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  • Java library for trees similar to JGraphT for graphs?

    - by lexicore
    I'm a big fan of JGraphT, a Java library for graphs. Could anyone recommend a similar Java library for trees? Preferrably FOSS. What I need is a good API, preferrably typesafe with generics which allows modelling different kinds of trees (with some user data attached to verticies/edges) and run different algorithms and operations on these trees. For instance, traverse or balance. At the moment I'm not interested in visualization of trees.

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  • How to detect if a certain range resides (partly) within an other range?

    - by Tom
    Lets say I've got two squares and I know their positions, a red and blue square: redTopX; redTopY; redBotX; redBotY; blueTopX; blueTopY; blueBotX; blueBotY; Now, I want to check if square blue resides (partly) within (or around) square red. This can happen in a lot of situations, as you can see in this image I created to illustrate my situation better: Note that there's always only one blue and one red square, I just added multiple so I didn't have to redraw 18 times. My original logic was simple, I'd check all corners of square blue and see if any of them are inside square red: if ( ((redTopX >= blueTopX) && (redTopY >= blueTopY) && (redTopX <= blueBotX) && (redTopY <= blueBotY)) || //top left ((redBotX >= blueTopX) && (redTopY >= blueTopY) && (redBotX <= blueBotX) && (redTopY <= blueBotY)) || //top right ((redTopX >= blueTopX) && (redBotY >= blueTopY) && (redTopX <= blueBotX) && (redBotY <= blueBotY)) || //bottom left ((redBotX >= blueTopX) && (redBotY >= blueTopY) && (redBotX <= blueBotX) && (redBotY <= blueBotY)) //bottom right ) { //blue resides in red } Unfortunately, there are a couple of flaws in this logic. For example, what if red surrounds blue (like in situation 1)? I thought this would be pretty easy but am having trouble coming up with a good way of covering all these situations.. can anyone help me out here? Regards, Tom

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  • Recursive breadth-first travel function in Java or C++?

    - by joejax
    Here is a java code for breadth-first travel: void breadthFirstNonRecursive(){ Queue<Node> queue = new java.util.LinkedList<Node>(); queue.offer(root); while(!queue.isEmpty()){ Node node = queue.poll(); visit(node); if (node.left != null) queue.offer(node.left); if (node.right != null) queue.offer(node.right); } } Is it possible to write a recursive function to do the same? At first, I thought this would be easy, so I came out with this: void breadthFirstRecursive(){ Queue<Node> q = new LinkedList<Node>(); breadthFirst(root, q); } void breadthFirst(Node node, Queue<Node> q){ if (node == null) return; q.offer(node); Node n = q.poll(); visit(n); if (n.left != null) breadthFirst(n.left, q); if (n.right != null) breadthFirst(n.right, q); } Then I found it doesn't work. It is actually does the same thing as this: void preOrder(Node node) { if (node == null) return; visit(node); preOrder(node.left); preOrder(node.right); } Has any one thought about this before?

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  • Python list recursion type error

    - by Jacob J Callahan
    I can't seem to figure out why the following code is giving me a TypeError: 'type' object is not iterable pastebin: http://pastebin.com/VFZYY4v0 def genList(self): #recursively generates a sorted list of child node values numList = [] if self.leftChild != 'none': numList.extend(self.leftChild.genList()) #error numList.extend(list((self.Value,))) if self.rightChild != 'none': numList.extend(self.rightChild.genList()) #error return numList code that adds child nodes (works correctly) def addChild(self, child): #add a child node. working if child.Value < self.Value: if self.leftChild == 'none': self.leftChild = child child.parent = self else: self.leftChild.addChild(child) elif child.Value > self.Value: if self.rightChild == 'none': self.rightChild = child child.parent = self else: self.rightChild.addChild(child) Any help would be appreciated. Full interpreter session: >>> import BinTreeNode as BTN >>> node1 = BTN.BinaryTreeNode(5) >>> node2 = BTN.BinaryTreeNode(2) >>> node3 = BTN.BinaryTreeNode(12) >>> node3 = BTN.BinaryTreeNode(16) >>> node4 = BTN.BinaryTreeNode(4) >>> node5 = BTN.BinaryTreeNode(13) >>> node1.addChild(node2) >>> node1.addChild(node3) >>> node1.addChild(node4) >>> node1.addChild(node5) >>> node4.genList() <class 'list'> >>> node1.genList() Traceback (most recent call last): File "<interactive input>", line 1, in <module> File "C:...\python\BinTreeNode.py", line 47, in genList numList.extend(self.leftChild.genList()) #error File "C:...\python\BinTreeNode.py", line 52, in genList TypeError: 'type' object is not iterable

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  • Insertion into BST without header Node JAVA

    - by Petiatil
    I am working on a recursive insertion method for a BST. This function is suppose to be a recursive helper method and is in a private class called Node. The Node class is in a class called BinarySearchTree which contains an instance variable for the root. When I am trying to insert an element, I get a NullPointerException at : this.left = insert(((Node)left).element); I am unsure about why this occurs. If I understand correctly, in a BST, I am suppose to insert the item at the last spot on the path transversed. Any help is appreciated! private class Node implements BinaryNode<E> { E item; BinaryNode<E> left, right; public BinaryNode<E> insert(E item) { int compare = item.compareTo(((Node)root).item); if(root == null) { root = new Node(); ((Node)root).item = item; } else if(compare < 0) { this.left = insert(((Node)left).item); } else if(compare > 0) { this.right = insert(((Node)right).item); } return root; } }

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  • Python iterate object with a list of objects

    - by nerd
    First time poster, long time reader. Is it possible to iterate though an object that contains a list of objects. For example, I have the following class Class Page(object) def __init__(self, name): self.name = name self.pages = [] I then create a new Page object and add other page objects to it. page = Page('FirstPage') apagepage = Page('FirstChild') anotherpagepage = Page('SecondChild') apagepage.pages.append(Page('FirstChildChild')) apagepage.pages.append(Page('SecondChildChild')) page.pages.append(apagepage) page.pages.append(anotherpagepage) What I would like to do is for thispage in page: print thispage.name And get the following output FirstPage FirstChild SecondChild FirstChildChild SecondChildChild So I get all the 1st level, then the 2nd, then the 3rd. However, the following output would be find as well FirstPage FirstChild FirstChildChild SecondChildChild SecondChild

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  • What web technology could I use which would support a decision tree?

    - by Rami Alhamad
    I am a big game development fan but I haven't done any commercial work in the past. I have been asked by a non-profit to look at developing a game similar to the award-winning www.playspent.org They want the following features: support 5 scenarios mobile isn't important but compatibility with older browsers would be a big bonus they want it to be visual and audible bonus is to have it easily modifiable support 4 languages I don't have much knowledge of Flash and would rather avoid using it as a solution. I started breaking down the problem into segments that I will need to examine, they are as follows: ability to read the game flow from a file that they can produce (xml, etc.) db design to store decision tree language challenge browser compatibility I am leaning towards an Google app engine/GWT solution but I am not sure what technology is best for this. I am really hoping to get your opinion/recommendation on my approach and on what technology is best. A special thanks (and beer if you live in Toronto) will be awarded to anyone who can help give me a ballpark estimate on how much such a game should go for. I know it's tough to estimate but any rough figure will help (how much would you charge for building something like playspent.org?) Thanks in advance

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  • Script/tool to import series of snapshots, each being a new edition, into GIT, populating source tree?

    - by Rob
    I've developed code locally and taken a fairly regular snapshot whenever I reach a significant point in development, e.g. a working build. So I have a long-ish list of about 40 folders, each folder being a snapshot e.g. in ascending date YYYYMMDD order, e.g.:- 20100523 20100614 20100721 20100722 20100809 20100901 20101001 20101003 20101104 20101119 20101203 20101218 20110102 I'm looking for a script to import each of these snapshots into GIT. The end result being that the latest code is the same as the last snapshot, and other editions are accessible and are as numbered. Some other requirements: that the latest edition is not cumulative of the previous snapshots, i.e., files that appeared in older snapshots but which don't appear in later ones (e.g. due to refactoring etc.) should not appear in the latest edition of the code. meanwhile, there should be continuity between files that do persist between snapshots. I would like GIT to know that there are previous editions of these files and not treat them as brand new files within each edition. Some background about my aim: I need to formally revision control this work rather than keep local private snapshot copies. I plan to release this work as open source, so version controlling would be highly recommended I am evaluating some of the current popular version control systems (Subversion and GIT) BUT I definitely need a working solution in GIT as well as subversion. I'm not looking to be persuaded to use one particular tool, I need a solution for each tool I am considering. (I haved posted an answer separately for each tool so separate camps of folks who have expertise in GIT and Subversion will be able to give focused answers on one or the other). The same but separate question for Subversion: Script/tool to import series of snapshots, each being a new revision, into Subversion, populating source tree?

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  • Traverse tree with results. Maybe type in Java?

    - by Angelo.Hannes
    I need to check a tree's node state. It can either be OK or NOT_OK. But that state is dependent on its children. So for a node to be OK, every of its children needs to be OK. If one or more of its children is NOT_OK the whole node is NOT_OK. To determine the state of a node I need to aggregate some properties of the node. So I thought of two possible implementations. And they are more or less covered in this question: Why is Option/Maybe considered a good idea and checked exceptions are not? Exception I could pass the properties up the recursion path, and throw an exception if something went wrong. Maybe I implement an Maybe type and let it either hold an error or the aggregated properties. Maybe it is more an Either. I tend towards the last option. And I'm thinking of an enum with two objects. Where I can additionally set those aggregated properties. Am I on the right track? I'm not familiar with the new JDK8 functional stuff. But I'm stuck on JDK7 anyway, so please focus on JDK7.

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  • UPK Customer Success Story: The City and County of San Francisco

    - by karen.rihs(at)oracle.com
    The value of UPK during an upgrade is a hot topic and was a primary focus during our latest customer roundtable featuring The City and County of San Francisco: Leveraging UPK to Accelerate Your PeopleSoft Upgrade. As the Change Management Analyst for their PeopleSoft 9.0 HCM project (Project eMerge), Jan Crosbie-Taylor provided a unique perspective on how they're utilizing UPK and UPK pre-built content early on to successfully manage change for thousands of city and county employees and retirees as they move to this new release. With the first phase of the project going live next September, it's important to the City and County of San Francisco to 1) ensure that the various constituents are brought along with the project team, and 2) focus on the end user aspects of the implementation, including training. Here are some highlights on how UPK and UPK pre-built content are helping them accomplish this: As a former documentation manager, Jan really appreciates the power of UPK as a single source content creation tool. It saves them time by streamlining the documentation creation process, enabling them to record content once, then repurpose it multiple times. With regard to change management, UPK has enabled them to educate the project team and gain critical buy in and support by familiarizing users with the application early on through User Experience Workshops and by promoting UPK at meetings whenever possible. UPK has helped create awareness for the project, making the project real to users. They are taking advantage of UPK pre-built content to: Educate the project team and subject matter experts on how PeopleSoft 9.0 works as delivered Create a guide/storyboard for their own recording Save time/effort and create consistency by enhancing their recorded content with text and conceptual information from the pre-built content Create PeopleSoft Help for their development databases by publishing and integrating the UPK pre-built content into the application help menu Look ahead to the next release of PeopleTools, comparing the differences to help the team evaluate which version to use with their implemtentation When it comes time for training, they will be utilizing UPK in the classroom, eliminating the time and cost of maintaining training databases. Instructors will be able to carry all training content on a thumb drive, allowing them to easily provide consistent training at their many locations, regardless of the environment. Post go-live, they will deploy the same UPK content to provide just-in-time, in-application support for the entire system via the PeopleSoft Help menu and their PeopleSoft Enterprise Portal. Users will already be comfortable with UPK as a source of help, having been exposed to it during classroom training. They are also using UPK for a non-Oracle application called JobAps, an online job application solution used by many government organizations. Jan found UPK's object recognition to be excellent, yet it's been incredibly easy for her to change text or a field name if needed. Please take time to listen to this recording. The City and County of San Francisco's UPK story is very exciting, and Jan shared so many great examples of how they're taking advantage of UPK and UPK pre-built content early on in their project. We hope others will be able to incorporate these into their projects. Many thanks to Jan for taking the time to share her experiences and creative uses of UPK with us! - Karen Rihs, Oracle UPK Outbound Product Management

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  • Supporting HR Transformation with HelpDesk for Human Resources

    - by Robert Story
    Upcoming WebcastTitle: Supporting HR Transformation with HelpDesk for Human ResourcesDate: May 13, 2010 Time: 9:00 am PDT, 10 am MDT, 17:00 GMT Product Family: PeopleSoft HCM & EBS HRMS Summary HR transformation is a strategic initiative at many companies where world-class employee HR service delivery and a reduction of HR operating costs are top priorities. Having a centralized service delivery model and providing employees with tools to better help themselves can be very key to this initiative. This session shares how Oracle's PeopleSoft HelpDesk for Human Resources provides the technology foundation and best practices for this transformation. HelpDesk for Human Resources now integrates with both PeopleSoft HCM and E-Business Suite HRMS. This one-hour session is recommended for technical and functional users who want to understand what is new in PeopleSoft Help Desk for Human Resources 9.1 and how it benefits both PeopleSoft HCM and E-Business Suite HRMS customers. Topics will include: Understand the latest features and functionality Gain insight into future product direction Plan for implementation or upgrade of this module in your current system A short, live demonstration (only if applicable) and question and answer period will be included. Click here to register for this session....... ....... ....... ....... ....... ....... .......The above webcast is a service of the E-Business Suite Communities in My Oracle Support.For more information on other webcasts, please reference the Oracle Advisor Webcast Schedule.Click here to visit the E-Business Communities in My Oracle Support Note that all links require access to My Oracle Support.

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  • Final Series Webcast: Exalogic Enables Super Fast Oracle Apps - Nov 29, 18:00 GMT

    - by swalker
    Invite customers to learn how Exalogic provides high-speed performance for Oracle JD Edwards, E-Business Suite, and PeopleSoft Enterprise applications. The third and final webcast in this series "Oracle Exalogic for Oracle PeopleSoft Applications," November 29, 2011 at 10AM PT, will show customers how Exalogic can simplify their PeopleSoft architecture and help them achieve new levels of performance, scalability, and reliability. Share this evite.

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  • An Oracle Event for Your Facility & Equipment Maintenance Staff

    - by Mark Rosenberg
    The 7th Annual Oracle Maintenance Summit will occur February 4 – 6, 2013 at the Hyatt Regency San Francisco. This year, the Maintenance Summit will be one of the major pillars of a larger Oracle Value Chain Summit. What makes this event different from the other events hosted by Oracle and the PeopleSoft Community’s various user groups is that it is specifically meant to provide a venue for the facility and equipment maintenance community to talk about all things related to maintenance.  Maintenance Planners, Maintenance Schedulers, Vice Presidents and Directors of Physical Plant, Operations Managers, Craft Supervisors, IT management, and IT analysts typically attend this event and find it to be a very valuable experience. The Maintenance pillar will provide the same atmosphere and opportunity to hear from PeopleSoft Maintenance Management customers, Oracle Product Strategy, and partners, as in past years.  For more information, you can access the registration website for the Value Chain Summit. For existing PeopleSoft Maintenance Management customers…if you are interested in participating in the PeopleSoft Maintenance Management Focus Group in which Oracle discusses product roadmap topics with the community of customers who have licensed the PeopleSoft Maintenance Management application, please contact [email protected], [email protected], or [email protected]. The Focus Group will meet on February 7th, and attendance is by invitation only.We look forward to seeing you in San Francisco! P.S.  The Early Bird registration fee is $195. Register before December 31 to take advantage of this introductory low price, as the registration fee will go up to $295 after that date.

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  • New Interaction Hub Statement of Direction Published

    - by Matthew Haavisto
    The latest PeopleSoft Interaction Hub Statement of Direction is now available on My Oracle Support.  We think this subject will be particularly interesting to customers given the impending release of the PeopleSoft Fluid User Experience and all that offers.  The Statement of Direction describes how we see the Interaction Hub being used with the new user experience and the Hub's continued place in a PeopleSoft environment.  This paper also discusses subjects like branding, content management, easier design/deployment, and the optional restricted use license.

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  • How to get the size of a binary tree ?

    - by Andrei Ciobanu
    I have a very simple binary tree structure, something like: struct nmbintree_s { unsigned int size; int (*cmp)(const void *e1, const void *e2); void (*destructor)(void *data); nmbintree_node *root; }; struct nmbintree_node_s { void *data; struct nmbintree_node_s *right; struct nmbintree_node_s *left; }; Sometimes i need to extract a 'tree' from another and i need to get the size to the 'extracted tree' in order to update the size of the initial 'tree' . I was thinking on two approaches: 1) Using a recursive function, something like: unsigned int nmbintree_size(struct nmbintree_node* node) { if (node==NULL) { return(0); } return( nmbintree_size(node->left) + nmbintree_size(node->right) + 1 ); } 2) A preorder / inorder / postorder traversal done in an iterative way (using stack / queue) + counting the nodes. What approach do you think is more 'memory failure proof' / performant ? Any other suggestions / tips ? NOTE: I am probably going to use this implementation in the future for small projects of mine. So I don't want to unexpectedly fail :).

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  • Recursively resize images from one directory tree to another?

    - by davr
    I have a large complex directory tree full of JPG images. I would like to create a second directory tree that exactly mirrors the first, but resizing all the images down to a set size (say 2000x1500 or something) and quality (perhaps 85%). Is there any tool that would allow me to easily do this on Windows? I could write some scripts to automate it with bash and image magick, but first want to see if it's already been done. Faster is better too, as I have thousands of images. So something like Photoshop is probably not a good solution as it might take a couple of seconds per image.

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  • Dell 2950 Perc 6/i "physical disk" and "Enclosure(Backplane)" under Connector 1 in OMSA tree- Troubleshoot help

    - by user66357
    Just looking for someone who might know why this could occur... In OMSA, on my Dell 2950, there usually is only one "Physical Disks" child under "Enclosure (Backplane)" in the tree view. Currently, the tree looks like this: Dell PERC 6/i Integrated Connector 1 (RAID) Enclosure (Backplane) Physical Disks (1:04 good, 1:05 removed) Physical Disks (1:33 Ready but unused) Normally it's like this: Connector 1 (RAID) Enclosure (Backplane) Physical Disks (1:04 good, 1:05 good) From the front, 6 of 6 3.5" SAS drives are connected. The server is showing Slot 5 as bad and the disk as removed. It seems that the drive in Slot 5 is being sensed as external to the Enclosure. Any ideas why this would happen? Think I can get away with rebuilding the virtual disk by replacing 1:05 with 1:33? Thanks.

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  • Is there any way to get tree organisation for Windows 7 file explorer favorites?

    - by fostandy
    In XP there was a MenuBar called Favorites which seemed to be based on Internet Explorer Favorites. It was fantastic because it allowed for very fast tree style navigation (if set up correctly you could navigate it using first letter keystrokes, so to access a shortcut named "videos" in a folder named "files" was as quick as Alt-A f v) This was removed in Vista (and imo generally regressed the file explorer). This was fine because I never used it, but I'm resigned to eventually embracing the inevitability that is Windows 7. Dealing with a single non-nested list of favourites is pretty painful to me as I have quite a lot of them. Is there a way to make a tree like favorites structure in Windows 7? My fingers are crossed.

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  • pyqt QTreeWidget setItemWidget dissapears after drag/drop

    - by mleep
    I'm trying to keep a widget put into a QTreeWidgetItem after a reparent (drag and drop) using QTreeWidget.setItemWidget() But the result, if you compile the following code - is that the widget inside the QTreeWidgetItem disappears. Any idea why? What code would fix this (repopulate the QTreeWidgetItem with the widget I guess?) from PyQt4.QtCore import * from PyQt4.QtGui import * class InlineEditor (QWidget): _MUTE = 'MUTE' def __init__ (self, parent): QWidget.__init__ (self, parent) self.setAutoFillBackground (True) lo = QHBoxLayout() lo.setSpacing(4) self._cbFoo = QComboBox() for x in ["ABC", "DEF", "GHI", "JKL"]: self._cbFoo.addItem(x) self._leBar = QLineEdit('', self) lo.addWidget (self._cbFoo, 3) lo.addSpacing (5) lo.addWidget (QLabel ( 'Bar:')) lo.addWidget (self._leBar, 3) lo.addStretch (5) self.setLayout (lo) class Form (QDialog): def __init__(self,parent=None): QDialog.__init__(self, parent) grid = QGridLayout () tree = QTreeWidget () # Here is the issue? tree.setDragDropMode(QAbstractItemView.InternalMove) tree.setColumnCount(3) for n in range (2): i = QTreeWidgetItem (tree) # create QTreeWidget the sub i i.setText (0, "first" + str (n)) # set the text of the first 0 i.setText (1, "second") for m in range (2): j = QTreeWidgetItem(i) j.setText (0, "child first" + str (m)) #b1 = QCheckBox("push me 0", tree) # this wont work w/ drag by itself either #tree.setItemWidget (tree.topLevelItem(0).child(1), 1, b1) item = InlineEditor(tree) # deal with a combination of multiple controls tree.setItemWidget(tree.topLevelItem(0).child(1), 1, item) grid.addWidget (tree) self.setLayout (grid) app = QApplication ([]) form = Form () form.show () app.exec_ ()

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  • c++ templates and inheritance

    - by Armen Ablak
    Hey, I'm experiencing some problems with breaking my code to reusable parts using templates and inheritance. I'd like to achieve that my tree class and avltree class use the same node class and that avltree class inherits some methods from the tree class and adds some specific ones. So I came up with the code below. Compiler throws an error in tree.h as marked below and I don't really know how to overcome this. Any help appreciated! :) node.h: #ifndef NODE_H #define NODE_H #include "tree.h" template <class T> class node { T data; ... node() ... friend class tree<T>; }; #endif tree.h #ifndef DREVO_H #define DREVO_H #include "node.h" template <class T> class tree { public: //signatures tree(); ... void insert(const T&); private: node<T> *root; //missing type specifier - int assumed. Note: C++ does not support default-int }; //implementations #endif avl.h #ifndef AVL_H #define AVL_H #include "tree.h" #include "node.h" template <class T> class avl: public tree<T> { public: //specific int findMin() const; ... protected: void rotateLeft(node<T> *)const; private: node<T> *root; }; #endif avl.cpp (I tried separating headers from implementation, it worked before I started to combine avl code with tree code) #include "drevo" #include "avl.h" #include "vozlisce.h" template class avl<int>; //I know that only avl with int can be used like this, but currently this is doesn't matter :) //implementations ...

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  • Multiple Components in a JTree Node Renderer & Node Editor

    - by Samad Lotia
    I am attempting to create a JTree where a node has several components: a JPanel that holds a JCheckBox, followed by a JLabel, then a JComboBox. I have attached the code at the bottom if one wishes to run it. Fortunately the JTree correctly renders the components. However when I click on the JComboBox, the node disappears; if I click on the JCheckBox, it works fine. It seems that I am doing something wrong with how the TreeCellEditor is being set up. How could I resolve this issue? Am I going beyond the capabilities of JTree? Here's a quick overview of the code I have posted below. The class EntityListDialog merely creates the user interface. It is not useful to understand it other than the createTree method. Node is the data structure that holds information about each node in the JTree. All Nodes have a name, but samples may be null or an empty array. This should be evident by looking at EntityListDialog's createTree method. The name is used as the text of the JCheckBox. If samples is non-empty, it is used as the contents of the JCheckBox. NodeWithSamplesRenderer renders Nodes whose samples are non-empty. It creates the complicated user interface with the JPanel consisting of the JCheckBox and the JComboBox. NodeWithoutSamplesRenderer creates just a JCheckBox when samples is empty. RendererDispatcher decides whether to use a NodeWithSamplesRenderer or a NodeWithoutSamplesRenderer. This entirely depends on whether Node has a non-empty samples member or not. It essentially functions as a means for the NodeWith*SamplesRenderer to plug into the JTree. Code listing: import java.awt.*; import java.awt.event.*; import java.util.*; import javax.swing.*; import javax.swing.tree.*; public class EntityListDialog { final JDialog dialog; final JTree entitiesTree; public EntityListDialog() { dialog = new JDialog((Frame) null, "Test"); entitiesTree = createTree(); JScrollPane entitiesTreeScrollPane = new JScrollPane(entitiesTree); JCheckBox pathwaysCheckBox = new JCheckBox("Do additional searches"); JButton sendButton = new JButton("Send"); JButton cancelButton = new JButton("Cancel"); JButton selectAllButton = new JButton("All"); JButton deselectAllButton = new JButton("None"); dialog.getContentPane().setLayout(new GridBagLayout()); GridBagConstraints c = new GridBagConstraints(); JPanel selectPanel = new JPanel(new FlowLayout(FlowLayout.LEFT)); selectPanel.add(new JLabel("Select: ")); selectPanel.add(selectAllButton); selectPanel.add(deselectAllButton); c.gridx = 0; c.gridy = 0; c.weightx = 1.0; c.weighty = 0.0; c.fill = GridBagConstraints.HORIZONTAL; dialog.getContentPane().add(selectPanel, c); c.gridx = 0; c.gridy = 1; c.weightx = 1.0; c.weighty = 1.0; c.fill = GridBagConstraints.BOTH; c.insets = new Insets(0, 5, 0, 5); dialog.getContentPane().add(entitiesTreeScrollPane, c); c.gridx = 0; c.gridy = 2; c.weightx = 1.0; c.weighty = 0.0; c.insets = new Insets(0, 0, 0, 0); c.fill = GridBagConstraints.HORIZONTAL; dialog.getContentPane().add(pathwaysCheckBox, c); JPanel buttonsPanel = new JPanel(new FlowLayout(FlowLayout.RIGHT)); buttonsPanel.add(sendButton); buttonsPanel.add(cancelButton); c.gridx = 0; c.gridy = 3; c.weightx = 1.0; c.weighty = 0.0; c.fill = GridBagConstraints.HORIZONTAL; dialog.getContentPane().add(buttonsPanel, c); dialog.pack(); dialog.setVisible(true); } public static void main(String[] args) { EntityListDialog dialog = new EntityListDialog(); } private static JTree createTree() { DefaultMutableTreeNode root = new DefaultMutableTreeNode( new Node("All Entities")); root.add(new DefaultMutableTreeNode( new Node("Entity 1", "Sample A", "Sample B", "Sample C"))); root.add(new DefaultMutableTreeNode( new Node("Entity 2", "Sample D", "Sample E", "Sample F"))); root.add(new DefaultMutableTreeNode( new Node("Entity 3", "Sample G", "Sample H", "Sample I"))); JTree tree = new JTree(root); RendererDispatcher rendererDispatcher = new RendererDispatcher(tree); tree.setCellRenderer(rendererDispatcher); tree.setCellEditor(rendererDispatcher); tree.setEditable(true); return tree; } } class Node { final String name; final String[] samples; boolean selected; int selectedSampleIndex; public Node(String name, String... samples) { this.name = name; this.selected = false; this.samples = samples; if (samples == null) { this.selectedSampleIndex = -1; } else { this.selectedSampleIndex = 0; } } public boolean isSelected() { return selected; } public void setSelected(boolean selected) { this.selected = selected; } public String toString() { return name; } public int getSelectedSampleIndex() { return selectedSampleIndex; } public void setSelectedSampleIndex(int selectedSampleIndex) { this.selectedSampleIndex = selectedSampleIndex; } public String[] getSamples() { return samples; } } interface Renderer { public void setForeground(final Color foreground); public void setBackground(final Color background); public void setFont(final Font font); public void setEnabled(final boolean enabled); public Component getComponent(); public Object getContents(); } class NodeWithSamplesRenderer implements Renderer { final DefaultComboBoxModel comboBoxModel = new DefaultComboBoxModel(); final JPanel panel = new JPanel(); final JCheckBox checkBox = new JCheckBox(); final JLabel label = new JLabel(" Samples: "); final JComboBox comboBox = new JComboBox(comboBoxModel); final JComponent components[] = {panel, checkBox, comboBox, label}; public NodeWithSamplesRenderer() { Boolean drawFocus = (Boolean) UIManager.get("Tree.drawsFocusBorderAroundIcon"); if (drawFocus != null) { checkBox.setFocusPainted(drawFocus.booleanValue()); } for (int i = 0; i < components.length; i++) { components[i].setOpaque(true); } panel.add(checkBox); panel.add(label); panel.add(comboBox); } public void setForeground(final Color foreground) { for (int i = 0; i < components.length; i++) { components[i].setForeground(foreground); } } public void setBackground(final Color background) { for (int i = 0; i < components.length; i++) { components[i].setBackground(background); } } public void setFont(final Font font) { for (int i = 0; i < components.length; i++) { components[i].setFont(font); } } public void setEnabled(final boolean enabled) { for (int i = 0; i < components.length; i++) { components[i].setEnabled(enabled); } } public void setContents(Node node) { checkBox.setText(node.toString()); comboBoxModel.removeAllElements(); for (int i = 0; i < node.getSamples().length; i++) { comboBoxModel.addElement(node.getSamples()[i]); } } public Object getContents() { String title = checkBox.getText(); String[] samples = new String[comboBoxModel.getSize()]; for (int i = 0; i < comboBoxModel.getSize(); i++) { samples[i] = comboBoxModel.getElementAt(i).toString(); } Node node = new Node(title, samples); node.setSelected(checkBox.isSelected()); node.setSelectedSampleIndex(comboBoxModel.getIndexOf(comboBoxModel.getSelectedItem())); return node; } public Component getComponent() { return panel; } } class NodeWithoutSamplesRenderer implements Renderer { final JCheckBox checkBox = new JCheckBox(); public NodeWithoutSamplesRenderer() { Boolean drawFocus = (Boolean) UIManager.get("Tree.drawsFocusBorderAroundIcon"); if (drawFocus != null) { checkBox.setFocusPainted(drawFocus.booleanValue()); } } public void setForeground(final Color foreground) { checkBox.setForeground(foreground); } public void setBackground(final Color background) { checkBox.setBackground(background); } public void setFont(final Font font) { checkBox.setFont(font); } public void setEnabled(final boolean enabled) { checkBox.setEnabled(enabled); } public void setContents(Node node) { checkBox.setText(node.toString()); } public Object getContents() { String title = checkBox.getText(); Node node = new Node(title); node.setSelected(checkBox.isSelected()); return node; } public Component getComponent() { return checkBox; } } class NoNodeRenderer implements Renderer { final JLabel label = new JLabel(); public void setForeground(final Color foreground) { label.setForeground(foreground); } public void setBackground(final Color background) { label.setBackground(background); } public void setFont(final Font font) { label.setFont(font); } public void setEnabled(final boolean enabled) { label.setEnabled(enabled); } public void setContents(String text) { label.setText(text); } public Object getContents() { return label.getText(); } public Component getComponent() { return label; } } class RendererDispatcher extends AbstractCellEditor implements TreeCellRenderer, TreeCellEditor { final static Color selectionForeground = UIManager.getColor("Tree.selectionForeground"); final static Color selectionBackground = UIManager.getColor("Tree.selectionBackground"); final static Color textForeground = UIManager.getColor("Tree.textForeground"); final static Color textBackground = UIManager.getColor("Tree.textBackground"); final JTree tree; final NodeWithSamplesRenderer nodeWithSamplesRenderer = new NodeWithSamplesRenderer(); final NodeWithoutSamplesRenderer nodeWithoutSamplesRenderer = new NodeWithoutSamplesRenderer(); final NoNodeRenderer noNodeRenderer = new NoNodeRenderer(); final Renderer[] renderers = { nodeWithSamplesRenderer, nodeWithoutSamplesRenderer, noNodeRenderer }; Renderer renderer = null; public RendererDispatcher(JTree tree) { this.tree = tree; Font font = UIManager.getFont("Tree.font"); if (font != null) { for (int i = 0; i < renderers.length; i++) { renderers[i].setFont(font); } } } public Component getTreeCellRendererComponent(JTree tree, Object value, boolean selected, boolean expanded, boolean leaf, int row, boolean hasFocus) { final Node node = extractNode(value); if (node == null) { renderer = noNodeRenderer; noNodeRenderer.setContents(tree.convertValueToText( value, selected, expanded, leaf, row, false)); } else { if (node.getSamples() == null || node.getSamples().length == 0) { renderer = nodeWithoutSamplesRenderer; nodeWithoutSamplesRenderer.setContents(node); } else { renderer = nodeWithSamplesRenderer; nodeWithSamplesRenderer.setContents(node); } } renderer.setEnabled(tree.isEnabled()); if (selected) { renderer.setForeground(selectionForeground); renderer.setBackground(selectionBackground); } else { renderer.setForeground(textForeground); renderer.setBackground(textBackground); } renderer.getComponent().repaint(); renderer.getComponent().invalidate(); renderer.getComponent().validate(); return renderer.getComponent(); } public Component getTreeCellEditorComponent( JTree tree, Object value, boolean selected, boolean expanded, boolean leaf, int row) { return getTreeCellRendererComponent( tree, value, true, expanded, leaf, row, true); } public Object getCellEditorValue() { return renderer.getContents(); } public boolean isCellEditable(final EventObject event) { if (!(event instanceof MouseEvent)) { return false; } final MouseEvent mouseEvent = (MouseEvent) event; final TreePath path = tree.getPathForLocation( mouseEvent.getX(), mouseEvent.getY()); if (path == null) { return false; } Object node = path.getLastPathComponent(); if (node == null || (!(node instanceof DefaultMutableTreeNode))) { return false; } DefaultMutableTreeNode treeNode = (DefaultMutableTreeNode) node; Object userObject = treeNode.getUserObject(); return (userObject instanceof Node); } private static Node extractNode(Object value) { if ((value != null) && (value instanceof DefaultMutableTreeNode)) { DefaultMutableTreeNode node = (DefaultMutableTreeNode) value; Object userObject = node.getUserObject(); if ((userObject != null) && (userObject instanceof Node)) { return (Node) userObject; } } return null; } }

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  • Is there a way to replace the Eclipse JDT's code completion list with a multi-level tree?

    - by Uri
    I know that the eclipse code completion widget can be customized to add new suggestions and even to change the order. I'm wondering whether there's a way to replace the current list format (or single-level tree, if this is a tree control) with a tree of multiple levels. Thus, for example, instead of selecting from a list of methods sorted by name, I will select from a category and then from a subcategory, and then from the items. I'm not too familiar with that part of the SDK, but I'd like to know if this is feasible. Thanks!

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