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  • How do I resolve a plugin conflict in Eclipse?

    - by Jason Thompson
    I'd like to upgrade my Helios installation of Eclipse to Indigo. When I do, I get the following message: Cannot complete the install because of a conflicting dependency. Software being installed: Eclipse IDE for Java EE Developers 1.4.2.20120213-0813 (epp.package.jee 1.4.2.20120213-0813) Software currently installed: Oracle GlassFish Server Tools 1.6.1.201009290929 (oracle.eclipse.tools.helios.glassfish.feature.group 1.6.1.201009290929) So my first thought was to simply uninstall GlassFish. For the life of me, I can't figure out how and where to go to do this. I went to Help-About Eclipse...-Installation Details. The only place that it looks like I can uninstall stuff is in the "Installed Software" tab. I do not see the Oracle Glassfish package anywhere. If I go to "Feature" or "Plug-ins", I can find it just fine, but there is no option to uninstall. So my next thought was to upgrade Glassfish. So I put the indigo repo in there, but I still get the same message when trying to update. Any ideas?

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  • Does Jquery and Mootools usually have conflict if both are used on a webpage? [migrated]

    - by Charming Prince
    I have this website am designing, i tried using mootools 1.31 to animate some of the div boxes when clicked or when the mouse hover rounds it, to shows the content. the thing is that it doesn't seem to work on the webpage, but if i try the same script on a blank webpage it works, am thinking probably it's because i have Jquery 1.52 on the same page and maybe both scripts are conflicting with each other because, if i remove the Jquery, the Mootools works. What should be my option, because i need the Jquery to do some validations for me, so i can't remove it completely. Here are the codes <script> //-vertical var mySlide = new Fx.Slide('test'); $('slidein').addEvent('click', function(e){ e = new Event(e); mySlide.slideIn(); e.stop(); }); $('slideout').addEvent('click', function(e){ e = new Event(e); mySlide.slideOut(); e.stop(); }); $('toggle').addEvent('click', function(e){ e = new Event(e); mySlide.toggle(); e.stop(); }); $('hide').addEvent('click', function(e){ e = new Event(e); mySlide.hide(); e.stop(); }); </script> here's the HTML <html> <h3 class="section">Fx.Slide Vertical</h3> <a id="slideout" href="#">slideout</a> | <a id="slidein" href="#">slidein</a> | <a id="toggle" href="#"> toggle</a> | <a id="hide" href="#">hide</a> <div id="test"> Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua. Ut enim ad mi nim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat. Duis aute irure dolor in reprehenderit in voluptate velit esse cillum dolore eu fugiat nulla pariatur. Excepteur sint occaecat cupidatat non proident, sunt in culpa qui officia deserunt mollit anim id est laborum. </div> Here's the CSS #test { background: #222; color: #fff; padding: 10px; margin: 20px; border: 10px solid pink; } #test2 { background: #222; color: #fff; padding: 10px; margin: 20px; border: 10px solid pink; } Am using the exact same code supplied by Mootools in their own example, if i do this on a blank webpage it works but incorporated into my own webpage, it doesn't, and my own page just have the script tag of the Jquery in the head section of the HTML.

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  • Why is insertion into my tree faster on sorted input than random input?

    - by Juliet
    Now I've always heard binary search trees are faster to build from randomly selected data than ordered data, simply because ordered data requires explicit rebalancing to keep the tree height at a minimum. Recently I implemented an immutable treap, a special kind of binary search tree which uses randomization to keep itself relatively balanced. In contrast to what I expected, I found I can consistently build a treap about 2x faster and generally better balanced from ordered data than unordered data -- and I have no idea why. Here's my treap implementation: http://pastebin.com/VAfSJRwZ And here's a test program: using System; using System.Collections.Generic; using System.Linq; using System.Diagnostics; namespace ConsoleApplication1 { class Program { static Random rnd = new Random(); const int ITERATION_COUNT = 20; static void Main(string[] args) { List<double> rndTimes = new List<double>(); List<double> orderedTimes = new List<double>(); rndTimes.Add(TimeIt(50, RandomInsert)); rndTimes.Add(TimeIt(100, RandomInsert)); rndTimes.Add(TimeIt(200, RandomInsert)); rndTimes.Add(TimeIt(400, RandomInsert)); rndTimes.Add(TimeIt(800, RandomInsert)); rndTimes.Add(TimeIt(1000, RandomInsert)); rndTimes.Add(TimeIt(2000, RandomInsert)); rndTimes.Add(TimeIt(4000, RandomInsert)); rndTimes.Add(TimeIt(8000, RandomInsert)); rndTimes.Add(TimeIt(16000, RandomInsert)); rndTimes.Add(TimeIt(32000, RandomInsert)); rndTimes.Add(TimeIt(64000, RandomInsert)); rndTimes.Add(TimeIt(128000, RandomInsert)); string rndTimesAsString = string.Join("\n", rndTimes.Select(x => x.ToString()).ToArray()); orderedTimes.Add(TimeIt(50, OrderedInsert)); orderedTimes.Add(TimeIt(100, OrderedInsert)); orderedTimes.Add(TimeIt(200, OrderedInsert)); orderedTimes.Add(TimeIt(400, OrderedInsert)); orderedTimes.Add(TimeIt(800, OrderedInsert)); orderedTimes.Add(TimeIt(1000, OrderedInsert)); orderedTimes.Add(TimeIt(2000, OrderedInsert)); orderedTimes.Add(TimeIt(4000, OrderedInsert)); orderedTimes.Add(TimeIt(8000, OrderedInsert)); orderedTimes.Add(TimeIt(16000, OrderedInsert)); orderedTimes.Add(TimeIt(32000, OrderedInsert)); orderedTimes.Add(TimeIt(64000, OrderedInsert)); orderedTimes.Add(TimeIt(128000, OrderedInsert)); string orderedTimesAsString = string.Join("\n", orderedTimes.Select(x => x.ToString()).ToArray()); Console.WriteLine("Done"); } static double TimeIt(int insertCount, Action<int> f) { Console.WriteLine("TimeIt({0}, {1})", insertCount, f.Method.Name); List<double> times = new List<double>(); for (int i = 0; i < ITERATION_COUNT; i++) { Stopwatch sw = Stopwatch.StartNew(); f(insertCount); sw.Stop(); times.Add(sw.Elapsed.TotalMilliseconds); } return times.Average(); } static void RandomInsert(int insertCount) { Treap<double> tree = new Treap<double>((x, y) => x.CompareTo(y)); for (int i = 0; i < insertCount; i++) { tree = tree.Insert(rnd.NextDouble()); } } static void OrderedInsert(int insertCount) { Treap<double> tree = new Treap<double>((x, y) => x.CompareTo(y)); for(int i = 0; i < insertCount; i++) { tree = tree.Insert(i + rnd.NextDouble()); } } } } And here's a chart comparing random and ordered insertion times in milliseconds: Insertions Random Ordered RandomTime / OrderedTime 50 1.031665 0.261585 3.94 100 0.544345 1.377155 0.4 200 1.268320 0.734570 1.73 400 2.765555 1.639150 1.69 800 6.089700 3.558350 1.71 1000 7.855150 4.704190 1.67 2000 17.852000 12.554065 1.42 4000 40.157340 22.474445 1.79 8000 88.375430 48.364265 1.83 16000 197.524000 109.082200 1.81 32000 459.277050 238.154405 1.93 64000 1055.508875 512.020310 2.06 128000 2481.694230 1107.980425 2.24 I don't see anything in the code which makes ordered input asymptotically faster than unordered input, so I'm at a loss to explain the difference. Why is it so much faster to build a treap from ordered input than random input?

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  • How to create a complete binary tree of height 'h' using Python?

    - by Jack
    Here is the node structure class Node: def __init__(self, data): # initializes the data members self.left = None self.right = None self.parent = None self.data = data complete binary tree Definition: A binary tree in which every level, except possibly the deepest, is completely filled. At depth n, the height of the tree, all nodes must be as far left as possible. -- http://www.itl.nist.gov/div897/sqg/dads/HTML/completeBinaryTree.html I am looking for an efficient algorithm.

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  • In GWT, how to known from a SelectionEvent in a Tree if the Shift button is pressed

    - by Vinze
    Hi, I try in GWT to create a Tree with multiple selection for the nodes and ran into a problem similar to this question http://stackoverflow.com/questions/1411752/shift-key-in-gwt. When a selectionEvent is raised from the Tree, I would like to know if the Shift key is pressed or not. SelectionHandler<TreeItem> getSelectionHandler() { return new SelectionHandler<TreeItem>(){ @Override public void onSelection(SelectionEvent<TreeItem> event) { // is shift key pressed ? } }; } The solution in the question above cannot apply in this case as the SelectionHandler class does not inherit from DOMEvent and then does not have a getNativeEvent() function. I tried a dirty solution by adding keyDownEventHandler and keyUpEventHandler to the Tree with a boolean flag but the handlers are only called when the focus is on the tree so this doesn't work. Is there a simple solution (or just a solution even if it's not simple) ? Thanks.

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  • How can I find the common ancestor of two nodes in a binary tree?

    - by Siddhant
    The Binary Tree here is not a Binary Search Tree. Its just a Binary Tree. The structure could be taken as - struct node { int data; struct node *left; struct node *right; }; The maximum solution I could work out with a friend was something of this sort - Consider this binary tree (from http://lcm.csa.iisc.ernet.in/dsa/node87.html) : The inorder traversal yields - 8, 4, 9, 2, 5, 1, 6, 3, 7 And the postorder traversal yields - 8, 9, 4, 5, 2, 6, 7, 3, 1 So for instance, if we want to find the common ancestor of nodes 8 and 5, then we make a list of all the nodes which are between 8 and 5 in the inorder tree traversal, which in this case happens to be [4, 9, 2]. Then we check which node in this list appears last in the postorder traversal, which is 2. Hence the common ancestor for 8 and 5 is 2. The complexity for this algorithm, I believe is O(n) (O(n) for inorder/postorder traversals, the rest of the steps again being O(n) since they are nothing more than simple iterations in arrays). But there is a strong chance that this is wrong. :-) But this is a very crude approach, and I'm not sure if it breaks down for some case. Is there any other (possibly more optimal) solution to this problem?

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  • Can anyone provide Java program for btree or b+tree???

    - by rohit
    Hi, I am doing a project in which i require btree or b+tree data structure. but its not an important part of project. it would take my time to write a code for it. I googled it but didn't get anything.... So, can anyone provide java code for btree or b+tree implementation (with insert, delete, search algorithms)?????? it should accept string as input and form btree or b+tree of these string.

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  • How does Git know which Index blob to add to a tree?

    - by drozzy
    In Pro Git Ch9 the author says: Git normally creates a tree by taking the state of your staging area or index and writing a tree object from it. My question is how does git know which of two consequitive index entries to create the Tree object from? For example: $ echo 'First change' > one.txt $ git add one.txt $ find .git/objects -type f .git/objects/1f/755a7fffe4 //first index entry $ echo 'Second change' > one.txt $ git add one.txt $ find .git/objects -type f .git/objects/2d/234asdf2 //second index entry $ git commit -a -m "Initial commit" $ git cat-file master^{tree} 100644 blob 2d234asdf2 one.txt //How did it know not to take 1f755?? Does it just look at the blob timestamps? Also - what happens to the first blob created - no one is referencing it. Does it just get destroyed or forgotten?

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  • What has the most efficient intersection test against an AABB tree - OBB, Cylinder or Capsule?

    - by identitycrisisuk
    I'm currently trying to find collisions in 3D between a tighter volume than an AABB and a tree of AABB volumes. I just need to know whether they are intersecting, no closest distance or collision response. An OBB, Cylinder or Capsule would all roughly fit these purposes but Cylinder and Capsule were the first thing I thought of, which I have found little information about detecting intersections online. Am I right in thinking that they would always be more complex to perform Separating Axis Tests on even though they might seem like simpler shapes? I figure by the time I get my head around SAT for curved shapes I could have done the thing with OBBs but I wanted to find out for sure.

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  • What does it mean for SVN "to pollute the local source tree"?

    - by asd
    I'm reading "Professional Team Foundation Server 2010" by Wrox, and in an advantages/disadvantages list, the said: "Like CVS, SVN makes use of .svn directories inside the source folders to store state of the local working copy, and to allow synchronization with the server. However, it can have the affect of polluting the local source tree, and can cause performance issues wiht very large projects or files." What does the bit about pollution mean? I've used SVN for C# & ASP.NET projects for a long time and haven't encountered any problems. What probably does this quote think I should have been watching out for?

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  • File audit in Linux: how to watch directory tree for deletions?

    - by FractalizeR
    Hello. I have a forum script running on server and somehow small number of attachments begin to get lost. I want to find out what is deleting them and at what time. How can I setup Linux auditd (auditctl) to watch directory tree (attachments are stored inside multi-level directory tree) to watch for file deletions there? May be I should use some other tool for this?

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  • When to use HTTP status code 404 in an API

    - by Sybiam
    I am working on a project and after arguing with people at work for about more than a hour. I decided to know what people on stack-exchange might say. We're writing an API for a system, there is a query that should return a tree of Organization or a tree of Goals. The tree of Organization is the organization in which the user is present, In other words, this tree should always exists. In the organization, a tree of goal should be always present. (that's where the argument started). In case where the tree doesn't exist, my co-worker decided that it would be right to answer response with status code 200. And then started asking me to fix my code because the application was falling apart when there is no tree. I'll try to spare flames and fury. I suggested to raise a 404 error when there is no tree. It would at least let me know that something is wrong. When using 200, I have to add special check to my response in the success callback to handle errors. I'm expecting to receive an object, but I may actually receive an empty response because nothing is found. It sounds totally fair to mark the response as a 404. And then war started and I got the message that I didn't understand HTTP status code schema. So I'm here and asking what's wrong with 404 in this case? I even got the argument "It found nothing, so it's right to return 200". I believe that it's wrong since the tree should be always present. If we found nothing and we are expecting something, it should be a 404. More info, I forgot to add the urls that are fetched. Organizations /OrgTree/Get Goals /GoalTree/GetByDate?versionDate=... /GoalTree/GetById?versionId=... My mistake, both parameters are required. If any versionDate that can be parsed to a date is provided, it will return the closes revision. If you enter something in the past, it will return the first revision. If by Id with a id that doesn't exists, I suspect it's going to return an empty response with 200. Extra Also, I believe the best answer to the problem is to create default objects when organizations are created, having no tree shouldn't be a valid case and should be seen as an undefined behavior. There is no way an account can be used without both trees. For that reasons, they should be always present. also I got linked this (one similar but I can't find it) http://viswaug.files.wordpress.com/2008/11/http-headers-status1.png

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  • How to speed up calculation of length of longest common substring?

    - by eSKay
    I have two very large strings and I am trying to find out their Longest Common Substring. One way is using suffix trees (supposed to have a very good complexity, though a complex implementation), and the another is the dynamic programming method (both are mentioned on the Wikipedia page linked above). Using dynamic programming The problem is that the dynamic programming method has a huge running time (complexity is O(n*m), where n and m are lengths of the two strings). What I want to know (before jumping to implement suffix trees): Is it possible to speed up the algorithm if I only want to know the length of the common substring (and not the common substring itself)?

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  • How to traverse a Btree?

    - by Phenom
    I have a Btree and I'm trying to figure out how traverse it so that the keys are displayed ascending order. All I can figure out is that this can be done with a recursive function. What's the pseudo-code to do it?

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  • Using Lambda Expressions trees with IEnumerable

    - by Loathian
    I've been trying to learn more about using Lamba expression trees and so I created a simple example. Here is the code, this works in LINQPad if pasted in as a C# program. void Main() { IEnumerable<User> list = GetUsers().Where(NameContains("a")); list.Dump("Users"); } // Methods public IEnumerable<User> GetUsers() { yield return new User{Name = "andrew"}; yield return new User{Name = "rob"}; yield return new User{Name = "chris"}; yield return new User{Name = "ryan"}; } public Expression<Func<User, bool>> NameContains(string namePart) { return u => u.Name.Contains(namePart); } // Classes public class User { public string Name { get; set; } } This results in the following error: The type arguments for method 'System.Linq.Enumerable.Where(System.Collections.Generic.IEnumerable, System.Func)' cannot be inferred from the usage. Try specifying the type arguments explicitly. However if I just substitute the first line in main with this: IEnumerable<User> list = GetUsers().Where(u => u.Name.Contains("a")); It works fine. Can tell me what I'm doing wrong, please?

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  • Move node in adjacency list

    - by Industrial
    Hi everyone, I am working on an adjacency list with mySQL and can not (atleast by myself) do the thinking needed to make a decent enough query to be able to move a set of nodes (together with eventual children nodes) around. The table has following columns: id name left right Thanks a lot!

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  • Git - tidying up a repo

    - by Simon Woods
    Hi I have got my repo into a bit of a state and want to be able to work my way out of it The repo looks a bit like this (A1, B1, C1 etc are obviously commits) A1 ---- A2 ---- A3 ---- A4 ---- A5 ---- A6 ---- A7 ---- A8 / (from a remote repo) B1 ---- B2 --------------------------------- | \ \ C1 ---------------------------------C2 \ / D1 --- D2 --- D3 --- D4 --- D5 --- D6 Ideally I'd like to be able to remove all the revisions (with rebase?) on the B, C and D lines (I'm loathed to say branches simply because there are now no local branches on these lines except ref branches to the remote repo) and try to merge in the remote repo again, perhaps in a better way. I'd be grateful of any suggestions as to how to get rid of all these commits. Could I ask that any answers use revision SHA1s rather than branch names. I thought that somehow I'd be able to revert the merge into A7 but can't quite work out how to do it I hope that is sufficient information. Many thx Simon

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  • Intersecting boundaries with lucene

    - by Silvio Donnini
    I'm using Lucene, and I'm trying to find a way to index and retrieve documents that have a ranged property. For example I have: Document 1: Price:[30 TO 50] Document 2: Price:[45 TO 60] Document 3: Price:[60 TO 70] And I would like to search for all the documents whose ranges intersect a specific interval, in the above example, if I search for Price in [55 TO 65] I should get Document 2 and Document 3 as results. I don't think NumericRangeQueries alone would do the trick, I need to work on the index with something similar to R-trees, but are they implemented in Lucene? Also, I suppose that what I need should be a subclass of MultiTermQuery, because the query Price in [55 TO 65] has two boundaries, but I don't see anything suitable among MultiTermQuery's subclasses. Any help is appreciated, thanks, Silvio P.S. I'm using Lucene 2.9.0, but I can update to the latest release if needed.

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