Search Results

Search found 25373 results on 1015 pages for 'sort to directory'.

Page 39/1015 | < Previous Page | 35 36 37 38 39 40 41 42 43 44 45 46  | Next Page >

  • Cannot delete .Trash-503 directory, returns a $RECYCLE.BIN.trashinfo: Input/output error

    - by Parto
    I cannot delete .Trash-503 folder via GUI or terminal, it returns a $RECYCLE.BIN.trashinfo: Input/output error Not even sudo rm -r or even a simple ls works in that trash directory. Check terminal output below: subroot@subroot:~$ cd /media/xxxxx/ subroot@subroot:/media/xxxxx$ rm .Trash-503/ rm: cannot remove `.Trash-503/': Is a directory subroot@subroot:/media/xxxxx$ rm -r .Trash-503/ rm: cannot remove `.Trash-503/info/$RECYCLE.BIN.trashinfo': Input/output error rm: cannot remove `.Trash-503/info/found.000.trashinfo': Input/output error rm: cannot remove `.Trash-503/info': Directory not empty subroot@subroot:/media/xxxxx$ sudo rm -r .Trash-503/ [sudo] password for subroot: rm: cannot remove `.Trash-503/info/$RECYCLE.BIN.trashinfo': Input/output error rm: cannot remove `.Trash-503/info/found.000.trashinfo': Input/output error subroot@subroot:/media/xxxxx$ cd .Trash-503/ subroot@subroot:/media/xxxxx/.Trash-503$ ls info subroot@subroot:/media/xxxxx/.Trash-503$ cd info/ subroot@subroot:/media/xxxxx/.Trash-503/info$ ls ls: cannot access $RECYCLE.BIN.trashinfo: Input/output error ls: cannot access found.000.trashinfo: Input/output error found.000.trashinfo $RECYCLE.BIN.trashinfo subroot@subroot:/media/xxxxx/.Trash-503/info$ What's going on here and how can I delete this folder? EDIT I tried checking and repairing the partition using gparted only to get this error message: ERROR: Filesystem check failed! ERROR: 264 clusters are referenced multiple times. NTFS is inconsistent. Run chkdsk /f on Windows then reboot it TWICE! The usage of the /f parameter is very IMPORTANT! No modification was and will be made to NTFS by this software until it gets repaired. I don't have windows installed, how can I run chkdsk /f from ubuntu?

    Read the article

  • OUD as a OAM Identity Store

    - by Sylvain Duloutre
    Since 11gR2, OUD can be used natively as a OAM Identity Store. Select  "OUD: Oracle Unified Directory" as Store Type as described here. As an alternate solution, you can also configure OVD as Identity Store with OAM and then configure LDAP adapter for OVD with OUD details.Configuring Identity store for OAM is documented here. Choose "OVD: Oracle Virtual Directory" as store type and provide store details as per the document. Configuring LDAP adapter for OVD is documented here. Provide your OUD details required as per the document.

    Read the article

  • Script to recursively grep data from certain files in the directory

    - by Jude
    I am making a simple shell script which will minimize the time I spend in searching all directories under a parent directory and grep some things inside some files. Here's my script. #!/bin/sh MainDir=/var/opt/database/1227-1239/ cd "$MainDir" for dir in $(ls); do grep -i "STAGE,te_start_seq Starting" "$dir"/his_file | tail -1 >> /home/xtee/sst-logs.out if [ -f "$dir"/sysconfig.out]; then grep -A 1 "Drive Model" "$dir"/sysconfig.out | tail -1 >> /home/xtee/sst-logs.out else grep -m 1 "Physical memory size" "$dir"/node0/setupsys.out | tail -1 >> /home/xtee/sst-logs.out fi done The script is supposed to grep the string STAGE,te_start_seq Starting under the file his_file then dump it sst-logs.out which it does. My problem though is the part in the if statement. The script should check the current directory for sysconfig.out, grep drive model and dump it to sst-logs.out if it exists, otherwise, change directory to node0 then grep physical memory size from setupsys.out and dump it to sst-logs.out. My problem is, it seems the if then else statement seems not to work as it doesn`t dump any data at all but if i execute grep manually, i do have data. What is wrong with my shell script? Is there any more efficient way in doing this?

    Read the article

  • New convenient Information Center about OUD in My Oracle Support

    - by Sylvain Duloutre
    A new "Information Center" dedicated to Oracle Unified Directory is available from the Oracle Support Site. This page provides you with all the useful links and news related to the product, including technical articles, docs, licensing info and the latest patches available. To access it, log into MOS (My Oracle Support) at http://support.oracle.com,  search for 1418884.2 doc id in the search field on the front page, then click on the "Information Center : Overview Oracle Unified Directory (OUD)" link.

    Read the article

  • How to Organize Subdirectories? [closed]

    - by Gary Iverson
    I am working on my first major (several hundred pages) website design and development project. I want to create subdirectories for each of the website's categories, which in turn have their own subdirectories for easy user navigation. Example: website.com/directory. I am aware that by placing an index.html file within each directory, the browser automatically detects and navigates to that page, but that seems like a messy solution (having multiple index.html files, albeit in distinct folders), and I cannot imagine everyone does that. So my question is...how do you properly organize and use subdirectories?

    Read the article

  • Webcast: DB Enterprise User Security Integration with Oracle Directory Services

    - by B Shashikumar
    The typical enterprise has a large number of DBA (Database administrator) accounts that are locally managed, which is often very costly, problematic and error-prone. Databases are a crucial component of your enterprise IT infrastructure, housing sensitive corporate data and database user accounts and privileges. To ensure the integrity of your enterprise's data, it's imperative to have a well-managed identity management system. This begins with centralized management of user accounts and access rights. Enterprise User Security (EUS), an Oracle Database Enterprise Edition feature, combined with Oracle Identity Management, gives you the ability to centrally manage database users and their authorizations in one central place. The cost of user provisioning and password resets is dramatically reduced. This technology is a must for new application development and should be considered for existing applications as well. Join Oracle Advisors for a live webcast on Jul 11 at 8am Pacific Time where Oracle experts will briefly introduce EUS, followed by a detailed discussion about the various directory options that are supported, including integration with Microsoft Active Directory. We'll conclude how to avoid common pitfalls deploying EUS with directory services. To register for this event, click here  

    Read the article

  • SteamCMD can't add files to my home directory

    - by Angle O'Saxon
    I'm trying to clean up the administration of some game servers I run on a Ubuntu box, part of which has been finally setting permissions properly so I can run the Steam console tool that controls updates and such. I had been running it as root using sudo, but I changed the permissions so that I can start it as a regular user rather than root. That bit seems to work fine, but now when SteamCMD actually starts, it errors with the following output ./steam.sh: line 24: /home/angleosaxon/.steampid: Permission denied Installing breakpad exception handler for appid(steam)/version(1334262703) SteamUpdater: Error: Couldn't create directory /home/angleosaxon/Steam/package, got error 13 [ 0%] Download complete. [----] Verifying installation... unlinked 0 orphaned pipes [----] !!! Fatal Error: Steam failed to load: *SteamStartEngine(0xbfa7cfa0) failed with error 1: Failed to open logfile /home/angleosaxon/Steam/steam.log Leaving aside the question of why it wants to add this information to my home directory, why is it getting access denied errors? As I understand it, since it's being run by my account, it operates with my permissions, so it should be able to read/write from my home directory, shouldn't it? This is the command I'm using to run it: /opt/steamcmd/steam.sh "+login UserAccount \"This is not my actual password.\"" +force_install_dir $ServerDir "+app_update 215360 validate" +quit

    Read the article

  • Active Directory Services: PrincipalContext -- What is the DN of a "container" object?

    - by Ranger Pretzel
    I'm currently trying to authenticate via Active Directory Services using the PrincipalContext class. I would like to have my application authenticate to the Domain using Sealed and SSL contexts. In order to do this, I have to use the following constructor of PrincipalContext (link to MSDN page): public PrincipalContext( ContextType contextType, string name, string container, ContextOptions options ) Specifically, I'm using the constructor as so: PrincipalContext domainContext = new PrincipalContext( ContextType.Domain, domain, container, ContextOptions.Sealing | ContextOptions.SecureSocketLayer); MSDN says about "container": The container on the store to use as the root of the context. All queries are performed under this root, and all inserts are performed into this container. For Domain and ApplicationDirectory context types, this parameter is the distinguished name (DN) of a container object. What is the DN of a container object? How do I find out what my container object is? Can I query the Active Directory (or LDAP) server for this?

    Read the article

  • How to Delete a Virtual Directory from an FTP Site in IIS 7 and IIS 7.5 using C#/VB.Net and WMI?

    - by Steve Johnson
    Hi all. I hope everybody is doing fine. I try to delete a virtual directory using WMi (Server Manager Class) and recreate with different values. The problem i am facing is that the virtual directory is not getting deleted. Please help. Here is my code. Try Using mgr As New ServerManager() Dim site As Site = mgr.Sites(DomainName) Dim app As Application = site.Applications("/") '.CreateElement() '("/" & VirDirName) Dim VirDir As VirtualDirectory = app.VirtualDirectories.CreateElement() For Each VirDir In app.VirtualDirectories If VirDir("path") = "/" & VirDirName Then app.VirtualDirectories.Remove(VirDir) Exit For End If Next mgr.CommitChanges() End Using Catch Err As Exception Ex = Err Throw New Exception(Err.Message, Ex) End Try

    Read the article

  • How do I sort an array of Person Objects by using compareto()?

    - by Adam
    Here is my code: > import java.util.Scanner; import java.util.Arrays; /** This class tests the Person class. */ public class PersonDemo { public static void main(String[] args) { int count = 0; Scanner in = new Scanner(System.in); boolean more = false; Person first = null; Person last = null; while (more) { System.out.println( "Please enter the person's name or a blank line to quit"); String name = in.nextLine(); if (name.equals("")) more = false; else { Person p = new Person(name); //new person object created with inputted name Person[] people = new Person[10]; //new array of 10 person objects people[count] = p; //declare person object with index of variable count as the new person object first = people[count]; // I have no idea what to do here. This is where I'm stuck. last = people[count]; // I can't figure out what to do with this either. first.compareTo(p); //call compareTo method on first and new person object last.compareTo(p); //call compareTo method on last and new person object count++; // increase count variable } } System.out.println("First: " + first.toString()); System.out.println("Last: " + last.toString()); } } And the Person class: /** A person with a name. */ public class Person implements Comparable { /** * Constructs a Person with a name. * @param aName the person's name */ public Person(String aName) { name = aName; } public String getName() { return name; } @Override public int compareTo(Object otherObject) { Person other = (Person)otherObject; if (name.compareTo(other.name) < 0) return -1; if (name.compareTo(other.name) > 0) return 1; return 0; } /** Returns a string representation of the object. @return name of Person */ public String toString() { return "[name=" + name + "]"; } private String name; }

    Read the article

  • Mocking Sort With Mocha

    - by josephmate
    How can I mock an array's sort expect a lambda expression? This is a trivial example of my problem: # initializing the data l = lambda { |a,b| a <=> b } array = [ 1, 2, 3, 4, 5 ] sorted_array = [ 2, 3, 8, 9, 1] # I expect that sort will be called using the lambda as a parameter array.expects(:sort).with( l ).returns( sorted_array ) # perform the sort using the lambda expression temp = array.sort{|a,b| l.call(a,b) } Now, at first I expected that this would work; however, I got the following error: - expected exactly once, not yet invoked: [ 1, 2, 3, 4, 5 ].sort(#<Proc:0xb665eb48>) Is there a way to do what I am looking for? Cheers, Joseph

    Read the article

  • How to Look Up Email by Full Name in Active Directory?

    - by Danny
    I want to search for a user's email by using Active Directory. Available is the user's full name (ex. "John Doe" for the email with an email "[email protected]"). From what I've searched, this comes close to what I'm looking to do -- except that the Filter is set to "SAMAccountName", which is not what I have. Unless I'm misunderstanding, I just need to pick the right attribute and toss in the full name name in the same way. Unfortunately, I don't know what this attribute is, apparently no one has had to ask about searching for information in this manner, and that is a pretty big list (msdn * microsoft * com/en-us/library/ms675090(v=VS.85) * aspx, stackoverflow didn't let me link 2 hyperlinks because I don't have 10 rep) of attributes. Does anyone know how to obtain the user's email address through an Active Directory lookup by using the user's full name?

    Read the article

  • Why wont this sort in Solr work?

    - by Camran
    I need to sort on a date-field type, which name is "mod_date". It works like this in the browser adress-bar: http://localhost:8983/solr/select/?&q=bmw&sort=mod_date+desc But I am using a phpSolr client which sends an URL to Solr, and the url sent is this: fq=+category%3A%22Bilar%22+%2B+car_action%3AS%C3%A4ljes&version=1.2&wt=json&json.nl=map&q=%2A%3A%2A&start=0&rows=5&sort=mod_date+desc // This wont work and is echoed after this in php: $queryString = http_build_query($params, null, $this->_queryStringDelimiter); $queryString = preg_replace('/%5B(?:[0-9]|[1-9][0-9]+)%5D=/', '=', $queryString); This wont work, I dont know why! Everything else works fine, all right fields are returned. But the sort doesn't work. Any ideas? Thanks BTW: The field "mod_date" contains something like: 2010-03-04T19:37:22.5Z EDIT: First I use PHP to send this to a SolrPhpClient which is another php-file called service.php: require_once('../SolrPhpClient/Apache/Solr/Service.php'); $solr = new Apache_Solr_Service('localhost', 8983, '/solr/'); $results = $solr->search($querystring, $p, $limit, $solr_params); $solr_params is an array which contains the solr-parameters (q, fq, etc). Now, in service.php: $params['version'] = self::SOLR_VERSION; // common parameters in this interface $params['wt'] = self::SOLR_WRITER; $params['json.nl'] = $this->_namedListTreatment; $params['q'] = $query; $params['sort'] = 'mod_date desc'; // HERE IS THE SORT I HAVE PROBLEM WITH $params['start'] = $offset; $params['rows'] = $limit; $queryString = http_build_query($params, null, $this->_queryStringDelimiter); $queryString = preg_replace('/%5B(?:[0-9]|[1-9][0-9]+)%5D=/', '=', $queryString); if ($method == self::METHOD_GET) { return $this->_sendRawGet($this->_searchUrl . $this->_queryDelimiter . $queryString); } else if ($method == self::METHOD_POST) { return $this->_sendRawPost($this->_searchUrl, $queryString, FALSE, 'application/x-www-form-urlencoded'); } The $results contain the results from Solr... So this is the way I need to get to work (via php). This code below (also on top of this Q) works but thats because I paste it into the adress bar manually, not via the PHPclient. But thats just for debugging, I need to get it to work via the PHPclient: http://localhost:8983/solr/select/?&q=bmw&sort=mod_date+des // Not via phpclient, but works UPDATE (2010-03-08): I have tried Donovans codes (the urls) and they work fine. Now, I have noticed that it is one of the parameters causing the 'SORT' not to work. This parameter is the "wt" parameter. If we take the url from top of this Q, (fq=+category%3A%22Bilar%22+%2B+car_action%3AS%C3%A4ljes&version=1.2&wt=json&json.nl=map&q=%2A%3A%2A&start=0&rows=5&sort=mod_date+desc), and just simply remove the "wt" parameter, then the sort works. BUT the results appear differently, thus making my php code not able to recognize the results I believe. Donovan would know this I think. I am guessing in order for the PHPClient to work, the results must be in a specific structure, which gets messed up as soon as I remove the wt parameter. Donovan, help me please... Here is some background what I use your SolrPhpClient for: I have a classifieds website, which uses MySql. But for the searching I am using Solr to search some indexed fields. Then Solr returns an array of ID:numbers (for all matches of the search criteria). Then I use those ID:numbers to find everything in a MySql db and fetch all other information (example is not searchable information). So simplified: Search - Solr returns all matches in an array of ID:nrs - Id:numbers from Solr are the same as the Id numbers in the MySql db, so I can just make a simple match agains every record with the ID matching the ID from the Solr results array. I don't use Faceting, no boosting, no relevancy or other fancy stuff. I only sort by the latest classified put, and give the option to users to also sort on the cheapest price. Nothing more. Then I use the "fq" parameter to do queries on different fields in Solr depending on category chosen by users (example "cars" in this case which in my language is "Bilar"). I am really stuck with this problem here... Thanks for all help

    Read the article

  • Active Directory: User UPN or DN for NTLM name, using pure LDAP?

    - by Bernd Haug
    I have a Java app that can authenticate to LDAP by logging users into the AD LDAP server with the NTLM name (which they are used to - this is a requirement). I now also need to do authorization, and hence need to find a forest-unique identifier for the user (DN or UPN should work), from which I can further query the directory. The method needs to be absolutely portable, even if the AD is structured in an unusual fashion, otherwise I could just do a string replacement and search for a UPN of "${ntlm-user}@${ntlm-domain}.${configured-trailing-domain}" How can I do this, using pure LDAP? Currently, I'm using the java.naming.directory package, which I'd like to keep using, since it doesn't throw up problems when not binding with a DN but logging in with an NTLM name?

    Read the article

  • Confused about GNU `sort(1)` of a numerical sub field

    - by Chen Levy
    I wish to sort a space separated table, with the numerical value that found on the 2nd field. I can assume that the 2nd field is always fooN but the length of N is unknown: antiq. foo11 girls colleaguing foo2 Leinsdorf Cousy foo0 Montgomeryville bowlegged foo1 pollack Chevrier foo10 ill-conceived candlebomb foo3 seventieths autochthony foo101 re-enable beneficiate foo100 osteometric I read man sort(1) and played with all sort of options. On my system I found the line: sort -n -k2.5 table to work. My question is why? According to the man page: -k, --key=POS1[,POS2] start a key at POS1, end it at POS 2 (origin 1) ... POS is F[.C][OPTS], where F is the field number and C the characterposition in the field. OPTS is one or more single-letter ordering options, which override global ordering options for that key. If no key is given, use the entire line as the key. So why sort -n -k2.4 table don't work and sort -n -k.5 does?

    Read the article

  • Sort a GridView Column related to other Table

    - by Tim
    Hello, i have a GridView bound to a DataView. Some columns in the DataView's table are foreignkeys to related tables(f.e. Customer). I want to enable sorting for these columns too, but all i can do is sorting the foreignkey(fiCustomer) and not the CustomerName. I have tried this without success(" Cannot find column ERP_Customer.CustomerName "): <asp:TemplateField HeaderText="Customer" SortExpression="ERP_Customer.CustomerName" > A tried also the DataViewManager, but i've a problem to detect the table to sort: Dim viewManager As New DataViewManager(Me.dsERP) viewManager.DataViewSettings(dsERP.ERP_Charge).RowFilter = filter viewManager.DataViewSettings(dsERP.ERP_Charge).Sort = sort 'sort is the GridView's SortExpression Me.GrdCharge.DataSource = viewManager.CreateDataView(dsERP.ERP_Charge) I have to apply the sort on a distinct table of the DataViewManager, but this table would differ on the related tables. I have bound the TemplateColumns in Codebehind in RowDataBound-Event f.e.: Dim LblCustomer As Label = DirectCast(e.Row.FindControl("LblCustomer"), Label) LblCustomer.Text = drCharge.ERP_CustomerRow.CustomerName 'drCharge inherits DataRow What is the recommended way to sort a GridView on columns related to another table?

    Read the article

  • Active Directory on local server and intranet on external server.

    - by cvack
    I have a local Active Directory server and a external web server where my intranet is located. $ad = ldap_connect("ldap://ip-address") or die("Couldn't connect to AD!"); ldap_set_option($ad, LDAP_OPT_PROTOCOL_VERSION, 3); $bd = ldap_bind( $ad, "user@domain", "password") or die("Can't bind to server."); When I run this on a local web server it succesfully binds the connection. If I run the same code on the external server its unable to bind the ldap connection. Both port 389 and 636 is open on the AD server. I've tried google for an answer, but all the tutorials is for Active Directory and webserver on the same server. Is this even possible?

    Read the article

  • What's the best way to tell if a file exists in a directory?

    - by Nano HE
    I'm trying to move a file but I want to ensure that it exists before I do so. What's the simplest way to do this in Perl? My code is like this. I looked up the open command, but I am not sure it is the simplest way or not. if #Parser.exe exist in directory of Debug { move ("bin/Debug/Parser.exe","Parser.exe"); } elsif #Parser.exe exist in directory of Release { move ("bin/Release/Parser.exe","Parser.exe"); } else { die "Can't find the Parser.exe."; } Thank you.

    Read the article

  • Can a shell loop unzip all the files in a directory?

    - by helpwithshell
    I've seen loops to unzip all zip files in a directory. However, before I run this, I would rather make sure what I'm about to run will work right: for i in dir; do cd $i; unzip '*.zip'; rm -rf *.zip; cd ..; done Basically I want it to look at the output of "dir" see all the folders, for each directory cd into it, unzip all the zip archives, then remove them, then cd back and do it again until there are no more. Is this something I should do in a single command or should I consider doing this in Perl?

    Read the article

  • Where can I get a one-off server of Active Directory for Developing against?

    - by umbrae
    We're not a windows shop, but one of our products is going to need to optionally integrate with Active Directory - things like SSO etc. I'd really rather not go through the rigamarole of setting up a whole server just to develop against it and then leave it hanging around for testing purposes. Is there a simple cloud-based service where I can purchase a server running active directory for a month or two just for development purposes? I looked into Amazon EC2 but it looks like you may still need to go through a significant set up (I may be wrong on this).

    Read the article

  • Mysql select most frequent and sort alphabetically

    - by user2605793
    I am trying to select the most common 100 names from a table then display the list showing the names and count. I want the user to be able to re-sort the list alphabetically rather than based on count. I thought the following code would do it. It works for the default sort by count but fails on the sort alphabetically. The line "$count = mysql_num_rows($table);" gives an error: mysql_num_rows() expects parameter 1 to be resource, boolean given. Any help would be greatly appreciated. // Get most popular surnames echo '<h2>Most Common Surnames</h2>'; if ($sort == "") { // default sort by count echo '<a href="http://mysite/names.php?id='.$id.'&sort=name">Sort by name</a><br>'; $query = "SELECT family_name, COUNT(*) as count FROM namefile WHERE record_key = $id GROUP BY family_name ORDER BY count DESC LIMIT 100"; } else { // sort alphabetically echo '<a href="http://mysite/names.php?id='.$id.'">Sort by count</a><br>'; $query = "SELECT * FROM ( SELECT family_name, COUNT(*) as count FROM namefile WHERE record_key = $id GROUP BY family_name ORDER BY count DESC LIMIT 100) AS alpha ORDER BY family_name"; } $table = mysql_query($query); $count = mysql_num_rows($table); $tot = 0; $i = 0; echo '<table><tr>'; while ($tot < $count2) { $rec2 = mysql_fetch_array($table2); echo '<td>'.$rec2[0].'</td><td>'.$rec2[1].'</td><td width="40">&nbsp;</td><td>'; if ($i++ == 6) { echo '</tr><tr>'; $i = 0; } $tot++; } echo '</tr></table><br>'; UPDATE: I needed to add "AS alpha" to give the outer select a unique name. (alpha is just a random name I made up.) It now works perfectly. Code updated for the benefit of any others who need something similar.

    Read the article

  • Apache redirect when users home directory is completely empty.

    - by Scott M
    I work for an ISP and I have a server with thousands of users 10MB of free storage. They get this free storage with every e-mail account they have with us. An example of a users storage address: http://users.example.com/~username/ One problem I can see is scanning the server for user names to see what accounts are available, basically getting a list of all our customers valid e-mail addresses. This would be very, very bad. So I'm wanting to redirect to our homepage if someone comes across a users account that is empty (I'd say 90% of them are completely empty). I also do not want to simply -Indexes them and use a custom 403 because the few customers that do use them, want +Indexes. I know I can always just tell the customers to put a htaccess file in their directory with Options +indexes if they want directory listing, but that's a last resort. How can I make it pretty much impossible to tell what accounts are on the server but not in use at all?

    Read the article

  • Method to sort MYSQL results by an arbitriary letter (ie, show all rows starting with F first)

    - by Buzz
    I have a column of states, and, depending on the query, I want to order by results by a particular state, then by id (Asc or Desc, depending). For instance, I might want to show all rows with state "HI", sorted by ID desc, and then all the other rows, sorted by id desc. I was hoping I could do this in one query, rather than getting all my favored state results, and then getting the rest. Can I?

    Read the article

  • How can i add Active Directory security groups to a SharePoint site to control permissions, rather than individual user accounts

    - by user574811
    SharePoint does integrate active directory accounts, of course, but how about security groups? Have a few sites where I'm fairly confident access is going through an existing Active Directory (AD) security groups (i.e. only an AD security group has been granted permissions through the 'People and Groups') In another situation, where I created the AD group and granted it permissions to a site, the customers were not able to access immediately. Eventually had to fast-track it and add the individuals to the People and Groups to keep the project going, but hoping not to have to maintain it that way. Any specific requirements of the security group in AD? Universal, Global, or domain local? Is there any time delay between modifying group members in AD and having that take effect in SharePoint?

    Read the article

  • Algorithm of JavaScript "sort()" Function

    - by Knowledge Craving
    Recently when I was working with JavaScript "sort()" function, I found in one of the tutorials that this function does not sort the numbers properly. Instead to sort numbers, a function must be added that compares numbers, like the following code:- <script type="text/javascript"> function sortNumber(a,b) { return a - b; } var n = ["10", "5", "40", "25", "100", "1"]; document.write(n.sort(sortNumber)); </script> The output then comes as:- 1,5,10,25,40,100 Now what I didn't understand is that why is this occurring & can anybody please tell in details as to what type of algorithm is being used in this "sort()" function? This is because for any other language, I didn't find this problem where the function didn't sort the numbers correctly. Any help is greatly appreciated.

    Read the article

< Previous Page | 35 36 37 38 39 40 41 42 43 44 45 46  | Next Page >