Search Results

Search found 26887 results on 1076 pages for 'jquery ui widget factory'.

Page 391/1076 | < Previous Page | 387 388 389 390 391 392 393 394 395 396 397 398  | Next Page >

  • How to copy and paste text from one page to another page using jquery?

    - by ischnura
    I have to copy repeatedly data (contact info such as name, surname, telephone...) from form A (page 1 in domain x.com) to form B (page 2 in domain y.com) I have been thinking about creating a chrome extension with the help of jquery to copy the data from form A, and inject it form B... I have a feeling that this is not the best way to solve this problem... What do you think is the best way to copy and paste data from pages in different domains?

    Read the article

  • How can you use jQuery to make sIFR-replaced elements fade in?

    - by Sam Goldman
    This is what I currently have: // #content is visibility=hidden sIFR.replace(mix_bold, { selector: '#content p', onReplacement: function(fi) { $('#content').fadeIn("slow"); } }); The fade in happens, but for a split second the replaced flash movie appears before being hidden. Has anyone gotten this to work? I am using jQuery 1.2.6 and sIFR 3 r436. Tested in Safari 4 and FF 3. Thanks!

    Read the article

  • How do I simulate a scrollbar click with jQuery?

    - by Ian Davis
    How do I simulate a scrollbar click with jQuery? So, if a user clicks on a div that says "scroll down," it'll be the exact same behavior as if he/she clicked on the down arrow of the browser's scrollbar. Using the current browser's behavior would be optimal, vs. doing something like $.browser.scrolldown(200,'fast'). Something like $.browser.triggerDownArrowOnScrollBar() would be sweet!

    Read the article

  • How can i check if key is pressed during click event with jquery?

    - by daniel smith
    Hi, I would like to catch a click event with jquery and be able to tell if a key was pressed at the same time so i can fork within the callback function based on the keypress. for example: $("button").click(function() { if([KEYPRESSED WHILE CLICKED]) { do something... } else { do something different... } }); Does anyone know if this is possible at all or how it can be done if it is possible?

    Read the article

  • How can call a JQuery function when it in side the from view (asp.net control)?

    - by ricky roy
    Hi, All I have a Span in side the Form view. I wanted to Call a Jquery Fucntion when the from load how can i do this? Thanks Waiting for your reply here is my code <asp:FormView ID="FormView1" runat="server" OnItemCommand="FormView1_ItemCommand"> <ItemTemplate> <asp:HiddenField ID="hidProductID" Value='<%#Eval("ProductID") %>' runat="server" /> <asp:HiddenField ID="hidCustomerID" Value='<%#Eval("CustomerID") %>' runat="server" /> <a href='<%=WinToSave.SettingsConstants.SiteURL%>WintoSave/AuctionProduct.aspx?id=<%#Eval("ProductID") %>'> <%#Eval("ProductName")%> </a> <br /> <img src='<%#Eval("ImagePath")%>' alt="Image No available" /> <br /> <asp:Label ID="lblTime" runat="server" Text='<%#Convert.ToDateTime(Eval("ModifiedOn")).ToString("hh:mm:ss") %>'></asp:Label> <span id='Countdown_<%#Eval("ProductID") %>' onload="GetTimeOnLoad('<%#Eval("ModifiedOn")%>','Countdown_<%#Eval("ProductID") %>');"></span> <br /> <asp:Label ID="lblFinalPrice" runat="server" Text='<%#Convert.ToDouble(Eval("FinalPrice")).ToString("#.00")%>'></asp:Label> <br /> <asp:Label ID="lblFullName" runat="server" Text='<%#Eval("FullName") %>'></asp:Label> <br /> <asp:Button ID="btnAddbid" Text="Bid" CommandName="AddBid" CommandArgument='<%#Eval("ID")%>' runat="server" /> </ItemTemplate> </asp:FormView> and following is my jquery code function GetTimeOnLoad(shortly,DivID) { var dt = new Date(shortly); alert(dt); alert(shortly); alert(DivID); var ProductDivID = "#" +DivID; alert(ProductDivID); $(ProductDivID).countdown({ until: dt, onExpiry: liftOff, onTick: watchCountdown, format: 'HMS', layout: '{hnn}{sep}{mnn}{sep}{snn}' }); } function liftOff(){}; function watchCountdown(){}; In above code I Used ' onload="GetTimeOnLoad('<%#Eval("ModifiedOn")%','Countdown_<%#Eval("ProductID") %');" but is not working

    Read the article

  • How to give user message and choice before ActionLink

    - by RememberME
    I have the following link. On click, I'd like to check the item.primary_company field and if populated, give the user a warning and ask if they would like to continue. How can I do this? <a href="<%= Url.Action("Activate", new {id = item.company_id}) %>" class="fg=button fg-button-icon-solo ui-state-default ui-corner-all"><span class="ui-icon ui-icon-refresh"></span></a>

    Read the article

  • Is it possible to return the "highlighted" (like Firebug) css selector or dom id with jquery?

    - by Jonathan
    Hi Folks, When you click the "Click an element on the page to inspect" arrow with FireBug, it puts a Blue Border around the target element, and also returns the DOM Id. I am building an application and that feature would be awesome to add. Be able to hover over elements and highlight the target, upon clicking return the DOM Id or CSS selector to the application. Is there a jquery plugin that does this magic? Some other smart way? Thanks!, Jonathan

    Read the article

  • Jquery - Loading a page with .load and selector doesn't execute script?

    - by PirateKitten
    I'm trying to load one page into another using the .load() method. This loaded page contains a script that I want to execute when it has finished loading. I've put together a barebones example to demonstrate: Index.html: <html> <head> <title>Jquery Test</title> <script type="text/javascript" src="script/jquery-1.3.2.min.js"></script> <script type="text/javascript"> $(document).ready(function() { $('#nav a').click(function() { $('#contentHolder').load('content.html #toLoad', '', function() {}); return false; }); }); </script> </head> <body> <div id="nav"> <a href="content.html">Click me!</a> </div> <hr /> <div id="contentHolder"> Content loaded will go here </div> </body> </html> Content.html: <div id="toLoad"> This content is from content.html <div id="contentDiv"> This should fade away. </div> <script type="text/javascript"> $('#contentDiv').fadeOut('slow', function() {} ); </script> </div> When the link is clicked, the content should load and the second paragraph should fade away. However it doesn't execute. If I stick a simple alert("") in the script of content.html it doesn't execute either. However, if I do away with the #toLoad selector in the .load() call, it works fine. I am not sure why this is, as the block is clearly in the scope of the #toLoad div. I don't want to avoid using the selector, as in reality the content.html will be a full HTML page, and I'll only want a select part out of it. Any ideas? If the script from content.html was in the .load() callback, it works fine, however I obviously don't want that logic contained within index.html. I could possibly have the callback use .getScript() to load "content.html.js" afterwards and have the logic in there, that seems to work? I'd prefer to keep the script in content.html, if possible, so that it executes fine when loaded normally too. In fact, I might do this anyway, but I would like to know why the above doesn't work.

    Read the article

  • jQuery - How can I temporarily disable the onclick event listener after the event has been fired?

    - by aldux
    How can I temporarily disable the onclick event listener, (jQuery preferred), after the event has been fired? Example: After the user clicks on the button and fires this function below, I want to disabled the onclick listener, therefore not firing the same command to my django view. $(".btnRemove").click(function(){ $(this).attr("src", "/url/to/ajax-loader.gif"); $.ajax({ type: "GET", url: "/url/to/django/view/to/remove/item/" + this.id, dataType: "json", success: function(returned_data){ $.each(returned_data, function(i, item){ // do stuff }); } }); Thanks a lot, Aldo

    Read the article

  • How do they do it? Dialogs over home screen.

    - by Brian515
    Hi all, I'm writing an Android application and I would like to place a dialog or view over the home screen so that a user can enter text without jumping into my full application. I can't seem to get this to work. If I present a dialog (even in a transparent activity), my application launches. If you don't know what I'm talking about, take a look at the Facebook widget. I want to replicate a similar behavior to the clicking on the "What's on your mind?" box. Thanks for any help in advance! -Brian

    Read the article

  • Submiting a Form without Refreshing the page with jQuery and Ajax Not updating MySQL database.

    - by HEEEEEEELP
    I'm a newbie to JQuery and have a problem, when I click submit button on the form everything says registration was successful but my MYSQL database was not updated everything worked fine until I tried to add the JQuery to the picture. Can someone help me fix this problem so my database is updated? Thanks Here is the JQuery code. $(function() { $(".save-button").click(function() { var address = $("#address").val(); var address_two = $("#address_two").val(); var city_town = $("#city_town").val(); var state_province = $("#state_province").val(); var zipcode = $("#zipcode").val(); var country = $("#country").val(); var email = $("#email").val(); var dataString = 'address='+ address + '&address_two=' + address_two + '&city_town=' + city_town + '&state_province=' + state_province + '&zipcode=' + zipcode + '&country=' + country + '$email=' + email; if(address=='' || address_two=='' || city_town=='' || state_province=='' || zipcode=='' || country=='' || email=='') { $('.success').fadeOut(200).hide(); $('.error').fadeOut(200).show(); } else { $.ajax({ type: "POST", url: "http://localhost/New%20Project/home/index.php", data: dataString, success: function(){ $('.success').fadeIn(200).show(); $('.error').fadeOut(200).hide(); } }); } return false; }); }); Here is the PHP code. if (isset($_POST['contact_info_submitted'])) { // Handle the form. // Query member data from the database and ready it for display $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.*, contact_info.* FROM users INNER JOIN contact_info ON contact_info.user_id = users.user_id WHERE users.user_id=3"); $user_id = mysqli_real_escape_string($mysqli, htmlentities('3')); $address = mysqli_real_escape_string($mysqli, htmlentities($_POST['address'])); $address_two = mysqli_real_escape_string($mysqli, htmlentities($_POST['address_two'])); $city_town = mysqli_real_escape_string($mysqli, htmlentities($_POST['city_town'])); $state_province = mysqli_real_escape_string($mysqli, htmlentities($_POST['state_province'])); $zipcode = mysqli_real_escape_string($mysqli, htmlentities($_POST['zipcode'])); $country = mysqli_real_escape_string($mysqli, htmlentities($_POST['country'])); $email = mysqli_real_escape_string($mysqli, strip_tags($_POST['email'])); //If the table is not found add it to the database if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO contact_info (user_id, address, address_two, city_town, state_province, zipcode, country, email) VALUES ('$user_id', '$address', '$address_two', '$city_town', '$state_province', '$zipcode', '$country', '$email')"); } //If the table is in the database update each field when needed if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE contact_info SET address = '$address', address_two = '$address_two', city_town = '$city_town', state_province = '$state_province', zipcode = '$zipcode', country = '$country', email = '$email' WHERE user_id = '$user_id'"); } if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); return; } } Here is the XHTML code. <form method="post" action="index.php"> <fieldset> <ul> <li><label for="address">Address 1: </label><input type="text" name="address" id="address" size="25" class="input-size" value="<?php if (isset($_POST['address'])) { echo $_POST['address']; } else if(!empty($address)) { echo $address; } ?>" /></li> <li><label for="address_two">Address 2: </label><input type="text" name="address_two" id="address_two" size="25" class="input-size" value="<?php if (isset($_POST['address_two'])) { echo $_POST['address_two']; } else if(!empty($address_two)) { echo $address_two; } ?>" /></li> <li><label for="city_town">City/Town: </label><input type="text" name="city_town" id="city_town" size="25" class="input-size" value="<?php if (isset($_POST['city_town'])) { echo $_POST['city_town']; } else if(!empty($city_town)) { echo $city_town; } ?>" /></li> <li><label for="state_province">State/Province: </label> <?php echo '<select name="state_province" id="state_province">' . "\n"; foreach($state_options as $option) { if ($option == $state_province) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="zipcode">Zip/Post Code: </label><input type="text" name="zipcode" id="zipcode" size="5" class="input-size" value="<?php if (isset($_POST['zipcode'])) { echo $_POST['zipcode']; } else if(!empty($zipcode)) { echo $zipcode; } ?>" /></li> <li><label for="country">Country: </label> <?php echo '<select name="country" id="country">' . "\n"; foreach($countries as $option) { if ($option == $country) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else if($option == "-------------") { echo '<option value="' . $option . '" disabled="disabled">' . $option . '</option>'; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="email">Email Address: </label><input type="text" name="email" id="email" size="25" class="input-size" value="<?php if (isset($_POST['email'])) { echo $_POST['email']; } else if(!empty($email)) { echo $email; } ?>" /><br /><span>We don't spam or share your email with third parties. We respect your privacy.</span></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="contact_info_submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form>

    Read the article

  • Jquery AJAX: How to display the Flash error message when validation on the server side fails?

    - by Shripad K
    I am using the Jquery form plugin to submit the form via ajax. I have set up validations on the server side in my models. Now when the validation fails i want to display the same flash[:error] message to the user using ajax. If the validation succeeds I can display the flash[:notice] as it is available after the request is completed. How do i go about displaying flash[:error]?

    Read the article

< Previous Page | 387 388 389 390 391 392 393 394 395 396 397 398  | Next Page >