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  • Hibernate Criteria query on association

    - by DD
    Hi There, How would I go about executing the following Hibernate query using the criteria API. I have an object Parent with List children. I would like to search through all parents and find which parents contain a specified child. i.e. List findParent(Child child); Thanks.

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  • Why is an oracle sequence named hibernate_sequence being created with JPA using Hibernate with the O

    - by JavaRocky
    All my entities use this type of @Id @Id @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "MYENTITY_SEQ") @SequenceGenerator(name = "MYENTITY_SEQ", sequenceName = "MYENTITY_SEQ") @Column(name = "MYENTITY", nullable = false) private Long id; Or @Id @Column(name = "MYENTITY") I find that an oracle sequence named hibernate_sequence is always created. Why is this so? And how can i avoid this? I am using JPA1 with Hibernate 3 and the Oracle 10g dialect.

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  • Maven archetype for basic spring hibernate struts2 application

    - by Shekhar
    Hello I am looking for a basic maven archetype which can help me create a spring hibernate struts2 application. I have tried using appfuse but it sucks. It took more than half an hour to download n number of dependencies and the project it created was having errors also. if you know anyother maven archetype please tell me. Thanks Shekhar

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  • Working with Hibernate Queries

    - by jschoen
    I am new to hibernate queries, and trying to get a grasp on how everything works. I am using Hibernate 3 with Netbeans 6.5. I have a basic project set up and have been playing around with how to do everything. I started with essentially a search query. Where the user can enter values into one or more fields. The table would be Person with the columns first_name, middle_name, last_name for the sake of the example. The first way I found was to have a method that took firstName, middleName, and lastName as parameters: Session session = HibernateUtil.getSessionFactory().getCurrentSession(); Transaction tx = session.beginTransaction(); String query = "from Person where (first_name = :firstName or :firstName is null) "+ "and (middle_name = :middleName or :middleName is null) " "and (last_name = :lastname or :lastName is null)"; Query q = session.createQuery(query); q.setString("firstName", firstName); q.setString("middleName", middleName); q.setString("lastName", lastName); List<Person> results = (List<Person>) q.list(); This did not sit well with me, since it seemed like I should not have to write that much, and well, that I was doing it wrong. So I kept digging and found another way: Session session = HibernateUtil.getSessionFactory().getCurrentSession(); Transaction tx = session.beginTransaction(); Criteria crit = session.createCriteria(Person.class); if (firstName != null) { crit.add(Expression.ge("firstName", firstName); } if (middleName != null) { crit.add(Expression.ge("middleName", middleName); } if (lastName != null) { crit.add(Expression.ge("lastName", lastName); } List<Person> results = (List<Person>) crit.list(); So what I am trying to figure out is which way is the preferred way for this type of query? Criteria or Query? Why? I am guessing that Criteria is the preferred way and you should only use Query when you need to write it by hand for performance type reasons. Am I close?

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  • How to create markers on a google local search api?

    - by cheesebunz
    As the question says, i do not want to use it from the API, and instead combine it on my code, but i can't seem to implement it with the code i have now. the markers do not come out and the search completely disappears if i try implementing with the code. This is a section of my codings : http://www.mediafire.com/?0minqxgwzmx

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  • Hibernate criteria DB2 composite keys in IN clause

    - by nkr1pt
    Hibernate criteria, using DB2 dialect, generates the following sql with composite keys in the IN clause, but DB2 answers that the query is incorrect: select * from tableA where (x, y) IN ( ( 'x1', y1) ) but, DB2 throws this: SQL0104N An unexpected token "," was found following ", y) in ( ('x1'". Expected tokens may include: "+". SQLSTATE=42601

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  • Hibernate - how to map an EnumSet

    - by al nik
    Hi all, I've a Color Enum public enum color { GREEN, WHITE, RED } and I have MyEntity that contains it. public class MyEntity { private Set<Color> colors; ... Do you know how to map this in the relative Hibernate hbm.xml? Do I need a UserType or there's an easiest way? Thanks

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  • Why bind hibernate SessionFactory to a JNDI resource?

    - by jschoen
    In my current adventure of learning hibernate and setting it up to use an appserver's connection pool, most examples and resources out there point you in the direction of binding the SessionFactory to a JNDI resource in your appserver in the process. I wondering what the benefit of this is? Since the you can access a the connection pool with out doing this.

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  • Including hibernate jar dependencies in ant build

    - by Patrick
    Hi, I'm trying to compile a runnable jar-file for a project that makes use of hibernate. I'm trying to construct an ant build.xml file to streamline my build process, but I'm having troubles with the inclusion of the hibernate3.jar inside the final jar-file. If I run the ant script I manage to include all my library jars, and they are put in the final jar-file's root. When I run the jar-file I get a java.lang.NoClassDefFoundError: org/hibernate/Session error. If I make use of the built-in export to jar in Eclipse, it works only if I choose "extract required libraries into jar". But that bloats the jar, and includes too much of my project (i.e. unit tests). Below is my generated manifest: Manifest-Version: 1.0 Main-Class: main.ServerImpl Class-Path: ./ antlr-2.7.6.jar commons-collections-3.1.jar dom4j-1.6.1.jar hibernate3.jar javassist-3.9.0.GA.jar jta-1.1.jar slf4j-api-1.5.11.jar slf4j-simple-1.5.11.jar mysql-connector-java-5.1.12-bin.jar rmiio-2.0.2.jar commons-logging-1.1.1.jar And the part of the build.xml looks like this: <target name="dist" depends="compile" description="Generates the Distribution Jar(s)"> <mkdir dir="${dist.dir}" /> <jar destfile="${dist.dir}/${dist.file.name}.jar" basedir="${build.prod.dir}" filesetmanifest="mergewithoutmain"> <manifest> <attribute name="Main-Class" value="${main.class}" /> <attribute name="Class-Path" value="./ ${manifest.classpath} " /> <attribute name="Implementation-Title" value="${app.name}" /> <attribute name="Implementation-Version" value="${app.version}" /> <attribute name="Implementation-Vendor" value="${app.vendor}" /> </manifest> <zipfileset refid="hibernatefiles" /> <zipfileset refid="slf4jfiles" /> <zipfileset refid="mysqlfiles" /> <zipfileset refid="commonsloggingfiles" /> <zipfileset refid="rmiiofiles" /> </jar> </target> The refids' for the zipfilesets point to the directories in a library directory lib in the root of the project. The manifest.classpath-variable takes the classpath of all those library jar-files, and flattens them with pathconvert and mapper. I've also tried to set the manifest classpath to ".", "./" and only the library jar, but to no difference at all. I'm hoping there's a simple remedy to my problems...

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  • Hibernate CRUD à la Ruby on Rails' Scaffolding

    - by schonarth
    Guys, Do you know of any tool that would do like Ruby on Rails' Scaffolding (create simple CRUD pages for any particular class to allow quickly populating a database with dummy data), only which used Java classes with Hibernate for database access, and JSP/JSF for the pages? It is a drag when you are programming one part of an application, but need data that can only be added with another part that is not ready yet, or very cumbersomely by directly inserting it into the DB.

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  • How to properly test Hibernate length restriction?

    - by Cesar
    I have a POJO mapped with Hibernate for persistence. In my mapping I specify the following: <class name="ExpertiseArea"> <id name="id" type="string"> <generator class="assigned" /> </id> <version name="version" column="VERSION" unsaved-value="null" /> <property name="name" type="string" unique="true" not-null="true" length="100" /> ... </class> And I want to test that if I set a name longer than 100 characters, the change won't be persisted. I have a DAO where I save the entity with the following code: public T makePersistent(T entity){ transaction = getSession().beginTransaction(); transaction.begin(); try{ getSession().saveOrUpdate(entity); transaction.commit(); }catch(HibernateException e){ logger.debug(e.getMessage()); transaction.rollback(); } return entity; } Actually the code above is from a GenericDAO which all my DAOs inherit from. Then I created the following test: public void testNameLengthMustBe100orLess(){ ExpertiseArea ea = new ExpertiseArea( "1234567890" + "1234567890" + "1234567890" + "1234567890" + "1234567890" + "1234567890" + "1234567890" + "1234567890" + "1234567890" + "1234567890"); assertTrue("Name should be 100 characters long", ea.getName().length() == 100); ead.makePersistent(ea); List<ExpertiseArea> result = ead.findAll(); assertEquals("Size must be 1", result.size(),1); ea.setName(ea.getName()+"1234567890"); ead.makePersistent(ea); ExpertiseArea retrieved = ead.findById(ea.getId(), false); assertTrue("Both objects should be equal", retrieved.equals(ea)); assertTrue("Name should be 100 characters long", (retrieved.getName().length() == 100)); } The object is persisted ok. Then I set a name longer than 100 characters and try to save the changes, which fails: 14:12:14,608 INFO StringType:162 - could not bind value '12345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890' to parameter: 2; data exception: string data, right truncation 14:12:14,611 WARN JDBCExceptionReporter:100 - SQL Error: -3401, SQLState: 22001 14:12:14,611 ERROR JDBCExceptionReporter:101 - data exception: string data, right truncation 14:12:14,614 ERROR AbstractFlushingEventListener:324 - Could not synchronize database state with session org.hibernate.exception.DataException: could not update: [com.exp.model.ExpertiseArea#33BA7E09-3A79-4C9D-888B-4263314076AF] //Stack trace 14:12:14,615 DEBUG GenericDAO:87 - could not update: [com.exp.model.ExpertiseArea#33BA7E09-3A79-4C9D-888B-4263314076AF] 14:12:14,616 DEBUG JDBCTransaction:186 - rollback 14:12:14,616 DEBUG JDBCTransaction:197 - rolled back JDBC Connection That's expected behavior. However when I retrieve the persisted object to check if its name is still 100 characters long, the test fails. The way I see it, the retrieved object should have a name that is 100 characters long, given that the attempted update failed. The last assertion fails because the name is 110 characters long now, as if the ea instance was indeed updated. What am I doing wrong here?

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  • Are Hibernate named HQL queries (in annotations) optimised?

    - by Graham Lea
    A new colleague has just suggested using named HQL queries in Hibernate with annotations (i.e. @NamedQuery) instead of embedding HQL in our XxxxRepository classes. What I'd like to know is whether using the annotation provides any advantage except for centralising quueries? In particular, is there some performances gain, for instance because the query is only parsed once when the class is loaded rather than every time the Repository method is executed?

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  • hibernate - lazy init joined component

    - by robinmag
    I used the mapping solution from this question to have a joined component. But it make hibernate trigger join query to obtain the component event i use fetch="select" in <join> Please tell me how can i make the joined component lazy init. Thank you

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  • Hibernate : Disabling contextual LOB creation as createClob() method threw error

    - by Giri Byaks
    Hi, I am using using hibernate 3.5.6 with Oracle 10g. I am seeing the below exception during initialization but the application itself is working fine. What is the cause for this exception? and how it can be corrected? Exception Disabling contextual LOB creation as createClob() method threw error : java.lang.reflect.InvocationTargetException Info Oracle version: Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 JDBC driver: Oracle JDBC driver, version: 11.1.0.7.0 Thanks, Girish

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  • Issue in Adding data into database using hibernate

    - by sarah
    Hi , I am getting the following exception "org.hibernate.HibernateException: The database returned no natively generated identity value "while adding data into database i am using the following code.Please let me know what is wrong Sesion session=HibernateUtil.getSession(); Transaction tx = session.beginTransaction(); session.save(user); logger.info("Successfully data insert in database"); tx.commit(); isSaved=true; Thankx

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  • Getting fewer columns with hibernate

    - by Gandalf StormCrow
    I have a table with 11 columns, but I need to get only 2 of them in my application, I'm using spring/hibernate/DAO combination. For now I have a domain class which includes all 11 fields, and mapping file which maps all 11 columns in table. How do I use get just 2 of them not all?

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  • Hibernate can't load Custom SQL collection

    - by Geln Yang
    Hi, There is a table Item like, code,name 01,parent1 02,parent2 0101,child11 0102,child12 0201,child21 0202,child22 Create a java object and hbm xml to map the table.The Item.parent is a Item whose code is equal to the first two characters of its code : class Item{ String code; String name; Item parent; List<Item> children; .... setter/getter.... } <hibernate-mapping> <class name="Item" table="Item"> <id name="code" length="4" type="string"> <generator class="assigned" /> </id> <property name="name" column="name" length="50" not-null="true" /> <many-to-one name="parent" class="Item" not-found="ignore"> <formula> <![CDATA[ (select i.code,r.name from Item i where (case length(code) when 4 then i.code=SUBSTRING(code,1,2) else false end)) ]]> </formula> </many-to-one> <bag name="children"></bag> </class> </hibernate-mapping> I try to use formula to define the many-to-one relationship,but it doesn't work!Is there something wrong?Or is there other method? Thanks! ps,I use mysql database. add 2010/05/23 Pascal's answer is right,but the "false" value must be replaced with other expression,like "1=2".Because the "false" value would be considered to be a column of the table. select i.code from Item i where ( case length(code) when 4 then i.code=SUBSTRING(code,1,2) else 1=2 end) And I have another question about the children "bag" mapping.There isn't formula configuration option for "bag",but we can use "loader" to load a sql-query.I configure the "bag" as following.But it get a list whose size is 0.What's wrong with it? <class> ... ... <bag name="children"> <key /> <one-to-many class="Item"></one-to-many> <loader query-ref="getChildren"></loader> </bag> </class> <sql-query name="getChildren"> <load-collection alias="r" role="Item.children" /> <![CDATA[(select {r.*} from Item r join Item o where o.code=:code and ( case length(o.code) when 2 then (length(r.code)=4 and SUBSTRING(r.code,1,2)=o.code) else 1=2 end ))]]> </sql-query>

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  • Hibernate persist order

    - by user213855
    Hi there! I have a question about how Hibernate persists entity relations. Let's say I have an entity A that has a relation with entity B and another one with entity C. I create an A instance and populate it with new instances of B and C. When I persist A I need C to be persisted previous to B. Is there any way of doing this? Thanks a lot.

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