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• Suppressing the language select button iPhone

  - by AWinter

  I'm working on an application now that contains an account register section. One field with secureTextEntry = NO (for registering only). The idea is this make registration faster and hopefully increases the number of signups. It's simple enough for me to just place a regular UITextField but if the user has any additional language keyboards then it's possible for the user to enter non-password friendly characters. Unlike in when secureTextEntry = YES. I know I can do textField.keyboardType = UIKeyboardTypeASCIICapable to get the text field to display the ASCII keyboard first, but the user will still have the keyboard switch button which will allow them to get to undesirable characters. Is there a simple method for suppressing the international button or forcing ASCII only keyboard with no international button? [EDIT] Another perhaps better option might be to suppress multi byte keyboards or even to display the text in the case that secureTextEntry = YES any ideas here? [EDIT AGAIN] I've decided it's a really bad idea to suppress the international button as non-multibyte characters should all be allowed.

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• Why isn't DBIx::Class::Schema::Loader creating my classes?

  - by Robert Wohlfarth

  I am trying to generate static schemas using DBIx::Class in Perl. The command shown below outputs a Schema.pm and no other files. Any idea what I'm doing wrong, or how to to debug this? U:\wohlfarj\Software\PARS>perl -MDBIx::Class::Schema::Loader=make_schema_at,dump_to_dir:.\lib -e "make_schema_at('PARS::Schema',{debug=>1},['dbi:ODBC:PARS','user','password',{AutoCommit=>0}])" Dumping manual schema for PARS::Schema to directory .\lib ... Schema dump completed. I'm using Strawberry Perl on Windows XP. The database is SQL Server 2000, accessed through an ODBC connection. I can successfully run queries using plain old DBI with the same ODBC connection.

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• CREATE USER in MS Access 2010

  - by Anakela

  I have been searching for several hours regarding how to create a user using SQL for a database I am building in Access. I found several sources on Microsoft's website that say I can use the CREATE USER command to do this. However, whenever I attempt to run the query, an error saying Syntax error in CREATE TABLE statement pops up. What am I doing wrong? Thank you in advance for your help! If you're interested, the code format I am attempting to use is as follows: CREATE USER username, password, pid.

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• Teamcity NTLM Authentication change - admin user lost in transition

  - by hawkeye

  I've switched in teamcity from using basic authentication to using NTLM, on an existing installation. This works fine, except that the admin user didn't have a corresponding NT account, and so doesn't work on the NTLM configuration. (It is easy to roll back, so it is not a stress). My question is - what is the command to set a user to admin manually - ie modifying the database? (like this: TeamCity forgotten admin password - where to look?) but changing the role of a user to global system administrator.

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• Extending Windows Desktop using C#

  - by Lijo

  Hi Team, I am trying to customize my Windows XP’s desktop using C# code. This is my first venture of this kind. Could you please point me to some documentation that will Give the names of classes that can be used for extending/customizing Windows’ desktop Some example code What I am trying to do specifically is as follows I am planning to customize the desktop. When I unlock my computer (by entering user name and password) the files should come(by flying) into their required places. Initially the files are to be located in the right end corner. Thanks Lijo Cheeran Joseph

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• subversion problem - commit access

  - by Calvin

  Hi everyone, I'm new to setting up subversion but originally when I made a repository, all my team members could update and commit without problem. There was a problem with it so we decided to recreate it, but now only I can commit changes to it. And my username/password doesn't work on their computers, so I'm sure it's something obvious and silly, but I just don't know enough to know what's causing it. The passwd and svnserve.conf files are the same as the original repository that worked for everyone. Any ideas? Thanks in advance.

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• What keying option does the keychain use?

  - by Rudiger

  I have read into the keychain and have found that it uses Triple DES. What I can't find is what keying option it uses. I am guessing / hoping that its keying option 1 where all 3 passwords are unique but if thats the case I can only think of two passwords it can use (user password and App ID that comes from your dev cert) so where is the third coming from? Is it a key private to Apple? If its keying option 2 (first and third key are the same) it might not be secure enough for our company to rely on. Although that might sound paranoid I have to justify to our security department that it is secure enough.

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• Powerpoint file can be deleted without consequence

  - by John Maloney

  I am working on a license management type application that copies a password protected zip file to the applications root. The user clicks a button "Open Presentation" and the zipped file is extracted into the root folder and then I use the Office interop to open the file in Powerpoint. At this point to my surprise I am able to delete the extracted file that is currently open in the Powerpoint application. I had assumed that trying to delete the file would fail as the file is still open in Powerpoint. Why is it allowing me to delete the file? Is the file somehow copied to a temp folder and then opened in PowerPoint? Can I move forward with the application relying on this ability to delete the file as soon as it is opened in Powerpoint? This would be optimal because it helps insure that the file cannot be copied(I am also using the xml to stop "Save As" and "Save" from appearing int Powerpoint). Thanks for the insight, John

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• MySQL INSERT data does not get stored in proper db, only temporary?

  - by greye

  I'm having trouble with MySQL or Python and can't seem to isolate the problem. INSERTs only seem to last the run of the script and are not stored in the database. I have this script: import MySQLdb db = MySQLdb.connect(host="localhost", user="user", passwd="password", db="example") dbcursor = db.cursor() dbcursor.execute("select * from tablename") temp = dbcursor.fetchall() print 'before: '+str(temp) dbcursor.execute('INSERT INTO tablename (data1, data2, data3) VALUES ("1", "a", "b")') dbcursor.execute("select * from tablename") temp = dbcursor.fetchall() print 'after: '+str(temp) The first time I run it I get the expected output: >>> before: () after: ((1L, 'a', 'b'),) The problem is that if I run it again, the before comes out empty when it should already have the entry in it and the after doesn't break (data 1 is primary key). >>> before: () after: ((1L, 'a', 'b'),) >>> before: () after: ((1L, 'a', 'b'),) >>> before: () after: ((1L, 'a', 'b'),) If I try running the insert command twice in the same script it will break ("Duplicate entry for PRIMARY KEY") Any idea what might be happening here?

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• Using gmail as SMTP server in Java web app is slow

  - by Annie

  Hi, I was wondering if anyone might be able to explain to me why it's taking nearly 30 seconds each time my Java web app sends an email using Gmail's SMTP server? See the following timestamps: 13/04/2010-22:24:27:281 DEBUG test.service.impl.SynchronousEmailService - Before sending mail. 13/04/2010-22:24:52:625 DEBUG test.service.impl.SynchronousEmailService - After sending mail. I'm using spring's JavaMailSender class with the following settings: email.host=smtp.gmail.com [email protected] email.password=mypassword email.port=465 mail.smtp.auth.required=true Note that the mail is getting sent and I'm receiving it fine, there's just this delay which is resulting in a slow experience for the application user. If you know how I can diagnose the problem myself that would be good too :)

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• How does one encrypt site passwords for a Dreamweaver export file?

  - by ngreenwood6

  We have over 500 sites that we host. All of their ftp information is in a database. Whenever one of our programmers have to add a site they have to get all the info and set it up. However, I found that you can export them and it has all the info except for one problem. The password is encrypted. I am not trying to hack anything, I want to know how to encrypt our passwords so that we can import them using dreamweavers import feature. Can anyone tell me what encryption they use or a link on how to encrypt. I am not interested in decrypting at all because we already have all of them so it would not do me any good.

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• For Loop help In a Hash Cracker Homework.

  - by aaron burns

  On the homework I am working on we are making a hash cracker. I am implementing it so as to have my cracker. java call worker.java. Worker.java implements Runnable. Worker is to take the start and end of a list of char, the hash it is to crack, and the max length of the password that made the hash. I know I want to do a loop in run() BUT I cannot think of how I would do it so it would go to the given max pasword length. I have posted the code I have so far. Any directions or areas I should look into.... I thought there was a way to do this with a certain way to write the loop but I don't know or can't find the correct syntax. Oh.. also. In main I divide up so x amount of threads can be chosen and I know that as of write now it only works for an even number of the 40 possible char given. package HashCracker; import java.util.*; import java.security.MessageDigest; import java.security.NoSuchAlgorithmException; public class Cracker { // Array of chars used to produce strings public static final char[] CHARS = "abcdefghijklmnopqrstuvwxyz0123456789.,-!".toCharArray(); public static final int numOfChar=40; /* Given a byte[] array, produces a hex String, such as "234a6f". with 2 chars for each byte in the array. (provided code) */ public static String hexToString(byte[] bytes) { StringBuffer buff = new StringBuffer(); for (int i=0; i<bytes.length; i++) { int val = bytes[i]; val = val & 0xff; // remove higher bits, sign if (val<16) buff.append('0'); // leading 0 buff.append(Integer.toString(val, 16)); } return buff.toString(); } /* Given a string of hex byte values such as "24a26f", creates a byte[] array of those values, one byte value -128..127 for each 2 chars. (provided code) */ public static byte[] hexToArray(String hex) { byte[] result = new byte[hex.length()/2]; for (int i=0; i<hex.length(); i+=2) { result[i/2] = (byte) Integer.parseInt(hex.substring(i, i+2), 16); } return result; } public static void main(String args[]) throws NoSuchAlgorithmException { if(args.length==1)//Hash Maker { //create a byte array , meassage digestand put password into it //and get out a hash value printed to the screen using provided methods. byte[] myByteArray=args[0].getBytes(); MessageDigest hasher=MessageDigest.getInstance("SHA-1"); hasher.update(myByteArray); byte[] digestedByte=hasher.digest(); String hashValue=Cracker.hexToString(digestedByte); System.out.println(hashValue); } else//Hash Cracker { ArrayList<Thread> myRunnables=new ArrayList<Thread>(); int numOfThreads = Integer.parseInt(args[2]); int charPerThread=Cracker.numOfChar/numOfThreads; int start=0; int end=charPerThread-1; for(int i=0; i<numOfThreads; i++) { //creates, stores and starts threads. Runnable tempWorker=new Worker(start, end, args[1], Integer.parseInt(args[1])); Thread temp=new Thread(tempWorker); myRunnables.add(temp); temp.start(); start=end+1; end=end+charPerThread; } } } import java.util.*; public class Worker implements Runnable{ private int charStart; private int charEnd; private String Hash2Crack; private int maxLength; public Worker(int start, int end, String hashValue, int maxPWlength) { charStart=start; charEnd=end; Hash2Crack=hashValue; maxLength=maxPWlength; } public void run() { byte[] myHash2Crack_=Cracker.hexToArray(Hash2Crack); for(int i=charStart; i<charEnd+1; i++) { Cracker.numOfChar[i]////// this is where I am stuck. } } }

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• how to add svn repository for an iphone application

  - by ratnasomu

  hellow all i am using svn for version control for an iphone application . i have created it from xcode repositories by giving url ,user name and password its authenticated .After that i have created a directory from there itself and have imported my project there. Then i have checked out to the local directory and have updated something in it. Click on commit changes. It done. After that i came to terminal to commit the project first time from terminal .There i have removed the build of the project then gave a command like "svn update". here i am getting error like svn: PROPFIND request failed on '/svn/pacman/GameDevelopment/Game'and 403 Forbidden error whts going wrong here? could any one help me in this ? Thanks..

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• Security in API authentication

  - by Carlos

  We are in the process of revamping our server side API, and we need to manage security. Our current model requires that a credentials object (containing user, password, and pin) be included in each method invocation. Our development team, however, has decided that we should have session objects instead (which is fine by me), but the new credentials are just a GUID. This is very different from what I've seen in other APIs in our industry, so I'm a bit concerned about how secure the new model will be. I asked them if they had analyzed both alternatives, and they said they haven't. Does anyone know if there're any clear advantages, disadvantages, risks, etc. of using a set of credentials versus just one element (complex as it may be)? PS: the communication channel would be secure in either case, and it's separate from this particular topic

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• Drupal: I cannot connect to the database.. please help

  - by Patrick

  hi, I've hard time to make Drupal work on IIS Microsoft server. I've succesfully run Joomla on the same server so I'm pretty sure the following information are correct: host: localhost user: user pass: pass databaseName = servername_databasename I've set the following line in settings.php file: $db_url = 'mysql://user:password@localhost/servername_databasename'; but what I get is this: If you are the maintainer of this site, please check your database settings in the settings.php file and ensure that your hosting provider's database server is running. For more help, see the handbook, or contact your hosting provider. I don't get any other error message such as: database doesn't exist, user/pass wrong.. just this. The database is running, I can access with phpmyadmin. I've tried both "mysql" and "mysqli". The host is a private server (IIS Microsoft), the database is Mysql The database and website files upload have also been succesfull.. so I dunno what to do to fix this issue. thanks

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• Simulating a cookie-enabled browser in PHP

  - by Itamar Benzaken

  How can I open a web-page and receive its cookies using PHP? The motivation: I am trying to use feed43 to create an RSS feed from the non-RSS-enabled HighLearn website (remote learning website). I found the web-page that contains the feed contents I need to parse, however, it requires to login first. Luckily, logging in can be done via a GET request so it's as easy as fopen()ing "http://highlearn.website/login_page.asp?userID=foo&password=bar" for example. But I still need to get the cookies generated when I logged in, pass the cookies to the real client (using setcookie() maybe?) and then redirect.

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• how do i connect to MSSQL 2008 database in JAVA with jbbc

  - by shuxer

  Hello I have MSSQL 2008 installed on my local PC, and my java application needs to connect to a mssql database. I am a new to MSSQL and i would like get some help on creating user login for my java application and getting connection via jdbc. So far i tried to create a user login for my app and used following connection string, but i doest work at all. Any help and hint will be appreciated. jdbc:jtds:sqlserver://127.0.0.1:1433/dotcms username="shuxer" password="itarator" Thanks in advance.

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• Converting LDAP from Tomcat to GlassFish

  - by Jon

  Hi, I have a simple web-app that is developed in Netbeans(6.8) and works fine in Tomcat(6) using LDAP(Active Directory). I need to convert this to an EE (JSF2), so I am moving from Tomcat to GlassFish(v3). I have changed the web files to xhtml and configured the xml files. However, I cannot get the GlassFish LDAP configuration to authenticate. I am attaching my old web.xml and server.xml (from Tomcat) snippets and the portions of the new web.xml, sun-web.xml, and the GlassFish configuration. If anyone can help me figure out where I am missing the piece that will allow a user to be authenticated, I would appreciate it. (btw, I am not using roles, just authenticating against the LDAP db is good enought.) As it is right now, my app will prompt me to enter a user when I try to access a file in the 'protected' area and the GlassFish server throws an exception when it fails to authenticate. Because it works under Tomcat, I know I have the right information, I just don't know how to format it to get GlassFish to pass it along. Thanks. TOMCAT FILES: - Tomcat server.xml: web.xml: <web-resource-collection> <web-resource-name>Protected Area</web-resource-name> <description>Authentication Required</description> <url-pattern>/faces/protected/*</url-pattern> </web-resource-collection> <auth-constraint> <role-name>*</role-name> </auth-constraint> * BASIC Please enter your user name and password: GLASSFISH FILES: (I enabled the Security Manager on the Security panel, set the Default Realm to 'LDAPRealm', and added "-Djava.naming.referral=follow" JVM options.) - domain.xml: <auth-realm name="certificate" classname="com.sun.enterprise.security.auth.realm.certificate.CertificateRealm" /> <auth-realm classname="com.sun.enterprise.security.auth.realm.ldap.LDAPRealm" name="LdapRealm"> <property description="()" name="search-bind-password" value="xxxxxxxx" /> <property description="()" name="search-bind-dn" value="cn=xxxxxxxx,ou=Administrators,ou=Information Technology,ou=ITTS,ou=Administrative,ou=xxx,dc=xxxxxx,dc=xxx" /> <property name="jaas-context" value="ldapRealm" /> <property name="base-dn" value="ou=xxx,dc=xxxxxx,dc=xxx" /> <property name="directory" value="ldap://xxxx.xxxxxx.xxx:389" /> <property name="search-filter" value="(&amp;(objectClass=user)(sAMAccountName=%s))" /> </auth-realm> -web.xml: <security-constraint> <display-name>protected</display-name> <web-resource-collection> <web-resource-name>ProtectedArea</web-resource-name> <description/> <url-pattern>/faces/protected/*</url-pattern> </web-resource-collection> <auth-constraint> <description/> <role-name>*</role-name> </auth-constraint> </security-constraint> <security-role> <description/> <role-name>*</role-name> </security-role> <login-config> <auth-method>FORM</auth-method> <realm-name>LDAPRealm</realm-name> <form-login-config> <form-login-page>/faces/login.xhtml</form-login-page> <form-error-page>/faces/loginError.xhtml</form-error-page> </form-login-config> </login-config> sun-web.xml: Here is the exception that it throws: SEVERE: SEC1113: Exception in LdapRealm when trying to authenticate user. javax.security.auth.login.LoginException: javax.security.auth.login.LoginException: User yyyyyyy not found. at com.sun.enterprise.security.auth.realm.ldap.LDAPRealm.findAndBind(LDAPRealm.java:450)

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• App logicstics & changes due to scope creep

  - by Kevin Brown

  I started an app that was initially a testing platform--user management, and managers that can view their employees tests. Recently, functionality has been extended (not built yet) to allow users to complete a test in place of an employee--basically adding a record, but no user. I have three tables in use for this: users(contains user info for login/security), profiles (all personal info: address, height, etc.), and survey (contains survey answers for user). How do I extend my application to encompass this functionality with minimal change to the structure? I assume that the best way to do this would be to insert records to the tables profiles and survey, and have no username/password/email? There MUST be a user_id associated b/c the tables are linked through the user_ids...

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• How to make a remote connection to a MySQL Database Server?

  - by MLB

  Hello: I am trying to connect to a MySQL database server (remote), but I can't. I am using an user with grant privileges (not root user). The error message is the following: Can't obtain database list from the server. Access denied for user 'myuser'@'mypcname' (using password: YES) "myuser" is an user I created with grant access. This user allows me to connect locally to every database. I am using the same software versions in both hosts: MySQL Server 4.1 (server) and EMS SQL Manager 2005 for MySQL, edition 3.7.0.1 (client). The point is that I need to connect to the remote server using a different user, not root user. So, how to make the connection? Thanks.

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• Is there an implementation of rapid concurrent syntactical sugar in scala? eg. map-reduce

  - by TiansHUo

  Passing messages around with actors is great. But I would like to have even easier code. Examples (Pseudo-code) val splicedList:List[List[Int]]=biglist.partition(100) val sum:Int=ActorPool.numberOfActors(5).getAllResults(splicedList,foldLeft(_+_)) where spliceIntoParts turns one big list into 100 small lists the numberofactors part, creates a pool which uses 5 actors and receives new jobs after a job is finished and getallresults uses a method on a list. all this done with messages passing in the background. where maybe getFirstResult, calculates the first result, and stops all other threads (like cracking a password)

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• jQuery default/placeholder input text and problems with saved information

  - by user318106

  Hey Guys, I'm new to jQuery and have an annoying problem. I have some login fields that are filled with default text when the field is empty and then removed when clicked. My problem is that when the user has their username/password saved (with browser), if they return to the page the login fields are filled with the users saved input as well as the default input. $('#login input.text').each(function(i, field) { field = $(field); if (field.val().length 0) { field.prev().css('display', 'none'); } field.focus(function() { field.prev().css('display', 'none'); }).blur(function() { if (field.val() == '') field.prev().css('display', 'block'); }); })

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• Htaccess... first force www than ask for login

  - by FinalFrag

  I have an .htaccess file that mainly does 2 things. Force www on the domain and ask for login credentials (with .htpasswd). If I now visit domain.com it will ask for a username and password. When I fill them in I get redirected to www.domain.com and then it asks me to log in again. Is there any way to get the www redirection done before the login? I already tried putting the force www code on the top of the .htaccess file.

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• mysql and .net: when using tableadapters I’m getting MySqlException “insert command denied for user”

  - by Deveti Putnik

  Hi! I am using mysql as db for my asp.net application. Here are the facts: I am using connection string from web.config which has both username and password. I can do SELECT with tableadapter. When I am trying to do INSERT with tableadapter, I am getting "mysqlexception insert command denied for user" error When I try to do INSERT programatically, i.e. using connection, command object, etc. everything is fine. In this case, I'm reading connection string from web.config, too. This can be only applied to GoDaddy hosting, but on local machine I don't have this kind of problems. Can anyone suggest what can I do to make it work on GoDaddy hosting? Regards, D

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• Security approach in web application

  - by meep

  Hello everyone. I am designing a web application in ASP.NET / C# where each registered user has the ability to add/modify/delete rows based on their user-id. Take this example: I am going to edit my route on the page /route.aspx?routeid=854 which belongs to me (user-id: 1). But because I am a curious guy I try to access /route.aspx?routeid=855 which belongs to another user (user-id: 2). How can I best avoid people from accessing other peoples data? Should I send each user id (from session) with each database-call, should I validate user/password on every page load or what is the best and most secure approach? I hope I made this clear enough.

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