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  • Django Formset management-form validation error

    - by gramware
    I have a form and a formset on my template. The problem is that the formset is throwing validation error claiming that the management form is "missing or has been tampered with". Here is my view @login_required def home(request): user = UserProfile.objects.get(pk=request.session['_auth_user_id']) blogz = list(blog.objects.filter(deleted='0')) delblog = modelformset_factory(blog, exclude=('poster','date' ,'title','content')) if request.user.is_staff== True: staff = 1 else: staff = 0 staffis = 1 if request.method == 'POST': delblogformset = delblog(request.POST) if delblogformset.is_valid(): delblogformset.save() return HttpResponseRedirect('/home') else: delblogformset = delblog(queryset=blog.objects.filter( deleted='0')) blogform = BlogForm(request.POST) if blogform.is_valid(): blogform.save() return HttpResponseRedirect('/home') else: blogform = BlogForm(initial = {'poster':user.id}) blogs= zip(blogz,delblogformset.forms) paginator = Paginator(blogs, 10) # Show 25 contacts per page # Make sure page request is an int. If not, deliver first page. try: page = int(request.GET.get('page', '1')) except ValueError: page = 1 # If page request (9999) is out of range, deliver last page of results. try: blogs = paginator.page(page) except (EmptyPage, InvalidPage): blogs = paginator.page(paginator.num_pages) return render_to_response('home.html', {'user':user, 'blogform':blogform, 'staff': staff, 'staffis': staffis, 'blog':blogs, 'delblog':delblogformset}, context_instance = RequestContext( request )) my template {%block content%} <h2>Home</h2> {% ifequal staff staffis %} {% if form.errors %} <ul> {% for field in form %} <H3 class="title"> <p class="error"> {% if field.errors %}<li>{{ field.errors|striptags }}</li>{% endif %}</p> </H3> {% endfor %} </ul> {% endif %} <h3>Post a Blog to the Front Page</h3> <form method="post" id="form2" action="" class="infotabs accfrm"> {{ blogform.as_p }} <input type="submit" value="Submit" /> </form> <br> <br> {% endifequal %} <div class="pagination"> <span class="step-links"> {% if blog.has_previous %} <a href="?page={{ blog.previous_page_number }}">previous</a> {% endif %} <span class="current"> Page {{ blog.number }} of {{ blog.paginator.num_pages }}. </span> {% if blog.has_next %} <a href="?page={{ blog.next_page_number }}">next</a> {% endif %} </span> <form method="post" action="" class="usertabs accfrm"> {{delblog.management_form}} {% for b, form in blog.object_list %} <div class="blog"> <h3>{{b.title}}</h3> <p>{{b.content}}</p> <p>posted by <strong>{{b.poster}}</strong> on {{b.date}}</p> {% ifequal staff staffis %}<p>{{form.as_p}}<input type="submit" value="Delete" /></p>{% endifequal %} </div> {% endfor %} </form> {%endblock%}

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  • Unit Testing a Django Form with a FileField

    - by Jason Christa
    I have a form like: #forms.py from django import forms class MyForm(forms.Form): title = forms.CharField() file = forms.FileField() #tests.py from django.test import TestCase from forms import MyForm class FormTestCase(TestCase) def test_form(self): upload_file = open('path/to/file', 'r') post_dict = {'title': 'Test Title'} file_dict = {} #?????? form = MyForm(post_dict, file_dict) self.assertTrue(form.is_valid()) How do I construct the *file_dict* to pass *upload_file* to the form?

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  • Simulate Form Post in PHP

    - by Aakash
    I have an HTML form (form action="https:..." method="post"). I want to handle the post in PHP. How do I simulate the form post in PHP? So, instead, I will have (form action="helper.php") a and helper.php will post the form data.

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  • Python Mechanize select a form with no name

    - by mvid
    I am attempting to have mechanize select a form from a page, but the form in question has no "name" attribute in the html. What should I do? when I try to use br.select_form(name = "") i get errors that no form is declared with that name, and the function requires a name input. There is only one form on the page, is there some other way I can select that form?

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  • C# Adding Items To A Windows Form

    - by Soo
    I built a little console application in C# and need to add a windows form interface to it. I added a form item, and now have a blank form. I don't know how to go from here and start adding buttons and menus to the form. Is there a form design toolbar or do I have to add buttons and menus using code?

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  • Mechanize complex form input name

    - by ADAM
    Hi there i am trying to access a form in mechanize with ugly characters in the object name similar to this agent = Mechanize.new page = agent.get('http://domain.com) form = page.forms[0] form.ct600$Main$LastNameTextBox = "whatever" page = agent.submit(form) The problem is the $ in the html name is messing with ruby because Is there another method i could use ie: form.element_by_name("ct600$Main$LastNameTextBox") = "whatever" Unfortunately i cant change the html

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  • Slow form submission.

    - by Tony
    When I submit a form, I can see my browser's progress bar slowly increased, it takes 4-6s to submit a form. It was a generic form like : <form id="someid" name="someName" action="someAction.do"> ... </form> I test it in IE8 and Firefox 3,both are very slow. My network condition is fine, my server works great. What could be the problem?

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  • Aligning Form in Visual Studio 2005

    - by patrick
    I am trying to add functionality to a form in Visual Studio 2005 that extends the form to the left. However, I am unable to figure out how to change the top and left alignment of he form in the form designer. There has to be a way to change the alignment of a form in the designer, right?

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  • Looping through array in PHP to post several multipart form-data

    - by Léon Pelletier
    I'm trying in an asp web application to code a function that would loop through a list of files in a multiple upload form and send them one by one. Is this something that can be done in ASP? Because I've read some posts about how to attach several files together, but saw nothing about looping through the files. I can easily imagine it in C# via HttpWebRequest or with socket, but in php, I guess there are already function designed to handle it? // This is false/pseudo-code :) for (int index = 0; index < number_of_files; index++) { postfile(file[index]); } And in each iteration, it should send a multipart form-data POST. postfile(TheFileInfos) should make a POST like it: POST /afs.aspx?fn=upload HTTP/1.1 [Header stuff] Content-Type: multipart/form-data; boundary=----------Ef1Ef1cH2Ij5GI3ae0gL6KM7GI3GI3 [Header stuff] ------------Ef1Ef1cH2Ij5GI3ae0gL6KM7GI3GI3 Content-Disposition: form-data; name="Filename" myimage1.png ------------Ef1Ef1cH2Ij5GI3ae0gL6KM7GI3GI3 Content-Disposition: form-data; name="fileid" 58e21ede4ead43a5201206101806420000007667212251 ------------Ef1Ef1cH2Ij5GI3ae0gL6KM7GI3GI3 Content-Disposition: form-data; name="Filedata"; filename="myimage1.png" Content-Type: application/octet-stream [Octet Stream] [Edit] I'll try it: <html> <head> <title>Untitled Document</title> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"> </head> <body> <form name="form1" enctype="multipart/form-data" method="post" action="processFiles.php"> <p> <? // start of dynamic form $uploadNeed = $_POST['uploadNeed']; for($x=0;$x<$uploadNeed;$x++){ ?> <input name="uploadFile<? echo $x;?>" type="file" id="uploadFile<? echo $x;?>"> </p> <? // end of for loop } ?> <p><input name="uploadNeed" type="hidden" value="<? echo $uploadNeed;?>"> <input type="submit" name="Submit" value="Submit"> </p> </form> </body> </html>

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  • information need to display below in Form using Swing

    - by vamshikpd
    Hi All, I am using SunJavaStudio Enterprise 8 , using swing framework I created form,In form I added Jlable,JFormattedTextfield,Jpanle1,Jpanel2 and Jpanel3 in order wise.I am using GridBag layout.Above order displayed in form first line onwards, I want , In Form ,above will some gap and middle layer display the added fields . how to arrange the Form? Please help me,its urgent

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  • Django Form field initial value on failed validation

    - by John
    Hi, how do I set the value of a field element after a form has been submitted but has failed validation? e.g. if form.is_valid(): form.save() else: form.data['my_field'] = 'some different data' I don't really want to put it in the view though and would rather have it as part of the form class. Thanks

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  • FORM TIPS with jquery or other library

    - by xRobot
    This is a form validation for jquery: http://www.position-absolute.com/articles/jquery-form-validator-because-form-validation-is-a-mess/ I need something like that but the tips has to appear when I select the input text form by clicking on it and has to dissapear when I select another input text form. Is there a way to do this with jquery, mootools, scriptaculus or any other library ? Thanks ^_^

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  • filling a form with parameter already selected using ajax

    - by kawtousse
    hi every one, My goal untill now is to fill a form with values from a table (html table). it is a kind of refreshing the form. so the user who wants to modify the html table through the form must prefill the form with values wich he already selected. I used the DOM to acces to each row and cell in the table and i used ajax to pass parameter to other jsp. but Iam confused what shall be the next step to fill the form.

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  • How to configure a shortcut for an SSH connection through a SSH tunnel

    - by Simone Carletti
    My company production servers (FOO, BAR...) are located behind two gateway servers (A, B). In order to connect to server FOO, I have to open a ssh connection with server A or B with my username JOHNDOE, then from A (or B) I can access any production server opening a SSH connection with a standard username (let's call it WEBBY). So, each time I have to do something like: ssh johndoe@a ... ssh webby@foo ... # now I can work on the server As you can imagine, this is a hassle when I need to use scp or if I need to quickly open multiple connections. I have configured a ssh key and also I'm using .ssh/config for some shortcuts. I was wondering if I can create some kind of ssh configuration in order to type ssh foo and let SSH open/forward all the connections for me. Is it possible? Edit womble's answer is exactly what I was looking for but it seems right now I can't use netcat because it's not installed on the gateway server. weppos:~ weppos$ ssh foo -vv OpenSSH_5.1p1, OpenSSL 0.9.7l 28 Sep 2006 debug1: Reading configuration data /Users/xyz/.ssh/config debug1: Applying options for foo debug1: Reading configuration data /etc/ssh_config debug2: ssh_connect: needpriv 0 debug1: Executing proxy command: exec ssh a nc -w 3 foo 22 debug1: permanently_drop_suid: 501 debug1: identity file /Users/xyz/.ssh/identity type -1 debug2: key_type_from_name: unknown key type '-----BEGIN' debug2: key_type_from_name: unknown key type 'Proc-Type:' debug2: key_type_from_name: unknown key type 'DEK-Info:' debug2: key_type_from_name: unknown key type '-----END' debug1: identity file /Users/xyz/.ssh/id_rsa type 1 debug2: key_type_from_name: unknown key type '-----BEGIN' debug2: key_type_from_name: unknown key type 'Proc-Type:' debug2: key_type_from_name: unknown key type 'DEK-Info:' debug2: key_type_from_name: unknown key type '-----END' debug1: identity file /Users/xyz/.ssh/id_dsa type 2 bash: nc: command not found ssh_exchange_identification: Connection closed by remote host

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  • reaching 99.9999% uptime

    - by user35204
    I am currently developing a project which is mission-critical. The actual domain name is registered with 1 & 1 and I plan on purchasing DynDNS Custom DNS service (which has 5 different geographical locations for DNS) and then another secondary DNS service to make sure my DNS is as failover safe as possible. Does it matter that the registration is with 1 & 1 - are they a weak link in the chain? All I really use them for is to say that DynDNS is my primary DNS nameserver and then my secondary DNS is my other nameserver. I can transfer the registration to DynDNS - Im just not sure if it really matters or not. Thanks

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  • How come I can't redirect TCP ports on this wireless router?

    - by George Edison
    I am configuring a router to redirect TCP port 5900 (yes, this is for VNC) to a specific IP address on the network. Here is what I have: From a local computer on the same network, I can telnet to 192.168.1.64 (port 5900) just fine. However, when trying to telnet to the machine (port 5900) using its external IP address, it doesn't work. (The connection times out.) The router is a Gigaset SE567, if that helps.

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  • 100% uptime for a web application

    - by Chris Lively
    We received an interesting "requirement" from a client today. They want 100% uptime with off-site failover on a web application. From our web application's viewpoint, this isn't an issue. It was designed to be able to scale out across multiple database servers, etc. However, from a networking issue I just can't seem to figure out how to make it work. In a nutshell, the application will live on servers within the client's network. It is accessed by both internal and external people. They want us to maintain an off-site copy of the system that in the event of a serious failure at their premises would immediately pick up and take over. Now we know there is absolutely no way to resolve it for internal people (carrier pigeon?), but they want the external users to not even notice. Quite frankly, I haven't the foggiest idea of how this might be possible. It seems that if they lose Internet connectivity then we would have to do a DNS change to forward traffic to the external machines... Which, of course, takes time. Ideas? UPDATE I had a discussion with the client today and they clarified on the issue. They stuck by the 100% number, saying the application should stay active even in the event of a flood. However, that requirement only kicks in if we host it for them. They said they would handle the uptime requirement if the application lives entirely on their servers. You can guess my response.

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  • What should I do about this user?

    - by Tim Brigham
    What should I do about this user? The user is: Downloading pornography Attempting unauthorized access Running hacking software Sending unsolicited email Installing software / tampering with the system etc This is intended as a generic answer for employee behavioral problems, a la Can you help me with my software licensing question? I could see where acceptable use issues are a touch out of scope for SF, however it is one of those things most sysadmins will run into. I don't want to keep rewriting similar answers.

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  • Persisting Session Between Different Browser Instances

    - by imran_ku07
        Introduction:          By default inproc session's identifier cookie is saved in browser memory. This cookie is known as non persistent cookie identifier. This simply means that if the user closes his browser then the cookie is immediately removed. On the other hand cookies which stored on the user’s hard drive and can be reused for later visits are called persistent cookies. Persistent cookies are less used than nonpersistent cookies because of security. Simply because nonpersistent cookies makes session hijacking attacks more difficult and more limited. If you are using shared computer then there are lot of chances that your persistent session will be used by other shared members. However this is not always the case, lot of users desired that their session will remain persisted even they open two instances of same browser or when they close and open a new browser. So in this article i will provide a very simple way to persist your session even the browser is closed.   Description:          Let's create a simple ASP.NET Web Application. In this article i will use Web Form but it also works in MVC. Open Default.aspx.cs and add the following code in Page_Load.    protected void Page_Load(object sender, EventArgs e)        {            if (Session["Message"] != null)                Response.Write(Session["Message"].ToString());            Session["Message"] = "Hello, Imran";        }          This page simply shows a message if a session exist previously and set the session.          Now just run the application, you will just see an empty page on first try. After refreshing the page you will see the Message "Hello, Imran". Now just close the browser and reopen it or just open another browser instance, you will get the exactly same behavior when you run your application first time . Why the session is not persisted between browser instances. The simple reason is non persistent session cookie identifier. The session cookie identifier is not shared between browser instances. Now let's make it persistent.          To make your application share session between different browser instances just add the following code in global.asax.    protected void Application_PostMapRequestHandler(object sender, EventArgs e)           {               if (Request.Cookies["ASP.NET_SessionIdTemp"] != null)               {                   if (Request.Cookies["ASP.NET_SessionId"] == null)                       Request.Cookies.Add(new HttpCookie("ASP.NET_SessionId", Request.Cookies["ASP.NET_SessionIdTemp"].Value));                   else                       Request.Cookies["ASP.NET_SessionId"].Value = Request.Cookies["ASP.NET_SessionIdTemp"].Value;               }           }          protected void Application_PostRequestHandlerExecute(object sender, EventArgs e)        {             HttpCookie cookie = new HttpCookie("ASP.NET_SessionIdTemp", Session.SessionID);               cookie.Expires = DateTime.Now.AddMinutes(Session.Timeout);               Response.Cookies.Add(cookie);         }          This code simply state that during Application_PostRequestHandlerExecute(which is executed after HttpHandler) just add a persistent cookie ASP.NET_SessionIdTemp which contains the value of current user SessionID and sets the timeout to current user session timeout.          In Application_PostMapRequestHandler(which is executed just before th session is restored) we just check whether the Request cookie contains ASP.NET_SessionIdTemp. If yes then just add or update ASP.NET_SessionId cookie with ASP.NET_SessionIdTemp. So when a new browser instance is open, then a check will made that if ASP.NET_SessionIdTemp exist then simply add or update ASP.NET_SessionId cookie with ASP.NET_SessionIdTemp.          So run your application again, you will get the last closed browser session(if it is not expired).   Summary:          Persistence session is great way to increase the user usability. But always beware the security before doing this. However there are some cases in which you might need persistence session. In this article i just go through how to do this simply. So hopefully you will again enjoy this simple article too.

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  • Removing existing filtered pages from Google's index: noindex / 301 / canonical to non-filtered page?

    - by Noam
    I've decided to remove some of my site's pages from the Google index to focus more of the indexed pages on higher quality pages. The pages I'm going to remove are already in the index. These removed pages are filtered pages which will continue to exist, I just don't want them in the google index because they add little quality to the same page without any filter selected. I've added in webmaster tools specification of narrow for the parameters that set these filters, but it doesn't seem this changes anything in how he handles these pages. So I'm considering three options: Adding <meta name="robots" content="noindex" /> to the html header of these filtered pages 301 to the non-filtered page that contains the most similar information and will remain in the index Canonical tag. Which I'm not sure is exactly the mainstream use case, as these aren't really the same pages. Which should I use?

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  • Canonical détaille ses plans pour le support de l'UEFI Secure Boot, GRUB 2 ne sera plus utilisé par défaut sur les futures versions d'Ubuntu

    Canonical détaille ses plans pour le support de l'UEFI Secure Boot GRUB 2 ne sera plus utilisé par défaut sur les futures versions d'Ubuntu Pour son futur système d'exploitation Windows 8, Microsoft a opté pour l'utilisation de l'UEFI ( Unified Extensible Firmware Interface) en remplacement du BIOS. Les constructeurs désireux de proposer des dispositifs sous l'OS seront donc obligés de passer à l'UEFI, avec une activation par défaut de la fonction Secure Boot. Cette fonctionnalité de sécurité offrira au système d'exploitation un processus de démarrage signé et mesuré, qui aide à protéger le PC en détectant les logiciels malveillants au démarrage, et en empêchant le chargement de c...

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  • Ajax call from a form rendered as Ajax response (jQuery + Grails: chaining ajax requests)

    - by bsreekanth
    Hello, I was expecting the below scenario common, but couldn't find much help online. I have a form loaded through Ajax (say, create entity form). It is loaded through a button click (load) event $("#bt-create").click(function(){ $ ('#pid').load('/controller/vehicleModel/create3'); return false; }); the response (a form) is written in to the pid element. The name and id of the form is ajax-form, and the submit event is attached to an ajax post request $(function() { $("#ajax-form").submit(function(){ // do something... var url = "/app/controller/save" $.post(url, $(this).serialize(), function(data) { alert( data ) ; /// alert data from server }); I could make the above ajax operations individually. That is the ajax post operation succeeds if it calls from a static html file. But if I chain the requests (after completing the first), so that it calls from the output form generated by the first request, nothing happens. I could see the post method is called through firebug. Is there a better way to handle above flow? One more interesting thing I noticed. As you could see, I use grails as my platform. If I keep the javascripts in the main.gsp (master layout), the submit event would not register as the breakpoint is not hit in firebug. But, if I define the javascript in the template file (which renders the form above), the breakpoint is hit, but as I explained, the action is not called at the controller. I changes the javascript to the head section but same result. any help greatly appreciated. thanks, Babu.

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