Search Results

Search found 784 results on 32 pages for 'chars'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 4/32 | < Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >

  • regular expression with special chars

    - by xRobot
    I need a regular expression to validate string with one or more of these characters: a-z A-Z ' àòèéùì simple white space FOR EXAMPLE these string are valide: D' argon calabrò maryòn l' Ancol these string are NOT valide: hello38239 my_house work [tab] with me I tryed this: re.match(r"^[a-zA-Z 'òàèéìù]+$", self.cleaned_data['title'].strip()) It seems to work in my python shell but in Django I get this error: SyntaxError at /home/ ("Non-ASCII character '\\xc3' ... Why ?

    Read the article

  • Remove special chars from URL

    - by John Jones
    Hi, I have a product database and I am displaying trying to display them as clean URLs, below is example product names: PAUL MITCHELL FOAMING POMADE (150ml) American Crew Classic Gents Pomade 85g Tigi Catwalk Texturizing Pomade 50ml What I need to do is display like below in the URL structrue: www.example.com/products/paul-mitchell-foaming-gel(150ml) The problem I have is I want to do the following: Remove anything with braquets(and the braquets) Remove any numbers next to g or ml e.g. 400ml, 10g etc... I have been banging my head trying different string replaces but cant get it right, I would really appreciate some help. Cheers

    Read the article

  • JQuery - remove the chars not matching regEx

    - by JQueryBeginner
    Hi All, I am trying to use jquery for validating forms. This is the pattern that is allowed in a text box for a user. var pattern = /^[a-zA-Z0-9!#$&%*+,-./: ;=?@_]/g; If the user types anything else other than this then that has to be replaced with a "". $(document).ready(function() { $('#iBox').blur(function() { var jVal = $('#iBox').val(); if(jVal.match(pattern)) { alert("Valid"); } else { alert("New "+jVal.replace(!(pattern),"")); } }); }); }); But the replace function does not work this way.

    Read the article

  • replacing the beginning and end but not the same chars within a string

    - by Jordan Trainor
    lines = "some stuff\"some other \"stuff\"\""; lines = lines.Replace("\"", "\""); lines = lines.Replace("\"", "\""); in its current context and in its simplest form these two actions seem absolutely pointless but when I put this into code it will be not be pointless and will have a purpose other than replacing itself with itself. OK so I have the String lines that has 4 escaped quotation marks and I wish to replace the first quote with a quote and the end quote with a quote how would I accomplish this without replacing any of the inner quotes?

    Read the article

  • Ignoring certain chars globally

    - by shi kui
    Consider it that '_'s in a number doesn't change that number's value so 1000==1_000==10_00. The Problem: given numbers like 1_244_23 1412_2 1_1111 etc..., how could I decide whether certain number appears in that collection? For example: 1244_23 yes, 11_111 yes, 1412_1 no. How could using regex to solve this? I mean, if I could tell the regex engine just ignore these '_''s when matching then this problem becomes trivial? How could I do so?

    Read the article

  • C++ beginner question regarding chars

    - by Samwhoo
    I'm just messing around with some C++ at the moment trying to make a simple tic-tac-toe game and I'm running into a bit of a problem. This is my code: #include <iostream> using namespace std; class Square { public: char getState() const; void setState(char); Square(); ~Square(); private: char * pState; }; class Board { public: Board(); ~Board(); void printBoard() const; Square getSquare(short x, short y) const; private: Square board[3][3]; }; int main() { Board board; board.getSquare(1,2).setState('1'); board.printBoard(); return 0; } Square::Square() { pState = new char; *pState = ' '; } Square::~Square() { delete pState; } char Square::getState() const { return *pState; } void Square::setState(char set) { *pState = set; } Board::~Board() { } Board::Board() { } void Board::printBoard() const { for (int x = 0; x < 3; x++) { cout << "|"; for (int y = 0; y < 3; y++) { cout << board[x][y].getState(); } cout << "|" << endl; } } Square Board::getSquare(short x, short y) const { return board[x][y]; } Forgive me if there are blatantly obvious problems with it or it's stupidly written, this is my first program in C++ :p However, the problem is that when I try and set the square 1,2 to the char '1', it doesn't print out as a 1, it prints out as some strange character I didn't recognise. Can anyone tell me why? :) Thanks in advance.

    Read the article

  • Getting a substring in Ruby by x number of chars

    - by wotaskd
    I'm trying to produce some Ruby code that will take a string and return a new one, with a number x number of characters removed from its end - these can be actual letters, numbers, spaces etc. Ex: given the following string a_string = "a1wer4zx" I need a simple way to get the same string, minus - say - the 3 last digits. In the case above, that would be "a1wer". The way I'm doing it right now seems very convoluted: an_array = a_string.split(//,(a_string.length-2)) an_array.pop new_string = an_array.join Any ideas?

    Read the article

  • Javascript: How to escape Unicode Chars

    - by user293006
    JSON String: { "id":31896, "name":"Zickey attitude - McKinley, La Rosi\u00e8re, 21 ao\u00fbt 2006", ... } this causes an unterminated string in javascript. my focus on solution is: data.replace(/(\S)\1(\1)+/g, ''); or data.replace(/\u([0-9A-Z])/, ''); any ideas/solution? example: http://api.jamendo.com/get2/id+name+url+stream+album_name+album_url+album_id+artist_id+artist_name/track/jsonpretty/track_album+album_artist/?n=13&order=ratingmonth_desc&tag_idstr=jazz last node is the problem, fyi. (/\u([0-9A-Z])/, '\1');

    Read the article

  • Regex: Match opening/closing chars with spaces

    - by Israfel
    I'm trying to complete a regular expression that will pull out matches based on their opening and closing characters, the closest I've gotten is ^(\[\[)[a-zA-Z.-_]+(\]\]) Which will match a string such as "[[word1]]" and bring me back all the matches if there is more than one, The problem is I want it to pick up matchs where there may be a space in so for example "[[word1 word2]]", now this will work if I add a space into my pattern above however this pops up a problem that it will only get one match for my entire string so for example if I have a string "Hi [[Title]] [[Name]] [[surname]], How are you" then the match will be "[[Title]] [[Name]] [[surname]]" rather than 3 matches "[[Title]]", "[[Name]]", "[[surname]]". I'm sure I'm just a char or two away in the Regex but I'm stuck, How can I make it return the 3 matches. Thanks

    Read the article

  • Java, UnmarshallingException caused by XML attribute with special chars: ;ìè+òàù-<^èç°§_>!£$%&/()=?~

    - by segolas
    Hi, my xml file has a tag with an attribute "containsValue" which contains the "special" characters you can see in the subject: <original_msg_body id="msgBodySpecialCharsRule" containsValue=";ìè+òàù-<^èç°§_>!£$%&/()=?~`'#;" /> in my xml schema the attribute has xs:string: <xs:attribute name="containsValue" type="xs:string" /> I use this value inside a Java software which check if this value is contained inside another String. but I always obtain this Exception: javax.xml.bind.UnmarshalException - with linked exception: [org.xml.sax.SAXParseException: The value of attribute "containsValue" associated with an element type "original_msg_body" must not contain the '<' character.] How can I solve it? I've tried changing the attribute type to xs:NMTOKEN, ut I get the same exception. Is there any other type? I think I could change the characters encoding, for example using the HTML representation, like <, but than could be tricky for the string comparison...

    Read the article

  • Best way to create SEO friendly URI string

    - by Mat Banik
    The method below allows only "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ-" chars in URI strings. What better way is there to make nice SEO URI string? import org.apache.commons.lang.StringUtils; public static String safeChar(String input) { input = input.trim(); input = StringUtils.replace(input, " -", "-"); input = StringUtils.replace(input, "- ", "-"); input = StringUtils.replace(input, " - ", "-"); input = StringUtils.replaceChars(input, '\'', '-'); input = StringUtils.replaceChars(input, ' ', '-'); char[] allowed = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ-".toCharArray(); char[] charArray = input.toCharArray(); StringBuilder result = new StringBuilder(); for (char c : charArray) { for (char a : allowed) { if (c == a) result.append(a); } } return result.toString(); }

    Read the article

  • UTF-8 bit representation

    - by Yanick Rochon
    I'm learning about UTF-8 standards and this is what I'm learning : Definition and bytes used UTF-8 binary representation Meaning 0xxxxxxx 1 byte for 1 à 7 bits chars 110xxxxx 10xxxxxx 2 bytes for 8 à 11 bits chars 1110xxxx 10xxxxxx 10xxxxxx 3 bytes for 12 à 16 bits chars 11110xxx 10xxxxxx 10xxxxxx 10xxxxxx 4 bytes for 17 à 21 bits chars And I'm wondering, why 2 bytes UTF-8 code is not 10xxxxxx instead, thus gaining 1 bit all the way up to 22 bits with a 4 bytes UTF-8 code? The way it is right now, 64 possible values are lost (from 1000000 to 10111111). I'm not trying to argue the standards, but I'm wondering why this is so? ** EDIT ** Even, why isn't it UTF-8 binary representation Meaning 0xxxxxxx 1 byte for 1 à 7 bits chars 110xxxxx xxxxxxxx 2 bytes for 8 à 13 bits chars 1110xxxx xxxxxxxx xxxxxxxx 3 bytes for 14 à 20 bits chars 11110xxx xxxxxxxx xxxxxxxx xxxxxxxx 4 bytes for 21 à 27 bits chars ...? Thanks!

    Read the article

  • Return a pointer to a char array in C

    - by snitko
    I've seen a lot of questions on that on StackOverflow, but reading the answers did not clear that up for me, probably because I'm a total newbie in C programming. Here's the code: #include <stdio.h> char* squeeze(char s[], char c); main() { printf("%s", squeeze("hello", 'o')); } char* squeeze(char s[], char c) { int i, j; for(i = j = 0; s[i] != '\0'; i++) if(s[i] != c) s[j++] = s[i]; s[j] = '\0'; return s; } It compiles and I get segmentation fault when I run it. I've read this faq about about returning arrays and tried the 'static' technique that is suggested there, but still could not get the program working. Could anyone point out exactly what's wrong with it and what should I be paying attention in the future?

    Read the article

  • highlighting non-ascii text

    - by non-techie
    As a non-techie, I would really appreciate your help on this. I have some files (html) that need to be in pure ascii form to be properly processed. Since these files are produced by humans, every so often non-ascii characters sneak in. Often it is a stray " (curled variety) or something similar that is difficult to find and need to be removed. I have found text editors (eg. textmate) that can strip out all non-ascii characters, but I need to find one that can highlight where they are, rather than remove them (as I need to remove them from the source and not the html file). I hope this makes sense and appreciate any assistance you can provide. Thanks!

    Read the article

  • InvalidAttributeValueException when using non-ascii characters in JNDI

    - by matdan
    Hi, I have some trouble using JNDI since it accepts only 7-bits encoded parameters. I am trying to change an LDAP entry using JNDI with the following code : Attribute newattr = new BasicAttribute("userpassword", password); ModificationItem[] mods = new ModificationItem[1]; mods[0] = new ModificationItem(DirContext.REPLACE_ATTRIBUTE, newattr); context.modifyAttributes("uid=anID,ou=People,o=MyOrganisation,c=com", mods); If my password contains only ascii characters, it works perfectly, but if I use a non-ascii character, like "à", I have this error message : javax.naming.directory.InvalidAttributeValueException: [LDAP: error code 19 - The value is not 7-bit clean: à]; My ldap supports those characters so I guess it comes from JNDI. Does anyone know how to fix that? Am I supposed to convert my parameter? How can I do that easily? Thanks

    Read the article

  • Doctrine Searchable with non-ASCII characters

    - by oyerli
    Hi, I have text in Turkish language: "selam günaydin". Doctrine searchable converts it to keywords in table: -selam -guenaydin So "guenaydin" was saved in table as keyword "günaydin" so when somebody writes in search "günaydin" he gets nothing - what can I do?

    Read the article

  • How can I copy from the browser and paste to vim without unicode problems

    - by dsummersl
    This happens to me all the time: I copy something from a rich text screen (usually a browser) and then paste it into vim. Usually its a code block and then when I go to compile or run or what have you I get all kind of bazaar errors. I scratch my head, and then spend half an hour trying to figure out what is wrong before I realize I've copied some non ASCII characters: dashes, left and right quotes, long underscores, multiplication signs in place of x's, etc. So I ask you: how can I copy non-ASCII into my VIM session without error? Is there a paste mode that automatically 'down samples' unicode to ASCII? Is there a quick/dirty search for non ASCII characters in a file?

    Read the article

  • What is the sense of permiting the user to use no passwords longer than xx chars?

    - by reox
    Its more like a usability question or maybe database, or even maybe security (consider injection attacks) but what is the sense of permiting the user's password to a be not longer than xx chars? It does not make any sense to me, because longer passwords are mostly considered better and even harder to crack, and some users use password safes, so the password length should not matter. I understand that passwords with more than 20 chars are hardly to remember, but if you use diceware or password safe you dont have any problem with that. I really cant understand why there are sites that say "your password need to be between 5 and 8 chars"... also should the password saved as hash, so the length of the field in the database is fixed, so where is the problem? i think that most of the sites where the password is has to be a fixed length are not even using any hashing method...

    Read the article

  • Is it posibble to send websocket data over 126 chars?

    - by Udi Talias
    Its seems that everybody says that it is possible to send over 126 chars of data over websocket. I looked at many websocket server examples on the web and non of them can transfer over 126 chars from client to server and from server to client. I understand that it is something with dataframes and opcodes but i never figured it out. I'm using C#. Can somebody please put some light on this subject? any code example for receiving and sending data over 126 chars will be very very thankful

    Read the article

  • Sort ArrayList alphabetically

    - by relyt
    I'm trying to find all permutations of a string and sort them alphabetically. This is what I have so far: public class permutations { public static void main(String args[]) { Scanner s = new Scanner(System.in); System.out.print("Enter String: "); String chars = s.next(); findPerms("", chars); } public static void findPerms(String mystr, String chars) { List<String> permsList = new ArrayList<String>(); if (chars.length() <= 1) permsList.add(mystr + chars); //System.out.print(mystr + chars + " "); else for (int i = 0; i < chars.length(); i++) { String newString = chars.substring(0, i) + chars.substring(i + 1); findPerms(mystr + chars.charAt(i), newString); } Collections.sort(permsList); for(int i=0; i<permsList.size(); i++) { System.out.print(permsList.get(i) + " "); } } } IF I enter a string "toys" I get: toys tosy tyos tyso tsoy tsyo otys otsy oyts oyst osty osyt ytos ytso yots yost ysto ysot stoy styo soty soyt syto syot What am I doing wrong. How can I get them in alphabetical order? Thanks!

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >