Search Results

Search found 13534 results on 542 pages for 'python 2 1'.

Page 389/542 | < Previous Page | 385 386 387 388 389 390 391 392 393 394 395 396  | Next Page >

  • Turbogears 2 vs Django - any advice on choosing replacement for Turbogears 1?

    - by michela
    I have been using Turbogears 1 for prototyping small sites for the last couple of years and it is getting a little long in the tooth. Any suggestions on making the call between upgrading to Turbogears 2 or switching to something like Django? I'm torn between the familiarity of the TG community who are pretty responsive and do pretty good documentation vs the far larger community using Django. I am quite tempted by the built-in CMS features and the Google AppEngine support. Any advice? Thanks .M.

    Read the article

  • Modify passed, nested dict/list

    - by Gerenuk
    I was thinking of writing a function to normalize some data. A simple approach is def normalize(l, aggregate=sum, norm_by=operator.truediv): aggregated=aggregate(l) for i in range(len(l)): l[i]=norm_by(l[i], aggregated) l=[1,2,3,4] normalize(l) l -> [0.1, 0.2, 0.3, 0.4] However for nested lists and dicts where I want to normalize over an inner index this doesnt work. I mean I'd like to get l=[[1,100],[2,100],[3,100],[4,100]] normalize(l, ?? ) l -> [[0.1,100],[0.2,100],[0.3,100],[0.4,100]] Any ideas how I could implement such a normalize function? Maybe it would be crazy cool to write normalize(l[...][0]) Is it possible to make this work?? Or any other ideas? Also not only lists but also dict could be nested. Hmm... EDIT: I just found out that numpy offers such a syntax (for lists however). Anyone know how I would implement the ellipsis trick myself?

    Read the article

  • Encrypt file using M2Crypto

    - by Bear
    It is known that I can read the whole file content in memory and encrypt it using the following code. contents = fin.read() cipher = M2Crypto.EVP.Cipher(alg="aes_128_cbc", key = aes_key, iv = aes_iv, op = 1) encryptedContents = cipher.update(contents) encryptedContents += cipher.final() But what if the file size is large, is there a way for me to pass the input stream to M2Crypto instead of reading the whole file first?

    Read the article

  • How to sort a Pandas DataFrame according to multiple criteria?

    - by user1715271
    I have the following DataFrame containing song names, their peak chart positions and the number of weeks they spent at position no 1: Song Peak Weeks 76 Paperback Writer 1 16 117 Lady Madonna 1 9 118 Hey Jude 1 27 22 Can't Buy Me Love 1 17 29 A Hard Day's Night 1 14 48 Ticket To Ride 1 14 56 Help! 1 17 109 All You Need Is Love 1 16 173 The Ballad Of John And Yoko 1 13 85 Eleanor Rigby 1 14 87 Yellow Submarine 1 14 20 I Want To Hold Your Hand 1 24 45 I Feel Fine 1 15 60 Day Tripper 1 12 61 We Can Work It Out 1 12 10 She Loves You 1 36 155 Get Back 1 6 8 From Me To You 1 7 115 Hello Goodbye 1 7 2 Please Please Me 2 20 92 Strawberry Fields Forever 2 12 93 Penny Lane 2 13 107 Magical Mystery Tour 2 16 176 Let It Be 2 14 0 Love Me Do 4 26 157 Something 4 9 166 Come Together 4 10 58 Yesterday 8 21 135 Back In The U.S.S.R. 19 3 164 Here Comes The Sun 58 19 96 Sgt. Pepper's Lonely Hearts Club Band 63 12 105 With A Little Help From My Friends 63 7 I'd like to rank these songs in order of popularity, so I'd like to sort them according to the following criteria: songs that reached the highest position come first, but if there is a tie, the songs that remained in the charts for the longest come first. I can't seem to figure out how to do this in Pandas.

    Read the article

  • Adding a child node to a JSON node dynamically

    - by Sai
    I have to create a nested multi level json depending on the resultset that I get from MYSQL. I created a json object initially. Now I want to add child nodes to the already child nodes in the object. d = collections.OrderedDict() jsonobj = {"test": dict(updated_at="today", ID="ID", ads=[])} for rows1 in rs: jsonobj['list']["ads"].append(dict(unit = "1", type ="ad_type", id ="123", updated_at="today", x_id="111", x_name="test")) cur.execute("SELECT * from f_test") rs1 = cur.fetchall() for rows2 in rs1: propertiesObj = [] d["name"]="propName" d["type"]="TypeName" d["value"]="Value1" propertiesObj.append(d) jsonobj['play_list']["ads"].append() Here in the above line I want to add another child node to [play_list].[ads] which is a array list again. the output should look like the following [list].[ads].[preferences].

    Read the article

  • What is the difference between .get() and .fetch(1)

    - by AutomatedTester
    I have written an app and part of it is uses a URL parser to get certain data in a ReST type manner. So if you put /foo/bar as the path it will find all the bar items and if you put /foo it will return all items below foo So my app has a query like data = Paths.all().filter('path =', self.request.path).get() Which works brilliantly. Now I want to send this to the UI using templates {% for datum in data %} <div class="content"> <h2>{{ datum.title }}</h2> {{ datum.content }} </div> {% endfor %} When I do this I get data is not iterable error. So I updated the Django to {% for datum in data.all %} which now appears to pull more data than I was giving it somehow. It shows all data in the datastore which is not ideal. So I removed the .all from the Django and changed the datastore query to data = Paths.all().filter('path =', self.request.path).fetch(1) which now works as I intended. In the documentation it says The db.get() function fetches an entity from the datastore for a Key (or list of Keys). So my question is why can I iterate over a query when it returns with fetch() but can't with get(). Where has my understanding gone wrong?

    Read the article

  • Divide numpy array

    - by BandGap
    Hi all I have some data represented in a 1300x1341 matrix. I would like to split this matrix in several pieces (e.g. 9) so that I can loop over and process them. The data needs to stay ordered in the sense that x[0,1] stays below (or above if you like) x[0,0] and besides x[1,1]. Just like if you had imaged the data, you could draw 2 vertical and 2 horizontal lines over the image to illustrate the 9 parts. If I use numpys reshape (eg. matrix.reshape(9,260,745) or any other combination of 9,260,745) it doesn't yield the required structure since the above mentioned ordering is lost... Did I misunderstand the reshape method or can it be done this way? What other pythonic/numpy way is there to do this?

    Read the article

  • How to get these values with BeautifulSoup?

    - by Damiano
    Hello everybody, I have this html table: <table> <tr> <td class="datax">a</td> <td class="datax">b</td> <td class="datax">c</td> <td class="datax">d</td> </tr> <tr> <td class="datax">e</td> <td class="datax">f</td> <td class="datax">g</td> <td class="datax">h</td> </tr> </table> How to get the second and the fourth value of each <tr> ? If i do: bs.findAll('td', {'class':'datax'}) I get: <td class="datax">a</td> <td class="datax">b</td> <td class="datax">c</td> <td class="datax">d</td> <td class="datax">e</td> <td class="datax">f</td> <td class="datax">g</td> <td class="datax">h</td> it's correct! but I would like to have this result: <td class="datax">b</td> <td class="datax">d</td> <td class="datax">f</td> <td class="datax">h</td> so, the values I want are - b - d - f - h (the second and the forth <td> of each <tr>) Is it possible with BeautifulSoup module? Thank you very much!

    Read the article

  • How to select a MenuItem programatically

    - by Shaung
    I am trying to add a global shortcut to a gtk.MenuItem which has a sub menu. Here is my code: import pygtk, gtk import keybinder dlg = gtk.Dialog('menu test') dlg.set_size_request(200, 40) menubar = gtk.MenuBar() menubar.show() menuitem = gtk.MenuItem('foo') menuitem.show() menubar.append(menuitem) mitem = gtk.MenuItem('bar') mitem.show() menu = gtk.Menu() menu.add(mitem) menu.show() menuitem.set_submenu(menu) def show_menu_cb(): menubar.select_item(menuitem) keybinder.bind('<Super>i', show_menu_cb) dlg.vbox.pack_start(menubar) dlg.show() dlg.run() When I press the key menu pops up, I can then select items in the sub menu or press Esc to make it disappear. But after that the menuitem keeps selected and other windows never get input focus again. I have to click on the menuitem twice to get everything back normal.

    Read the article

  • Django, url tag in template doesn't work: NoReverseMatch

    - by Lukasz Jocz
    I've encountered a problem with generating reverse url in templates in django. I'm trying to solve it since a few hours and I have no idea what the problem might be. URL reversing works great in models and views: # like this in models.py @models.permalink def get_absolute_url(self): return ('entry', (), { 'entry_id': self.entry.id, }) # or this in views.py return HttpResponseRedirect(reverse('entry',args=(entry_id,))) but when I'm trying to make it in template I get such an error: NoReverseMatch at /entry/1/ Reverse for ''add_comment'' with arguments '(1L,)' and keyword arguments '{}' not found. My file structure looks like this: project/ +-- frontend ¦   +-- models.py ¦   +-- urls.py ¦   +-- views.py +-- settings.py +-- templates ¦   +-- add_comment.html ¦   +-- entry.html +-- utils ¦   +-- with_template.py +-- wsgi.py My urls.py: from project.frontend.views import * from django.conf.urls import patterns, include, url urlpatterns = patterns('project.frontend.views', url(r'^entry/(?P<entry_id>\d+)/', 'entry', name="entry"), (r'^entry_list/', 'entry_list'), Then entry_list.html: {% extends "base.html" %} {% block content %} {% for entry in entries %} {% url 'entry' entry.id %} {% endfor %} {% endblock %} In views.py I have: @with_template def entry(request, entry_id): entry = Entry.objects.get(id=entry_id) entry.comments = entry.get_comments() return locals() where with_template is following decorator(but I don't think this is a case): class TheWrapper(object): def __init__(self, default_template_name): self.default_template_name = default_template_name def __call__(self, func): def decorated_func(request, *args, **kwargs): extra_context = kwargs.pop('extra_context', {}) dictionary = {} ret = func(request, *args, **kwargs) if isinstance(ret, HttpResponse): return ret dictionary.update(ret) dictionary.update(extra_context) return render_to_response(dictionary.get('template_name', self.default_template_name), context_instance=RequestContext(request), dictionary=dictionary) update_wrapper(decorated_func, func) return decorated_func if not callable(arg): return TheWrapper(arg) else: default_template_name = ''.join([ arg.__name__, '.html']) return TheWrapper(default_template_name)(arg) Do you have any idea, what may cause the problem? Great thanks in advance!

    Read the article

  • Attribute Address getting displayed instead of Attribute Value

    - by Manish
    I am try to create the following. I want to have one drop down menu. Depending on the option selected in the first drop down menu, options in second drop down menu will be displayed. The options in 2nd drop down menu is supposed by dynamic, i.e., options change with the change of values in first menu. Here, instead of getting the drop down menus, I am getting the following Choose your Option1: Choose your Option2: Note: I strictly don't want to use javascript. home_form.py class HomeForm(forms.Form): def __init__(self, *args, **kwargs): var_filter_con = kwargs.pop('filter_con', None) super(HomeForm, self).__init__(*args, **kwargs) if var_filter_con == '***': var_empty_label = None else: var_empty_label = ' ' self.option2 = forms.ModelChoiceField(queryset = db_option2.objects.filter(option1_id = var_filter_con).order_by("name"), empty_label = var_empty_label, widget = forms.Select(attrs={"onChange":'this.form.submit();'}) ) self.option1 = forms.ModelChoiceField(queryset = db_option1.objects.all().order_by("name"), empty_label=None, widget=forms.Select(attrs={"onChange":'this.form.submit();'}) ) view.py def option_view(request): if request.method == 'POST': form = HomeForm(request.POST) if form.is_valid(): cd = form.cleaned_data if cd.has_key('option1'): f = HomeForm(filter_con = cd.get('option1')) return render_to_response('homepage.html', {'home_form':f,}, context_instance=RequestContext(request)) return render_to_response('invalid_data.html', {'form':form,}, context_instance=RequestContext(request)) else: f = HomeForm(filter_con = '***') return render_to_response('homepage.html', {'home_form':f,}, context_instance=RequestContext(request)) homepage.html <!DOCTYPE HTML> <head> <title>Nivaaran</title> </head> <body> <form method="post" name = 'choose_opt' action=""> {% csrf_token %} Choose your Option1: {{ home_form.option1 }} <br/> Choose your Option2: {{ home_form.option2 }} </form> </body>

    Read the article

  • scrapping blog contents

    - by goh
    Hi lads, After obtaining the urls for various blogspots, tumblr and wordpress pages, I faced some problems processing the html pages. The thing is, i wish to distinguish between the content,title and date for each blog post. I might be able to get the date through regex, but there are so many custom scripts people are using now that the html classes and structure is so different. Does anyone has a solution that may help?

    Read the article

  • Possible to change function name in definition?

    - by Bird Jaguar IV
    I tried several ways to change the function name in the definition, but they failed. >>> def f(): pass >>> f.__name__ 'f' >>> def f(): f.__name__ = 'new name' >>> f.__name__ 'f' >>> def f(): self.__name__ = 'new name' >>> f.__name__ 'f' But I can change the name attribute after defining it. >>> def f(): pass >>> f.__name__ = 'new name' >>> f.__name__ 'new name' Any way to change/set it in the definition (other than using a decorator)?

    Read the article

  • How to slice a list of objects in association of the object attributes

    - by gizgok
    I have a list of fixtures.Each fixture has a home club and a away club attribute.I want to slice the list in association of its home club and away club.The sliced list should be of homeclub items and awayclub items. Easier way to implement this is to first slice a list of fixtures.Then make a new list of the corresponding Home Clubs and Away Clubs.I wanted to know if we can do this one step.

    Read the article

  • How to call same method for a list of objects?

    - by Dmitry
    Suppose code like this: class Base: def start(self): pass def stop(self) pass class A(Base): def start(self): ... do something for A def stop(self) .... do something for A class B(Base): def start(self): def stop(self): a1 = A(); a2 = A() b1 = B(); b2 = B() all = [a1, b1, b2, a2,.....] Now I want to call methods start and stop (maybe also others) for each object in the list all. Is there any elegant way for doing this except of writing a bunch of functions like def start_all(all): for item in all: item.start() def stop_all(all): .....

    Read the article

  • how to create a theme with QT

    - by Moayyad Yaghi
    hello im looking for a way to make my pyqt interface look nicer by adding a theme to it. im new to Qt and i still have no idea how to add a custom theme for widgets.. so how is that possible ? and is it possible through qt designer ? sorry for my bad english , its my third language. i hope the idea is clear enough . please let me know if something was unclear .. thanks in advace

    Read the article

  • datetime object

    - by Rahul99
    My input string is '16-MAR-2010 03:37:04' and i want to store it as datetime. I am trying to use: db_inst.HB_Create_Ship_Date = datetime.strptime(fields[7]," %d-%b-%Y %H:%M:%S ") fields[7] = '16-MAR-2010 03:37:04' I am getting an error: ::ValueError: time data '16-MAR-2010 03:37:04' does not match format ' %d-%b-%Y %H:%M:%S ' Which format do I have to use?

    Read the article

  • I Made Simple Generator,, Is there any faster way ??

    - by Rami Jarrar
    Hi, i do like this: import time f = open('wl4.txt', 'w') hh = 0 ###################################### for n in range(1,5): for l in range(33,127): if n==1: b = chr(l) + '\n' f.write(b) hh += 1 elif n==2: for s0 in range(33, 127): b = chr(l) + chr(s0) + '\n' f.write(b) hh += 1 elif n==3: for s0 in range(33, 127): for s1 in range(33, 127): b = chr(l) + chr(s0) + chr(s1) + '\n' f.write(b) hh += 1 elif n==4: for s0 in range(33, 127): for s1 in range(33, 127): for s2 in range(33,127): b = chr(l) + chr(s0) + chr(s1) + chr(s2) + '\n' f.write(b) hh += 1 ###################################### print "We Made %d Words." %(hh) ###################################### f.close() So, is there any faster method to make it faster,,

    Read the article

  • Can I db.put models without db.getting them first?

    - by Liron
    I tried to do something like ss = Screenshot(key=db.Key.from_path('myapp_screenshot', 123), name='flowers') db.put([ss, ...]) It seems to work on my dev_appserver, but on live I get this traceback: 05-07 09:50PM 19.964 File "/base/data/home/apps/quixeydev3/12.341796548761906563/common/appenginepatch/appenginepatcher/patch.py", line 600, in put E 05-07 09:50PM 19.964 result = old_db_put(models, *args, **kwargs) E 05-07 09:50PM 19.964 File "/base/python_runtime/python_lib/versions/1/google/appengine/ext/db/init.py", line 1278, in put E 05-07 09:50PM 19.964 keys = datastore.Put(entities, rpc=rpc) E 05-07 09:50PM 19.964 File "/base/python_runtime/python_lib/versions/1/google/appengine/api/datastore.py", line 284, in Put E 05-07 09:50PM 19.965 raise _ToDatastoreError(err) E 05-07 09:50PM 19.965 InternalError: the new entity or index you tried to insert already exists I happen to know just the ID of an existing Screenshot entity I want to update; that's why I was manually constructing its key. Am I doing it wrong?

    Read the article

< Previous Page | 385 386 387 388 389 390 391 392 393 394 395 396  | Next Page >