Search Results

Search found 11785 results on 472 pages for 'password protection'.

Page 382/472 | < Previous Page | 378 379 380 381 382 383 384 385 386 387 388 389  | Next Page >

  • uitextfield secure

    - by D_R
    I have a UITexetField with "Secure" option enabled in InterfaceBuilder (used to enter a password). Then I try to read, what the user entered. (void)textFieldDidEndEditing:(UITextField *)textField{ NSString *txt = textField.text; int a = 0; } It works fine with iOS 5 but since I use it in iOS6, this method no longer works - neither in simulator, nor at the real device. It was called, but textField.text returns always an empty string. With other UITextFields, without "Secure" option, it works fine. Could somebody help me ?

    Read the article

  • Is it possible to authenticate user manually with oauth2

    - by iixi
    I want to authenticate a user with oauth2 to access google drive. I can get the access token required when using AccountManager to retrieve an account and then get the token with: mgr.blockingGetAuthToken(account, ApiConst.DRIVE_AUTH_SCOPE, true); But I want the user to be able to authenticate by providing username and password instead of using the account added to the phone. Is this possible? EDIT So I have tried to implement the authorization in a WebView. I followed this example. I have extracted the code request parameter but the code used to retrieve the access token seems to be deprecated and not compatible with the packages used by Google Drive SDK. This is the code used to retrieve the access token in the example: AccessTokenResponse accessTokenResponse = new GoogleAuthorizationCodeGrant(new NetHttpTransport(), new JacksonFactory(), OAuth2ClientCredentials.CLIENT_ID, OAuth2ClientCredentials.CLIENT_SECRET, code, OAuth2ClientCredentials.REDIRECT_URI).execute(); Can this be done in some other way or should I just give up?

    Read the article

  • [MySQL] Optimize Query

    - by bordeux
    Hello. I have problem with optimize this query: SET @SEARCH = "dokumentalne"; SELECT SQL_NO_CACHE `AA`.`version` AS `Version` , `AA`.`contents` AS `Contents` , `AA`.`idarticle` AS `AdressInSQL` , `AA` .`topic` AS `Topic` , MATCH (`AA`.`topic` , `AA`.`contents`) AGAINST (@SEARCH) AS `Relevance` , `IA`.`url` AS `URL` FROM `xv_article` AS `AA` INNER JOIN `xv_articleindex` AS `IA` ON ( `AA`.`idarticle` = `IA`.`adressinsql` ) INNER JOIN ( SELECT `idarticle` , MAX( `version` ) AS `version` FROM `xv_article` WHERE MATCH (`topic` , `contents`) AGAINST (@SEARCH) GROUP BY `idarticle` ) AS `MG` ON ( `AA`.`idarticle` = `MG`.`idarticle` ) WHERE `IA`.`accepted` = "yes" AND `AA`.`version` = `MG`.`version` ORDER BY `Relevance` DESC LIMIT 0 , 30 Now, this query using ^ 20 seconds. How to optimize this? EXPLAIN gives this: 1 PRIMARY AA ALL NULL NULL NULL NULL 11169 Using temporary; Using filesort 1 PRIMARY ALL NULL NULL NULL NULL 681 Using where 1 PRIMARY IA ALL accepted NULL NULL NULL 11967 Using where 2 DERIVED xv_article fulltext topic topic 0 1 Using where; Using temporary; Using filesort This is example server with my data: user: bordeux_4prog password: 4prog phpmyadmin: http://phpmyadmin.bordeux.net/ chive: http://chive.bordeux.net/

    Read the article

  • What is the proper design of storing temporary users? [closed]

    - by Mendy
    In SO site both real users and temporary users can add a new questions. I assume each user type has a different table. My question is how can I attach the question to the right user? I assuming the temp users have their own table from the following reasons: Temp users don't have all the data that real users have. like: email, password, and all users details. On the other hand, temp users are a lot more then real users. So it make more sense to have they in their own table.

    Read the article

  • Are there any alternative to the header(); function ?

    - by Simon
    The thing is, I have a log-in page. And, when user enters Username & Password, they must be re-directed to success/failure page. Now, I have placed a "header('location:welcome.php');" after mysql rows are returned. But, it is giving me Header already sent errors, and I don't know much about PHP to do anything about it, let alone understand why it is happening. So, how to you transfer a user to another page after log-in data is verified? Same problem is happening with register, post, comment and search functions in my site.

    Read the article

  • having problems using Zend_Db_Table_Abstract::createRow()

    - by Gootik
    Hey, I have built a model that extends Zend_Db_Table_Abstract and I can't figure out why I can't use createRow(); here is my code: class Model_User extends Zend_Db_Table_Abstract { public function createUser() { $row = $this->createRow(); $row->name = 'test'; $row->save(); } } and in a controller I use: $userModel = new Model_User(); $userModel->createUser(); which when run displays an error An error occurred Application error here is my setup in application.ini resources.db.adapter = "pdo_mysql" resources.db.params.host = "localhost" resources.db.params.username = "root" resources.db.params.password = "pass" resources.db.params.dbname = "app_db" resources.db.isDefaultTableAdapter = true I am sure that my user/pass/dbname is correct. I would appreciate it if you point me in the right direction.

    Read the article

  • Using the same cookie in two logins

    - by cer9ss
    Hi everyone, I need your help I've a MVC project that uses Jquery, where I've implemented a mechanism of "Remember Me" using cookies to save, clear and retrieve the login and password. I also have two screens where the user does the login. I want that both logins manipulate the same cookie. I've got to implement it, but I've realized that each one has a different behaviour. I mean, the cookie's value I save in the first login is not the same than the value that retrieves the second login (when I open it). In other words, if I mark "remind me" on the first login, it isn't reflected on the second login and viceversa. What can I do to make that both of them manipulate and read the same values from the same cookie? Is it possible? PS: For this situations I'm using the same web navigator: Firefox or IE. Thanks in advance

    Read the article

  • Convert JSON data into String

    - by san6086
    Hi I am converting JSON data into String. Please find the JSON data below. I am facing an issue where in the system is unable to convert NULL values into string. Therefore, I am getting the following error: can't convert nil into String (TypeError) JSON DATA: {"success":true,"message":null,"data":null} Code Used: c = Curl::Easy.new(Configuration.fetch("<URL where we can find the above JSON DATA and nothing else>")) # c.follow_location = true # c.http_auth_types = :basic # c.username = Configuration.fetch('auth_user', false) # c.password = Configuration.fetch('auth_pass', false) # c.headers["User-Agent"] = 'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.17 (KHTML, like Gecko) Chrome/24.0.1312.52 Safari/537.17' # c.perform result=JSON.parse(c) puts result["Success"] Please help.

    Read the article

  • Why my query is not working?

    - by Poma
    my website has PHP command: mysql_query("SELECT * FROM users WHERE id=" . $_GET["id"]) or die(mysql_error()); When I enter URL http://example.com/index.php?id=1;%20UPDATE%20users%20SET%20password=123%20WHERE%20id=1 I get following error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'UPDATE users SET password=abc WHERE id=1' at line 1 But in phpmyamin query executes successfully. What's wrong here? Why it doesn't execute in browser?

    Read the article

  • Offer access to a private page without login

    - by dccarmo
    So I've been struggling with a nice and easy way to allow users to access a private page without asking them to fill out a login/password form. What I'm thinking about using right now is for each private page I generate a uniqueid (using php uniqid function) and then send the URI to the user. He would access his private page as "www.mywebsite.com/private_page/13ffa2c4a". I think it's relatively safe and user friendly, without asking too much of information. I thought maybe when the user access this page it would ask for it's e-mail just to be sure, but the best would be nothing at all. Is this really safe? I mean not internet banking safe, but enough for a simple access? Do you think there's a better solution? Thanks. :)

    Read the article

  • How to create arrayType for WSDL in Python (using suds)?

    - by Uri
    Environment: Python v2.6.2 suds v0.3.7 The WSDL (server) I work with, have the following schema sub-sections (I tried to write it clearly using plain text) - [ sub-section #1 ] searchRequest: (searchRequest){ userIdentification = (userIdentification){ username = "" password = "" } itineraryArr = (itineraryArray){ _arrayType = "" _offset = "" _id = "" _href = "" _arrayType = "" } ... ... [ sub-section #2 ] itinerary: (itinerary){ departurePoint = (locationPoint){ locationId = None radius = None } arrivalPoint = (locationPoint){ locationId = None radius = None } ... ... There is no problem with 'userIdentification' (which is a "simple" type) But, 'itineraryArr' is an array of 'itinerary', and I don't know how to use python to create XML array. I tried few combinations, for example itinerary0 = self.client.factory.create('itinerary') itineraryArray = self.client.factory.create('itineraryArray') itineraryArray = [itinerary0] searchRequest.itineraryArr = itineraryArray But all my trials resulted with the same server error - Server raised fault: 'Cannot use object of type itinerary as array' (Fault){ faultcode = "SOAP-ENV:Server" faultstring = "Cannot use object of type itinerary as array" } Appreciate you help..... Thanks, Uri

    Read the article

  • Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in

    - by alundra00
    hi i am new to php and now i having problem with login Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in... Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in.... coding php: <?php include ("config/koneksi.php"); include ("config/library.php"); $pass = md5($_POST['password']); $login = mysql_query("SELECT * FROM user WHERE id_user='$_POST[username]' AND sesi='$pass'"); $found = mysql_num_rows($login); //error $r = mysql_fetch_array($login); //error if ($r){ session_start(); session_register("username"); session_register("sesi"); session_register("role"); $_SESSION[username] = $r[id_user]; $_SESSION[sesi] = $r[sesi]; $_SESSION[role]= $r[role]; header ('location:home.php'); }

    Read the article

  • php/mysql question, retrieving information

    - by chance
    Hey SO, I have a question, pretty new at PHP and MySql but was curious is it possible to display only the most recent column to a table, from a database? I know it is possible to display a list of all information, or if you have just one column of information in your table to display that using the Here is my code for my basic script (just loads 1 column of information) I would like it to only print out the recent column i added to the table $con = mysql_connect ("localhost","username","password"); if (!$con) { die ('Could not connect:' . mysql_error()0; } mysql_select_db("db_name", $con); $result = mysql_query(Select column FROM table"); while($row = mysql_fetch_array($result)) { echo $row['column']; } mysql_close($con); * keep in mind, im not looking for someone to shoot me my code with it completed, though it would be handy, however just giving me the options of what I have to do, or what the script is called would be plentiful enough for my research, thanks!

    Read the article

  • safe dereferencing and deletion

    - by serejko
    Hi, I'm relatively new to C++ and OOP in general and currently trying to make such a class that allows to dereference and delete a dead or invalid pointer without any care of having undefined behavior or program fault in result, and I want to ask you is it a good idea and is there something similar which is already implemented by someone else? or maybe I'm doing something completely wrong? I've just started making it and here is the code I currently have: template<class T> class SafeDeref { public: T& operator *() { hash_set<T*>::iterator it = theStore.find(reinterpret_cast<T*>(ptr)); if (it != theStore.end()) return *this; return theDefaultObject; } T* operator ->() { hash_set<T*>::iterator it = theStore.find(reinterpret_cast<T*>(ptr)); if (it != theStore.end()) return this; return &theDefaultObject; } void* operator new(size_t size) { void* ptr = malloc(size * sizeof(T)); if (ptr != 0) theStore.insert(reinterpret_cast<T*>(ptr)); return ptr; } void operator delete(void* ptr) { hash_set<T*>::iterator it = theStore.find(reinterpret_cast<T*>(ptr)); if (it != theStore.end()) { theStore.erase(it); free(ptr); } } protected: static bool isInStore(T* ptr) { return theStore.find(ptr) != theStore.end(); } private: static T theDefaultObject; static hash_set<T*> theStore; }; The idea is that each class with the safe dereference should be inherited from it like this: class Foo : public SafeDeref<Foo> { void doSomething(); }; So... Any advices? Thanks in advance. P.S. If you're wondering why I need this... well, I'm creating a set of native functions for some scripting environment, and all of them use pointers to internally allocated objects as handles to them and they're able to delete them as well (input data can be wrong), so this is kinda protection from damaging host application's memory And I really sorry for my bad English

    Read the article

  • Use sudo su - <username> to access the <username's> account but sudo su - shouldn't be possible with a sudo user

    - by Winnie
    There is a requirement I got. My sudo users (for which their entry in sudoers file) should be able to access other user's account say Oracle using following command: sudo su - Oracle The above should work with giving current users password. But if the same user is firing the following command, sudo su - it shouldn't work and thus root access shouldnt be given to current user. I am not using su because because i dont want current user to know the credentials of other user(root,Oracle etc.). Can anyone please help me . Its urgent...

    Read the article

  • syncing data with server

    - by user155673
    Hi all, I'm trying to sync data from my application onto the server. I'm very new to this kind of work. For this i wrote a small web service in php, insertData($_get['username'], $_get['password']); ? Now, i'm not able to figure out how to call this web service and how to send the 2 variable values to the insertData function from the app using xCode. Any kind of help on this would be appreciated. Thanks & Regards, NR

    Read the article

  • read variables from file

    - by TonyVipros
    Hi, I'm trying to write a shell script to backup websites, I've got it to go through each directory in vhosts and create a new directory vhosts/{siteurl}/private/backups/ and gzip up the site into there. However, I also want it to read a file from private that will contain database name, user and password. So I can then use these to perform a mysqldump to private/backups/. The problem is that I've never written a shell script before so I've go no idea how to read variable data into my script, or how I should format the file to be read. Hope that's enough information.

    Read the article

  • Why is my socket closing?

    - by Tommy3244
    Ok, so I am making a multiplayer game. I am working out the kinks in the server/client connectivity system. I can't seam to work out this error. Mainly, my server code does the following: Accepts Client Using SocketServer Module CLIENT -- SERVER sends Login byte (1 byte) + login username and password (200 bytes) SERVER request for 1 byte by struct.calcsize('b') CLIENT has exception on read SERVER recieves byte from CLIENT and sends CLIENT a struct packed byte with the value of 4 SERVER has exception on send So, it is the client excepting. The client exception is: socket.error: (10054, 'Connection reset by peer') And the server error is this: error: (9, 'Bad file descriptor')

    Read the article

  • PHP: I got hacked...

    - by jun
    I just checked my site it suddenly jumps me to this site: xxxp://www1.re*******3.net/?p=p52dcWpkbG6HjsbIo216h3de0KCfaFbVoKDb2YmHWJjOxaCbkXp%2FWqyopHaYXsiaY2eRaGNpnFPVpJHaotahiaJ0WKrO1c%2Beb1qfnaSZdV%2FXlsndblaWpG9plmGQYWCcW5eakWppWKjKx6ChpqipbmdjpKjEjtDOoKOhY56n1pLWn1%2FZodXN02BdpqmikpVwZWpxZGxpcV%2FVoJajYmJkZ2hwlGGXaVbJkKC0q1eum5qimZxx I found out that in the first line of my index.php file, that looks like this: <?php /**/ eval(base64_decode("aWYoZnVuY3Rpb25fZXhpc3RzKCdvYl9zdGFydCcpJiYhaXNzZXQoJEdMT0JBTFNbJ21yX25vJ10pKXsgICAkR0xPQkFMU1snbXJfbm8nXT0xOyAgIGlmKCFmdW5jdGlvbl9leGlzdHMoJ21yb2JoJykpeyAgICAgIGlmKCFmdW5jdGlvbl9leGlzdHMoJ2dtbCcpKXsgICAgIGZ1bmN0aW9uIGdtbCgpeyAgICAgIGlmICghc3RyaXN0cigkX1NFUlZFUlsiSFRUUF9VU0VSX0FHR/* Snip *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"));?> How do I stop this? thanks! UPDATE: What kind of attack is this? is this really xss? No one really knows about my ftp password.

    Read the article

  • A global login (many sites)

    - by John
    We are a growing network but we figured we want to keep that the User only would need one account in order to access the network different sites. (Similar to Stackoverflow's login, If you login in to another "site" you use your account credentials and than your account is created). We want our own login system (Username, password) and not OpenId, as we'd probably have that in the future, but the main focus right now is the global login. How can I do this? Do a Curl request and send back a cookie? Have a "database" just for the login procedure and on first login also create a new "User" in the site specified database? Suggestions?.

    Read the article

  • Using ftp in C# to send a file

    - by pm_2
    I'm trying to send a file using ftp. I have the following code: string server = "x.x.x.x"; // Just the IP Address FileStream stream = File.OpenRead(filename); byte[] buffer = new byte[stream.Length]; WebRequest request = WebRequest.Create("ftp://" + server); request.Method = WebRequestMethods.Ftp.UploadFile; request.Credentials = new NetworkCredential(username, password); Stream reqStream = request.GetRequestStream(); // This line fails reqStream.Write(buffer, 0, buffer.Length); reqStream.Close(); But when I run it, I get the following error: The requested URI is invalid for this FTP command. Please can anyone tell me why? Am I using this incorrectly?

    Read the article

  • Rails 3 many-to-many query on includes or joins

    - by Myat
    I have three models User, Activity and ActivityRecord. class User < ActiveRecord::Base # Include default devise modules. Others available are: # :token_authenticatable, :confirmable, # :lockable, :timeoutable and :omniauthable devise :database_authenticatable, :registerable, :recoverable, :rememberable, :trackable, :validatable # Setup accessible (or protected) attributes for your model attr_accessible :first_name, :last_name, :email, :gender, :password, :password_confirmation, :remember_me # attr_accessible :title, :body has_many :activities has_many :activity_records , :through=> :activities end class Activity < ActiveRecord::Base attr_accessible :point, :title belongs_to :user has_many :activity_records end class ActivityRecord < ActiveRecord::Base attr_accessible :activity_id belongs_to :activity scope :today, lambda { where("DATE(#{'activity_records'}.created_at) = '#{Date.today.to_s(:db)}'")} end I would like to query all activities for a user together with the count for their respective activity records for today. For example, after querying and converting to json format, I would like to have something like below [ { id: 23 title: "jogging", point: "5", today_activity_records_count: 1, }, { id: 12 title: "diet dinner", point: "2", today_activity_records_count: 0, }, ] Please kindly guide me how I can achieve that. Thanks

    Read the article

  • Error 1045 MySQL during setup

    - by user1364513
    Could anyone explaine me the error 1045 during MySQL setup I ll be preciated. I'm getting this error after reinstalling. I 'm going to install on windows 7. On the last stage of installation i.e apply security settings I'm getting the following message:"The security settings could not be applied. Error Number 1045. Access denied for user 'root' @ 'loaclhost'(usinf password: NO)". I know another way how to fix it that is reinstalling of operating system, but I can't do it please help how can I solve it?. I'll be preciated. Thanks!

    Read the article

  • Restful client on Codeigniter issue

    - by user1852837
    This is weird. I don't know what is problem on my website. My website works on local server but not on live server. Login page works on first signin but after logout then re-login again message says: "invalid username and password" since it works on first attempt. I found out when I debugging that http://xxxxx.com/api/authentication/sign not found. It display 404 page not found. Sometimes you can login and sometimes not. In my local it works. I contact the web server admin and I ask what is the status of the session on the server and How does it execute it's web requests? (Sockets, file_get_contents, curl?). They said that No problems reproduced with Server Sessions and PHP Curl works fine. I know it's weird but can somebody here can figure it out what is the problem behind of it.

    Read the article

  • MySQL Query Problem

    - by user559744
    Hello guys, I'm getting following error message. Please help me. Thanks Notice: Trying to get property of non-object in C:\xampp\htdocs\my\include\user_functions.php on line 34 Here is my Code $conn = db_connection(); if($conn == false) { user_error('Unable to connect to database'); return false; } $query = "UPDATE user SET passwd = '".$new_passwd."' WHERE username = '".$username."' "; $result=$conn->query($query); if($result == false) { user_error('Query Error'.$conn->error); return false; } if($result->num_rows == 1) { echo 'Password changed'; } else { echo 'Failed '; } here is my db_connection function db_connection() { $db = new mysqli('localhost','root','','php_login'); if(!$db) { echo 'Could not connect to database server'; } else { return $db; } }

    Read the article

< Previous Page | 378 379 380 381 382 383 384 385 386 387 388 389  | Next Page >