Search Results

Search found 39999 results on 1600 pages for 'php session'.

Page 38/1600 | < Previous Page | 34 35 36 37 38 39 40 41 42 43 44 45  | Next Page >

• Cannot login to ISCSI Target - hangs after sending login details

  - by Frank

  I have an ISCSI target volume, to which i am trying to connect using CentOS Linux server. Everything works fine, but cannot its stuck at login. Here are the steps i am performing: [root@neon ~]# iscsiadm -m node -l iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session20 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session21 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session22 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session23 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session30 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session31 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session78 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session79 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session80 iscsiadm: could not read session targetname: 5 iscsiadm: could not find session info for session81 Logging in to [iface: eql.eth2, target: iqn.2001-05.com.equallogic:0-8a0906-ab4764e0b-55ed2ef5cf350a66-neon105, portal: 10.10.1.1,3260] (multiple) After this step, its stucks, waits for some time and then gives this output: Logging in to [iface: iface1, target: iqn.2001-05.com.equallogic:0-8a0906-ab4764e0b-55ed2ef5cf350a66-neon105, portal: 10.10.1.1,3260] (multiple) iscsiadm: Could not login to [iface: eql.eth2, target: iqn.2001-05.com.equallogic:0-8a0906-ab4764e0b-55ed2ef5cf350a66-neon105, portal: 10.10.1.1,3260]. My iscsi.conf is this: node.startup = automatic node.session.timeo.replacement_timeout = 15 # default 120; RedHat recommended node.conn[0].timeo.login_timeout = 15 node.conn[0].timeo.logout_timeout = 15 node.conn[0].timeo.noop_out_interval = 5 node.conn[0].timeo.noop_out_timeout = 5 node.session.err_timeo.abort_timeout = 15 node.session.err_timeo.lu_reset_timeout = 20 node.session.initial_login_retry_max = 8 # default 8; Dell recommended node.session.cmds_max = 1024 # default 128; Equallogic recommended node.session.queue_depth = 32 # default 32; Equallogic recommended node.session.iscsi.InitialR2T = No node.session.iscsi.ImmediateData = Yes node.session.iscsi.FirstBurstLength = 262144 node.session.iscsi.MaxBurstLength = 16776192 node.conn[0].iscsi.MaxRecvDataSegmentLength = 262144 discovery.sendtargets.iscsi.MaxRecvDataSegmentLength = 32768 node.conn[0].iscsi.HeaderDigest = None node.session.iscsi.FastAbort = Yes Also, in access control, i have given full access to Any IP, Any CHAP user and fixed iscsi initiator name. With same access level, all other volumes on rest of servers are working, except this one.

  Read the article

• Asp.Net: Open a second browser window with new session id

  - by Daniel Brink

  Right google isn't helping me on this one. I need to open a second browser window or tab, but it must have a different session id. Opening the new browser window from my asp.net page is easy, but then it shares the same cookie and thus session ID with the original. So how can I do this? I need the original browser window to keep its cookies and session and the new browser window to have a new session.

  Read the article

• On uploading php page, it is giving warning. Error seems to be of session related

  - by Shantanu Gupta

  Error I tried this page to run on local, it is running perfectly fine but showing me a warning on uploading. What might be the reason. I used session as per given in w3schools.. The session_start() function must appear BEFORE the tag

  Read the article

• CakePHP 1.3.4: EmailComponent error - Undefined property: EmailComponent::$Controller

  - by Kevin S.

  I'm trying to develop an invitation system for my website which runs on CakePHP 1.3.4. I am trying to use the built in EmailComponent to send an email. I'm getting this error (expanded): Notice (8): Undefined property: EmailComponent::$Controller [CORE/cake/libs/controller/components/email.php, line 428] Code | Context */ function _render($content) { $viewClass = $this-Controller-view; $content = array( "", "" ) EmailComponent::_render() - CORE/cake/libs/controller/components/email.php, line 428 EmailComponent::send() - CORE/cake/libs/controller/components/email.php, line 368 UsersController::send_quick_add_email() - APP/controllers/users_controller.php, line 77 UsersController::quick_add() - APP/controllers/users_controller.php, line 104 SinglesResultsController::quick_add() - APP/controllers/singles_results_controller.php, line 63 Dispatcher::_invoke() - CORE/cake/dispatcher.php, line 204 Dispatcher::dispatch() - CORE/cake/dispatcher.php, line 171 [main] - APP/webroot/index.php, line 83 I also get the following, which I can expand if necessary: Notice (8): Trying to get property of non-object [CORE/cake/libs/controller/components/email.php, line 428] Notice (8): Undefined property: EmailComponent::$Controller [CORE/cake/libs/controller/components/email.php, line 433] Notice (8): Trying to get property of non-object [CORE/cake/libs/controller/components/email.php, line 433] Notice (8): Undefined property: View::$webroot [CORE/cake/libs/view/view.php, line 805] Warning (2): Cannot modify header information - headers already sent by (output started at /Applications/MAMP/htdocs/cake/cake/libs/debugger.php:673) [CORE/cake/libs/controller/controller.php, line 746] I think that the EmailComponent object holds a reference to the controller it's being called from. I don't know why it's undefined in this case. Here is the code that fails (specifically, it errors on the call to $this-Email-send()): function send_quick_add_email($email) { if($email) { $this->Email->reset(); $this->Email->to = $email; $this->Email->subject = 'Some subject text'; $this->Email->from = '[email protected]'; $this->Email->template = 'email_template'; $this->set('user', $user); $this->set('token', $token); $this->Email->delivery = 'debug'; $this->Email->send(); } } Ok, for more clarification: The main data I am collecting on the site is results of a game played in meatspace. SinglesResultsController has an action, quick_add, which expects email addresses of people not already registered on the site. If the email addresses aren't associated with Users, UsersController::quick_add is called, which creates an inactive user, and sends an invitation email in UsersController::send_quick_add_email() I think the problem is related to the fact that the email isn't being sent in the first controller initialized (SinglesResultsController). Any thoughts on how to make it work? The Email component is declared at the top of both Controllers.

  Read the article

• Can't i set Session in a class file?

  - by uzay95

  Why session is null in this even if i set: public class HelperClass { public AtuhenticatedUser f_IsAuthenticated(bool _bRedirect) { HttpContext.Current.Session["yk"] = DAO.context.GetById<AtuhenticatedUser>(1); if (HttpContext.Current.Session["yk"] == null) { if (_bRedirect) { HttpContext.Current.Response.Redirect(ConfigurationManager.AppSettings["loginPage"] + "?msg=You have to login."); } return null; } return (AtuhenticatedUser)HttpContext.Current.Session["yk"]; } }

  Read the article

• asp.net state server session - cross appDomain?

  - by newone1

  When using a State server for session, are sessions still appDomain specific? So for example, I have two different IIS applications(virtual directories) on a web server, and they both point to one state server for session. The session guid from the cookie will be the same across requests from both applications, so will the same session be accessible across both of these applications? Thanks.

  Read the article

• Http web request doesn't maintaining session.

  - by Pankaj Mishra

  Hello, I have program where i want to scrap some Useful study material for me. This site site maintaining session key and some other key also. If I trying to go nested page then it will throw me out and showing session out message. I unable to maintaining session key in web request class. so please give me some idea that how can i maintain session in web request class.

  Read the article

• Storing Credit Card Numbers in SESSION - ways around it?

  - by JM4

  I am well aware of PCI Compliance so don't need an earful about storing CC numbers (and especially CVV nums) within our company database during checkout process. However, I want to be safe as possible when handling sensitive consumer information and am curious how to get around passing CC numbers from page to page WITHOUT using SESSION variables if at all possible. My site is built in this way: Step 1) collect Credit Card information from customer - when customer hits submit, the information is first run through JS validation, then run through PHP validation, if all passes he moves to step 2. Step 2) Information is displayed on a review page for customer to make sure the details of their upcoming transaction are shown. Only the first 6 and last 4 of the CC are shown on this page but card type, and exp date are shwon fully. If he clicks proceed, Step 3) The information is sent to another php page which runs one last validation, sends information through secure payment gateway, and string is returned with details. Step 4) If all is good and well, the consumer information (personal, not CC) is stored in DB and redirected to a completion page. If anything is bad, he is informed and told to revisit the CC processing page to try again (max of 3 times). Any suggestions?

  Read the article

• (mySQL) Unable to query 2 tables properly for data

  - by Devner

  I have 2 tables. One is 'page_links' and the other is 'rpp'. Table page_links is the superset of table rpp. The following is the schema of my tables: -- Table structure for table `page_links` -- CREATE TABLE IF NOT EXISTS `page_links` ( `page` varchar(255) NOT NULL, `page_link` varchar(100) NOT NULL, `heading_id` tinyint(3) unsigned NOT NULL, PRIMARY KEY (`page`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; -- -- Dumping data for table `page_links` -- INSERT INTO `page_links` (`page`, `page_link`, `heading_id`) VALUES ('a1.php', 'A1', 8), ('b1.php', 'B1', 8), ('c1.php', 'C1', 5), ('d1.php', 'D1', 5), ('e1.php', 'E1', 8), ('f1.php', 'F1', 8), ('g1.php', 'G1', 8), ('h1.php', 'H1', 1), ('i1.php', 'I1', 1), ('j1.php', 'J1', 8), ('k1.php', 'K1', 8), ('l1.php', 'L1', 8), ('m1.php', 'M1', 8), ('n1.php', 'N1', 8), ('o1.php', 'O1', 8), ('p1.php', 'P1', 4), ('q1.php', 'Q1', 5), ('r1.php', 'R1', 4); -- Table structure for table `rpp` -- CREATE TABLE IF NOT EXISTS `rpp` ( `role_id` tinyint(3) unsigned NOT NULL, `page` varchar(255) NOT NULL, `is_allowed` tinyint(1) NOT NULL, PRIMARY KEY (`role_id`,`page`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; -- -- Dumping data for table `rpp` -- INSERT INTO `rpp` (`role_id`, `page`, `is_allowed`) VALUES (3, 'a1.php', 1), (3, 'b1.php', 1), (3, 'c1.php', 1), (3, 'd1.php', 1), (3, 'e1.php', 1), (3, 'f1.php', 1), (3, 'h1.php', 1), (3, 'i1.php', 1), (3, 'l1.php', 1), (3, 'm1.php', 1), (3, 'n1.php', 1), (4, 'a1.php', 1), (4, 'b1.php', 1), (4, 'q1.php', 1), (5, 'r1.php', 1); WHAT I AM TRYING TO DO: I am trying to query both the above tables (in a single query) in such a way that all the pages from page_links are displayed along with the is_allowed value from rpp for a particular role. For example, I want to get the is_allowed value of all the pages from rpp for role_id = 3 and at the same time, list all the available pages from page_links. A clear example of my expected result would be: page is_allowed role_id ---------------------------------------- a1.php 1 3 b1.php 1 3 c1.php 1 3 d1.php 1 3 e1.php 1 3 f1.php 1 3 g1.php NULL NULL h1.php 1 3 i1.php 1 3 j1.php NULL NULL k1.php NULL NULL l1.php 1 3 m1.php 1 3 n1.php 1 3 o1.php NULL NULL p1.php NULL NULL q1.php NULL NULL r1.php NULL NULL One more example of my desired result could be achieved by doing a LEFT JOIN rpp ON page_links.page = rpp.page but we need to omit using role_id = 3 (or any value) to be able to get that. But I do want to specify the role_id as well and get the results. I need the query to be able to get this result. I would appreciate any replies that could help me with this. If you can suggest me any changes as well to the table(s) design to be able to achieve the desired result, that's good as well. Thanks in advance.

  Read the article

• How to implement session like stackoverflow?

  - by stacker

  I'm implementing this kink of login: http://jaspan.com/improved_persistent_login_cookie_best_practice In this design a new token issued to the user each new login. So it tells me that I need to Now I need to implement a session, for this login. I'd like to implement session like stackoverflow, so people will can have session without login. but for a login there will be always a session. Any ideas how?

  Read the article

• Why does every thread in my application use a different hibernate session?

  - by Ittai

  Hi, I have a web-application which uses hibernate and for some reason every thread (httprequest or other threads related to queueing) uses a different session. I've implemented a HibernateSessionFactory class which looks like this: public class HibernateSessionFactory { private static final ThreadLocal<Session> threadLocal = new ThreadLocal<Session>(); private static Configuration configuration = new AnnotationConfiguration(); private static org.hibernate.SessionFactory sessionFactory; static { try { configuration.configure(configFile); sessionFactory = configuration.buildSessionFactory(); } catch (Exception e) {} } private HibernateSessionFactory() {} public static Session getSession() throws HibernateException { Session session = (Session) threadLocal.get(); if (session == null || !session.isOpen()) { if (sessionFactory == null) { rebuildSessionFactory();//This method basically does what the static init block does } session = (sessionFactory != null) ? sessionFactory.openSession(): null; threadLocal.set(session); } return session; } //More non relevant methods here. Now from my testing it seems that the threadLocal member is indeed initialized only once when the class is first loaded by the JVM but for some reason when different threads access the getSession() method they use different sessions. When a thread first accesses this class (Session) threadLocal.get(); will return null but as expected all other access requests will yeild the same session. I'm not sure how this can be happening as the threadLocal variable is final and the method threadLocal.set(session) is only used in the above context (which I'm 99.9% sure has to yeild a non null session as I would have encountered a NullPointerException at a different part of my app). I'm not sure this is relevant but these are the main parts of my hibernate.cfg.xml file: <hibernate-configuration> <session-factory> <property name="connection.url">someURL</property> <property name="connection.driver_class"> com.microsoft.sqlserver.jdbc.SQLServerDriver</property> <property name="dialect">org.hibernate.dialect.SQLServerDialect</property> <property name="hibernate.connection.isolation">1</property> <property name="hibernate.connection.username">User</property> <property name="hibernate.connection.password">Password</property> <property name="hibernate.connection.pool_size">10</property> <property name="show_sql">false</property> <property name="current_session_context_class">thread</property> <property name="hibernate.hbm2ddl.auto">update</property> <property name="hibernate.cache.use_second_level_cache">false</property> <property name="hibernate.cache.provider_class">org.hibernate.cache.NoCacheProvider</property> <!-- Mapping files --> I'd appreciate any help granted and of course if anyone has any questions I'd be happy to clarify. Ittai

  Read the article

• state server session - cross appDomain?

  - by newone1

  When using a State server for session, are sessions still appDomain specific? So for example, I have two different IIS applications(virtual directories) on a web server, and they both point to one state server for session. The session guid from the cookie will be the same across requests from both applications, so will the same session be accessible across both of these applications? Thanks.

  Read the article

• Session state server saying extended class no serializable

  - by jenson-button-event

  I am storing an object in session state (using local session state server), class def is: [Serializable] public class ExtendedOAuth2Parameters : OAuth2Parameters but the service is still reporting: Unable to serialize the session state. In 'StateServer' and 'SQLServer' mode, ASP.NET will serialize the session state objects, and as a result non-serializable objects or MarshalByRef objects are not permitted. [SerializationException: Type 'Google.GData.Client.OAuth2Parameters' in Assembly 'Google.GData.Client, Version=2.1.0.0, Culture=neutral, PublicKeyToken=04a59ca9b0273830' is not marked as serializable.] How to get around it?

  Read the article

• Any reason to have a session ID within a form?

  - by RadiantHex

  Hi folks, is there any reason for me to place the session ID within a form, as a hidden form field? Thank you everyone!! :)

  Read the article

• With HipHop for PHP, what happens with PHP errors

  - by Matthieu

  HipHop compiles PHP in a C executable. What happens with PHP errors ? Is that harder to debug ? edit : I looked through the documentation but didn't find anything

  Read the article

• How to get an hierarchical php structure from a db table, in php array, or JSON

  - by daniel

  Hi guys, can you please help me. How to get an hierarchical php structure from a db table, in php array, or JSON, but with the following format: [{ "attributes" : {"id" : "111"}, "data" : "Some node title", "children" : [ { "attributes" : { "id" : "555"}, "data" : "A sub node title here" } ], "state" : "open" }, { "attributes" : {"id" : "222"}, "data" : "Other main node", "children" : [ { "attributes" : { "id" : "666"}, "data" : "Another sub node" } ], "state" : "open" }] My SQL table contains the fields: ID, PARENT, ORDER, TITLE Can you please help me with this? I'm going crazy trying to get this. Many thanks in advance. Daniel

  Read the article

• php preg_replace with php code

  - by john

  I have a function that finds a regex thingy, then replaces with php code. I want to have it replace the found regex with php code on the screen, like have it echo out ". except when it echos that in the source, it shows all the

  Read the article

• Non PHP site generates php errors

  - by YsoL8

  Hello. I have this error appearing: Parse error: syntax error, unexpected T_STRING in /home/ondesign/public_html/ywamleicester.org/index.html on line 1 Which I think is a php error. However, the site in question is an out of the box iweb design with no php in it. I have no idea what could be doing it.

  Read the article

• Critiquing PHP-code / PerlCritic for PHP?

  - by jeekl

  I'm looking for an equivalent of PerlCritic for PHP. PerlCritc is a static source code analyzer that qritiques code and warns about everything from unused variables, to unsafe ways to handle data to almost anything. Is there such a thing for PHP that could (preferably) be run outside of an IDE, so that source code analysis could be automated?

  Read the article

• Should i upgradde my server php to php 5.3

  - by Mirage

  I have php 5.2.11 on my server. Should I upgrade to the new PHP 5.3.2? Any new features which can save my life? Any suggesstions?

  Read the article

• What does "<?php=" mean when seen in PHP

  - by joslinm

  Sorry for the silly question, but I ran across code that used: <?=$MAP_OBJECT->printOnLoad();?> <?=$MAP_OBJECT->printMap();?> <?=$MAP_OBJECT->printSidebar();?> Is there anything special about <?php= over <?php or just plain <? ?

  Read the article

• Using Powershell regex to find PHP strings like "<?php eval "

  - by MrGrant

  Hello, I've been trying to find a string in PHP that matches something like this: Currently I've tried something like this; <()\?php eval(^ but it dosen't seem to get the string correctly.

  Read the article

• PHP is making me use <?php instead of <?

  - by John Smith

  Hi, My Apache/PHP installation is making me use instead of . Where is this found in the configuration file so that I don't need to do the former? I'm assuming it's in php.ini, but not sure what it would be called.

  Read the article

• Exception: Zend Extension ./filename.php does not exist

  - by safarov

  When i try to execute php file though CLI this message appear: Exception: Zend Extension ./filename.php does not exist But while run like this /usr/local/bin/php -q -r "echo 'test';" works as expected I tried to figure out what causing this, no success yet. Here some information about enviroment may be usefull: I have eaccelerator installed (working ok). In php.ini: zend_extension="/usr/local/lib/php/extensions/no-debug-non-zts-20100525/eaccelerator.so" eaccelerator.shm_size="16" eaccelerator.cache_dir="/var/cache/eaccelerator" eaccelerator.enable="1" eaccelerator.optimizer="1" eaccelerator.check_mtime="1" eaccelerator.debug="0" eaccelerator.filter="" eaccelerator.shm_ttl="0" eaccelerator.shm_prune_period="0" eaccelerator.shm_only="0" Apache and all sites are working Content of filename.php #!/usr/local/bin/php -q <?php echo 'test'; ?> What is the problem ?

  Read the article

• PHP 5.3.1 Undefined Symbol: OnUpdateLong error on Apache Startup

  - by docgnome

  I'm running Ubuntu 8.04 on this server. I had PHP 5.2 installed via the package manager. I removed it to install PHP 5.3.1 by hand. I built the packages like so ./configure --prefix=/opt/php --with-mysql --with-curl=/usr/bin --with-apxs2=/usr/bin/apxs2 make make install This installed PHP 5.3.1 in /opt/php/ $ php -v PHP 5.3.1 (cli) (built: Dec 7 2009 10:51:14) Copyright (c) 1997-2009 The PHP Group Zend Engine v2.3.0, Copyright (c) 1998-2009 Zend Technologies However, when I try to start Apache I get this. # /etc/init.d/apache2 restart * Restarting web server apache2 apache2: Syntax error on line 185 of /etc/apache2/apache2.conf: Syntax error on line 1 of /etc/apache2/mods-enabled/php5.load: Cannot load /usr/lib/apache2/modules/libphp5.so into server: /usr/lib/apache2/modules/libphp5.so: undefined symbol: OnUpdateLong [fail] Any ideas what's causing this error? All the references I can see have to do with building php5 packages for php4 or the like. PHP4 has never been installed on this machine.

  Read the article

< Previous Page | 34 35 36 37 38 39 40 41 42 43 44 45  | Next Page >