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  • Default FileField names for Django files

    - by Adam Nelson
    I have a model: class Example(models.Model): unique_hash = models.CharField(max_length=32,unique=True) content = models.FileField(upload_to='source',blank=True,verbose_name="HTML Content File") I would like to be able to set the content filename to default to a callable, but I don't see any way to have the callable reference unique_hash (or vice versa). Is this possible?

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  • How to retrieve items from a django queryset?

    - by sharataka
    I'm trying to get the video element in a queryset but am having trouble retrieving it. user_channel = Everything.objects.filter(profile = request.user, playlist = 'Channel') print user_channel[0] #returns the first result without error print user_channel[0]['video'] #returns error Models.py: class Everything(models.Model): profile = models.ForeignKey(User) playlist = models.CharField('Playlist', max_length = 2000, null=True, blank=True) platform = models.CharField('Platform', max_length = 2000, null=True, blank=True) video = models.CharField('VideoID', max_length = 2000, null=True, blank=True) video_title = models.CharField('Title of Video', max_length = 2000, null=True, blank=True) def __unicode__(self): return u'%s %s %s %s %s' % (self.profile, self.playlist, self.platform, self.video, self.video_title)

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  • Django menu item sorting

    - by doktorno
    Hi i've got MenuItem model : MenuItem(models.Model) name=models.CharField(max_length=50) url = models.URLField() position = models.IntegerField() Class Meta: ordering =['position'] then i'm retriving it by MenuItem.objects.all() My question is how can i make any user friendly interface in admin panel to allow sorting MenuItems - for example list with + and - buttons to move MenuItem up and down ....

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  • Django: common template subsections

    - by Parand
    What's a good way to handle commonly occurring subsections of templates? For example, there is a sub-header section that's used across 4 different pages. The pages are different enough to not work well with template inheritance (ie. "extends" doesn't fit well). Is "include" the recommended method here? It feels a bit heavyweight, requiring each subsection or snippet to be in its own file. Are there any performance issues in using include or is it smart about forming template from the subsections (ie. if I make extensive use of it, do I pay any penalties)? I think what I'm looking for is something like template tags, but without the programming - a simple way to create a library of html template tags I can sprinkle in other templates.

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  • Django Find Out if User is Authenticated in Custom Tag

    - by greggory.hz
    I'm trying to create a custom tag. Inside this custom tag, I want to be able to have some logic that checks if the user is logged in, and then have the tag rendered accordingly. This is what I have: def user_actions(context): request = template.Variable('request').resolve(context) return { 'auth': request['user'].is_athenticated() } register.inclusion_tag('layout_elements/user_actions.html', takes_context=True)(user_actions) When I run this, I get this error: Caught VariableDoesNotExist while rendering: Failed lookup for key [request] in u'[{}]' The view that renders this ends like this: return render_to_response('start/home.html', {}, context_instance=RequestContext(request)) Why doesn't the tag get a RequestContext object instead of the Context object? How can I get the tag to receive the RequestContext instead of the Context? EDIT: Whether or not it's possible to get a RequestContext inside a custom tag, I'd still be interested to know the "correct" or best way to determine a user's authentication state from within the custom tag. If that's not possible, then perhaps that kind of logic belongs elsewhere? Where?

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  • django overwrite form clean method

    - by John
    Hi, When overwriting a form clean method how do you know if its failed validation on any of the fields? e.g. in the form below if I overwrite the clean method how do I know if the form has failed validation on any of the fields? class PersonForm(forms.Form): title = Forms.CharField(max_length=100) first_name = Forms.CharField(max_length=100) surname = Forms.CharField(max_length=100) password = Forms.CharField(max_length=100) def clean(self, value): cleaned_data = self.cleaned_data IF THE FORM HAS FAILED VALIDATION: self.data['password'] = 'abc' raise forms.ValidationError("You have failed validation!") ELSE: return cleaned_data Thanks

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  • I want to select the distict value from models field and then update them (django)

    - by qulzam
    I have models... class Item(models.Model): name = models.CharField('Item Name', max_length = 30) item_code = models.CharField(max_length = 10) color = models.CharField(max_length = 150, null = True, blank = True) size = models.CharField(max_length = 30, null = True, blank = True) fabric_code = models.CharField(max_length = 30, null = True, blank = True) I have values in Item. in Item model name field has the similar values..(but the other values of record are change). I want to select the name field values distinctly(ie similar values select only ones). in one box(like combo box). What kind of form or views i use??

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  • How do I set prifix to django contrib tables names?

    - by Software Enthusiastic
    HI One of my requirement is to have prefix on all the tables of the django based project (Because db is hosted on shared server). I have used db_table Meta option to set the prefix for the tables which I have created. Now my query is how do I set the prefix for tables provided by django.contrib. Instead of auth_group django should create prefix_auth_group.... How do I do that? Thank you very much...

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  • reverse many to many fields in Django + count them

    - by cleliodpaula
    I'm trying to figure out how to solve this class Item(models.Model): type = models.ForeignKey(Type) name = models.CharField(max_lenght = 10) ... class List(models.Model): items = models.ManyToManyField(Item) ... I want to count how many an Item appears in another Lists, and show on template. view def items_by_list(request, id_): list = List.objects.get(id = id_) qr = list.items.all() #NOT TESTED num = [] i = 0 for item in qr: num[i] = List.objects.filter(items__id = item__id ).count() #FINISH NOT TESTED c = {} c.update(csrf(request)) c = {'request':request, 'list' : qr, 'num' : num} return render_to_response('items_by_list.html', c, context_instance=RequestContext(request)) template {% for dia in list %} <div class="span4" > <div> <h6 style="color: #9937d8">{{item.type.description}}</h6> <small style="color: #b2e300">{{ item.name }}</small> <small style="color: #b2e300">{{COUNT HOW MANY TIMES THE ITEM APPEAR ON OTHER LISTS}}</small> </div> {% endfor %} This seems to be easy, but I could not implement yet. If anyone has some glue to me, please help me. Thanks in advance.

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  • Django template CSS/IMG is "off" in the URL

    - by erimar77
    I have /path/to/my/theme/static/css/frontend.css which is called by base.html <link rel="stylesheet" type="text/css" href="{{ STATIC_URL }}css/frontend.css" media="all" /> In which I've got a background for the header: #header-wrapper min-width: 960px; height: 150px; background: transparent url(img/header-bg.png) repeat-x center bottom; } The file is /path/to/my/theme/static/img I've run manage.py collectstatic to gather the files and almost everything looks correct except the link generated looks like: http://example.com/static/css/img/header-bg.png In which the image does not show, because the correct URL is: http://example.com/static/img/header-bg.png Where am I going wrong??

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  • django flatpage redirects

    - by Joe
    I want to make sure all of my flatpages have the "www" subdomain and redirect to it if they don't. I've looked at some middlewares that redirect to www, but 1. they usually redirect all urls to www and 2. the ones I've found don't work with flatpages. I don't want all of my site urls to redirect to include the www subdomian, just the flatpages. Anyone know how I should go about doing this? Thanks

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  • Django forms: prepopulate form with request.user and url parameter

    - by Malyo
    I'm building simple Course Management App. I want Users to sign up for Course. Here's sign up model: class CourseMembers(models.Model): student = models.ForeignKey(Student) course = models.ForeignKey(Course) def __unicode__(self): return unicode(self.student) Student model is extended User model - I'd like to fill the form with request.user. In Course model most important is course_id, which i'm passing into view throught URL parameter (for example http://127.0.0.1:8000/courses/course/1/). What i want to achieve, is to generate 'invisible' (so user can't change the inserted data) form with just input, but containing request.user and course_id parameter.

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  • Permission to view, but not to change! - Django

    - by RadiantHex
    Hi folks, is it possible to give users the permission to view, but not to change or delete. currently in the only permissions I see are "add", "change" and "delete"... but there is no "read/view" in there. I really need this as some users will only be able to consult the admin panel, in order to see what has been added in. Help would be amazing!

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  • How to loop X times in Django?

    - by Mark
    I have user reviews on my site. Each review has a rating of 1-5 stars. I want to print that many stars. How do I do it? I only see {% for X in Y %} which lets you iterate over a list, but not a certain number of times.

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  • Django model data consistency

    - by Mark
    When creating a form, you can define a bunch of methods, clean_xyz, to make sure the data gets forced into the correct format. Is there any way to do this on a model level? Perhaps I can override the field setters somehow? I want it so that if I write something like my_address.postal_code = 'a1b2c3' It will automatically get formatted into A1B 2C3. Perhaps throw an exception if it can't be converted. That way I know I'll never have any malformed data in the database.

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  • Postfix on IspCP cannot send to google apps mail if it is in the same domain

    - by Evan Sap
    In my vps setup I have ispcp omega 1.0.7 installed. Everything works fine except the fact that postfix cannot send to google apps mail when the domain of google apps is also registered in ispcp. Postfix sends an email to normal addresses (hotmail, yahoo, gmail etc). I use external dns. There is also a discussion I started in the ispcp forum here .mail.log file provides these messages: mail for exampledomain.gr loops back to myself". postfix/bounce: sender non-delivery notification. postfix/qmgr: removed Any help would be appreciated.

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  • Apache mod_wsgi error: ImportError: No module named django.core.handlers.wsgi

    - by bigmac
    I am using Python 2.7 with mod_python 3.3.1 and mod_wsgi 3.3. I get an Internal Server Error and this stack trace in the apache logs: [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] import django.core.handlers.wsgi [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] ImportError: No module named django.core.handlers.wsgi [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] mod_wsgi (pid=4463): Target WSGI script '/home/one/codebase/campman/wsgi_handler.py' cannot be loaded as Python module. [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] mod_wsgi (pid=4463): Exception occurred processing WSGI script '/home/one/codebase/campman/wsgi_handler.py'. [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] Traceback (most recent call last): [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] File "/home/one/codebase/campman/wsgi_handler.py", line 13, in <module> [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] import django.core.handlers.wsgi [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] ImportError: No module named django.core.handlers.wsgi

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  • ReadyNAS issue with Google Apps?

    - by Jauder Ho
    The power went out (again) in my house today so I decided to set up some alerting. Since I have a ReadyNAS and the latest version of Raidinator seems to have SMTP TLS support, I figured I would try setting things up to email to a domain I have hosted on Google Apps. At this point, I have everything working IF I use a Gmail account but as soon as I switch to a Google Apps email address, it stops working and complains with smtpstatus=535 smtpmsg='535-5.7.1 Username and Password not accepted. Learn more at \n535 5.7.1 http://mail.google.com/support/bin/answer.py?answer=14257 30sm16076226wfd.23' errormsg='authentication failed (GNU SASL, method PLAIN)' exitcode=EX_NOPERM I'm wondering if anyone else has encountered this. Google's extremely aggressive captcha does not help but I am able to log in now without a captcha from a browser so I'm open to any ideas why the simple switch of a user/password combo that is supposed to work does not. I'm also attaching my config so that others can see how to set things up.

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  • Google I/O 2010 - Developing web apps for Chrome Web Store

    Google I/O 2010 - Developing web apps for Chrome Web Store Google I/O 2010 - Developing web apps for the Chrome Web Store Chrome 101 Erik Kay Google Chrome is a powerful platform for developing web apps. With Chrome web apps, we're making it easier for users to discover and use these apps. Learn how to build and sell apps for the Chrome Web Store. For all I/O 2010 sessions, please go to code.google.com From: GoogleDevelopers Views: 8 0 ratings Time: 01:00:29 More in Science & Technology

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  • Apache mod_wsgi error: ImportError: No module named django.core.handlers.wsgi

    - by bigmac
    I am using Python 2.7 with mod_python 3.3.1 and mod_wsgi 3.3. I get an Internal Server Error and this stack trace in the apache logs: [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] import django.core.handlers.wsgi [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] ImportError: No module named django.core.handlers.wsgi [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] mod_wsgi (pid=4463): Target WSGI script '/home/one/codebase/campman/wsgi_handler.py' cannot be loaded as Python module. [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] mod_wsgi (pid=4463): Exception occurred processing WSGI script '/home/one/codebase/campman/wsgi_handler.py'. [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] Traceback (most recent call last): [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] File "/home/one/codebase/campman/wsgi_handler.py", line 13, in <module> [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] import django.core.handlers.wsgi [Thu Apr 21 10:25:37 2011] [error] [client 83.244.243.242] ImportError: No module named django.core.handlers.wsgi

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  • How to debug slow queries in Django+Postgres

    - by lacker
    My database queries from Django are starting to take 1-2 seconds and I'm having trouble figuring out why. Not too big a site, about 1-2 requests per second (that hit Django; static files are just served from nginx.) The thing that confuses me is, I can replicate the slowness in the Django shell using debug mode. But when I issue the exact same queries at an sql prompt they are fast. It takes about a second for a query to return, but when I check connection.queries it reports the time as under 10 ms. Here's an example (from the Django shell): >>> p = PlayerData.objects.get(uid="100000521952372") >>> a = time.time(); p.save(); print time.time() - a 1.96812295914 >>> for d in connection.queries: print d["time"] ... 0.002 0.000 0.000 How can I figure out where this extra time is being spent? I'm using Apache+mod_wsgi in daemon mode, but this happens with just the django shell as well, so I figure it is not apache-related.

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