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  • custom function is not getting called

    - by nectar
    here my code - $child1 = create_childid()."01"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child1', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); echo $newid; update_level(); $child2 = create_childid()."02"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child2', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); update_level(); $child3 = create_childid()."03"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child3', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); update_level(); $child4 = create_childid()."04"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child4', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); update_level(); $child5 = create_childid()."05"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child5', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); update_level(); ERROR : update_level(); is executing only once why??

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  • How could I compare these database values in PHP?

    - by Dan
    So a user selects from a drop down list a value. I take this value, put it into a variable, then select from the database the ID value of that table A holding the selected value also. So now I'm trying to use that ID value to get to a many-to-many relationship table that has the selected value from table A to a different table B. The many-to-many relationship table has both IDs. How can I compare this using PHP? So it would be like: $A = $_POST['a']; $sql = "SELECT a, aID from TABLEA WHERE a = $A"; What do I do then to compare the aID with the many-to-many relationships table, then get the other ID in that table and then take that ID to get values from table B?

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  • how can I check data has been inserted successfully

    - by Piyush
    I have two insert statements.Second one will be executed only after successful execution of First one.What I wd like to do is- $sqlone="Insert into ....."; $sqltwo="Insert into....."; If(mysql_query($sqlone)) { If(mysql_query($sqltwo)) { show message Data inserted in both tables. } }

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  • Need help with a sub query/group/order (get latest comment for each ordered topic)

    - by Scarface
    Hey guys I have a query that currently finds the latest comment for each of a user's topics and then orders topics by that comment's timestamp. What I want to do is expand on this query's use and print the latest comment for each topic. The problem with this query is that while it orders the topics correctly, it prints seemingly random comments for each topic. I am trying to implement a sub query but I am not quite sure how to approach it. I was thinking that I just had to somehow use this query to get the comments. If anyone has any ideas I would really appreciate it. Here is what I think I need to add SELECT * FROM comments where topic_id='$topic_id' ORDER BY timestamp DESC LIMIT 1 Here is the query I need to modify SELECT topic.topic_title, topic.content_type, topic.subject_id, topic.creator, topic.description, topic.topic_id,comments.message,comments.user FROM comments JOIN topic ON topic.topic_id = comments.topic_id WHERE topic.creator = '$user' AND comments.timestamp > $week GROUP BY topic_id ORDER BY MAX(comments.timestamp) DESC

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  • Combining IN and NOT IN in SQL as single result

    - by UltraVi01
    I apologize for the vague title. I am attempting to write a query that returns an alias column with matching values (resulting from an IN) as well as an alias column with values that do not match (using NOT IN). I want the result set to have: userId | matches | nonmatches. I currently have the following query which returns the matches as expected. I am having trouble getting the nonmatches in the result set -- that is, from a NOT IN statement SET @userId = 9; SELECT ug.user_id, COUNT(DISTINCT goal_id) as matches FROM user_goal ug WHERE ug.user_id!=@userId AND goal_id IN (SELECT iug.goal_id FROM user_goal iug WHERE user_id=@userId) GROUP BY user_id ORDER BY matches DESC LIMIT 4 So, the NOT IN would look something like this: goal_id NOT IN(SELECT uggg.goal_id FROM user_goal uggg WHERE user_id=@userId) AS nonmatches I am just not sure how to incorporate the NOT IN statement in my query so I get all the results

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  • How can I select the required records?

    - by simple
    Tables: Product: [id, name, brand_id, is_published] Brand: [id, name, is_published] Awards: [id, name] ProductAwards [product_id, award_id] How do I select the list of PUBLISHED brands along with the number of AWARDS of brand's products that are Published. I am cool with all the part except issuing the "is_published" restriction when counting Awards. I hope this is clear; can anyone just suggest where to dig?

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  • 2 table SQL Query weird results

    - by javArc
    Ok this is driving me nuts, I need to write an SQL query that will grab product information from 2 tables. The first table 'products' contains the productId, productname, quantityperunit and unitprice. Now I can search by productname and categoryname individually, but when I try to combine the 2 I get crazy results, Here's the query: "SELECT DISTINCT productId, productname, quantityperunit, unitprice FROM products pr, categories ca WHERE pr.categoryID = ca.categoryID AND ProductName LIKE '%" + searchTerm + "%' OR CategoryName LIKE '%" + searchTerm + "%' excuse the java style in there, here it is formatted better: SELECT DISTINCT productId, productname, quantityperunit, unitprice FROM products pr, categories ca WHERE pr.categoryID = ca.categoryID AND ProductName LIKE 'Tofu' OR CategoryName LIKE 'Tofu' any help would be appreciated.

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  • which sql query is more efficient: select count(*) or select ... where key>value?

    - by davka
    I need to periodically update a local cache with new additions to some DB table. The table rows contain an auto-increment sequential number (SN) field. The cache keeps this number too, so basically I just need to fetch all rows with SN larger than the highest I already have. SELECT * FROM table where SN > <max_cached_SN> However, the majority of the attempts will bring no data (I just need to make sure that I have an absolutely up-to-date local copy). So I wander if this will be more efficient: count = SELECT count(*) from table; if (count > <cache_size>) // fetch new rows as above I suppose that selecting by an indexed numeric field is quite efficient, so I wander whether using count has benefit. On the other hand, this test/update will be done quite frequently and by many clients, so there is a motivation to optimize it.

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  • how to change a while sql query loop into an array loop

    - by Mac Taylor
    hey guys i record number of queries of my website and in page the below script runs , 40 extra queries added to page . how can I change this sql connection into a propper and light one function tree_set($index) { //global $menu; Remove this. $q=mysql_query("select id,name,parent from cats where parent='$index'"); if(mysql_num_rows($q) === 0) { return; } // User $tree instead of the $menu global as this way there shouldn't be any data duplication $tree = $index > 0 ? '<ul>' : ''; // If we are on index 0 then we don't need the enclosing ul while($arr=mysql_fetch_assoc($q)) { $subFileCount=mysql_query("select id,name,parent from cats where parent='{$arr['id']}'"); if(mysql_num_rows($subFileCount) > 0) { $class = 'folder'; } else { $class = 'file'; } $tree .= '<li>'; $tree .= '<span class="'.$class.'">'.$arr['name'].'</span>'; $tree .=tree_set("".$arr['id'].""); $tree .= '</li>'."\n"; } $tree .= $index > 0 ? '</ul>' : ''; // If we are on index 0 then we don't need the enclosing ul return $tree; } i heard , this can be done by changing it into an array , but i don't know how to do so thanks in advance

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  • Where I get wrong?

    - by Ole Jak
    I have PHP code like this require_once( "includes" . DIRECTORY_SEPARATOR . "constants.php"); $userID = validKey( $key ); $query = "select a.username, b.streamID from user a, streams b where a.id = b.userID;)"; $connection = mysql_connect(DB_SERVER,DB_USER,DB_PASS); if (!$connection) { die("Database connection failed: " . mysql_error()); } $db_select = mysql_select_db(DB_NAME,$connection); if (!$db_select) {die( "Database selection failed: " . mysql_error()); } $generated_table = mysql_fetch_array(mysql_query($query, $connection)); // line (*) print_r($generated_table); But PHP gives me error/worning and does not print anything out Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given on line (*) 1) Why It does not printed me anything out 2) Where am I wrong?

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  • Help with sql query

    - by user225269
    I have two tables: subject and student. I'm trying to count the number of subjects enrolled by each student. How do I do that?I'm trying the code below but it doesn't give the answer I need. Please help. SELECT COUNT( subject.SUBJECT ) , student.IDNO, student.FIRSTNAME, subject.SUBJECT FROM student, subject GROUP BY subject.SUBJECT LIMIT 0 , 30

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  • how to select all the data from many tables?

    - by Syom
    how to select all the data from many tables? i try `"SELECT * FROM `table1`, `table2`"` , but result none understandable for me. it returns only some rows from table1, and 3 times all the data from table2. i've red one same question here, but don't understand the answer. so could you help me? thanks in advance. update: when i try (SELECT * FROM `videos`) UNION (SELECT * FROM `users`) it returns #1222 - The used SELECT statements have a different number of columns

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  • a bugging query

    - by Sachindra
    i need to get a query where the elements are displayed in case the first letter is E (the word is electronics).. i have tried with the following : mysql_query("select * from nested_category where name like '[A-F]%'");

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  • php mysql_fetch_array() error

    - by user1877823
    I am getting this error while i am trying to delete a record the query is working but this line remains on the page. i want to echo "Deleted" written in the while should show up but the while loop is not working, i have tried and searched alot nothing helps! mysql_fetch_array() expects parameter 1 to be resource, boolean given in delete.php on line 27 delete.php <html> <body> <form method="post"> Id : <input type="text" name="id"> Name : <input type="text" name="name"> Description : <input type="text" name="des"> <input type="submit" value="delete" name="delete"> </form> <?php include("connect.php"); $id = $_POST['id']; $name = $_POST['name']; $des = $_POST['des']; $result = mysql_query("DELETE FROM fact WHERE id='$id'") or die(mysql_error()); while($row = mysql_fetch_array($result)) { echo "Deleted"; } mysql_close($con); ?> </body> </html> connect.php <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("Dataentry", $con); ?> How should i make the while loop work..

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  • HTML Purifier Coding Help?

    - by TaG
    I read the http://htmlpurifier.org/docs/enduser-youtube.html doc, but I still can't figure out where to put the code to allow object, param and embed tags and Use experimental features with my htmlpurifier. Can someone please show me how to do this?

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  • I'm making a resume...what would you consider as intermediate python programming skills?

    - by user285884
    I've made a couple of scripts. One is a stock screener that can search through every stock. Another creates a heatmap that tells you what's performed well and badly over the past day. They aren't really that useful, just did them to work on my programming skills. I was able to throw some SQL in my scripts too. Would you call that intermediate? Thanks? How do you guys list your programming skills on your resume? Maybe there's a better way of putting it on my resume than "intermediate" or "beginner."

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  • LOAD DATA LOCAL INFILE custom value

    - by NR03
    How to add a custom value using LOAD DATA LOCAL INFILE? The column time_added is the 7th column and the file has only 2 values for the first and the second column. For the 7th column, time_added I want to use the unix timestamp when loading from file. This code isn't working: $result = mysql_query("LOAD DATA LOCAL INFILE '{$myFile}' INTO TABLE {$table} FIELDS TERMINATED BY ':' LINES TERMINATED BY '\n' SET `time_added`=unix_timestamp()");

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  • Working with sets of rows in (My)SQL and comparing values

    - by Pep.
    Hello, I am trying to figure out the SQL for doing some relatively simple operations on sets of records in a table but I am stuck. Consider a table with multiple rows per item, all identified by a common key. For example: serial model color XX1 A blue XX2 A blue XX3 A green XX5 B red XX6 B blue XX1 B blue What I would for example want to do is: Assuming that all model A rows must have the same color, find the rows which dont. (for example, XX3 is green). Assuming that a given serial number can only point to a single type of model, find out the rows which that does not occur (for example XX1 points both to A and B) These are all simple logically things to do. To abstract it, I want to know how to group things by using a single key (or combination of keys) and then compare the values of those records. Should I use a join on the same table? should i use some sort of array or similar? thanks for your help

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  • Select products with users

    - by Ploppe
    I have not worked with SQL for quite a long time, and I need some help for a basic query. I have the three following tables: users (id, name) products (id, name) owners (userid, productid, date) One product can be sold by user A to user B and then back to A. Now, I want the list of all products currently owned by every single user with the date of transaction. Currently, my query is this one, but I'm stuck with old data (first association of one product to one user, and not the newest one): SELECT users.name, products.name, date FROM products JOIN owners ON products.id = owners.id JOIN users ON owners.id = user.id GROUP BY product.id Do you have some hints? Thanks

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  • PHP Framework Benefits / Downfalls

    - by Lizard
    I have been a PHP developer for about 10 years now and until about a month ago I have never used a framework. The framework I am now using due to an existing codebase is cakePHP 1.2 I can see certain benefits of the frameworks with the basic helpers like default layouts. I can definitely see the benefits of MVC keeping the logic separate etc. But the query building just seems to be bloated. Is this expected? Am I likely to be able to build better queries than the framework could build? I just feel I could get my apps running better without a framework. What are your thoughts?

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  • wordpress query custom fields and category

    - by InnateDev
    I have a query that creates a table view and then another that queries the view. The results are extremely slow. Here is the code: create or replace view $view_table_name as select * from wp_2_postmeta where post_id IN ( select ID FROM wp_2_posts wposts LEFT JOIN wp_2_term_relationships ON (wposts.ID = wp_2_term_relationships.object_id) LEFT JOIN wp_2_term_taxonomy ON (wp_2_term_relationships.term_taxonomy_id = wp_2_term_taxonomy.term_taxonomy_id) WHERE wp_2_term_taxonomy.taxonomy = 'category' AND wp_2_term_taxonomy.parent = $cat || wp_2_term_taxonomy.term_id = $cat AND wposts.post_status = 'publish' AND wposts.post_type = 'post') The $values have been put it in for this example that queries the view table for the results. select distinct(ID) from $view_table_name wposts LEFT JOIN wp_2_postmeta wpostmeta ON wposts.ID = wpostmeta.post_id WHERE post_status = 'publish' AND ID NOT IN (SELECT post_id FROM wp_2_postmeta WHERE meta_key = '$var' && meta_value = '$value1') AND ID NOT IN (SELECT post_id FROM wp_2_postmeta WHERE meta_key = '$var' && meta_value = '$value2') AND ID NOT IN (SELECT post_id FROM wp_2_postmeta WHERE meta_key = '$var' && meta_value = '$value3') AND postmeta.meta_key = 'pd_form' ORDER BY CASE wpostmeta.meta_value WHEN '$value5' THEN 1 WHEN '$value6' THEN 2 WHEN '$value7' THEN 3 WHEN '$value8' THEN 4 WHEN '$value9' THEN 5 THEN '$value10' THEN 6 WHEN '$value11' THEN 7 WHEN '$value11' THEN 8 END

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