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  • Javascript how many characters replaced in a regex?

    - by macca1
    I am sanitizing an input field and manually getting and setting the caret position in the process. With some abstraction, here's the basic idea: <input type="text" onkeyup"check(this)"> And javascript... function check(element) { var charPosition = getCaretPosition(element); $(element).val( sanitize( $(element).val() ) ); setCaretPosition(element, charPosition); } function sanitize(s) { return s.replace(/[^a-zA-Z0-9\s]/g, ''); } This is working fine except when a character does actually get sanitized, my caret position is off by one. Basically I'd like a way to see if the sanitize function has actually replaced a character (and at what index) so then I can adjust the charPosition if necessary. Any ideas?

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  • What is proper RegEx expression for SWIFT codes?

    - by abatishchev
    I have to filter user input to on my web ASP.NET page: <asp:TextBox runat="server" ID="recipientBankIDTextBox" MaxLength="11" /> <asp:RegularExpressionValidator runat="server" ValidationExpression="?" ControlToValidate="recipientBankIDTextBox" ErrorMessage="*" /> As far is I know SWIFT code must contain 5 or 6 letters and other symbols up to total length 11 are alphanumeric. How to implement such rule properly? TIO

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  • understanding this regex

    - by DarthVader
    I m trying to understand what the following does. ^([^=]+)(?:(?:\\=)(.+))?$ Any ideas? This is being used here. Obviously it s command line parser but i m trying to understand the syntax so i can actually run the program. This is from commandline-jmxclient , they have no documents on setting JMX properties but in their source code, there is such an option, so i just want to understand how i can invoke that method. Matcher m = Client.CMD_LINE_ARGS_PATTERN.matcher(command); if ((m == null) || (!m.matches())) { throw new ParseException("Failed parse of " + command, 0); } this.cmd = m.group(1); if ((m.group(2) != null) && (m.group(2).length() > 0)) this.args = m.group(2).split(","); else this.args = null;

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  • bash: assign grep regex results to array

    - by Ryan
    Hello everyone, I am trying to assign a regular expression result to an array inside of a bash script but I am unsure whether that's possible, or if I'm doing it entirely wrong. The below is what I want to happen, however I know my syntax is incorrect: indexes[4]=$(echo b5f1e7bfc2439c621353d1ce0629fb8b | grep -o '[a-f0-9]\{8\}') such that: index[1]=b5f1e7bf index[2]=c2439c62 index[3]=1353d1ce index[4]=0629fb8b Any links, or advice, would be wonderful :)

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  • Regex optional match in python fails

    - by AaronG
    tickettypepat = (r'MIS Notes:.**(//p//)?.**') retype = re.search(tickettypepat,line) if retype: print retype.group(0) print retype.group(1) Given the input. MIS Notes: //p// Can anyone tell me why group(0) is MIS Notes: //p// and group(1) is returning as None?

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  • cant get regex to work as i want

    - by Jorm
    With this function: function bbcode_parse($str) { $str = htmlentities($str); $find = array( '/\\*\*(.[^*]*)\*\*/is', ); $replace = array( '<b>' ); $str = preg_replace($find, $replace, $str); return $str; } And with text "My name is **bob**" I get in source code Hi my name is <b> Been trying to get this to work for a while now. Would appricate some expert help :)

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  • JS regex and angle brackets

    - by chaz
    Seriously, why can't I parse a string with angle brackets using the Javascript regular expression object? var r = new RegExp(), r; r.compile("\\<div\\>", "g"); r = r.exec("<div>Hello</div>"); //Equals null yo Why does that not work?

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  • get particular string using regex java

    - by hussain
    i want to know how to get the string from group of string String j = "<a href=\"/watch?v=4Qx-lBqOqiQ&feature=popular\" onclick=\"\" onmousedown=\"yt.analytics.urchinTracker(\'/Events/Home/PersonalizedHome/POP/Logged_Out');\" ><span class=\"video-thumb video-thumb-220 \" id=\"video-thumb-4Qx-lBqOqiQ-8821469\"><img src=\"http://i1.ytimg.com/vi/4Qx-lBqOqiQ/hqdefault.jpg\" class=\"vimg220\" alt=\"Dog Squirrel Chasing A Squirrel\" title=\"Dog Squirrel Chasing A Squirrel\" onclick=\";yt.www.watch.watch5.IEshenanigans(event, this)\"><span class=\"video-time\"><span>1:08</span></span><span class=\"video-actions\"><button class=\"yt-uix-button-short yt-uix-button yt-uix-button-arrowbutton\" onclick=\"; return false;\" type=\"button\"> <img class=\"yt-uix-button-arrow\" src=\"http://s.ytimg.com/yt/img/pixel-vfl73.gif\" alt=\"\"> hai</a>"; i want to get the string href=\"/watch?v=4Qx-lBqOqiQ&feature=popular\" and src=\"http://i1.ytimg.com/vi/4Qx-lBqOqiQ/hqdefault.jpg\" thanks and advance

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  • php regex filename

    - by Patrick
    Hi, anyone can help me with a preg_match? I'd like to use php's preg_match to determine if an input is a valid filename or not (only the filename + file extension, not the full path). General rules: 1) filename = a-z, A-Z, 0-9 2) extension = 3 or 4 letters Thank you!

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  • How to get rid of duplicates in regex

    - by Emmanuel Smith
    Suppose I had a string, "cats cats cats and dogs dogs dogs." What regular expression would I use in order to replace that string with,"cats and dogs." i.e. removing duplicates. The expression however must only remove duplicates that follow after each other. For instance: "cats cats cats and dogs dogs dogs and cats cats and dogs dogs" Would return: "cats and dogs and cats and dogs"

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  • Regex: Strip HTML attributes except SRC

    - by Ian Silber
    Hi, I'm trying to write a regular expression that will strip all tag attributes except for the SRC attribute. For example: <p id="paragraph" class="green">This is a paragraph with an image <img src="/path/to/image.jpg" width="50" height="75"/></p> Would be returned as: <p>This is a paragraph with an image <img src="/path/to/image.jpg" /></p> I have a regular expression to strip all attributes, but I'm trying to tweak it to leave in src. Here's what I have so far: <?php preg_replace('/<([A-Z][A-Z0-9]*)(\b[^>]*)>/i', '<$1>', '<html><goes><here>'); Using PHP's preg_replace() for this. Thanks! Ian

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  • Scala capture group using regex

    - by Geo
    Let's say I have this code: val string = "one493two483three" val pattern = """two(\d+)three""".r pattern.findAllIn(string).foreach(println) I expected findAllIn to only return 483, but instead, it returned two483three. I know I could use unapply to extract only that part, but I'd have to have a pattern for the entire string, something like: val pattern = """one.*two(\d+)three""".r val pattern(aMatch) = string println(aMatch) // prints 483 Is there another way of achieving this, without using the classes from java.util directly, and without using unapply?

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  • JavaScript regex refactoring

    - by JamesBrownIsDead
    I'm performing this on a string: var poo = poo .replace(/[%][<]/g, "'<") .replace(/[>][%]/g, ">'") .replace(/[%]\s*[+]/g, "'+") .replace(/[+]\s*[%]/g, "+'"); Given the similar if these statements, can these regexs be comebined somehow?

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  • Finding words strictly starting with $, Regex C#

    - by Anirudh Goel
    I need to find all matches of word which strictly begins with "$" and contains only digits. So I wrote [$]\d+ which gave me 4 matches for $10 $10 $20a a$20 so I thought of using word boundaries using \b: [$]\d+\b But it again matched a$20 for me. I tried \b[$]\d+\b but I failed. I'm looking for saying, ACCEPT ONLY IF THE WORD STARTS WITH $ and is followed by DIGITS. How do I tell IT STARTS WITH $, because I think \b is making it assume word boundaries which means surrounded inside alphanumeric characters. What is the solution?

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  • Search for content in functions with regex

    - by Marlun
    Hello, How would I with regular expression search for functions which contains the use of a global variable without running "global $var" first? The files looks like this: class TestClass { function correctFunc() { global $var; $name = $var->name; } function invalidFuncIWantToFind() { $age = $var->user->age; } } I want to find the function names of all the invalidFuncIWantToFind. At work this would have really speeded up our work but I didn't get how to do it.

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  • python regex of a date in some text, enclosed by two keywords

    - by Horace Ho
    This is Part 2 of this question and thanks very much for David's answer. What if I need to extract dates which are bounded by two keywords? Example: text = "One 09 Jun 2011 Two 10 Dec 2012 Three 15 Jan 2015 End" Case 1 bounding keyboards: "One" and "Three" Result expected: ['09 Jun 2011', '10 Dec 2012'] Case 2 bounding keyboards: "Two" and "End" Result expected: ['10 Dec 2012', '15 Jan 2015'] Thanks!

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  • How to find files according RegEx in C#

    - by bao
    I need to get list of files on some drive with paths that matches specific pattern, for example FA\d\d\d\d.xml where \d is digit (0,1,2..9). So files can have names like FA5423.xml. What is the most efficient name to do this?

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  • regex in textfield

    - by klox
    dear all..i have this code: <script> var str="KD-R435MUN2D"; var matches=str.match(/(EE|[EJU]).*(D)/i); if (matches) { var firstletter = matches [1]; var secondletter = matches [2]; var thirdletter = matches [3]; alert(firstletter + secondletter + thirdletter); }else{ alert (":("); } </script> i want it can control a textfield <input type="text" id="mod">..how must i do?

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  • regex to format a float in php

    - by Itamar Bar-Lev
    I have a PHP function for formatting a float to a given amount of decimal points that uses number_format(), and then removes the unneeded zeros (and also the '.' if possible): $float = number_format($float, $decimalPlaces, '.', ''); for ($i = 0; $i < $decimalPlaces; $i++) { if (substr($float, strlen($float) - 1, strlen($float)) == '0') { $float = substr($float, 0, strlen($float) - 1); } } if (substr($float, strlen($float) - 1, strlen($float)) == '.') { $float = substr($float, 0, strlen($float) - 1); } Is it possible to do so more effectively with a regular expression?

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  • Clean up domain list in Excel - regex / macros?

    - by Tim
    I have a huge spreadsheet of domains that I need to clean up as follows: Remove all http:// (simple replace all - "http://" with "") Remove any www. (simple replace all - "www." with "") Delete any sub-domains (delete the actual row completely, not just the subdomain from the url) Remove anything after the domain extension (i.e. website.com/blah/blahbah/ becomes just website.com (simple replace all - "/*" with "", then replace all "/" with "") So what I'm left with is just a spreadsheet of clean domains like "website.com". I think I've got 1, 2 and 4 sorted (as above), but I'm really struggling with 3. Any ideas? Can I do this with regexp / vba, and actually delete the row completely? Sample data: http://www.scholastic.com/kids/stacks/games/ http://imgworld.teamworkonline.com/ http://topfreegraphics.com/ http://www.workcircle.co.uk/ http://www.healthycanadians.gc.ca/index-eng.php http://gsociology.icaap.org/methods/soft.html Post 1, 2 and 4 would leave me with: scholastic.com imgworld.teamworkonline.com topfreegraphics.com workcircle.co.uk healthycanadians.gc.ca gsociology.icaap.org It's those pesky sub-domains I need to just delete completely, just delete the row. I've realised I can't just search for 2 x ".", because obviously plenty of domain extensions (i.e .co.uk) include that. Any help appreciated.

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  • VBA regex pattern

    - by KeyMs92
    This is probably a simple problem, but unfortunately I wasn't able to get the results I wanted... Say, I have the following line: "Wouldn't It Be Nice" (B. Wilson/Asher/Love) I would have to look for this pattern: " (<any string>) In order to retrieve: B. Wilson/Asher/Love I tried something like "" (([^))]*)) but it doesn't seem to work. Also, I'd like to use Match.Submatches(0) so that might complicate things a bit because it relies on brackets...

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