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  • Modify passed, nested dict/list

    - by Gerenuk
    I was thinking of writing a function to normalize some data. A simple approach is def normalize(l, aggregate=sum, norm_by=operator.truediv): aggregated=aggregate(l) for i in range(len(l)): l[i]=norm_by(l[i], aggregated) l=[1,2,3,4] normalize(l) l -> [0.1, 0.2, 0.3, 0.4] However for nested lists and dicts where I want to normalize over an inner index this doesnt work. I mean I'd like to get l=[[1,100],[2,100],[3,100],[4,100]] normalize(l, ?? ) l -> [[0.1,100],[0.2,100],[0.3,100],[0.4,100]] Any ideas how I could implement such a normalize function? Maybe it would be crazy cool to write normalize(l[...][0]) Is it possible to make this work?? Or any other ideas? Also not only lists but also dict could be nested. Hmm... EDIT: I just found out that numpy offers such a syntax (for lists however). Anyone know how I would implement the ellipsis trick myself?

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  • Calling methods in super class constructor of subclass constructor?

    - by deamon
    Calling methods in super class constructor of subclass constructor? Passing configuration to the __init__ method which calls register implicitely: class Base: def __init__(self, *verbs=("get", "post")): self._register(verbs) def _register(self, *verbs): pass class Sub(Base): def __init__(self): super().__init__("get", "post", "put") Or calling register explicitely in the subclass' __init__ method: class Base: def __init__(self): self._register("get", "post") def _register(self, *verbs): pass class Sub(Base): def __init__(self): _register("get", "post", "put") What is better or more pythonic? Or is it only a matter of taste?

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  • How can I make a dashboard with all pending tasks using Celery?

    - by e-satis
    I want to have some place where I can watch all the pendings tasks. I'm not talking about the registered functions/classes as tasks, but the actual scheduled jobs for which I could display: name, task_id, eta, worker, etc. Using Celery 2.0.2 and djcelery, I found `inspect' in the documentation. I tried: from celery.task.control import inspect def get_scheduled_tasks(nodes=None): if nodes: i = inspect(nodes) else: i = inspect() scheduled_tasks = [] dump = i.scheduled() if dump: for worker, tasks in dump: for task in tasks: scheduled_task = {} scheduled_task.update(task["request"]) del task["request"] scheduled_task.update(task) scheduled_task["worker"] = worker scheduled_tasks.append(scheduled_task) return scheduled_tasks But it hangs forever on dump = i.scheduled(). Strange, because otherwise everything works. Using Ubuntu 10.04, django 1.0 and virtualenv.

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  • What is an efficient way to erase substrings?

    - by Legend
    I have a long string and a set of <end-index, string> list like the following: long_sentence = "This is a long long long long sentence" indices = [[6, "is"], [8, "is a"], [18, "long"], [23, "long"]] An element 6, "is" indicates that 6 is the end index of the word "is" in the string. I want to get the following string in the end: >> print long_sentence This .... long ......... long sentence" I tried an approach like this: temp = long_sentence for i in indices: temp = temp[:int(i[0]) - len(i[1])] + '.'*(len(i[1])+1) + temp[i[0]+1:] While this seems to be working, it is taking exceptionally long time (more than 6 hours on 5000 strings inside a 300 MB file). Is there a way to speed this up?

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  • Interesting task using random numbers only

    - by psihodelia
    Given any number of the random real numbers from the interval [0,1] is there exist any method to construct a floating point number with zero decimal part? Your algorithm can use only random() function calls and no variables or constants. No constants and variables are allowed, no type casting is allowed. You can use for/while, if/else or any other programming language operands.

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  • PyQt - How to connect multiple signals to the same widget

    - by Orchainu
    [ ]All1 [ ]All2 [ ]checkbox1A [ ]checkbox1B [ ]checkbox2A [ ]checkbox2B Based on the chart above, a few things need to happen: The All checkboxes only affect the on/off of the column it resides in, and checks on/off all the checkboxes in that column. All checkboxes work in pairs, so if checkbox1A is on/off, checkbox1B needs to be on/off If an All checkbox is checked on, and then the user proceeds to check off one or more checkbox in the column, the All checkbox should be unchecked, but all the checkboxes that are already checked should remain checked. So really this is more like a chain reaction setup. If checkbox All1 is on, then chieckbox1A and 2A will be on, and because they are on, checkbox1B and 2B are also on, but checkbox All2 remains off. I tried hooking up the signals based on this logic, but only the paired logic works 100%. The All checkbox logic only works 50% of the time, and not accurately, and there's no way for me to turn off the All checkbox without turning all already checked checkboxes off. Really really need help ... T-T Sample code: cbPairKeys = cbPairs.keys() for key in cbPairKeys: cbOne = cbPairs[key][0][0] cbTwo = cbPairs[key][1][0] cbOne.stateChanged.connect(self.syncCB) cbTwo.stateChanged.connect(self.syncCB) def syncCB(self): pairKeys = cbPairs.keys() for keys in pairKeys: cbOne = cbPairs[keys][0][0] cbOneAllCB = cbPairs[keys][0][4] cbTwo = cbPairs[keys][1][0] cbTwoAllCB = cbPairs[keys][1][4] if self.sender() == cbOne: if cbOne.isChecked() or cbTwoAllCB.isChecked(): cbTwo.setChecked(True) else: cbTwo.setChecked(False) else: if cbTwo.isChecked() or cbOneAllCB.isChecked(): cbOne.setChecked(True) else: cbOne.setChecked(False) EDIT Thanks to user Avaris's help and patience, I was able to reduce the code down to something much cleaner and works 100% of the time on the 1st and 2nd desired behavior: #Connect checkbox pairs cbPairKeys = cbPairs.keys() for key in cbPairKeys: cbOne = cbPairs[key][0][0] cbTwo = cbPairs[key][1][0] cbOne.toggled.connect(cbTwo.setChecked) cbTwo.toggled.connect(cbOne.setChecked) #Connect allCB and allRO signals cbsKeys = allCBList.keys() for keys in cbsKeys: for checkbox in allCBList[keys]: keys.toggled.connect(checkbox.setChecked) Only need help on turning off the All checkbox when the user selectively turns off the modular checkboxes now

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  • Django - partially validating form

    - by aeter
    I'm new to Django, trying to process some forms. I have this form for entering information (creating a new ad) in one template: class Ad(models.Model): ... category = models.CharField("Category",max_length=30, choices=CATEGORIES) sub_category = models.CharField("Subcategory",max_length=4, choices=SUBCATEGORIES) location = models.CharField("Location",max_length=30, blank=True) title = models.CharField("Title",max_length=50) ... I validate it with "is_valid()" just fine. Basically for the second validation (another template) I want to validate only against "category" and "sub_category": In another template, I want to use 2 fields from the same form ("category" and "sub_category") for filtering information - and now the "is_valid()" method would not work correctly, cause it validates the entire form, and I need to validate only 2 fields. I have tried with the following: ... if request.method == 'POST': # If a filter for data has been submitted: form = AdForm(request.POST) try: form = form.clean() category = form.category sub_category = form.sub_category latest_ads_list = Ad.objects.filter(category=category) except ValidationError: latest_ads_list = Ad.objects.all().order_by('pub_date') else: latest_ads_list = Ad.objects.all().order_by('pub_date') form = AdForm() ... but it doesn't work. How can I validate only the 2 fields category and sub_category?

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  • problem on strings, tuple strings

    - by suresh
    Write a function, called constrainedMatchPair which takes three arguments: a tuple representing starting points for the first substring, a tuple representing starting points for the second substring, and the length of the first substring. The function should return a tuple of all members (call it n) of the first tuple for which there is an element in the second tuple (call it k) such that n+m+1 = k, where m is the length of the first substring. Complete the definition def constrainedMatchPair(firstMatch,secondMatch,length):

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  • Serving large generated files using Google App Engine?

    - by John Carter
    Hiya, Presently I have a GAE app that does some offline processing (backs up a user's data), and generates a file that's somewhere in the neighbourhood of 10 - 100 MB. I'm not sure of the best way to serve this file to the user. The two options I'm considering are: Adding some code to the offline processing code that 'spoofs' it as a form upload to the blob store, and going thru the normal blobstore process to serve the file. Having the offline processing code store the file somewhere off of GAE, and serving it from there. Is there a much better approach I'm overlooking? I'm guessing this is functionality that isn't well suited to GAE. I had thought of storing in the datastore as db.Text or Dd.Blob but there I encounter the 1 MB limit. Any input would be appreciated,

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  • How do I specify a null relation in SQLAlchemy?

    - by Jesse
    Not sure what the correct title for this question should be. I have the following schema: Matters have a one-many relationship to WorkItems. WorkItems have a one-one (or one-zero) relationship to LineItems. I am trying to create the following relation between Matters and WorkItems Matter.unbilled_work_items = orm.relation(WorkItem, primaryjoin = (Matter.id == WorkItem.matter_id) and (WorkItem.line_item_id == None), foreign_keys = [WorkItem.matter_id, WorkItem.line_item_id], viewonly=True ) This throws: AttributeError: '_Null' object has no attribute 'table' That seems to be saying that the second clause in the primaryjoin returns an object of type _Null, but it seems to be expecting something with a "table" attribute. This seems like it should be pretty straightforward to me, am I missing something obvious?

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  • concatenate multi values in one record without duplication

    - by mikehjun
    I have a dbf table like below which is the result of one to many join from two tables. I want to have unique zone values from one Taxlot id field. table name: input table tid ----- zone 1 ------ A 1 ------ A 1 ------ B 1 ------ C 2 ------ D 2 ------ E 3 ------ C Desirable output table table name: input table tid ----- zone 1 ------ A, B, C 2 ------ D, E 3 ------ C I got some help but couldn't make it to work. inputTbl = r"C:\temp\input.dbf" taxIdZoningDict = {} searchRows = gp.searchcursor(inputTbl) searchRow = searchRows.next() while searchRow: if searchRow.TID in taxIdZoningDict: taxIdZoningDict[searchRow.TID].add(searchRow.ZONE) else: taxIdZoningDict[searchRow.TID] = set() #a set prevents dulpicates! taxIdZoningDict[searchRow.TID].add(searchRow.ZONE) searchRow = searchRows.next() outputTbl = r"C:\temp\output.dbf" gp.CreateTable_management(r"C:\temp", "output.dbf") gp.AddField_management(outputTbl, "TID", "LONG") gp.AddField_management(outputTbl, "ZONES", "TEXT", "", "", "20") tidList = taxIdZoningDict.keys() tidList.sort() #sorts in ascending order insertRows = gp.insertcursor(outputTbl) for tid in tidList: concatString = "" for zone in taxIdZoningDict[tid] concatString = concatString + zone + "," insertRow = insertRows.newrow() insertRow.TID = tid insertRow.ZONES = concatString[:-1] insertRows.insertrow(insertRow) del insertRow del insertRows

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  • Weird callback execution order in Twisted?

    - by SlashV
    Consider the following code: from twisted.internet.defer import Deferred d1 = Deferred() d2 = Deferred() def f1(result): print 'f1', def f2(result): print 'f2', def f3(result): print 'f3', def fd(result): return d2 d1.addCallback(f1) d1.addCallback(fd) d1.addCallback(f3) #/BLOCK==== d2.addCallback(f2) d1.callback(None) #=======BLOCK/ d2.callback(None) This outputs what I would expect: f1 f2 f3 However when I swap the order of the statements in BLOCK to #/BLOCK==== d1.callback(None) d2.addCallback(f2) #=======BLOCK/ i.e. Fire d1 before adding the callback to d2, I get: f1 f3 f2 I don't see why the time of firing of the deferreds should influence the callback execution order. Is this an issue with Twisted or does this make sense in some way?

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  • What is the difference between .get() and .fetch(1)

    - by AutomatedTester
    I have written an app and part of it is uses a URL parser to get certain data in a ReST type manner. So if you put /foo/bar as the path it will find all the bar items and if you put /foo it will return all items below foo So my app has a query like data = Paths.all().filter('path =', self.request.path).get() Which works brilliantly. Now I want to send this to the UI using templates {% for datum in data %} <div class="content"> <h2>{{ datum.title }}</h2> {{ datum.content }} </div> {% endfor %} When I do this I get data is not iterable error. So I updated the Django to {% for datum in data.all %} which now appears to pull more data than I was giving it somehow. It shows all data in the datastore which is not ideal. So I removed the .all from the Django and changed the datastore query to data = Paths.all().filter('path =', self.request.path).fetch(1) which now works as I intended. In the documentation it says The db.get() function fetches an entity from the datastore for a Key (or list of Keys). So my question is why can I iterate over a query when it returns with fetch() but can't with get(). Where has my understanding gone wrong?

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  • How to slice a list of objects in association of the object attributes

    - by gizgok
    I have a list of fixtures.Each fixture has a home club and a away club attribute.I want to slice the list in association of its home club and away club.The sliced list should be of homeclub items and awayclub items. Easier way to implement this is to first slice a list of fixtures.Then make a new list of the corresponding Home Clubs and Away Clubs.I wanted to know if we can do this one step.

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  • better way of handling nested list

    - by laspal
    Hi, I have list my_list = [ [1,2,3,4,5,6], [1,3,4],[34,56,56,56]] for item in my_list: var1,var2,var3,var4,var5,var6 = None if len(item) ==1: var1 = item[0] if len(item) == 2: var1 = item[0] var2 = item[1] if len(item) == 3: var1 = item[0] var2 = item[1] var3 = item[2] if len(item) == 4: var1 = item[0] var2 = item[1] var3 = item[2] var4 = item[3] fun(var1,var2,var3,var4,var5,var6) I have a function def fun(var1, var2 = None, var3 = None, var4 = None, var5=None, var6= None) Depending upon the values in my inner list. I am passing it to function. I hope I made it clear. Thanks

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  • How to select a MenuItem programatically

    - by Shaung
    I am trying to add a global shortcut to a gtk.MenuItem which has a sub menu. Here is my code: import pygtk, gtk import keybinder dlg = gtk.Dialog('menu test') dlg.set_size_request(200, 40) menubar = gtk.MenuBar() menubar.show() menuitem = gtk.MenuItem('foo') menuitem.show() menubar.append(menuitem) mitem = gtk.MenuItem('bar') mitem.show() menu = gtk.Menu() menu.add(mitem) menu.show() menuitem.set_submenu(menu) def show_menu_cb(): menubar.select_item(menuitem) keybinder.bind('<Super>i', show_menu_cb) dlg.vbox.pack_start(menubar) dlg.show() dlg.run() When I press the key menu pops up, I can then select items in the sub menu or press Esc to make it disappear. But after that the menuitem keeps selected and other windows never get input focus again. I have to click on the menuitem twice to get everything back normal.

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  • Model Django Poll

    - by MacPython
    I followed the django tutorial here: http://docs.djangoproject.com/en/dev/intro/tutorial01/ and now I am at creating a poll. The code below works fine until I want to create choices, where for some reason I always get this error message: line 22, in unicode return self.question AttributeError: 'Choice' object has no attribute 'question' Unfortunatley, I dont understand where I made an error. Any help would be greatly appreciated. Thanks for the time! CODE: import datetime from django.db import models class Poll(models.Model): question = models.CharField(max_length=200) pub_date = models.DateTimeField('date published') def __unicode__(self): return self.question def was_published_today(self): return self.pub_date.date() == datetime.date.today() class Choice(models.Model): poll = models.ForeignKey(Poll) choice = models.CharField(max_length=200) votes = models.IntegerField() def __unicode__(self): return self.question

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  • What are the common patterns in web programming?

    - by lankerisms
    I have been trying to write my first big web app (more than one cgi file) and as I kept moving forward with the rough prototype, paralelly trying to predict more tasks, this is the todo that got accumulated (In no particular order). * Validations and input sanitizations * Object versioning (to avoid edit conflicts. I dont want hard locks) * Exception handling * memcache * xss and injection protections * javascript * html * ACLs * phonetics in search, match and find duplicates (for form validation) * Ajaxify!!! (I have snipped off the project specific items.) I know that each todo will be quite tied up to its project and technologies used. What I am wondering though, is if there is a pattern in your todo items as well as the sequence in which you experienced guys have come across them.

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  • Suffix if statement

    - by Aardschok
    I was looking for a way to add a suffix to jointchain in Maya. The jointchain has specific naming so I create a list with the names they need to be. The first chain has "_1" as suffix, result: R_Clavicle_1|R_UpperArm_1|R_UnderArm_1|R_Wrist_1 When I create the second this is the result: R_Clavicle_2|R_UpperArm_1|R_UnderArm_1|R_Wrist_1 The code: DRClavPos = cmds.xform ('DRClavicle', q=True, ws=True, t=True) DRUpArmPos = cmds.xform ('DRUpperArm', q=True, ws=True, t=True) DRUnArmPos = cmds.xform ('DRUnderArm', q=True, ws=True, t=True) DRWristPos = cmds.xform ('DRWrist', q=True, ws=True, t=True), cmds.xform('DRWrist', q=True, os=True, ro=True) suffix = 1 jntsA = cmds.ls(type="joint", long=True) while True: jntname = ["R_Clavicle_"+str(suffix),"R_UpperArm_"+str(suffix),"R_UnderArm_"+str(suffix),"R_Wrist_"+str(suffix)] if jntname not in jntsA: cmds.select (d=True) cmds.joint ( p=(DRClavPos)) cmds.joint ( p=(DRUpArmPos)) cmds.joint ( 'joint1', e=True, zso=True, oj='xyz', radius=0.5, n=jntname[0]) cmds.joint ( p=(DRUnArmPos)) cmds.joint ( 'joint2', e=True, zso=True, oj='xyz', radius=0.5, n=jntname[1]) cmds.joint ( p=(DRWristPos[0])) cmds.joint ( 'joint3', e=True, zso=True, oj='xyz', radius=0.5, n=jntname[2]) cmds.rename ('joint4', jntname[3]) cmds.select ( cl=True) break else: suffix + 1 I tried adding +1 in jntname which resulted in a good second chain but the third chain had "_2" after R_Clavicle_3 The code, in my eyes should work. Can anybody point me in the correct direction :)

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  • How do I use a string as a keyword argument?

    - by Issac Kelly
    Specifically, I'm trying to use a string to arbitrairly filter the ORM. I've tried exec and eval solutions, but I'm running into walls. The code below doesn't work, but it's the best way I know how to explain where I'm trying to go from gblocks.models import Image f = 'image__endswith="jpg"' # Would be scripted in another area, but passed as text <user input> d = Image.objects.filter(f) #for the non-django pythonistas: d = Image.objects.filter(image__endswith="jpg") # would be the non-dynamic equivalent.

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  • get the list and input from one function and run them in different function

    - by rookie
    i have a programm that generate the list and then i ask them to tell me what they want to do from the menu and this is where my problem start i was able to get the input form the user to different function but when i try to use the if else condition it doesn't check, below are my code def menu(x,l): print (x) if x == 1: return make_table(l) if x == 2: y= input("enter a row (as a number) or a column (as an uppercase letter") if y in [ "1",'2','3']: print("Minmum is:",minimum(y,l)) if x== 3: print ('bye') def main(): bad_filename = True l =[] while bad_filename == True: try: filename = input("Enter the filename: ") fp = open(filename, "r") for f_line in fp: f_str=f_line.strip() f_str=f_str.split(',') for unit_str in f_str: unit=float(unit_str) l.append(unit) bad_filename = False except IOError: print("Error: The file was not found: ", filename) #print(l) condition=True while condition==True: print('1- open\n','2- maximum') x=input("Enter the choice") menu(x,l) main() from the bottom function i can get list and i can get the user input and i can get the data and move it in second function but it wont work after that.thank you

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  • How to invert alternate bits of a number

    - by Cupidvogel
    The problem is how to invert alternate bits of a number, starting from the LSB. Currently what I am doing is first doing a count = -1 while n: n >>= 1 count += 1 to first find the position of the leftmost set bit, then running a loop to invert every alternate bit: i = 0 while i <= count: num ^= 1<<i i += 2 Is there a quick hack solution instead of this rather boring loop solution? Of course, the solution can't make any asumption about the size of the integer.

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