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  • Bring Spring to Your Desktop with the Dreamgarden Theme for Windows 7

    - by Asian Angel
    Are you ready for Spring? Then bring the beauty of the season to your desktop with the Dreamgarden Theme for Windows 7. This refreshing theme comes with eighteen images full of springtime color by photographer Christina Manchenko. Download the Dreamgarden Theme [Windows 7 Personalization Gallery] How to Own Your Own Website (Even If You Can’t Build One) Pt 1 What’s the Difference Between Sleep and Hibernate in Windows? Screenshot Tour: XBMC 11 Eden Rocks Improved iOS Support, AirPlay, and Even a Custom XBMC OS

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  • OpenEjb DeploymentLoader.getWebDescriptors NullPointerException

    - by jwmajors81
    I am currently getting the following error when I try to startup an EAR that includes OpenEJB. The error is: java.lang.NullPointerException at org.apache.openejb.config.DeploymentLoader.getWebDescriptors(DeploymentLoader.java:1057) at org.apache.openejb.config.DeploymentLoader.discoverModuleType(DeploymentLoader.java:1162) at org.apache.openejb.config.DeploymentsResolver.processUrls(DeploymentsResolver.java:294) at org.apache.openejb.config.DeploymentsResolver.loadFromClasspath(DeploymentsResolver.java:248) at org.apache.openejb.spring.ClassPathApplication.loadApplications(ClassPathApplication.java:56) at org.apache.openejb.spring.AbstractApplication.deployApplication(AbstractApplication.java:106) at org.apache.openejb.spring.OpenEJB.deployApplication(OpenEJB.java:342) at org.apache.openejb.spring.AbstractApplication.start(AbstractApplication.java:94) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:79) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:618) at org.springframework.beans.factory.annotation.InitDestroyAnnotationBeanPostProcessor$LifecycleElement.invoke(InitDestroyAnnotationBeanPostProcessor.java:340) The environment consists of: - Spring 3.0 - OpenEJB 3.1 - WebSphere 6.1 (Without EJB/Web Service feature packs) - OpenEJB-Spring jar The app-config.xml that configures Spring and OpenEJB looks like: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" xmlns:p="http://www.springframework.org/schema/p" xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd" Also please note that I do have a JUnit test that runs against the app-config.xml specified above that can successfully load the application context file. It is just when I deploy it to WebSphere I encounter the error provided at the beginning of this message. Any assistance would be greatly appreciated. Thanks, Jeremy

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  • How do you use stereotype annotations in Spring 2.5.x?

    - by grigory
    When moving to Spring 2.5.x I found that it adds more stereotype annotations (on top of @Repository from 2.0): @Component, @Service and @Controller. How do you use them? Do you rely on implicit Spring support or you define custom stereotype specific functions/aspects/features? Or is it predominately for marking beans (compile time, conceptual, etc.)?

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  • Is there a way to specify a default property value in Spring XML?

    - by Rog
    We are using a PropertyPlaceholderConfigurer to use java properties in our Spring configuration (details here) eg: <foo name="port"> <value>${my.server.port}</value> </foo> We would like to add an additional property, but have a distributed system where existing instances could all use a default value. Is there a way to avoid updating all of our properties files, by indicating a default value in the Spring config for when there isn't an overriding property value defined?

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  • How to parameterize @Scheduled(fixedDelay) with Spring 3.0 expression language?

    - by ngeek
    When using the Spring 3.0 capability to annotate the a scheduled task, I would like to set the fixedDelay as parameter from my configuration file, instead of hard-wiring it into my task class, like currently... @Scheduled(fixedDelay=5000) public void readLog() { ... } Unfortunately it seems that with the means of the Spring Expression Language (EL) @Value returns a String object which in turn is not able to be auto-boxed to a long value as required by the fixedDelay parameter. Thanks in advance for your help on this.

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  • How to integrate Windows Azure, Spring.NET and NHibernate?

    - by paologios
    Hi, we have a ASP.NET web application which makes use of NHibernate and Spring.NET (to do the session and transaction management stuff). Now we want to port parts of it to a Windows Azure application without making lots of changes to the used components. I already found this article of stackoverflow so I hope to get NHibernate running on Azure. My question: Has anybody experiences in running Spring.NET on Azure (with or without NHibernate) ??

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  • Why would I use Scala/Lift over Java/Spring?

    - by Chris J
    Hi, I know this question is a bit open but I have been looking at Scala/Lift as an alternative to Java/Spring and I am wonder what are the real advantages that Scala/Lift has over it. From my perspective and experience, Java Annotations and Spring really minimizes the amount of coding that you have to do for an application. Does Scala/Lift improve upon that?

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  • How to generate a metamodel for POJOs

    - by Stefan Haberl
    I'm looking for a metamodel generation library for simple Java POJOs. I'm thinking about something along the lines of JPA 2.0's metamodel, which can be used to generate type safe criterias for JPA entities (see this Question on SO for JPA specific implementations). Does something similar exist for general purpose JavaBeans, i.e., POJOS, that are not JPA entities? Specifically, I want to implement Spring MVC's WebDataBinder.setAllowedFields() method in a type safe way in my Spring MVC @Controllers

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  • How do I get spring to inject my EntityManager?

    - by Trampas Kirk
    I'm following the guide here, but when the DAO executes, the EntityManager is null. I've tried a number of fixes I found in the comments on the guide, on various forums, and here (including this), to no avail. No matter what I seem to do the EntityManager remains null. Here are the relevant files, with packages etc changed to protect the innocent. spring-context.xml <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:tx="http://www.springframework.org/schema/tx" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd" xmlns:p="http://www.springframework.org/schema/p"> <context:component-scan base-package="com.group.server"/> <context:annotation-config/> <tx:annotation-driven/> <bean id="propertyPlaceholderConfigurer" class="com.group.DecryptingPropertyPlaceholderConfigurer" p:systemPropertiesModeName="SYSTEM_PROPERTIES_MODE_OVERRIDE"> <property name="locations"> <list> <value>classpath*:spring-*.properties</value> <value>classpath*:${application.environment}.properties</value> </list> </property> </bean> <bean id="orderDao" class="com.package.service.OrderDaoImpl"/> <bean class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor"/> <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="persistenceUnitName" value="MyServer"/> <property name="loadTimeWeaver"> <bean class="org.springframework.instrument.classloading.InstrumentationLoadTimeWeaver"/> </property> <property name="dataSource" ref="dataSource"/> <property name="jpaVendorAdapter"> <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"> <property name="showSql" value="${com.group.server.vendoradapter.showsql}"/> <property name="generateDdl" value="${com.group.server.vendoradapter.generateDdl}"/> <property name="database" value="${com.group.server.vendoradapter.database}"/> </bean> </property> </bean> <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager"> <property name="entityManagerFactory" ref="entityManagerFactory"/> <property name="dataSource" ref="dataSource"/> </bean> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="${com.group.server.datasource.driverClassName}"/> <property name="url" value="${com.group.server.datasource.url}"/> <property name="username" value="${com.group.server.datasource.username}"/> <property name="password" value="${com.group.server.datasource.password}"/> </bean> <bean id="executorService" class="java.util.concurrent.Executors" factory-method="newCachedThreadPool"/> </beans> persistence.xml <persistence xmlns="http://java.sun.com/xml/ns/persistence" version="1.0"> <persistence-unit name="MyServer" transaction-type="RESOURCE_LOCAL"/> </persistence> OrderDaoImpl package com.group.service; import com.group.model.Order; import org.springframework.stereotype.Repository; import org.springframework.transaction.annotation.Transactional; import javax.persistence.EntityManager; import javax.persistence.PersistenceContext; import javax.persistence.Query; import java.util.List; @Repository @Transactional public class OrderDaoImpl implements OrderDao { private EntityManager entityManager; @PersistenceContext public void setEntityManager(EntityManager entityManager) { this.entityManager = entityManager; } @Override public Order find(Integer id) { Order order = entityManager.find(Order.class, id); return order; } @Override public List<Order> findAll() { Query query = entityManager.createQuery("select o from Order o"); return query.getResultList(); } @Override public List<Order> findBySymbol(String symbol) { Query query = entityManager.createQuery("select o from Order o where o.symbol = :symbol"); return query.setParameter("symbol", symbol).getResultList(); } }

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  • Spring MVC: How to resolve the path to subdirectories of the root 'JSP' folder in a web application

    - by chrisjleu
    What is a simple way to resolve the path to a JSP file that is not located in the root JSP directory of a web application using SpringMVCs viewResolvers? For example, suppose we have the following web application structure: web-app |-WEB-INF |-jsp |-secure |-admin.jsp |-admin2.jsp index.jsp login.jsp I would like to use some out-of-the-box components to resolve the JSP files within the jsp root folder and the secure subdirectory. I have a *-servlet.xml file that defines: an out-of-the-box, InternalResourceViewResolver: <bean id="jspViewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"></property> <property name="prefix" value="/WEB-INF/jsp/"></property> <property name="suffix" value=".jsp"></property> </bean> a handler mapping: <bean id="handlerMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping"> <property name="mappings"> <props> <prop key="/index.htm">urlFilenameViewController</prop> <prop key="/login.htm">urlFilenameViewController</prop> <prop key="/secure/**">urlFilenameViewController</prop> </props> </property> </bean> an out-of-the-box UrlFilenameViewController controller: <bean id="urlFilenameViewController" class="org.springframework.web.servlet.mvc.UrlFilenameViewController"> </bean> The problem I have is that requests to the JSPs in the secure directory cannot be resolved, as the jspViewResolver only has a prefix defined as /jsp/ and not /jsp/secure/. Is there a way to handle subdirectories like this? I would prefer to keep this structure because I'm also trying to make use of Spring Security and having all secure pages in a subdirectory is a nice way to do this. There's probably a simple way to acheive this but I'm new to Spring and the Spring MVC framework so any pointers would be appreciated.

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  • How to make a request from an android app that can enter a Spring Security secured webservice method

    - by johnrock
    I have a Spring Security (form based authentication) web app running CXF JAX-RS webservices and I am trying to connect to this webservice from an Android app that can be authenticated on a per user basis. Currently, when I add an @Secured annotation to my webservice method all requests to this method are denied. I have tried to pass in credentials of a valid user/password (that currently exists in the Spring Security based web app and can log in to the web app successfully) from the android call but the request still fails to enter this method when the @Secured annotation is present. The SecurityContext parameter returns null when calling getUserPrincipal(). How can I make a request from an android app that can enter a Spring Security secured webservice method? Here is the code I am working with at the moment: Android call: httpclient.getCredentialsProvider().setCredentials( //new AuthScope("192.168.1.101", 80), new AuthScope(null, -1), new UsernamePasswordCredentials("joeuser", "mypassword")); String userAgent = "Android/" + getVersion(); HttpGet httpget = new HttpGet(MY_URI); httpget.setHeader("User-Agent", userAgent); httpget.setHeader("Content-Type", "application/xml"); HttpResponse response; try { response = httpclient.execute(httpget); HttpEntity entity = response.getEntity(); ... parse xml Webservice Method: @GET @Path("/payload") @Produces("application/XML") @Secured({"ROLE_USER","ROLE_ADMIN","ROLE_GUEST"}) public Response makePayload(@Context Request request, @Context SecurityContext securityContext){ Payload payload = new Payload(); payload.setUsersOnline(new Long(200)); if (payload == null) { return Response.noContent().build(); } else{ return Response.ok().entity(payload).build(); } }

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  • VBUG Spring Conference, 28th and 29th March in Reading

    - by Eric Nelson
    I presented at VBUG last year and can confirm that they put on a really good event. This year I stood aside for my “replacement” Steve Plank to work his magic. Worth checking out… VBUG SPRING CONFERENCE 28/29 March 2011 Wokefield Park, Mortimer, Reading RG7 3AH Day One (Mon 28 March): Developing SharePoint 2010 with Visual Studio 2010 - Dave McMahon Cache Out with Windows Server AppFabric – Phil Pursglove Extending your Corporate Network in to the Windows Azure Data Centre with Windows Azure Connect – Steve Plank Silverlight Development on Windows Phone 7 - Andy Wigley Day Two (Tues 29 March): Self Service BI for your users, but what does that mean for you? - Andrew Fryer Design Patterns – Compare and Contrast – Gary Short Projecting your corporate identity to the cloud – Steve Plank May the Silverlight 4 be with you – Richard Costall The Step up to ALM – an Introduction to Visual Studio 2010 TFS for the Visual Sourcesafe User - Richard Fennell For more information go to http://cms.vbug.net (It isn’t free but it is high quality)

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  • JPA 2 and Hibernate 3.5.1 MEMBER OF query doesnt work.

    - by Ed_Zero
    I'm trying the following JPQL and it fails misserably: Query query = em.createQuery("SELECT u FROM User u WHERE 'admin' MEMBER OF u.roles"); List users = query.query.getResultList(); I get the following exception: ERROR [main] PARSER.error(454) | <AST>:0:0: unexpected end of subtree java.lang.IllegalArgumentException: org.hibernate.hql.ast.QuerySyntaxException: unexpected end of subtree [SELECT u FROM com.online.data.User u WHERE 'admin' MEMBER OF u.roles] ERROR [main] PARSER.error(454) | <AST>:0:0: expecting "from", found '<ASTNULL>' ... ... Caused by: org.hibernate.hql.ast.QuerySyntaxException: unexpected end of subtree [SELECT u FROM com.online.data.User u WHERE 'admin' MEMBER OF u.roles] I have Spring 3.0.1.RELEASE, Hibernate 3.5.1-Final and maven to glue dependencies. User class: @Entity public class User { @Id @Column(name = "USER_ID") @GeneratedValue(strategy = GenerationType.IDENTITY) private long id; @Column(unique = true, nullable = false) private String username; private boolean enabled; @ElementCollection private Set<String> roles = new HashSet<String>(); ... } Spring configuration: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" xmlns:tx="http://www.springframework.org/schema/tx" xmlns:p="http://www.springframework.org/schema/p" xmlns:aop="http://www.springframework.org/schema/aop" xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/tx/spring-context-3.0.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.0.xsd"> <!-- Reading annotation driven configuration --> <tx:annotation-driven transaction-manager="transactionManager" /> <bean class="org.springframework.dao.annotation.PersistenceExceptionTranslationPostProcessor" /> <bean class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" /> <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close"> <property name="driverClassName" value="${jdbc.driverClassName}" /> <property name="url" value="${jdbc.url}" /> <property name="username" value="${jdbc.username}" /> <property name="password" value="${jdbc.password}" /> <property name="maxActive" value="100" /> <property name="maxWait" value="1000" /> <property name="poolPreparedStatements" value="true" /> <property name="defaultAutoCommit" value="true" /> </bean> <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager"> <property name="entityManagerFactory" ref="entityManagerFactory" /> <property name="dataSource" ref="dataSource" /> </bean> <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="dataSource" ref="dataSource" /> <property name="jpaVendorAdapter"> <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"> <property name="showSql" value="true" /> <property name="databasePlatform" value="${hibernate.dialect}" /> </bean> </property> <property name="loadTimeWeaver"> <bean class="org.springframework.instrument.classloading.InstrumentationLoadTimeWeaver" /> </property> <property name="jpaProperties"> <props> <prop key="hibernate.hbm2ddl.auto">update</prop> <prop key="hibernate.current_session_context_class">thread</prop> <prop key="hibernate.cache.provider_class">org.hibernate.cache.NoCacheProvider</prop> <prop key="hibernate.show_sql">true</prop> <prop key="hibernate.format_sql">false</prop> <prop key="hibernate.show_comments">true</prop> </props> </property> <property name="persistenceUnitName" value="punit" /> </bean> <bean id="JpaTemplate" class="org.springframework.orm.jpa.JpaTemplate"> <property name="entityManagerFactory" ref="entityManagerFactory" /> </bean> </beans> Persistence.xml <?xml version="1.0" encoding="UTF-8"?> <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence"> <persistence-unit name="punit" transaction-type="RESOURCE_LOCAL" /> </persistence> pom.xml maven dependencies. <dependency> <groupId>org.hibernate</groupId> <artifactId>hibernate</artifactId> <version>${hibernate.version}</version> <type>pom</type> </dependency> <dependency> <groupId>org.hibernate</groupId> <artifactId>hibernate-core</artifactId> <version>${hibernate.version}</version> </dependency> <dependency> <groupId>org.hibernate</groupId> <artifactId>hibernate-annotations</artifactId> <version>${hibernate.version}</version> </dependency> <dependency> <groupId>org.hibernate</groupId> <artifactId>hibernate-entitymanager</artifactId> <version>${hibernate.version}</version> </dependency> <dependency> <groupId>commons-dbcp</groupId> <artifactId>commons-dbcp</artifactId> <version>1.2.2</version> <type>jar</type> </dependency> <dependency> <groupId>org.springframework.security</groupId> <artifactId>spring-security-web</artifactId> <version>${spring.version}</version> </dependency> <dependency> <groupId>org.springframework.security</groupId> <artifactId>spring-security-config</artifactId> <version>${spring.version}</version> </dependency> <dependency> <groupId>org.springframework.security</groupId> <artifactId>spring-security-taglibs</artifactId> <version>${spring.version}</version> </dependency> <dependency> <groupId>org.springframework.security</groupId> <artifactId>spring-security-acl</artifactId> <version>${spring.version}</version> </dependency> <dependency> <groupId>javax.annotation</groupId> <artifactId>jsr250-api</artifactId> <version>1.0</version> </dependency> <properties> <!-- Application settings --> <spring.version>3.0.1.RELEASE</spring.version> <hibernate.version>3.5.1-Final</hibernate.version> Im running a unit test to check the configuration and I am able to run other JPQL queries the only ones that I am unable to run are the IS EMPTY, MEMBER OF conditions. The complete unit test is as follows: TestIntegration @RunWith(SpringJUnit4ClassRunner.class) @ContextConfiguration(locations = { "/spring/dataLayer.xml"}) @Transactional @TransactionConfiguration public class TestUserDaoImplIntegration { @PersistenceContext private EntityManager em; @Test public void shouldTest() throws Exception { try { //WORKS Query query = em.createQuery("SELECT u FROM User u WHERE 'admin' in elements(u.roles)"); List users = query.query.getResultList(); //DOES NOT WORK } catch (Exception e) { e.printStackTrace(); throw e; } try { Query query = em.createQuery("SELECT u FROM User u WHERE 'admin' MEMBER OF u.roles"); List users = query.query.getResultList(); } catch (Exception e) { e.printStackTrace(); throw e; } } }

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  • Need advice on framework design: how to make extending easy

    - by beginner_
    I'm creating a framework/library for a rather specific use-case (data type). It uses diverse spring components, including spring-data. The library has a set of entity classes properly set up and according service and dao layers. The main work or main benefit of the framework lies in the dao and service layer. Developers using the framework should be able to extend my entity classes to add additional fields they require. Therefore I made dao and service layer generic so it can be used by such extended entity classes. I now face an issue in the IO part of the framework. It must be able to import the according "special data type" into the database. In this part I need to create a new entity instance and hence need the actual class used. My current solution is to configure in spring a bean of the actual class used. The problem with this is that an application using the framework could only use 1 implementation of the entity (the original one from me or exactly 1 subclass but not 2 different classes of the same hierarchy. I'm looking for suggestions / desgins for solving this issue. Any ideas?

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  • ASP.NET MVC, Spring.NET, NHibernate initial setup/example/tutorial.

    - by Bubba88
    Hello! Have you been doing some ASP.NET MVC developement involving Spring.NET and NHibernate both? I would like to see an informative example of such setup, so I could build my own project off that. I tried googling, found some pretty things like S#arp Architecture, an article about regular ASP.NET (WebForms) integrated with the frameworks and so on. Still, I'm missing a good tutorial on ASP.NET MVC & the subj. P.S.: I do know how Spring and Hibernate works, I just need to plug them into an MVC application. Don't want to use S#arp Architecture by now. P.P.S: I'll update the links later, including this one:

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  • How to achieve conditional resource import in a Spring XML context?

    - by Boris Terzic
    What I would like to achieve is the ability to "dynamically" (i.e. based on a property defined in a configuration file) enable/disable the importing of a child Spring XML context. I imagine something like: <import condition="some.property.name" resource="some-context.xml"/> Where the property is resolved (to a boolean) and when true the context is imported, otherwise it isn't. Some of my research so far: Writing a custom NamespaceHandler (and related classes) so I can register my own custom element in my own namespace. For example: <myns:import condition="some.property.name" resource="some-context.xml"/> The problem with this approach is that I do not want to replicate the entire resource importing logic from Spring and it isn't obvious to me what I need to delegate to to do this. Overriding DefaultBeanDefinitionDocumentReader to extend the behaviour of the "import" element parsing and interpretation (which happens there in the importBeanDefinitionResource method). However I'm not sure where I can register this extension.

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  • Spring Security DB Authentication w/Hibernate and hashed passwords?

    - by Seth
    I'm trying to set up spring security 3 to authenticate users against my hibernate 3 database. I'm storing only sha1 hashes of the passwords in the database (not plaintext). I've looked at this and this, which tell me to implement my own UserDetailsService. Unfortunately, the UserDetails that loadUserByUsername spits out seem to need the plaintext password, which I don't have. How is this usually handled? Can Spring Security actually do what I need here? Am I missing something?

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  • Spring MVC Controller redirect using URL parameters instead of in response.

    - by predhme
    I am trying to implement RESTful urls in my Spring MVC application. All is well except for handling form submissions. I need to redirect either back to the original form or to a "success" page. @Controller @RequestMapping("/form") public class MyController { @RequestMapping(method = RequestMethod.GET) public String setupForm() { // do my stuff return "myform"; } @RequestMapping(method = RequestMethod.POST) public String processForm(ModelMap model) { // process form data model.addAttribute("notification", "Successfully did it!"); return "redirect:/form"; } } However as I read in the Spring documentation, if you redirect any parameters will be put into the url. And that doesn't work for me. What would be the most graceful way around this?

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  • Howto: Configure Spring-WS to publish WSDL files with a '?WSDL' style URL?

    - by Darren
    I am trying to configure web service proxying using Mule ESB. I am attempting to do this using Mule's WSProxyService, but after stepping through the corresponding code (with the debugger), it is clear that this class replaces endpoint addresses. The problem is Spring-WS WSDL addresses are of the style http://xxxx/xxxx.wsdl, but WSProxyService expects http://xxxx/xxxx?wsdl or http://xxxx/xxxx&wsdl. It replaces the remote endpoint addresses with the local WSDL address; it cuts the remote WSDL address at the question mark i.e. '?WSDL' is intended to be chopped off, so to create the search term. But because of Spring-WS, this does not work. To break it down: WSProxyService ends up trying to use http://xxxx/xxxx.wsdl to replace http://xxxx/xxxx with http://yyyy/yyyy which fails... leading to actual web service call going direct and not through the proxy. Has anyone ever noticed/solved this problem?? Cheers, Darren

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  • Spring security annotations with EL -- requires debug information compiled in?

    - by HDave
    I am considering using Spring Security annotations for my application, with the EL (expression language) feature. For example: @PreAuthorize("hasPermission(#contact, 'admin')") public void deletePermission(Contact contact, Sid recipient, Permission permission); I need the EL capability because I have built my own ACL implementation. However, to use this capability with the "#contact" type arguments, the Spring documentation says this: You can access any of the method arguments by name as expression variables, provided your code has debug information compiled in. This begs two questions: It is acceptable to have a production application commercially distributed with debug info in it? If not, is there any way around this? Thanks for any guidance on this!

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