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  • cgi.FieldStorage always empty - never returns POSTed form Data

    - by Dan Carlson
    This problem is probably embarrassingly simple. I'm trying to give python a spin. I thought a good way to start doing that would be to create a simple cgi script to process some form data and do some magic. My python script is executed properly by apache using mod_python, and will print out whatever I want it to print out. My only problem is that cgi.FieldStorage() is always empty. I've tried using both POST and GET. Each trial I fill out both form fields. <form action="pythonScript.py" method="POST" name="ARGH"> <input name="TaskName" type="text" /> <input name="TaskNumber" type="text" /> <input type="submit" /> </form> If I change the form to point to a perl script it reports the form data properly. The python page always gives me the same result: number of keys: 0 #!/usr/bin/python import cgi def index(req): pageContent = """<html><head><title>A page from""" pageContent += """Python</title></head><body>""" form = cgi.FieldStorage() keys = form.keys() keys.sort() pageContent += "<br />number of keys: "+str(len(keys)) for key in keys: pageContent += fieldStorage[ key ].value pageContent += """</body></html>""" return pageContent I'm using Python 2.5.2 and Apache/2.2.3. This is what's in my apache conf file (and my script is in /var/www/python): <Directory /var/www/python/> Options FollowSymLinks +ExecCGI Order allow,deny allow from all AddHandler mod_python .py PythonHandler mod_python.publisher </Directory>

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  • How can I get VS2008 winforms designer to render a Form that implements an abstract base class

    - by BeowulfOF
    Hi, I engadged a problem with inherited Controls in WinForms, and need some advice on it. I do use a base class for items in a List (selfmade GUI list made of a panel) and some inherited controls that are for each type of data that could be added to the list. There was no problem with it, but I know found out, that it would be right, to make the base-control an abstract class, since it has methods, that need to be implemented in all inherited controls, called from the code inside the base-control, but must not and can not be implemented in the base class. When I mark the base-control as abstract, the VS2008 Designer refuses to load the window. Is there any way to get the Designer work with the base-control made abstract?

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  • Why does asp.net mvc form submits itself on button clicks when javascript function error?

    - by melaos
    hi guys, i'm new to the asp.net mvc, and while working on this, i used very basic asp.net mvc stuff like beginform, etc. i used a lot of jquery codes this round for client side validation, ajax data retrieval, and other gui works. and i used a combinations of html inputs buttons, etc and the asp.net mvc type of controls. what i noticed is that whenever i click on a button control, which sometimes are tied to either jquery oclick events, when there's a javascript error, the page will just go on and submit. why is this happening and what am i missing here? my bad for the dumb questions.. thanks

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  • Calling a method within Portlet when submitting form

    - by Roland
    I have a Portlet that contains a form. Now what I want to achieve is the following. 1) A Porlet containing a form is called within a page via <?php $this->widget('form'); ?> 2) The user fills in this form and clicks on submit "The submit button should be an ajax button" 3) When submit has been pressed the form should call a method within the form portlet class and the form should be replaced with a Thank you message. 4) I only want the current view in the portlet replaced with another view. My portlet class looks like this Yii::import('zii.widgets.CPortlet'); class Polls extends CPortlet{ public $usr_id=''; public function init(){ $cs = Yii::app()->clientScript; $cs->registerCoreScript('jquery'); parent::init(); } protected function renderContent(){ $this->render('form'); } public function update(){ $this->render('thankyou'); } } } Any advise, help would be highly appreciated.

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  • dynamically created controls and responding to control events

    - by Dirk
    I'm working on an ASP.NET project in which the vast majority of the forms are generated dynamically at run time (form definitions are stored in a DB for customizability). Therefore, I have to dynamically create and add my controls to the Page every time OnLoad fires, regardless of IsPostBack. This has been working just fine and .NET takes care of managing ViewState for these controls. protected override void OnLoad(EventArgs e) { base.OnLoad(e); RenderDynamicControls() } private void RenderDynamicControls(){ //1. call service layer to retrieve form definition //2. create and add controls to page container } I have a new requirement in which if a user clicks on a given button (this button is created at design time) the page should be re-rendered in a slightly different way. So in addition to the code that executes in OnLoad (i.e. RenderDynamicControls()), I have this code: protected void MyButton_Click(object sender, EventArgs e) { RenderDynamicControlsALittleDifferently() } private void RenderDynamicControlsALittleDifferently() (){ //1. clear all controls from the page container added in RenderDynamicControls() //2. call service layer to retrieve form definition //3. create and add controls to page container } My question is, is this really the only way to accomplish what I'm after? It seems beyond hacky to effectively render the form twice simply to respond to a button click. I gather from my research that this is simply how the page-lifecycle works in ASP.NET: Namely, that OnLoad must fire on every Postback before child events are invoked. Still, it's worthwhile to check with the SO community before having to drink the kool-aid. On a related note, once I get this feature completed, I'm planning on throwing an UpdatePanel on the page to perform the page updates via Ajax. Any code/advice that make that transition easier would be much appreciated. Thanks

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  • HTML Form HIdden Fields added with Javascript not POSTing

    - by dscher
    I have a form where the user can enter a link, click the "add link" button, and that link is then(via jQuery) added to the form as a hidden field. The problem is it's not POSTing when I submit the form. It's really starting to confound me. The thing is that if I hardcode a hidden field into the form, it is posted, but my function isn't working for some reason. The hidden field DOES get added to my form as I can see with Firebug but it's just not being sent with the POST data. Just to note, I'm using an array in Javascript to hold the elements until the form is submitted which also posts them visibly for the user to see what they've added. I'm using [] notation on the "name" field of the element because I want the links to feed into an array in PHP. Here is the link creation which is being appended to my form: function make_hidden_element_tag(item_type, item_content, item_id) { return '<input type="hidden" name="' + item_type + '[]" id="hidden_link_' + item_id + '" value="' + item_content + '"/>'; Does anyone have an idea why this might not be posting. As stated above, any hard-coded tags that are nearly identical to the above works fine, it's just that this tag isn't working. Here is how I'm adding the tag to the form with jQUery: $('#link_td').append( make_hidden_element_tag('links', link, link_array.length - 1)); I'm using the Kohana 3 framework, although I'm not sure that has any bearing on this because it's not really doing anything from the time the HTML is added to the page and the submit button is pressed.

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  • inserting a form to session raises picklingerror - django

    - by shanyu
    I receive an exception when I add a form to the session: PicklingError: Can't pickle <class 'django.utils.functional.__proxy__'>: attribute lookup django.utils.functional.__proxy__ failed The form includes a few simple fields and has some javascript attached to a widget. It might be that Django forms cannot be pickled at all, but the exception seems to point to unicode lazy translation. To test further, I have also tried to insert only the form errors (an errordict) to the session and received the same error. I appreciate some help here, thanks in advance. EDIT: Here's why I insert a form into the session: I have an app that has a form. This form is rendered by a template tag in another app. When posted, if the form is valid, no problem, I do stuff and redirect to "next". However if it is not valid, I want to go back to the posting page to show errors. Recall that the comments app in this case redirects to an intermediate "hey, please fix the errors" page. I am trying to avoid this, and hence redirect back to the posting page with the form and its errors in the session that the template tag will render.

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  • How to add a specific class to an input which has generated a form error?

    - by Kamil Mroczek
    I want to add a specific class to an input if an error is genereted by the input. For example, if input is empty and has required validator it shouls look like this: <dd id="login-element"> <input type="text" name="login" id="login" value="" class="input-text error" /> <ul class="errors"> <li>Value is required and can't be empty</li> </ul> </dd> class="input-text error" Please tell me how to do that.

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  • How can I adjust the position of a label for a zend form Radio element?

    - by murze
    Hi, with this piece of code $feOnline = New Zend_Form_Element_Radio('online'); $feOnline->setValue($article->online) ->addMultiOptions(array(0=>'offline', 1=>'online')) ->setLabel('Online'); this html is generated <dd id="online-element"> <label for="online-0"> <input type="radio" checked="checked" value="0" id="online-0" name="online">offline </label><br> <label for="online-1"><input type="radio" value="1" id="online-1" name="online">online </label> </dd> However I don't want the input-tag inside the label-tag. No need for the "" either... What decorators must I add to get this output? <dd id="online-element"> <input type="radio" checked="checked" value="0" id="online-0" name="online"><label for="online-0">offline</label> <input type="radio" value="1" id="online-1" name="online"><label for="online-1">online</label> </dd>

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  • Submit a form and get a JSON response with jQuery

    - by Leopd
    I expect this is easy, but I'm not finding a simple explanation anywhere of how to do this. I have a standard HTML form like this: <form name="new_post" action="process_form.json" method=POST> <label>Title:</label> <input id="post_title" name="post.title" type="text" /><br/> <label>Name:</label><br/> <input id="post_name" name="post.name" type="text" /><br/> <label>Content:</label><br/> <textarea cols="40" id="post_content" name="post.content" rows="20"></textarea> <input id="new_post_submit" type="submit" value="Create" /> </form> I'd like to have javascript (using jQuery) submit the form to the form's action (process_form.json), and receive a JSON response from the server. Then I'll have a javascript function that runs in response to the JSON response, like function form_success(json) { alert('Your form submission worked'); // process json response } How do I wire up the form submit button to call my form_success method when done? Also it should override the browser's own navigation, since I don't want to leave the page. Or should I move the button out of the form to do that?

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  • Ruby on Rails user login form in main layout

    - by Jimmy
    Hey guys I have a simple ror application for some demo stuff. I am running into a problem with trying to move my login form from the users controller and just have it displayed in the main navigation so that a user can easily log in from anywhere. The problem is the form doesn't generate the correct action for the html form. Ruby code: <% form_for(url_for(:action => 'login'), :method => 'post') do |f| %> <li><%= f.text_field("username") %></li> <li><%= f.password_field("password") %></li> <li><%= submit_tag("Login")%></li> <% end %> The problem is depending on the controller I am currently in this generates HTML actions like <form action="/home" method="post">...</form> when it should be generating HTML like so <form action="/login" method="post">...</form> I know I could simply do an HTML form here but I want to keep things as easy to maintain as possible. Any help?

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  • Symfony2 Forms: is it possible to bind a form in an "unconventional way"?

    - by DonCallisto
    Imagine this scenario: in our company there is an employee that "play" around graphic,css,html and so on. Our new project will born under symfony2 so we're trying some silly - but "real" - stuff (like authentication from db, submit data from a form and persist it to db and so on..) The problem As far i know, learnt from symfony2 "book" that i found on the site (you can find it here), there is an "automated" way for creating and rendering forms: 1) Build the form up into a controller in this way $form = $this->createFormBuilder($task) ->add('task','text'), ->add('dueDate','date'), ->getForm(); return $this->render('pathToBundle:Controller:templateTwig', array('form'=>$form->createview()); 2) Into templateTwig render the template {{ form_widget(form) }} // or single rows method 3) Into a controller (the same that have a route where you can submit data), take back submitted information if($rquest->getMethod()=='POST'){ $form->bindRequest($request); /* and so on */ } Return to scenario Our graphic employee don't want to access controllers, write php and other stuff like those. So he'll write a twig template with a "unconventional" (from symfony2 point of view, but conventional from HTML point of view) method: /* into twig template */ <form action="{{ path('SestanteUserBundle_homepage') }}" method="post" name="userForm"> <div> USERNAME: <input type="text" name="user_name" value="{{ user.username}}"/> </div> <div> EMAIL: <input type="text" name="user_mail" value="{{ user.email }}"/> </div> <input type="hidden" name="user_id" value="{{ id }}" /> <input type="submit" value="modifica i dati"> </form> Now, if into the controller that handle the submission of data we do something like that public function indexAction(Request $request) { if($request->getMethod() == 'POST'){ // sono arrivato per via di un submit, quindi devo modificare i dati prima di farli vedere a video $defaultData = array('message'=>'ho visto questa cosa in esempio, ma non capisco se posso farne a meno'); $form = $this->createFormBuilder($defaultData) ->add('user_name','text') ->add('user_mail','email') ->add('user_id','integer') ->getForm(); $form->bindRequest($request); //bindo la form ad una request $data = $form->getData(); //mi aspetto un'array chiave=>valore /* .... */ We expected that $data will contain an array with key,value from the submitted form. We found that it isn't true. After googling for a while and try with other "bad" ideas, we're frozen into that. So, if you have a "graphic office" that can't handle directly php code, how can we interface from form(s) to controller(s) ? UPDATE It seems that Symfony2 use a different convention for form's field name and lookup once you've submitted that. In particular, if my form's name is addUser and a field is named userName, the field's name will be AddUser[username] so maybe it have a "dynamic" lookup method that will extract form's name, field's name, concat them and lookup for values. Is it possible?

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  • Can JQuery.Validate plugin prevent submission of an Ajax form

    - by berko
    I am using the JQuery form plugin (http://malsup.com/jquery/form/) to handle the ajax submission of a form. I also have JQuery.Validate (http://docs.jquery.com/Plugins/Validation) plugged in for my client side validation. What I am seeing is that the validation fails when I expect it to however it does not stop the form from submitting. When I was using a traditional form (i.e. non-ajax) the validation failing prevented the form for submitting at all.... which is my desired behaviour. I know that the validation is hooked up correctly as the validation messages still appear after the ajax submit has happened. So what I am I missing that is preventing my desired behaviour? Sample code below.... <form id="searchForm" method="post" action="/User/GetDetails"> <input id="username" name="username" type="text" value="user.name" /> <input id="submit" name="submit" type="submit" value="Search" /> </form> <div id="detailsView"> </div> <script type="text/javascript"> var options = { target: '#detailsView' }; $('#searchForm').ajaxForm(options); $('#searchForm').validate({ rules: { username: {required:true}}, messages: { username: {required:"Username is a required field."}} }); </script>

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  • Spring MVC Table selected row

    - by ich-bin-drin
    Hi, in a Spring MVC 2.5 application i'm using a spring <form:form> component and in this form a table with c:forEach is rendered. In each row a submit button is placed in. If i start a submit by clicking a button i would like to knwo, which button has processed the submit. <form:form commandName="formObject"> <table class="data-table" cellpadding="1" cellspacing="1" border="0"> <thead> <tr> </tr> </thead> <c:forEach items="${list}" var="document" varStatus="row"> <tr> <td> <input type="submit" value="${document.title}"/> <td> </tr> </c:forEach> </table> </form:form> THX.

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  • Data not transfred from form to mysql table (updating of data is not happening)

    - by Jimson
    Hi all and thanks in advance to all for this I tired and was unable to find the answer i am looking for an answer. my problem is that i am unable to update the values enterd in the form. I have attached all the files i'm using MYSQL database to fetch data. what happens is that i'm able to add and delete records from form using ajax and PHP scripts to MYSQL database, but i am not able to update data which was retrived from database. the file structure is as follows index.php is a file with ajax functions where it displays form for adding new data to MYSQL using save.php file and list of all records are view without refrishing page (calling load-list.php to view all records from index.php works fine, and save.php to save data from form) - *Delete*is an ajax function called from index.php to delete record from mysql database (function calling delete.php works fine) - Update is an ajax function called from index.php to update data using update-form.php by retriving specific record from mysql tabel, (works fine) Problem lies in updating data from update-form.php to update.php (in which update query is wrriten for mysql) i had tried in many ways at last i had figured out that data is not being transfred from update-form.php to update.php there is a small problem in jquery ajax function where it is not transfering data to update.php page. can any one correct this ????? i will be greatfull to them..... please find the link below for all files link to get my form files

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  • Error while sending image through ajax to WCF

    - by Samar Rizvi
    Here is my form: <form id="register" enctype="multipart/form-data"> <input type="text" name="first_name" placeholder="First Name" id="first_name" /> <input type="text" name="last_name" placeholder="Last Name" id="last_name" /> <input type="text" name="input_email" placeholder="Confirm your email" id="input_email" class="loginEmail" /> <input type="password" name="input_password" placeholder="Password" id="input_password" class="loginPassword" /> <input type="password" name="repeat_password" placeholder="Repeat password" id="repeat_password" class="loginPassword" /> <input type="file" name="image_file" id="image_file" /> <div class="logControl"> <div class="memory"></div> <input type="submit" name="submit" value="Register" class="buttonM bBlue" id="register_submit"/> <div class="clear"></div> </div> <p><h3>Or click <a href="login.html">here</a> to login</h3></p> </form> Here is jquery call that I make: function WCFJSON() { $(".memory").html('<img src="images/elements/loaders/7s.gif" />'); Data = new FormData($('form')[0]); $.ajax({ type: 'POST', //GET or POST or PUT or DELETE verb url: "WCFService/Service.svc/Register", // Location of the service data: Data, //Data sent to server async:false, cache:false, contentType: false, // content type sent to server dataType: DataType, //Expected data format from server processdata: false, //True or False success: function(msg) {//On Successfull service call ... }, error: ...// When Service call fails }); } $(document).ready(function(){ $("#register").submit(function(){ $('#input_password').val(CryptoJS.MD5($('#input_password').val())); $('#repeat_password').val(CryptoJS.MD5($('#repeat_password').val())); WCFJSON(); return false; }); }); Now when I submit the form , page refreshes with get elements in the url. But if I remove the file input from the form, jquery works fine.

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  • Using jQuery with form to eliminate spam

    - by Thierry-Dimitri Roy
    I have put a form on a web page where the user can send us data. Unfortunately, the webmaster does get a lot of spam through this form and the valid submissions gets buried. I have used captcha to bypass this problem. But I think that everyone would agree that captcha is a big annoyance to users. I switched to another solution: now the URL of the submit form points to null: <form id="sendDataForm" action="/null" method="post"> ... </form> And I bypass the form submission using jQuery excellent form plugin: $('#sendDataForm').ajaxForm({ url: '/ajax-data/' }); Since then, no spam has reached the webmaster, and valid comments gets through. The only drawbacks is that users without javascript cannot send us the form. But since this is on top of a javascript web application, we can safely assume that these are not valid users. My question is: in a world where 99% of users has javascript enabled (and a mechanism for those user could be build that uses captcha), why is this solution not more used? What drawback am I not seeing?

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  • Inserting Row in Table inside Form tag autosubmitting in firefox/chrome

    - by user1861489
    I have a form that will have dynamic elements inserted with javascript and am experiencing some strange behavior. When I click the button to add another element to the table in the form, it adds the element but seems to to a form post immediately (without intending to submit the form yet) I have created a simplified example of the page that has the same behavior. the first table element is created on page load and subsequent elements are added when clicking on the button. this form works successfully in IE. does anyone have an idea of how to prevent this behavior? here is the code sample. <!DOCTYPE html> <html> <head> <title>Test Creating Form</title> <meta http-equiv="Content-type" content="text/html;charset=UTF-8"> <style type="text/css"> td{font-family:verdana;} </style> <script type="text/javascript"> var counter = 0; function makeTitle(title){ if(counter){ title += " " + counter; } counter++; var tbl = document.getElementById('tbl'); var tr = tbl.insertRow(-1) var td1 = tr.insertCell(-1); td1.innerHTML = title; } function load1(){ makeTitle('Primary Specimen'); } </script> </head> <body onload="load1();"> <form action="formtest.htm" method="post" name="testForm" id="testForm"> <table id="tbl" border="1"></table> <button onclick="makeTitle('Alternate Specimen')" id="clone" >Add Another Specimen</button> </form> </body> </html>

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  • ASP.NET MVC2 - Trim white space from form submits before server-side validation?

    - by David Lively
    If I add a validation attribute: public class ProductDownloadListModel { //xxxxx-xxxxx-xxxxx [Required] [StringLength(17)] public string PSN { get; set; } public DateTime PsnExpirationDate { get; set; } public DataTable Downloads { get; set; } } and the user enters a 17-character string but includes white space on the end, I get a validation error because the string is greater than that specified by the [StringLength(17)] attribute. How can I prevent this? I'd prefer not to have to have javaScript trim the string before submits.

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