BBB C D D EE FF G G HHH I J KK L A A B B C D D E F G G H H I J J K K L A A BBB CCC DD EEE F GGG H H III JJJ K K LLL Input: MNOPQRSTUVWX Output: M M N N OOO PPP QQQ RR SSS TTT U U V V W W X X MMM NNN O O P P Q Q R R S T U U V V W W X M M NNN O O PPP Q Q RR SSS T U U V V WWW X M M N N O O P QQQ R R S T U U V V WWW X M M N N OOO P QQQ R R SSS T UUU V WWW X X Input: YZ! Output: Y Y ZZZ !!! Y Y Z !!! YYY Z !!! Y Z YYY ZZZ !!! The winner is the shortest source code. Source code should read input from stdin, output to stdout. You can assume input will only contain [A-Z! ]. If you insult the user on incorrect input, you get a 10 character discount =P. I was going to require these exact 27 characters, but to make it more interesting, you can choose how you want them to look - whatever makes your code shorter! To prove that your letters do look like normal letters, show the output of the last three runs.

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  • Code Golf: Word Search Solver

    - by Maxim Z.
    Note: This is my first Code Golf challenge/question, so I might not be using the correct format below. I'm not really sure how to tag this particular question, and should this be community wiki? Thanks! This Code Golf challenge is about solving word searches! A word search, as defined by Wikipedia, is: A word search, word find, word seek, word sleuth or mystery word puzzle is a word game that is letters of a word in a grid, that usually has a rectangular or square shape. The objective of this puzzle is to find and mark all the words hidden inside the box. The words may be horizontally, vertically or diagonally. Often a list of the hidden words is provided, but more challenging puzzles may let the player figure them out. Many word search puzzles have a theme to which all the hidden words are related. The word searches for this challenge will all be rectangular grids with a list of words to find provided. The words can be written vertically, horizontally, or diagonally. Input/Output The user inputs their word search and then inputs a word to be found in their grid. These two inputs are passed to the function that you will be writing. It is up to you how you want to declare and handle these objects. Using a strategy described below or one of your own, the function finds the specific word in the search and outputs its starting coordinates (simply row number and column number) and ending coordinates. If you find two occurrences of the word, you must output both's set of coordinates. Example Input: A I Y R J J Y T A S V Q T Z E X B X G R Z P W V T B K U F O E A F L V F J J I A G B A J K R E S U R E P U S C Y R S Y K F B B Q Y T K O I K H E W G N G L W Z F R F H L O R W A R E J A O S F U E H Q V L O A Z B J F B G I F Q X E E A L W A C F W K Z E U U R Z R T N P L D F L M P H D F W H F E C G W Z B J S V O A O Y D L M S T C R B E S J U V T C S O O X P F F R J T L C V W R N W L Q U F I B L T O O S Q V K R O W G N D B C D E J Y E L W X J D F X M Word to find: codegolf Output: row 12, column 8 --> row 5, column 1 Strategies Here are a few strategies you might consider using. It is completely up to you to decide what strategy you want to use; it doesn't have to be in this list. Looking for the first letter of the word; on each occurrence, looking at the eight surrounding letters to see whether the next letter of the word is there. Same as above, except looking for a part of a word that has two of the same letter side-by-side. Counting how often each letter of the alphabet is present in the whole grid, then selecting one of the least-occurring letters from the word you have to find and searching for the letter. On each occurrence of the letter, you look at its eight surrounding letters to see whether the next and previous letters of the word is there.

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  • Code Golf: Tic Tac Toe

    - by Aistina
    Post your shortest code, by character count, to check if a player has won, and if so, which. Assume you have an integer array in a variable b (board), which holds the Tic Tac Toe board, and the moves of the players where: 0 = nothing set 1 = player 1 (X) 2 = player 2 (O) So, given the array b = [ 1, 2, 1, 0, 1, 2, 1, 0, 2 ] would represent the board X|O|X -+-+- |X|O -+-+- X| |O For that situation, your code should output 1 to indicate player 1 has won. If no-one has won you can output 0 or false. My own (Ruby) solution will be up soon. Edit: Sorry, forgot to mark it as community wiki. You can assume the input is well formed and does not have to be error checked. Update: Please post your solution in the form of a function. Most people have done this already, but some haven't, which isn't entirely fair. The board is supplied to your function as the parameter. The result should be returned by the function. The function can have a name of your choosing.

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  • Why do people still use Vi and Emacs?

    - by mawg
    This is not a subjective question. I am genuinely looking for techinccal reasons to do so. I will risk offending some folks (not intended as an offence – maybe as a goad) by saying that I have been coding for 30+ years and used to be religously attched to each of them, but as soone as I saw editor-cum-IDE which seemed to offer more, I moved on. Is there any compelling reason, in this day and age, to choose Vi / Emacs over – say- Eclipse for code editing? Even Notepad++ for win-doze users seems to offer more. Just sayin'

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  • Decision Tree code golf

    - by Chris Jester-Young
    In Google Code Jam 2009, Round 1B, there is a problem called Decision Tree that lent itself to rather creative solutions. Post your shortest solution; I'll update the Accepted Answer to the current shortest entry on a semi-frequent basis, assuming you didn't just create a new language just to solve this problem. :-P Current rankings: 107 Perl 121 PostScript (binary) 136 Ruby 154 Arc 160 PostScript (ASCII85) 170 PostScript 192 Python 199 Common Lisp 214 LilyPond 222 JavaScript 273 Scheme 280 R 312 Haskell 314 PHP 339 m4 346 C 406 Fortran 462 Java 476 Java (well, kind of) 718 OCaml 759 F# 1741 sed C++ not qualified for now

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  • Remove In-App Purchase from free app and increase the price

    - by Arseniy Banayev
    The current version of an application in the App Store is free and has very limited functionality. An In-App Purchase unlocks everything else. I have decided to remove the In-App Purchase and just make the application cost the same price as the In-App Purchase did. But if I make the update now, then those users who have the free version but who have not yet paid for the In-App Purchase will get a free update into the full version. I have removed all traces of my singleton class, PurchaseManager, from the application, so that at this point, when I build/run it, all of the features are unlocked. At this point, how can I make sure that the free-version users don't just ride an update into the full version? Maybe there's a way to test whether the app is obtained through an update or through a purchase? That way, if it's through an update, I will see if it's the free version w/o the IAP and then force the user to purchase the IAP to continue playing. Any ideas?

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  • Palindrome Golf

    - by Claudiu
    The goal: Any language. The smallest function which will return whether a string is a palindrome. Here is mine in Python: R=lambda s:all(a==b for a,b in zip(s,reversed(s))) 50 characters. The accepted answer will be the current smallest one - this will change as smaller ones are found. Please specify the language your code is in.

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  • Examples of IOC/DI over Singleton

    - by Amitd
    Hi, Just started learning/reading about DI and IOC frameworks. Also I read many articles on SO and internet that say that one should prefer DI/IOC over singleton. Can anyone give/link examples of exactly how DI/IOC eliminates/solves the various issues regarding the Singleton pattern? (hopefully code and explanation for better understanding) Also given a system has already implemented Singleton pattern, how to refactor/implement DI/IOC for the same? (any examples for the same?) (Language/Framework no bars..C# would be helpful) Thanks

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