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  • xampp admin page access forbidden

    - by Vihaan Verma
    I m new to apache world ! I read some docs online to setup virtual host . Which works fine ! Here are the content of httpd-vhosts.conf file <Directory C:/vhosts> Order Deny,Allow Allow from all </Directory> NameVirtualHost *:80 <VirtualHost *:80> DocumentRoot "C:/htdocs" ServerName localhost </VirtualHost> <VirtualHost *:80> DocumentRoot "C:/vhosts/phpdw" ServerName phpdw </VirtualHost> But now when I access the xampp control panel and try accessing the apache admin page I get access defined eror (403) . My guess is that there needs to be some more configuration in this file to allow access to localhost. I could not find anything relevant . Thanks

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  • Interface vs Abstract Class (general OO)

    - by Kave
    Hi, I have had recently two telephone interviews where I've been asked about the differences between an Interface and an Abstract class. I have explained every aspect of them I could think of, but it seems they are waiting for me to mention something specific, and I dont know what it is. From my experience I think the following is true, if i am missing a major point please let me know: Interface: Every single Method declared in an Interface will have to be implemented in the subclass. Only Events, Delegates, Properties (C#) and Methods can exist in a Interface. A class can implement multiple Interfaces. Abstract Class Only Abstract methods have to be implemented by the subclass. An Abstract class can have normal methods with implementations. Abstract class can also have class variables beside Events, Delegates, Properties and Methods. A class can only implement one abstract class only due non-existence of Multi-inheritance in C#. 1) After all that the interviewer came up with the question What if you had an Abstract class with only abstract methods, how would that be different from an interface? I didnt know the answer but I think its the inheritance as mentioned above right? 2) An another interviewer asked me what if you had a Public variable inside the interface, how would that be different than in Abstract Class? I insisted you can't have a public variable inside an interface. I didn't know what he wanted to hear but he wasn't satisfied either. Many Thanks for clarification, Kave See Also: When to use an interface instead of an abstract class and vice versa Interfaces vs. Abstract Classes How do you decide between using an Abstract Class and an Interface?

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  • How to store and locate multiple interface types within a Delphi TInterfaceList

    - by Brian Frost
    Hi, I'm storing small interfaces from a range of objects into a single TInterfaceList 'store' with the intention of offering list of specific interface types to the end user, so each interface will expose a 'GetName' function but all other methods are unique to that interface type. For example here are two interfaces: IBase = interface //---------------------------------------- function GetName : string; //---------------------------------------- end; IMeasureTemperature = interface(IBase) //------------------------------------ function MeasureTemperature : double; //---------------------------------------- end; IMeasureHumidity = interface(IBase) //---------------------------------------- function MeasureHumidity: double; //---------------------------------------- end; I put several of these interfaces into a single TInterfaceList and then I'd like to scan the list for a specific interface type (e.g. 'IMeasureTemperature') building another list of pointers to the objects exporting those interfaces. I wish to make no assumptions about the locations of those objects, some may export more than one type of interface. I know I could do this with a class hierarchy using something like: If FList[I] is TMeasureTemperature then .. but I'd like to do something simliar with an interface type, Is this possible?

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  • nginx not serving admin static files?

    - by toto_tico
    First, I want to clarify that this error is just for the admin static files. This means my problem is specific just to the static files that corresponds to the Django admin. The rest of the static files are working perfect. Basically my problem is that for some reason I cannot access those admin static files with the ngix server. It works perfect with the micro server of Django and the collect static is doing its job. This means it is putting the files on the expected place in the static folder. The urls are correct but I cannot even access the admin static files directly, but the others I can. So, for example, I am able to access this url (copying it in the browser): myserver.com:8080/static/css/base/base.css but i am not able to access this other url (copying it in the browser): myserver.com:8080/static/admin/css/admin.css I also tried to copy the admin/ directory structure into other_admin_directory_name/. Then I can access myserver.com:8080/static/other_admin_directory_name/css/admin.css Then, it works. So, I checked permissions and everything is fine. I tried to change ADMIN_MEDIA_PREFIX = '/static/admin/' to ADMIN_MEDIA_PREFIX = '/static/other_admin_directory_name/', it doesn't work. This a mistery in itself that I am exploring but still no luck. Finally, and it seems to be an important clue: I tried to copy the admin/ directory structure into admin_and_then_any_suffix/. Then I cannot access myserver.com:8080/static/admin_and_then_any_suffix//css/admin.css So, if the name of the directory starts with admin (for example administration or admin2) it doesn't work. * added thanks to sarnold observation ** the problem seems to be in the nginx configuration file /etc/nginx/sites-available/mysite location /static/admin { alias /home/vl3/.virtualenvs/vl3/lib/python2.7/site-packages/django/contrib/admin/media/; }

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  • Prepopulating inlines based on the parent model in the Django Admin

    - by Alasdair
    I have two models, Event and Series, where each Event belongs to a Series. Most of the time, an Event's start_time is the same as its Series' default_time. Here's a stripped down version of the models. #models.py class Series(models.Model): name = models.CharField(max_length=50) default_time = models.TimeField() class Event(models.Model): name = models.CharField(max_length=50) date = models.DateField() start_time = models.TimeField() series = models.ForeignKey(Series) I use inlines in the admin application, so that I can edit all the Events for a Series at once. If a series has already been created, I want to prepopulate the start_time for each inline Event with the Series' default_time. So far, I have created a model admin form for Event, and used the initial option to prepopulate the time field with a fixed time. #admin.py ... import datetime class OEventInlineAdminForm(forms.ModelForm): start_time = forms.TimeField(initial=datetime.time(18,30,00)) class Meta: model = OEvent class EventInline(admin.TabularInline): form = EventInlineAdminForm model = Event class SeriesAdmin(admin.ModelAdmin): inlines = [EventInline,] I am not sure how to proceed from here. Is it possible to extend the code, so that the initial value for the start_time field is the Series' default_time?

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  • Rate limiting Django admin login with Nginx to prevent dictionary attack

    - by shreddies
    I'm looking into the various methods of rate limiting the Django admin login to prevent dictionary attacks. One solution is explained here: simonwillison.net/2009/Jan/7/ratelimitcache/ However, I would prefer to do the rate limiting at the web server side, using Nginx. Nginx's limit_req module does just that - allowing you to specify the maximum number of requests per minute, and sending a 503 if the user goes over: http://wiki.nginx.org/NginxHttpLimitReqModule Perfect! I thought I'd cracked it until I realised that Django admin's login page is not in a consistent place, eg /admin/blah/ gives you a login page at that URL, rather than bouncing to a standard login page. So I can't match on the URL. Can anyone think of another way to know that the admin page was being displayed (regexp the response HTML?)

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  • Django Admin drop down combobox and assigned values

    - by Daniel Garcia
    I have several question for the Django Admin feature. Im kind of new in Django so im not sure how to do it. Basically what Im looking to do is when Im adding information on the model. Some of the fields i want them to be drop-downs and maybe combo-boxes with AutoCompleteMode. Also looking for some fields to have the same information, for example if i have a datatime field I want that information to feed the fields day, month and year from hoti.hotiapp.models import Occurrence from django.contrib import admin class MyModelAdmin(admin.ModelAdmin): exclude = ['reference',] admin.site.register(Occurrence, MyModelAdmin) Anything helps Thanks in advance

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  • Django Admin: not seeing any app (permission problem?)

    - by Facundo
    I have a site with Django running some custom apps. I was not using the Django ORM, just the view and templates but now I need to store some info so I created some models in one app and enabled the Admin. The problem is when I log in the Admin it just says "You don't have permission to edit anything", not even the Auth app shows in the page. I'm using the same user created with syncdb as a superuser. In the same server I have another site that is using the Admin just fine. Using Django 1.1.0 with Apache/2.2.10 mod_python/3.3.1 Python/2.5.2, with psql (PostgreSQL) 8.1.11 all in Gentoo Linux 2.6.23 Any ideas where I can find a solution? Thanks a lot. UPDATE: It works from the development server. I bet this has something to do with some filesystem permission but I just can't find it. UPDATE2: vhost configuration file: <Location /> SetHandler python-program PythonHandler django.core.handlers.modpython SetEnv DJANGO_SETTINGS_MODULE gpx.settings PythonDebug On PythonPath "['/var/django'] + sys.path" </Location> UPDATE 3: more info /var/django/gpx/init.py exists and is empty I run python manage.py from /var/django/gpx directory The site is GPX, one of the apps is contable and lives in /var/django/gpx/contable the user apache is webdev group and all these directories and files belong to that group and have rw permission UPDATE 4: confirmed that the settings file is the same for apache and runserver (renamed it and both broke) UPDATE 5: /var/django/gpx/contable/init.py exists This is the relevan part of urls.py: urlpatterns = patterns('', (r'^admin/', include(admin.site.urls)), ) urlpatterns += patterns('gpx', (r'^$', 'menues.views.index'), (r'^adm/$', 'menues.views.admIndex'),

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  • Tying in to Django Admin's Model History

    - by akdom
    The Setup: I'm working on a Django application which allows users to create an object in the database and then go back and edit it as much as they desire. Django's admin site keeps a history of the changes made to objects through the admin site. The Question: How do I hook my application in to the admin site's change history so that I can see the history of changes users make to their "content" ?

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  • django: displaying group users count in admin

    - by gruszczy
    I would like to change admin for a group, so it would display how many users are there in a certain group. I'd like to display this in the view showing all groups, the one before you enter admin for certain group. Is it possible? I am talking both about how to change admin for a group and how to add function to list_display.

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  • Adding interactions to admin pages generated by the admin generator

    - by Stick it to THE MAN
    I am using Symfony 1.2.9 (with Propel ORM) to create a website. I have started using the admin generator to implement the admin functionality. I have come accross a slight 'problem' however. My models are related (e.g. one table may have several 1:N relations and N:N relations). I have not found a way to address this satisfactorily yet. As a tactical solution (for list views), I have decided to simply show the parent object, and then add interactions to show the related objects. I'll use a Blog model to illustrate this. Here are the relationships for a blog model: N:M relationship with Blogroll (models a blog roll) 1:N relationship with Blogpost (models a post submitted to a blog) I had originally intended on displaying the (paged) blogpost list for a blog,, when it was selected, using AJAX, but I am struggling enough with the admin generator as it is, so I have shelved that idea - unless someone is kind enough to shed some light on how to do this. Instead, what I am now doing (as a tactical/interim soln), is I have added interactions to the list view which allow a user to: View a list of the blog roll for the blog on that row View a list of the posts for the blog on that row Add a post for the blog on tha row In all of the above, I have written actions that will basically forward the request to the approriate action (admin generated). However, I need to pass some parameters (like the blog id etc), so that the correct blog roll or blog post list etc is returned. I am sure there is a better way of doing what I want to do, but in case there isn't here are my questions: How may I obtain the object that relates to a specific row (of the clicked link) in the list view (e.g. the blog object in this example) Once I have the object, I may choose to extract various fields: id etc. How can I pass these arguments to the admin generated action ? Regarding the second question, my guess is that this may be the way to do it (I may be wrong) public function executeMyAddedBlogRollInteractionLink(sfWebRequest $request) { // get the object *somehow* (I'm guessing this may work) $object = $this->getRoute()->getObject(); // retrieve the required parameters from the object, and build a query string $query_str=$object->getId(); //forward the request to the generated code (action to display blogroll list in this case) $this->forward('backendmodulename',"getblogrolllistaction?params=$query_string"); } This feels like a bit of a hack, but I'm not sure how else to go about it. I'm also not to keen on sending params (which may include user_id etc via a GET, even a POST is not that much safer, since it is fairly sraightforward to see what requests a browser is making). if there is a better way than what I suggest above to implement this kind of administration that is required for objects with 1 or more M:N relationships, I will be very glad to hear the "recommended" way of going about it. I remember reading about marking certain actions as internal. i.e. callable from only within the app. I wonder if that would be useful in this instance?

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  • Changing User ModelAdmin for Django admin

    - by Leon
    How do you override the admin model for Users? I thought this would work but it doesn't? class UserAdmin(admin.ModelAdmin): list_display = ('email', 'first_name', 'last_name') list_filter = ('is_staff', 'is_superuser') admin.site.register(User, UserAdmin) I'm not looking to override the template, just change the displayed fields & ordering. Solutions please?

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  • How do I secure all the admin actions in all controllers in cakePHP

    - by Gaurav Sharma
    Hello Everyone, I am developing an application using cakePHP v 1.3 on windows (XAMPP). Most of the controllers are baked with the admin routing enabled. I want to secure the admin actions of every controller with a login page. How can I do this without repeating much ? One solution to the problem is that "I check for login information in the admin_index action of every controller" and then show the login screen accordingly. Is there any better way of doing this ? The detault URL to admin (http://localhost/app/admin) is pointing to the index_admin action of users controller (created a new route for this in routes.php file) Thanks

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  • Hide fields in Django admin

    - by jwesonga
    I'm tying to hide my slug fields in the admin by setting editable=False but every time I do that I get the following error: KeyError at /admin/website/program/6/ Key 'slug' not found in Form Request Method: GET Request URL: http://localhost:8000/admin/website/program/6/ Exception Type: KeyError Exception Value: Key 'slug' not found in Form Exception Location: c:\Python26\lib\site-packages\django\forms\forms.py in __getitem__, line 105 Python Executable: c:\Python26\python.exe Python Version: 2.6.4 Any idea why this is happening

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  • Dropdown sorting in django-admin

    - by Andrey
    I'd like to know how can I sort values in the Django admin dropdowns. For example, I have a model called Article with a foreign key pointing to the Users model, smth like: class Article(models.Model): title = models.CharField(_('Title'), max_length=200) slug = models.SlugField(_('Slug'), unique_for_date='publish') author = models.ForeignKey(User) body = models.TextField(_('Body')) status = models.IntegerField(_('Status')) categories = models.ManyToManyField(Category, blank=True) publish = models.DateTimeField(_('Publish date')) I edit this model in django admin: class ArticleAdmin(admin.ModelAdmin): list_display = ('title', 'publish', 'status') list_filter = ('publish', 'categories', 'status') search_fields = ('title', 'body') prepopulated_fields = {'slug': ('title',)} admin.site.register(Article, ArticleAdmin) and of course it makes the nice user select dropdown for me, but it's not sorted and it takes a lot of time to find a user by username.

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  • Django admin's filter_horizontal (& filter_vertical) not working

    - by negus
    I'm trying to use ModelAdmin.filter_horizontal and ModelAdmin.filter_vertical for ManyToMany field instead of select multiple box but all I get is: My model: class Title(models.Model): #... production_companies = models.ManyToManyField(Company, verbose_name="????????-?????????????") #... My admin: class TitleAdmin(admin.ModelAdmin): prepopulated_fields = {"slug": ("original_name",)} filter_horizontal = ("production_companies",) radio_fields = {"state": admin.HORIZONTAL} #... The javascripts are loading OK, I really don't get what happens. Django 1.1.1 stable.

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  • Interface helpers or delegating interface parent

    - by Craig Peterson
    If I have an existing IInterface descendant implemented by a third party, and I want to add helper routines, does Delphi provide any easy way to do so without redirecting every interface method manually? That is, given an interface like so: IFoo = interface procedure Foo1; procedure Foo2; ... procedure FooN; end; Is anything similar to the following supported? IFooHelper = interface helper for IFoo procedure Bar; end; or IFooBar = interface(IFoo) procedure Bar; end; TFooBar = interface(TInterfacedObject, IFoo, IFooBar) private FFoo: IFoo; public procedure Bar; property Foo: IFoo implements IFoo; end; I'm specifically wondering about ways to that allow me to always refer to IFoo, IFooBar, or TFooBar, without switching between them, and without adding all of IFoo's methods to TFooBar.

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  • where is everything in django admin?

    - by FurtiveFelon
    Hi all, I would like to figure out where everything is in django admin. Since i am currently trying to modify the behavior rather heavily right now, so perhaps a reference would be helpful. For example, where is ModelAdmin located, i cannot find it anywhere in C:\Python26\Lib\site-packages\django\contrib\admin. I need that because i would like to look at how it is implemented so that i can override with confidence. I need to do that in part because of this page: http://docs.djangoproject.com/en/dev/ref/contrib/admin/#modeladmin-methods, for example, i would like to override ModelAdmin.add_view, but i can't find the original source for that. As well as i would like to see the url routing file for admin, so i can easily figure out which url corresponding to which template etc. Thanks a lot for any pointers!

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  • Admin auto generation

    - by Me-and-Coding
    Hi, I create custom CMS sites and then go ahead for the backend/admin side. Is there any tool out there to automatically create admin side of my sites, for example, based on table relationships or whatever customization we may put in place. PHPMaker seems to claim something like what i ask for but i have not used it. Any tool out there to auto-create admin side or PHPMaker is up to the point? Thanks

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  • Building Admin Areas in Rails - General Questions

    - by Carb
    What is the typical format/structure for creating an administrative area in a Rails application? Specifically I am stumped in the vicinity of these topics: How do you deal with situations where a model's resources are available to both the public and the Admin? i.e. A User model where anyone can create users, login, etc but only the admin can view users, delete/update them, etc. What is the proper convention for routing? How does one structure controllers? Are duplicate controllers considered OK? i.e. An admin version and the non-admin version? Thank you!

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  • Django admin - remove field if editing an object

    - by John McCollum
    I have a model which is accessible through the Django admin area, something like the following: # model class Foo(models.Model): field_a = models.CharField(max_length=100) field_b = models.CharField(max_length=100) # admin.py class FooAdmin(admin.ModelAdmin): pass Let's say that I want to show field_a and field_b if the user is adding an object, but only field_a if the user is editing an object. Is there a simple way to do this, perhaps using the fields attribute? If if comes to it, I could hack a JavaScript solution, but it doesn't feel right to do that at all!

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  • Is “Application Programming Interface” a bad name?

    - by Taylor Hawkes
    Application programming interface seems like a bad name for what it is. Is there a reason it was named such? I understand that people used to call them Advanced Programming Interfaces and then renamed to Application Programming Interface. Is that why it is poorly named? Why is it not named Application (to) Programmer Interface. I guess I'm just confused of the meaning behind that name? I write more about my confusion around the name here: BREAKING DOWN THE WORD “APPLICATION PROGRAMMING INTERFACE” This is a very confusing word. We mostly understand what the word Interface means, but “Application Programming”, what even is that. Honestly I'm confused. Is that suppose to be two words like “Application”, “Programming” and then the “Interface” is suppose to mean between the two? Like would a “Computer Human Interface” be an interface between a “Computer” and a “Human” (monitor , keyboard, mouse ) or is a “Computer Human” a real thing - perhaps the terminator. So a CHI is our boy Kyle Reese who is the only way we are able to work with the computer human. I think more likely “Application Programming Interface” was simply poorly named and doesn't really make sense. It was originally called an “Advanced Programming Interface” , but perhaps being a bit to ostentatious merged into the now wildly accepted “Application Programming Interface”. So now, not wanting to change an acronym has confused the living heck out everyone.... Any thoughts or clarification would be great, I'm giving a lecture on this topic in a month, so I would prefer not to BS my way through it.

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