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• ** EDITED ** 'NoneType' object has no attribute 'day'

  - by Asinox

  Hi guy, i dont know where is my error, but Django 1.2.1 is give this error: 'NoneType' object has no attribute 'day' when i try to save form from the Administrator Area models.py from django.db import models from django.contrib.auth.models import User class Editorial(models.Model): titulo = models.CharField(max_length=250,help_text='Titulo del editorial') editorial = models.TextField(help_text='Editorial') slug = models.SlugField(unique_for_date='pub_date') autor = models.ForeignKey(User) pub_date = models.DateTimeField(auto_now_add=True) activa = models.BooleanField(verbose_name="Activa") enable_comments = models.BooleanField(verbose_name="Aceptar Comentarios",default=False) editorial_html = models.TextField(editable=False,blank=True) def __unicode__(self): return unicode(self.titulo) def get_absolute_url(self): return "/editorial/%s/%s/" % (self.pub_date.strftime("%Y/%b/%d").lower(), self.slug) class Meta: ordering=['-pub_date'] verbose_name_plural ='Editoriales' def save(self,force_insert=False, force_update=False): from markdown import markdown if self.editorial: self.editorial_html = markdown(self.editorial) super(Editorial,self).save(force_insert,force_update) i dont know why this error, COMPLETED ERROR: Traceback: File "C:\wamp\bin\Python26\lib\site-packages\django\core\handlers\base.py" in get_response 100. response = callback(request, *callback_args, **callback_kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\contrib\admin\options.py" in wrapper 239. return self.admin_site.admin_view(view)(*args, **kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\utils\decorators.py" in _wrapped_view 76. response = view_func(request, *args, **kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\views\decorators\cache.py" in _wrapped_view_func 69. response = view_func(request, *args, **kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\contrib\admin\sites.py" in inner 190. return view(request, *args, **kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\utils\decorators.py" in _wrapper 21. return decorator(bound_func)(*args, **kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\utils\decorators.py" in _wrapped_view 76. response = view_func(request, *args, **kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\utils\decorators.py" in bound_func 17. return func(self, *args2, **kwargs2) File "C:\wamp\bin\Python26\lib\site-packages\django\db\transaction.py" in _commit_on_success 299. res = func(*args, **kw) File "C:\wamp\bin\Python26\lib\site-packages\django\contrib\admin\options.py" in add_view 777. if form.is_valid(): File "C:\wamp\bin\Python26\lib\site-packages\django\forms\forms.py" in is_valid 121. return self.is_bound and not bool(self.errors) File "C:\wamp\bin\Python26\lib\site-packages\django\forms\forms.py" in _get_errors 112. self.full_clean() File "C:\wamp\bin\Python26\lib\site-packages\django\forms\forms.py" in full_clean 269. self._post_clean() File "C:\wamp\bin\Python26\lib\site-packages\django\forms\models.py" in _post_clean 345. self.validate_unique() File "C:\wamp\bin\Python26\lib\site-packages\django\forms\models.py" in validate_unique 354. self.instance.validate_unique(exclude=exclude) File "C:\wamp\bin\Python26\lib\site-packages\django\db\models\base.py" in validate_unique 695. date_errors = self._perform_date_checks(date_checks) File "C:\wamp\bin\Python26\lib\site-packages\django\db\models\base.py" in _perform_date_checks 802. lookup_kwargs['%s__day' % unique_for] = date.day Exception Type: AttributeError at /admin/editoriales/editorial/add/ Exception Value: 'NoneType' object has no attribute 'day' thanks guys sorry with my English

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• So now that Django 1.2 is officially out...

  - by Fedor

  Since I have Django 1.1x on my Debian setup - how can I use virtualenv or similar and not have it mess up my system's default django version which in turn would break all my sites? Detailed instructions or a great tutorial link would very much be appreciated - please don't offer vague advice since I'm still a noob. Currently I store all my django projects in ~/django-sites and I am using Apache2 + mod_wsgi to deploy.

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• Django-Registration & Django-Profile, using your own custom form

  - by Issy

  Hey All, I am making use of django-registration and django-profile to handle registration and profiles. I would like to create a profile for the user at the time of registration. I have created a custom registration form, and added that to the urls.py using the tutorial on: http://dewful.com/?p=70 The basic idea in the tutorial is to override the default registration form to create the profile at the same time. forms.py - In my profiles app from django import forms from registration.forms import RegistrationForm from django.utils.translation import ugettext_lazy as _ from profiles.models import UserProfile from registration.models import RegistrationProfile attrs_dict = { 'class': 'required' } class UserRegistrationForm(RegistrationForm): city = forms.CharField(widget=forms.TextInput(attrs=attrs_dict)) def save(self, profile_callback=None): new_user = RegistrationProfile.objects.create_inactive_user(username=self.cleaned_data['username'], password=self.cleaned_data['password1'], email=self.cleaned_data['email']) new_profile = UserProfile(user=new_user, city=self.cleaned_data['city']) new_profile.save() return new_user In urls.py from profiles.forms import UserRegistrationForm and url(r'^register/$', register, {'backend': 'registration.backends.default.DefaultBackend', 'form_class' : UserRegistrationForm}, name='registration_register'), The form is displayed, and i can enter in City, however it does not save or create the entry in the DB.

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• django error ,about django-sphinx

  - by zjm1126

  from django.db import models from djangosphinx.models import SphinxSearch class MyModel(models.Model): search = SphinxSearch() # optional: defaults to db_table # If your index name does not match MyModel._meta.db_table # Note: You can only generate automatic configurations from the ./manage.py script # if your index name matches. search = SphinxSearch('index_name') # Or maybe we want to be more.. specific searchdelta = SphinxSearch( index='index_name delta_name', weights={ 'name': 100, 'description': 10, 'tags': 80, }, mode='SPH_MATCH_ALL', rankmode='SPH_RANK_NONE', ) queryset = MyModel.search.query('query') results1 = queryset.order_by('@weight', '@id', 'my_attribute') results2 = queryset.filter(my_attribute=5) results3 = queryset.filter(my_other_attribute=[5, 3,4]) results4 = queryset.exclude(my_attribute=5)[0:10] results5 = queryset.count() # as of 2.0 you can now access an attribute to get the weight and similar arguments for result in results1: print result, result._sphinx # you can also access a similar set of meta data on the queryset itself (once it's been sliced or executed in any way) print results1._sphinx and Traceback (most recent call last): File "D:\zjm_code\sphinx_test\models.py", line 1, in <module> from django.db import models File "D:\Python25\Lib\site-packages\django\db\__init__.py", line 10, in <module> if not settings.DATABASE_ENGINE: File "D:\Python25\Lib\site-packages\django\utils\functional.py", line 269, in __getattr__ self._setup() File "D:\Python25\Lib\site-packages\django\conf\__init__.py", line 38, in _setup raise ImportError("Settings cannot be imported, because environment variable %s is undefined." % ENVIRONMENT_VARIABLE) ImportError: Settings cannot be imported, because environment variable DJANGO_SETTINGS_MODULE is undefined.

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• Django TemplateSyntaxError only on live server (templates exist)

  - by Tom

  I'm getting a strange error that only occurs on the live server. My Django templates directory is set up like so base.html two-column-base.html portfolio index.html extranet base.html index.html The portfolio pages work correctly locally on multiple machines. They inherit from either the root base.html or two-column-base.html. However, now that I've posted them to the live box (local machines are Windows, live is Linux), I get a TemplateSyntaxError: "Caught TemplateDoesNotExist while rendering: base.html" when I try to load any portfolio pages. It seems to be a case where the extends tag won't work in that root directory (???). Even if I do a direct_to_template on two-column-base.html (which extends base.html), I get that error. The extranet pages all work perfectly, but those templates all live inside the /extranet folder and inherit from /extranet/base.html. Possible issues I've checked: file permissions on the server are fine the template directory is correct on the live box (I'm using os.path.dirname(os.path.realpath(__file__)) to make things work across machines) files exist and the /templates directories exactly match my local copy removing the {% extends %} block from the top of any broken template causes the templates to render without a problem manually starting a shell session and calling get_template on any of the files works, but trying to render it blows up with the same exception on any of the extended templates. Doing the same with base.html, it renders perfectly (base.html also renders via direct_to_template) Django 1.2, Python 2.6 on Webfaction. Apologies in advance because this is my 3rd or 4th "I'm doing something stupid" question in a row. The only x-factor I can think of is this is my first time using Mercurial instead ofsvn. Not sure how I could have messed things up via that. EDIT: One possible source of problems: local machine is Python 2.5, live is 2.6. Here's a traceback of me trying to render 'two-column-base.html', which extends 'base.html'. Both files are in the same directory, so if it can find the first, it can find the second. c is just an empty Context object. >>> render_to_string('two-column-base.html', c) Traceback (most recent call last): File "<console>", line 1, in <module> File "/home/lightfin/webapps/django/lib/python2.6/django/template/loader.py", line 186, in render_to_string return t.render(context_instance) File "/home/lightfin/webapps/django/lib/python2.6/django/template/__init__.py", line 173, in render return self._render(context) File "/home/lightfin/webapps/django/lib/python2.6/django/template/__init__.py", line 167, in _render return self.nodelist.render(context) File "/home/lightfin/webapps/django/lib/python2.6/django/template/__init__.py", line 796, in render bits.append(self.render_node(node, context)) File "/home/lightfin/webapps/django/lib/python2.6/django/template/debug.py", line 72, in render_node result = node.render(context) File "/home/lightfin/webapps/django/lib/python2.6/django/template/loader_tags.py", line 103, in render compiled_parent = self.get_parent(context) File "/home/lightfin/webapps/django/lib/python2.6/django/template/loader_tags.py", line 100, in get_parent return get_template(parent) File "/home/lightfin/webapps/django/lib/python2.6/django/template/loader.py", line 157, in get_template template, origin = find_template(template_name) File "/home/lightfin/webapps/django/lib/python2.6/django/template/loader.py", line 138, in find_template raise TemplateDoesNotExist(name) TemplateSyntaxError: Caught TemplateDoesNotExist while rendering: base.html I'm wondering if this is somehow related to the template caching that was just added to Django. EDIT 2 (per lazerscience): template-related settings: import os PROJECT_ROOT = os.path.dirname(os.path.realpath(__file__)) TEMPLATE_DIRS = ( os.path.join(PROJECT_ROOT, 'templates'), ) sample view: def project_list(request, jobs, extra_context={}): context = { 'jobs': jobs, } print context context.update(extra_context) return render_to_response('portfolio/index.html', context, context_instance=RequestContext(request)) The templates in reverse-order are: http://thosecleverkids.com/junk/index.html http://thosecleverkids.com/junk/portfolio-base.html http://thosecleverkids.com/junk/two-column-base.html http://thosecleverkids.com/junk/base.html though in the real project the first two live in a directory called "portfolio".

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• Help a Python newbie with a Django model inheritance problem

  - by Joshmaker

  I'm working on my first real Django project after years of PHP programming, and I am running into a problem with my models. First, I noticed that I was copying and pasting code between the models, and being a diligent OO programmer I decided to make a parent class that the other models could inherit from: class Common(model.Model): self.name = models.CharField(max_length=255) date_created = models.DateTimeField(auto_now_add=True) date_modified = models.DateTimeField(auto_now=True) def __unicode__(self): return self.name class Meta: abstract=True So far so good. Now all my other models extend "Common" and have names and dates like I want. However, I have a class for "Categories" were the name has to be unique. I assume there should be a relatively simple way for me to access the name attribute from Common and make it unique. However, the different methods I have tried to use have all failed. For example: class Category(Common): def __init__(self, *args, **kwargs): self.name.unique=True Spits up the error "Caught an exception while rendering: 'Category' object has no attribute 'name' Can someone point me in the right direction?

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• Subclassed django models with integrated querysets

  - by outofculture

  Like in this question, except I want to be able to have querysets that return a mixed body of objects: >>> Product.objects.all() [<SimpleProduct: ...>, <OtherProduct: ...>, <BlueProduct: ...>, ...] I figured out that I can't just set Product.Meta.abstract to true or otherwise just OR together querysets of differing objects. Fine, but these are all subclasses of a common class, so if I leave their superclass as non-abstract I should be happy, so long as I can get its manager to return objects of the proper class. The query code in django does its thing, and just makes calls to Product(). Sounds easy enough, except it blows up when I override Product.__new__, I'm guessing because of the __metaclass__ in Model... Here's non-django code that behaves pretty much how I want it: class Top(object): _counter = 0 def __init__(self, arg): Top._counter += 1 print "Top#__init__(%s) called %d times" % (arg, Top._counter) class A(Top): def __new__(cls, *args, **kwargs): if cls is A and len(args) > 0: if args[0] is B.fav: return B(*args, **kwargs) elif args[0] is C.fav: return C(*args, **kwargs) else: print "PRETENDING TO BE ABSTRACT" return None # or raise? else: return super(A).__new__(cls, *args, **kwargs) class B(A): fav = 1 class C(A): fav = 2 A(0) # => None A(1) # => <B object> A(2) # => <C object> But that fails if I inherit from django.db.models.Model instead of object: File "/home/martin/beehive/apps/hello_world/models.py", line 50, in <module> A(0) TypeError: unbound method __new__() must be called with A instance as first argument (got ModelBase instance instead) Which is a notably crappy backtrace; I can't step into the frame of my __new__ code in the debugger, either. I have variously tried super(A, cls), Top, super(A, A), and all of the above in combination with passing cls in as the first argument to __new__, all to no avail. Why is this kicking me so hard? Do I have to figure out django's metaclasses to be able to fix this or is there a better way to accomplish my ends?

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• Odd behavior in Django Form (readonly field/widget)

  - by jamida

  I'm having a problem with a test app I'm writing to verify some Django functionality. The test app is a small "grade book" application that is currently using Alex Gaynor's readonly field functionality http://lazypython.blogspot.com/2008/12/building-read-only-field-in-django.html There are 2 problems which may be related. First, when I flop the comment on these 2 lines below: # myform = GradeForm(data=request.POST, instance=mygrade) myform = GradeROForm(data=request.POST, instance=mygrade) it works like I expect, except of course that the student field is changeable. When the comments are the shown way, the "studentId" field is displayed as a number (not the name, problem 1) and when I hit submit I get an error saying that studentId needs to be a Student instance. I'm at a loss as to how to fix this. I'm not wedded to Alex Gaynor's code. ANY code will work. I'm relatively new to both Python and Django, so the hints I've seen on websites that say "making a read-only field is easy" are still beyond me. // models.py class Student(models.Model): name = models.CharField(max_length=50) parent = models.CharField(max_length=50) def __unicode__(self): return self.name class Grade(models.Model): studentId = models.ForeignKey(Student) finalGrade = models.CharField(max_length=3) # testbed.grades.readonly is alex gaynor's code from testbed.grades.readonly import ReadOnlyField class GradeROForm(ModelForm): studentId = ReadOnlyField() class Meta: model=Grade class GradeForm(ModelForm): class Meta: model=Grade // views.py def modifyGrade(request,student): student = Student.objects.get(name=student) mygrade = Grade.objects.get(studentId=student) if request.method == "POST": # myform = GradeForm(data=request.POST, instance=mygrade) myform = GradeROForm(data=request.POST, instance=mygrade) if myform.is_valid(): grade = myform.save() info = "successfully updated %s" % grade.studentId else: # myform=GradeForm(instance=mygrade) myform=GradeROForm(instance=mygrade) return render_to_response('grades/modifyGrade.html',locals()) // template <p>{{ info }}</p> <form method="POST" action=""> <table> {{ myform.as_table }} </table> <input type="submit" value="Submit"> </form> // Alex Gaynor's code from django import forms from django.utils.html import escape from django.utils.safestring import mark_safe from django.forms.util import flatatt class ReadOnlyWidget(forms.Widget): def render(self, name, value, attrs): final_attrs = self.build_attrs(attrs, name=name) if hasattr(self, 'initial'): value = self.initial return mark_safe("<span %s>%s</span>" % (flatatt(final_attrs), escape(value) or '')) def _has_changed(self, initial, data): return False class ReadOnlyField(forms.FileField): widget = ReadOnlyWidget def __init__(self, widget=None, label=None, initial=None, help_text=None): forms.Field.__init__(self, label=label, initial=initial, help_text=help_text, widget=widget) def clean(self, value, initial): self.widget.initial = initial return initial

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• Simple Observation in Django: How Can I Correctly Modify The `attrs` sent to __new__ of a Django Mod

  - by DGGenuine

  Hello, I'm a strong proponent of the observer pattern, and this is what I'd like to be able to do in my Django models.py: class AModel(Model): __metaclass__ = SomethingMagical @post_save(AnotherModel) @classmethod def observe_another_model_saved(klass, sender, instance, created, **kwargs): pass @pre_init('YetAnotherModel') @classmethod def observe_yet_another_model_initializing(klass, sender, *args, **kwargs): pass @post_delete('DifferentApp.SomeModel') @classmethod def observe_some_model_deleted(klass, sender, **kwargs): pass This would connect a signal with sender = the decorator's argument and receiver = the decorated method. Right now my signal connection code all exists in __init__.py which is okay, but a little unmaintainable. I want this code all in one place, the models.py file. Thanks to helpful feedback from the community I'm very close (I think.) (I'm using a metaclass solution instead of the class decorator solution in the previous question/answer because you can't set attributes on classmethods, which I need.) I am having a strange error I don't understand. At the end of my post are the contents of a models.py that you can pop into a fresh project/application to see the error. Set your database to sqlite and add the application to installed apps. This is the error: Validating models... Unhandled exception in thread started by Traceback (most recent call last): File "/Library/Python/2.6/site-packages//lib/python2.6/site-packages/django/core/management/commands/runserver.py", line 48, in inner_run File "/Library/Python/2.6/site-packages/django/core/management/base.py", line 253, in validate raise CommandError("One or more models did not validate:\n%s" % error_text) django.core.management.base.CommandError: One or more models did not validate: local.myothermodel: 'my_model' has a relation with model MyModel, which has either not been installed or is abstract. I've indicated a few different things you can comment in/out to fix the error. First, if you don't modify the attrs sent to the metaclass's __new__, then the error does not arise. (Note even if you copy the dictionary element by element into a new dictionary, it still fails; only using the exact attrs dictionary works.) Second, if you reference the first model by class rather than by string, the error also doesn't arise regardless of what you do in __new__. I appreciate your help. I'll be githubbing the solution if and when it works. Maybe other people would enjoy a simplified way to use Django signals to observe application happenings. #models.py from django.db import models from django.db.models.base import ModelBase from django.db.models import signals import pdb class UnconnectedMethodWrapper(object): sender = None method = None signal = None def __init__(self, signal, sender, method): self.signal = signal self.sender = sender self.method = method def post_save(sender): return _make_decorator(signals.post_save, sender) def _make_decorator(signal, sender): def decorator(view): return UnconnectedMethodWrapper(signal, sender, view) return decorator class ConnectableModel(ModelBase): """ A meta class for any class that will have static or class methods that need to be connected to signals. """ def __new__(cls, name, bases, attrs): unconnecteds = {} ## NO WORK newattrs = {} for name, attr in attrs.iteritems(): if isinstance(attr, UnconnectedMethodWrapper): unconnecteds[name] = attr newattrs[name] = attr.method #replace the UnconnectedMethodWrapper with the method it wrapped. else: newattrs[name] = attr ## NO WORK # newattrs = {} # for name, attr in attrs.iteritems(): # newattrs[name] = attr ## WORKS # newattrs = attrs new = super(ConnectableModel, cls).__new__(cls, name, bases, newattrs) for name, unconnected in unconnecteds.iteritems(): _connect_signal(unconnected.signal, unconnected.sender, getattr(new, name), new._meta.app_label) return new def _connect_signal(signal, sender, receiver, default_app_label): # full implementation also accepts basestring as sender and will look up model accordingly signal.connect(sender=sender, receiver=receiver) class MyModel(models.Model): __metaclass__ = ConnectableModel @post_save('In my application this string matters') @classmethod def observe_it(klass, sender, instance, created, **kwargs): pass @classmethod def normal_class_method(klass): pass class MyOtherModel(models.Model): ## WORKS # my_model = models.ForeignKey(MyModel) ## NO WORK my_model = models.ForeignKey('MyModel')

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• django auth : strange error with authenticate()

  - by Rohit

  I am using authenticate() to authenticating users manually. Using admin interface I can see that there is no 'last_login' attribute for Users Debug traceback is : Environment: Request Method: GET Request URL: https://localhost/login/ Django Version: 1.1.1 Python Version: 2.6.5 Installed Applications: ['django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'django.contrib.admin', 'mobius.polls'] Installed Middleware: ('django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware') Traceback: File "/usr/lib/pymodules/python2.6/django/core/handlers/base.py" in get_response 92. response = callback(request, *callback_args, **callback_kwargs) File "/usr/lib/pymodules/python2.6/django/contrib/auth/__init__.py" in login 55. user.last_login = datetime.datetime.now() Exception Type: AttributeError at /login/ Exception Value: 'unicode' object has no attribute 'last_login' I cant figure out, why is there this discrepancy. Any kind of help would be appreciated. Thanks in advance!

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• Why was JavaScript Implemented Using Prototypal Inheritance?

  - by nickyt

  There's lots of articles and posts explaining how JavaScript inheritance works, but I'm curious why JavaScript was implemented using prototypal inheritance instead of classical inheritance. I love JavaScript so I'm not saying it's bad thing... I'm just curious.

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• is multiple inheritance a compiler writers problem? - c++

  - by Dr Deo

  i have been reading about multiple inheritance http://stackoverflow.com/questions/225929/what-is-the-exact-problem-with-multiple-inheritance http://en.wikipedia.org/wiki/Diamond_problem http://en.wikipedia.org/wiki/Virtual_inheritance http://en.wikipedia.org/wiki/Multiple_inheritance But since the code does not compile until the ambiguity is resolved, doesn't this make multiple inheritance a problem for compiler writers only? - how does this problem affect me in case i don't want to ever code a compiler

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• Confusion about inheritance

  - by Samuel Adam

  I know I might get downvoted for this, but I'm really curious. I was taught that inheritance is a very powerful polymorphism tool, but I can't seem to use it well in real cases. So far, I can only use inheritance when the base class is an abstract class. Examples : If we're talking about Product and Inventory, I quickly assumed that a Product is an Inventory because a Product must be inventorized as well. But a problem occured when user wanted to sell their Inventory item. It just doesn't seem to be right to change an Inventory object to it's subtype (Product), it's almost like trying to convert a parent to it's child. Another case is Customer and Member. It is logical (at least for me) to think that a Member is a Customer with some more privileges. Same problem occurred when user wanted to upgrade an existing Customer to become a Member. A very trivial case is the Employee case. Where Manager, Clerk, etc can be derived from Employee. Still, the same upgrading issue. I tried to use composition instead for some cases, but I really wanted to know if I'm missing something for inheritance solution here. My composition solution for those cases : Create a reference of Inventory inside a Product. Here I'm making an assumption about that Product and Inventory is talking in a different context. While Product is in the context of sales (price, volume, discount, etc), Inventory is in the context of physical management (stock, movement, etc). Make a reference of Membership instead inside Customer class instead of previous inheritance solution. Therefor upgrading a Customer is only about instantiating the Customer's Membership property. This example is keep being taught in basic programming classes, but I think it's more proper to have those Manager, Clerk, etc derived from an abstract Role class and make it a property in Employee. I found it difficult to find an example of a concrete class deriving from another concrete class. Is there any inheritance solution in which I can solve those cases? Being new in this OOP thing, I really really need a guidance. Thanks!

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• Installing Django on Shared Server: No module named MySQLdb?

  - by Mark

  I'm getting this error Traceback (most recent call last): File "/home/<username>/flup/server/fcgi_base.py", line 558, in run File "/home/<username>/flup/server/fcgi_base.py", line 1116, in handler File "/home/<username>/python/django/django/core/handlers/wsgi.py", line 241, in __call__ response = self.get_response(request) File "/home/<username>/python/django/django/core/handlers/base.py", line 73, in get_response response = middleware_method(request) File "/home/<username>/python/django/django/contrib/sessions/middleware.py", line 10, in process_request engine = import_module(settings.SESSION_ENGINE) File "/home/<username>/python/django/django/utils/importlib.py", line 35, in import_module __import__(name) File "/home/<username>/python/django/django/contrib/sessions/backends/db.py", line 2, in ? from django.contrib.sessions.models import Session File "/home/<username>/python/django/django/contrib/sessions/models.py", line 4, in ? from django.db import models File "/home/<username>/python/django/django/db/__init__.py", line 41, in ? backend = load_backend(settings.DATABASE_ENGINE) File "/home/<username>/python/django/django/db/__init__.py", line 17, in load_backend return import_module('.base', 'django.db.backends.%s' % backend_name) File "/home/<username>/python/django/django/utils/importlib.py", line 35, in import_module __import__(name) File "/home/<username>/python/django/django/db/backends/mysql/base.py", line 13, in ? raise ImproperlyConfigured("Error loading MySQLdb module: %s" % e) ImproperlyConfigured: Error loading MySQLdb module: No module named MySQLdb when I try to run this script on my shared server #!/usr/bin/python import sys, os sys.path.insert(0, "/home/<username>/python/django") sys.path.insert(0, "/home/<username>/python/django/www") # projects directory os.chdir("/home/<username>/python/django/www/<project>") os.environ['DJANGO_SETTINGS_MODULE'] = "<project>.settings" from django.core.servers.fastcgi import runfastcgi runfastcgi(method="threaded", daemonize="false") But, my web host just installed MySQLdb for me a few hours ago. When I run python from the shell I can import MySQLdb just fine. Why would this script report that it can't find it?

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• Django deployment - can't import app.urls

  - by hora

  I just moved a django project to a deployment server from my dev server, and I'm having some issues deploying it. My apache config is as follows: <Location "/"> Order allow,deny Allow from all SetHandler python-program PythonHandler django.core.handlers.modpython SetEnv DJANGO_SETTINGS_MODULE project.settings PythonDebug On PythonPath "['/home/django/'] + sys.path" </Location> Django does work, since it renders the Django debug views, but I get the following error: ImportError at / No module named app.urls And here is all the information Django gives me: Request Method: GET Request URL: http://myserver.com/ Django Version: 1.1.1 Python Version: 2.6.5 Installed Applications: ['django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'django.contrib.admin', 'django.contrib.admindocs', 'project.app'] Installed Middleware: ('django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware') Traceback: File "/usr/lib64/python2.6/site-packages/django/core/handlers/base.py" in get_response 83. request.path_info) File "/usr/lib64/python2.6/site-packages/django/core/urlresolvers.py" in resolve 218. sub_match = pattern.resolve(new_path) File "/usr/lib64/python2.6/site-packages/django/core/urlresolvers.py" in resolve 216. for pattern in self.url_patterns: File "/usr/lib64/python2.6/site-packages/django/core/urlresolvers.py" in _get_url_patterns 245. patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module) File "/usr/lib64/python2.6/site-packages/django/core/urlresolvers.py" in _get_urlconf_module 240. self._urlconf_module = import_module(self.urlconf_name) File "/usr/lib64/python2.6/site-packages/django/utils/importlib.py" in import_module 35. __import__(name) Exception Type: ImportError at / Exception Value: No module named app.urls Any ideas as to why I get an import error?

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• In django changing the file name of uploading file.

  - by Software Enthusiastic

  Hi Is it possible to change the file name of the uploading file in the django? I searched, but couldn't find any answer. My requirement is whenever a file is uploaded its file name should be changed in the following format. format = userid + transaction_uuid + file_extension Thank yo very much...

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• Django "comment_was_flagged" signal

  - by tsoporan

  Hello, This is my first time working with django signals and I would like to hook the "comment_was_flagged" signal provided by the comments app to notify me when a comment is flagged. This is my code, but it doesn't seem to work, am I missing something? from django.contrib.comments.signals import comment_was_flagged from django.core.mail import send_mail def comment_flagged_notification(sender, **kwargs): send_mail('testing moderation', 'testing', 'test@localhost', ['[email protected]',]) comment_was_flagged.connect(comment_flagged_notification) (I am just testing the email for now, but I have assured the email is sending properly.) Thanks!

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• django-multilingual and switching between languages on template side

  - by israkir

  I am trying to use django-multilingual and setup it properly. But what I found is that everything is clear for django-multilingual except a template usage example. I just started to use django and I don't know, maybe because of this reason, I cannot figure out how to switch between languages on template side. Is there any example that you can give or any 'more' clear source/documentation about this?

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• Edit/show Primary Key in Django Admin

  - by emcee

  It appears Django hides fields that are flagged Primary Key from being displayed/edited in the Django admin interface. Let's say I'd like to input data in which I may or may not want to specify a primary key. How would I go about displaying primary keys in Django-admin, and how could I make specifying it optional? Many thanks in advance, beloved hive-mind.

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• Django Admin Actions missing

  - by Andrew C

  One of my Django sites is missing the Django Admin Action bar shown here: http://docs.djangoproject.com/en/dev/ref/contrib/admin/actions/#ref-contrib-admin-actions There is no checkbox next to each row and no Action select box near the top of the page. This is happening on every model. I have several sites running Django 1.1, and they all show the Admin Actions, so it feels like a local configuration issue. Anyone seen this before?

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• user inheritance in django

  - by amateur

  Hi guys, I saw a couple of ways extending user information of users and decided to adopt the model inheritance method. for instance, I have : class Parent(User): contact_means = models.IntegerField() is_staff = False objects = userManager() Now it is done, I've downloaded django_registration to help me out with sending emails to new users. The thing is, instead of using registration forms to register new user, I want to to invoke the email sending/acitvation capability of django_registration. So my workflow is: 1. add new Parent object in admin page. 2. send email My problem is, the django-registration creates a new registration profile together with a new user in the user table. how do I tweak this such that I am able to add the user entry into the custom user table. I have tried to create a modelAdmin and alter the save_model method to launch the create_inactive_user from django_registration, however I do not how to save the user object generated from django_registration into my Parent table when I have using model inheritance and I do not have a Foreign key attribute in my parent model.

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• Django authentication in django nonrel on GAE

  - by tooba

  I'm using the Django nonrel project on a google app engine project running locally in development. I've created my own models and these are fine when they are saved and retrieved in the datastore. I'm hoping to use django.contrib.auth to provide the user functionality. I can use the shell to create users and these get assigned an ID. When I create one of my own models which references User I have to pass in a user ID as it quite rightly fails otherwise. However, checking via the gae admin interface I can't see the User model in the datastore for the users I've created via the shell. Nor can I retreive the user details from one of my models which references them. Calls to mymodel.user.username return nothing. Nor can I log into admin using the username and password I've set up. I can see saved versions of the models I've made in the gae admin app. I get the impression that users are being created somewhere other than the datastore. Is there something else I need to do to use the standard contrib.auth users with django-nonrel and gae?

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• How do I find the "concrete class" of a django model baseclass

  - by Mr Shark

  I'm trying to find the actual class of a django-model object, when using model-inheritance. Some code to describe the problem: class Base(models.model): def basemethod(self): ... class Child_1(Base): pass class Child_2(Base): pass If I create various objects of the two Child classes and the create a queryset containing them all: Child_1().save() Child_2().save() (o1, o2) = Base.objects.all() I want to determine if the object is of type Child_1 or Child_2 in basemethod, I can get to the child object via o1.child_1 and o2.child_2 but that reconquers knowledge about the childclasses in the baseclass. I have come up with the following code: def concrete_instance(self): instance = None for subclass in self._meta.get_all_related_objects(): acc_name = subclass.get_accessor_name() try: instance = self.__getattribute__(acc_name) return instance except Exception, e: pass But it feels brittle and I'm not sure of what happens when if I inherit in more levels.

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• PyDev and Django: PyDev breaking Django shell?

  - by Rosarch

  I've set up a new project, and populated it with simple models. (Essentially I'm following the tut.) When I run python manage.py shell on the command line, it works fine: >python manage.py shell Python 2.6.4 (r264:75708, Oct 26 2009, 08:23:19) [MSC v.1500 32 bit (Intel)] on win32 Type "help", "copyright", "credits" or "license" for more information. (InteractiveConsole) >>> from mysite.myapp.models import School >>> School.objects.all() [] Works great. Then, I try to do the same thing in Eclipse (using a Django project that is composed of the same files.) Right click on mysite project Django Shell with Django environment This is the output from the PyDev Console: >>> import sys; print('%s %s' % (sys.executable or sys.platform, sys.version)) C:\Python26\python.exe 2.6.4 (r264:75708, Oct 26 2009, 08:23:19) [MSC v.1500 32 bit (Intel)] >>> >>> from django.core import management;import mysite.settings as settings;management.setup_environ(settings) 'path\\to\\mysite' >>> from mysite.myapp.models import School >>> School.objects.all() Traceback (most recent call last): File "<console>", line 1, in <module> File "C:\Python26\lib\site-packages\django\db\models\query.py", line 68, in __repr__ data = list(self[:REPR_OUTPUT_SIZE + 1]) File "C:\Python26\lib\site-packages\django\db\models\query.py", line 83, in __len__ self._result_cache.extend(list(self._iter)) File "C:\Python26\lib\site-packages\django\db\models\query.py", line 238, in iterator for row in self.query.results_iter(): File "C:\Python26\lib\site-packages\django\db\models\sql\query.py", line 287, in results_iter for rows in self.execute_sql(MULTI): File "C:\Python26\lib\site-packages\django\db\models\sql\query.py", line 2368, in execute_sql cursor = self.connection.cursor() File "C:\Python26\lib\site-packages\django\db\backends\__init__.py", line 81, in cursor cursor = self._cursor() File "C:\Python26\lib\site-packages\django\db\backends\sqlite3\base.py", line 170, in _cursor self.connection = Database.connect(**kwargs) OperationalError: unable to open database file What am I doing wrong here?

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• Django: UserProfile with Unique Foreign Key in Django Admin

  - by lazerscience

  Hi, I have extended Django's User Model using a custom user profile called UserExtension. It is related to User through a unique ForeignKey Relationship, which enables me to edit it in the admin in an inline form! I'm using a signal to create a new profile for every new user: def create_user_profile(sender, instance, created, **kwargs): if created: try: profile, created = UserExtension.objects.get_or_create(user=instance) except: pass post_save.connect(create_user_profile, sender=User) (as described here for example: http://stackoverflow.com/questions/44109/extending-the-user-model-with-custom-fields-in-django) The problem is, that, if I create a new user through the admin, I get an IntegritiyError on saving "column user_id is not unique". It doesnt seem that the signal is called twice, but i guess the admin is trying to save the profile AFTERWARDS? But I need the creation through signal if I create a new user in other parts of the system!

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