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• Django limit access by group only

  - by Mike

  I only you can limit what a user can do via the user permissions in admin.. But is there a way to limit them in admin via what group you add them to? I want to allow a certain group to do everything in that model if they belong to a certain group thanks!

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• Do something every 3 loop in django-templates?

  - by eos87

  hi people, i wanna make change in css class every 3 loop. In the first three i want to use the CSS class A, in the next three i want to use the CSS class B, in the next three i want to use the CSS class A again and so on. can anyone help? Thanks

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• Get Url Parameters In Django

  - by picomon

  I want to get current transaction id in url. it should be like this www.example.com/final_result/53432e1dd34b3 . I wrote the below codes, but after successful payment, I'm redirected to Page 404. (www.example.com/final_result//) Views.py @csrf_exempt def pay_notif(request, v_transaction_id): if request.method=='POST': v_transaction_id=request.POST.get('transaction_id') endpoint='https://testpay.com/?v_transaction_id={0}&type=json' req=endpoint.format(v_transaction_id) last_result=urlopen(req).read() if 'Approved' in last_result: session=Pay.objects.filter(session=request.session.session_key).latest('id') else: return HttpResponse(status=204) return render_to_response('final.html',{'session':session},context_instance=RequestContext(request)) Urls.py url(r'^final_result/(?P<v_transaction_id>[-A-Za-z0-9_]+)/$', 'digiapp.views.pay_notif', name="pay_notif"), Template: <input type='hidden' name='v_merchant_id' value='{{newpayy.v_merchant_id}}' /> <input type='hidden' name='item_1' value='{{ newpayy.esell.up_name }}' /> <input type='hidden' name='description_1' value='{{ newpayy.esell.up_description }}' /> <input type='hidden' name='price_1' value='{{ newpayy.esell.up_price }}' /> #page to be redirected to after successful payment <input type='hidden' name='success_url' value='http://127.0.0.1:8000/final_result/{{newpayy.v_transaction_id}}/' /> How can I go about this?

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• Django modelform ForeignKey List

  - by Harry

  How do you get each item in the ForeignKey field in a list, for example: class Delegate(models.Model): excursion = models.ForeignKey(Excursion, limit_choices_to = {'is_activity': False}, related_name='excursion', null=True, blank=True) Template: {% for object in formset.excursion_set.all %} {{ object.lable }} etc {% endfor %} My reason is that I don't want the options to display as a dropdown, but in a custom way that I will style etc.

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• How to save links in Django

  - by xRobot

  I have a simple Blog model with a TextFields. What is the best way to save link ? 1) Saving link in the database in this form: http://www.example.com and then using some filter in the template to trasform it in form: <a rel="nofollow" href="http://www.example.com>http://www.example.com</a> 2) Saving link in the database directly in this form: <a rel="nofollow" href="http://www.example.com>http://www.example.com</a>

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• Default FileField names for Django files

  - by Adam Nelson

  I have a model: class Example(models.Model): unique_hash = models.CharField(max_length=32,unique=True) content = models.FileField(upload_to='source',blank=True,verbose_name="HTML Content File") I would like to be able to set the content filename to default to a callable, but I don't see any way to have the callable reference unique_hash (or vice versa). Is this possible?

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• How to retrieve items from a django queryset?

  - by sharataka

  I'm trying to get the video element in a queryset but am having trouble retrieving it. user_channel = Everything.objects.filter(profile = request.user, playlist = 'Channel') print user_channel[0] #returns the first result without error print user_channel[0]['video'] #returns error Models.py: class Everything(models.Model): profile = models.ForeignKey(User) playlist = models.CharField('Playlist', max_length = 2000, null=True, blank=True) platform = models.CharField('Platform', max_length = 2000, null=True, blank=True) video = models.CharField('VideoID', max_length = 2000, null=True, blank=True) video_title = models.CharField('Title of Video', max_length = 2000, null=True, blank=True) def __unicode__(self): return u'%s %s %s %s %s' % (self.profile, self.playlist, self.platform, self.video, self.video_title)

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• Django: common template subsections

  - by Parand

  What's a good way to handle commonly occurring subsections of templates? For example, there is a sub-header section that's used across 4 different pages. The pages are different enough to not work well with template inheritance (ie. "extends" doesn't fit well). Is "include" the recommended method here? It feels a bit heavyweight, requiring each subsection or snippet to be in its own file. Are there any performance issues in using include or is it smart about forming template from the subsections (ie. if I make extensive use of it, do I pay any penalties)? I think what I'm looking for is something like template tags, but without the programming - a simple way to create a library of html template tags I can sprinkle in other templates.

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• Django menu item sorting

  - by doktorno

  Hi i've got MenuItem model : MenuItem(models.Model) name=models.CharField(max_length=50) url = models.URLField() position = models.IntegerField() Class Meta: ordering =['position'] then i'm retriving it by MenuItem.objects.all() My question is how can i make any user friendly interface in admin panel to allow sorting MenuItems - for example list with + and - buttons to move MenuItem up and down ....

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• Django Find Out if User is Authenticated in Custom Tag

  - by greggory.hz

  I'm trying to create a custom tag. Inside this custom tag, I want to be able to have some logic that checks if the user is logged in, and then have the tag rendered accordingly. This is what I have: def user_actions(context): request = template.Variable('request').resolve(context) return { 'auth': request['user'].is_athenticated() } register.inclusion_tag('layout_elements/user_actions.html', takes_context=True)(user_actions) When I run this, I get this error: Caught VariableDoesNotExist while rendering: Failed lookup for key [request] in u'[{}]' The view that renders this ends like this: return render_to_response('start/home.html', {}, context_instance=RequestContext(request)) Why doesn't the tag get a RequestContext object instead of the Context object? How can I get the tag to receive the RequestContext instead of the Context? EDIT: Whether or not it's possible to get a RequestContext inside a custom tag, I'd still be interested to know the "correct" or best way to determine a user's authentication state from within the custom tag. If that's not possible, then perhaps that kind of logic belongs elsewhere? Where?

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• django overwrite form clean method

  - by John

  Hi, When overwriting a form clean method how do you know if its failed validation on any of the fields? e.g. in the form below if I overwrite the clean method how do I know if the form has failed validation on any of the fields? class PersonForm(forms.Form): title = Forms.CharField(max_length=100) first_name = Forms.CharField(max_length=100) surname = Forms.CharField(max_length=100) password = Forms.CharField(max_length=100) def clean(self, value): cleaned_data = self.cleaned_data IF THE FORM HAS FAILED VALIDATION: self.data['password'] = 'abc' raise forms.ValidationError("You have failed validation!") ELSE: return cleaned_data Thanks

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• I want to select the distict value from models field and then update them (django)

  - by qulzam

  I have models... class Item(models.Model): name = models.CharField('Item Name', max_length = 30) item_code = models.CharField(max_length = 10) color = models.CharField(max_length = 150, null = True, blank = True) size = models.CharField(max_length = 30, null = True, blank = True) fabric_code = models.CharField(max_length = 30, null = True, blank = True) I have values in Item. in Item model name field has the similar values..(but the other values of record are change). I want to select the name field values distinctly(ie similar values select only ones). in one box(like combo box). What kind of form or views i use??

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• How do I set prifix to django contrib tables names?

  - by Software Enthusiastic

  HI One of my requirement is to have prefix on all the tables of the django based project (Because db is hosted on shared server). I have used db_table Meta option to set the prefix for the tables which I have created. Now my query is how do I set the prefix for tables provided by django.contrib. Instead of auth_group django should create prefix_auth_group.... How do I do that? Thank you very much...

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• reverse many to many fields in Django + count them

  - by cleliodpaula

  I'm trying to figure out how to solve this class Item(models.Model): type = models.ForeignKey(Type) name = models.CharField(max_lenght = 10) ... class List(models.Model): items = models.ManyToManyField(Item) ... I want to count how many an Item appears in another Lists, and show on template. view def items_by_list(request, id_): list = List.objects.get(id = id_) qr = list.items.all() #NOT TESTED num = [] i = 0 for item in qr: num[i] = List.objects.filter(items__id = item__id ).count() #FINISH NOT TESTED c = {} c.update(csrf(request)) c = {'request':request, 'list' : qr, 'num' : num} return render_to_response('items_by_list.html', c, context_instance=RequestContext(request)) template {% for dia in list %} <div class="span4" > <div> <h6 style="color: #9937d8">{{item.type.description}}</h6> <small style="color: #b2e300">{{ item.name }}</small> <small style="color: #b2e300">{{COUNT HOW MANY TIMES THE ITEM APPEAR ON OTHER LISTS}}</small> </div> {% endfor %} This seems to be easy, but I could not implement yet. If anyone has some glue to me, please help me. Thanks in advance.

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• Django template CSS/IMG is "off" in the URL

  - by erimar77

  I have /path/to/my/theme/static/css/frontend.css which is called by base.html <link rel="stylesheet" type="text/css" href="{{ STATIC_URL }}css/frontend.css" media="all" /> In which I've got a background for the header: #header-wrapper min-width: 960px; height: 150px; background: transparent url(img/header-bg.png) repeat-x center bottom; } The file is /path/to/my/theme/static/img I've run manage.py collectstatic to gather the files and almost everything looks correct except the link generated looks like: http://example.com/static/css/img/header-bg.png In which the image does not show, because the correct URL is: http://example.com/static/img/header-bg.png Where am I going wrong??

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• Do something every 3 loops in django-templates?

  - by eos87

  hi people, I wanna make change in css class every 3 loops. In the first three I want to use the CSS class A, in the next three I want to use the CSS class B, in the next three I want to use the CSS class A again and so on. can anyone help? Thanks

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• django flatpage redirects

  - by Joe

  I want to make sure all of my flatpages have the "www" subdomain and redirect to it if they don't. I've looked at some middlewares that redirect to www, but 1. they usually redirect all urls to www and 2. the ones I've found don't work with flatpages. I don't want all of my site urls to redirect to include the www subdomian, just the flatpages. Anyone know how I should go about doing this? Thanks

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• Django forms: prepopulate form with request.user and url parameter

  - by Malyo

  I'm building simple Course Management App. I want Users to sign up for Course. Here's sign up model: class CourseMembers(models.Model): student = models.ForeignKey(Student) course = models.ForeignKey(Course) def __unicode__(self): return unicode(self.student) Student model is extended User model - I'd like to fill the form with request.user. In Course model most important is course_id, which i'm passing into view throught URL parameter (for example http://127.0.0.1:8000/courses/course/1/). What i want to achieve, is to generate 'invisible' (so user can't change the inserted data) form with just input, but containing request.user and course_id parameter.

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• Permission to view, but not to change! - Django

  - by RadiantHex

  Hi folks, is it possible to give users the permission to view, but not to change or delete. currently in the only permissions I see are "add", "change" and "delete"... but there is no "read/view" in there. I really need this as some users will only be able to consult the admin panel, in order to see what has been added in. Help would be amazing!

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• How to loop X times in Django?

  - by Mark

  I have user reviews on my site. Each review has a rating of 1-5 stars. I want to print that many stars. How do I do it? I only see {% for X in Y %} which lets you iterate over a list, but not a certain number of times.

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• Django model data consistency

  - by Mark

  When creating a form, you can define a bunch of methods, clean_xyz, to make sure the data gets forced into the correct format. Is there any way to do this on a model level? Perhaps I can override the field setters somehow? I want it so that if I write something like my_address.postal_code = 'a1b2c3' It will automatically get formatted into A1B 2C3. Perhaps throw an exception if it can't be converted. That way I know I'll never have any malformed data in the database.

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• Running multiple FCGI/Django on Nginx for load sharing

  - by Barry

  I am running a web-service on Nginx/FastCGI/Django. Our processing time is fairly long and CPU intensive and I would like to be able to run multiple processes of Django/FastCGI to share the load. How do I set Nginx to rout requests from a single source to multiple instances of Django/FastCGI? (I can run the multiple instances on multiple ports/sockets, but I don't know how to make Nginx share the processing load between them.) Any help much appreciated.

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• MediaTemple Django Bad Gateway

  - by Eeyore

  I have a site running on GS server on MediaTemple. It's Django/PostgreSQL setup. For some reason from time to time I get Bad Gateway error and I can't figure out what's causing it. What can cause this error? What else can I do to find the cause of the problem? url.access-deny = ( "~", ".inc" ) fastcgi.server = ( "/main.fcgi" => ( "main" => ( "socket" => "/var/tmp/" + appname + ".sock", # don't change this "check-local" => "disable", ) ) ) alias.url = ( "/media/" => "/home/xxx/data/python/django/django/contrib/admin/media/", "/static/" => "/home/xxx/containers/django/site/static/", ) url.rewrite-once = ( "^(/media.*)$" => "$1", "^(/static.*)$" => "$1", "^/favicon\.ico$" => "/media/favicon.ico", "^(/.*)$" => "/main.fcgi$1", ) server.error-handler-404 = "/main.fcgi"

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• GIT and Django Projects

  - by Garfonzo

  I have two servers, a Dev server and a Production server. The Production server runs a live Django site, while the Dev server has a copy of the Django project. I use the Dev server to work on the Django site, make improvements, fix bugs, etc. Once I am satisfied with how the Dev version is working, I move the whole Django directory from the Dev server and replace the same directory on the Production server. The two servers are not on the same LAN so the process is not straight forward. There are a few issues with this that I am having so far. Moving the whole directory is laborious and time consuming If I only change a few files, it is even move tedious to replace a few files than the whole directory since the project is getting fairly large and I worry that I'll miss something I often run into permission issues after I've moved things It's super inefficient, and, due to lack of time, I haven't bothered figuring out a new method. Now it's just getting out of hand and i need to address the situation. I am thinking I need to move to a GIT repository for this process. But my question is how would I set this all up? Do I host the repository on the Production server, pull from the Dev server, do work, then commit? Then I would pull from the Production server (same server the repo is hosted on) to run the current working version? Do I host the repo on the Dev Server, pulling from the same server to do work on the repo, then pull a working version onto the Production server? Should I be hosting the repo on a different server than the Production server and the Dev server (a third server)? Are there any special considerations with Django and repos that I need to worry about? Thanks for the help :)

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• UK-based web hosting with Django support

  - by mattbd

  I'm planning to set up a personal website in the near future, and I'd like to use Django on the site. I haven't yet made any decisions about hosting and I was thinking of going with Fasthosts, who support Python, but their website doesn't mention Django at all. Anyone know whether they support it or not? If not, can anyone recommend a good UK-based web host that does support Django?

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