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  • changing order of items in tkinter listbox

    - by user1104854
    Is there an easier way to change the order of items in a tkinter listbox than deleting the values for specific key, then re-entering new info? For example, I want to be able to re-arrange items in a listbox. If I want to swap the position of two, this is what I've done. It works, but I just want to see if there's a quicker way to do this. def moveup(self,selection): value1 = int(selection[0]) - 1 #value to be moved down one position value2 = selection #value to be moved up one position nameAbove = self.fileListSorted.get(value1) #name to be moved down nameBelow = self.fileListSorted.get(value2) #name to be moved up self.fileListSorted.delete(value1,value1) self.fileListSorted.insert(value1,nameBelow) self.fileListSorted.delete(value2,value2) self.fileListSorted.insert(value2,nameAbove)

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  • Why isn't my IO executed in order?

    - by HaskellElephant
    Hi, I'm having some fun learning about the haskell IO. However in my recent exploration of it I have encountered some problems with IO not executing in order, even inside a do construct. In the following code I am just keeping track of what cards are left, where the card is a tuple of chars (one for suit and one for value) then the user is continously asked for wich cards have been played. I want the putStr to be executed between each input, and not at the very end like it is now. module Main where main = doLoop cards doLoop xs = do putStr $ show xs s <- getChar n <- getChar doLoop $ remove (s,n) xs suits = "SCDH" vals = "A23456789JQK" cards = [(s,n) | s <- suits, n <- vals] type Card = (Char,Char) remove :: Card -> [Card] -> [Card] remove card xs = filter (/= card) xs

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  • JS assignment order of properties in objects

    - by devdev
    Just had a quick question about why a certain order of assignment works and another doesn't. I wanted to create a simple "inherit" / "copy" function (just for testing it) that copies properties from one object to another: var cat = { tail:"yes", hairy:"yes, hairy" }; var dog = { sick:"extremely ill"}; function inherit(obj1, obj2) { for (var p in obj1) { obj2[p] = obj1[p]; // this works, but "obj1[p] = obj2[p];" doesn't. Why?? } } inherit(cat, dog); console.log(dog.tail);

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  • Order objects for Northwind Access database

    - by Artem Shnayder
    I need to build two objects: an OrderList and an Order. Using those two objects, I have to populate a DataGridView with a history of the orders. However, I am instructed not to use binding sources for the connection or other drag and drop controls. Unfortunately, from Google it seems like those are the most popular options for this type of problem. Can anyone point me in the right direction? I don't have much experience with C#. Thanks.

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  • Rails ActiveRecord - How to set association save order

    - by Altonymous
    I have a weird relationship that needs to be maintained for legacy processes. I'm trying to figure out how to create the relationship given the new model association. New Relationship Setup Machine has_many MachineReadings has_many Disks has_many DiskReadings Old Relationship Setup Machine has_many MachineReadings has_many DiskReadings has_many Disks The problem is data will come in on the Machine model as nested attributes using the new relationship setup. I need to update the machine_reading_id in the DiskReading model so the old association can continue to be used. I tried doing this via an after_save hook that would traverse back up to the machine and then down to the readings to get the machine_reading.id so I could populate the DiskReading model. However, the associations aren't being saved in the order I would expect. They are saving the Disks & DiskReadings before saving the MachineReadings. So when I go after the machine_reading.id it hasn't been written and thus I am unable to get access to it. For example: #machine_disk_reading.rb after_save :build_old_relationship def build_old_relationship self.machine_reading_id = self.disk.machine.readings.find_by_date_time(self.date_time).id end

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  • Order of declaration in an anonymous pl/sql block

    - by RenderIn
    I have an anonymous pl/sql block with a procedure declared inside of it as well as a cursor. If I declare the procedure before the cursor it fails. Is there a requirement that cursors be declared prior to procedures? What other rules are there for order of declaration in a pl/sql block? This works: DECLARE cursor cur is select 1 from dual; procedure foo as begin null; end foo; BEGIN null; END; This fails with error PLS-00103: Encountered the symbol "CURSOR" when expecting one of the following: begin function package pragma procedure form DECLARE procedure foo as begin null; end foo; cursor cur is select 1 from dual; BEGIN null; END;

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  • what are most important things that i must know in order to jump into silverlight development

    - by Poni
    I have vast programming knowledge; C++/C#/ActionScript/ASM/PHP..... so learning the language of SilverLight itself isn't of an issue. To keep long story short, when asking this question I'm asking it as a developer who's coming from Flash world - great graphics/sounds/media support, fully cross-platform, ability to combine several SWFs within a "movie" (which also implies code reusability). A Flash developer have pretty much freedom. What are most important things that i must know in order to jump into silverlight development? Did you already make the move to SilverLight from Flash yourself? Are you a "guru" at both? Great, let's hear what you have to say - developer to developer! =)

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  • Unexpected behaviour of Order by clause(SQL SERVER 2005)

    - by Newbie
    I have a table which looks like Col1 col2 col3 col4 col5 1 5 1 4 6 1 4 0 3 7 0 1 5 6 3 1 8 2 1 5 4 3 2 1 4 The script is declare @t table(col1 int, col2 int, col3 int,col4 int,col5 int) insert into @t select 1,5,1,4,6 union all select 1,4,0,3,7 union all select 0,1,5,6,3 union all select 1,8,2,1,5 union all select 4,3,2,1,4 If I do a sorting (ascending), the output is Col1 col2 col3 col4 col5 0 1 5 6 3 1 4 0 3 7 1 5 1 4 6 1 8 2 1 5 4 3 2 1 4 The query is Select * from @t order by col1,col2,col3,col4,col5 But as can be seen that the sorting output is wrong (col2 to col5). Why so and how to overcome this? Thanks in advance

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  • C# logic order and compiler behavior

    - by Terrapin
    In C#, (and feel free to answer for other languages), what order does the runtime evaluate a logic statement? Example: DataTable myDt = new DataTable(); if (myDt != null && myDt.Rows.Count > 0) { //do some stuff with myDt } Which statement does the runtime evaluate first - myDt != null or: myDt.Rows.Count > 0 ? Is there a time when the compiler would ever evaluate the statement backwards? Perhaps when an "OR" operator is involved?

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  • MySQL: Order by time (MM:SS)?

    - by Shpigford
    I'm currently storing various metadata about videos and one of those bits of data is the length of a video. So if a video is 10 minutes 35 seconds long, it's saved as "10:35" in the database. But what I'd like to do is retrieve a listing of videos by length (longest first, shortest last). The problem I'm having is that if a video is "2:56", it's coming up as longest because the number 2 is more than the number 1 in. So, how can I order data based on that length field so that "10:35" is recognized as being longer than "2:56" (as per my example)?

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  • IB z-order on simulator 6.0

    - by Stanley
    Consider the above's IB objects listing. Siblings further down the list should be on top of the siblings listed further up when rendered on the screen. Under Xcode 4.5.2, everything is ok if iphone simulator 5.1 is used. But for simulator 6.0 the map just covers everything. The same if using actual devices (phones) for testing. Hope that somebody knowledgeable could help. Please also add comments if you do not find such a problem on simulator 6.0. Because chances are the problem is related to how my project is setup. Update : Have setup a test project with the iOS 6 map view. There seems to be no problem with the z-order. So the problem should relate to my code.

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  • select similar value from MySQL and order the result

    - by mathew
    how do I order this result?? $range = 5; // you'll be selecting around this range. $min = $rank - $range; $max = $rank + $range; $limit = 10; // max number of results you want. $result = mysql_query("select * from table where rank between $min and $max limit $limit"); while($row = mysql_fetch_array($result)) { echo $row['name']."&nbsp;-&nbsp;".$row['rank']."<br>"; }

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  • How to order my objects in a C++ class correctly

    - by Julen
    Hello, I have been coding regurlarly in C++ in the past months. I am getting used to it step by step... but there are things that confuse me about formatting. I know there is a lot of legacy from C that I supousee mixes with C++. This time I have doubts about how to order properly my members and functions within in a class. Also considering their access modifiers. How is the convention in this? Until know I am doing everything "public" and writing first constructor of class, then destructor, next members and finally functions. It this correct? What happens when introducing "private" and "protected" access modifiers or "virtual" functions? From the documents I have look in the Internet there is different ways of doing things. But my questions aims to get the knowledge from a community that develops in C++ that I want to blend into. ;-) Thanks a lot!!!

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  • ASP.NET MVC 2 model properties binding order

    - by bniwredyc
    Is there a way to change order in which the default binder binds property values of model? For example I have model class A: class A { public string A1 {get; set;} public string A2 {get; set;} } and action DoSomethig: public ActionResult DoSomething(A model) { ... } I want that A2 property has been bound before the A1 property. Is it possible? Or I need to write custom binder?

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  • Rspec: "array.should == another_array" but without concern for order

    - by nicholaides
    I often want to compare arrays and make sure that they contain the same elements, in any order. IS there a consise way to do this in RSpec? Here are methods that aren't acceptable: #to_set For example: array.to_set.should == another_array.to_set This fails when the arrays contain duplicate items. #sort For example: array.sort.should == another_array.sort This fails when the arrays elements don't implement #<=> #size and #to_set For example: array.to_set.should == another_array.to_set array.size.should == another_array.size This would work, but there's got to be a better way.

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  • How to save an order (permutation) in an sql db

    - by Bendlas
    I have a tree structure in an sql table like so: CREATE TABLE containers ( container_id serial NOT NULL PRIMARY KEY, parent integer REFERENCES containers (container_id)) Now i want to define an ordering between nodes with the same parent. I Have thought of adding a node_index column, to ORDER BY, but that seem suboptimal, since that involves modifying the index of a lot of nodes when modifying the stucture. That could include adding, removing, reordering or moving nodes from some subtree to another. Is there a sql datatype for an ordered sequence, or an efficient way to emulate one? Doesn't need to be fully standard sql, I just need a solution for mssql and hopefully postgresql EDIT To make it clear, the ordering is arbitrary. Actually, the user will be able to drag'n'drop tree nodes in the GUI

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  • Getting a java collection of objects in Alphabetical order

    - by MichaelMcCabe
    I have a question that I dont really know where to start. So I thought i'd ask it here. Basically, I have a drop down with names in it. I want these names to be in alphabetical order. Populating the drop down happens as follows; I query a database and pull down an Id and Name, make a object called "UserList", and set the name and id variables with what I get back. I then add this object to an ArrayList. I do this over and over. I then convert this collection to an array, and pass it to my JSP page using session.setAttribute("userList", UserList); I then populate the drop down as below. <c:forEach items="${usersCompanysList}" var="c" > There probably is a simple answer but how to I sort these names?

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  • Oracle date / order by question

    - by user561793
    I want to select a date from oracle table formatted like select (to_char(req_date,'MM/YYYY')) but I also want to order the result set on this date format. I want them to be ordered like dates not strings. Like this 09/2009 10/2009 11/2009 12/2009 01/2010 02/2010 03/2010 04/2010 05/2010 06/2010 07/2010 08/2010 09/2010 10/2010 11/2010 12/2010 Not like 01/2010 02/2010 03/2010 04/2010 05/2010 06/2010 07/2010 08/2010 09/2009 09/2010 10/2009 10/2010 11/2009 11/2010 12/2009 12/2010 Any way to do this in sql? full sql is select (to_char(req_date,'MM/YYYY')) as monthYear,count(req_id) as count from REQUISITION_CURRENT t group by to_char(req_date,'MM/YYYY') Thanks

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  • question about order in class

    - by helloWorld
    hello, can somebody please explain the order of private and public is important or no? for example: class Account{ public: Account(string firstName, string lastName, int id); void printAccount(); private: string strLastName; string strFirstName; }; will be the same as: class Account{ private: string strLastName; string strFirstName; public: Account(string firstName, string lastName, int id); void printAccount(); };

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  • SQL SERVER – SSMS Automatically Generates TOP (100) PERCENT in Query Designer

    - by pinaldave
    Earlier this week, I was surfing various SQL forums to see what kind of help developer need in the SQL Server world. One of the question indeed caught my attention. I am here regenerating complete question as well scenario to illustrate the point in a precise manner. Additionally, I have added added second part of the question to give completeness. Question: I am trying to create a view in Query Designer (not in the New Query Window). Every time I am trying to create a view it always adds  TOP (100) PERCENT automatically on the T-SQL script. No matter what I do, it always automatically adds the TOP (100) PERCENT to the script. I have attempted to copy paste from notepad, build a query and a few other things – there is no success. I am really not sure what I am doing wrong with Query Designer. Here is my query script: (I use AdventureWorks as a sample database) SELECT Person.Address.AddressID FROM Person.Address INNER JOIN Person.AddressType ON Person.Address.AddressID = Person.AddressType.AddressTypeID ORDER BY Person.Address.AddressID This script automatically replaces by following query: SELECT TOP (100) PERCENT Person.Address.AddressID FROM Person.Address INNER JOIN Person.AddressType ON Person.Address.AddressID = Person.AddressType.AddressTypeID ORDER BY Person.Address.AddressID However, when I try to do the same from New Query Window it works totally fine. However, when I attempt to create a view of the same query it gives following error. Msg 1033, Level 15, State 1, Procedure myView, Line 6 The ORDER BY clause is invalid in views, inline functions, derived tables, subqueries, and common table expressions, unless TOP, OFFSET or FOR XML is also specified. It is pretty clear to me now that the script which I have written seems to need TOP (100) PERCENT, so Query . Why do I need it? Is there any work around to this issue. I particularly find this question pretty interesting as it really touches the fundamentals of the T-SQL query writing. Please note that the query which is automatically changed is not in New Query Editor but opened from SSMS using following way. Database >> Views >> Right Click >> New View (see the image below) Answer: The answer to the above question can be very long but I will keep it simple and to the point. There are three things to discuss in above script 1) Reason for Error 2) Reason for Auto generates TOP (100) PERCENT and 3) Potential solutions to the above error. Let us quickly see them in detail. 1) Reason for Error The reason for error is already given in the error. ORDER BY is invalid in the views and a few other objects. One has to use TOP or other keywords along with it. The way semantics of the query works where optimizer only follows(honors) the ORDER BY in the same scope or the same SELECT/UPDATE/DELETE statement. There is a possibility that one can order after the scope of the view again the efforts spend to order view will be wasted. The final resultset of the query always follows the final ORDER BY or outer query’s order and due to the same reason optimizer follows the final order of the query and not of the views (as view will be used in another query for further processing e.g. in SELECT statement). Due to same reason ORDER BY is now allowed in the view. For further accuracy and clear guidance I suggest you read this blog post by Query Optimizer Team. They have explained it very clear manner the same subject. 2) Reason for Auto Generated TOP (100) PERCENT One of the most popular workaround to above error is to use TOP (100) PERCENT in the view. Now TOP (100) PERCENT allows user to use ORDER BY in the query and allows user to overcome above error which we discussed. This gives the impression to the user that they have resolved the error and successfully able to use ORDER BY in the View. Well, this is incorrect as well. The way this works is when TOP (100) PERCENT is used the result is not guaranteed as well it is ignored in our the query where the view is used. Here is the blog post on this subject: Interesting Observation – TOP 100 PERCENT and ORDER BY. Now when you create a new view in the SSMS and build a query with ORDER BY to avoid the error automatically it adds the TOP 100 PERCENT. Here is the connect item for the same issue. I am sure there will be more connect items as well but I could not find them. 3) Potential Solutions If you are reading this post from the beginning in that case, it is clear by now that ORDER BY should not be used in the View as it does not serve any purpose unless there is a specific need of it. If you are going to use TOP 100 PERCENT with ORDER BY there is absolutely no need of using ORDER BY rather avoid using it all together. Here is another blog post of mine which describes the same subject ORDER BY Does Not Work – Limitation of the Views Part 1. It is valid to use ORDER BY in a view if there is a clear business need of using TOP with any other percentage lower than 100 (for example TOP 10 PERCENT or TOP 50 PERCENT etc). In most of the cases ORDER BY is not needed in the view and it should be used in the most outer query for present result in desired order. User can remove TOP 100 PERCENT and ORDER BY from the view before using the view in any query or procedure. In the most outer query there should be ORDER BY as per the business need. I think this sums up the concept in a few words. This is a very long topic and not easy to illustrate in one single blog post. I welcome your comments and suggestions. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Server Management Studio, SQL Tips and Tricks, SQL View, T SQL, Technology

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  • Sort List C# in arbitrary order

    - by Jasper
    I have a C# List I.E. List<Food> x = new List<Food> () ; This list is populated with this class Public class Food { public string id { get; set; } public string idUser { get; set; } public string idType { get; set; } //idType could be Fruit , Meat , Vegetable , Candy public string location { get; set; } } Now i have this unsorted List<Food> list ; which has I.E. 15 elements. There are 8 Vegetable Types , 3 Fruit Types , 1 Meat Types , 1 Candy Types I would sort this so that to have a list ordered in this way : 1° : Food.idType Fruit 2° : Food.idType Vegetables 3° : Food.idType Meat 4° : Food.idType Candy 5° : Food.idType Fruit 6° : Food.idType Vegetables 7° : Food.idType Fruit //Becouse there isnt more Meat so i insert the //next one which is Candy but also this type is empty //so i start from begin : Fruit 8° : Food.idType Vegetables 9° : Food.idType Vegetables // For the same reason of 7° 10 ° Food.idType Vegetables ...... .... .... 15 : Food.idType Vegetables I cant find a rule to do this. Is there a linq or List.Sort instruction which help me to order the list in this way? Update i changed the return value of idType and now return int type instead string so 1=Vegetable , 2=Fruit , 3=Candy 4=Meat

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  • C# Wholesale Order form - textboxes in Gridviews in Repeater

    - by tnriverfish
    I'm building a wholesale order form on a website. The current plan is to... -get an ArrayList of DepartmentUnits -a DepartmentUnit has various attributes like "deptId", "description" and its own ArrayList of StoreItems -The StoreItems have attached ArrayList of various SizeOptions -The SizeOptions have an inventory count integer along with their description -Planning on putting an asp:Repeater on the page that has an asp:GridView in it -Each DepartmentUnit will have its own GridView -EachStore item will have a row in the GridView -Each SizeOption will have a TextBox in the row (approximately 10 options) -Each inventory count will be watermarked over the size option textbox The question becomes how will I then collect all this information correctly once the form has been filled out? I don't like the idea of putting all this information in an update panel and then posting back each time a GridView row or worse one of the row's textboxes changes. Any advice on putting a single save button on the page and looping through each Repeater item - and each GridViewRow - and each textbox - to get all the values entered? Better to try collecting all the items added in a single table at the bottom of the page and updating the string with jquery each time a text box is modified? Then just looping through the new table when saved? Not sure I know how to loop through that table though - updating if quantity is changed might be a bear too. If it considerably simplifies the process I could just remove the Repeater aspect and put separate GridViews on separate pages. Thanks!

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  • Django forms, inheritance and order of form fields

    - by Hannson
    I'm using Django forms in my website and would like to control the order of the fields. Here's how I define my forms: class edit_form(forms.Form): summary = forms.CharField() description = forms.CharField(widget=forms.TextArea) class create_form(edit_form): name = forms.CharField() The name is immutable and should only be listed when the entity is created. I use inheritance to add consistency and DRY principles. What happens which is not erroneous, in fact totally expected, is that the name field is listed last in the view/html but I'd like the name field to be on top of summary and description. I do realize that I could easily fix it by copying summary and description into create_form and loose the inheritance but I'd like to know if this is possible. Why? Imagine you've got 100 fields in edit_form and have to add 10 fields on the top in create_form - copying and maintaining the two forms wouldn't look so sexy then. (This is not my case, I'm just making up an example) So, how can I override this behavior? Edit: Apparently there's no proper way to do this without going through nasty hacks (fiddling with .field attribute). The .field attribute is a SortedDict (one of Django's internal datastructures) which doesn't provide any way to reorder key:value pairs. It does how-ever provide a way to insert items at a given index but that would move the items from the class members and into the constructor. This method would work, but make the code less readable. The only other way I see fit is to modify the framework itself which is less-than-optimal in most situations. In short the code would become something like this: class edit_form(forms.Form): summary = forms.CharField() description = forms.CharField(widget=forms.TextArea) class create_form(edit_form): def __init__(self,*args,**kwargs): forms.Form.__init__(self,*args,**kwargs) self.fields.insert(0,'name',forms.CharField()) That shut me up :)

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  • Strange rare out-of-order data received using Indy

    - by Jim
    We're having a bizarre problem with Indy10 where two large strings (a few hundred characters each) that we send out one after the other are appearing at the other end intertwined oddly. This happens extremely infrequently. Each string is a complete XML message terminated with a LF and in general the READ process reads an entire XML message, returning when it sees the LF. The call to actually send the message is protected by a critical section around the call to the IOHandler's writeln method and so it is not possible for two threads to send at the same time. (We're certain the critical section is implemented/working properly). This problem happens very rarely. The symptoms are odd...when we send string A followed by string B what we received at the other end (on the rare occasions where we have failure) is the trailing section of string A by itself (i.e., there's a LF at the end of it) followed by the leading section of string A and then the entire string B followed by a single LF. We've verified that the "timed out" property is not true after the partial read - we log that property after every read that returns content. Also, we know there are no embedded LF characters in the string, as we explicitly replace all non-alphanumeric characters in the string with spaces before appending the LF and sending it. We have log mechanisms inside the critical sections on both the transmission and receiving ends and so we can see this behavior at the "wire". We're completely baffled and wondering (although always the lowest possibility) whether there could be some low-level Indy issues that might cause this issue, e.g., buffers being sent in the wrong order....very hard to believe this could be the issue but we're grasping at straws. Does anyone have any bright ideas?

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  • Average of two strings in alphabetical/lexicographical order

    - by Bemmu
    Suppose you take the strings 'a' and 'z' and list all the strings that come between them in alphabetical order: ['a','b','c' ... 'x','y','z']. Take the midpoint of this list and you find 'm'. So this is kind of like taking an average of those two strings. You could extend it to strings with more than one character, for example the midpoint between 'aa' and 'zz' would be found in the middle of the list ['aa', 'ab', 'ac' ... 'zx', 'zy', 'zz']. Might there be a Python method somewhere that does this? If not, even knowing the name of the algorithm would help. I began making my own routine that simply goes through both strings and finds midpoint of the first differing letter, which seemed to work great in that 'aa' and 'az' midpoint was 'am', but then it fails on 'cat', 'doggie' midpoint which it thinks is 'c'. I tried Googling for "binary search string midpoint" etc. but without knowing the name of what I am trying to do here I had little luck.

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