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  • Relogging a user in with different Spring Security Authorities programmatically

    - by user1331982
    PreReq: User logs in and is given roles got from the database using a custom implementation of userService. i.e. authentication-provider user-service-ref="securityPolicyService" The implemented method loadUserByUsername gets called and the roles are load for the user for the particular club they are logging into, Default one is loaded first time in. The user then click on a different club from the UI and I call a method on a service that gets the new list of authorities for this club. I then perform the following: Object principle = SecurityContextHolder.getContext().getAuthentication().getPrincipal(); SecureMember sm = (SecureMember) principle; Authentication auth = new UsernamePasswordAuthenticationToken(sm, null, newAuthories); <br><br> SecurityContextHolder.getContext().setAuthentication(auth);<br> request.getSession(false).invalidate(); SecureMember extends User from SpringFramework. The problem is the SecureMember authorities are never updated with the new ones. thanks Gary

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  • Application not releasing database connection Spring.net + NHibernate

    - by anupam3m
    Even after successful transaction.Application connection with the database persist.in Nhibernate log it shows Nhibernate Log 2010-05-21 14:45:08,428 [Worker] [0] DEBUG NHibernate.Impl.SessionImpl [(null)] <(null) - executing flush 2010-05-21 14:45:08,428 [Worker] [0] DEBUG NHibernate.Impl.ConnectionManager [(null)] <(null) - registering flush begin 2010-05-21 14:45:08,428 [Worker] [0] DEBUG NHibernate.Impl.ConnectionManager [(null)] <(null) - registering flush end 2010-05-21 14:45:08,428 [Worker] [0] DEBUG NHibernate.Impl.SessionImpl [(null)] <(null) - post flush 2010-05-21 14:45:08,428 [Worker] [0] DEBUG NHibernate.Impl.SessionImpl [(null)] <(null) - before transaction completion 2010-05-21 14:45:08,428 [Worker] [0] DEBUG NHibernate.Impl.ConnectionManager [(null)] <(null) - aggressively releasing database connection 2010-05-21 14:45:08,428 [Worker] [0] DEBUG NHibernate.Connection.ConnectionProvider [(null)] <(null) - Closing connection 2010-05-21 14:45:08,428 [Worker] [0] DEBUG NHibernate.Impl.SessionImpl [(null)] <(null) - transaction completion 2010-05-21 14:45:08,428 [Worker] [0] DEBUG NHibernate.Transaction.AdoTransaction [(null)] <(null) - running AdoTransaction.Dispose() 2010-05-21 14:45:08,428 [Worker] [0] DEBUG NHibernate.Impl.SessionImpl [(null)] <(null) - closing session 2010-05-21 14:45:08,428 [Worker] [0] DEBUG NHibernate.Impl.BatcherImpl [(null)] <(null) - running BatcherImpl.Dispose(true) Underneath given is my dataconfiguration file -- Risco.Rsp.Ac.RMAC.Mapping Risco.Rsp.Ac.Logging.Appenders -- Please help me out with this issue.Thanks

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  • Sending data back to Controller Spring-MVC

    - by Umesh Awasthi
    I am not sure if this is a complex problem but as a starting person this seems a bit complex to me. I have an object based on which i need to show some values on the UI and let user select some of them, i need to send data back to another controller when user click on the submit button.Here is the structure of my data object public class PrsData{ private Map<String, List<PrsCDData>> prsCDData; } public class PrsCDData{ private Map<String, Collection<ConfiguredDesignData>> configuredDesignData; } public ConfiguredDesignData{ // simple fields } I have set the object in model before showing the view like model.addAttribute("prsData", productData.getPrData()); In the form i have following settings <form:form method="post" commandName="prsData" action="${addProductToCartAction}" > <form:hidden path="prsCDData['${prsCDDataMap.key}'] [${status.index}].configuredDesignData['${configuredDesignDataMap.key}'] [${configuredDesignDataStatus.index}].code"/> <form:hidden path="prsCDData['${prsCDDataMap.key}'] [${status.index}].configuredDesignData['${configuredDesignDataMap.key}'] [${configuredDesignDataStatus.index}].description"/> </form:form> This is what i have at AddProductToCartController public String addToCart(@RequestParam("productCodePost") final String code, @ModelAttribute("prsData") final PrsData prsData, final Model model, @RequestParam(value = "qty", required = false, defaultValue = "1") final long qty) On submitting the form i am getting following exception org.springframework.beans.NullValueInNestedPathException: Invalid property 'prsCDData[Forced][0]' of bean class [com.product.data.PrsData]: Cannot access indexed value of property referenced in indexed property path 'prsCDData[Forced][0]': returned null It seems like its trying to access the values on this controller while i am trying to send value to that controller and trying to create same object with selected values Can any one tell me where i am doing wrong and what i need to take care of

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  • Why my onsubmitg is not firing - Spring

    - by GigaPr
    Hi, i have a controller public class EditUserController extends BaseController { public EditUserController() { setCommandClass(User.class); setCommandName("editaUser"); } public ModelAndView handleRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { ModelAndView modelAndView = new ModelAndView("editUser"); String id = request.getParameter("id"); if(!id.isEmpty()) { User user = this.userServiceImplementation.get(Integer.parseInt(id)); modelAndView.addObject("editaUser", user); } return modelAndView; } } and the view <form:form method="POST" commandName="editaUser" cssClass="addUserForm"> <div class="floatL"> <div class="padding5"> <div class="fieldContainer"> <strong>First Name:</strong>&nbsp; </div> <form:errors path="firstName" cssClass="error"/> <form:input path="firstName" cssClass="textArea" /> </div> <div class="padding5"> <div class="fieldContainer"> <strong>Last Name:</strong>&nbsp; </div> <form:errors path="lastName" cssClass="error"/> <form:input path="lastName" cssClass="textArea" /> </div> </div> <div class="floatR"> <div class="padding5"> <div class="fieldContainer"> <strong>Username:</strong>&nbsp; </div> <form:errors path="username" cssClass="error"/> <form:input path="username" cssClass="textArea" /> </div> <div class="padding5"> <div class="fieldContainer"> <strong>Password</strong>&nbsp; </div> <form:errors path="password" cssClass="error"/> <form:input path="password" cssClass="textArea"/> </div> </div> <input type="submit" class="floatR" value="Save" > </form:form> and the bean definition looks like <bean name="/editUser.htm" class="com.rssFeed.mvc.EditUserController"> <property name="userServiceImplementation" ref="userServiceImplementation"/> <property name="commandName" value="editaUser" /> <property name="successView" value="users"/> <property name="sessionForm" value="true"/> </bean> I populate the view using the querystring but i would lke to update the record in the database on click of the submit button. i tried to insert a on submit method protected ModelAndView onSubmit(Object command, BindException bindException) throws Exception { return new ModelAndView(getSuccessView()); } but it never fires What is the problem i do not get it?? thanks

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  • Spring MVC simple case

    - by coure2011
    Trying to understand a sample code... I am returning a modelview successfully from my AthuenticationController like this modelAndView = new ModelAndView("redirect:/home/"); .... return modelAndView; and my browser url is changed to /home/ but its showing a 404 page I have a HomePageController and it has methods @RequestMapping(method = RequestMethod.GET) public String loadHome and @RequestMapping(method = RequestMethod.GET, value = "/main") public String reloadHome but System.out.println("Message") is not executing in any of the above methods. When authenticated I want to load a home.jsp page? It is in WEB-INF/jsp/...

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  • Spring Web Flow

    - by cedric
    hi. I am really having a problem about what to use as an alternative for web flow. I have read that not all functionalities should be handled by web flow. Only those which needs complex xstate management. For those easy stuffs like just login, editing or deleting records what will I use as an alternative for web flow?

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  • Spring MVC 3.1 How to access HttpSession in Custom Authentication Provider (which implements AuthenticationProvider)

    - by user1506231
    My application calls a web service during the Authentication process (as shown in code below). How can I save some information in HttpSession during this process? This information like customer-account-number will be used in various other places in the application after the user is logged in. Is it possible to pass HttpSession parameter to the MyServiceManager's static login method? public class MyAuthenticationManager implements AuthenticationProvider { @Override public boolean supports(Class<? extends Object> authentication) { return authentication.equals(UsernamePasswordAuthenticationToken.class); } @Override public Authentication authenticate(Authentication authentication) { //MyServiceManager.login - makes a call to web service if(MyServiceManager.login(authentication.getName(), authentication.getCredentials().toString(), XXX_HTTP_SESSION_XXX)) { List<GrantedAuthority> authorities = new ArrayList<GrantedAuthority> (); authorities.add(new GrantedAuthorityImpl("ROLE_USER")); authorities.add(new GrantedAuthorityImpl("ROLE_SUPERVISOR")); return new UsernamePasswordAuthenticationToken(authentication.getName(), authentication.getCredentials(),authorities); } else { return null; } } }

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  • Spring Controller's URL request mapping not working as expected

    - by Atharva
    I have created a mapping in web.xml something like this: <servlet> <servlet-name>dispatcher</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>dispatcher</servlet-name> <url-pattern>/about/*</url-pattern> </servlet-mapping> In my controller I have something like this: import org.springframework.stereotype.Controller; @Controller public class MyController{ @RequestMapping(value="/about/us", method=RequestMethod.GET) public ModelAndView myMethod1(ModelMap model){ //some code return new ModelAndView("aboutus1.jsp",model); } @RequestMapping(value="/about", method=RequestMethod.GET) public ModelAndView myMethod2(ModelMap model){ //some code return new ModelAndView("aboutus2.jsp",model); } } And my dispatcher-servlet.xml has view resolver like: <mvc:annotation-driven/> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver" p:viewClass="org.springframework.web.servlet.view.JstlView" p:prefix="/WEB-INF/jsp/" p:suffix=".jsp"/> To my surprise: request .../about/us is not reaching to myMethod1 in the controller. The browser shows 404 error. I put a logger inside the method but it isn't printing anything, meaning, its not being executed. .../about works fine! What can be the done to make .../about/us request work? Any suggestions?

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  • Spring annotation-based container configuration context:include & exclude filters

    - by lisak
    Hey, first off I point to the similar question. I spent more than an hour to set this up, but PathMatchingResourcePatternResolver still scans everything. I have one common.xml (that is imported from specific.xml) and a specific.xml bean definition file. The context is loaded from specific.xml. In common.xml there is this element: <context:component-scan base-package="cz.instance.transl"> <context:exclude-filter type="aspectj" expression="cz.instance.transl.model..* &amp;&amp; cz.instance.transl.service..* &amp;&amp; cz.instance.transl.hooks..*"/> </context:component-scan> Where classes in packages like cz.instance.transl.service.* should not be subject of scanning, but everything else in here cz.instance.transl.* should be scanned through. But PathMatchingResourcePatternResolver marks everything as matching resources. It is the same with regex. BTW: in xml style configuration, one can have many components that share a common.xml beans via "import resource" when loading context. How this is done when Annotation-based container configuration is used ?

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  • Spring + hibernate + shared remote tomcat environment setup

    - by hrushi
    I could set up the environment in my local host, But i have no choice like deploying my war file as its shared server, my admin ask me to extract the war file and upload through ftp. Now the problem is I am new to remote server. Please guide me with the remote environment file system and complete directory structure in remote tomcat. And how to use FTP for deployment ? Thanks in advance Hrushi

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  • Mapping restful ajax requests to spring

    - by Diones
    I have this piece of code: @RequestMapping(value = "/test.json", method = RequestMethod.GET) @ResponseStatus(HttpStatus.OK) public @ResponseBody Object[] generateFile(@RequestParam String tipo) { Object[] variaveis = Variavel.getListVariavelByTipo(tipo); return variaveis; } As far as I know it should take a request to test.json?tipo=H and return the JSON representation of Variavel[], however when I make such request I get: HTTP Status 406 - type Status report message descriptionThe resource identified by this request is only capable of generating responses with characteristics not acceptable according to the request "accept" headers () By using the following function I can get the expected json: @RequestMapping(value = "/teste.json") public void testeJson(Model model, @RequestParam String tipo) { model.addAttribute("data", Variavel.getListVariavelByTipo("H")); } What I'm doing wrong?

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  • Is Spring hard compared to Ruby on Rails?

    - by johnny
    If I have no to little experience in either of them, but know enough Java and Ruby to be comfortable, is one framework harder to learn than the other? Is one easier to use for the beginner on these? I know it is hard to answer. Just looking for general thoughts on it.

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  • Spring singleton lifecycle

    - by EugeneP
    Reading this When a bean is a singleton, only one shared instance of the bean will be managed and all requests for beans with an id or ids matching that bean definition will result in that one specific bean instance being returned. Will be managed... What does that mean? If there's only one object, than any modification to this object will result in that every another attempt to get this bean will return a modified instance??

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  • Spring Web: Correct way to have a single default ViewResolver

    - by wuntee
    What is the best way to have every request be sent to a single ViewResolver - specifically in this case a JsonView? Was thinking this: <bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.json.MappingJacksonJsonView" /> <property name="prefix" value="*" /> </bean> but, is there something better/easier?

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