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  • PHP shorthand syntax

    - by alex
    I've just came across this on GitHub. ($config === NULL) and $config = Kohana::config('email'); Is that the equivalent of if ($config === NULL) { $config = Kohana::config('email'); } Is this commonplace? Would I expect other developers looking at my code if I used that first way to instantly know what it was doing?

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  • count and fetch rows in php

    - by Mac Taylor
    hey guys i have a table in my mysql database named (names) now everyone can save their real names now i want to query this table and find out how many times these names used forexample the output should be : Jakob (20) Jenny (17) now this is my own code : list($usernames) =mysql_fetch_row(mysql_query('SELECT name FROM table_user GROUP BY name ORDER BY COUNT(name) DESC LIMIT 50 ')); list($c) =mysql_num_rows(mysql_query('SELECT COUNT(name) FROM table_user GROUP BY name ')); print $usernames.'('.$c.')' is this a correct approach ?!

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  • PHP Object conversion question

    - by karlthorwald
    I am converting from JSON to object and from object to array. It does not what I expected, can you explain to me? $json = '{"0" : "a"}'; $obj = json_decode($json); $a = (array) $obj; print_r($a); echo("a0:".$a["0"]."<br>"); $b = array("0" => "b"); print_r($b); echo("b0:".$b["0"]."<br>"); The output here is: Array ( [0] => a ) a0: Array ( [0] => b ) b0:b I would have expected a0:a at the end of the first line.

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  • How to achieve auto logoff in php ?

    - by Ramakrishnan
    I need auto-logoff system in my application. if user not using the application more than thirty minutes.they should log in again. this is what i need. lastAccessTime should be lesser than 30 minutes. if lastAccessTime exceeds than 30 minutes user should login again with their credentials. (currently i auto log off using Lastaccesstime field in My user table (database) and compare lastaccesstime with current time for every page loads, I do not think this is right way.) is their any way to achieve? Thanks in advance.

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  • PHP, is_array() generating an "Undefined property: stdClass::$crit " error

    - by Brook Julias
    is_array($src2->crit) is generating an "Undefined property: stdClass::$crit" error. The line throwing the error is: if(is_array($src2->crit) && count($src->crit) > 0){ $src2->crit is initialized here. $src2->crit = array(); $src2->crit[0] = new dataSet(); $src2->crit[0]->tblName = $tbl2; $src2->crit[0]->colName = "ID"; $src2->crit[0]->val = $elm->editID; When testing $src2->crit with this code. print("\$src->crit is a ".$src->crit."<br />"); print_r($src->crit); print("<br />"); This is returned. $src2->crit is a Array Array ( [0] => dataSet Object ( [tblName] => sExam [colName] => ID [val] => 10 ) ) What am I not seeing/understanding correctly? If print("\$src2->crit is a ".$src->crit."<br />") returns that it is an array then why is is_array($src2->$crit) generating an error?

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  • PHP versions warning on Plesk 11.0.9 upgrade on CentOS server

    - by Pixman
    I have a server turning on Plesk 10.4.4 and I want to upgrade it to 11.0.9. When I use the online upgrade tool, I have this warning: Parallels Panel pre-upgrade check... WARNING: You have a mixed set of 'php' and 'php53' packages installed. Installation or upgrade may fail or produce unexpected results. To resolve this issue run "sed -i.bak -e '/^\s*skip-bdb\s*$/d' /etc/my.cnf ; yum update 'php*' 'mysql*'". PHP Warning: Directive 'safe_mode' is deprecated in PHP 5.3 and greater in Unknown on line 0 I have run the code in ssh, but nothing changes. I have already searched all package names with "php", and I have this list: # yum list installed | grep php php-common.i386 5.3.13-5.el5.art installed php-pear.noarch 1:1.4.9-8.el5 installed php5-ioncube-loader.i386 4.0.7-11062118 installed php53.i386 5.3.3-13.el5_8 installed php53-cli.i386 5.3.3-13.el5_8 installed php53-devel.i386 5.3.3-13.el5_8 installed php53-gd.i386 5.3.3-13.el5_8 installed php53-imap.i386 5.3.3-13.el5_8 installed php53-mbstring.i386 5.3.3-13.el5_8 installed php53-mcrypt.i386 5.3.3-1.el5 installed php53-mysql.i386 5.3.3-13.el5_8 installed php53-pdo.i386 5.3.3-13.el5_8 installed php53-sqlite2.i386 5.3.2-11041315 installed php53-xml.i386 5.3.3-13.el5_8 installed psa-appvault-phpads.noarch 2.0.8-8203520080409011611 installed psa-appvault-phpbb.noarch 3.0.0-8200820080409011626 installed psa-appvault-phpbook.noarch 1.50-8203220080409011638 installed psa-appvault-phpbugtracker.noarch 1.19-8203820080416050605 installed psa-appvault-phpdig.noarch 1.85-8203120080409011645 installed psa-appvault-phpmoney.noarch 1.3-8204320080409011649 installed psa-appvault-phpmyfamily.noarch 1.4.1-8203420080409011655 installed psa-appvault-phpmyvisites.noarch 2.3-8202820080409011701 installed psa-appvault-phprojekt.noarch 5.2-8200820080409011713 installed psa-appvault-phpsurveyor.noarch 0.98-8204320080409011723 installed psa-appvault-phpwebsite.noarch 0.10.2-8203420080409011738 installed psa-appvault-phpwiki.noarch 1.3.11-8204320080409011808 installed psa-php53-configurator.i386 1.6.1-cos5.build1013111101.14 installed After verification in the Plesk file: panel_preupgrade_checker.php I think the warning is due to these lines: (from : panel_preupgrade_checker.php) foreach ($packages as $package) { $name = $package['name']; $hasPhp5 |= ($name == 'php' || strpos($name, 'php-') === 0); $hasPhp53 |= (strpos($name, 'php53') === 0); } Now, I think the problem is just due to the names of theses packages: php-common.i386 5.3.13-5.el5.art installed php-pear.noarch 1:1.4.9-8.el5 installed Can you help me to resolve this situation?

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  • How do i serlialize the product using php?

    - by Ibrahim Azhar Armar
    hi, i am building a real estate application where in it will store the properties and search it. the property will have different categories like (residential, commercial, industrial or agricultural). based upon the category i want to serailize each and every property listing . for example the property with id 1 belongs to resedential will have the serial code rs_SOMERANDOMUNIQUENUMBER. and for commercial it can be cm_SOMERANDOMUNIQUENUMBER and so on. for this my database table looks like this. CREATE TABLE IF NOT EXISTS `propSerials` ( `id` bigint(20) NOT NULL auto_increment, `serial` varchar(50) NOT NULL, `property_id` int(10) UNIQUE NOT NULL, PRIMARY KEY  (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8; what would be the best possible format to store the serial with the prefix according to category? thank you

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  • php class extend - run something before running parent function

    - by Patrick
    Hi, say I have this class: class animal { function noise() { print 'woof'; } function move() { print 'moved'; } } class dog extends animal { } What I would like to do is when i run $dog-noise() or $dog-move(), it would run something first prior to calling animal class's noise/move. Is this doable? Like maybe logging the function call. If not with class extend, what else can I use to achieve this? Thank you!

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  • php forms insert and update

    - by DAFFODIL
    I have a form.The user enter the data ,the data will be stored in the data base. Now,using phpmysql,i need to display the whole data present in db to front end.The user will click a particular thing and make some modifications and if,he press update the data should get into database. Give me a snippet http://dpaste.com/hold/178740/

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  • Are Dynamic Prepared Statements Bad? (with php + mysqli)

    - by John
    I like the flexibility of Dynamic SQL and I like the security + improved performance of Prepared Statements. So what I really want is Dynamic Prepared Statements, which is troublesome to make because bind_param and bind_result accept "fixed" number of arguments. So I made use of an eval() statement to get around this problem. But I get the feeling this is a bad idea. Here's example code of what I mean // array of WHERE conditions $param = array('customer_id'=>1, 'qty'=>'2'); $stmt = $mysqli->stmt_init(); $types = ''; $bindParam = array(); $where = ''; $count = 0; // build the dynamic sql and param bind conditions foreach($param as $key=>$val) { $types .= 'i'; $bindParam[] = '$p'.$count.'=$param["'.$key.'"]'; $where .= "$key = ? AND "; $count++; } // prepare the query -- SELECT * FROM t1 WHERE customer_id = ? AND qty = ? $sql = "SELECT * FROM t1 WHERE ".substr($where, 0, strlen($where)-4); $stmt->prepare($sql); // assemble the bind_param command $command = '$stmt->bind_param($types, '.implode(', ', $bindParam).');'; // evaluate the command -- $stmt->bind_param($types,$p0=$param["customer_id"],$p1=$param["qty"]); eval($command); Is that last eval() statement a bad idea? I tried to avoid code injection by encapsulating values behind the variable name $param. Does anyone have an opinion or other suggestions? Are there issues I need to be aware of?

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  • php shuffle() returns one item

    - by mike
    Anyone have any idea why shuffle() would only return 1 item? when using: $array2 = shuffle($array1); with the following array($array1): Array ( [0] => 1 [1] => 5 [2] => 6 [3] => 7 [4] => 8 [5] => 10 [6] => 11 [7] => 12 [8] => 13 [9] => 14 ) The output of: print_r($array2); is simply: 1 Any idea as to why it would not only not shuffle the array, but knock off the remaining 9 items in the array? thanks!

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  • MySQL access classes in PHP

    - by Mike
    I have a connection class for MySQL that looks like this: class MySQLConnect { private $connection; private static $instances = 0; function __construct() { if(MySQLConnect::$instances == 0) { //Connect to MySQL server $this->connection = mysql_connect(MySQLConfig::HOST, MySQLConfig::USER, MySQLConfig::PASS) or die("Error: Unable to connect to the MySQL Server."); MySQLConnect::$instances = 1; } else { $msg = "Close the existing instance of the MySQLConnector class."; die($msg); } } public function singleQuery($query, $databasename) { mysql_select_db(MySQLConfig::DB, $this->connection) or die("Error: Could not select database " . MySQLConfig::DB . " from the server."); $result = mysql_query($query) or die('Query failed.'); return $result; } public function createResultSet($query, $databasename) { $rs = new MySQLResultSet($query, MySQLConfig::DB, $this->connection ) ; return $rs; } public function close() { MySQLConnect::$instances = 0; if(isset($this->connection) ) { mysql_close($this->connection) ; unset($this->connection) ; } } public function __destruct() { $this->close(); } } The MySQLResultSet class looks like this: class MySQLResultSet implements Iterator { private $query; private $databasename; private $connection; private $result; private $currentRow; private $key = 0; private $valid; public function __construct($query, $databasename, $connection) { $this->query = $query; //Select the database $selectedDatabase = mysql_select_db($databasename, $connection) or die("Error: Could not select database " . $this->dbname . " from the server."); $this->result = mysql_query($this->query) or die('Query failed.'); $this->rewind(); } public function getResult() { return $this->result; } // public function getRow() // { // return mysql_fetch_row($this->result); // } public function getNumberRows() { return mysql_num_rows($this->result); } //current() returns the current row public function current() { return $this->currentRow; } //key() returns the current index public function key() { return $this->key; } //next() moves forward one index public function next() { if($this->currentRow = mysql_fetch_array($this->result) ) { $this->valid = true; $this->key++; }else{ $this->valid = false; } } //rewind() moves to the starting index public function rewind() { $this->key = 0; if(mysql_num_rows($this->result) > 0) { if(mysql_data_seek($this->result, 0) ) { $this->valid = true; $this->key = 0; $this->currentRow = mysql_fetch_array($this->result); } } else { $this->valid = false; } } //valid returns 1 if the current position is a valid array index //and 0 if it is not valid public function valid() { return $this->valid; } } The following class is an example of how I am accessing the database: class ImageCount { public function getCount() { $mysqlConnector = new MySQLConnect(); $query = "SELECT * FROM images;"; $resultSet = $mysqlConnector->createResultSet($query, MySQLConfig::DB); $mysqlConnector->close(); return $resultSet->getNumberRows(); } } I use the ImageCount class like this: if(!ImageCount::getCount()) { //Do something } Question: Is this an okay way to access the database? Could anybody recommend an alternative method if it is bad? Thank-you.

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  • How does my php function for converting a date to facebook timestamp look? New to PHP.

    - by First2Drown
    any suggestions to make it better? function convertToFBTimestamp($date){ $this_date = date('Y-m-d-H-i-s', strtotime($date)); $cur_date = date('Y-m-d-H-i-s'); list ($this_year, $this_month, $this_day, $this_hour, $this_min, $this_sec) = explode('-',$this_date); list ($cur_year, $cur_month, $cur_day, $cur_hour, $cur_min, $cur_sec) = explode('-',$cur_date); $this_unix_time = mktime($this_hour, $this_min, $this_sec, $this_month, $this_day, $this_year); $cur_unix_time = mktime($cur_hour, $cur_min, $cur_sec, $cur_month, $cur_day, $cur_year); $cur_unix_date = mktime(0, 0, 0, $cur_month, $cur_day, $cur_year); $dif_in_sec = $cur_unix_time - $this_unix_time; $dif_in_min = (int)($dif_in_sec / 60); $dif_in_hours = (int)($dif_in_min / 60); if(date('Y-m-d',strtotime($date))== date('Y-m-d')) { if($dif_in_sec < 60) { return $dif_in_sec." seconds ago"; } elseif($dif_in_sec < 120) { return "about a minute ago"; } elseif($dif_in_min < 60) { return $dif_in_min." minutes ago"; } else { if($dif_in_hours == 1) { return $dif_in_hours." hour ago"; } else { return $dif_in_hours." hours ago"; } } } elseif($cur_unix_date - $this_unix_time < 86400 ) { return strftime("Yesterday at %l:%M%P",$this_unix_time); } elseif($cur_unix_date - $this_unix_time < 259200) { return strftime("%A at %l:%M%P",$this_unix_time); } else { if($this_year == $cur_year) { return strftime("%B, %e at %l:%M%P",$this_unix_time); } else { return strftime("%B, %e %Y at %l:%M%P",$this_unix_time); } } }

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  • PHP Modify Array

    - by Ozzy
    Hi all, I have the following array: array(a, a, a, b, b, c, c, c, c, d, d); When I loop through it and echo it, the result is: a a a b b c c c c d d How ever I want to echo it in such a way that it displays: a b c d a b c d a c c Here is the array in a grid to better explain what im trying to achieve Current a a a b b c c c c d d What im tryin to do a b c d a b c d a c c How would I do this?

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  • Php is stripping one letter "g" from my rtrim function but not other chars

    - by Chase
    I'm trying to trim some youtube URLs that I am reading in from a playlist. The first 3 work fine and all their URLs either end in caps or numbers but this one that ends in a lower case g is getting trimmed one character shorter than the rest. for ($z=0; $z <= 3; $z++) { $ythref2 = rtrim($tubeArray["feed"]["entry"][$z]["link"][0]["href"], '&feature=youtube_gdata'); The URL is http://www.youtube.com/watch?v=CuE88oVCVjg&feature=youtube_gdata .. and it should get trimmed down to .. http://www.youtube.com/watch?v=CuE88oVCVjg but instead it is coming out as http://www.youtube.com/watch?v=CuE88oVCVj. I think it may be the ampersand symbol but I am not sure.

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  • php regex - can't find the error

    - by peirix
    Just one simple, specific question: I've got the string {var1}12345{var2}, and I want to get the variable names used. if (preg_match("/{([a-zA-Z0-9]*)}/g", $url, $matches)) { print_r($matches); } If I remove the global flag, it works, but I only get the first variable, as expected. Why isn't it working with a global flag? It works when I'm testing it with the Regex Tester

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  • Wrong colors when merging images with PHP

    - by OfficeJet
    Hi, I want to get images ID's and creat from files a merged image according to the given ID's. This code is called by ajax and return the image file name (which is the server time to prevent browser caching). code: if (isset($_REQUEST['items'])){ $req_items = $_REQUEST['items']; } else { $req_items = 'a'; } $items = explode(',',$req_items); $bg_img = imagecreatefrompng('bg.png'); for ($i=0; $i<count($items); $i++){ $main_img = $items[$i].'-large.png'; $image = imagecreatefrompng($main_img); $image_tc = imagecreatetruecolor(300, 200); imagecopy($image_tc,$image,0,0,0,0,300,200); $black = imagecolorallocate($image_tc, 0, 0, 0); imagecolortransparent($image_tc, $black); $opacity = 100; $bg_width = 300; $bg_height = 200; $dest_x = 0;//$image_size[0] - $bg_width - $padding; $dest_y = 0;//$image_size[1] - $bg_height - $padding; imagecopymerge($bg_img, $image_tc, $dest_x, $dest_y, 0, 0, $bg_width, $bg_height, $opacity) ; } $file = $_SERVER['REQUEST_TIME'].'.jpg'; imagejpeg($bg_img, $file, 100); echo $file; imagedestroy($bg_img); imagedestroy($image); die(); The images are shown exactly as I want but with wrong colors. I lately added the part with imagecreatetruecolor and imagecolortransparent, and still got wrong results. I also saved the PNG itself on a 24 bit format and also later as 8 bit - not helping. every ideas is very welcomed ! Thanks

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  • change font in sharedbook api in php

    - by ashish
    I m using Sharedbook api to generate a memory book, although it's working perfect, but font of the memory book is unchangeable ...means i can't change the font family of that book. I tried to change the font then it display error. please suggest me how to change Font of that memory book.. Thank is advance

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  • Best way to stop SQL Injection in PHP

    - by Andrew G. Johnson
    So specifically in a mysql database. Take the following code and tell me what to do. // connect to the mysql database $unsafe_variable = $_POST["user-input"]; mysql_query("INSERT INTO table (column) VALUES ('" . $unsafe_variable . "')"); // disconnect from the mysql database

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  • get value from MySQL database with PHP

    - by Hristo
    $from = $_POST['from']; $to = $_POST['to']; $message = $_POST['message']; $query = "SELECT * FROM Users WHERE `user_name` = '$from' LIMIT 1"; $result = mysql_query($query); while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $fromID = $row['user_id']; } I'm trying to have $formID be the user_id for a user in my database. Each row in the Users table is like: user_id | user_name | user_type 1 | Hristo | Agent So I want $from = 1 but the above code isn't working. Any ideas why?

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  • php push 2d array into mysql

    - by john
    Hay All, I cant seem to get my head around this dispite the number to examples i read. Basically I have a 2d array and want to insert it into MySQL. The array contains a few strings. I cant get the following to work... $value = addslashes(serialize($temp3));//temp3 is my 2d array, do i need to use keys? (i am not at the moment) $query = "INSERT INTO table sip (id,keyword,data,flags) VALUES(\"$value\")"; mysql_query($query) or die("Failed Query"); Thanks Guys,

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