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  • How do I do MongoDB console-style queries in PHP?

    - by Zoe Boles
    I'm trying to get a MongoDB query from the javascript console into my PHP app. What I'm trying to avoid is having to translate the query into the PHP "native driver"'s format... I don't want to hand build arrays and hand-chain functions any more than I want to manually build an array of MySQL's internal query structure just to get data. I already have a string producing the exact content I want in the Mongo console: db.intake.find({"processed": {"$exists": "false"}}).sort({"insert_date": "1"}).limit(10); The question is, is there a way for me to hand this string, as is, to MongoDB and have it return a cursor with the dataset I request? Right now I'm at the "write your own parser because it's not valid json to kinda turn a subset of valid Mongo queries into the format the PHP native driver wants" state, which isn't very fun. I don't want an ORM or a massive wrapper library; I just want to give a function my query string as it exists in the console and get an Iterator back that I can work with. I know there are a couple of PHP-based Mongo manager applications that apparently take console-style queries and handle them, but initial browsing through their code, I'm not sure how they handle the translation. I absolutely love working with mongo in the console, but I'm rapidly starting to loathe the thought of converting every query into the format the native writer wants...

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  • FFmpeg & Installation on phpmyadmin

    - by Vivek
    I am attempting to have an interface in which people can upload music files and listen to them through the site. The biggest problem obviously is that someone who uploads an audio track in mp3 format into Mozilla wouldn't be able to play it back (since MF doesn't support mp3 playback since I'm using jPlayer). I did some research and found out that I could use command line php using FFmpeg to convert the mp3 to ogg or some other supportable format. I believe I understand (a little bit) how command line php works but I was wondering how I could install it onto phpmyadmin on my hosting service? Could anyone link me to a tutorial or care to explain? I tried googling it but I just couldn't find it.

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  • PHPForm Data Generate PDF & Send to Email?

    - by tom
    I'm a beginner in PHP I was wondering if this is easy to do or if i'd have to outsource this to a programmer - Basically when a user fills in the PHP Form and submits it I need this to generate as a PDF (with all the labels etc) which will then email/attach to MY email and NOT the user who submitted this form. I have looked at tcpdf, fpdi but i dont think any of those scripts allow me to do this specifically as from what i heard it generates a download link for the user, and that is not what i need. If anyone can help me it would be greatly appreciated. Regards Tom

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  • How can I create a dynamic site that is still search-bot friendly?

    - by zuko
    If I want to have a slide effect between pages. You click a link, it is loaded off to the side and then slides in (pushing the old page off the other side). I can imagine using jQuery to do the PHP and the effects... but how do I do something like this that gracefully degrades for users without Javascript, including bots? Possibly more problematic: what if I wanted to have a sort of mural background across the site, perhaps with a parallax scrolling effect, and sliding to other pages reveals more of the, possibly giant image? Again, I can imagine how to do this with lots of fancy jQuery and PHP but it would heavily rely on those. How can I gracefully degrade in a situation like that? Any pointers, articles or books would be greatly appreciated. I keep trying to search for answers but I just get a lot of "theory"-based, unhelpful blogs.

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  • Mod Rewrite not working on my addon domain

    - by Ogugua Belonwu
    have a wordpress website on my main domain For the wordpress website i have this in my .htaccess file # BEGIN WordPress <IfModule mod_rewrite.c> RewriteEngine On RewriteBase / RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule . /index.php </IfModule> # END WordPress I just created an addon domain and wanted to use new rules for it I created a .htaccess file and put it inside the addon folder eg /newaddon In the .htaccess file i have: Options -Indexes <IfModule mod_rewrite.c> RewriteEngine On RewriteBase / RewriteRule ^readjob/(.*)/(.*)/(.*)/$ readjob.php?id=$1&amp;cat=$2&amp;title=$3 </IfModule> The url stucture i have is this: http://www.website.com/readjob/3/jobs/web-designers-potech-integrated-services/ But it keeps telling me link is broken I dont know what to do, pls i need assistance (pls i just learnt mod rewriting today, so clarity will be highly appreciated) Thanks

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  • What web oriented language would work best with binary data?

    - by Qqwy
    I want to create a service where people can upload files. However, since file storage costs money, I want to compress the files so they take less space. I would want to write my own compression algorithm, however, PHP doesn't have good ways to handle binary data (which is needed for many compression algorithms). So I wondered, what would be a better language to create such a website in? I have knowledge of PHP (and Javascript, HTML and CSS) but no experience with other things like Ruby, Perl, Python, and other web development languages.

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  • XMLHttpRequest not working, trying to test database connection [closed]

    - by Frederick Marcoux
    I'm currently creating my own CMS for personnal use but I'm blocked at a code. I'm trying to make a installation script but the AJAX request to test if database works, doesn't work... There's my JS code: function testDB() { "use strict"; var host = document.getElementById('host').value; var username = document.getElementById('username').value; var password = document.getElementById('password').value; var db = document.getElementById('db_name').value; var xmlhttp = new XMLHttpRequest(); var url = "test_db.php"; var params = "host="+host+"&username="+username+"&password="+password+"&db="+db; xmlhttp.open("POST", url, true); xmlhttp.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); xmlhttp.setRequestHeader("Content-length", params.length); xmlhttp.setRequestHeader("Connection", "close"); xmlhttp.send(params); $('#loader').removeAttr('style'); if (xmlhttp.responseText !== '') { if (xmlhttp.readyState===4 && xmlhttp.status===200) { $('#next').removeAttr('disabled'); $('#test').attr('disabled', 'disabled'); $('#test').text('Connection Successful!'); $('#test').addClass('btn-success'); $('#login').addClass('success'); $('#login1').addClass('success'); $('#db').addClass('success'); $('#loader').attr('style', 'display: none;'); } else { $('#next').attr('disabled', 'disabled'); $('#test').removeClass('btn-success'); $('#test').removeAttr('disabled'); $('#test').text('Test Connection'); $('#login').removeClass('success'); $('#login1').removeClass('success'); $('#db').removeClass('success'); $('#loader').attr('style', 'display: none;'); } } else { $('#next').attr('disabled', 'disabled'); $('#next').attr('disabled', 'disabled'); $('#test').removeClass('btn-success'); $('#test').removeAttr('disabled'); $('#test').text('Test Connection'); $('#login').removeClass('success'); $('#login1').removeClass('success'); $('#db').removeClass('success'); $('#loader').attr('style', 'display: none;'); } } And there's my PHP code: <?php $link = mysql_connect($_POST['host'], $_POST['username'], $_POST['password']); if (!$link) { echo ''; } else { if (mysql_select_db($_POST['db'])) { echo 'Connection Successful!'; } else { echo ''; } } mysql_close($link); ?> I don't know why it doesn't work but I tried with JQuery $.ajax, $.get, $.post but nothing work...

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  • Alternative to Instant Form Pro

    - by TechDaddyK
    I was looking for a PHP form generator this morning and ran across "Instant Form Pro" by Joel Comm (http://www.instantformpro.com). It looks like it offers what I'm looking for (easy to use quick form generator based on PHP and MySQL that's self-hosted with no other fees), but the site smacks of "scam." It's being pitched as a way to generate surveys to increase your business, make lots more money, etc. Is this thing worth the $97 or is there an open source alternative that might be... safer?

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  • Share on Facebook does not show thumbnail images

    - by matt74tm
    I have a PHP application which has a "Share on Facebook" button that, On the development server shows the thumbnail images correctly and allows the user to select between them On the live server, it does NOT show the thumbnail images at all. The relevant portion of the .htaccess file is: # Set up caching on media files for 2 days <FilesMatch "\.(gif|jpg|jpeg|png|flv)$"> ExpiresDefault A172800 Header append Cache-Control "public" </FilesMatch> I'm using the exact same set of php files and .htaccess, but the server configuration is different. What could be causing this? Note that the text appears fine. Edit1 We are also doing some URL rewriting related to images in the .htaccess (on both servers): ... RewriteRule ^.*/content/image/(.*)$ content/image/$1 [L] ... RewriteRule ^.*/images/(.*)$ images/$1 [L] ... Would that be somehow making a difference? Images appear fine all throughout the site. (I posted this question earlier as http://stackoverflow.com/questions/4142597/share-on-facebook-does-not-show-thumbnail-images) )

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  • is it possible if callback in array_filter receive parameter ?

    - by justjoe
    i got this multiple array name $files[], who consist keys and values as below : [0] = Array ( [name] = index1.php [path] = http://localhost/php/gettingstarted/ [number] = 1 ) [1] = Array ( [name] = index10.php [path] = http://localhost/php/gettingstarted/ [number] = 2 ) [2] = Array ( [name] = index11.php [path] = http://localhost/php/gettingstarted/ [number] = 3 ) and i use this code to create new array consist of 'name' keys only. but it failed array_filter($files, "is_inarr_key('name')"); function is_inarr_key($array, $key) { //TODO : remove every array except those who got the same $key } and i got this error array_filter() [function.array-filter]: The second argument, 'is_inarr_key('name')', should be a valid callback in C:\xampp\htdocs\php\gettingstarted\index.php on line 15 so the queastion : 1. is it possible to make call-back function on array_filter has ability to receive parameter ? What is general rule of thumb on how to use callback in anyPHP built-in function ?

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  • drupal : How to set separate editing template files for each nodes ?

    - by Thomas John
    Hello guys I have a 3 page drupal(6.20) site, each page has its own template like page-node-1.tpl.php, page-node-2.tpl.php, page-node-3.tpl.php, I would like to set separate templates when editing each node, I tried page-node-1-edit.tpl.php but its not working, but page-node-edit.tpl is working, but its common to all nodes, I need separate editing templates for each node like page-node-1-edit.tpl.php and page-node-2-edit.tpl.php Thanks a lot for your time

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  • How to allow multiple filters to be selected - pagination?

    - by NewSOuser
    Hey, I am still trying to allow multiple filters to be selected for my pagination script but not sure how to do it being very new to php and programing in general. So in my pagination, when a user clicks the 'marketing' button(link) it queries the database just for the category that = marketing. The same goes for the other 2 filter buttons as seen in the script below. (automotive, sports). The problem is, I want to be able to select multiple filters like only marketing and auomotive or automotive and sports, for example if I click the marketing filter and then the automotive, it would display the categories that equal marketing, and automotive. I have no idea how to accomplish this, so I have come to the experts to help me out. This is the script I am working on: <h3>Filter results by:</h3> <a href='pagi_test.php?category=marketing'>marketing</a> <a href='pagi_test.php?category=automotive'>automotive</a> <a href='pagi_test.php?category=sports'>sports</a> <br /> <h3>Results:</h3> <?php //connecting to the database $error = "Could not connect to the database"; mysql_connect('localhost','root','root') or die($error); mysql_select_db('ajax_demo') or die($error); //max displayed per page $per_page = 3; //get start variable $start = $_GET['start']; $category = mysql_real_escape_string($_GET['category']); //count records $record_count = mysql_num_rows(mysql_query("SELECT * FROM explore WHERE category='$category'")); //count max pages $max_pages = $record_count / $per_page; //may come out as decimal if (!$start) $start = 0; //display data $get = mysql_query("SELECT * FROM explore WHERE category='$category' LIMIT $start, $per_page"); ?> <table width="800px"> <?php while ($row = mysql_fetch_assoc($get)) { // get data $id = $row['id']; $site_name = $row['site_name']; $site_description = $row['site_description']; ?> <tr> <td><?php echo $id; ?></td> <td><?php echo $site_name; ?></td> <td><?php echo $site_description; ?></td> </tr> <?php } //setup prev and next variables $prev = $start - $per_page; $next = $start + $per_page; //show prev button if (!($start<=0)) echo "<a href='pagi_test.php?category=$category&start=$prev'>Prev</a> "; //show page numbers //set variable for first page $i=1; for ($x=0;$x<$record_count;$x=$x+$per_page) { if ($start!=$x) echo " <a href='pagi_test.php?category=$category&start=$x'>$i</a> "; else echo " <a href='pagi_test.php?category=$category&start=$x'><b>$i</b></a> "; $i++; } //show next button if (!($start>=$record_count-$per_page)) echo " <a href='pagi_test.php?category=$category&start=$next'>Next</a>"; ?> Any help on this would be great. Thank you. -- EDIT -- If anyone has a better method of doing a pagination system with multiple filters than the one above, please let me know.

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  • Should I Learn C/C++ Even If I Just Want To Do Web Programming?

    - by Daniel
    My goal is to be able to create online apps and dynamic, database driven websites. For instance, if in the future I get the idea for the next Digg or Facebook, I want to be able to code it myself. To arrive there I think I have basically two paths: Path 1 Start at a basic level, learning C, then C++ for OOP, then algorithms and data structures, with the goal of getting a solid grasp of computer programming. Only then move to PHP/MySQL/HTTP and start working on practical programming projects. Path 2 Start directly with PHP/MySQL/HTTP and getting my hands dirty with practical projects right away. What would you guys recommend?

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  • PHP Magic faster than simply setting the class attribute?

    - by Marc Trudel
    Well, not exactly that, but here is an example. Can anyone explain the difference between B and C? How can it be faster to use a magic function to dynamically set a value instead of simply setting the value in the attribute definition? Here is some code: [root@vm-202-167-238-17 ~]# cat test.php; for d in A B C; do echo "------"; ./test.php $d; done; #!/usr/bin/php <?php $className = $argv[1]; class A { public function __get($a) { return 5; } } class B { public $a = 5; } class C { public function __get($a) { $this->a = 5; return 5; } } $a = new $className; $start = microtime(true); for ($i=0; $i < 1000000; $i++) $b = $a->a; $end = microtime(true); echo (($end - $start) * 1000) ." msec\n"; ------ 598.90794754028 msec ------ 205.48391342163 msec ------ 189.7759437561 msec

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  • Looking for a 24 Hour project for multiple languages [closed]

    - by Daan Timmer
    Right two friends and I came up with this idea of having a 24h programming competition. Where we are going to meet at one place and program away for 24hours long. Though we need a 'project'. Something that needs to be made within 24h. Doesn't have to be a real thing, just a nice learning 'thing'. The rules that we setup for ourselves is that the project can be programmed in any language of our own choice. What I know is that one guy is a PHP enthousiastic, we've got a C#/.NET person. And I am quite easy in languages and speak quite a few (PHP/C#.net/C++STL/Python/JavaScript/Java). Anything really language specific is out of the question. Is there anyone who happens to have a great idea for this?

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  • Topics for covering in-depth programming knowledge

    - by black_belt
    I pursued my bachelors' degree in business administration, but my interest in Information Technology led me to acquire some knowledge of PHP programming and MySQL database. I find programming so interesting that I haven't applied for any job since my graduation. Currently I am staying home and just trying to acquire in-depth knowledge of PHP programming. So far I have developed couple of websites and web applications including Inventory+ Point of Sale Software and an Accounting system for small organizations. I aim to have knowledge that a Computer Science graduate should have, and for that I want to read books but I have no idea where to start from. Could you please suggest me some books and topics that I should study on? Thanks a lot :)

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  • What is the impact of a CMS on page load time versus a static site?

    - by PleaseStand
    I am creating a 20-page site that will go on shared hosting. Each page will be about 20 KB (including HTML, CSS, and images common to all pages). To avoid manually adding navigation elements to each page, I am considering using a CMS. However, I am concerned that on a busy server, using a CMS would make the site load more slowly. In a shared hosting environment where PHP is run as a CGI binary, how much does a CMS (WordPress, Drupal, etc.) generally affect page load time, compared to both "plain HTML" static sites and those using PHP as merely a templating language?

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  • How to make categories and current page highlighting in PHP?

    - by Markus Ossi
    I am trying to find some example code or best practices about making CMS-type categories with PHP. This is a problem that has for sure been solved gazillion times but for some reason I am unable to find any example code using PHP about how to implement this. As far as I can tell, there are two parts to the problem. The first one has to with the styling side of things: outputting the link in the navigation so that the current page has a special style (class="active") and to not print out the link for the current page. The second part is handling categories, subcategories and the dynamic pages under the categories. The second part seems pretty straightforward. I am thinking of making it so that the name of the category in the navigation is a link to categories.php?id=x and on this page I just print out the pages with that category id. Then, if the user klicks on a page he will be taken to pages.php?id=y. However, I am not quite sure on how to make a navigation to check if we are now on the current page. Should I just use some case switch or what? Any ideas or links to some good example code are much appreciated.

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  • how to add multiple filters to pagination?

    - by ClarkSKent
    Hey, I am trying to allow multiple filters to be selected for my pagination script. So in my pagination, when a user clicks the 'marketing' button(link) it queries the database just for the category that = marketing. The same goes for the other 2 filter buttons as seen in the script below. (automotive, sports). The problem is, I want to be able to select multiple filters like only marketing and auomotive or automotive and sports, for example if I click the marketing filter and then the automotive, it would display the categories that equal marketing, and automotive. I have no idea how to accomplish this, so I have come to the experts to help me out. This is the script I am working on (I am very new to PHP and programming in general): <h3>Filter results by:</h3> <a href='pagi_test.php?category=marketing'>marketing</a> <a href='pagi_test.php?category=automotive'>automotive</a> <a href='pagi_test.php?category=sports'>sports</a> <br /> <h3>Results:</h3> <?php //connecting to the database $error = "Could not connect to the database"; mysql_connect('localhost','root','root') or die($error); mysql_select_db('ajax_demo') or die($error); //max displayed per page $per_page = 3; //get start variable $start = $_GET['start']; $category = mysql_real_escape_string($_GET['category']); //count records $record_count = mysql_num_rows(mysql_query("SELECT * FROM explore WHERE category='$category'")); //count max pages $max_pages = $record_count / $per_page; //may come out as decimal if (!$start) $start = 0; //display data $get = mysql_query("SELECT * FROM explore WHERE category='$category' LIMIT $start, $per_page"); ?> <table width="800px"> <?php while ($row = mysql_fetch_assoc($get)) { // get data $id = $row['id']; $site_name = $row['site_name']; $site_description = $row['site_description']; ?> <tr> <td><?php echo $id; ?></td> <td><?php echo $site_name; ?></td> <td><?php echo $site_description; ?></td> </tr> <?php } //setup prev and next variables $prev = $start - $per_page; $next = $start + $per_page; //show prev button if (!($start<=0)) echo "<a href='pagi_test.php?category=$category&start=$prev'>Prev</a> "; //show page numbers //set variable for first page $i=1; for ($x=0;$x<$record_count;$x=$x+$per_page) { if ($start!=$x) echo " <a href='pagi_test.php?category=$category&start=$x'>$i</a> "; else echo " <a href='pagi_test.php?category=$category&start=$x'><b>$i</b></a> "; $i++; } //show next button if (!($start>=$record_count-$per_page)) echo " <a href='pagi_test.php?category=$category&start=$next'>Next</a>"; ?>

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  • Finding the right name for an include that is to be executed before HTML output

    - by Pekka
    I am defining naming conventions for a simple plugin framework. For example: index.php - the main plugin file info.php - returns an array with plugin information install.php - self-explanatory can you think of an elegant, short-hand name for a PHP file that contains the code that is to be executed before any HTML is output? Do any examples from other frameworks come to your mind? What I have been thinking of: head.php - misleading, could be mixed up with HTML <head> before_output.php - clumsy, too long init.php - not exactly correct start.php - current favourite

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  • Installing php_apc.dll on wampsever [closed]

    - by dotman14
    I need your help. I'm trying to install php_apc.dll into my php directory. So far this is what i've done: I copied php_apc.dll to c:\wamp\bin\php\php5.3.0\ext. I've also restarted the server several times. But when i checked http://localhost/?phpinfo=1 There wasnt any evidence of APC Extension Installation. Please what i'm i doing wrong? I'll be most delighted with your answers, comments and suggestions. Thank you.

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  • cannot modify header information [closed]

    - by mohanraj
    Possible Duplicate: cannot modify header information Warning: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\register&login\logout.php:1) in C:\xampp\htdocs\register&login\logout.php on line 4 Warning: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\register&login\logout.php:1) in C:\xampp\htdocs\register&login\logout.php on line 5 Warning: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\register&login\logout.php:1) in C:\xampp\htdocs\register&login\logout.php on line 6

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  • Parse error: syntax error, unexpected T_STRING with index.php?

    - by janoChen
    It works perfectly in local host but when I upload it intothe server it has the following error: Parse error: syntax error, unexpected T_STRING in D:\Hosting\4923367\html\beta\index.php on line 4 index.php: <?php include_once 'localization.php'; ?> <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html> <head> <!--Start Kampyle Exit-Popup Code--> <script type="text/javascript"> var k_push_vars = { "view_percentage": 10, "popup_font_color": "#000000", "popup_background": "#D4E2F0", "header": "Your feedback is important to us!", "question": "Would you be willing to give us a short (1 minute) feedback?", "footer": "Thank you for helping us improve our website", "yes": "Yes", "no": "No", "text_direction": "ltr", "images_dir": "http://cf.kampyle.com/", "yes_background": "#76AC78", "no_background": "#8D9B86", "site_code": 9662374 } </script> <script type="text/javascript" src="http://cf.kampyle.com/k_push.js"></script> <!--End Kampyle Exit-Popup Code--> <!-- Start Kampyle Css --> <link rel="stylesheet" type="text/css" media="screen" href="http://cf.kampyle.com/k_button.css" /> <!-- End Kampyle Css --> (continues)

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  • To View multiple uploaded images [closed]

    - by Nilesh Sonawane
    PHP Javascript Image Upload function updatepicture(pic) { document.getElementById("image").setAttribute("src", pic); document.getElementById("image1").setAttribute("src", pic); document.getElementById("image2").setAttribute("src", pic); } Vastu deals Image Upload Upload message will go here. //query for insert timepass.php 0) { if ($_FILES['file']['size'] parent.document.getElementById("message").innerHTML = ""; parent.document.getElementById("file").value = ""; window.parent.updatepicture(""); parent.document.getElementById("message").innerHTML = "There was an error uploading your image. Please try again later."; parent.document.getElementById("message").innerHTML = "Your file is larger than 150kb. Please choose a different picture.";

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  • can I forward "referrer" information to other address?

    - by user5679
    I have two addresses for two servers: www.urlA.com www.urlB.com I have all my websites installed in www.urlB.com, but visitors recognize www.urlA.com primarily. I have www.urlA.com/index.php as the following <?php header('Location: http://www.urlB.com/'); ?> But, when I use this forwarding method, the tracking javascript in www.urlB.com cannot recognize where the visitors are from. I only obtain "NO REFERRING LINK" What should I do to do the following two jobs: 1. to forward urlA.com to urlB.com 2. to receive the referrer information

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