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  • SQL SERVER – Challenge – Puzzle – Why does RIGHT JOIN Exists

    - by pinaldave
    I had interesting conversation with the attendees of the my SQL Server Performance Tuning course. I was asked if LEFT JOIN can do the same task as RIGHT JOIN by reserving the order of the tables in join, why does RIGHT JOIN exists? The definitions are as following: Left Join – select all the records from the LEFT table and then pick up any matching records from the RIGHT table   Right Join – select all the records from the RIGHT table and then pick up any matching records from the LEFT table Most of us read from LEFT to RIGHT so we are using LEFT join. Do you have any explaination why RIGHT JOIN exists or can you come up with example, where RIGHT JOIN is absolutely required and the task can not be achieved with LEFT JOIN. Other Puzzles: SQL SERVER – Puzzle – Challenge – Error While Converting Money to Decimal SQL SERVER – Challenge – Puzzle – Usage of FAST Hint Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Pinal Dave, SQL, SQL Authority, SQL Puzzle, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • SQL SERVER – SELECT TOP Shortcut in SQL Server Management Studio (SSMS)

    - by pinaldave
    This is tool is pretty old, yet always comes as a handy tip. I had a great trip at TechEd in India. And, during one of my presentations, I was asked if there are any shortcuts to SELECT only TOP 100 records from SSMS. I immediately told him that if he explores the table in SSMS, he can just right click on it and SELECT TOP 1000 records. If he wanted only 100 records, then he could edit that 1000 to 100 by means of going to Options. Go to Options, then hover the mouse over the SQL Server Object Explorer, then proceed to Commands. Afterwards, change the Value for Select Top <n> Audit Records. After narrating the steps, he told me that he was not looking for the right click option; rather he was asking if there is any kind of keyboard shortcut for convenience’s sake. Actually, a keyboard shortcut is also possible. SQL Server Management Studio (SSMS) lets you configure the settings you want using a shortcut. Here is how you can do it. Go to Options, then to Environment. Proceed to Keyboard, and from there, configure your T-SQL with the desired keyword. Now, open SSMS New Query Window, and then click and type in any table name.  After that, just hit the shortcut you just made earlier. Doing this should display TOP 100 records in the Result window. I am sure this trick is quite old, but it is still helpful to many. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, SQL, SQL Add-On, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Mozilla Weave can't sync Firefox. What's wrong?

    - by Mehper C. Palavuzlar
    For the last few days, Mozilla Weave can't sync. Below is the activity log. Any ideas? 2010-05-02 20:47:15 Service.Main WARN Unknown error while downloading metadata record. Aborting sync. 2010-05-02 20:47:15 Service.Main CONFIG Starting backoff, next sync at:Sun May 02 2010 21:16:09 GMT+0300 (GTB Yaz Saati) 2010-05-02 20:47:15 Service.Main DEBUG Exception: aborting sync, remote setup failed No traceback available 2010-05-02 21:16:09 Service.Main DEBUG Idle timer created for sync, will sync after 5 seconds of inactivity. 2010-05-02 21:16:30 Net.Resource DEBUG GET success 200 https://sj-weave03.services.mozilla.com/1.0/mehper/storage/meta/global 2010-05-02 21:16:30 Service.Main DEBUG Weave Version: 1.2.3 Local Storage: 2 Remote Storage: 2 2010-05-02 21:26:50 Net.Resource DEBUG GET success 200 https://sj-weave03.services.mozilla.com/1.0/mehper/info/collections 2010-05-02 21:26:50 Engine.Clients INFO 0 outgoing items pre-reconciliation 2010-05-02 21:26:50 Engine.Clients INFO Records: 0 applied, 0 reconciled, 0 left to fetch 2010-05-02 21:26:50 Engine.Clients DEBUG Total (ms): sync 6, processIncoming 3, uploadOutgoing 0, syncStartup 3, syncFinish 0 2010-05-02 21:26:50 Engine.Bookmarks INFO 0 outgoing items pre-reconciliation 2010-05-02 21:26:50 Engine.Bookmarks INFO Records: 0 applied, 0 reconciled, 0 left to fetch 2010-05-02 21:26:50 Engine.Bookmarks DEBUG Total (ms): sync 13, processIncoming 5, uploadOutgoing 0, syncStartup 3, syncFinish 3 2010-05-02 21:26:50 Engine.Forms INFO 1 outgoing items pre-reconciliation 2010-05-02 21:26:50 Engine.Forms INFO Records: 0 applied, 0 reconciled, 0 left to fetch 2010-05-02 21:26:50 Engine.Forms INFO Uploading all of 1 records 2010-05-02 21:26:50 Collection DEBUG POST Length: 388 2010-05-02 21:27:06 Collection DEBUG POST success 200 https://sj-weave03.services.mozilla.com/1.0/mehper/storage/forms 2010-05-02 21:27:06 Engine.Forms DEBUG Total (ms): sync 15924, processIncoming 3, uploadOutgoing 15918, syncStartup 3, syncFinish 0, createRecord 1 2010-05-02 21:27:06 Engine.History INFO 55 outgoing items pre-reconciliation 2010-05-02 21:27:06 Engine.History INFO Records: 0 applied, 0 reconciled, 0 left to fetch 2010-05-02 21:27:09 Engine.History INFO Uploading all of 55 records 2010-05-02 21:27:09 Collection DEBUG POST Length: 35337 2010-05-02 21:27:32 Collection DEBUG POST success 200 https://sj-weave03.services.mozilla.com/1.0/mehper/storage/history 2010-05-02 21:27:32 Engine.History DEBUG Total (ms): sync 25588, processIncoming 4, uploadOutgoing 25580, syncStartup 3, syncFinish 0, createRecord 2540 2010-05-02 21:27:32 Engine.Passwords INFO 0 outgoing items pre-reconciliation 2010-05-02 21:27:32 Engine.Passwords INFO Records: 0 applied, 0 reconciled, 0 left to fetch 2010-05-02 21:27:32 Engine.Passwords DEBUG Total (ms): sync 8, processIncoming 4, uploadOutgoing 0, syncStartup 4, syncFinish 0 2010-05-02 21:27:32 Engine.Prefs INFO 0 outgoing items pre-reconciliation 2010-05-02 21:27:32 Engine.Prefs INFO Records: 0 applied, 0 reconciled, 0 left to fetch 2010-05-02 21:27:32 Engine.Prefs DEBUG Total (ms): sync 8, processIncoming 3, uploadOutgoing 0, syncStartup 4, syncFinish 0 2010-05-02 21:27:32 Engine.Tabs INFO 1 outgoing items pre-reconciliation 2010-05-02 21:27:32 Engine.Tabs INFO Records: 0 applied, 0 reconciled, 0 left to fetch 2010-05-02 21:27:32 Engine.Tabs INFO Uploading all of 1 records 2010-05-02 21:27:32 Collection DEBUG POST Length: 393 2010-05-02 21:27:54 Collection DEBUG POST success 200 https://sj-weave03.services.mozilla.com/1.0/mehper/storage/tabs 2010-05-02 21:27:54 Engine.Tabs DEBUG Total (ms): sync 21943, processIncoming 3, uploadOutgoing 21936, syncStartup 3, syncFinish 0, createRecord 8 2010-05-02 21:27:54 Service.Main INFO Sync completed successfully 2010-05-02 22:27:53 Service.Main DEBUG Idle timer created for sync, will sync after 5 seconds of inactivity. 2010-05-02 22:28:14 Net.Resource DEBUG GET success 200 https://sj-weave03.services.mozilla.com/1.0/mehper/storage/meta/global 2010-05-02 22:28:14 Service.Main DEBUG Weave Version: 1.2.3 Local Storage: 2 Remote Storage: 2 2010-05-02 22:28:16 Net.Resource DEBUG GET fail 503 https://sj-weave03.services.mozilla.com/1.0/mehper/info/collections 2010-05-02 22:28:16 Service.Main DEBUG Exception: aborting sync, failed to get collections No traceback available 2010-05-02 23:28:15 Service.Main DEBUG Idle timer created for sync, will sync after 5 seconds of inactivity. 2010-05-03 00:26:42 Service.Main DEBUG Exception: Could not acquire lock No traceback available 2010-05-03 00:31:03 RecordMgr DEBUG Failed to import record: App. Quitting JS Stack trace: Res__request(...)@resource.js:208 < Res_get()@resource.js:271 < RecordMgr_import("https://sj-weave03.services.mozilla.com/1.0/mehper/storage/meta/global")@wbo.js:119 < WeaveSvc__remoteSetup()@service.js:824 < ()@service.js:1187 < WrappedNotify()@util.js:114 < WrappedLock()@util.js:86 < WrappedCatch()@util.js:65 < sync(false)@service.js:1146 < ([object Object])@service.js:414 < notify([object XPCWrappedNative_NoHelper])@util.js:629 2010-05-03 00:31:03 Service.Main DEBUG Weave Version: 1.2.3 Local Storage: 2 Remote Storage: 2010-05-03 00:31:03 Service.Main WARN Unknown error while downloading metadata record. Aborting sync. 2010-05-03 00:31:03 Service.Main DEBUG Exception: aborting sync, remote setup failed No traceback available 2010-05-03 17:26:25 Service.Main INFO Loading Weave 1.2.3 2010-05-03 17:26:25 Engine.Bookmarks DEBUG Engine initialized 2010-05-03 17:26:25 Engine.Forms DEBUG Engine initialized 2010-05-03 17:26:25 Engine.History DEBUG Engine initialized 2010-05-03 17:26:25 Engine.Passwords DEBUG Engine initialized 2010-05-03 17:26:25 Engine.Prefs DEBUG Engine initialized 2010-05-03 17:26:25 Engine.Tabs DEBUG Engine initialized 2010-05-03 17:26:25 Engine.Tabs DEBUG Resetting tabs last sync time 2010-05-03 17:26:25 Service.Main INFO Mozilla/5.0 (Windows; U; Windows NT 6.1; tr; rv:1.9.2.3) Gecko/20100401 Firefox/3.6.3 (.NET CLR 3.5.30729) 2010-05-03 17:26:26 Service.Main DEBUG Caching URLs under storage user base: https://sj-weave03.services.mozilla.com/1.0/mehper/ 2010-05-03 17:26:30 Service.Main DEBUG Autoconnecting in 3 seconds 2010-05-03 17:26:36 Service.Main INFO Logging in user mehper 2010-05-03 17:45:46 Service.Main DEBUG Exception: Could not acquire lock No traceback available 2010-05-03 17:53:18 Service.Main DEBUG Exception: Could not acquire lock No traceback available

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  • Django Inline formset for editing multiple related records at once - the right way to go?

    - by Bert
    Hi, When using inline formsets, how does one do paging? I'm using django 1.1. The situation I'm in, is that the user needs to be able to edit the related objects quickly and easily (which is why I think I should be using an inline formset). However, there can be a more than a hundred objects to edit, which makes a pretty large formset, so paging would make sense. Is there a better way to be doing this? Thanks Bert

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  • Simple recursive DNS resolver for debugging (app or VM)

    - by notpeter
    I have an issue which I believe is caused by incorrect DNS queries (doubled subdomains like _record.host.subdomain.tld.subdomain.tld) when querying for SRV records. So I need to an alternate DNS server with heavy logging so I can see every query (especially stupid ones), acting as a recursive resolver with the ability create records which override real DNS records so I can not only find the records it's (wrongly) looking for, but populate those records as well. I know I could install a DNS server on yet another linux box, but I feel like this is the sort of thing that someone may already setup a simple python script or single use vm just for this purpose.

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  • Can't import obj in Python on OS X 10.6.3 Snow Leopard - libiconv.2.dylib?

    - by James
    on OS X 10.6.3 Snow Leopard % python Python 2.6.1 (r261:67515, Feb 11 2010, 00:51:29) [GCC 4.2.1 (Apple Inc. build 5646)] on darwin Type "help", "copyright", "credits" or "license" for more information. import objc Traceback (most recent call last): File "", line 1, in File "/Library/Python/2.6/site-packages/pyobjc_core-2.2-py2.6-macosx-10.6-universal.egg/objc/__init__.py", line 22, in _update() File "/Library/Python/2.6/site-packages/pyobjc_core-2.2-py2.6-macosx-10.6-universal.egg/objc/__init__.py", line 19, in _update import _objc ImportError: dlopen(/Library/Python/2.6/site-packages/pyobjc_core-2.2-py2.6-macosx-10.6-universal.egg/objc/_objc.so, 2): Library not loaded: /opt/local/lib/libiconv.2.dylib Referenced from: /Library/Python/2.6/site-packages/pyobjc_core-2.2-py2.6-macosx-10.6-universal.egg/objc/_objc.so Reason: Incompatible library version: _objc.so requires version 8.0.0 or later, but libiconv.2.dylib provides version 7.0.0 -- what do I need to do?

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  • Performance Enhancement in Full-Text Search Query

    - by Calvin Sun
    Ever since its first release, we are continuing consolidating and developing InnoDB Full-Text Search feature. There is one recent improvement that worth blogging about. It is an effort with MySQL Optimizer team that simplifies some common queries’ Query Plans and dramatically shorted the query time. I will describe the issue, our solution and the end result by some performance numbers to demonstrate our efforts in continuing enhancement the Full-Text Search capability. The Issue: As we had discussed in previous Blogs, InnoDB implements Full-Text index as reversed auxiliary tables. The query once parsed will be reinterpreted into several queries into related auxiliary tables and then results are merged and consolidated to come up with the final result. So at the end of the query, we’ll have all matching records on hand, sorted by their ranking or by their Doc IDs. Unfortunately, MySQL’s optimizer and query processing had been initially designed for MyISAM Full-Text index, and sometimes did not fully utilize the complete result package from InnoDB. Here are a couple examples: Case 1: Query result ordered by Rank with only top N results: mysql> SELECT FTS_DOC_ID, MATCH (title, body) AGAINST ('database') AS SCORE FROM articles ORDER BY score DESC LIMIT 1; In this query, user tries to retrieve a single record with highest ranking. It should have a quick answer once we have all the matching documents on hand, especially if there are ranked. However, before this change, MySQL would almost retrieve rankings for almost every row in the table, sort them and them come with the top rank result. This whole retrieve and sort is quite unnecessary given the InnoDB already have the answer. In a real life case, user could have millions of rows, so in the old scheme, it would retrieve millions of rows' ranking and sort them, even if our FTS already found there are two 3 matched rows. Apparently, the million ranking retrieve is done in vain. In above case, it should just ask for 3 matched rows' ranking, all other rows' ranking are 0. If it want the top ranking, then it can just get the first record from our already sorted result. Case 2: Select Count(*) on matching records: mysql> SELECT COUNT(*) FROM articles WHERE MATCH (title,body) AGAINST ('database' IN NATURAL LANGUAGE MODE); In this case, InnoDB search can find matching rows quickly and will have all matching rows. However, before our change, in the old scheme, every row in the table was requested by MySQL one by one, just to check whether its ranking is larger than 0, and later comes up a count. In fact, there is no need for MySQL to fetch all rows, instead InnoDB already had all the matching records. The only thing need is to call an InnoDB API to retrieve the count The difference can be huge. Following query output shows how big the difference can be: mysql> select count(*) from searchindex_inno where match(si_title, si_text) against ('people')  +----------+ | count(*) | +----------+ | 666877 | +----------+ 1 row in set (16 min 17.37 sec) So the query took almost 16 minutes. Let’s see how long the InnoDB can come up the result. In InnoDB, you can obtain extra diagnostic printout by turning on “innodb_ft_enable_diag_print”, this will print out extra query info: Error log: keynr=2, 'people' NL search Total docs: 10954826 Total words: 0 UNION: Searching: 'people' Processing time: 2 secs: row(s) 666877: error: 10 ft_init() ft_init_ext() keynr=2, 'people' NL search Total docs: 10954826 Total words: 0 UNION: Searching: 'people' Processing time: 3 secs: row(s) 666877: error: 10 Output shows it only took InnoDB only 3 seconds to get the result, while the whole query took 16 minutes to finish. So large amount of time has been wasted on the un-needed row fetching. The Solution: The solution is obvious. MySQL can skip some of its steps, optimize its plan and obtain useful information directly from InnoDB. Some of savings from doing this include: 1) Avoid redundant sorting. Since InnoDB already sorted the result according to ranking. MySQL Query Processing layer does not need to sort to get top matching results. 2) Avoid row by row fetching to get the matching count. InnoDB provides all the matching records. All those not in the result list should all have ranking of 0, and no need to be retrieved. And InnoDB has a count of total matching records on hand. No need to recount. 3) Covered index scan. InnoDB results always contains the matching records' Document ID and their ranking. So if only the Document ID and ranking is needed, there is no need to go to user table to fetch the record itself. 4) Narrow the search result early, reduce the user table access. If the user wants to get top N matching records, we do not need to fetch all matching records from user table. We should be able to first select TOP N matching DOC IDs, and then only fetch corresponding records with these Doc IDs. Performance Results and comparison with MyISAM The result by this change is very obvious. I includes six testing result performed by Alexander Rubin just to demonstrate how fast the InnoDB query now becomes when comparing MyISAM Full-Text Search. These tests are base on the English Wikipedia data of 5.4 Million rows and approximately 16G table. The test was performed on a machine with 1 CPU Dual Core, SSD drive, 8G of RAM and InnoDB_buffer_pool is set to 8 GB. Table 1: SELECT with LIMIT CLAUSE mysql> SELECT si_title, match(si_title, si_text) against('family') as rel FROM si WHERE match(si_title, si_text) against('family') ORDER BY rel desc LIMIT 10; InnoDB MyISAM Times Faster Time for the query 1.63 sec 3 min 26.31 sec 127 You can see for this particular query (retrieve top 10 records), InnoDB Full-Text Search is now approximately 127 times faster than MyISAM. Table 2: SELECT COUNT QUERY mysql>select count(*) from si where match(si_title, si_text) against('family‘); +----------+ | count(*) | +----------+ | 293955 | +----------+ InnoDB MyISAM Times Faster Time for the query 1.35 sec 28 min 59.59 sec 1289 In this particular case, where there are 293k matching results, InnoDB took only 1.35 second to get all of them, while take MyISAM almost half an hour, that is about 1289 times faster!. Table 3: SELECT ID with ORDER BY and LIMIT CLAUSE for selected terms mysql> SELECT <ID>, match(si_title, si_text) against(<TERM>) as rel FROM si_<TB> WHERE match(si_title, si_text) against (<TERM>) ORDER BY rel desc LIMIT 10; Term InnoDB (time to execute) MyISAM(time to execute) Times Faster family 0.5 sec 5.05 sec 10.1 family film 0.95 sec 25.39 sec 26.7 Pizza restaurant orange county California 0.93 sec 32.03 sec 34.4 President united states of America 2.5 sec 36.98 sec 14.8 Table 4: SELECT title and text with ORDER BY and LIMIT CLAUSE for selected terms mysql> SELECT <ID>, si_title, si_text, ... as rel FROM si_<TB> WHERE match(si_title, si_text) against (<TERM>) ORDER BY rel desc LIMIT 10; Term InnoDB (time to execute) MyISAM(time to execute) Times Faster family 0.61 sec 41.65 sec 68.3 family film 1.15 sec 47.17 sec 41.0 Pizza restaurant orange county california 1.03 sec 48.2 sec 46.8 President united states of america 2.49 sec 44.61 sec 17.9 Table 5: SELECT ID with ORDER BY and LIMIT CLAUSE for selected terms mysql> SELECT <ID>, match(si_title, si_text) against(<TERM>) as rel  FROM si_<TB> WHERE match(si_title, si_text) against (<TERM>) ORDER BY rel desc LIMIT 10; Term InnoDB (time to execute) MyISAM(time to execute) Times Faster family 0.5 sec 5.05 sec 10.1 family film 0.95 sec 25.39 sec 26.7 Pizza restaurant orange county califormia 0.93 sec 32.03 sec 34.4 President united states of america 2.5 sec 36.98 sec 14.8 Table 6: SELECT COUNT(*) mysql> SELECT count(*) FROM si_<TB> WHERE match(si_title, si_text) against (<TERM>) LIMIT 10; Term InnoDB (time to execute) MyISAM(time to execute) Times Faster family 0.47 sec 82 sec 174.5 family film 0.83 sec 131 sec 157.8 Pizza restaurant orange county califormia 0.74 sec 106 sec 143.2 President united states of america 1.96 sec 220 sec 112.2  Again, table 3 to table 6 all showing InnoDB consistently outperform MyISAM in these queries by a large margin. It becomes obvious the InnoDB has great advantage over MyISAM in handling large data search. Summary: These results demonstrate the great performance we could achieve by making MySQL optimizer and InnoDB Full-Text Search more tightly coupled. I think there are still many cases that InnoDB’s result info have not been fully taken advantage of, which means we still have great room to improve. And we will continuously explore the area, and get more dramatic results for InnoDB full-text searches. Jimmy Yang, September 29, 2012

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  • ASP.NET 4.0 and the Entity Framework 4 - Part 2: Perform CRUD Operations Using the Entity Framework

    In this article, Vince demonstrates the usage of the Entity Framework 4 to create, read, update, and delete records in the database which was created in Part 1 of this series. After a short introduction, he discusses the various step involved in the modification of the database, creation of a web form, the selection records to load a drop down list, and the adding, updating, deletion and retrieval of records from the database with the help of relevant source code and screen shots.

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  • Sharepoint OLE DB - cannot insert records? "Field not updateable" error

    - by Pandincus
    I need to write a simple C# .NET application to retrieve, update, and insert some data in a Sharepoint list. I am NOT a Sharepoint developer, and I don't have control over our Sharepoint server. I would prefer not to have to develop this in a proper sharepoint development environment simply because I don't want to have to deploy my application on the Sharepoint server -- I'd rather just access data externally. Anyway, I found out that you can access Sharepoint data using OLE DB, and I tried it successfully using some ADO.NET: var db = DatabaseFactory.CreateDatabase(); DataSet ds = new DataSet(); using (var command = db.GetSqlStringCommand("SELECT * FROM List")) { db.LoadDataSet(command, ds, "List"); } The above works. However, when I try to insert: using (var command = db.GetSqlStringCommand("INSERT INTO List ([HeaderName], [Description], [Number]) VALUES ('Blah', 'Blah', 100)")) { db.ExecuteNonQuery(command); } I get this error: Cannot update 'HeaderName'; field not updateable. I did some Googling and apparently you cannot insert data through OLE DB! Does anyone know if there are some possible workarounds? I could try using Sharepoint Web Services, but I tried that initially and was having a heck of a time authenticating. Is that my only option?

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  • Is it possible to "merge" the values of multiple records into a single field without using a stored

    - by j0rd4n
    A co-worker posed this question to me, and I told them, "No, you'll need to write a sproc for that". But I thought I'd give them a chance and put this out to the community. Essentially, they have a table with keys mapping to multiple values. For a report, they want to aggregate on the key and "mash" all of the values into a single field. Here's a visual: --- ------- Key Value --- ------- 1 A 1 B 1 C 2 X 2 Y The result would be as follows: --- ------- Key Value --- ------- 1 A,B,C 2 X,Y They need this in SQLServer 2005. Again, I think they need to write a stored procedure, but if anyone knows a magic out-of-the-box function that does this, I'd be impressed.

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  • SQL Server 2008: Comparing similar records - Need to still display an ID for a record when the JOIN has no matches

    - by aleppke
    I'm writing a SQL Server 2008 report that will compare genetic test results for animals. A genetic test consists of an animalId, a gene and a result. Not all animals will have the same genes tested but I need to be able to display the results side-by-side for a given set of animals and only include the genes that are present for at least one of the selected animals. My TestResult table has the following data in it: animalId gene result 1 a CC 1 b CT 1 d TT 2 a CT 2 b CT 2 c TT 3 a CT 3 b TT 3 c CC 3 d CC 3 e TT I need to generate a result set that looks like the following. Note that Animal 3 is not being displayed (user doesn't want to see its results) and neither are results for Gene "e" since neither Animal 1 nor Animal 2 have a result for that gene: SireID SireResult CalfID CalfResult Gene 1 CC 2 CT a 1 CT 2 CT b 1 NULL 2 TT c 1 TT 2 NULL d But I can only manage to get this: SireID SireResult CalfID CalfResult Gene 1 CC 2 CT a 1 CT 2 CT b NULL NULL 2 TT c 1 TT NULL NULL d This is the query I'm using. SELECT sire.animalId AS 'SireID' ,sire.result AS 'SireResult' ,calf.animalId AS 'CalfID' ,calf.result AS 'CalfResult' ,sire.gene AS 'Gene' FROM (SELECT s.animalId ,s.result ,m1.gene FROM (SELECT [animalId ] ,result ,gene FROM TestResult WHERE animalId IN (1)) s FULL JOIN (SELECT DISTINCT gene FROM TestResult WHERE animalId IN (1, 2)) m1 ON s.marker = m1.marker) sire FULL JOIN (SELECT c.animalId ,c.result ,m2.gene FROM (SELECT animalId ,result ,gene FROM TestResult WHERE animalId IN (2)) c FULL JOIN (SELECT DISTINCT gene FROM TestResult WHERE animalId IN (1, 2)) m2 ON c.gene = m2.gene) calf ON sire.gene = calf.gene How do I get the SireIDs and CalfIDs to display their values when they don't have a record associated with a particular Gene? I was thinking of using COALESCE but I can't figure out how to specify the correct animalId to pass in. Any help would be appreciated.

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  • Find all records in database that are within a certain distance of a set of lat and long points

    - by Mike L
    I've seen all the examples and here's what I got so far. my table is simple: schools (table name) - School_ID - lat - long - county - extrainfo here's my code: <?php $con = mysql_connect("xxx","xxx","xxx"); if (!$con) { die('Could not connect: ' . mysql_error()); } else {} mysql_select_db("xxx", $con); $latitude = "36.265541"; $longitude = "-119.207153"; $distance = "1"; //miles $qry = "SELECT *, (3958.75 * ACOS(SIN(" . $latitude . " / 57.2958)*SIN(lat / 57.2958)+COS(" . $latitude . " / 57.2958)*COS(lat / 57.2958)*COS(long / 57.2958 - " . $longitude . " / 57.2958))) as distance FROM schools WHERE (3958.75 * ACOS(SIN(" . $latitude . " / 57.2958)*SIN(lat / 57.2958)+COS(" . $latitude . " / 57.2958)*COS(lat / 57.2958)*COS(long / 57.2958 - " . $longitude . " / 57.2958))) <= " . $distance; $results = mysql_query($qry); if (mysql_num_rows($results) > 0) { while($row = mysql_fetch_assoc($results)) { print_r($row); } } else {} mysql_close($con); ?> but I get this error when I try to run it: Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource

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  • Criteria API - How to get records based on collection count?

    - by Cosmo
    Hello Guys! I have a Question class in ActiveRecord with following fields: [ActiveRecord("`Question`")] public class Question : ObcykaniDb<Question> { private long id; private IList<Question> relatedQuestions; [PrimaryKey("`Id`")] private long Id { get { return this.id; } set { this.id = value; } } [HasAndBelongsToMany(typeof(Question), ColumnRef = "ChildId", ColumnKey = "ParentId", Table = "RelatedQuestion")] private IList<Question> RelatedQuestions { get { return this.relatedQuestions; } set { this.relatedQuestions = value; } } } How do I write a DetachedCriteria query to get all Questions that have at least 5 related questions (count) in the RelatedQuestions collection? For now this gives me strange results: DetachedCriteria dCriteria = DetachedCriteria.For<Question>() .CreateCriteria("RelatedQuestions") .SetProjection(Projections.Count("Id")) .Add(Restrictions.EqProperty(Projections.Id(), "alias.Id")); DetachedCriteria dc = DetachedCriteria.For<Question>("alias").Add(Subqueries.Le(5, dCriteria)); IList<Question> results = Question.FindAll(dc); Any ideas what I'm doing wrong?

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  • Reconstructing trees from a "fingerprint"

    - by awshepard
    I've done my SO and Google research, and haven't found anyone who has tackled this before, or at least, anyone who has written about it. My question is, given a "universal" tree of arbitrary height, with each node able to have an arbitrary number of branches, is there a way to uniquely (and efficiently) "fingerprint" arbitrary sub-trees starting from the "universal" tree's root, such that given the universal tree and a tree's fingerprint, I can reconstruct the original tree? For instance, I have a "universal" tree (forgive my poor illustrations), representing my universe of possibilities: Root / / / | \ \ ... \ O O O O O O O (Level 1) /|\/|\...................\ (Level 2) etc. I also have tree A, a rooted subtree of my universe Root / /|\ \ O O O O O / Etc. Is there a way to "fingerprint" the tree, so that given that fingerprint, and the universal tree, I could reconstruct A? I'm thinking something along the lines of a hash, a compression, or perhaps a functional/declarative construction? Big-O analysis (in time or space) is a plus. As a for-instance, a nested expression like: {{(Root)},{(1),(2),(3)},{(2,3),(1),(4,5)}...} representing the actual nodes present at each level in the tree is probably valid, but can it be done more efficiently?

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  • how to count all distinct records in many-to-many relations in django ORM?

    - by marduk-pl
    hi, i have two models: class Project(models.Model): categories = models.ManyToManyField(Category) class Category(models.Model): name = models.CharField() now, i make some queryset: query = Project.objects.filter(id__in=[1,2,3,4]) and i like to get list of all distinct categories in this queryset with count of projects with refering to these categories - exactly i would like to get that results: category1 - 10 projects category2 - 5 projects that is opposite to this query: query2 = query.annotate(Count('categories')) what return me: project1 - 2categories project2 - 7categories how can i make it in django ORM?

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  • What's the proper format for an SPF record?

    - by deltanovember
    Querying my domain I get: The TXT records found for your domain are: v=spf1 ip4:50.22.72.198 a mx:wordswithfriends.net ~all So superficially it appears OK. However I also get the following message SPF records should also be published in DNS as type SPF records. No type SPF records found. I want to make sure things are absolutely airtight. So in addition to TXT records I also want a pure SPF record. However I cannot figure out the format. Placing the same text in an SPF record does not seem to work. Edit: At the moment I have a TXT record but not SPF record. When I cut and paste from TXT straight to SPF I get some type of crazy recursive DNS error so quickly deleted the SPF. I just want to know the correct format. Copying v=spf1 ip4:50.22.72.198 a mx:wordswithfriends.net ~all Straight into an SPF record doesn't work.

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  • How can I make an SQL statement that finds unassociated records?

    - by William Calleja
    I have two tables as follows: tblCountry (countryID, countryCode) tblProjectCountry(ProjectID, countryID) The tblCountry table is a list of all countries with their codes and the tblProjectCountry table associates certain countries with certain projects. I need an SQL statement that gives me a list of the countries with their country code that do NOT have an associated record in the tblProjectCountry table. so far I got to here: SELECT tblCountry.countryID, tblCountry.countryCode FROM tblProjectCountry INNER JOIN tblCountry ON tblProjectCountry.countryID = tblCountry.countryID WHERE (SELECT COUNT(ProjectID) FROM tblProjectCountry WHERE (ProjectID = 1) AND (countryID = tblCountry.countryID)) = 0 The above statement parses as correct but doesn't give the exact result I'm looking for. Can anyone help?

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  • checking if records exists in DB, in single step or 2 steps?

    - by Sinan
    Suppose you want to get a record from database which returns a large data and requires multiple joins. So my question would be is it better to use a single query to check if data exists and get the result if it exists. Or do a more simple query to check if data exists then id record exists, query once again to get the result knowing that it exists. Example: 3 tables a, b and ab(junction table) select * from from a, b, ab where condition and condition and condition and condition etc... or select id from a, b ab where condition then if exists do the query above. So I don't know if there is any reason to do the second. Any ideas how this affects DB performance or does it matter at all?

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