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  • Combining two queries on same table

    - by user1830856
    I've looked through several previous questions but I am struggling to apply the solutions to my specific example. I am having trouble combining query 1 and query 2. My query originally returned (amongst other details) the values "SpentTotal" and "UnderSpent" for all members/users for the current month. My issue has been adding two additional columns to this original quert that will return JUST these two columns (Spent and Overspent) but for the previous months data Original Query #1: set @BPlanKey = '##CURRENTMONTH##' EXECUTE @RC = Minimum_UpdateForPeriod @BPlanKey SELECT cm.clubaccountnumber, bp.Description , msh.PeriodMinObligation, msh.SpentTotal, msh.UnderSpent, msh.OverSpent, msh.BilledDate, msh.PeriodStartDate, msh.PeriodEndDate, msh.OverSpent FROM MinimumSpendHistory msh INNER JOIN BillPlanMinimums bpm ON msh.BillingPeriodKey = @BPlanKey and bpm.BillPlanMinimumKey = msh.BillPlanMinimumKey INNER JOIN BillPlans bp ON bp.BillPlanKey = bpm.BillPlanKey INNER JOIN ClubMembers cm ON cm.parentmemberkey is null and cm.ClubMemberKey = msh.ClubMemberKey order by cm.clubaccountnumber asc, msh.BilledDate asc Query #2, query of all columns for PREVIOUS month, but I only need two (spent and over spent), added to the query from above, joined on the customer number: set @BPlanKeyLastMo = '##PREVMONTH##' EXECUTE @RCLastMo = Minimum_UpdateForPeriod @BPlanKeyLastMo SELECT cm.clubaccountnumber, bp.Description , msh.PeriodMinObligation, msh.SpentTotal, msh.UnderSpent, msh.OverSpent, msh.BilledDate, msh.PeriodStartDate, msh.PeriodEndDate, msh.OverSpent FROM MinimumSpendHistory msh INNER JOIN BillPlanMinimums bpm ON msh.BillingPeriodKey = @BPlanKeyLastMo and bpm.BillPlanMinimumKey = msh.BillPlanMinimumKey INNER JOIN BillPlans bp ON bp.BillPlanKey = bpm.BillPlanKey INNER JOIN ClubMembers cm ON cm.parentmemberkey is null and cm.ClubMemberKey = msh.ClubMemberKey order by cm.clubaccountnumber asc, msh.BilledDate asc Big thank you to any and all that are willing to lend their help and time. Cheers! AJ CREATE TABLE MinimumSpendHistory( [MinimumSpendHistoryKey] [uniqueidentifier] NOT NULL, [BillPlanMinimumKey] [uniqueidentifier] NOT NULL, [ClubMemberKey] [uniqueidentifier] NOT NULL, [BillingPeriodKey] [uniqueidentifier] NOT NULL, [PeriodStartDate] [datetime] NOT NULL, [PeriodEndDate] [datetime] NOT NULL, [PeriodMinObligation] [money] NOT NULL, [SpentTotal] [money] NOT NULL, [CurrentSpent] [money] NOT NULL, [OverSpent] [money] NULL, [UnderSpent] [money] NULL, [BilledAmount] [money] NOT NULL, [BilledDate] [datetime] NOT NULL, [PriorPeriodMinimum] [money] NULL, [IsCommitted] [bit] NOT NULL, [IsCalculated] [bit] NOT NULL, [BillPeriodMinimumKey] [uniqueidentifier] NOT NULL, [CarryForwardCounter] [smallint] NULL, [YTDSpent] [money] NOT NULL, [PeriodToAccumulateCounter] [int] NULL, [StartDate] [datetime] NOT NULL,

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  • Filtering two arrays to avoid Inf/NaN values

    - by Gacek
    I have two arrays of doubles of the same size, containg X and Y values for some plots. I need to create some kind of protection against Inf/NaN values. I need to find all that pairs of values (X, Y) for which both, X and Y are not Inf nor NaN If I have one array, I can do it using lambdas: var filteredValues = someValues.Where(d=> !(double.IsNaN(d) || double.IsInfinity(d))).ToList(); Now, for two arrays I use following loop: List<double> filteredX=new List<double>(); List<double> filteredX=new List<double>(); for(int i=0;i<XValues.Count;i++) { if(!double.IsNan(XValues[i]) && !double.IsInfinity(XValues[i]) && !double.IsNan(YValues[i]) && !double.IsInfinity(YValues[i]) ) { filteredX.Add(XValues[i]); filteredY.Add(YValues[i]); } } Is there any way of filtering two arrays at the same time using LINQ/Lambdas, as it was done for single array?

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  • accessing values in two dimensional arrays

    - by BrainLikeADullPencil
    In some code I'm trying to learn from, the Maze string below is turned into an array (code not shown for that) and saved in the instance variable @maze. The starting point of the Maze is represented by the letter 'A' in that Maze, which can be accessed at @maze[1][13]---row 1, column 13. However, the code I'm looking at uses @maze[1][13,1] to get the A, which you can see returns the same result in my console. If I do @maze[1][13,2], it returns the letter "A " with two blank spaces next to it, and so on. [13,3] returns "A " with three blank spaces. Does the 2 in [13,2] mean, "return two values starting at [1][13]? If so, why? Is this some feature of arrays or two dimensional arrays that I don't get? [20] pry(#<Maze>):1> @maze[1][13] => "A" [17] pry(#<Maze>):1> @maze[1][13,1] => "A" [18] pry(#<Maze>):1> @maze[1][13,2] => "A " [19] pry(#<Maze>):1> @maze[1][13,3] => "A " Maze String MAZE1 = %{##################################### # # # #A # # # # # # # # # ####### # ### # ####### # # # # # # # # # # # ##### # ################# # ####### # # # # # # # # # ##### ##### ### ### # ### # # # # # # # # # # # # B# # # # # # # # ##### ##### # # ### # # ####### # # # # # # # # # # # # # # ### ### # # # # ##### # # # ##### # # # # # # # # #####################################}

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  • Why is joining two vectors simply not working?

    - by Jim
    I have two vectors of MyObj structs. MyObj is defined as follows: struct MyObj { float x, y; unsigned int data[8]; unsigned int tmp[1]; MyObj(const MyObj &m) { x = m.x; y = m.y; tmp[0] = 0; for (int i = 0; i < 8; ++i) { data[i] = m.data[i]; } } }; I then have two vectors... vector<MyObj> v1; vector<MyObj> v2; // both get data eventually. v1.insert(v1.end(), v2.begin(), v2.end()); v2 has 3535004 elements in my experiment. v1 is similarly sized. I've also tried building a new vector and just using .push_back to build it from both vectors. Essentially, when I try to merge the two vectors I just get an error from visual studio saying "Debug error! R6010, abort() has been called". Very non-useful... So my question is: what could be causing this error, and how can I solve it? Thank you

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  • Combining two exe files

    - by Sophia
    Here's some background to my problem: I have a project in Visual C++ 2006 and a project in in Visual C++ 2010 Express. Both compiles to form an exe file each. I cannot convert my 2006 project to 2010 because I get a lot of "unable to load project" errors. I also cannot port my 2010 project code to 2006 (I always get errors no matter what I try, something to do with libraries). My final solution requires me to only have ONE executable. Is there anything I can do to achieve that? I've done some quick search on Google and found there to be exe joiners, but I've also heard that those things are often used to make malware. For reference, I am working with "dummy" clients, and therefore want to simplify things on their end as much as possible. Thus, having them executing one exe is better than having them execute two. Also, I do not wish for their antivirus to go haywire because I used some program to join two exe together. What do? Edit: The two project files do different things. For example, the project in VS2006 one sets up a server, and the project in VS2010 one grabs info on the user's OS. The code for the "server", I think, has a lot of dependencies and for some reason cannot convert to Visual c++ 2010. The code for "grabbing" requires some newer libraries and compiling options, and would not work if I port to 2006.

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  • How to merge two didctionaries in C# with duplicates

    - by user320587
    Hi, Is there a way in C# to merge two dictionaries? I have two dictionaries that may has the same keys, but I am looking for a way to merge them so, in the end there is a dictionary with one key and the values from both the dictionaries merged. I found the following code but it does not handle duplicates. Dictionary Mydictionary<string, string[]> = new Dictionary<string, string[]>(); Mydictonary.Union(secondDictionary).ToDictionary( pair => pair.Key, pair => pair.Value);

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  • Windows7 hardlink over two different drives

    - by Sandro
    I am trying to create a hardlink on my C drive that points to a file on my D drive. I open up a terminal with Administrator privileges and try the following: C:\Users\sandro>mklink /H _vimrc D:\sandro-desktop\.vimrc The error that I get is: The system cannot move the file to a different disk drive. When I try a softlink I get the issue that for some reason changes to the link contents aren't reflected on the targeted file. Thank you!

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  • Database theory - relationship between two tables

    - by iansinke
    I have a database with two tables - let's call them Foo and Bar. Each foo may be related to any number of bars, and each bar may be related to any number of foos. I want to be able to retrieve, with one query, the foos that are associated with a certain bar, and the bars that are associated with a certain foo. My question is, what is the best way of recording these relationships? Should I have a separate table with records of each relationship (e.g. two columns, foo and bar)? Should the foo table have a column for a list of bars, and vice versa? Is there another option that I'm overlooking? I'm using SQL Server, if that makes a difference.

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  • Java Compare Two Lists

    - by agazerboy
    Hi All, Thanks for stoping to help me :) I have a question, may be for some of you, it will be a basic question :) I have two lists ( not java lists, you can say two columns) For example **List 1** **Lists 2** milan hafil dingo iga elpha binga hafil mike meat dingo iga neeta.peeta What I want ! I want that it returns me that how many elements are same. For this example it should be 3 and it should return me similar values of both list and different values too. Should I use hashmap if yes then what method to get my result? Please help P.S: It is not a school assignment :) So if you just guide me it will be enough

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  • Sendmail - Multiple Domains, One Box - Blocking One Or Two Domains

    - by TangoOversway
    I have a number of domains hosted at a web hosting service. They use sendmail to handle incoming email. I have six domains on this service (which we can call aaa.com, bbb.com and so on). Each email account has the same name and one email box. In other words, [email protected], [email protected], [email protected] and all the others go into one box, /var/spool/mail/tango, where my email program on my desktop picks it up. I have done very little work in sendmail. I haven't had to, and I've been warned it's a steep learning curve. But now I'm running into an issue. I was in a business situation where, for years, my email address was on the website for aaa.com. (We won't go into why this was necessary - it wasn't my preference and it's in the past.) Now I'm using [email protected] instead of [email protected]. I was getting about 1,000 or more pieces of spam a day, but SpamAssassin and my own email program caught about 75% of that. (Which still left stuff to delete.) Now, after checking, I see that 90% or more goes to [email protected], the one that was on the web for years. I'd like to deactivate [email protected] and possibly [email protected] and [email protected], but want to keep using [email protected]. Remember, email to tango at any of these domains will go into one email box. I've had people tell me that sendmail can be configured so I can deactivate [email protected] (and other domains) and still use [email protected] (and others, if I want to). In other words, I can configure sendmail to use this account on some domains and not others. One of the people who was teling me this was in tech support at the hosting service. But I wrote to tech support with a work order to do this and now I'm told it can't be done. I can modify config files myself on this account if needed, but I was hoping to just let them do it. (I love delegation -- it means I spend more time doing my stuff.) Is it possible to keep an email account active on one domain and not others with sendmail, when all domains are hosted on the same server? Is there a name for this process or setting? Any information would be helpful - either pointers to instructions so I can do it, or enough info so I can tell tech support, "This is where to look, and it can be done, so please pass my request on to someone who works with sendmail and knows how to do it." Is this something sendmail can do?

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  • Why can’t two programs access my webcam simultaneously?

    - by qdii
    I first launch cheese and my webcam turns on. I then run vlc to grab the output of /dev/video0 but it fails with: [0x7f3ea40012e8] v4l2 demux error: cannot set input 0: Device or resource busy [0x7f3ea40012e8] v4l2 demux error: cannot set input 0: Device or resource busy [0x7f3ea4002168] v4l2 access error: cannot set input 0: Device or resource busy [0x7f3ea4002168] v4l2 access error: cannot set input 0: Device or resource busy [0x7f3eb4000b78] main input error: open of `v4l2:///dev/video0' failed Whatever pair of video programs I run (skype, cheese, vlc, etc.), the result is always the same: the second program can no longer use the webcam when the first one has already grabbed the output. However I find it curious as video4linux states: In general, V4L2 devices can be opened more than once. When this is supported by the driver, users can for example start a "panel" application to change controls like brightness or audio volume, while another application captures video and audio. My webcam is seen in lspci as 058f:a014 Alcor Micro Corp. Asus Integrated Webcam, but I don’t even know what the underlying driver is, so I can’t check whether my problem is driver-related or not. Any input would be more than welcome!

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  • Homoscedascity test for Two-Way ANOVA

    - by aL3xa
    I've been using var.test and bartlett.test to check basic ANOVA assumptions, among others, homoscedascity (homogeniety, equality of variances). Procedure is quite simple for One-Way ANOVA: bartlett.test(x ~ g) # where x is numeric, and g is a factor var.test(x ~ g) But, for 2x2 tables, i.e. Two-Way ANOVA's, I want to do something like this: bartlett.test(x ~ c(g1, g2)) # or with list; see latter: var.test(x ~ list(g1, g2)) Of course, ANOVA assumptions can be checked with graphical procedures, but what about "an arithmetic option"? Is that manageable? How do you test homoscedascity in Two-Way ANOVA?

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  • Homoscedascity test for Two-Way ANOVA

    - by aL3xa
    I've been using var.test and bartlett.test to check basic ANOVA assumptions, among others, homoscedascity (homogeniety, equality of variances). Procedure is quite simple for One-Way ANOVA: bartlett.test(x ~ g) # where x is numeric, and g is a factor var.test(x ~ g) But, for 2x2 tables, i.e. Two-Way ANOVA's, I want to do something like this: bartlett.test(x ~ c(g1, g2)) # or with list; see latter: var.test(x ~ list(g1, g2)) Of course, ANOVA assumptions can be checked with graphical procedures, but what about "an arithmetic option"? Is that, at all, manageable? How do you test homoscedascity in Two-Way ANOVA?

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  • One Linux server has two timer

    - by garconcn
    The time on one of our Linux box is very weird. Whenever I call date 3 times, the 4th call will give a wrong time(usually 1 hour later). I have setup cron to sync with ntp server. We have 20+ similar servers, only this one has this problem. Any idea? Thanks. Linux 2.6.18-6-686 #1 SMP Thu Aug 20 21:56:59 UTC 2009 i686 GNU/Linux :~# date Fri Jun 11 17:00:51 PDT 2010 :~# date Fri Jun 11 17:00:52 PDT 2010 :~# date Fri Jun 11 17:00:53 PDT 2010 :~# date Fri Jun 11 18:14:12 PDT 2010 :~# date Fri Jun 11 17:00:55 PDT 2010 :~# date Fri Jun 11 17:00:56 PDT 2010 :~# date Fri Jun 11 17:00:56 PDT 2010 :~# date Fri Jun 11 18:14:15 PDT 2010 :~# date Fri Jun 11 17:00:58 PDT 2010 :~# date Fri Jun 11 17:00:58 PDT 2010 :~# date Fri Jun 11 17:00:59 PDT 2010 :~# date Fri Jun 11 18:14:18 PDT 2010 :~# date Fri Jun 11 17:01:01 PDT 2010 :~# date Fri Jun 11 17:01:01 PDT 2010 :~# date Fri Jun 11 17:01:02 PDT 2010 :~# date Fri Jun 11 18:14:21 PDT 2010 :~# date Fri Jun 11 17:01:03 PDT 2010 :~# date Fri Jun 11 17:01:04 PDT 2010 :~# date Fri Jun 11 17:01:05 PDT 2010

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  • Configuring VLAN's on two HP procurve switches

    - by pan
    Trying to route a new ISP (Microwave link) from one of my out buildings to my computer room and hence my firewall. Old ISP came direct into firewall. In the outbuilding the Microwave modem connects with cat5 to HP Procurve 2524 switch. Because this ISP is coming through my internal network, I plan on using a new vlan called "airspeed" only for this ISP traffic. Up until now I've just been using the Default_vlan on both HP switches (4108 + 2524). So far I've been unable to ping from my laptop to the ISP modem both of which are on the new vlan 2 ("Airspeed"). No traffic needs to cross from vlan 2 to vlan 1 so I've left the ports as untagged. I've used the subnet provide from my ISP as the new vlan 2 subnet. Can anybody see what I'm doing wrong here? I've added the configuration of both switch below. Rough diagram: Microwave modem (Gateway IP 77.75.00.49) | HP 2524 switch (port 24) | HP 2524 switch fibre link | HP 4108GL switch fibre link | HP 4108GL switch (port D1) | Laptop configured with IP 77.75.00.50 (for testing but will be connected to firewall) And my 4108GL config: ; J4865A Configuration Editor; Created on release #G.07.21 hostname "HP ProCurve Switch 4108GL" cdp run module 1 type J4864A module 2 type J4862B module 3 type J4862B module 4 type J4862B ip default-gateway 128.1.146.50 snmp-server community "public" Unrestricted snmp-server host 128.1.146.51 "public" Not-INFO snmp-server host 128.1.146.38 "public" vlan 1 name "DEFAULT_VLAN" untagged A1-A3,B1-B24,C1-C24,D2-D24 ip address 128.1.146.203 255.255.0.0 no untagged D1 exit vlan 2 name "Airspeed" untagged D1 ip address 77.75.00.51 255.255.255.248 exit Finally my 2524 config: ; J4813A Configuration Editor; Created on release #F.04.08 hostname "HP ProCurve Switch 2524" cdp run ip default-gateway 0.0.0.0 snmp-server community "public" Unrestricted snmp-server host 128.1.146.51 "public" Not-INFO snmp-server host 128.1.146.51 "public" snmp-server host 128.1.146.38 "public" vlan 1 name "DEFAULT_VLAN" untagged 1-23,25-26 no untagged 24 ip address 128.1.146.204 255.255.0.0 exit vlan 2 name "Airspeed" untagged 24 ip address 77.75.00.51 255.255.255.248 exit no aaa port-access authenticator active

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  • Virtualbox two networks slow

    - by Petr Marek
    I am running an Ubuntu server guest on Win 7 guest, and am running a webrick server (RoR dev). If I have just a host-only network, everything works fine and the browser response is instant. However, if I add a second network (NAT), so that the server can connect to the internet (for various updates etc.), the host-to-guest access gets really slow. I can't use the bridge connection. I am using the port 3000 (RoR Webrick server) and connecting to the guest via internet browser on this port (eg http://192.168.56.102:3000). Any idea, what could be causing this? If I ping the IP from host console, I get < 0ms. Here are the settings (relevant info is in english; Povoleno vše is Everything is allowed):

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  • Extending my desktop across two monitors with Nvidia Geforce 8800 GT

    - by Vega Sera
    When I played my old computer before I got this one, I was able to use the horizontal span. (Nvidia Geforce 6200 I believe) However, with this new computer, using vista and the 8800, the horizontal span option is gone, and all I have is dual veiw, which doesn't suit my needs. I play World of Warcraft on both my monitors, using CT_Viewport to keep my character and my veiwport on a single screen, while the majority of my addons lie on my other monitor. The problem with dual view is that the WoW will only stay on my primary monitor. Horizontal span would fix this easily, but there is no option for it. Any help regarding this?

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  • Bidirectional real-time sync of large file tree between two distant linux servers

    - by dlo
    By large file tree I mean about 200k files, and growing all the time. A relatively small number of files are being changed in any given hour though. By bidirectional I mean that changes may occur on either server and need to be pushed to the other, so rsync doesn't seem appropriate. By distant I mean that the servers are both in data centers, but geographically remote from each other. Currently there are only 2 servers, but that may expand over time. By real-time, it's ok for there to be a little latency between syncing, but running a cron every 1-2 minutes doesn't seem right, since a very small fraction of files may change in any given hour, let alone minute. EDIT: This is running on VPS's so I might be limited on the kinds of kernel-level stuff I can do. Also, the VPS's are not resource-rich, so I'd shy away from solutions that require lots of ram (like Gluster?). What's the best / most "accepted" approach to get this done? This seems like it would be a common need, but I haven't been able to find a generally accepted approach yet, which was surprising. (I'm seeking the safety of the masses. :) I've come across lsyncd to trigger a sync at the filesystem change level. That seems clever though not super common, and I'm a bit confused by the various lsyncd approaches. There's just using lsyncd with rsync, but it seems this could be fragile for bidirectionality since rsync doesn't have a notion of memory (eg- to know whether a deleted file on A should be deleted on B or whether it's a new file on B that should be copied to A). lipsync appears to be just a lsyncd+rsync implementation, right? Then there's using lsyncd with csync2, like this: http://www.axivo.com/community/threads/lightning-fast-synchronization-with-csync2-and-lsyncd.121/ ... I'm leaning towards this approach, but csync2 is a little quirky, though I did do a successful test of it. I'm mostly concerned that I haven't been able to find a lot of community confirmation of this method. People on here seem to like Unison a lot, but it seems that it is no longer under active development and it's not clear that it has an automatic trigger like lsyncd. I've seen Gluster mentioned, but maybe overkill for what I need? UPDATE: fyi- I ended up going with the original solution I mentioned: lsyncd+csync2. It seems to work quite well, and I like the architectural approach of having the servers be very loosely joined, so that each server can operate indefinitely on its own regardless of the link quality between them.

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  • Handling two WebException's properly

    - by baron
    Hi Everyone, I am trying to handle two different WebException's properly. Basically they are handled after calling WebClient.DownloadFile(string address, string fileName) AFAIK, so far there are two I have to handle, both WebException's: The remote name could not be resolved (i.e. No network connectivity to access server to download file) (404) File not nound (i.e. the file doesn't exist on the server) There may be more but this is what I've found most important so far. So how should I handle this properly, as they are both WebException's but I want to handle each case above differently. This is what I have so far: try { using (var client = new WebClient()) { client.DownloadFile("..."); } } catch(InvalidOperationException ioEx) { if (ioEx is WebException) { if (ioEx.Message.Contains("404") { //handle 404 } if (ioEx.Message.Contains("remote name could not") { //handle file doesn't exist } } } As you can see I am checking the message to see what type of WebException it is. I would assume there is a better or a more precise way to do this? Thanks

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  • Compare two NTP servers

    - by David Turner
    Hi, I want to compare the time used by our internal servers against time.microsoft.com. Is there an easy way to do this? Basically a third party sends me messages stamped with a time that has been synced iwth time.microsoft.com, unfortunately our servers are using a different time server, so I want to calculate if there is a significant difference between the our NTP synced time, and theirs. Is there a simple way to accurately compare times? regards, David.

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  • mySQL - query to combine two tables

    - by W.Gerick
    Hi there, I have two tables. The first one holds information about cities: Locations: locID | locationID | locationName | countryCode | 1 | 2922239 | Berlin | de | 2 | 291074 | Paris | fr | 3 | 295522 | Orlando | us | 3 | 292345 | Tokyo | jp | There is a second table, which holds alternative names for locations. There might be NO alternative name for a location in the Locations table: AlternateNames: altNameID | locationID | alternateName | 1 | 2922239 | Berlino | 2 | 2922239 | Berlina | 3 | 291074 | Parisa | 4 | 291074 | Pariso | 5 | 295522 | Orlandola | 6 | 295522 | Orlandolo | What I would like to get is the locationID, name and the countryCode of a location for a location name search like "Berlin", or "Ber": | locationID | name | countryCode | | 2922239 | Berlin | de | However, if the user searches for "Berlino", I would like to get the alternateName back: | locationID | name | countryCode | | 2922239 | Berlino | de | The "locationName" has a higher priority than the alternateName, if the searchterm matches both. I can't figure out how to build a query to do that. Since the name can come from one of the two tables, it seems quite difficult to me. Any help is really appreciated!

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  • Can I split an IEnumerable into two by a boolean criteria without two queries?

    - by SFun28
    Folks, Is it possible to split an IEnumerable into two IEnumerables using LINQ and only a single query/linq statement? In this way, I would avoid iterating through the IEnumerable twice. For example, is it possible to combine the last two statements below so allValues is only traversed once? IEnumerable<MyObj> allValues = ... List<MyObj> trues = allValues.Where( val => val.SomeProp ).ToList(); List<MyObj> falses = allValues.Where( val => !val.SomeProp ).ToList();

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  • CVS: command-line diff on a remote CVS server between two HEAD revs

    - by Gugussee
    My CVS-fu is not very strong anymore (after years of SVN'ing and now Mercurial'ing). I'm trying to do a diff between two revisions of the HEAD branch (everything is in the HEAD anyway). I received an IDE already set up to use a :pserver:myname@cvsserver:port/cvs/project CVS. I'm on Windows XP. I do not want to use the IDE (the goal here is to learn CVS a bit more). Apparently I cannot login using SSH to the CVS server. How can I run a remote CVS diff between two HEAD revs using the command line? P.S: I am new here, mod me up so I can comment etc. :)

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