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• Code understanding, reverse engineering, best concepts and tools. Java.

  - by core07

  One of most demanding tasks for any programmer, architect is understanding other's code. E.g. I am contractor, hired to rescue some project very quickly. Fix bugs, plan global refactoring and therefore I need most efficient way to understand the code. What is the list of concepts, their priority and best tools for this? Of what I know: reverse code engineering to create object models (creating of diagram per package is not so convenient), create sequence diagrams (the tool connects in debug mode to the system and generates diagrams from runtime). Some visualizing techniques, using some tools to work not just with .java but also with e.g. JPA implementors like Hibernate. Generate diagram for not all the codebase, but add some class and then classes used by it. Is Sparx Enterprise Architect state of the art in reverse engineering or far from that. Any other better tools? Ideally would be that tool makes me understand the code as if I wrote it myself :)

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• How to Store Cookies in Ruby?

  - by viatropos

  I am programmatcally accessing authenticated content in my CDN on Google App Engine, and it's returning a cookie that I'm supposed to store: {"set-cookie"=>"ACSID=cookie-hash; expires=Mon, 12-Apr-2010 01:56:06 GMT; path=/"} What do I do with that? This is my first time dealing with Cookies. I can put in the header of the next request, but what's the recommended way to store that? I'm testing this with irb in the console and when I exit and try again, the cookie is gone. How do I save it for a few days/weeks? I'm using pure ruby without Rails or anything. Thanks so much.

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• Django: problem with merging querysets after annotation

  - by Björn Lilja

  Hi I have a manager for "Dialog" looking like this: class AnnotationManager(models.Manager): def get_query_set(self): return super(AnnotationManager, self).get_query_set().annotate( num_votes=Count('vote', distinct=True), num_comments=Count('comment', distinct=True), num_commentators = Count('comment__user', distinct=True), ) Votes and Comments has a ForeignKey to Dialog. Comments has a ForeignKey to User. When I do this: dialogs_queryset = Dialog.public.filter(organization=organization) dialogs_popularity = dialogs_queryset.exclude(num_comments=0) | dialogs_queryset.exclude(num_votes=0) ...dialogs_popularity will never returned the combination, but only the dialogs with more than 0 comments, or if I change the order of the OR, the dialogs with more than 0 votes! To me, the expected behavior would be to get the dialogs with more than 0 votes AND the dialogs with more than 0 comments. What am I missing? Or is there a bug in the annotation behavior here?

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• Ruby get inheriting class

  - by Brian D.

  I'm working on creating my first plugin for rails. I'm still pretty new to ruby and I was wondering if its possible to get the inheriting class? For example, I'm trying to create a plugin that will allow unit testing and functional testing when you are not using migrations. What I'm trying to do is initialize a class variable named controller to be initialized to the type of controller that is being tested. If I have a base class ControllerTest: class ControllerTest < Test::Unit::TestCase attr_accessor :controller def initialize super @controller = "call function that will find the inheriting classes name and create an instance of that controller type." end end So what I'm currently stuck on is getting the name of the inheriting class. Is this possible? And if not, does anyone know another way on how I could go about implementing this? Thanks in advance.

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• Perl script to print out cars model and car color

  - by Gary Liggons

  I am tying to create a perl script to printout car models and colors, and the data is below. I want to know if there is anyway to make the car model heading a field so that I can print it any time I want to? the data below is a csv file. the way I want the data to look on a report is below as well This is how the data looks* Chevy blue,1978,Washington brown,1989,Dallas black,2001,Queens white,2003,Manhattan Toyota red,2003,Bronx green,2004,Queens brown,2002,Brooklyn black,1999,Harlem ****This is how I am trying to get the data to look in a report**** Car Model:Toyota Color:Red Year:2002 City: Queens

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• How to create a test environnement on the production FTP

  - by Clement Herreman

  Hello, I'm currently working on a symfony webapp, which is already on production. To develop and add/delete/modify functionnality of the model, I work on my laptop, using symfony 'dev' environnemment. I test if everything work fine, then I pray a little and deploy it on the prod server (with all the risk of data error, like when I add new not null attributes on the model, prod server configuration special stuff, version of php/apache etc.). The problem is that I would like to setup a "staging" server, which would be a copy of the production server (same database, same configuration apache/php), so that, if the deployment goes bad, the production user stay untouched and working, only the staging server is down. But my client has only 1 FTP available. So, the question is : can I run 2 symfony project, with different models, on the same FTP ? Or is there another way to do what I want to do ? Thank you !

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• Django filter with two constraints on related model

  - by BJ Homer

  I have a django app with models as follows: A Question model An Answer model, with a ForeignKey back to the Question. (A question can have multiple answers.) A Flag model, with a ForeignKey to the Answer. (An answer can be flagged as inappropriate.) All of the above also have a user field, defining the user that created that object. I'm trying to get a list of all Questions with answers from the current user which have been flagged. I tried this: Question.objects.filter(answer__user=user).\ filter(answer__flag__isnull=True).distinct() … but I believe that will return a list of Questions with answers from the current user and with answers which have been flagged, but will not necessarily guarantee that it is the user's answer that has been flagged. Is there an easy way to do this? Basically, I want to make the answer part of the filter refer to the same answer on both of them. Please let me know if something is unclear.

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• Override transparency color when converting transparent PNG to JPG

  - by Alexander Malfait

  I'm using Dragonfly to generate thumbnail images in a Rails app. I'm serving all picture images as JPG's. Now the client is uploading transparent PNG files, like this one: http://www.ibanez.co.jp/products/images/eg2010/ART120_TRF_12_02.png Dragonfly uses RMagick to convert these images to JPG. The problem is that it converts the PNG images to JPG with a black background, and my site's design requires a white background. I've tried to override it like this: encoded_image = Magick::Image.from_blob(image.data).first if encoded_image.format.downcase == format image # do nothing else encoded_image.format = format encoded_image.background_color = "white" encoded_image.transparent_color = "white" encoded_image.to_blob end But the produced JPG images still contain a black background. Does anyone know how to beat RMagick into using a white background when converting the transparent layer? I know I could just serve as PNG, but then the images are 10 times as large, and the site is already pretty bandwidth heavy.

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• [Django] How to find out whether a model's column is a foreign key?

  - by codethief

  I'm dynamically storing information in the database depending on the request: // table, id and column are provided by the request table_obj = getattr(models, table) record = table_obj.objects.get(pk=id) setattr(record, column, request.POST['value']) The problem is that request.POST['value'] sometimes contains a foreign record's primary key (i.e. an integer) whereas Django expects the column's value to be an object of type ForeignModel: Cannot assign "u'122'": "ModelA.b" must be a "ModelB" instance. Now, is there an elegant way to dynamically check whether b is a column containing foreign keys and what model these keys are linked to? (So that I can load the foreign record by it's primary key and assign it to ModelA?) Or doesn't Django provide information like this to the programmer so I really have to get my hands dirty and use isinstance() on the foreign-key column?

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• How to access a plugin model from a regular controller in PHP Cake 1.1

  - by Duncan

  Hopefully a simple question: I've a plugin which uses a set of tables (kb_items, kb_item_tags, etc). and I'd like to be able to access these models from another controller (say, my Pages controller), thus: class PagesController extends AppController{ function knowledgebase(){ $items = $this->KbItem->findAll(...); } } I am admittedly breaking the rules a little (by not placing this controller inside the knowledge base plugin), but this in this case its a custom page that doesn't need to be part of the knowledge base plugin code base. Please let me know if you need more details. Thanks in advance for any help!

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• Cross-platform GUI toolkits with WPF-style composition capabilities

  - by Alexey Romanov

  A huge advantage of WPF over, say, WinForms is its composability. To quote Programming WPF: One level up, WPF provides its “content model,” which allows any control to host any group of other controls. You don’t have to build special BitmapButton or IconComboBox classes; you put as many images, shapes, videos, 3D models, or whatever into a Button (or a ComboBox, ListBox, etc.) as suit your fancy. Are there any cross-platform GUI frameworks (preferably with Java bindings) out there which also let you do this?

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• many to many query for ActiveRecord

  - by JP

  I have three data models, Users, Conversations and Lines, where each conversation has many lines and certain participating users, each line has one conversation and one user and each user has many conversations and many lines. I have arranged these in ActiveRecord like this: class Line < ActiveRecord::Base belongs_to :conversation belongs_to :user end class User < ActiveRecord::Base has_and_belongs_to_many :conversations has_many :lines end class Conversation < ActiveRecord::Base has_many :lines has_and_belongs_to_many :users end If I want to create a new conversation with 4 users, where the users are either found or created inside the users table, how would I go about doing this? I thought I could do: c = Conversation.new c.users.find_or_create_by_username('myUsername') c.save But this will create a new username in the Users table even if that username already exists! (ie. running the above code 3 times will result in Users having 3 rows with 'myUsername' as the username, one for each conversation, rather than three conversations all with the same 'myUsername' entry listed in their associated users) I'm not sure how to search for this kind of information with google - can anyone help?

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• Combining regroup with get_foo_display in Django templates

  - by shacker

  I'm using the regroup template tag to group queryset output on a Choices field. In the model: RESOURCE_TYPES = ( ('tut','External tutorial'), ('read','Additional reading'), ('org','Company or organization'), ) restype = models.CharField('Resource type',max_length=6,choices=RESOURCE_TYPES) in the view: resources = Resource.objects.filter(tutorial=tutorial) in the template: {% regroup resources by restype as resource_list %} {% for type in resource_list %} <h3>{{type.grouper}}</h3> So type.grouper renders as 'tut' or 'org' on the page, rather than the long form. Normally you would use the get_foo_display syntax to get at the value of the choice, rather than the key. But the value doesn't seem to be available after going through regroup. There's no way I can find to use get_foo_display on {{type.grouper}}. It makes sense when you think about it, but what's the workaround? Thanks.

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• Create an own "OpenID-like system" Provider

  - by user502052

  I know that Facebook use their own OpenID-like system called "Facebook connect", which you can use to authenticate users on your site, among other features. In my case I have multiple Ruby on Rails applications: users.example.com profiles.example.com photos.example.com ... I would like to use 'users.example.com' as a web service that allows users to authenticate to all my other applications the same way as works "Facebook connect" or OpenID. In few words, 'users.example.com' must works as a "OpenID-like system" for my applications in 'example.com'. Can anyone give me tips and links to some useful resources? P.S.: since I am a newbie in this matter, I do not know if I'm saying things that make sense. So someone could help me to understand (if I am wrong) ...

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• Django 1.5 custom User model error. "Manager isn't available; User has been swapped"

  - by bpetit

  I extend the django user model as described in the dev doc. I wan't to keep most of the original User model features so I extend the AbstractUser class. I've defined in settings.py: AUTH_USER_MODEL = 'myapp.CustomUser' My user class: class CustomUser(AbstractUser): custom_field = models.ForeignKey('OtherModel') objects = UserManager() Everything seems to work fine but when I try to make it managed by the admin site: admin.site.register(CustomUser, UserAdmin) I get this error on the admin CustomUser creation page (after validation of the password confirmation form): AttributeError: Manager isn't available; User has been swapped for 'myapp.CustomUser' The point is that I need this model managed by the admin site in order to have the same creation process as with the original User model (two step process with password validation). Thanks for any reply

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• How to limit fields in django-admin depending on user?

  - by minder

  I suppose similar problem would have been discussed here, but I couldn't find it. Let's suppose I have an Editor and a Supervisor. I want the Editor to be able to add new content (eg. a news post) but before publication it has to be acknowledged by Supervisor. When Editor lists all items, I want to set some fields on the models (like an 'ack' field) as read-only (so he could know what had been ack'ed and what's still waiting approval) but the Supervisor should be able to change everything (list_editable would be perfect) What are the possible solutions to this problem?

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• How can I make a Twitter style alert stick to the top of the window?

  - by Robert Robb

  There is an excellent code example on how to make nice jQuery Twitter style alerts here: http://blog.codecrate.com/2009/10/twitter-style-alerts-in-rails.html $(function () { var alert = $('.alert'); if (alert.length > 0) { alert.show().animate({height: alert.outerHeight()}, 200); window.setTimeout(function() { alert.slideUp(); }, 3000); } }); However, one thing that the code doesn't include is functions to stick the alert div to the top of the window, no matter how far down the page the user has scrolled. I have found a few examples but nothing seems to play nice with this existing code. Any ideas?

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• How Do I create a synchronous version of NSURLConnection

  - by quinn

  I am using NSURLConnection inside of an NSIncrementalStore to synchronize my NSManagedObject with rest based web service built in Rails. I am aware of +sendSynchronousRequest:returningResponse:error but my understanding is that will not allow me to access such things as the HTTP response status code which I will need to properly handle the response, my understanding is sendSynchronousRequest returns the data if it responds in the 200 range and fails if it doesn't and doesn't really give you much more than that. I'm assuming I will somehow have to block the current method call after the NSURLConnection is instantiated and unblock it after NSURLConnection's delegate sets some value that can be returned by the blocked method. I'm assuming this will involve some combination of NSLock and NSThread but I really don't know where to start with this, any help will be greatly appreciated, thank you.

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• asp.mvc model design

  - by Radu D

  Hi, I am pretty new to MVC and I am looking for a way to design my models. I have the MVC web site project and another class library that takes care of data access and constructing the business objects. If I have in that assembly a class named Project that is a business object and I need to display all projects in a view ... should I make another model class Project? In this case the classes will be identical. Do I gain something from doing a new model class? I don't like having in views references to objects from another dll ... but i don't like duplicating the code neither. Did you encounter the same problem?

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• Is there a Cart/Catalog app out there that isnt a full site?

  - by prodigitalson

  Every solution i come across seems to be a complete store with far too many options and too much functionality. I can write my own cart to get the minimal functionality i need out of the frontend, im just trying to cut out the time writing a complex backend. What im really looking for is something that offers the backend functionality for a product catalog, order management, etc. while providing a smooth and consistent API to access the data for my completely custom frontend application. The frontend will be in PHP so the API would have to be native PHP or some kind of web service interface i can create my own php models around. It would need to run on a LAMP stack and would preferably be written in PHP, Python, or Ruby just in case i need to customize the backend (she curently has ZenCart and hates it - says its far too complicated and sophisticated for her needs). Does such a thing exist? Or what would be the next best thing?

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• Scrollable display of multiple video icons

  - by Tam

  Hello, I want to have multiple video icons at the top my website's front page. I will have about 20 or so which won't fit on one line (I want to keep the videos on one like) so I thought of having two button on the right of the group and on the left of the group where you click to scroll and view more videos. Do you know an easy way to do this? I can pass in the video links from the server in different Divs or anyway that will make it easy. I thought of using AJAX and pass it different set every time from the server with every click (I'm using Rails and it's fairly easy to do it) but that will be an extra load on the server which I'm trying to avoid. I'd rather send all the icons at once and let the JavaScript handle the scrolling. I thought of using iFrame but I don't like the idea of scrollbar and wanted to be more like button Any ideas? Thanks, Tam

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• How to get started with embedded systems in the airline or submarine industries?

  - by Jason

  Hi, Not 100% sure how to frame this question but here goes... I currently work as a Rails developer but want to work on more substancial / "meaty" projects and have always been very interested in embedded systems, especially systems that run on aircraft and especially submarines.....I know strange combination. I have been doing some searching & found lockheed martin produces a lot of underwater systems for various navys around the world e.g. http://www.naval-technology.com/projects/nssn/ However, there is very little information about what software is used within these systems, what OS's they use or anything else "technical", presume there is a lot of C / C++ involved but that is just a guess... so its hard to know where to even begin learning what is required to potential work in these areas. Just wondering if anyone has any experiance working with or more information about embeddeed systems in either the airline (onboard flight systems) or especially submarine systems? Thanks!

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• In plain English, what are Django generic views?

  - by allyourcode

  The first two paragraphs of this page explain that generic views are supposed to make my life easier, less monotonous, and make me more attractive to women (I made up that last one): http://docs.djangoproject.com/en/dev/topics/generic-views/#topics-generic-views I'm all for improving my life, but what do generic views actually do? It seems like lots of buzzwords are being thrown around, which confuse more than they explain. Are generic views similar to scaffolding in Ruby on Rails? The last bullet point in the intro seems to indicate this. Is that an accurate statement?

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• Problem w/ Paperclip, MacPorts, ImageMagick & Snow Leopard

  - by Kyle Decot

  I'm attempting to use ImageMagick along w/ Paperclip to handle the images on my rails app. The problem is whenever I try to upload an image I get the following in the terminal: [paperclip] An error was received while processing: #<Paperclip::NotIdentifiedByImageMagickError: /var/folders/go/goZ833AaFaqyvv5RnLqQmE+++TM/-Tmp-/stream20110107-6356-1xfs9j1-0.jpg is not recognized by the 'identify' command.> I have added the following to my environments/development.rb file: Paperclip.options[:command_path] = "/usr/local/bin" If I try to interact w/ ImageMagick in the terminal by using "convert" or something similar I get: dyld: Library not loaded: /opt/local/lib/libltdl.7.dylib Referenced from: /usr/local/bin/convert Reason: Incompatible library version: convert requires version 10.0.0 or later, but libltdl.7.dylib provides version 9.0.0 Trace/BPT trap I've already tried updating everything w/ port but the problem still persists. Does anyone have any ideas or suggestions?

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• How to model my database when using entity framework 4?

  - by Junior Ewing

  Trying to wrap my head around the best approach in modelling a database when we are using Entity Framework 4 as the ORM layer. We are going to use asp.net mvc 2 for the application. Is it worth trying to model using the class diagram modeller that comes with Visual Studio 2010 where you graphically configure your models into the EDMX file and then generate out the database structure? I have run into a bunch of non trivial issues and for complex many to many mappings or multi primary key entities the answer is not that obvious even after poking around a while with the tools. I figure its easy at this point to give up and start modelling the DB using real, working DB modelling tools and then try to generate out the EDMX from the database, rather than trying to do the model first approach.

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