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  • Codeigniter view file looping query

    - by user2505513
    Right, I'm unsure about how to code my view file to generate following query results WITHOUT compromising the principles of mvc. Query in model: SELECT * FROM events GROUP BY country, area ORDER BY country, area View: <?php if (isset($query)):?> <?php foreach ($query as $row):?> <h2><?=$row->country?></h2> <h3><?=$row->area?></h3> <?php endforeach;?> <?php endif;?> I want the results to display: England North South West - utilising the GROUP BY parameter As opposed to: England North England South England West Has anybody any advice as to how to achieve this?

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  • Zend_Session: unserialize session data

    - by takeshin
    I'm using session SaveHandler to persist session data in the database. Sample session_data column from the database: Messenger|a:1:{s:13:"page_messages";a:0:{}}userSession|a:1:{s:7:"referer";s:32:"http://cms.dev/user/profile/view";}Zend_Auth|a:1:{s:7:"storage";O:19:"User_Model_Identity":3:{s:2:"id";s:1:"1";s:8:"username";s:13:"administrator";s:4:"slug";s:13:"administrator";}} I want to delete Zend_Auth object from this session data. How can I unserialize those objects and remove object I need? I suspect, that I don't have to write my custom parser, that Zend_Session already has a method to do this. I have tried different combinations of unserialize but it still returns false. I'm using autoloader from ZF 1.10.2 and Doctrine 1.2

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  • PHP ZF: I can't debug my IndexController.php actions code

    - by overthetop
    Hi I'm new to php and I'm using xampp, eclipse pdt, xdebug. I've set xdebug so that I can debug my site on apache but when I click 'debug as web page' in the eclipse ide only the breakpoint in the public/index.php and in the views get hit. If I put a breakpoin here public function indexAction() { // action body $this->view->s = "deam"; } the debugger don't stop?! why is that? I can't debug the most important part of my application. :( Plese help me with this.

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  • url to http request object

    - by takeshin
    I need to convert string like this: $url = 'module/controller/action/param1/param1value/paramX/paramXvalue'; to url regarding current router (including translation and so on). Usually I generate the target urls using url view helper, but for this I need to specify all params, so I would need to manually explode the string. I tried to use request object, like this: $request = new Zend_Controller_Request_Http(); // some code here passing the $url Zend_Debug::dump($request->getControllerName()); // null instead of 'controllers' Zend_Debug::dump($request->getParams()); // null instead of array but this seems to be suspected. Do I need to dispatch this request? How to handle this case well?

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  • Developing high-performance and scalable zend framework website

    - by Daniel
    We are going to develop an ads website like http://www.gumtree.com/ (it will not be like this one but just to give you an ideea) and we are having some issues regarding performance and scalability. We are planning on using Zend Framework for this project but this is all that I'm sure off at this point. I don't think a classic approch like Zend Framework (PHP) + MySQL + Memcache + jQuery (and I would throw Doctrine 2 in there to) will fix result in a high-performance application. I was thinking on making this a RESTful application (with Zend Framework) + NGINX (or maybe MongoDB) + Memcache (or eAccelerator -- I understand this will create problems with scalability on multiple servers) + jQuery, a CDN for static content, a server for images and a scalable server for the requests and the rest. My questions are: - What do you think about my approch? - What solutions would you recommand in terms of servers approch (MySQL, NGINX, MongoDB or pgsql) for a scalable application expected to have a lot of traffic using PHP?...I would be interested in your approch. Note: I'm a Zend Framework developer and don't have to much experience with the servers part (to determin what would be best solution for my scalable application)

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  • Correct way to import Blueprint's ie.css via DotLess in a Spark view

    - by Chris F
    I am using the Spark View Engine for ASP.NET MVC2 and trying to use Blueprint CSS. The quick guide to Blueprint says to add links to the css files like so: <link rel="stylesheet" href="blueprint/screen.css" type="text/css" media="screen, projection"> <link rel="stylesheet" href="blueprint/print.css" type="text/css" media="print"> <!--[if lt IE 8]><link rel="stylesheet" href="blueprint/ie.css" type="text/css" media="screen, projection"><![endif]--> But I'm using DotLess and wish to simplify Blueprint as suggested here. So I'm doing this in my site.less (which gets compiled to site.min.css by Chirpy): @import "screen.css"; #header { #title { .span-10; .column; } } ... Now my site can just reference site.min.css and it includes blueprint's screen.css, which includes my reset. I can also tack on an @import "print.css" after my @import "screen.css" if desired. But now, I'm trying to figure out the best way to bring in the ie.css file to have Blueprint render correctly in IE6 & IE7. In my Spark setup, I have a partial called _Styles.spark that is brought into the Application.spark and is passed a view model that includes the filenames for all stylesheets to include (and an HtmlExtension to get the full path) and they're added using an "each" iterator. <link each="var styleSheet in Model.Styles" href="${Html.Stylesheet(styleSheet)}" rel="stylesheet" type="text/css" media="all"/> Should I simply put this below the above line in my _Styles.spark file? <!--[if lt IE 8]><link rel="stylesheet" href="${Html.Stylesheet("ie.css")}" type="text/css" media="screen, projection"><![endif]--> Will Spark even process it because it's surrounded by a comment?

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  • Any good example about Autocomplete with Zend Framework? (JQuery and ZendX)

    - by joanballester
    Hi guys, I have a problem, I don't find good examples of "autocomplete" with zend framework (using jQuery with zendx). I need one that works to understand how to develop it. Someone has done it? Thank you very much in advance PS: I know how to do it without ZendX, I mean, doing the form myself (and using jquery as usual with a autocomplete.php file using the parameter typed in the input field), but I would like to use the zend framework properly, so I would like to know if someone has made it.

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  • iPhone contacts app styled indexed table view implementation

    - by KSH
    My Requirement: I have this straight forward requirement of listing names of people in alphabetical order in a Indexed table view with index titles being the starting letter of alphabets (additionally a search icon at the top and # to display misc values which start with a number and other special characters). What I have done so far: 1. I am using core data for storage and "last_name" is modelled as a String property in the Contacts entity 2.I am using a NSFetchedResultsController to display the sorted indexed table view. Issues accomplishing my requirement: 1. First up, I couldn't get the section index titles to be the first letter of alphabets. Dave's suggestion in the following post, helped me achieve the same: http://stackoverflow.com/questions/1112521/nsfetchedresultscontroller-with-sections-created-by-first-letter-of-a-string The only issue I encountered with Dave' suggestion is that I couldn't get the misc named grouped under "#" index. What I have tried: 1. I tried adding a custom compare method to NSString (category) to check how the comparison and section is made but that custom method doesn't get called when specified in the NSSortDescriptor selector. Here is some code: `@interface NSString (SortString) -(NSComparisonResult) customCompare: (NSString*) aStirng; @end @implementation NSString (SortString) -(NSComparisonResult) customCompare:(NSString *)aString { NSLog(@"Custom compare called to compare : %@ and %@",self,aString); return [self caseInsensitiveCompare:aString]; } @end` Code to fetch data: `NSArray *sortDescriptors = [NSArray arrayWithObject:[[[NSSortDescriptor alloc] initWithKey:@"last_name" ascending:YES selector:@selector(customCompare:)] autorelease]]; [fetchRequest setSortDescriptors:sortDescriptors]; fetchedResultsController = [[NSFetchedResultsController alloc] initWithFetchRequest:fetchRequest managedObjectContext:managedObjectContext sectionNameKeyPath:@"lastNameInitial" cacheName:@"MyCache"];` Can you let me know what I am missing and how the requirement can be accomplished ?

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  • Android accessibility focus - clicking a view changes focus to previous view

    - by benkdev
    I'm using android TalkBack to test my application for accessibility use. When I swipe to select a view and double tap, the focus returns the the view above it. Usually when swiping to a view and double clicking it, onClick is called. What am I doing wrong? <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" android:background="@color/all_white" > <ImageView android:layout_width="wrap_content" android:layout_height="wrap_content" android:src="@drawable/header" android:scaleType="center" /> <ImageView android:layout_width="wrap_content" android:layout_height="wrap_content" android:src="@drawable/green_bar" android:scaleType="center" /> <ImageView android:layout_width="wrap_content" android:layout_height="wrap_content" android:src="@drawable/blue_bar" android:scaleType="center" /> <EditText android:id="@+id/username" android:layout_width="325dp" android:layout_height="wrap_content" android:hint="@string/username" android:focusable="true" android:nextFocusDown="@id/password" /> <EditText android:id="@+id/password" android:inputType="textPassword" android:layout_width="325dp" android:layout_height="wrap_content" android:hint="@string/password" android:focusable="true" android:nextFocusUp="@id/username" android:nextFocusDown="@id/login" /> <Button android:id="@+id/login" android:onClick="doLogin" android:focusable="true" android:layout_width="325dp" android:layout_height="wrap_content" android:text="@string/login" android:nextFocusUp="@id/password" android:nextFocusDown="@id/create_trial_account" /> <Button android:id="@+id/create_trial_account" android:layout_width="100dip" android:layout_height="wrap_content" android:text="@string/new_user" android:onClick="createAccount" android:focusable="true" android:nextFocusUp="@id/login" /> <TextView android:id="@+id/copyright" android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="@string/copyright" /> <TextView android:id="@+id/buildNumber" android:layout_width="fill_parent" android:layout_height="wrap_content" /> </LinearLayout>

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  • Passing JSON object from Controller to View(jsp)

    - by user752233
    I am trying to send JSON object to my view from controller but unable to send it. Please help me out! I am using following code public class SystemController extends AbstractController{ protected ModelAndView handleRequestInternal(HttpServletRequest request, HttpServletResponse response) throws Exception { ModelAndView mav = new ModelAndView("SystemInfo", "System", "S"); response.setContentType("application/json;charset=UTF-8"); response.setHeader("Cache-Control", "no-cache"); JSONObject jsonResult = new JSONObject(); jsonResult.put("JVMVendor", System.getProperty("java.vendor")); jsonResult.put("JVMVersion", System.getProperty("java.version")); jsonResult.put("JVMVendorURL", System.getProperty("java.vendor.url")); jsonResult.put("OSName", System.getProperty("os.name")); jsonResult.put("OSVersion", System.getProperty("os.version")); jsonResult.put("OSArchitectire", System.getProperty("os.arch")); response.getWriter().write(jsonResult.toString()); // response.getWriter().close(); return mav; // return modelandview object } } and in the view side I am using <script type="text/javascript"> Ext.onReady(function(response) { //Ext.MessageBox.alert('Hello', 'The DOM is ready!'); var showExistingScreen = function () { Ext.Ajax.request({ url : 'system.htm', method : 'POST', scope : this, success: function ( response ) { alert('1'); var existingValues = Ext.util.JSON.decode(response.responseText); alert('2'); } }); }; return showExistingScreen(); });

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  • How to add View Controller with Tab Bar interfaced View Controller

    - by TechFusion
    I have created Window based Tab Bar controller app, One Tab Bar of viewController has been interfaced with WebVIew ..I am looking to create another view once touch event happened in that WebView.. //TabBarViewController.m - (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event { TabMainView *mainView = [[TabMainView alloc] init]; mainView.hidesBottomBarWhenPushed = YES; [self.navigationController pushViewController: mainView animated:YES]; [mainView release]; } I have created MainView, which is UIViewController Subclass. //TabMainView.m - (void)loadView { CGRect frame = CGRectMake(0.0, 0.0, 480, 320); WebView = [[[UIWebView alloc] initWithFrame:frame] autorelease]; WebView.backgroundColor = [UIColor whiteColor]; WebView.scalesPageToFit = YES; WebView.autoresizingMask = (UIViewAutoresizingFlexibleWidth | UIViewAutoresizingFlexibleHeight | UIViewAutoresizingFlexibleLeftMargin | UIViewAutoresizingFlexibleTopMargin); WebView.autoresizesSubviews = YES; WebView.exclusiveTouch = YES; //self.WebView.UserInteractionEnabled = NO; WebView.clearsContextBeforeDrawing = YES; self.view = WebView; [WebView release]; } - (void)viewWillAppear:(BOOL)animated { [self.WebView loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:@"http://www.apple.com"]]]; } Here when touch event happened then it is not passing control to TabMainView.m 's Viewload function although I am pushing it's view? TabBarView is also UIViewController subclass not a UINavigationController.

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  • iPhone SDK: Switching to one view then back to previous view errors

    - by Nic Hubbard
    I have a UITabBarConroller that I use to switch between 3 different views. This all works perfectly. On one of my tabs, I added a button at the to called "Add", I have added an outlet to this, as well as an IBAction method which looks like the following: // Method used to load up view where we can add a new ride - (IBAction)showAddNewRideView { MyRidesViewController *controller = [[MyRidesViewController alloc] initWithNibName:@"AddNewRide" bundle:nil]; controller.modalTransitionStyle = UIModalTransitionStyleCoverVertical; [self presentModalViewController:controller animated:YES]; [controller release]; }//end showAddNewRideView This currently works fine, and loads up my AddNewRide nib file. But, once that view loads, I have a cancel button, which, when clicked, I want to return to the previous view. So, I figured I would just do the reverse of the above, using the following method which would load back my previous nib: - (IBAction)cancelAddingNewRide { MyRidesViewController *controller = [[MyRidesViewController alloc] initWithNibName:@"MainWindow" bundle:nil]; controller.modalTransitionStyle = UIModalTransitionStyleCoverVertical; [self presentModalViewController:controller animated:YES]; [controller release]; }//end cancelAddingNewRide But, which trying to load the MainWindow nib, the program crashes, and I get the following error: 2010-05-05 20:24:37.211 Ride[6032:207] *** -[MyRidesViewController cancelAddingNewRide]: unrecognized selector sent to instance 0x501e450 2010-05-05 20:24:37.213 Ride[6032:207] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '*** -[MyRidesViewController cancelAddingNewRide]: unrecognized selector sent to instance 0x501e450' So, I am a little lost as to why it would work one way, but not the other.

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  • Zend_Controller_Router_Route: Could not find a translator

    - by Antonio
    I am developing a multilanguage application. In the bootstrap there is the routes setup: protected function _initRoutes() { $this->bootstrap('frontController'); $router = $this->frontController->getRouter(); // PAGES ROUTE $page = new Zend_Controller_Router_Route( ':language/:ident', array( 'module' => 'core', 'controller' => 'pagine', 'action' => 'view' ), array( 'ident' => '[a-zA-Z-_0-9]{3,}', 'language' => '[a-z]{2}' ) ); $registrazione = new Zend_Controller_Router_Route( ':language/@utenti/@registrati', array( 'module' => 'core', 'controller' => 'utenti', 'action' => 'registrazione' ), array( 'language' => '[a-z]{2}' ) ); $router->addRoute('page', $page); $router->addRoute('registrazione', $registrazione); ..... } I cannot set the default translator to Zend_Controller_Router_Route (for translated segments) because i don't know the language parameter in the request object. I get the language parameter in Multilanguage Plugin during the "routeShutdown": class Activa_Controller_Plugin_Multilanguage extends Zend_Controller_Plugin_Abstract { public function routeShutdown(Zend_Controller_Request_Abstract $request) { $language = $request->getParam("language"); $locale = new Zend_Locale($language); $translate = new Zend_Translate('array', APPLICATION_PATH.'/config/lang/'.$language.'.php', $locale); Zend_Registry::set('Zend_Locale', $locale); Zend_Registry::set('Zend_Translate', $translate); Zend_Controller_Router_Route::setDefaultTranslator($translate); //////////////////////// // BUT NOW IS TOO LATE //////////////////////// } When i type the address "http://servername/it/utenti/registrati" i get the exception with the message "Could not find a translator". How can i fix it? Antonio (Italy)

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  • Creating a [materialised]view from generic data in Oracle/Mysql

    - by Andrew White
    I have a generic datamodel with 3 tables CREATE TABLE Properties ( propertyId int(11) NOT NULL AUTO_INCREMENT, name varchar(80) NOT NULL ) CREATE TABLE Customers ( customerId int(11) NOT NULL AUTO_INCREMENT, customerName varchar(80) NOT NULL ) CREATE TABLE PropertyValues ( propertyId int(11) NOT NULL, customerId int(11) NOT NULL, value varchar(80) NOT NULL ) INSERT INTO Properties VALUES (1, 'Age'); INSERT INTO Properties VALUES (2, 'Weight'); INSERT INTO Customers VALUES (1, 'Bob'); INSERT INTO Customers VALUES (2, 'Tom'); INSERT INTO PropertyValues VALUES (1, 1, '34'); INSERT INTO PropertyValues VALUES (2, 1, '80KG'); INSERT INTO PropertyValues VALUES (1, 2, '24'); INSERT INTO PropertyValues VALUES (2, 2, '53KG'); What I would like to do is create a view that has as columns all the ROWS in Properties and has as rows the entries in Customers. The column values are populated from PropertyValues. e.g. customerId Age Weight 1 34 80KG 2 24 53KG I'm thinking I need a stored procedure to do this and perhaps a materialised view (the entries in the table "Properties" change rarely). Any tips?

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  • Performance of VIEW vs. SQL statement

    - by Matt W.
    I have a query that goes something like the following: select <field list> from <table list> where <join conditions> and <condition list> and PrimaryKey in (select PrimaryKey from <table list> where <join list> and <condition list>) and PrimaryKey not in (select PrimaryKey from <table list> where <join list> and <condition list>) The sub-select queries both have multiple sub-select queries of their own that I'm not showing so as not to clutter the statement. One of the developers on my team thinks a view would be better. I disagree in that the SQL statement uses variables passed in by the program (based on the user's login Id). Are there any hard and fast rules on when a view should be used vs. using a SQL statement? What kind of performance gain issues are there in running SQL statements on their own against regular tables vs. against views. (Note that all the joins / where conditions are against indexed columns, so that shouldn't be an issue.) EDIT for clarification... Here's the query I'm working with: select obj_id from object where obj_id in( (select distinct(sec_id) from security where sec_type_id = 494 and ( (sec_usergroup_id = 3278 and sec_usergroup_type_id = 230) or (sec_usergroup_id in (select ug_gi_id from user_group where ug_ui_id = 3278) and sec_usergroup_type_id = 231) ) and sec_obj_id in ( select obj_id from object where obj_ot_id in (select of_ot_id from obj_form left outer join obj_type on ot_id = of_ot_id where ot_app_id = 87 and of_id in (select sec_obj_id from security where sec_type_id = 493 and ( (sec_usergroup_id = 3278 and sec_usergroup_type_id = 230) or (sec_usergroup_id in (select ug_gi_id from user_group where ug_ui_id = 3278) and sec_usergroup_type_id = 231) ) ) and of_usage_type_id = 131 ) ) ) ) or (obj_ot_id in (select of_ot_id from obj_form left outer join obj_type on ot_id = of_ot_id where ot_app_id = 87 and of_id in (select sec_obj_id from security where sec_type_id = 493 and ( (sec_usergroup_id = 3278 and sec_usergroup_type_id = 230) or (sec_usergroup_id in (select ug_gi_id from user_group where ug_ui_id = 3278) and sec_usergroup_type_id = 231) ) ) and of_usage_type_id = 131 ) and obj_id not in (select sec_obj_id from security where sec_type_id = 494) )

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  • Magento: Attribute always returns default value in catalog view, works fine in product view

    - by colinodell
    I've created a new Yes/No attribute for products. I've extended the Product model to do some custom logic and the custom functions are working everywhere. When I initially tried getting the custom attribute value, I ran into some issue. Magento wasn't loading it for me, so calls to $product-getMyAttributeName() did nothing. In the product views, I got it working with this additional function: public function getAttrVal($attr_name) { return $this->getResource()->getAttribute($attr_name)->getFrontend()->getValue($this); } So that worked great when viewing a product on the frontend. It would fetch the assigned value if set, or the default if not. When I view any Category (grid of all products in that category), the same exact code is being executed. But my getAttrVal() function always returns the default value, even if I've explicitly set this value for my product. I can't, for the life of me, figure out why the attribute loads correctly in the Product view but the Category view always grabs the default value, despite running the same exact code. Any thoughts?

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  • Should strongly typed partial views on one page in asp.net mvc-2 have one combined view model?

    - by Kai
    Hi guys, I have a question about asp.net mvc-2 strongly typed partial views, and view models. I was just wondering if I can (or should) have two strongly typed partial views on one page, without implementing a whole new view model for that page. For example, I have a page that displays profiles, but also has an inline form to add a quick contact. Each of these entities already has it's own view model, i.e I have a ProfileViewModel and a ContactViewModel. So my view needs two strongly typed partial views, one using an IEnumerable List of ProfileViewModels, and one using a ContactViewModel. Is it possible or desirable to avoid making a third view model, an 'IndexViewModel' for this page, which holds a list of ProfileViewModels and a ContactViewModel? Is not implementing this view model bad practice, or tidier as it results in less view models? Thanks!

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