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  • How to change the OSX menubar in wxPython without any opened window?

    - by gyim
    I am writing a wxPython application that remains open after closing all of its windows - so you can still drag & drop new files onto the OSX dock icon (I do this with myApp.SetExitOnFrameDelete(False)). Unfortunately if I close all the windows, the OSX menubar will only contain a "Help" menu. I would like to add at least a File/Open menu item, or just keep the menubar of the main window. Is this somehow possible in wxPython? In fact, I would be happy with a non-wxPython hack as well (for example, setting the menu in pyobjc). wxPython development in OSX is such a hack anyway ;)

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  • How would make this run with an if statement and one for loop?

    - by Nick Jacobs
    I'm trying to get this to run by using an if statment, a for loop, and a list. The list is part of the parameters. I am not sure how to write the if statement and have the program loop through all of the different words and set everything how it is supposed to be. newSndIdx=0; for i in range (8700, 12600+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx +=1 newSndIdx=newSndIdx+500 for i in range (15700, 17600+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx +=1 newSndIdx=newSndIdx+500 for i in range (18750, 22350+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx +=1 newSndIdx=newSndIdx+500 for i in range (23700, 27250+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx +=1 newSndIdx=newSndIdx+500 for i in range (106950, 115300+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx+=1

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  • chatbot using twisted and wokkel

    - by dmitriy k.
    I am writing a chatbot using Twisted and wokkel and everything seems to be working except that bot periodically logs off. To temporarily fix that I set presence to available on every connection initialized. Does anyone know how to prevent going offline? (I assume if i keep sending available presence every minute or so bot wont go offline but that just seems too wasteful.) Suggestions anyone? Here is the presence code: class BotPresenceClientProtocol(PresenceClientProtocol): def connectionInitialized(self): PresenceClientProtocol.connectionInitialized(self) self.available(statuses={None: 'Here'}) def subscribeReceived(self, entity): self.subscribed(entity) self.available(statuses={None: 'Here'}) def unsubscribeReceived(self, entity): self.unsubscribed(entity) Thanks in advance.

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  • Alternative pygame resources

    - by Devo
    Hi, I have been trying to access the pygame website for a few weeks now, and I can't get to it. I doubt it's down, so I have to conclude that it's blocked because I am in China. I have no idea why. Anyways, I want the pygame documentation, but all the download links I fond lead back to pygame.org (which I does not even begin loading, it's such a politically subversive website you know!). Can anyone tell me where I can get documentation and other pygame resources without going through pygame.org? I would really appreciate it, thanks. PS I am on windows XP, if it matters.

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  • Function for averages of tuples in a dictionary

    - by Billy Mann
    I have a string, dictionary in the form: ('the head', {'exploded': (3.5, 1.0), 'the': (5.0, 1.0), "puppy's": (9.0, 1.0), 'head': (6.0, 1.0)}) Each parentheses is a tuple which corresponds to (score, standard deviation). I'm taking the average of just the first integer in each tuple. I've tried this: def score(string, d): for word in d: (score, std) = d[word] d[word]=float(score),float(std) if word in string: word = string.lower() number = len(string) return sum([v[0] for v in d.values()]) / float(len(d)) if len(string) == 0: return 0 When I run: print score('the head', {'exploded': (3.5, 1.0), 'the': (5.0, 1.0), "puppy's": (9.0, 1.0), 'head': (6.0, 1.0)}) I should get 5.5 but instead I'm getting 5.875. Can't figure out what in my function is not allowing me to get the correct answer.

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  • Pyqt - QMenu dynamically populated and clicked

    - by mleep
    I need to be able to know what item I've clicked in a dynamically generated menu system. I only want to know what I've clicked on, even if it's simply a string representation. def populateShotInfoMenus(self): self.menuFilms = QMenu() films = self.getList() for film in films: menuItem_Film = self.menuFilms.addAction(film) self.connect(menuItem_Film, SIGNAL('triggered()'), self.onFilmSet) self.menuFilms.addAction(menuItem_Film) def onFilmRightClick(self, value): self.menuFilms.exec_(self.group1_inputFilm.mapToGlobal(value)) def onFilmSet(self, value): print 'Menu Clicked ', value

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  • standard geographic tilizing/binning method?

    - by monkut
    I'm trying to learn and understand more about mapping and displaying values on a map. (GIS) At the moment I'M looking to take some values and apply those values to a tile or bin on a map. Ideally I'd like the tile sizes to be uniform, like 100 meters, 500 meters, etc. Is there a standard method for creating uniform tile sizes? Or Are what are common accepted method to deal with this kind of data display? (Currently I'm using geodjango and it's related toolset geos, proj4, etc)

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  • App-Engine Parse a UrlFetch UTF-8 encoded stream

    - by Davidrd91
    I am trying to parse an XML from a URL using the xml.sax parser. I know there are other libraries to use but coming from Java this is the one I am most familiar with and seems the least complicated to me. The code I'm using to parse is as follows: parser = xml.sax.make_parser() handler = MangaHandler() parser.setContentHandler(handler) url = urlfetch.Fetch('http://www.mangapanda.com/alphabetical', allow_truncated = False, follow_redirects = False, deadline = False) xml.sax.parseString(url.content, handler) This returns a SaxException (invalid token) once the parser reaches the first & sign: SAXParseException: <unknown>:582:34: not well-formed (invalid token) Because urlfetch returns a string and not a stream I cannot use the parse() (which only works with streams) and am left to use parseString() instead. To see if parsing as a stream would fix this I tried: parser.parse(io.StringIO(url.content).encode('utf-8')) but this returns: TypeError: initial_value must be unicode or None, not str I have also tried to use the urllib2 libraries which do return a stream instead of urlfetch but the file is too large and is automatically truncated, leaving me with missing data. Any Sort of work-around for this would be greatly appreciated as I've spent days getting around one obstacle just to be stopped by another.

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  • I Made Simple Generator,, Is there any faster way ??

    - by Rami Jarrar
    Hi, i do like this: import time f = open('wl4.txt', 'w') hh = 0 ###################################### for n in range(1,5): for l in range(33,127): if n==1: b = chr(l) + '\n' f.write(b) hh += 1 elif n==2: for s0 in range(33, 127): b = chr(l) + chr(s0) + '\n' f.write(b) hh += 1 elif n==3: for s0 in range(33, 127): for s1 in range(33, 127): b = chr(l) + chr(s0) + chr(s1) + '\n' f.write(b) hh += 1 elif n==4: for s0 in range(33, 127): for s1 in range(33, 127): for s2 in range(33,127): b = chr(l) + chr(s0) + chr(s1) + chr(s2) + '\n' f.write(b) hh += 1 ###################################### print "We Made %d Words." %(hh) ###################################### f.close() So, is there any faster method to make it faster,,

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  • Transaction within transaction

    - by user281521
    Hello, I want to know if open a transaction inside another is safe and encouraged? I have a method: def foo(): session.begin try: stuffs except Exception, e: session.rollback() raise e session.commit() and a method that calls the first one, inside a transaction: def bar(): stuffs try: foo() #<<<< there it is :) stuffs except Exception, e: session.rollback() raise e session.commit() if I get and exception on the foo method, all the operations will be rolled back? and everything else will work just fine? thanks!!

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  • Django complex queries

    - by Josh K
    I need to craft a filter for an object that checks date ranges. Right now I'm performing a very inefficient loop which checks all the objects. I would like to simplify this to a database call. The logic is you have a start and an end date objects. I need to check if the start OR the end is within the range of an appointment. if (start >= appointment.start && start < appointment.end) || (end > appointment.start && end <= appointment.end) I could do this in SQL, but I'm not as familiar with the Django model structure for more complex queries.

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  • Simplifying for-if messes with better structure?

    - by HH
    # Description: you are given a bitwise pattern and a string # you need to find the number of times the pattern matches in the string # any one liner or simple pythonic solution? import random def matchIt(yourString, yourPattern): """find the number of times yourPattern occurs in yourString""" count = 0 matchTimes = 0 # How can you simplify the for-if structures? for coin in yourString: #return to base if count == len(pattern): matchTimes = matchTimes + 1 count = 0 #special case to return to 2, there could be more this type of conditions #so this type of if-conditionals are screaming for a havoc if count == 2 and pattern[count] == 1: count = count - 1 #the work horse #it could be simpler by breaking the intial string of lenght 'l' #to blocks of pattern-length, the number of them is 'l - len(pattern)-1' if coin == pattern[count]: count=count+1 average = len(yourString)/matchTimes return [average, matchTimes] # Generates the list myString =[] for x in range(10000): myString= myString + [int(random.random()*2)] pattern = [1,0,0] result = matchIt(myString, pattern) print("The sample had "+str(result[1])+" matches and its size was "+str(len(myString))+".\n" + "So it took "+str(result[0])+" steps in average.\n" + "RESULT: "+str([a for a in "FAILURE" if result[0] != 8])) # Sample Output # # The sample had 1656 matches and its size was 10000. # So it took 6 steps in average. # RESULT: ['F', 'A', 'I', 'L', 'U', 'R', 'E']

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  • Including a Django app's url.py is resulting in a 404

    - by 828
    I have the following code in the urls.py in mysite project. /mysite/urls.py from django.conf.urls.defaults import * urlpatterns = patterns('', (r'^gallery/$', include('mysite.gallery.urls')), ) This results in a 404 page when I try to access a url set in gallery/urls.py. /mysite/gallery/urls.py from django.conf.urls.defaults import * urlpatterns = patterns('', (r'^gallery/browse/$', 'mysite.gallery.views.browse'), (r'^gallery/photo/$', 'mysite.gallery.views.photo'), ) 404 error Using the URLconf defined in mysite.urls, Django tried these URL patterns, in this order: ^gallery/$ The current URL, gallery/browse/, didn't match any of these. Also, the site is hosted on a media temple (dv) server and using mod_wsgi

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  • Which class should store the lookup table?

    - by max
    The world contains agents at different locations, with only a single agent at any location. Each agent knows where he's at, but I also need to quickly check if there's an agent at a given location. Hence, I also maintain a map from locations to agents. I have a problem deciding where this map belongs to: class World, class Agent (as a class attribute) or elsewhere. In the following I put the lookup table, agent_locations, in class World. But now agents have to call world.update_agent_location every time they move. This is very annoying; what if I decide later to track other things about the agents, apart from their locations - would I need to add calls back to the world object all across the Agent code? class World: def __init__(self, n_agents): # ... self.agents = {} self.agent_locations = {} for id in range(n_agents): x, y = self.find_location() agent = Agent(self,x,y) self.agents.append(agent) self.agent_locations[x,y] = agent def update_agent_location(self, agent, x, y): del self.agent_locations[agent.x, agent.y] self.agent_locations[x, y] = agent def update(self): # next step in the simulation for agent in self.agents: agent.update() # next step for this agent # ... class Agent: def __init__(self, world, x, y): self.world = world self.x, self.y = x, y def move(self, x1, y1): self.world.update_agent_location(self, x1, y1) self.x, self.y = x1, y1 def update(): # find a good location that is not occupied and move there for x, y in self.valid_locations(): if not self.location_is_good(x, y): continue if self.world.agent_locations[x, y]: # location occupied continue self.move(x, y) I can instead put agent_locations in class Agent as a class attribute. But that only works when I have a single World object. If I later decide to instantiate multiple World objects, the lookup tables would need to be world-specific. I am sure there's a better solution... EDIT: I added a few lines to the code to show how agent_locations is used. Note that it's only used from inside Agent objects, but I don't know if that would remain the case forever.

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  • how to create a theme with QT

    - by Moayyad Yaghi
    hello im looking for a way to make my pyqt interface look nicer by adding a theme to it. im new to Qt and i still have no idea how to add a custom theme for widgets.. so how is that possible ? and is it possible through qt designer ? sorry for my bad english , its my third language. i hope the idea is clear enough . please let me know if something was unclear .. thanks in advace

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  • more efficient way to pickle a string

    - by gatoatigrado
    The pickle module seems to use string escape characters when pickling; this becomes inefficient e.g. on numpy arrays. Consider the following z = numpy.zeros(1000, numpy.uint8) len(z.dumps()) len(cPickle.dumps(z.dumps())) The lengths are 1133 characters and 4249 characters respectively. z.dumps() reveals something like "\x00\x00" (actual zeros in string), but pickle seems to be using the string's repr() function, yielding "'\x00\x00'" (zeros being ascii zeros). i.e. ("0" in z.dumps() == False) and ("0" in cPickle.dumps(z.dumps()) == True)

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  • why is this dictionary line number count not working?

    - by jad
    i have this piece of code the last bit of the code starting from d = {} im trying to print the words with its line number located in the text but it is not working its only printing the words anyone know why ??? need help ASAP import sys import string text = [] infile = open(sys.argv[1], 'r').read() for punct in string.punctuation: infile = infile.replace(punct, "") text = infile.split() dict = open(sys.argv[2], 'r').read() dictset = [] dictset = dict.split() words = [] words = list(set(text) - set(dictset)) words = [text.lower() for text in words] words.sort() d = {} counter = 0 for lines in text: counter += 1 if word not in d: d[words] = [counter] else: d[words.append[counter] print(word, d)

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  • convert an int to list of individual digitals more faster?

    - by user478514
    All, I want define an int(987654321) <= [9, 8, 7, 6, 5, 4, 3, 2, 1] convertor, if the length of int number < 9, for example 10 the list will be [0,0,0,0,0,0,0,1,0] , and if the length 9, for example 9987654321 , the list will be [9, 9, 8, 7, 6, 5, 4, 3, 2, 1] >>> i 987654321 >>> l [9, 8, 7, 6, 5, 4, 3, 2, 1] >>> z = [0]*(len(unit) - len(str(l))) >>> z.extend(l) >>> l = z >>> unit [100000000, 10000000, 1000000, 100000, 10000, 1000, 100, 10, 1] >>> sum([x*y for x,y in zip(l, unit)]) 987654321 >>> int("".join([str(x) for x in l])) 987654321 >>> l1 = [int(x) for x in str(i)] >>> z = [0]*(len(unit) - len(str(l1))) >>> z.extend(l1) >>> l1 = z >>> l1 [9, 8, 7, 6, 5, 4, 3, 2, 1] >>> a = [i//x for x in unit] >>> b = [a[x] - a[x-1]*10 for x in range(9)] >>> if len(b) = len(a): b[0] = a[0] # fix the a[-1] issue >>> b [9, 8, 7, 6, 5, 4, 3, 2, 1] I tested above solutions but found those may not faster/simple enough than I want and may have a length related bug inside, anyone may share me a better solution for this kinds convertion? Thanks!

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