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  • How to keep your unit tests simple and isolated and still guarantee DDD invariants ?

    - by ian31
    DDD recommends that the domain objects should be in a valid state at any time. Aggregate roots are responsible for guaranteeing the invariants and Factories for assembling objects with all the required parts so that they are initialized in a valid state. However this seems to complicate the task of creating simple, isolated unit tests a lot. Let's assume we have a BookRepository that contains Books. A Book has : an Author a Category a list of Bookstores you can find the book in These are required attributes : a book has to have an author, a category and at least a book store you can buy the book from. There's likely to be a BookFactory since it is quite a complex object, and the Factory will initialize the Book with at least all the mentioned attributes. Now we want to unit test a method of the BookRepository that returns all the Books. To test if the method returns the books, we have to set up a test context (the Arrange step in AAA terms) where some Books are already in the Repository. If the only tool at our disposal to create Book objects is the Factory, the unit test now also uses and is dependent on the Factory and inderectly on Category, Author and Store since we need those objects to build up a Book and then place it in the test context. Would you consider this is a dependency in the same way that in a Service unit test we would be dependent on, say, a Repository that the Service would call ? How would you solve the problem of having to re-create a whole cluster of objects in order to be able to test a simple thing ? How would you break that dependency and get rid of all these attributes we don't need in our test ? By using mocks or stubs ? If you mock up things a Repository contains, what kind of mock/stubs would you use as opposed to when you mock up something the object under test talks to or consumes ?

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  • ISBNs are used as primary key, now I want to add non-book things to the DB - should I migrate to EAN

    - by fish2000
    I built an inventory database where ISBN numbers are the primary keys for the items. This worked great for a while as the items were books. Now I want to add non-books. some of the non-books have EANs or ISSNs, some do not. It's in PostgreSQL with django apps for the frontend and JSON api, plus a few supporting python command-line tools for management. the items in question are mostly books and artist prints, some of which are self-published. What is nice about using ISBNs as primary keys is that in on top of relational integrity, you get lots of handy utilities for validating ISBNs, automatically looking up missing or additional information on the book items, etcetera, many of which I've taken advantage. some such tools are off-the-shelf (PyISBN, PyAWS etc) and some are hand-rolled -- I tried to keep all of these parts nice and decoupled, but you know how things can get. I couldn't find anything online about 'private ISBNs' or 'self-assigned ISBNs' but that's the sort of thing I was interested in doing. I doubt that's what I'll settle on, since there is already an apparent run on ISBN numbers. should I retool everything for EAN numbers, or migrate off ISBNs as primary keys in general? if anyone has any experience with working with these systems, I'd love to hear about it, your advice is most welcome.

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  • MySQL: SELECT highest column value when WHERE finds similar entries

    - by Ike
    My question is comparable to this one, but not quite the same. I have a database with a huge amount of books, with different editions of some of the same book titles. I'm looking for an SQL statement giving me the highest edition number of each of the titles I'm selecting with a WHERE clause (to find specific book series). Here's what the table looks like: |id|title |edition|year| |--|-------------------------|-------|----| |01|Serie One Title One |1 |2007| |02|Serie One Title One |2 |2008| |03|Serie One Title One |3 |2009| |04|Serie One Title Two |1 |2001| |05|Serie One Title Three |1 |2008| |06|Serie One Title Three |2 |2009| |07|Serie One Title Three |3 |2010| |08|Serie One Title Three |4 |2011| |--|-------------------------|-------|----| The result I'm looking for is this: |id|title |edition|year| |--|-------------------------|-------|----| |03|Serie One Title One |3 |2009| |04|Serie One Title Two |1 |2001| |08|Serie One Title Three |4 |2011| |--|-------------------------|-------|----| The closest I got was using this statement: select id, title, max(edition), max(year) from books where title like "serie one%" group by name; but it returns the highest edition and year and includes the first id it finds: |--|-----------------------|-------|----| |01|Serie One Title One |3 |2009| |04|Serie One Title Two |1 |2001| |05|Serie One Title Three |4 |2011| |--|-----------------------|-------|----| This fancy join also comes close, but doesn't give the right result: select b.id, b.title, b.edition, b.year from books b inner join (select name, max(edition) as maxedition from books group by title) g on b.edition = g.maxedition where b.title like "serie one%" group by title; Using this I'm getting unique titles, but mostly old editions.

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  • How can I perform this query between related tables without using UNION?

    - by jeremy
    Suppose I have two separate tables that I watch to query. Both of these tables has a relation with a third table. How can I query both tables with a single, non UNION based query? I want the result of the search to rank the results by comparing a field on each table. Here's a theoretical example. I have a User table. That User can have both CDs and books. I want to find all of that user's books and CDs with a single query matching a string ("awesome" in this example). A UNION based query might look like this: SELECT "book" AS model, name, ranking FROM book WHERE name LIKE 'Awesome%' UNION SELECT "cd" AS model, name, ranking FROM cd WHERE name LIKE 'Awesome%' ORDER BY ranking DESC How can I perform a query like this without the UNION? If I do a simple left join from User to Books and CDs, we end up with a total number of results equal to the number of matching cds timse the number of matching books. Is there a GROUP BY or some other way of writing the query to fix this?

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  • Batch processing JDBC

    - by Wai Hein
    I am practicing JDBC batch processing and having errors: error 1: Unsupported feature error 2: Execute cannot be empty or null Property files include: itemsdao.updateBookName = Update Books set bookname = ? where books.id = ? itemsdao.updateAuthorName = Update books set authorname = ? where books.id = ? I know I can execute about DML statements in one update, but I am practicing batch processing in JDBC. Below is my method public void update(Item item) { String query = null; try { connection = DbConnector.getConnection(); property = SqlPropertiesLoader.getProperties("dml.properties"); connection.setAutoCommit(false); if ( property == null ) { Logging.log.debug("dml.properties does not exist. Check property loader or file name is spelled right"); return; } query = property.getProperty("itemsdao.updateBookName"); statement = connection.prepareStatement(query); statement.setString(1, item.getBookName()); statement.setInt(2, item.getId()); statement.addBatch(query); query = property.getProperty("itemsdao.updateAuthorName"); statement = connection.prepareStatement(query); statement.setString(1, item.getAuthorName()); statement.setInt(2, item.getId()); statement.addBatch(query); statement.executeBatch(); connection.commit(); }catch (ClassNotFoundException e) { Logging.log.error("Connection class does not exist", e); } catch (SQLException e) { Logging.log.error("Violating PK constraint",e); } //helper class th finally { DbUtil.close(connection); DbUtil.closePreparedStatement(statement); }

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  • Ordering the results of a Hibernate Criteria query by using information of the child entities of the

    - by pkainulainen
    I have got two entities Person and Book. Only one instance of a specific book is stored to the system (When a book is added, application checks if that book is already found before adding a new row to the database). Relevant source code of the entities is can be found below: @Entity @Table(name="persons") @SequenceGenerator(name="id_sequence", sequenceName="hibernate_sequence") public class Person extends BaseModel { @Id @Column(name = "id") @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "id_sequence") private Long id = null; @ManyToMany(targetEntity=Book.class) @JoinTable(name="persons_books", joinColumns = @JoinColumn( name="person_id"), inverseJoinColumns = @JoinColumn( name="book_id")) private List<Book> ownedBooks = new ArrayList<Book>(); } @Entity @Table(name="books") @SequenceGenerator(name="id_sequence", sequenceName="hibernate_sequence") public class Book extends BaseModel { @Id @Column(name = "id") @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "id_sequence") private Long id = null; @Column(name="name") private String name = null; } My problem is that I want to find persons, which are owning some of the books owned by a specific persons. The returned list of persons should be ordered by using following logic: The person owning most of the same books should be at the first of the list, second person of the the list does not own as many books as the first person, but more than the third person. The code of the method performing this query is added below: @Override public List<Person> searchPersonsWithSimilarBooks(Long[] bookIds) { Criteria similarPersonCriteria = this.getSession().createCriteria(Person.class); similarPersonCriteria.add(Restrictions.in("ownedBooks.id", bookIds)); //How to set the ordering? similarPersonCriteria.addOrder(null); return similarPersonCriteria.list(); } My question is that can this be done by using Hibernate? And if so, how it can be done? I know I could implement a Comparator, but I would prefer using Hibernate to solve this problem.

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  • Renaming a DOMNode in PHP

    - by python
    <?xml version='1.0' encoding='UTF-8' standalone='no'?> <Document xmlns='urn:iso:std:iso:20022:tech:xsd:pain.001.001.02'> <books> <book> <qty>12</qty> <title>C++</title> </book> <book> <qty>21</qty> <title>PHP</title> </book> </books> <books> <book> <qty>25</qty> <title>Java</title> </book> <book> <qty>32</qty> <title>Python</title> </book> <book> <qty>22</qty> <title>History</title> </book> </books> </Document> How Can I Rename ? <Document xmlns='urn:iso:std:iso:20022:tech:xsd:pain.001.001.02'> TO <Document>

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  • Help on MySQL table indexing when GROUP BY is used in a query

    - by Silver Light
    Thank you for your attention. There are two INNODB tables: Table authors id INT nickname VARCHAR(50) status ENUM('active', 'blocked') about TEXT Table books author_id INT title VARCHAR(150) I'm running a query against these tables, to get each author and a count of books he has: SELECT a. * , COUNT( b.id ) AS book_count FROM authors AS a, books AS b WHERE a.status != 'blocked' AND b.author_id = a.id GROUP BY a.id ORDER BY a.nickname This query is very slow (takes about 6 seconds to execute). I have an index on books.author_id and it works perfectly, but I do not know how to create an index on authors table, so that this query could use it. Here is how current EXPLAIN looks: id select_type table type possible_keys key key_len ref rows Extra 1 SIMPLE a ALL PRIMARY,id_status_nickname NULL NULL NULL 3305 Using where; Using temporary; Using filesort 1 SIMPLE b ref key_author_id key_author_id 5 a.id 2 Using where; Using index I've looked at MySQL manual on optimizing queries with group by, but could not figure out how I can apply it on my query. I'll appreciate any help and hints on this - what must be the index structure, so that MySQL could use it?

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  • Making more recent items more likely to be drawn

    - by bobo
    There are a few hundred of book records in the database and each record has a publish time. In the homepage of the website, I am required to write some codes to randomly pick 10 books and put them there. The requirement is that newer books need to have higher chances of getting displayed. Since the time is an integer, I am thinking like this to calculate the probability for each book: Probability of a book to be drawn = (current time - publish time of the book) / ((current time - publish time of the book1) + (current time - publish time of the book1) + ... (current time - publish time of the bookn)) After a book is drawn, the next round of the loop will minus the (current time - publish time of the book) from the denominator and recalculate the probability for each of the remaining books, the loop continues until 10 books have been drawn. Is this algorithm a correct one? By the way, the website is written in PHP. Feel free to suggest some PHP codes if you have a better algorithm in your mind. Many thanks to you all.

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  • South Florida Code Camp 2010 &ndash; VI &ndash; 2010-02-27

    - by Dave Noderer
    Catching up after our sixth code camp here in the Ft Lauderdale, FL area. Website at: http://www.fladotnet.com/codecamp. For the 5th time, DeVry University hosted the event which makes everything else really easy! Statistics from 2010 South Florida Code Camp: 848 registered (we use Microsoft Group Events) ~ 600 attended (516 took name badges) 64 speakers (including speaker idol) 72 sessions 12 parallel tracks Food 400 waters 600 sodas 900 cups of coffee (it was cold!) 200 pounds of ice 200 pizza's 10 large salad trays 900 mouse pads Photos on facebook Dave Noderer: http://www.facebook.com/home.php#!/album.php?aid=190812&id=693530361 Joe Healy: http://www.facebook.com/devfish?ref=mf#!/album.php?aid=202787&id=720054950 Will Strohl:http://www.facebook.com/home.php#!/album.php?aid=2045553&id=1046966128&ref=mf Veronica Gonzalez: http://www.facebook.com/home.php#!/album.php?aid=150954&id=672439484 Florida Speaker Idol One of the sessions at code camp was the South Florida Regional speaker idol competition. After user group level competitions there are five competitors. I acted as MC and score keeper while Ed Hill, Bob O’Connell, John Dunagan and Shervin Shakibi were judges. This statewide competition is being run by Roy Lawsen in Lakeland and the winner, Jeff Truman from Naples will move on to the state finals to be held at the Orlando Code Camp on 3/27/2010: http://www.orlandocodecamp.com/. Each speaker has 10 minutes. The participants were: Alex Koval Jeff Truman Jared Nielsen Chris Catto Venkat Narayanasamy They all did a great job and I’m working with each to make sure they don’t stop there and start speaking at meetings. Thanks to everyone involved! Volunteers As always events like this don’t happen without a lot of help! The key people were: Ed Hill, Bob O’Connell – DeVry For the months leading up to the event, Ed collects all of the swag, books, etc and stores them. He holds meeting with various DeVry departments to coordinate the day, he works with the students in the days  before code camp to stuff bags, print signs, arrange tables and visit BJ’s for our supplies (I go and pay but have a small car!). And of course the day of the event he is there at 5:30 am!! We took two SUV’s to BJ’s, i was really worried that the 36 cases of water were going to break his rear axle! He also helps with the students and works very hard before and after the event. Rainer Haberman – Speakers and Volunteer of the Year Rainer has helped over the past couple of years but this time he took full control of arranging the tracks. I did some preliminary work solicitation speakers but he took over all communications after that. We have tried various organizations around speakers, chair per track, central team but having someone paying attention to the details is definitely the way to go! This was the first year I did not have to jump in at the last minute and re-arrange everything. There were lots of kudo’s from the speakers too saying they felt it was more organized than they have experienced in the past from any code camp. Thanks Rainer! Ray Alamonte – Book Swap We saw the idea of a book swap from the Alabama Code Camp and thought we would give it a try. Ray jumped in and took control. The idea was to get people to bring their old technical books to swap or for others to buy. You got a ticket for each book you brought that you could then turn in to buy another book. If you did not have a ticket you could buy a book for $1. Net proceeds were $153 which I rounded up and donated to the Red Cross. There is plenty going on in Haiti and Chile! I don’t think we really got a count of how many books came in. I many cases the books barely hit the table before being picked up again. At the end we were left with a dozen books which we donated to the DeVry library. A great success we will definitely do again! Jace Weiss / Ratchelen Hut – Coffee and Snacks Wow, this was an eye opener. In past years a few of us would struggle to give some attention to coffee, snacks, etc. But it was always tenuous and always ended up running out of coffee. In the past we have tried buying Dunkin Donuts coffee, renting urns, borrowing urns, etc. This year I actually purchased 2 – 100 cup Westbend commercial brewers plus a couple of small urns (30 and 60 cup we used for decaf). We got them both started early (although i forgot to push the on button on one!) and primed it with 10 boxes of Joe from Dunkin. then Jace and Rachelen took over.. once a batch was brewed they would refill the boxes, keep the area clean and at one point were filling cups. We never ran out of coffee and served a few hundred more than last  year. We did look but next year I’ll get a large insulated (like gatorade) dispensing container. It all went very smoothly and having help focused on that one area was a big win. Thanks Jace and Rachelen! Ken & Shirley Golding / Roberta Barbosa – Registration Ken & Shirley showed up and took over registration. This year we printed small name tags for everyone registered which was great because it is much easier to remember someone’s name when they are labeled! In any case it went the smoothest it has ever gone. All three were actively pulling people through the registration, answering questions, directing them to bags and information very quickly. I did not see that there was too big a line at any time. Thanks!! Scott Katarincic / Vishal Shukla – Website For the 3rd?? year in a row, Scott was in charge of the website starting in August or September when I start on code camp. He handles all the requests, makes changes to the site and admin. I think two years ago he wrote all the backend administration and tunes it and the website a bit but things are pretty stable. The only thing I do is put up the sponsors. It is a big pressure off of me!! Thanks Scott! Vishal jumped into the web end this year and created a new Silverlight agenda page to replace the old ajax page. We will continue to enhance this but it is definitely a good step forward! Thanks! Alex Funkhouser – T-shirts/Mouse pads/tables/sponsors Alex helps in many areas. He helps me bring in sponsors and handles all the logistics for t-shirts, sponsor tables and this year the mouse pads. He is also a key person to help promote the event as well not to mention the after after party which I did not attend and don’t want to know much about! Students There were a number of student volunteers but don’t have all of their names. But thanks to them, they stuffed bags, patrolled pizza and helped with moving things around. Sponsors We had a bunch of great sponsors which allowed us to feed people and give a way a lot of great swag. Our major sponsors of DeVry, Microsoft (both DPE and UGSS), Infragistics, Telerik, SQL Share (End to End, SQL Saturdays), and Interclick are very much appreciated. The other sponsors Applied Innovations (also supply code camp hosting), Ultimate Software (a great local SW company), Linxter (reliable cloud messaging we are lucky to have here!), Mediascend (a media startup), SoftwareFX (another local SW company we are happy to have back participating in CC), CozyRoc (if you do SSIS, check them out), Arrow Design (local DNN and Silverlight experts),Boxes and Arrows (a local SW consulting company) and Robert Half. One thing we did this year besides a t-shirt was a mouse pad. I like it because it will be around for a long time on many desks. After much investigation and years of using mouse pad’s I’ve determined that the 1/8” fabric top is the best and that is what we got!   So now I get a break for a few months before starting again!

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  • How do I Reset Sync Location when rereading a Kindle Book

    - by dan.cramer
    I feel like an idiot but for the life of me I can't find the answer to this question. Whispernet syncs your reading location across all books right? How do you reset that location? If I want to read a book for the second time if I try to sync to the furthest page read it will push me to the last page because that's the furthest I've read. Am I doomed to only read Kindle books once?

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  • ItemSearch totally different from Amazon.com search - What am I doing wrong?

    - by RadiantHex
    I'm using ItemSearch in order to get a list of books ordered by 'salesrank' aka 'bestselling', problem is that the books that pop up for any BrowseNode are totally different from the Amazon list. Test Case Author:"J R R Tolkien", SearchIndex:"Books", Sort:"salesrank" Using the API: J.R.R. Tolkien Boxed Set (The Hobbit and The Lord of the Rings) The Hobbit: 70th Anniversary Edition The Lord of the Rings: 50th Anniversary, One Vol. Edition The Legend of Sigurd and Gudrun The Silmarillion The Lord of the Rings The Children of Hurin The Fellowship of the Ring: Being the First Part of The Lord of the Rings The Return of the King: Being the Third Part of The Lord of the Rings Using Amazon.com Adv. Search: The Lord of the Rings (Trilogy) The Hobbit J.R.R. Tolkien Boxed Set (The Hobbit and The Lord of the Rings) The Legend of Sigurd and Gudrun The Lord of the Rings: 50th Anniversary, One Vol. Edition The Silmarillion The Fellowship of the Ring The Children of Hurin Lord of the Rings, The Return of the King, The (Vol 3) Help would very much appreciated

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  • MySQl Error #1064

    - by 01010011
    Hi, I keep getting this error: MySQL said: #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'INSERT INTO books.book(isbn10,isbn13,title,edition,author_f_name,author_m_na' at line 15 with this query: USE books; DROP TABLE IF EXISTS book; CREATE TABLE `books`.`book`( `book_id` INT UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY, `isbn10` VARCHAR(15) NOT NULL, `isbn13` VARCHAR(15) NOT NULL, `title` VARCHAR(50) NOT NULL, `edition` VARCHAR(50) NOT NULL, `author_f_name` VARCHAR(50) NOT NULL, `author_m_name` VARCHAR(50) NOT NULL, `author_l_name` VARCHAR(50) NOT NULL, `cond` ENUM('as new','very good','good','fair','poor') NOT NULL, `price` DECIMAL(8,2) NOT NULL, `genre` VARCHAR(50) NOT NULL, `quantity` INT NOT NULL) INSERT INTO books.book(isbn10,isbn13,title,edition,author_f_name,author_m_name,author_l_name,cond,price,genre,quantity)** VALUES ('0136061699','978-0136061694','Software Engineering: Theory and Practice','4','Shari','Lawrence','Pfleeger','very good','50','Computing','2'); Any idea what the problem is?

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  • What's the best way to calculate similarity between rows in a table based on association?

    - by André Pena
    Suppose each Person has a collection of favorite Books. So I have a table for: Person Book The association between Person and Book (joint table for MxN) I want to fetch the Persons that are similar to a Person1 based on the favorite Books overlaping. That is: The more books they have in common, the more they are similar. I don't have to use only SQL to solve this problem. I could use programming also. I'm using SQL Server 2008 and C#. What solution would you experts use?

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  • Grouping data in an NSMutable array

    - by padatronic
    Hi guys, I have an array i load with lots of data from an xml file. I am displaying this on a tableview and then when you click on say an author it goes through to display all their books. At the minute my NSMutableArray has an entry for every each book with title, author and so on. So in the table of authors it display the authors name as many times as they have books. I want to group the array data so the table only displays each author once but the author contains an array of his books. Seems simple but I can't find a group method for arrays. thanks peeps

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  • Using LINQ-To-Entities to Generate Information

    - by parminder
    I am working on a website where a user can add tags to their posted books, much like is currently done for questions on Stack Overflow. Classes: Books { bookId, Title } Tags { Id Tag } BooksTags { Id BookId TagId } Here are few sample records. Books BookId Title 113421 A 113422 B Tags Id Tag 1 ASP 2 C# 3 CSS 4 VB 5 VB.NET 6 PHP 7 java 8 pascal BooksTags Id BookId TagId 1 113421 1 2 113421 2 3 113421 3 4 113421 4 5 113422 1 6 113422 4 7 113422 8 Questions I need to write something in LINQ to entity queries which gives me data according to the tags: Query: bookIds where tagid = 1 Returns: bookid: 113421, 113422 Query 2: tags 1 and 2 Returns: 113421 I need tags and their count to to show in related tags, so in first case my related tags class should have following result. RelatedTags Tag Count 2 1 3 1 4 2 8 1 Second Case: RelatedTags Tag Count 3 1 4 1 How do I do this in LINQ?

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  • How to study programming with C language

    - by gurugio
    I am using only C for 5 years. So I am sure that I know C grammer, but I have no idea how to advance programming skills. There are many books for modern languages (such as C++, Java) to study programming skills like the refactoring or pattern, software architecture. But no book is written with C language. The book author say that his/her book is not language-dependent, but I don't think so. How can I advance my programming skills? I have to study modern language and read the books? Are there books about software design or programming skill written with C?

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  • Advanced MySQL Search Help

    - by Brandon
    I've been trying to come up with something for a while now to no avail. My MySQL knowledge is rudimentary at best so I could use some guidance on what I should use for the following: I have 2 tables ('bible' and 'books') that I need to search from. Right now I am just searching 'bible' with the following query: SELECT * FROM bible WHERE text LIKE '%" . $query . "%' ORDER BY likes DESC LIMIT $start, 10 Now, I need to add another part that searches for some pretty advanced stuff. Here is what I want to do in pseudocode which I am aware doesn't work: SELECT * FROM bible WHERE books.book+' '+bible.chapter+':'+bible.verse = '$query' $query would equal something like Genesis 1:2, Genesis coming from books.book, 1 coming from bible.chapter and 2 coming from bible.verse Any help/guidance on this is much appreciated =)

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  • What is the fastest way to learn JPA ?

    - by Jacques René Mesrine
    I'm looking for the best resources (books, frameworks, tutorials) that will help me get up to speed with JPA. I've been happily using iBatis/JDBC for my persistence needs, so I need resources that will hopefully provide comparable functions on how to do things. e.g. how to I set the isolation level for each transaction ? I know there might be 10 books on the topic, so hopefully, your recommendation could narrow down to the best 2 books. Should I start with OpenJPA or are there other opensource JPA frameworks to use ? P.S. Do suggest if I should learn JPA2 or JPA1 ? My goal ultimately is to be able to write a Google App Engine app (which uses JPA1). Thanks Jacque

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  • Save VM properties with EF code first

    - by Julien
    I thought this would be simple but can't find any good examples. public Class BookVm : ImplementsPropertyChanged { public int BookId {get;set;} private bool _favorite; public bool Favorite { get { return _favorite; } set { _favorite = value; OnPropertyChanged("Favorite"); MyDbContext.SaveChanges() // this does not work } } Then in my XAML bound to Book <CheckBox Content="Favorite" IsChecked="{Binding Favorite}" /> How and when do I call SaveChanges() on my DatabaseContext? I don't want to implement a save button. If I intercept the PropertyChange event and call SaveChanges, nothing seems to happen. My object is modified in memory but the database does not see a change. My BookVm class is created on application startup like so: foreach (var book in MyDbContext.Books) Books.Add(book); Where Books is an ObservableCollection<Book> in my MainWindowVm

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  • Help debugging Apache, Passenger and Rails problem

    - by Matt Dressel
    We have an environment running that uses Apache, Passenger and rails. The system is handling most request normally, yet certain requests do not make it to the rails application. For instance, a request to /books is successful, but /books/1 hits apache and passenger, but does not even make it to rails. We set the apache log level to debug and the passenger log level to 3 so that we could monitor all incoming requests. We could see each request coming through and even the /books/1 request is being handled by passenger. But it never gets to rails. Is there any way to determine where the request goes between Passenger and rails or where debugging information might live? Has anyone ever seen any problems with passenger spawning or queuing? We have spawning set to conservative. Also, we have had some permission/ownership problems in the past, so I am not ruling this out yet. Thanks in advance

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  • Propel: How the "Affected Rows" Returned from doUpdate is defined

    - by Ngu Soon Hui
    In propel there is this doUpdate function, that will return the numbers of affected rows by this query. The question is, if there is no need to update the row ( because the set value is already the same as the field value), will those rows counted as the affected row? Take for example, I have the following table: ID | Name | Books 1 | S1oon | Me 2 | S1oon | Me Let's assume that I write a ORM function of the equivalent of the following query: update `new table` set Books='Me' where Name='S1oon'; What will the doUpdate result return? Will it return 0 ( because all the Books column are already Me, hence there is no need to update), or will it be 2 ( because there are 2 rows that fulfill the where condition) ?

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  • Select an entity according to a list of associated entities

    - by Maverickch
    I have the following database schema : Two tables, books and tags, with n-m relationship. Books - Tags We can have for example the book 1, with tags {A,B,C}, and book 2, with tags {A}. I would like to select the books according to a list of tags. For example : selected tags list : {A,B} - book 1 My idea was to use the MINUS SQL function, to subtract book tags list to the selected tags list, and return the book if the list was empty. Unfortunately, this SQL function is not supported by HQL. Any idea about that ?

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  • Med-PC Programing Language

    - by mknuii
    There's this programing language called Med-PC that works with animal behavior. I'm trying to learn a bit about it, but i can't seem to find any kind of books or material about it. I've "google it" but all i seem to find are some references about it and a PDF explaining the installing of the program itself and sensors(for the experiments), not actual programing instructions. I'm looking for some kind of guidance, documents or books, some kind of reference where i can improve and learn about this language, or if it is based on some other language. I just need some reference about it. So i've resorted to StackOverFlow to see if anybody has worked, knows about it or can point me some links/books about it.

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  • Why did the following linq to sql query generate a subquery?

    - by Xaisoft
    I did the following query: var list = from book in books where book.price > 50 select book; list = list.Take(50); I would expect the above to generate something like: SELECT top 50 id, title, price, author FROM Books WHERE price > 50 but it generates: SELECT [Limit1].[C1] as [C1] [Limit1].[id] as [Id], [Limit1].[title] as [title], [Limit1].[price] as [price], [Limit1].[author] FROM (SELECT TOP (50) [Extent1].[id] as as [Id], [Extent1].[title] as [title], [Extent1].[price] as [price], [Extent1].[author] as [author] FROM Books as [Extent1] WHERE [Extent1].[price] > 50 ) AS [Limit1] Why does the above linq query generate a subquery and where does the C1 come from?

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