Search Results

Search found 18333 results on 734 pages for 'temporary directory'.

Page 39/734 | < Previous Page | 35 36 37 38 39 40 41 42 43 44 45 46  | Next Page >

  • installing Ubuntu 32 bit and Lubuntu 64 bit with the same home directories

    - by rakesh
    Mine is a 64 bit machine and I had installed "32" bit Ubuntu to try it out and hence installed many apps and developed many things and configured it for many things. Now it seems that my laptop needs more resources as my development needs so much. My question is :to free up install Lubuntu "64" bit in other partition which uses the same home directory and apps and my development rendering my laptop to be faster than before. Is this possible ? Thanks in Advance.

    Read the article

  • How do I force folder view sort order to not ignore special characters?

    - by Jason Hartley
    I have many folders in my home directory that have names that begin with special characters such as _OLD_500GB_HD or !FolderIWantToSeeAtTheTop, but for some reason these folders are sorted according to their first alphanumeric character rather than the leading special character. So how can I force the folder to not ignore the special character, or how else can I make the sort view organize certain folders at the top or bottom of the sort? Thanks.

    Read the article

  • I have a global .gitignore but files aren't being ignored, why?

    - by Michael Durrant
    I have a .gitignore_global in my home directory durrantm.../durrantm$ pwd /home/durrantm durrantm.../durrantm$ ls .git* .gitconfig .gitignore_global The .gitignore_global has: durrantm.../durrantm$ head .gitignore_global # RubyMine # .idea/ # Compiled source # ################### *.dll *.exe # Logs and databases # ###################### but when I git status for a project I still end up getting the .idea files when I start using rubyMine. So my git status still shows this: # modified: .idea/dataSources.xml # modified: .idea/linker.iml # modified: .idea/misc.xml # modified: .idea/workspace.xml I have run git config --global core.excludesfile ~/.gitignore_global bvut it didn't help.

    Read the article

  • My home folder disappeared after using Chroot/debootstrap. Can it be recovered?

    - by Martin
    I was following the instructions from http://wiki.winehq.org/WineOn64bit but stopped after cloning wine. Afterwards I closed the terminal and terminated the process when asked. Ubuntu threw up an error report and when I tried to cd to ~/Downloads it was gone, along with all the other directories. So I tried restarting Ubuntu, whereupon I was greeted with the default desktop and home directory. Can I recover my home folder or has it been deleted?

    Read the article

  • is it possible to have duplicated folders on /home folder new partition as an error?

    - by ranna
    i move my home directory to it's own partition but i end with what it seems to be a duplicated home folders (there are 2 accounts admin and everyones account) i have "admin and everyones" folders and then i have in hide ".ecryptfs" inside i had again "admin and everyones" folder inside there is .encryptfs and .private inside each account cant read it's content as seems encrypted. which of both folders im able to delete the ones inside .encryptfs or the other showing in unhide mode "admin and everyones"? it seems is dulpicated as have the same file size.

    Read the article

  • on SSH login, get message 'Could not chdir to home directory"

    - by joachim
    I am SSHing into a Mac OS X server running Tiger. When I log in I get put in the root directory and shown this message: Could not chdir to home directory : No such file or directory My $HOME variable seems to be empty. I've googled the problem and found a mailing list thread which suggests using dscl to set up the home directory, but I've done that and the problem still persists even though now dscl correctly reports: $ dscl . -read /users/me NFSHomeDirectory NFSHomeDirectory: /Users/me

    Read the article

  • Specifying an additional Applications directory on Mac OS X

    - by 341008
    Is there any way I can specify an additional Applications directory. I basically want to keep the applications that come with Mac OS X in the default Applications directory, but, install all third-party software to a different directory which is in a separate partition. I want to retain all advantages of the actual Applications directory such as the one where copying files from a .dmg to the Applications folder installs software.

    Read the article

  • Sync local directory with remote FTPS?

    - by A T
    How do I keep my local directory in sync with my remote FTPS directory? Note that I've tried WinSCP, but found that it only works a few times then I need to restart it to get it going again. Also I've tried all the utilities mentioned here but only a few supported the connection requirements (explicit SSL over FTP), and those that did didn't have "realtime" directory sync. Also note that a curl, rsync or wput command which I can put into "scheduled tasks" will suffice, if it can do directory sync.

    Read the article

  • What's the correct SELinux type for a directory?

    - by unthar
    If I create a new filesystem/directory off of / and I set the Linux permissions to 770 I expect the group to be able to read and write files in that directory. SELinux was preventing me from doing this until I changed the SELinux type on that directory to public_content_rw_t. If this is just a directory in which users in that group will share files is this an acceptable SELinux type or should I be using another one? Writing a custom policy seems like overkill for these purposes. Thanks

    Read the article

  • How to access the relative directory of a ASP.NET website?

    - by Michael Schilling
    I need to access a folder that will contain various text files for my web site. I'm using Visual Web Developer 2010 Express. I made a web site using visual basic. Here is the failing code: Dim fileName As String fileName = CurDir.ToString + fileName.Text + ".txt" FileOpen(1, fileName, OpenMode.Output) FileClose(1) CurDir.ToString is giving me strange directory path that isn't anywhere near where my website files are located. I need to be able to access the files in a folder inside of the WebSite1 folder without using C:\Users\..., but I'm at a loss on how to do that. Can anyone help me out?

    Read the article

  • Can a user be a member of multiple Organization Units (OU) in Active Directory ?

    - by Stormshadow
    Can a user be a member of multiple Organization Units (OU) in Active Directory ? Also, is there a standard format mentioned by Microsoft on how an OU should be created and what its attributes are ? I found this in Wikipedia "However, Organizational Units are just an abstraction for the administrator, and do not function as true containers; the underlying domain operates as if objects were all created in a simple flat-file structure, without any OUs. It is not possible for example to create two user accounts with an identical username in two separate OUs, such as "fred.staff-ou.domain" and "fred.student-ou.domain"."

    Read the article

  • IIS Not Accepting Active Directory Login Credentials

    - by Dale Jay
    I have an ASP.NET web form using Microsoft's boilerplate Active Directory login page, set up exactly as suggested. Windows Authentication is activated on the "Default Website" and "MyWebsite" levels, and Domain\This.User is given "Allow" access to the site. After entering the valid credentials for This.User on the web form, a popup window appears asking me to enter my credentials yet again. Despite entering valid credentials for This.User (after attempting Domain\This.User and This.User formats), it rejects the credentials and returns an unauthorized security headers page (error 401.2). Active Directory user This.User is valid, the IP address of the AD server has been verified and SPN's have been set up for the server. Error Code: 0x80070005 Default Web Site security config: <system.web> <identity impersonate="true" /> <authentication mode="Windows" /> <customErrors mode="Off" /> <compilation debug="true" /> </system.web> Sub web site security <authentication mode="Windows"> <forms loginUrl="~/logon.aspx" timeout="2880" /> </authentication> <authorization> <deny users="?" /> <allow users="*" /> </authorization>

    Read the article

  • IIS - HTTP Redirect all requests for one virtual directory to another

    - by nekno
    How do I set up an HTTP Redirect rule to redirect all requests for a virtual directory to another virtual directory, when I don't know the hostname or complete URL, and cannot use the URL Rewrite module? The following redirects should work: http://host1/app/oldvdir -> http://host1/app/newvdir http://host1/app/oldvdir/ -> http://host1/app/newvdir/ http://host1/app/oldvdir/login.aspx -> http://host1/app/newvdir/login.aspx http://host2/app/oldvdir/login.aspx -> http://host2/app/newvdir/login.aspx I would like to place the redirect rule in the app's root web.config. I have attempted the following rules, but the end result is simply that the redirected vdir gets duplicated on the end of the original vdir until reaching the max URL length, e.g., http://host/oldvdir/login.aspx -> http://host/oldvdir/newvdir/newvdir/newvdir/... Rules in root web.config (I also have tried all sorts of combinations of settings with and without leading and trailing slashes, etc): <location path="oldvdir"> <system.webServer> <httpRedirect enabled="true" exactDestination="false" httpResponseStatus="Permanent"> <add wildcard="*/oldvdir/*" destination="/newvdir/"/> </httpRedirect> </system.webServer> </location> <location path="oldvdir/"> <system.webServer> <httpRedirect enabled="true" exactDestination="false" destination="/newvdir" httpResponseStatus="Permanent"/> </system.webServer> </location>

    Read the article

  • Best way to let users choose country/language when submiting an URL to a directory

    - by Claudiu
    Hi all, I want to offer the user the possibility to add the country/language for websites they would submit to a fairly simple website directory. I have a folder with flags from http://www.famfamfam.com/lab/icons/flags/ . The flag images are named according to the ISO 3166-1 alpha-2 country codes, meaning that I could make a PHP script that would be able to retrieve images and the name of the country retrieved from the image name (not the full name, but it wouldn't be necessary). Just to make things clearer, I couldn't find a proper combo-box jQuery plugin for my needs (that would act exactly like the native but with an icon before the text) and don't really have the time to develop one on my own. Considering the number of images, I also wouldn't just display them all with a radio box near them. Also, having a classic drop-down list would be a nightmare for me as I would have to assign the short country name manually to each entry, or do it once for every country. Offering the user a dropdown list with the short country names but no flag near them would also be unfriendly and confusing. The idea is that every website featured in the directory would have the country flag icon near it. I have the images named properly but I don't know how to let the user choose the right image for their website. Any idees? Thank you all in advance! EDIT Temporary solution is this file: http://www.andrewpatton.com/countrylist.csv It contains a list of countries including various other info, like the short country name, the same name that's used for the flag images. I can take that information and have a classic like this: <select name="countries"> <option value="ro">Romania</option> <option value="ie">Ireland</option> <!-- and so on --> </select> Still, If anybody has a better idea...

    Read the article

  • Best way to let users choose country/language when submiting an URL to a directory

    - by Claudiu
    I want to offer the user the possibility to add the country/language for websites they would submit to a fairly simple website directory. I have a folder with flags from http://www.famfamfam.com/lab/icons/flags/ . The flag images are named according to the ISO 3166-1 alpha-2 country codes, meaning that I could make a PHP script that would be able to retrieve images and the name of the country retrieved from the image name (not the full name, but it wouldn't be necessary). Just to make things clearer, I couldn't find a proper combo-box jQuery plugin for my needs (that would act exactly like the native but with an icon before the text) and don't really have the time to develop one on my own. Considering the number of images, I also wouldn't just display them all with a radio box near them. Also, having a classic drop-down list would be a nightmare for me as I would have to assign the short country name manually to each entry, or do it once for every country. Offering the user a dropdown list with the short country names but no flag near them would also be unfriendly and confusing. The idea is that every website featured in the directory would have the country flag icon near it. I have the images named properly but I don't know how to let the user choose the right image for their website. Any idees? Thank you all in advance! EDIT Temporary solution is this file: http://www.andrewpatton.com/countrylist.csv It contains a list of countries including various other info, like the short country name, the same name that's used for the flag images. I can take that information and have a classic like this: <select name="countries"> <option value="ro">Romania</option> <option value="ie">Ireland</option> <!-- and so on --> </select> Still, If anybody has a better idea...

    Read the article

  • mod_rewrite works within directory not on root

    - by Anvesh Saxena
    I am having problem in my RewriteRule for the tags portion. What I am able to debug is that the rule is been triggered at least because the page "tags.php" is been rendered but without the URL parameters. This .htaccess file with the rules is within root for my sub-domain and has following content for tags postion. # Rewrite rule for tags RewriteRule ^tags/(\w+)/(\d+)/?$ tags.php?tag_name=$1&tag_id=$2 RewriteRule ^tags/(\w+)/?$ tags.php?tag_name=$1 RewriteRule ^tags/?$ tags.php?tag_name= Another problem that I ain't able to debug is that the similar .htaccess file exists for a directory within my sub domain and is working as expected with the necessary URL parameters also been available. The .htaccess file within the directory reads as follows # Rewrite rule for tags RewriteRule ^tags/(\w+)/(\d+)/?$ restAPI.php?type=tags&tag_name=$1&tag_id=$2 RewriteRule ^tags/(\w+)/?$ restAPI.php?type=tags&tag_name=$1 RewriteRule ^tags/?$ restAPI.php?type=tags&tag_name= Could anyone point me the problem that I might be having in my Rewrite rules, I am also facing Internal server error sometimes which I am second guessing is due to the linked problem. Note:- I have Apache version 2.2.23 on my shared hosting.

    Read the article

  • Sun2Oracle: Upgrading from DSEE to the next generation Oracle Unified Directory

    - by Darin Pendergraft
    Mark your calendars and register to join this webcast featuring Steve Giovanetti from Hub City Media, Albert Wu from UCLA and our own Scott Bonnell as they discuss a directory upgrade project from Sun DSEE to Oracle Unified Directory. Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} Date: Thursday, September 13, 2012 Time: 10:00 AM Pacific Join us for this webcast and you will: Learn from one customer that has successfully upgraded to the new platform See what technology and business drivers influenced the upgrade Hear about the benefits of OUD’s elastic scalability and unparalleled performance Get additional information and resources for planning an upgrade Register Now!

    Read the article

  • Installing packages into local directory?

    - by Gili
    I'd like to install software packages, similar to apt-get install <foo> but: Without sudo, and Into a local directory The purpose of this exercise is to isolate independent builds in my continuous integration server. I don't mind compiling from source, if that's what it takes, but obviously I'd prefer the simplest approach possible. I tried apt-get source --compile <foo> as mentioned here but I can't get it working for packages like autoconf. I get the following error: dpkg-checkbuilddeps: Unmet build dependencies: help2man I've got help2man compiled in a local directory, but I don't know how to inform apt-get of that. Any ideas? UPDATE: I found an answer that almost works at http://askubuntu.com/a/350/23678. The problem with chroot is that it requires sudo. The problem with apt-get source is that I don't know how to resolve dependencies. I must say, chroot looks very appealing. Is there an equivalent command that doesn't require sudo?

    Read the article

  • Recursive Perl detail need help

    - by Catarrunas
    Hi everybody, i think this is a simple problem, but i'm stuck with it for some time now! I need a fresh pair of eyes on this. The thing is i have this code in perl: #!c:/Perl/bin/perl use CGI qw/param/; use URI::Escape; print "Content-type: text/html\n\n"; my $directory = param ('directory'); $directory = uri_unescape ($directory); my @contents; readDir($directory); foreach (@contents) { print "$_\n"; } #------------------------------------------------------------------------ sub readDir(){ my $dir = shift; opendir(DIR, $dir) or die $!; while (my $file = readdir(DIR)) { next if ($file =~ m/^\./); if(-d $dir.$file) { #print $dir.$file. " ----- DIR\n"; readDir($dir.$file); } push @contents, ($dir . $file); } closedir(DIR); } I've tried to make it recursive. I need to have all the files of all of the directories and subdirectories, with the full path, so that i can open the files in the future. But my output only returns the files in the current directory and the files in the first directory that it finds. If i have 3 folders inside the directory it only shows the first one. Ex. of cmd call: "perl readDir.pl directory=C:/PerlTest/" Thanks

    Read the article

  • Active Directory Membership Provider - how to expand on this?

    - by Jaxidian
    I'm working on getting an MVC app up and running via AD Membership Provider and I'm having some issues figuring this out. I have a base configuration setup and working when I login as [email protected] + password. <connectionStrings> <add name="MyConnString" connectionString="LDAP://domaincontroller/OU=Product Users,DC=my,DC=domain,DC=com" /> </connectionStrings> <membership defaultProvider="MyProvider"> <providers> <clear /> <add name="MyProvider" connectionStringName="MyConnString" connectionUsername="my.domain.com\service_account" connectionPassword="biguglypassword" type="System.Web.Security.ActiveDirectoryMembershipProvider, System.Web, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a" /> </providers> </membership> However, I'd LIKE to do some other things and I'm not sure how to go about them. Login without typing the domain (i.e. the "@my.domain.com"). I realize that this could only work if I limit myself to just one domain - that's fine. Organize users in up to N different OUs within a single OU. As you can tell from my current connection string, I'm authenticating users in my Product Users OU. I would LIKE to create OUs for various companies within this OU and put the users into those OUs. How can I authenticate across all of these different OUs? I'm trying to figure out how the Active Directory Membership Provider ties in with the Profile and Role providers. Are there AD versions of those too or am I stuck with SQL, home-grown, or finding something somebody else has coded up? Many thanks!!

    Read the article

  • How can I remove all users in an Active Directory group?

    - by Beavis
    I'm trying to remove all users from an AD group with the following code: private void RemoveStudents() { foreach (DirectoryEntry childDir in rootRefreshDir.Children) { DirectoryEntry groupDE = new DirectoryEntry(childDir.Path); for (int counter = 0; counter < groupDE.Properties["member"].Count; counter++) { groupDE.Properties["member"].Remove(groupDE.Properties["member"][counter]); groupDE.CommitChanges(); groupDE.Close(); } } } The rootRefreshDir is the directory that contains all the AD groups (childDir). What I'm finding here is that this code does not behave correctly. It removes users, but it doesn't do it after the first run. It does "some". Then I run it again, and again, and again - depending on how many users need to be deleted in a group. I'm not sure why it's functioning this way. Can someone help fix this code or provide an alternative method to delete all users in a group? Thanks!

    Read the article

  • Hiding elements based on last closed element jquery script

    - by Jared
    Hi my question is, how can I make this jquery script close all previously opened children when entering a new parent? At the moment it traverses thru all the tree structure fine, but switching from one parent to another does not close the previous children, but rather only the each individual parents elements as a user browses. Here is the jquery I'm using: <script type="text/javascript"> $(document).ready($(function(){ $('#nav>li>ul').hide(); $('.children').hide(); $('#nav>li').mousedown(function(){ // check that the menu is not currently animated if ($('#nav ul:animated').size() == 0) { // create a reference to the active element (this) // so we don't have to keep creating a jQuery object $heading = $(this); // create a reference to visible sibling elements // so we don't have to keep creating a jQuery object $expandedSiblings = $heading.siblings().find('ul:visible'); if ($expandedSiblings.size() > 0) { $expandedSiblings.slideUp(0, function(){ $heading.find('ul').slideDown(0); }); } else { $heading.find('ul').slideDown(0); } } }); $('#nav>li>ul>li').mousedown(function(){ // check that the menu is not currently animated if ($('#nav ul:animated').size() == 0) { // create a reference to the active element (this) // so we don't have to keep creating a jQuery object $heading2 = $(this); // create a reference to visible sibling elements // so we don't have to keep creating a jQuery object $expandedSiblings2 = $heading2.siblings().find('.children:visible'); if ($expandedSiblings2.size() > 0) { $expandedSiblings2.slideUp(0, function(){ $heading2.find('.children').slideDown(0); }); } else { $heading2.find('.children').slideDown(0); } } }); })); </script> and here is my html output <ul id="nav"> <li><a href="#">folder 4</a> <ul><li><a href="#">2001</a> <ul><li class="children"><a href="./directory//folder 4/2001/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder 4/2001/doc2.txt">doc2.txt</a></li> <li class="children"><a href="./directory//folder 4/2001/doc3.txt">doc3.txt</a></li> </ul> </li> <li><a href="#">2002</a> <ul><li class="children"><a href="./directory//folder 4/2002/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder 4/2002/doc2.txt">doc2.txt</a></li> <li class="children"><a href="./directory//folder 4/2002/doc3.txt">doc3.txt</a></li> <li class="children"><a href="./directory//folder 4/2002/doc4.txt">doc4.txt</a></li> </ul> </li> <li><a href="#">2003</a> <ul><li class="children"><a href="./directory//folder 4/2003/Copy of doc1.txt">Copy of doc1.txt</a></li> <li class="children"><a href="./directory//folder 4/2003/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder 4/2003/doc2.txt">doc2.txt</a></li> </ul> </li> <li><a href="#">2004</a> <ul><li class="children"><a href="./directory//folder 4/2004/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder 4/2004/doc2.txt">doc2.txt</a></li> <li class="children"><a href="./directory//folder 4/2004/doc3.txt">doc3.txt</a></li> <li class="children"><a href="./directory//folder 4/2004/doc4.txt">doc4.txt</a></li> </ul> </li> </ul> </li> <li><a href="#">folder1</a> <ul><li><a href="#">2001</a> <ul><li class="children"><a href="./directory//folder1/2001/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder1/2001/doc2.txt">doc2.txt</a></li> <li class="children"><a href="./directory//folder1/2001/doc3.txt">doc3.txt</a></li> </ul> </li> <li><a href="#">2002</a> <ul><li class="children"><a href="./directory//folder1/2002/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder1/2002/doc2.txt">doc2.txt</a></li> <li class="children"><a href="./directory//folder1/2002/doc3.txt">doc3.txt</a></li> <li class="children"><a href="./directory//folder1/2002/doc4.txt">doc4.txt</a></li> </ul> </li> <li><a href="#">2003</a> <ul><li class="children"><a href="./directory//folder1/2003/Copy of doc1.txt">Copy of doc1.txt</a></li> <li class="children"><a href="./directory//folder1/2003/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder1/2003/doc2.txt">doc2.txt</a></li> </ul> </li> <li><a href="#">2004</a> <ul><li class="children"><a href="./directory//folder1/2004/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder1/2004/doc2.txt">doc2.txt</a></li> <li class="children"><a href="./directory//folder1/2004/doc3.txt">doc3.txt</a></li> <li class="children"><a href="./directory//folder1/2004/doc4.txt">doc4.txt</a></li> </ul> </li> </ul> </li> <li><a href="#">folder2</a> <ul><li><a href="#">2001</a> <ul><li class="children"><a href="./directory//folder2/2001/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder2/2001/doc2.txt">doc2.txt</a></li> <li class="children"><a href="./directory//folder2/2001/doc3.txt">doc3.txt</a></li> </ul> </li> <li><a href="#">2002</a> <ul><li class="children"><a href="./directory//folder2/2002/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder2/2002/doc2.txt">doc2.txt</a></li> <li class="children"><a href="./directory//folder2/2002/doc3.txt">doc3.txt</a></li> <li class="children"><a href="./directory//folder2/2002/doc4.txt">doc4.txt</a></li> </ul> </li> <li><a href="#">2003</a> <ul><li class="children"><a href="./directory//folder2/2003/Copy of doc1.txt">Copy of doc1.txt</a></li> <li class="children"><a href="./directory//folder2/2003/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder2/2003/doc2.txt">doc2.txt</a></li> </ul> </li> <li><a href="#">2004</a> <ul><li class="children"><a href="./directory//folder2/2004/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder2/2004/doc2.txt">doc2.txt</a></li> <li class="children"><a href="./directory//folder2/2004/doc3.txt">doc3.txt</a></li> <li class="children"><a href="./directory//folder2/2004/doc4.txt">doc4.txt</a></li> </ul> </li> </ul> </li> <li><a href="#">folder3</a> <ul><li><a href="#">2001</a> <ul><li class="children"><a href="./directory//folder3/2001/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder3/2001/doc2.txt">doc2.txt</a></li> <li class="children"><a href="./directory//folder3/2001/doc3.txt">doc3.txt</a></li> </ul> </li> <li><a href="#">2002</a> <ul><li class="children"><a href="./directory//folder3/2002/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder3/2002/doc2.txt">doc2.txt</a></li> <li class="children"><a href="./directory//folder3/2002/doc3.txt">doc3.txt</a></li> <li class="children"><a href="./directory//folder3/2002/doc4.txt">doc4.txt</a></li> </ul> </li> <li><a href="#">2003</a> <ul><li class="children"><a href="./directory//folder3/2003/Copy of doc1.txt">Copy of doc1.txt</a></li> <li class="children"><a href="./directory//folder3/2003/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder3/2003/doc2.txt">doc2.txt</a></li> </ul> </li> <li><a href="#">2004</a> <ul><li class="children"><a href="./directory//folder3/2004/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder3/2004/doc2.txt">doc2.txt</a></li> <li class="children"><a href="./directory//folder3/2004/doc3.txt">doc3.txt</a></li> <li class="children"><a href="./directory//folder3/2004/doc4.txt">doc4.txt</a></li> </ul> </li> </ul> </li> </ul> I assume my problem is, jquery isn't closing the children between each new parent so I need to make a call, but I'm a bit lost on how to do that. I know the code is pretty messy, this project was done in a huge rush and a very tight timeframe. Appreciate your answers and any other constructive comments, cheers :)

    Read the article

  • Enabling Session Directory under Terminal Server Configuration Tool and Server Settings

    - by LPE
    Yello, I'm trying to add up a Terminal Server Session Directory client to an already fully functional Session Directory cluster which today runs two clients as well as the server. I've been reading up on both Google, Microsoft KB's as well as old documentation from an earlier employee but to no avail. The step I'm stuck at is when I open up Terminal Server Configuration Tool (tscc.msc), chooses ServerSettings. I know there should be an option saying "Session Directory" on the right hand side along with Active Desktop, Licensing and whatnot, but it's not there. I've logged on to both the other already functional clients and checked the same list and there the Session Directory option sure is both visible as well as working good with the specified information. This picture is the same view that I'm looking at at the moment, but mine is missing the bottom option that says "Session Directory" http://www.inetnj.com/doc/images/TerminalServerConfiguration.jpg Any help would be greatly appriciated. Regards LPE

    Read the article

  • Directory Not Found Error

    - by noobguy
    I am trying to verify tails and when I get to the command prompt portion of the verification some difficulties seem to have arose. Below is the script: noob@noob-System-Product-Name:~$ cd [/media/noob/UUI] bash: cd: [/media/noob/UUI]: No such file or directory noob@noob-System-Product-Name:~$ gpg --keyid-format long --import tails-signing.key gpg: can't open `tails-signing.key': No such file or directory gpg: Total number processed: 0 Same thing happens when I try from download directory; noob@noob-System-Product-Name:~$ cd [/home/noob/Downloads] bash: cd: [/home/noob/Downloads]: No such file or directory noob@noob-System-Product-Name:~$ gpg --keyid-format long --import tails-signing.key gpg: can't open `tails-signing.key': No such file or directory gpg: Total number processed: 0 Any suggestions would be greatly appreciated.

    Read the article

  • Jail Linux user to directory for FTP login

    - by Greg
    I'm planning on using vsftpd to act as a secure ftp server, but I am having difficulty controlling the linux users that will be used as ftp logins. The users are required to be "jailed" into a specific directory (and subdirectories) and have full read/write access. Requirements: - User account "admin_ftp" should be jailed to /var/www directory. - Other accounts will be added as needed, for each site... e.g: - User account "picturegallery_ftp" should be jailed to /var/www/picturegallery.com directory. I have tried the following, but to no avail: # Group to store all ftp accounts in. groupadd ftp_accounts # Group for single user, with the same name as the username. groupadd admin_ftp useradd -g admin_ftp -G ftp_accounts admin_ftp chgrp -R ftp_accounts /var/www chmod -R g+w /var/www When I log into FTP using account admin_ftp, I am given the error message: 500 OOPS: cannot change directory:/home/admin_ftp But didn't I specify the home directory? Extra internets for a guide how to do this specifically for vsftpd :)

    Read the article

< Previous Page | 35 36 37 38 39 40 41 42 43 44 45 46  | Next Page >