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  • Sending an HTTP POST request through the android emulator doesn't work

    - by Sotirios Delimanolis
    I'm running a tomcat servlet on my local machine and an Android emulator with an app that makes a post request to the servlet. The code for the POST is below (without exceptions and the like): String strUrl = "http://10.0.2.2:8080/DeviceDiscoveryServer/server/devices/"; Device device = Device.getUniqueInstance(); urlParameters += URLEncoder.encode("user", "UTF-8") + "=" + URLEncoder.encode(device.getUser(), "UTF-8"); urlParameters += "&" + URLEncoder.encode("port", "UTF-8") + "=" + URLEncoder.encode(new Integer(Device.PORT).toString(), "UTF-8"); urlParameters += "&" + URLEncoder.encode("address", "UTF-8") + "=" + URLEncoder.encode(device.getAddress().getHostAddress(), "UTF-8"); URL url = new URL(strUrl); HttpURLConnection connection = (HttpURLConnection) url.openConnection(); connection.setDoOutput(true); connection.setRequestMethod("POST"); OutputStreamWriter wr = new OutputStreamWriter(connection.getOutputStream()); wr.write(urlParameters); wr.flush(); wr.close(); Whenever this code is executed, the servlet isn't called. However if I change the type of the request to 'GET' and don't write anything to the outputstream, the servlet gets called and everything works fine. Am I just not making the POST correctly or is there some other error?

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  • mod_rewrite failing on uppercase dir

    - by user1855277
    I have a very basic mod_rewrite in a .htaccess file which I'm sure worked last time I looked at it, but now it is doing strange things with the case of the REQUEST_URI. It's intended purpose is to rewrite sub-domains to a given file, passing the subdomain as a php var of bnurl. Here is my code: RewriteCond %{REQUEST_URI}= "RSDEV/location/" [NC] RewriteCond %{HTTP_HOST} . RewriteCond %{HTTP_HOST} !^www\. [NC] RewriteCond %{HTTP_HOST} ^([^.]+)\.mydomain\.co\.uk(:80)? [NC] RewriteRule ^RSDEV/location/$ RSDEV/newmain.php?bnurl=%1&accesstype=new [NC,L] Now, typing joebloggs.mydomain.co.uk/RSDEV/location/ into my web browser comes back with the response "The requested URL /RSDEV/location/ was not found on this server" which is a correct statement because /RSDEV/location/ is not a real directory, but why did it not rewrite to RSDEV/newmain.php?bnurl=joebloggs&accesstype=new as expected? Now, the really strange thing here is that if I enter joebloggs.mydomain.co.uk/rsdev/location/ into my browser (note rsdev is now lowercase), it correctly rewrites as expected. The script newmain.php is in dir RSDEV (uppercase) so if it was going to fail, I would have expected it to fail the other way round with the lowercase rsdev. As you can see, I have [NC] on each line. Is this my mod_rewrite code failing or some other mystical server force keeping me up all night?

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  • c++ float subtraction rounding error

    - by Volkan Ozyilmaz
    I have a float value between 0 and 1. I need to convert it with -120 to 80. To do this, first I multiply with 200 after 120 subtract. When subtract is made I had rounding error. Let's look my example. float val = 0.6050f; val *= 200.f; Now val is 121.0 as I expected. val -= 120.0f; Now val is 0.99999992 I thought maybe I can avoid this problem with multiplication and division. float val = 0.6050f; val *= 200.f; val *= 100.f; val -= 12000.0f; val /= 100.f; But it didn't help. I have still 0.99 on my hand. Is there a solution for it? Edit: After with detailed logging, I understand there is no problem with this part of code. Before my log shows me "0.605", after I had detailed log and I saw "0.60499995946884155273437500000000000000000000000000" the problem is in different place.

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  • Perl Cookie not working

    - by grosseskino
    Hi! I already spent all day looking for an answer for this: I am using Perl with LWP::UserAgent and HTTP::Cookies. My problem is that I can't get past an cookie-base age-check. In Perl I use this code: my $browser = LWP::UserAgent->new; my $resp = $browser->get( $url, 'User-Agent' => 'MySpider/1.0' ); #Cookie Setup my $cookies = HTTP::Cookies->new(); $cookies->set_cookie(1,'age_check', '1','/','.example.com/', 80, ,0,3354512128, 0); $browser->cookie_jar($cookies); The Site is setting the Cookie with JavaScript function saveSplash(domain) { var expDate = new Date(); expDate.setTime(expDate.getTime()+(1*24*3600*1000)); setCookie("age_check", 1, expDate, '/', domain); setCookie("screen_width", getScreenWidth(), expDate, '/', domain); } This is the Cookie saved by my browser: age_check 1 example.com/ 1088 3354512128 30140182 2646218624 30139981 Any idea what I am doing wrong? Thanks in advance guys!

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  • Receiving UDP on different Android phones gives different results

    - by user1868982
    I am willing to create a server and client program on my android mobile devices. The devices communicate with each other on the same wifi network, therefore, some simple scanning mechanism must be implemented - The client phones search for a server phone through some kind of broadcast. What I did: My protocol - the client phone broadcasts a message port p on the wifi, the server listens on port p. when the server gets the broadcast message it sends a message back, therefore discovering itself to the client. My code - I have opened a broadcast socket on my app, it sends a broadcast message. Meanwhile there is a python script on my PC that listens and replies - I use python so that my testing will be easier - Wireshark on the PC and I can see everything. What happens: When I use one of my Galaxy S phones - it works and I get a response. When I use the other Galaxy S phone - it doesn't work. Now this is what I know: The phone that works actually has Nexus ROM on it Ver. 4.1.1 The phone that doesn't work has 2.3.3 regular galaxy ROM The python code says it receives both of the broadcasts sent from both phones, and replies to both of them without raising any exception. So far I was thought the problem may be 1. the older version'd phone. 2. the windows firewall 3. the router firewall So I have opened Wireshark, and Indeed I saw that both phones are sending their broadcasts - it was logged on Wireshark. But the python script only responded to the first one. So this is why 1 & 3 are irrelevant - if the router firewall was blocking my UDP I would have still seen the python server response, same with the older versioned phone. To get rid of 2 i just disabled the windows firewall - still same problem. Does anyone has a clue to why this effect might happen? Thanks!

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  • Combining two exe files

    - by Sophia
    Here's some background to my problem: I have a project in Visual C++ 2006 and a project in in Visual C++ 2010 Express. Both compiles to form an exe file each. I cannot convert my 2006 project to 2010 because I get a lot of "unable to load project" errors. I also cannot port my 2010 project code to 2006 (I always get errors no matter what I try, something to do with libraries). My final solution requires me to only have ONE executable. Is there anything I can do to achieve that? I've done some quick search on Google and found there to be exe joiners, but I've also heard that those things are often used to make malware. For reference, I am working with "dummy" clients, and therefore want to simplify things on their end as much as possible. Thus, having them executing one exe is better than having them execute two. Also, I do not wish for their antivirus to go haywire because I used some program to join two exe together. What do? Edit: The two project files do different things. For example, the project in VS2006 one sets up a server, and the project in VS2010 one grabs info on the user's OS. The code for the "server", I think, has a lot of dependencies and for some reason cannot convert to Visual c++ 2010. The code for "grabbing" requires some newer libraries and compiling options, and would not work if I port to 2006.

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  • How to calculate the y-pixels of someones weight on a graph? (math+programming question)

    - by RexOnRoids
    I'm not that smart like some of you geniuses. I need some help from a math whiz. My app draws a graph of the users weight over time. I need a surefire way to always get the right pixel position to draw the weight point at for a given weight. For example, say I want to plot the weight 80.0(kg) on the graph when the range of weights is 80.0 to 40.0kg. I want to be able to plug in the weight (given I know the highest and lowest weights in the range also) and get the pixel result 400(y) (for the top of the graph). The graph is 300 pixels high (starts at 100 and ends at 400). The highest weight 80kg would be plot at 400 while the lowest weight 40kg would be plot at 100. And the intermediate weights should be plotted appropriately. I tried this but it does not work: -(float)weightToPixel:(float)theWeight { float graphMaxY = 400; //The TOP of the graph float graphMinY = 100; //The BOTTOM of the graph float yOffset = 100; //Graph itself is offset 100 pixels in the Y direction float coordDiff = graphMaxY-graphMinY; //The size in pixels of the graph float weightDiff = self.highestWeight-self.lowestWeight; //The weight gap float pixelIncrement = coordDiff/weightDiff; float weightY = (theWeight*pixelIncrement)-(coordDiff-yOffset); //The return value return weightYpixel; }

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  • Website hosting from home - IIS6 [closed]

    - by Paul
    I'm wanting to host a few websites from home, primarily because I'm using some BETA Microsoft software (.NET 4 and EF) and don't want to install it on my production server which is hosted at eukhost.com. Basically, I'm completely new to this sort of thing. So far, here is what I've done: Registered the domain name at namecheap.com (let's call it mydomain.com) Gone to "Nameserver Registration" in the panel and entered my IP address for the NS1 and NS2 records (let's say the IP is 0.0.0.0). Gone to "Domain Name Server Setup" and entered ns1.mydomain.com & ns2.mydomain.com Forwarded requests from port 80 to my internal IP (let's say 192.168.1.254) Created the website in IIS (I'm just testing with a single website so far, so have not created any host header values) Now, if I type in the IP address (http://0.0.0.0) I get the site as expected. However, if I enter http://www.mydomain.com I get an error saying "DNS Error - Cannot find server". I'm aware that there is a service from DynDNS that will automatically change the IP if I have a dynamic address, however my IP has remained static since I installed the ISP (since October) so I don't need this. Is there any way that I can get the DNS to work just by configuring IIS or something in Windows? I don't really want to have to pay for any 3rd party service. Thanks,

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  • On load rather than on click

    - by connor
    I have the following code: jQuery(function ($) { var OSX = { container: null, init: function () { $("input.apply, a.apply").click(function (e) { e.preventDefault(); $("#osx-modal-content").modal({ overlayId: 'osx-overlay', containerId: 'osx-container', closeHTML: null, minHeight: 80, opacity: 65, position: ['0',], overlayClose: true, onOpen: OSX.open, onClose: OSX.close }); }); }, open: function (d) { var self = this; self.container = d.container[0]; d.overlay.fadeIn('fast', function () { $("#osx-modal-content", self.container).show(); var title = $("#osx-modal-title", self.container); title.show(); d.container.slideDown('fast', function () { setTimeout(function () { var h = $("#osx-modal-data", self.container).height() + title.height() + 20; // padding d.container.animate( {height: h}, 200, function () { $("div.close", self.container).show(); $("#osx-modal-data", self.container).show(); } ); }, 300); }); }) }, close: function (d) { var self = this; // this = SimpleModal object d.container.animate( {top:"-" + (d.container.height() + 20)}, 500, function () { self.close(); // or $.modal.close(); } ); } }; OSX.init(); }); To load this script, a button with the class "apply" has to be clicked... Does anyone know a way of loading this script "onload" without a button being clicked? I have tried a lot of things, but I am a newbie when it comes to Javascript. Thanks!

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  • PHP Mail() not working on remote server

    - by Amaerth
    I am developing an application and have been testing the mail() function in PHP. The following works just fine on my local machine to send emails to myself, but as soon as I try to send it from the testing environment to my local machine, it silently fails. I will still get the "Mail Sent" message, but no message is sent. I turned on the mail logging in the php.ini file, but even that doesn't seem to be populated after I refresh the page. Again, the .php files and php.ini files are identical in both environments. Port 25 has been opened on the testing environment, and we are using a Microsoft Exchange server. <?php $to = "[email protected]"; $subject = "Test mail"; $message = "Hello! This is a simple email message."; $from = "[email protected]"; $headers = "From:" . $from; mail($to,$subject,$message,$headers); echo "Mail Sent."; ?> SMTP area of the php.ini file: [mail function] ; For Win32 only. ; http://php.net/smtp SMTP = exhange.server.org ; http://php.net/smtp-port smtp_port = 25 ; For Win32 only. ; http://php.net/sendmail-from sendmail_from = [email protected]

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  • QTime or QTimer wait for timeout

    - by user968243
    I'm writting a Qt application, and I have a four hour loop (in a seperate thread). In that four hour loop, I have to: do stuff with the serial port; wait a fixed period of time; do some more stuff with the serial port; wait an arbitrary amount of time. when 500ms have past, do more stuff; Go to 1. and repeat for four hours. Currently, my method of doing this is really bad, and crashes some computers. I have a whole bunch of code, but the following snippet basically shows the problem. The CPU goes to ~100% and eventually can crash the computer. void CRelayduinoUserControl::wait(int timeMS) { int curTime = loopTimer->elapsed(); while(loopTimer->elapsed() < curTime + timeMS); } I need to somehow wait for a particular amount of time to pass before continuing on with the program. Is there some function which will just wait for some arbitrary period of time while keeping all the timers going?

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  • php png image transparency

    - by user1334130
    I have been working with some code to draw a circle but I am having problems with removing the black background from the shape. I am using imagecopyresampled for its AA features in order to draw a smooth circle, so I can't use a different drawing function. Thanks. <?php $img_2 = imagecreatetruecolor(200, 200); $red = imagecolorallocate($img_2, 255, 0, 0); imagefill($img_2, 0, 0, $red); //set circle values $xPos = 50; $yPos = 80; $diameter = 40; $img_1 = imagecreatetruecolor(($diameter + 2) * 2, ($diameter + 2) * 2); $green = imagecolorallocate($img_1, 0, 255, 0); //draw the circle imagefilledarc($img_1, $diameter+1, $diameter+1, ($diameter + 2) * 2, ($diameter + 2) * 2, 0, 360, $green, IMG_ARC_PIE); imagecopyresampled($img_2, $img_1, $xPos, $yPos, 0, 0, $diameter+2, $diameter+2, ($diameter + 2) * 2, ($diameter + 2) * 2); header("Content-type: image/png"); imagepng($img_2); imagedestroy($img_1); imagedestroy($img_2); ?>

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  • Expressjs route param as variable in main app

    - by MoDFoX
    For my app I have two route set up, app.get('/', routes.index); app.get('/:name', routes.index); I would like it to be so that if I don't specify a param, say just go to appurl.com (localhost:3000), it would load a default user, but if I do specify a param(localhost:3000/user), use that as the variable "username" in the following function (placed after my routes). (function getUser(){ var body = '', username = 'WillsonSM', options = { host: 'ws.audioscrobbler.com', port: 80, path: '/2.0/?method=user.gettopartists&user=' + username + '&format=json&limit=20&api_key=APIKEYGOESHERE' }; require('http').request(options, function(res) { res.setEncoding('utf8'); res.on('data', function(chunk) { body += chunk; }); res.on('end', function() { body = JSON.parse(body); artists = body.topartists.artist; }); }).end(); })(); Along with this I have my route set up like so: exports.index = function(req, res){ res.render('index', { title: 'LasTube' }); username = req.params.name; console.log(username); }; unfortunately setting username there to req.params.name does not seem to be accessible from the main app function. My question is: How can I set expressjs/nodejs to use the parameter set via /name when available, and just use a default - in this example "WillsonSM" if not available. I've tried taking "username" out of the main app, and just leaving it in the function, but username becomes undefined, as it is inaccessible from the route, and the app will not run. I can spit out "username" via the routes console.log, so assigning it there is not an issue, but as I am new to expressjs, I am unaware of how I should go about doing this. I have tried all I can think of and find from looking around the internet. Also, if there is a better way of doing this, or I am doing something wrong, please let me know. If I've left out any information, just throw in a comment and I'll try to address it.

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  • Cannot see echo message but my localhost works

    - by Sean
    This is my very first php code and I can't seem to get it to work. (I'm using Eclipse) <html> <body> <?php echo 'Hello World!'; $txt = "I <3 you!"; $num = 19; ?> </html> </body> When I run it (http://localhost/Assignment3.0/index.php), I get: Not Found The requested URL /Assignment3.0/index.php was not found on this server. Apache/2.2.22 (Ubuntu) Server at localhost Port 80 But when I run this (http://localhost/), I get: It works! This is the default web page for this server. The web server software is running but no content has been added, yet. So what could be the problem? Where's my "Hello World!"? Also, for Stackoverflow formatting, how do I start a new line w/o adding a blank line in between?

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  • how to get something to display only once in a while loop

    - by Matt Nathanson
    I've got a mysql query running and it checks to see if an iterator is equal to 1, then display this div title... if ($this->dliterator == 1) {echo "<div class='clientsection' id='downloads'>Downloads</div><br/>";}; The problem is, is that the dl iterator may not necessarily start at 1. (it is directly related to a downloadid from the database). How can I get this to display only for the first time through the loop ONLY? while ($row = mysql_fetch_assoc($result)) { if ($row['download'] != null){ if ($this->dliterator == 1) {echo "<div class='clientsection' id='downloads'>Downloads</div><br/>";}; if ($editDownload == 1) { echo "<div class='clientlink' style='margin-top: 15px;'>"; echo "<input name='downloads[$this->dliterator][name]' type='text' id='download$this->dliterator' value='" . $row['download'] . "'/>"; echo "<input name='downloads[$this->dliterator][title]' type='text' id='downloadtitle$this->dliterator' value='" . $row['downloadtitle'] . "'/>"; echo "<img class='removelink' src='/images/deletelink.png' width='15' />"; echo "<input id='downloadid' name='downloads[$this->dliterator][id]' type='hidden' value='".$row['downloadid']."' style='display: none'/>"; echo "<br/><img id='uploaddownload$uploaditerator' class='uploaddownload' src='../images/upload.png' width='80'/>"; echo "</div>"; }; }; $this->dliterator++; $uploaditerator++; };

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  • object-oriented question

    - by user522962
    I am attempting to put all my database connections in 1 php file, rather than in each of my individual php pages. I have the following: //conn.php: <?php class conn { var $username = "name"; var $password = "password"; var $server = "localhost"; var $port = "3306"; var $databasename = "db"; var $tablename = "tablename"; var $connection; public function getConnected() { $this->connection = mysqli_connect( $this->server, $this->username, $this->password, $this->databasename, $this->port ); } } ?> // file.php: <?php require_once("conn.php"); class myClass{ public function con() { $conn = new conn(); $conn->getConnected(); } public function myF() { $stmt = mysqli_prepare($conn->connection, "SELECT * FROM $conn->tablename"); mysqli_stmt_execute($stmt); } } ?> I then call this as follows: $myNew = new myClass(); $myNew-con(); $myNew-myF(); When I call this, I get the following error: Undefined property: myClass::$connection What am I doing wrong?

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  • '<=' operator is not working in sql server 2000

    - by Lalit
    Hello, Scenario is, database is in the maintenance phase. this database is not developed by ours developer. it is an existing database developed by the 'xyz' company in sql server 2000. This is real time database, where i am working now. I wanted to write the stored procedure which will retrieve me the records From date1 to date 2.so query is : Select * from MyTableName Where colDate>= '3-May-2010' and colDate<= '5-Oct-2010' and colName='xyzName' whereas my understanding I must get data including upper bound date as well as lower bound date. but somehow I am getting records from '3-May-2010' (which is fine but) to '10-Oct-2010' As i observe in table design , for ColDate, developer had used 'varchar' to store the date. i know this is wrong remedy by them. so in my stored procedure I have also used varchar parameters as @FromDate1 and @ToDate to get inputs for SP. this is giving me result which i have explained. i tried to take the parameter type as 'Datetime' but it is showing error while saving/altering the stored procedure that "@FromDate1 has invalid datatype", same for "@ToDate". situation is that, I can not change the table design at all. what i have to do here ? i know we can use user defined table in sql server 2008 , but there is version sql server 2000. which does not support the same. Please guide me for this scenario. **Edited** I am trying to write like this SP: CREATE PROCEDURE USP_Data (@Location varchar(100), @FromDate DATETIME, @ToDate DATETIME) AS SELECT * FROM dbo.TableName Where CAST(Dt AS DATETIME) >=@fromDate and CAST(Dt AS DATETIME)<=@ToDate and Location=@Location GO but getting Error: Arithmetic overflow error converting expression to data type datetime. in sql server 2000 What should be that ? is i am wrong some where ? also (202 row(s) affected) is changes every time in circular manner means first time sayin (122 row(s) affected) run again saying (80 row(s) affected) if again (202 row(s) affected) if again (122 row(s) affected) I can not understand what is going on ?

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  • Ajax to read from form

    - by Edwin
    Hello, I'm writing a store system for my game, it worked quite well until I found out that it only takes the amount of first entered Item. function pbuy(buyitem) { var amountc = "amount-"+buyitem, var amount = $("#"+amountc+"").val(); $.ajax({ type: "POST", url: "store2.php", data: "buyitem="+ buyitem+"&amount="+amount, success: function(resp){ document.getElementById('ajaxDiv').innerHTML = resp; }, error: function(e){ alert('Error: ' + e); } }); } I'm trying to give it it the Id of the form like so: function pbuy(buyitem) { var amountc = "amount-"+buyitem, var amount = $("#"+amountc+"").val(); But nothing happens. The code the creation of the forms is: <tr> <td class='items' width='80%' align='center' valign='top'><?PHP echo $itemstore->itemname;?> </td> <td width="20%"> Price:<?PHP echo $itemstore->newprice;?> <form method="post"> <input type='text' id='amount-<?PHP echo $row;?>)' /> <input name="itembid" type="button" onclick="pbuy(<?PHP echo $row;?>)" value="Buy" /></form></td> </tr> If I hardcode the amount in the ajax function it all runs fine like it should.

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  • Windows service: Listening on socket while running as LocalSystem

    - by Socob
    I'm writing a small server-like program in C for Windows (using MinGW/GCC, testing on Windows 7) which is eventually supposed to run as a service with the LocalSystem account. I am creating a socket, and using Windows Sockets bind(), listen() and accept() to listen for incoming connections. If I run the application from the command line (i.e. not as a service, but as a normal user), I have no problems connecting to it from external IPs. However, if I run the program as a service with the LocalSystem account, I can only connect to the service from my own PC, either with 127.0.0.1 or my local address, 192.168.1.80 (I'm behind a router in a small local network). Neither external IPs nor other PCs in the same local network, using my local address, can connect now, even though there were no problems without running as a service. Now, I've heard that networking is handled differently or even not accessible (?) when running as LocalSystem or LocalService or that services cannot access both the desktop and the network (note: my service is not interactive) at the same time due to security considerations. Essentially, I need to find out what's going wrong/how to listen for connections in a service. Is running as NetworkService the same as running as LocalSystem, but with network access? Surely there must be servers that can run as background services, so how do they do it?

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  • php parsing csv with ftell

    - by Robert82
    I have a 500mb csv file with over 500,000 lines, each with 80 fields. I am using fget to process the file line by line. $col1 = array(); while (($row = fgetcsv($handle, 1000, ",")) !== FALSE) { $col1[] = $row[0]; } Because of an execution time limit on the PHP file by my hosting provider (120 seconds), I can't process the whole file in one run. I tried using ftell() and fseek() to remember the last position for restart. The trouble is, sometimes the ftell() position is in the middle of a row, and resuming means missing the first half of the row. Is there an elegant way to know the last line successfully processed, and resume from the one after it? I realize I can do a simple counter, and then loop through to that point again, but that would produce diminishing returns on the rows I can process towards the end of the file. Is there something like ftell() and fseek() that would work in my case? Or a way to limit ftell() to return the pointer for the end of the previous line?

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  • How do i close a socket after a timeout in node.js?

    - by rramsden
    I'm trying to close a socket after a connection times out after 1000ms. I am able to set a timeout that gets triggered after a 1000ms but I can't seem to destroy the socket... any ideas? var connection = http.createClient(80, 'localhost'); var request = connection.request('GET', '/somefile.xml', {'host':'localhost'}); var start = new Date().getTime(); request.socket.setTimeout(1000); request.socket.addListener("timeout", function() { request.socket.destroy(); sys.puts("socket timeout connection closed"); }); request.addListener("response", function(response) { var responseBody = []; response.setEncoding("utf8"); response.addListener("data", function(chunk) { sys.puts(chunk); responseBody.push(chunk); }); response.addListener("end", function() { }); }); request.end(); returns socket timeout connection closed node.js:29 if (!x) throw new Error(msg || "assertion error"); ^ Error: assertion error at node.js:29:17 at Timer.callback (net:152:20) at node.js:204:9

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  • bluetooth BluetoothSocket.connect() thread. how to close this thread

    - by Hia
    I am trying to make an android app that makes connection with bluetooth device. It works fine but when I call BluetoothSocket.connect() and it is not able to connect to devise its blocking. The thread and does not throw any exception. So when I try to close application while connect() is running its not responding. How can I cancel it? Used BluetoothSocket.close() in ... but still its not working for me. protected void simpleComm(Integer port) { // The documents tell us to cancel the discovery process. try { Method m = mmDevice.getClass().getMethod("createRfcommSocket", new Class[] { int.class }); mmSocket = (BluetoothSocket) m.invoke(mmDevice, port); mmSocket.connect(); // <== blocks untill is not connected Log.d(TAG, " connection success==="); }catch(Exception e){ if (!abort) { connectionFailed(); // Close the socket try { mmSocket.close(); // Start the service over to restart listening mode BluetoothService.this.start(); } catch (IOException e2) { Log.e(TAG,"unable to close() socket during connection failure", e2); } } return; } } public void cancel() { try { abort = true; mmSocket.close(); } catch (IOException e) { Log.e(TAG, "close() of connect socket failed", e); } }

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  • login using UITableView

    - by EquinoX
    How can I create a login for username/password just like in the skype application? I know it's a grouped table view.. but how can I do that? I searched the site and found the following code: - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *CellIdentifier = @"Cell"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease]; UILabel *startDtLbl = [[UILabel alloc] initWithFrame:CGRectMake(10, 10, 80, 25)]; if (indexPath.row == 0) startDtLbl.text = @"Username"; else { startDtLbl.text = @"Password"; } startDtLbl.backgroundColor = [UIColor clearColor]; [cell.contentView addSubview:startDtLbl]; UITextField *passwordTF = [[UITextField alloc] initWithFrame:CGRectMake(100, 5, 200, 35)]; passwordTF.delegate = self; if (indexPath.row == 0) passwordTF.tag = 0; else { passwordTF.tag = 1; } [cell.contentView addSubview:passwordTF]; } return cell; } When I do: NSString * username = [((UITextField*)[self.view viewWithTag:0]) text]; NSString * password = [((UITextField*)[self.view viewWithTag:1]) text]; it gives me this error: Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[UIView text]: unrecognized selector sent to instance 0x6c3c600 Why is this?

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  • Uncaught TypeError: Property 'dist2' of object [object Object] is not a function

    - by Radu Vlad
    I have this functions that should return me the distance from point p to segment line v-w. The problem i have is after some time i receive the following error: Uncaught TypeError: Property 'dist2' of object [object Object] is not a function. I receive it in distToSegmentSquared directly,not even calling the function dist2().Is it any other dist2() anywhere in jquery?I found none... function sqr(x) { return x * x; } function dist2(v, w) { console.log(v); console.log(w); return sqr(v.x - w.x) + sqr(v.y - w.y); } function distToSegmentSquared(p, v, w) { var l2 = dist2(v, w); if (l2 == 0) return dist2(p, v); var t = ((p.x - v.x) * (w.x - v.x) + (p.y - v.y) * (w.y - v.y)) / l2; if (t < 0) return dist2(p, v); if (t > 1) return dist2(p, w); return dist2(p, {x: v.x + t * (w.x - v.x), y: v.y + t * (w.y - v.y)}); } function distToSegment(p, v, w) { return Math.sqrt(distToSegmentSquared(p, v, w)); } The values that are given in for that error are: p: Object x: 461 y: 333 v: Object x: 80 y: 120 w: Object x: 260 y: 120

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  • Mysql configuration problem

    - by jazzrai
    I have being trying since last night. At first it was working but this morning again its not working. I am installing mysql version 5.0 on vista machine. when i try to configure its says that: The security settings could not be applied to the database because the connnection had failed with the following error: Error Nr. 1045 access denied for user 'root'@'localhost'(using password:yes) if a personal firewall is runnig on your machine plaes make sure you have opened the tcp port 3306 for connections. otherwise no client applicaion can connect to the server. after you have opened the port please press retry to apply the secirity settings. if you are re-installing after you just installed the mysql server please not that the data directory was not removed automatically. therefore the old password from your last installation is still needed to connect to the server. in this case please select skip now and re-run the configuration wizard from the start menu. i tried disabling the wirefall, user accounts but getting the same error. can anyone suggest me something please.

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