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  • JPA @OneToMany and composite PK

    - by Fleuri F
    Good Morning, I am working on project using JPA. I need to use a @OneToMany mapping on a class that has three primary keys. You can find the errors and the classes after this. If anyone has an idea! Thanks in advance! FF javax.persistence.PersistenceException: No Persistence provider for EntityManager named JTA_pacePersistence: Provider named oracle.toplink.essentials.PersistenceProvider threw unexpected exception at create EntityManagerFactory: javax.persistence.PersistenceException javax.persistence.PersistenceException: Exception [TOPLINK-28018] (Oracle TopLink Essentials - 2.0.1 (Build b09d-fcs (12/06/2007))): oracle.toplink.essentials.exceptions.EntityManagerSetupException Exception Description: predeploy for PersistenceUnit [JTA_pacePersistence] failed. Internal Exception: Exception [TOPLINK-7220] (Oracle TopLink Essentials - 2.0.1 (Build b09d-fcs (12/06/2007))): oracle.toplink.essentials.exceptions.ValidationException Exception Description: The @JoinColumns on the annotated element [private java.util.Set isd.pacepersistence.common.Action.permissions] from the entity class [class isd.pacepersistence.common.Action] is incomplete. When the source entity class uses a composite primary key, a @JoinColumn must be specified for each join column using the @JoinColumns. Both the name and the referenceColumnName elements must be specified in each such @JoinColumn. at oracle.toplink.essentials.internal.ejb.cmp3.EntityManagerSetupImpl.predeploy(EntityManagerSetupImpl.java:643) at oracle.toplink.essentials.ejb.cmp3.EntityManagerFactoryProvider.createEntityManagerFactory(EntityManagerFactoryProvider.java:196) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:110) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:83) at isd.pacepersistence.common.DataMapper.(Unknown Source) at isd.pacepersistence.server.MainServlet.getDebugCase(Unknown Source) at isd.pacepersistence.server.MainServlet.doGet(Unknown Source) at javax.servlet.http.HttpServlet.service(HttpServlet.java:718) at javax.servlet.http.HttpServlet.service(HttpServlet.java:831) at org.apache.catalina.core.ApplicationFilterChain.servletService(ApplicationFilterChain.java:411) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:290) at org.apache.catalina.core.StandardContextValve.invokeInternal(StandardContextValve.java:271) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:202) There is the source code of my classes : Action : @Entity @Table(name="action") public class Action { @Id @GeneratedValue(strategy=GenerationType.IDENTITY) private int num; @ManyToOne(cascade= { CascadeType.PERSIST, CascadeType.MERGE, CascadeType.REFRESH }) @JoinColumn(name="domain_num") private Domain domain; private String name; private String description; @OneToMany @JoinTable(name="permission", joinColumns= { @JoinColumn(name="action_num", referencedColumnName="action_num", nullable=false, updatable=false) }, inverseJoinColumns= { @JoinColumn(name="num") }) private Set<Permission> permissions; public Action() { } Permission : @SuppressWarnings("serial") @Entity @Table(name="permission") public class Permission implements Serializable { @EmbeddedId private PermissionPK primaryKey; @ManyToOne @JoinColumn(name="action_num", insertable=false, updatable=false) private Action action; @ManyToOne @JoinColumn(name="entity_num", insertable=false, updatable=false) private isd.pacepersistence.common.Entity entity; @ManyToOne @JoinColumn(name="class_num", insertable=false, updatable=false) private Clazz clazz; private String kondition; public Permission() { } PermissionPK : @SuppressWarnings("serial") @Entity @Table(name="permission") public class Permission implements Serializable { @EmbeddedId private PermissionPK primaryKey; @ManyToOne @JoinColumn(name="action_num", insertable=false, updatable=false) private Action action; @ManyToOne @JoinColumn(name="entity_num", insertable=false, updatable=false) private isd.pacepersistence.common.Entity entity; @ManyToOne @JoinColumn(name="class_num", insertable=false, updatable=false) private Clazz clazz; private String kondition; public Permission() { }

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  • JPA @TableGenerator shared between multiple entities

    - by Mauricio
    Hi Guys, I have a 'dog' Entitiy with an @Id and a @TableGenerator ... @TableGenerator(table = "seq", name = "dog_gen", pkColumnName = "seq_name", valueColumnName="seq_val") @Id @GeneratedValue(strategy = GenerationType.TABLE, generator = "dog_gen") private Long id; ... Is there a way to reuse the same table generator (dog_gen) in other entity? I want to keep the same id sequence in two independent Entities, say dog=1, dog=2, dog=3, cat=4, cat=5, dog=6 and so on... Both entities don't share a common superclass to implement some kind of inheritance with the id property. If I add the @GeneratedValue( generator="dog_gen") on my cat entity, omitting the @TableGenerator declaration throws an Exception saying it can't find the generator when starting the context. Caused by: org.hibernate.AnnotationException: Unknown Id.generator: dog_gen at org.hibernate.cfg.BinderHelper.makeIdGenerator(BinderHelper.java:413) at org.hibernate.cfg.AnnotationBinder.bindId(AnnotationBinder.java:1795) at org.hibernate.cfg.AnnotationBinder.processElementAnnotations(AnnotationBinder.java:1229) at org.hibernate.cfg.AnnotationBinder.bindClass(AnnotationBinder.java:733) at org.hibernate.cfg.AnnotationConfiguration.processArtifactsOfType(AnnotationConfiguration.java:498) at org.hibernate.cfg.AnnotationConfiguration.secondPassCompile(AnnotationConfiguration.java:277)

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  • enj annotation @oneToMany and @manyToOne

    - by chetan
    I have four table one parent table other three are child table related parent with parent primary key. Now I want to get list of child table into parent table with @oneToMany and @ManyToOne annotation of EJB. parentTable name : tblm_attendancepolicy---primary key name ---attendancepolicyid first childtable name :tblm_empattendancepolicy second child table name : tblm_deptattendacepolicy. third child table name : tblm_compattendancepolicy.

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  • Using hibernate criteria, is there a way to escape special characters?

    - by Kevin Crowell
    For this question, we want to avoid having to write a special query since the query would have to be different across multiple databases. Using only hibernate criteria, we want to be able to escape special characters. This situation is the reason for needing the ability to escape special characters: Assume that we have table 'foo' in the database. Table 'foo' contains only 1 field, called 'name'. The 'name' field can contain characters that may be considered special in a database. Two examples of such a name are 'name_1' and 'name%1'. Both the '_' and '%' are special characters, at least in Oracle. If a user wants to search for one of these examples after they are entered in the database, problems may occur. criterion = Restrictions.ilike("name", searchValue, MatchMode.ANYWHERE); return findByCriteria(null, criterion); In this code, 'searchValue' is the value that the user has given the application to use for its search. If the user wants to search for '%', the user is going to be returned with every 'foo' entry in the database. This is because the '%' character represents the "any number of characters" wildcard for string matching and the SQL code that hibernate produces will look like: select * from foo where name like '%' Is there a way to tell hibernate to escape certain characters, or to create a workaround that is not database type sepecific?

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  • Is this possible: JPA/Hibernate query with list property in result ?

    - by Kdeveloper
    In hibernate I want to run this JPQL / HQL query: select new org.test.userDTO( u.id, u.name, u.securityRoles) FROM User u WHERE u.name = :name userDTO class: public class UserDTO { private Integer id; private String name; private List<SecurityRole> securityRoles; public UserDTO(Integer id, String name, List<SecurityRole> securityRoles) { this.id = id; this.name = name; this.securityRoles = securityRoles; } ...getters and setters... } User Entity: @Entity public class User { @id private Integer id; private String name; @ManyToMany @JoinTable(name = "user_has_role", joinColumns = { @JoinColumn(name = "user_id") }, inverseJoinColumns = {@JoinColumn(name = "security_role_id") } ) private List<SecurityRole> securityRoles; ...getters and setters... } But when Hibernate 3.5 (JPA 2) starts I get this error: org.hibernate.hql.ast.QuerySyntaxException: Unable to locate appropriate constructor on class [org.test.UserDTO] [SELECT NEW org.test.UserDTO (u.id, u.name, u.securityRoles) FROM nl.test.User u WHERE u.name = :name ] Is a select that includes a list as a result not possible? Should I just create 2 seperate queries?

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  • when to use Hibernate vs. Simple ResultSets for small application

    - by luke
    I just started working on upgrading a small component in a distributed java application. The main application is a rather complicated applet/servlet combo running on JBoss and it extensively uses Hibernate for its DataAccess. The component i am working on however is very a very straightforward data importing service. Basically the workflow is Listen for a network event Parse the data packet, extract a set of identifiers Map the identifier set to a primary key in our database Parse the rest of the packet and insert items in a related table using the foreign key found in step 3 Repeat in the previous version of this component it used a hibernate based DAL, that is no longer usable for a variety of reasons (in particular it is EOL), so I am in charge of replacing the Data Access layer for this component. So on the one hand I think i should use Hibernate because that's what the rest of the application does, but on the other i think i should just use regular java.sql.* classes because my requirements are really straightforward and aren't expected to change any time soon. So my question is (and i understand it is subjective) at what point do you think that the added complexity of using an ORM tool (in terms of configuration, dependencies...) is worth it? UPDATE due to the way the DataAccesLayer for the main application was written (weird dependencies) i cannot easily use it, i would have to implement it myself.

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  • Database connection timeout

    - by Clinton Bosch
    Hi I have read so many articles on the Internet about this problem but none seem to have a clear solution. Please could someone give me a definite answer as to why I am getting database timeouts. The app is a GWT app that is being hosted on a Tomcat 5.5 server. I use spring and the session factory is created in the applicationContext.xml as follows <bean id="sessionFactory" class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean"> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">${connection.dialect}</prop> <prop key="hibernate.connection.username">${connection.username}</prop> <prop key="hibernate.connection.password">${connection.password}</prop> <prop key="hibernate.connection.url">${connection.url}</prop> <prop key="hibernate.connection.driver_class">${connection.driver.class}</prop> <prop key="hibernate.show_sql">${show.sql}</prop> <prop key="hibernate.hbm2ddl.auto">update</prop> <prop key="hibernate.c3p0.min_size">5</prop> <prop key="hibernate.c3p0.max_size">20</prop> <prop key="hibernate.c3p0.timeout">1800</prop> <prop key="hibernate.c3p0.max_statements">50</prop> <prop key="hibernate.c3p0.idle_test_period">300</prop> </props> </property> <property name="annotatedClasses"> <list> <value>za.co.xxxx.traintrack.server.model.Answer</value> <value>za.co.xxxx.traintrack.server.model.Company</value> <value>za.co.xxxx.traintrack.server.model.CompanyRegion</value> <value>za.co.xxxx.traintrack.server.model.Merchant</value> <value>za.co.xxxx.traintrack.server.model.Module</value> <value>za.co.xxxx.traintrack.server.model.Question</value> <value>za.co.xxxx.traintrack.server.model.User</value> <value>za.co.xxxx.traintrack.server.model.CompletedModule</value> </list> </property> </bean> <bean id="dao" class="za.co.xxxx.traintrack.server.DAO"> <property name="sessionFactory" ref="sessionFactory"/> <property name="adminUsername" value="${admin.user.name}"/> <property name="adminPassword" value="${admin.user.password}"/> <property name="godUsername" value="${god.user.name}"/> <property name="godPassword" value="${god.user.password}"/> </bean> All works fine untile the next day: INFO | jvm 1 | 2010/06/15 14:42:27 | 2010-06-15 18:42:27,804 WARN [JDBCExceptionReporter] : SQL Error: 0, SQLState: 08S01 INFO | jvm 1 | 2010/06/15 14:42:27 | 2010-06-15 18:42:27,821 ERROR [JDBCExceptionReporter] : The last packet successfully received from the server was 38729 seconds ago.The last packet sent successfully to the server was 38729 seconds ago, which is longer than the server configured value of 'wait_timeout'. You should consider either expiring and/or testing connection validity before use in your application, increasing the server configured values for client timeouts, or using the Connector/J connection property 'autoReconnect=true' to avoid this problem. INFO | jvm 1 | 2010/06/15 14:42:27 | Jun 15, 2010 6:42:27 PM org.apache.catalina.core.ApplicationContext log INFO | jvm 1 | 2010/06/15 14:42:27 | SEVERE: Exception while dispatching incoming RPC call I have read so many different things (none of which worked), please help

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  • IntelliJ with Maven compilation

    - by Mik378
    I have a project that needs Hibernate jars. I added them as dependencies in the pom.xml and Maven compiles my project well. However, in the IDE, all annotations and calls to Hibernate API are marked as unresolved (red). How could I get IntelliJ being able to resolve them ? Is there a way to use Maven when I click on Build Project ? (ctrl+F9) Also, I am confused with the concept of facets within IntelliJ. Do I need them, let's say JPA facets to enable Persistence assistant etc... or there's an option to let Maven take care about ?

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  • How to survive if you can only do things your way as a programmer?

    - by niceguyjava
    I hate hibernate, I hate spring and I am the kind of programmer who likes to do things his way. I hate micro-management and other people making decisions for me about what framework I should use, what patterns I should apply (hate patterns too) and what architecture I should design. I consider myself a successful programmer and have a descent financial situation due to my performance in past jobs, but I just can't take the standard Java jobs out there. I really love to design things from scratch and hate when I have to maintain other people's bad code, design and architecture, which is the majority you find out there for sure. Does anybody relate to that? What do you guys recommend me? Open up my on company, do consulting, or just keep looking hard until I find a job that suits my preferences, as hard as this may look like with all the hibernate and spring crap out there?

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  • Hibernation is still missing from menu in 13.10 after enabling via polkit. How to enable?

    - by LiveWireBT
    I know that since 12.04, we need to add a policykit rule to enable hibernation (see question How to enable hibernation? and the Official Documentation). I can successfully bring my laptop into hibernation mode with sudo pm-hibernate or sudo s2disk, so the rule is in place and works, but the hibernation entry is still missing in the menu. I can tell from looking through the source of the indicator-session package (but not understanding the whole code) that there is still a hibernation menu entry in the code and it should be displayed when the system is capable of hibernating. Please calm down if you're enraged by this. This is very unlikely to be a conspiracy, but rather a bug/regression on a deeper level, which can happen when you move code around or replace it. Question: What needs to be done in 13.10 to properly tell indicator-session that the system can hibernate? Possible duplicate: Hibernation still not available - No activity, because saucy was in development at that time, so out of scope for AskUbuntu. Related bug report: https://bugs.launchpad.net/ubuntu/+source/indicator-session/+bug/1232814

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  • Generated queries contain schema and catalog name

    - by stacker
    I've the same problem as described here In the generated SQL Informix expects catalog:schema.table but what's actually generated is catalog.schema.table which leads to a syntax error. Setting: hibernate.default_catalog= hibernate.default_schema= had no effect. I even removed schema and catalog from the table annotation, this caused a different issues : the query looked like that ..table same for setting catalog and schema to an empty string. Versions seam 2.1.2 Hibernate Annotations 3.3.1.GA.CP01 Hibernate 3.2.4.sp1.cp08 Hibernate EntityManager 3.3.2.GAhibernate Jboss 4.3 (similar to 4.2.3)

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  • How to configure LocalSessionFactoryBean to release connections after transaction end?

    - by peter
    I am testing an application (Spring 2.5, Hibernate 3.5.0 Beta, Atomikos 3.6.2, and Postgreql 8.4.2) with the configuration for the DAO listed below. The problem that I see is that the pool of 10 connections with the dataSource gets exhausted after the 10's transaction. I know 'hibernate.connection.release_mode' has no effect unless the session is obtained with openSession rather then using a contextual session. I am wandering if anyone has found a way to configure the LocalSessionFactoryBean to release connections after any transaction. Thank you Peter <bean id="dataSource" class="com.atomikos.jdbc.AtomikosDataSourceBean" init-method="init" destroy-method="close"> <property name="uniqueResourceName"><value>XADBMS</value></property> <property name="xaDataSourceClassName"> <value>org.postgresql.xa.PGXADataSource</value> </property> <property name="xaProperties"> <props> <prop key="databaseName">${jdbc.name}</prop> <prop key="serverName">${jdbc.server}</prop> <prop key="portNumber">${jdbc.port}</prop> <prop key="user">${jdbc.username}</prop> <prop key="password">${jdbc.password}</prop> </props> </property> <property name="poolSize"><value>10</value></property> </bean> <bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean"> <property name="dataSource"> <ref bean="dataSource" /> </property> <property name="mappingResources"> <list> <value>Abc.hbm.xml</value> </list> </property> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">org.hibernate.dialect.PostgreSQLDialect</prop> <prop key="hibernate.show_sql">on</prop> <prop key="hibernate.format_sql">true</prop> <prop key="hibernate.connection.isolation">3</prop> <prop key="hibernate.current_session_context_class">jta</prop> <prop key="hibernate.transaction.factory_class">org.hibernate.transaction.JTATransactionFactory</prop> <prop key="hibernate.transaction.manager_lookup_class">com.atomikos.icatch.jta.hibernate3.TransactionManagerLookup</prop> <prop key="hibernate.connection.release_mode">auto</prop> <prop key="hibernate.transaction.auto_close_session">true</prop> </props> </property> </bean> <!-- Transaction definition here --> <bean id="userTransactionService" class="com.atomikos.icatch.config.UserTransactionServiceImp" init-method="init" destroy-method="shutdownForce"> <constructor-arg> <props> <prop key="com.atomikos.icatch.service"> com.atomikos.icatch.standalone.UserTransactionServiceFactory </prop> </props> </constructor-arg> </bean> <!-- Construct Atomikos UserTransactionManager, needed to configure Spring --> <bean id="AtomikosTransactionManager" class="com.atomikos.icatch.jta.UserTransactionManager" init-method="init" destroy-method="close" depends-on="userTransactionService"> <property name="forceShutdown" value="false" /> </bean> <!-- Also use Atomikos UserTransactionImp, needed to configure Spring --> <bean id="AtomikosUserTransaction" class="com.atomikos.icatch.jta.UserTransactionImp" depends-on="userTransactionService"> <property name="transactionTimeout" value="300" /> </bean> <!-- Configure the Spring framework to use JTA transactions from Atomikos --> <bean id="txManager" class="org.springframework.transaction.jta.JtaTransactionManager" depends-on="userTransactionService"> <property name="transactionManager" ref="AtomikosTransactionManager" /> <property name="userTransaction" ref="AtomikosUserTransaction" /> </bean> <!-- the transactional advice (what 'happens'; see the <aop:advisor/> bean below) --> <tx:advice id="txAdvice" transaction-manager="txManager"> <tx:attributes> <!-- all methods starting with 'get' are read-only --> <tx:method name="get*" read-only="true" propagation="REQUIRED"/> <!-- other methods use the default transaction settings (see below) --> <tx:method name="*" propagation="REQUIRED"/> </tx:attributes> </tx:advice> <aop:config> <aop:advisor pointcut="execution(* *.*.AbcDao.*(..))" advice-ref="txAdvice"/> </aop:config> <!-- DAO objects --> <bean id="abcDao" class="test.dao.impl.HibernateAbcDao" scope="singleton"> <property name="sessionFactory" ref="sessionFactory"/> </bean>

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  • How to use JTA support in Tomcat 6 for Hibernate ?

    - by EugeneP
    They recommend using JTA transaction support in JEE environment. But how to configure JTA in Tomcat6 so that Hibernate Session could use it ? Starting with version 3.0.1, Hibernate added the SessionFactory.getCurrentSession() method. Initially, this assumed usage of JTA transactions, where the JTA transaction defined both the scope and context of a current session. Given the maturity of the numerous stand-alone JTA TransactionManager implementations, most, if not all, applications should be using JTA transaction management, whether or not they are deployed into a J2EE container. Based on that, the JTA-based contextual sessions are all you need to use.

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  • "SELECT ... FOR UPDATE" not working for Hibernate and MySQL

    - by Andres Rodriguez
    Hi, We have a system in which we must use pessimistic locking in one entity. We are using hibernate, so we use LockMode.UPGRADE. However, it does not lock. The tables are InnoDB We have checked that locking works correctly in the database (5.0.32), so this bug http://bugs.mysql.com/bug.php?id=18184 seems to be no problem. We have checked that datasource includes the autoCommit = false parameter. We have checked that the SQL hibernate (version 3.2) generates includes the " FOR UPDATE". Thanks,

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  • How to user Hibernate @Valid constraint with Spring 3.x?

    - by Burak Dede
    I am working on simple form to validate fields like this one. public class Contact { @NotNull @Max(64) @Size(max=64) private String name; @NotNull @Email @Size(min=4) private String mail; @NotNull @Size(max=300) private String text; } I provide getter and setters hibernate dependencies on my classpath also.But i still do not get the how to validate simple form there is actually not so much documentation for spring hibernate combination. @RequestMapping(value = "/contact", method = RequestMethod.POST) public String add(@Valid Contact contact, BindingResult result) { .... } Could you explain it or give some tutorial , except original spring 3.x documentation

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  • Hibernate: How do I link a subclass to its superclass?

    - by Markus
    Hey there! I'm having a little problem setting up my webshop project. Thing is, I have a User() superclass and two subclasses, PrivateUser and BusinessUser. Now, I'm not quite sure how to get my head around storing this relationship via hibernate. For the purpose of this question, the User() class contains only one field: String address; the PrivateUser contains: String firstName; and the BusinessUser contains: String CompanyName; Each field has its getter and setter. As is right now, I would only store and be able to get firstName and companyName. When I fetch a user from my DB using Hibernate I would get a PrivateUser/BusinessUser with a null address. Bottom line is, could someone point me towards a useful tutorial or better yet show a similar example code? Thanks!

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  • How do I share a Hibernate SessionFactory across web applications?

    - by Jer
    I have two web applications that are running on a single Tomcat server and are connected to the same database with Hibernate. I am concerned that having two SessionFactory instances running around might cause some issues. Also, since both web applications share much of the same application logic, I thought it would be a good idea to centralize as much as I could. And since I use Spring for DI and Hibernate configuration it would make sense to have a single ApplicationContext as well. How would I go about doing something like this? Do I need to deploy a headless WAR that creates an ApplicationContext and thus a SessionFactory and allow each application access to it? Is this even a good idea?

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  • How to detect open database connection with Hibernate / JPA?

    - by John K
    I am learning JPA w/Hibernate using a Java SE 6 project. I'd simply like to be able to detect if the connection between Hibernate and my database (MS SQL Server) is open. For example, I'd like to be able to detect this, log it, and try reconnecting again in 60 seconds. This is what I thought would work but isOpen() doesn't appear to be what I want (always is true): EntityManagerFactory emf = Persistence.createEntityManagerFactory("rcc", props); if (emf != null && emf.isOpen()) { EntityManager em = emf.createEntityManager(); if (em == null || !emf.isOpen()) // error connecting to database else ... This seems to me to be a simple problem, but I cannot find an answer!

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  • Hibernate constraint ConstraintViolationException. Is there an easy way to ignore duplicate entries?

    - by vincent
    Basically I've got the below schema and I'm inserting records if they don't exists. However when it comes to inserting a duplicate it throws and error as I would expect. My question is whether there is an easy way to make Hibernate to just ignore inserts which would in effect insert duplicates? CREATE TABLE IF NOT EXISTS `method` ( `id` bigint(20) NOT NULL AUTO_INCREMENT, `name` varchar(10) DEFAULT NULL, PRIMARY KEY (`id`), UNIQUE KEY `name` (`name`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=2 ; SEVERE: Duplicate entry 'GET' for key 'name' Exception in thread "pool-11-thread-4" org.hibernate.exception.ConstraintViolationException: could not insert:

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  • Combine Hibernate class with @Bindable for SwingBuilder without Griffon?

    - by Misha Koshelev
    Dear All: I have implemented a back-end for my application in Groovy/Gradle, and am now trying to implement a GUI. I am using Hibernate for my data storage (with HSQLDB) per http://groovy.codehaus.org/Using+Hibernate+with+Groovy (with Jasypt for encryption) and it is working quite well. I was wondering if there are any good tips for using @Bindable with, e.g., an @Entity class such as @Entity class Book { @Id @GeneratedValue(strategy = GenerationType.AUTO) public Long id @OneToMany(cascade=CascadeType.ALL) public Set<Author> authors public String title String toString() { "$title by ${authors.name.join(', ')}" } } or if I am: (i) asking for Griffon (ii) completely on the wrong track? Thank you! Misha

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  • Different cache concurrent strategies for root entity and its collection (Hibernate with EHCache)?

    - by grigory
    Given example from Hibernate docs and modifying it so that root level entity (Customer) is read-only while one of its collections (tickets) is read-write: @Entity @Cache(usage = CacheConcurrencyStrategy.READ_ONLY) public class Customer { ... @OneToMany(...) @Cache(usage = CacheConcurrencyStrategy.READ_WRITE) public SortedSet<Ticket> getTickets() { return tickets; } ... } Would collection of tickets get refreshed when accessing customer from cache?

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  • Is there a way to combine streaming data retrieval with hibernate?

    - by Steve B.
    For the purposes of handling very large collections (and by very large I just mean "likely to throw OutOfMemory exception"), it seems problematic to use Hibernate because normally collection retrieval is done in a block, i.e. List values=session.createQuery("from X").list(), where you monolithically grab all N-million values and then process them. What I'd prefer to do is to retrieve the values as an iterator so that I grab 1000 or so (or whatever's a reasonable page size) at a time. Apart from writing my own iteration (which seems like it's likely to be re-inventing the wheel) is there a hibernate-native way to handle this?

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