Search Results

Search found 1393 results on 56 pages for 'employee'.

Page 4/56 | < Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >

  • Full Time Employee versus Contract Work?

    - by Elijah Manor
    What types of programmers tend to be attracted to full-time positions and what types are drawn to contract positions? Which type are you, and have you swapped between one to another? Does there come a time in a programmer's life when he/she typically switches from one to another? Do you find one more challenging than the other?

    Read the article

  • Little Employee/Shift timetable HELP!!!

    - by DAVID
    Morning Guys, I have the following tables: operator(ope_id, ope_name) ope_shift(ope_id, shift_id, shift_date) shift(shift_id, shift_start, shift_end) here is a better view of the data http://latinunit.net/emp_shift.txt here is the screenshot of a select statement to the tables http://img256.imageshack.us/img256/4013/opeshift.jpg im using this code SELECT OPE_ID, COUNT(OPE_ID) AS Total_shifts from operator_shift group by ope_id; to view the current total shifts per operator and it works, BUT if there was 500 more rows it would count them all aswell, THE QUESTION is, anyone has a better way of making my database work, or how can i tell the system that those rows are a whole month, i remember i friend said something about count then devide by 30 but im not sure, what if the month isnt finished? and you want to show the emp with highest shifts to date

    Read the article

  • Digital clocking systems/software? (employee clocking)

    - by Bill
    How does a digital clocking system deal with user error such as someone forgetting to clock out or someone erroneously entering their code causing them to clock someone else in/out (who might not even be on the schedule that day). Its obvious there could be issues of dishonesty, but what about human error?

    Read the article

  • Easy way to update models in your ASP.NET MVC business layer

    - by rajbk
    Brad Wilson just mentioned there is a static class ModelCopier that has a static method CopyModel(object from, object to) in the MVC Futures library. It uses reflection to match properties with the same name and compatible types. In short, instead of manually copying over properties as shown here: public void Save(EmployeeViewModel employeeViewModel){ var employee = (from emp in dataContext.Employees where emp.EmployeeID == employeeViewModel.EmployeeID select emp).SingleOrDefault(); if (employee != null) { employee.Address = employeeViewModel.Address; employee.Salary = employeeViewModel.Salary; employee.Title = employeeViewModel.Title; } dataContext.SubmitChanges();} you can use the method like so: public void Save(EmployeeViewModel employeeViewModel){ var employee = (from emp in dataContext.Employees where emp.EmployeeID == employeeViewModel.EmployeeID select emp).SingleOrDefault(); if (employee != null) { ModelCopier.CopyModel(employeeViewModel, employee); } dataContext.SubmitChanges();} Beautiful, isn’t it?

    Read the article

  • Validation not bubbling up to my other models.

    - by DJTripleThreat
    Ok, I have a relationship between People, Users and Employees such that All Employees are Users and all Users are People. Person is an abstract class that User is derived from and Employee is derived from that. Now... I have an EmployeesController class and the create method looks like this: def create @employee = Employee.new(params[:employee]) @employee.user = User.new(params[:user]) @employee.user.person = Person.new(params[:person]) respond_to do |format| if @employee.save flash[:notice] = 'Employee was successfully created.' format.html { redirect_to(@employee) } format.xml { render :xml => @employee, :status => :created, :location => @employee } else format.html { render :action => "new" } format.xml { render :xml => @employee.errors, :status => :unprocessable_entity } end end end As you can see, when I'm using the :polymorphic => true clause, the way you access the super class is by doing something like @derived_class_variable.super_class_variable.super_super_etc. The Person class has a validates_presence_of :first_name and when it is satisfied, on my form, everything is OK. However, if I leave out the first name, it won't prevent the employee from being saved. What happens is that the employee record is saved but the person record isn't (because of the validation). How can I get the validation errors to show up in the flash object?

    Read the article

  • Employee Info Starter Kit (v4.0.0) - Visual Studio 2010 and .NET 4.0 Version is Available Now

    Employee Info Starter Kit is a ASP.NET based web application, which includes very simple user requirements, where we can create, read, update and delete (crud) the employee info of a company. Based on just a database table, it explores and solves most of the major problems in web development architectural space.  This open source starter kit extensively uses major features available in latest Visual Studio, ASP.NET and Sql Server to make robust, scalable, secured and maintainable web applications...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

    Read the article

  • C# Design Questions

    - by guazz
    How to approach unit testing of private methods? I have a class that loads Employee data into a database. Here is a sample: public class EmployeeFacade { public Employees EmployeeRepository = new Employees(); public TaxDatas TaxRepository = new TaxDatas(); public Accounts AccountRepository = new Accounts(); //and so on for about 20 more repositories etc. public bool LoadAllEmployeeData(Employee employee) { if (employee == null) throw new Exception("..."); EmployeeRepository emps = new EmployeeRepository(); bool exists = emps.FetchExisting(emps.Id); if (!exists) { emps.AddNew(); } try { emps.Id = employee.Id; emps.Name = employee.EmployeeDetails.PersonalDetails.Active.Names.FirstName; emps.SomeOtherAttribute; } catch() {} try { emps.Save(); } catch(){} try { LoadorUpdateTaxData(employee.TaxData); } catch() {} try { LoadorUpdateAccountData(employee.AccountData); } catch() {} ... etc. for about 20 more other employee objects } private bool LoadorUpdateTaxData(employeeId, TaxData taxData) { if (taxData == null) throw new Exception("..."); ...same format as above but using AccountRepository } private bool LoadorUpdateAccountData(employee.TaxData) { ...same format as above but using TaxRepository } } I am writing an application to take serialised objects(e.g. Employee above) and load the data to the database. I have a few design question that I would like opinions on: A - I am calling this class "EmployeeFacade" because I am (attempting?) to use the facade pattern. Is it good practace to name the pattern on the class name? B - Is it good to call the concrete entities of my DAL layer classes "Repositories" e.g. "EmployeeRepository" ? C - Is using the repositories in this way sensible or should I create a method on the repository itself to take, say, the Employee and then load the data from there e.g. EmployeeRepository.LoadAllEmployeeData(Employee employee)? I am aim for cohesive class and but this will requrie the repository to have knowledge of the Employee object which may not be good? D - Is there any nice way around of not having to check if an object is null at the begining of each method? E - I have a EmployeeRepository, TaxRepository, AccountRepository declared as public for unit testing purpose. These are really private enities but I need to be able to substitute these with stubs so that the won't write to my database(I overload the save() method to do nothing). Is there anyway around this or do I have to expose them? F - How can I test the private methods - or is this done (something tells me it's not)? G- "emps.Name = employee.EmployeeDetails.PersonalDetails.Active.Names.FirstName;" this breaks the Law of Demeter but how do I adjust my objects to abide by the law?

    Read the article

  • Delete duplicate records from a SQL table without a primary key

    - by Shyju
    I have the below table with the below records in it create table employee ( EmpId number, EmpName varchar2(10), EmpSSN varchar2(11) ); insert into employee values(1, 'Jack', '555-55-5555'); insert into employee values (2, 'Joe', '555-56-5555'); insert into employee values (3, 'Fred', '555-57-5555'); insert into employee values (4, 'Mike', '555-58-5555'); insert into employee values (5, 'Cathy', '555-59-5555'); insert into employee values (6, 'Lisa', '555-70-5555'); insert into employee values (1, 'Jack', '555-55-5555'); insert into employee values (4, 'Mike', '555-58-5555'); insert into employee values (5, 'Cathy', '555-59-5555'); insert into employee values (6 ,'Lisa', '555-70-5555'); insert into employee values (5, 'Cathy', '555-59-5555'); insert into employee values (6, 'Lisa', '555-70-5555'); I dont have any primary key in this table .But i have the above records in my table already. I want to remove the duplicate records which has the same value in EmpId and EmpSSN fields. Ex : Emp id 5 Can any one help me to frame a query to delete those duplicate records Thanks in advance

    Read the article

  • Fluent Nhibernate Mapping Single class on two database tables

    - by nabeelfarid
    Hi guys, I am having problems with Mapping. I have two tables in my database as follows: Employee and EmployeeManagers Employee EmployeeId int Name nvarchar EmployeeManagers EmployeeIdFk int ManagerIdFk int So the employee can have 0 or more Managers. A manager itself is also an Employee. I have the following class to represent the Employee and Managers public class Employee { public virtual int Id { get; set; } public virtual string Name { get; set; } public virtual IList<Employee> Managers { get; protected set; } public Employee() { Managers = new List<Employee>(); } } I don't have any class to represent Manager because I think there is no need for it, as Manager itself is an Employee. I am using autoMapping and I just can't figure out how to map this class to these two tables. I am implementing IAutoMappingOverride for overriding automappings for Employee but I am not sure what to do in it. public class NodeMap : IAutoMappingOverride { public void Override(AutoMapping<Node> mapping) { //mapping.HasMany(x => x.ValidParents).Cascade.All().Table("EmployeeManager"); //mapping.HasManyToMany(x => x.ValidParents).Cascade.All().Table("EmployeeManager"); } } I also want to make sure that an employee can not be assigned the same manager twice. This is something I can verify in my application but I would like to put constraint on the EmployeeManager table (e.g. a composite key) so a same manager can not be assigned to an employee more than once. Could anyone out there help me with this please? Awaiting Nabeel

    Read the article

  • JPA 2?EJB 3.1?JSF 2????????! WebLogic Server 12c?????????Java EE 6??????|WebLogic Channel|??????

    - by ???02
    2012?2???????????????WebLogic Server 12c?????????Java EE 6?????????????????????????????????????????????????????????????Oracle Enterprise Pack for Eclipse 12c??WebLogic Server 12c(???)????Java EE 6??????3??????????????????????????????JPA 2.0??????????·?????????EJB 3.1???????·???????????????(???)???????O/R?????????????JPA 2.0 Java EE 6????????????????????Web?????????????3?????(3????)???????·????????????·????????????????????????????????JPA(Java Persistence API) 2.0???EJB(Enterprise JavaBeans) 3.1???JSF(JavaServer Faces) 2.0????3????????????????·???????????JPA??Java??????????????·?????????????O/R?????????????????????·???????????EJB?Session Bean??????????????????·??????????????????????JSF??????????????????????????????????????? ??????JPA????Oracle Database??EMPLOYEES?????Java??????????????????????Entity Bean??????XML?????????????????????????XML????????????????????????????????????????????????????·?????????????????????????????????????????????????????????????Java EE 6??????JPA 2.0??????????·???????????????????????????????????????????????????????????????????????????????????????? ?????????????????????????????????????????????????????????????Oracle Enterprise Pack for Eclipse(OEPE)??????File????????New?-?Other??????? ??????New??????????????????????????Web?-?Dynamic Web Project???????Next????????????????Dynamic Web Project?????????????Project name????OOW???????????Target Runtime????New Runtime????????? ???New Server Runtime Environment???????????????Oracle?-?Oracle WebLogic Server 12c(12.1.1)???????Next???????????????????????????WebLogic home????C:\Oracle\Middleware\wlserver_12.1???????Finish?????????????WebLogic Home????????????????????????Java home?????????????????????Finish??????????????????????Dynamic Web Project????????????????Finish??????????????????JPA 2.0??????????·?????? ???????????????JPA 2.0???????????????·??????????????????Eclipse??Project Explorer?(??????·???)?????????OOW?????????????????????????????·???????????????Properties?????????????????·???·????????????????????????????Project Facets?????????????JPA??????(?????????????Details?????JPA 2.0?????????????????????)???????????????????Further configuration available????????? ???Modify Faceted Project??????????????????????????????????Connection????????????????????????????Add Connection????????? ??????New Connection Profile????????????????Connection Profile Type????Oracle Database Connection??????Next???????????? ???Specify a Driver and Connection Details???????Drivers????Oracle Database 10g Driver Default???????????Properties?????????????????????SIDxeHostlocalhostPort number1521User nameHRPasswordhr ???????????Test Connection??????????????????Ping Succeeded!?????????????????????????????Finish???????????Modify Faceted Project????????OK????????????????Properties for OOW????????OK?????????????????? ?????????Eclipse????????????????OOW?????????????????·???????????????JPA Tools?-?Generate Entities from Tables...??????? ????Generate Custom Entities???????????????????????????????Schema????HR??????Tables????EMPLOYEES???????????Next???????????? ???????????Next???????????Customize Default Entity Generation??????Package????model???????Finish?????????????JPQL?????????? ?????????Oracle Database??EMPLOYEES??????????????????·????model.Employee.java?????????????????????????????????·?????OOW????Java Resources?-?src?-?model???????Employee.java????????????????????????????????·???Employee????(Employee.java)?package model; import java.io.Serializable; import java.math.BigDecimal; import java.util.Date; import java.util.Set; import javax.persistence.Column;<...?...>/**  * The persistent class for the EMPLOYEES database table.  *  */ @Entity  // ?@Table(name="EMPLOYEES")  // ?// Apublic class Employee implements Serializable {        private static final long serialVersionUID = 1L;       @Id  // ?       @Column(name="EMPLOYEE_ID")        private long employeeId;        @Column(name="COMMISSION_PCT")        private BigDecimal commissionPct;        @Column(name="DEPARTMENT_ID")        private BigDecimal departmentId;        private String email;        @Column(name="FIRST_NAME")        private String firstName;       @Temporal( TemporalType.DATE)  //?       @Column(name="HIRE_DATE")        private Date hireDate;        @Column(name="JOB_ID")        private String jobId;        @Column(name="LAST_NAME")        private String lastName;        @Column(name="PHONE_NUMBER")        private String phoneNumber;        private BigDecimal salary;        //bi-directional many-to-one association to Employee<...?...>}  ???????????????·???????????????????????????????????????????@Table(name="")??????@Table??????????????????????????????????????? ?????????????????????????????????????·???????????????? ?????????????????????????????SQL?Data?????????? ???????????????A?????JPA?????????JPQL(Java Persistence Query Language)?????????????JPQL?????SQL???????????????????????????????????????????????????????????????????????????????????Employee.selectByNameEmployee??firstName????????????????????employeeId????????? ?????????????????????import java.util.Date;import java.util.Set;import javax.persistence.Column;<...?...>/**  * The persistent class for the EMPLOYEES database table.  *  */ @Entity  // ?@Table(name="EMPLOYEES")  // ?@NamedQueries({       @NamedQuery(name="Employee.selectByName" , query="select e from Employee e where e.firstName like :name order by e.employeeId")})<...?...> ?????????·??????OOW?-?JPA Content?-?persistent.xml??????Connection???????????????Database????JTA data source:???jdbc/test????????????????????????Java EE 6??????JPA 2.0???????????????????????????????????·??????????????????????????????????????SQL????????????????????????·????????????·??????????????XML??????????????????1??????????????????????????????????????????????????????????????????EJB 3.1????????·???????????EJB 3.1????????·?????????????????EJB 3.1?Stateless Session Bean?????·????????????????·???????????????????·??????????????????? EJB3.1?????JPA 2.0???????????·???????????????????????XML???????????????????????????????EJB 3.1?????????·????EJB?????????????????????????????????????????????????????????????? ????????EJB 3.1?Session Bean?????·????????????????????????????????????????????????????public List<Employee> getEmp(String keyword)firstName????????????Employee?????? ????????????????????·???????????OOW????????????·???????????????New?-?Other???????????????????????????????????EJB?-?Session Bean(EJB 3.x)??????NEXT????????????????????Create EJB 3.x Session Bean?????????????Java Package????ejb???class name????EmpLogic???????????State Type????Stateless?????????No-interface???????????????????????Finish???????????? ?????????Stateless Session Bean??????·?????EmpLogic.java????????????????????EmpLogic????·????????EJB?????????????Stateless Session Bean?????????@Stateless?????????????????????????????????????EmpLogic????(EmpLogic.java)?package ejb;import javax.ejb.LocalBean;import javax.ejb.Stateless;<...?...>import model.Employee;@Stateless@LocalBeanpublic class EmpLogic {       public EmpLogic() {       }} ??????????????????????????????????????·???????????????????????import??????????????????EmpLogic??????????????????????????·???????????????????????import????????(EmpLogic.java)?package ejb;import javax.ejb.LocalBean;import javax.ejb.Stateless;import javax.persistence.EntityManager;  // ?import javax.persistence.PersistenceContext;  // ?<...?...>import model.Employee;@Stateless@LocalBeanpublic class EmpLogic {      @PersistenceContext(unitName = "OOW")  // ?      private EntityManager em;  // ?       public EmpLogic() {       }} ?????????·???????JPA???????????????????·????????????????????????????CRUD???????????????????·????????????EntityManager???????????????????????????1????????????????·???????????????????????@PersistenceContext?????unitName?????????????persistence.xml????persistence-unit???name?????????????? ???????EmpLogic?????·???????????????????????????????????????????????????????????????????????????????EmpLogic????????·???????(EmpLogic.java)?package ejb;import java.util.List;  // ? import javax.ejb.LocalBean;import javax.ejb.Stateless;import javax.persistence.EntityManager;  // ? import javax.persistence.PersistenceContext;  // ? <...?...>import model.Employee;@Stateless@LocalBeanpublic class EmpLogic {       @PersistenceContext(unitName = "OOW")  // ?        private EntityManager em;  // ?        public EmpLogic() {       }      @SuppressWarnings("unchecked")  // ?      public List<Employee> getEmp(String keyword) {  // ?             StringBuilder param = new StringBuilder();  // ?             param.append("%");  // ?             param.append(keyword);  // ?             param.append("%");  // ?             return em.createNamedQuery("Employee.selectByName")  // ?                    .setParameter("name", param.toString()).getResultList();  // ?      }} ???EJB 3.1???Stateless Session Bean?????????? ???JSF 2.0???????????????????????????????????????????????????JAX-RS????RESTful?Web??????????????????????

    Read the article

  • What rights does an employer have to the employee's computer?

    - by Terrence Brannon
    What access rights should an employee grant an employer for a work computer? For instance, let's assume that the business people come to the IT lab late at night for discussions with the CIO and they use my computer for reading email and general web surfing. In a sense, this means that they are taking full or partial responsibility for any security issues that crop up that get traced back to the employee's machine. Perhaps the proper way to provide a computer to an employee is to give him full and exclusive use of it while employed. Only supervised access (such as hardware/software maintenance) should be acceptable.

    Read the article

  • NHibernate mapping error SQL Server 2008 Express

    - by developer
    Hi All, I tried an example from NHibernate in Action book and when I try to run the app, it throws an exception saying "Could not compile the mapping document: HelloNHibernate.Employee.hbm.xml" Below is my code, Employee.hbm.xml <?xml version="1.0" encoding="utf-8" ?> <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" auto-import="true"> <class name="HelloNHibernate.Employee, HelloNHibernate" lazy="false" table="Employee"> <id name="id" access="field"> <generator class="native"/> </id> <property name="name" access="field" column="name"/> <many-to-one access="field" name="manager" column="manager" cascade="all"/> </class> Program.cs using System; using System.Collections.Generic; using System.Linq; using System.Text; using NHibernate; using System.Reflection; using NHibernate.Cfg; namespace HelloNHibernate { class Program { static void Main(string[] args) { CreateEmployeeAndSaveToDatabase(); UpdateTobinAndAssignPierreHenriAsManager(); LoadEmployeesFromDatabase(); Console.WriteLine("Press any key to exit..."); Console.ReadKey(); } static void CreateEmployeeAndSaveToDatabase() { Employee tobin = new Employee(); tobin.name = "Tobin Harris"; using (ISession session = OpenSession()) { using (ITransaction transaction = session.BeginTransaction()) { session.Save(tobin); transaction.Commit(); } Console.WriteLine("Saved Tobin to the database"); } } static ISession OpenSession() { if (factory == null) { Configuration c = new Configuration(); c.AddAssembly(Assembly.GetCallingAssembly()); factory = c.BuildSessionFactory(); } return factory.OpenSession(); } static void LoadEmployeesFromDatabase() { using (ISession session = OpenSession()) { IQuery query = session.CreateQuery("from Employee as emp order by emp.name asc"); IList<Employee> foundEmployees = query.List<Employee>(); Console.WriteLine("\n{0} employees found:", foundEmployees.Count); foreach (Employee employee in foundEmployees) Console.WriteLine(employee.SayHello()); } } static void UpdateTobinAndAssignPierreHenriAsManager() { using (ISession session = OpenSession()) { using (ITransaction transaction = session.BeginTransaction()) { IQuery q = session.CreateQuery("from Employee where name='Tobin Harris'"); Employee tobin = q.List<Employee>()[0]; tobin.name = "Tobin David Harris"; Employee pierreHenri = new Employee(); pierreHenri.name = "Pierre Henri Kuate"; tobin.manager = pierreHenri; transaction.Commit(); Console.WriteLine("Updated Tobin and added Pierre Henri"); } } } static ISessionFactory factory; } } Employee.cs using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace HelloNHibernate { class Employee { public int id; public string name; public Employee manager; public string SayHello() { return string.Format("'Hello World!', said {0}.", name); } } } App.config <?xml version="1.0" encoding="utf-8" ?> <configuration> <configSections> <section name="hibernate-configuration" type="NHibernate.Cfg.ConfigurationSectionHandler,NHibernate"/> </configSections> <hibernate-configuration xmlns="urn:nhibernate-configuration-2.2"> <session-factory> <property name="connection.provider">NHibernate.Connection.DriverConnectionProvider</property> <property name="connection.driver_class">NHibernate.Driver.SqlClientDriver</property> <property name="connection.connection_string"> Data Source=SQLEXPRESS2008;Integrated Security=True; User ID=SQL2008;Password=;initial catalog=HelloNHibernate </property> <property name="dialect">NHibernate.Dialect.MsSql2008Dialect</property> <property name="show_sql">false</property> </session-factory> </hibernate-configuration> </configuration>

    Read the article

  • How to minimize the risk of employees spreading critical information?

    - by Industrial
    Hi everyone, What's common sense when it comes to minimising the risk of employees spreading critical information to rivalling companies? As of today, it's clear that not even the US government and military can be sure that their data stays safely within their doors. Thereby I understand that my question probably instead should be written as "What is common sense to make it harder for employees to spread business critical information?" If anyone would want to spread information, they will find a way. That's the way life work and always has. If we make the scenario a bit more realistic by narrowing our workforce by assuming we only have regular John Does onboard and not Linux-loving sysadmins , what should be good precautions to at least make it harder for the employees to send business-critical information to the competition? As far as I can tell, there's a few obvious solutions that clearly has both pros and cons: Block services such as Dropbox and similar, preventing anyone to send gigabytes of data through the wire. Ensure that only files below a set size can be sent as email (?) Setup VLANs between departments to make it harder for kleptomaniacs and curious people to snoop around. Plug all removable media units - CD/DVD, Floppy drives and USB Make sure that no configurations to hardware can be made (?) Monitor network traffic for non-linear events (how?) What is realistic to do in a real world? How does big companies handle this? Sure, we can take the former employer to court and sue, but by then the damage has already been caused... Thanks a lot

    Read the article

  • How to minimize the risk of employees spreading critical information? [closed]

    - by Industrial
    What's common sense when it comes to minimising the risk of employees spreading critical information to rivalling companies? As of today, it's clear that not even the US government and military can be sure that their data stays safely within their doors. Thereby I understand that my question probably instead should be written as "What is common sense to make it harder for employees to spread business critical information?" If anyone would want to spread information, they will find a way. That's the way life work and always has. If we make the scenario a bit more realistic by narrowing our workforce by assuming we only have regular John Does onboard and not Linux-loving sysadmins , what should be good precautions to at least make it harder for the employees to send business-critical information to the competition? As far as I can tell, there's a few obvious solutions that clearly has both pros and cons: Block services such as Dropbox and similar, preventing anyone to send gigabytes of data through the wire. Ensure that only files below a set size can be sent as email (?) Setup VLANs between departments to make it harder for kleptomaniacs and curious people to snoop around. Plug all removable media units - CD/DVD, Floppy drives and USB Make sure that no configurations to hardware can be made (?) Monitor network traffic for non-linear events (how?) What is realistic to do in a real world? How does big companies handle this? Sure, we can take the former employer to court and sue, but by then the damage has already been caused... Thanks a lot

    Read the article

  • Am I personally liable for bugs in medical software I've developed as an employee? [closed]

    - by user466406
    Some background: I'm employed at a small, Australia-based web agency that is dipping it's toe into Mobile Application development (iOS). The project that I'm working on provides a way for users to save medication dosage information which is sync'd with a backend server. Users must agree to ToS, Disclaimer etc before using the application. This is my first iOS application, and the project is currently over budget. As a result, management is not devoting the resources to Q&A and is pushing instead for more features. I am an employee of the agency, that has been contracted by a non-for-profit. The application will probably be released under our agency's name, but we also have the option of releasing it as the not-for-profit. My question is, if there are bugs found in the application, and as a result a user takes an incorrect dosage of a medication, am I personally liable? Is there anything that I can or should do in order to protect myself personally?

    Read the article

  • Ruby - calling constructor without arguments & removal of new line characters

    - by Raj
    I am a newbie at Ruby, I have written down a sample program. I dont understand the following: Why constructor without any arguments are not called in Ruby? How do we access the class variable outside the class' definition? Why does it always append newline characters at the end of the string? How do we strip it? Code: class Employee attr_reader :empid attr_writer :empid attr_writer :name def name return @name.upcase end attr_accessor :salary @@employeeCount = 0 def initiaze() @@employeeCount += 1 puts ("Initialize called!") end def getCount return @@employeeCount end end anEmp = Employee.new print ("Enter new employee name: ") anEmp.name = gets() print ("Enter #{anEmp.name}'s employee ID: ") anEmp.empid = gets() print ("Enter salary for #{anEmp.name}: ") anEmp.salary = gets() theEmpName = anEmp.name.split.join("\n") theEmpID = anEmp.empid.split.join("\n") theEmpSalary = anEmp.salary.split.join("\n") anEmp = Employee.new() anEmp = Employee.new() theCount = anEmp.getCount puts ("New employee #{theEmpName} with employee ID #{theEmpID} has been enrolled, welcome to hell! You have been paid as low as $ #{theEmpSalary}") puts ("Total number of employees created = #{theCount}") Output: Enter new employee name: Lionel Messi Enter LIONEL MESSI 's employee ID: 10 Enter salary for LIONEL MESSI : 10000000 New employee LIONEL MESSI with employee ID 10 has been enrolled, welcome to hell! You have been paid as low as $ 10000000 Total number of employees created = 0 Thanks

    Read the article

  • GWT + JDO + ArrayList

    - by dvieira
    Hi, I'm getting a Null ArrayList in a program i'm developing. For testing purposes I created this really small example that still has the same problem. I already tried diferent Primary Keys, but the problem persists. Any ideas or suggestions? 1-Employee class @PersistenceCapable(identityType = IdentityType.APPLICATION) public class Employee { @PrimaryKey @Persistent(valueStrategy = IdGeneratorStrategy.IDENTITY) @Extension(vendorName="datanucleus", key="gae.encoded-pk", value="true") private String key; @Persistent private ArrayList<String> nicks; public Employee(ArrayList<String> nicks) { this.setNicks(nicks); } public String getKey() { return key; } public void setNicks(ArrayList<String> nicks) { this.nicks = nicks; } public ArrayList<String> getNicks() { return nicks; } } 2-EmployeeService public class BookServiceImpl extends RemoteServiceServlet implements EmployeeService { public void addEmployee(){ ArrayList<String> nicks = new ArrayList<String>(); nicks.add("name1"); nicks.add("name2"); Employee employee = new Employee(nicks); PersistenceManager pm = PMF.get().getPersistenceManager(); try { pm.makePersistent(employee); } finally { pm.close(); } } /** * @return * @throws NotLoggedInException * @gwt.typeArgs <Employee> */ public Collection<Employee> getEmployees() { PersistenceManager pm = getPersistenceManager(); try { Query q = pm.newQuery("SELECT FROM " + Employee.class.getName()); Collection<Employee> list = pm.detachCopyAll((Collection<Employee>)q.execute()); return list; } finally { pm.close(); } } }

    Read the article

  • Passing models between controllers in MVC4

    - by wtfsven
    I'm in the middle of my first foray into web development with MVC4, and I've run into a problem that I just know is one of the core issues in web development in general, but can't seem to wrap my mind around it. So I have two models: Employee and Company. Employee has a Company, therefore /Employee/Create contains a field that is either a dropdown list for selecting an existing Company, or an ActionLink to /Company/Create if none exists. But here's the issue: If a user has to create a Company, I need to preserve the existing Employee model across both Views--over to /Company/Create, then back to /Employee/Create. So my first approach was to pass the Employee model to /Company/Create with a @Html.ActionLink("Add...", "Create", "Organization", Model , null), but then when I get to Company's Create(Employee emp), all of emp's values are null. The second problem is that if I try to come back to /Employee/Create, I'd be passing back an Employee, which would resolve to the POST Action. Basically, the whole idea is to save the state of the /Employee/Create page, jump over to /Company/Create to create a Company record, then back to /Employee/Create to finish creating the Employee. I know there is a well understood solution to this because , but I can't seem to phase it well enough to get a good Google result out of it. I've though about using Session, but it seems like doing so would be a bit of a kludge. I'd really like an elegant solution to this.

    Read the article

  • Configuring JPA Primary key sequence generators

    - by pachunoori.vinay.kumar(at)oracle.com
    This article describes the JPA feature of generating and assigning the unique sequence numbers to JPA entity .This article provides information on jpa sequence generator annotations and its usage. UseCase Description Adding a new Employee to the organization using Employee form should assign unique employee Id. Following description provides the detailed steps to implement the generation of unique employee numbers using JPA generators feature Steps to configure JPA Generators 1.Generate Employee Entity using "Entities from Table Wizard". View image2.Create a Database Connection and select the table "Employee" for which entity will be generated and Finish the wizards with default selections. View image 3.Select the offline database sources-Schema-create a Sequence object or you can copy to offline db from online database connection. View image 4.Open the persistence.xml in application navigator and select the Entity "Employee" in structure view and select the tab "Generators" in flat editor. 5.In the Sequence Generator section,enter name of sequence "InvSeq" and select the sequence from drop down list created in step3. View image 6.Expand the Employees in structure view and select EmployeeId and select the "Primary Key Generation" tab.7.In the Generated value section,select the "Use Generated value" check box ,select the strategy as "Sequence" and select the Generator as "InvSeq" defined step 4. View image   Following annotations gets added for the JPA generator configured in JDeveloper for an entity To use a specific named sequence object (whether it is generated by schema generation or already exists in the database) you must define a sequence generator using a @SequenceGenerator annotation. Provide a unique label as the name for the sequence generator and refer the name in the @GeneratedValue annotation along with generation strategy  For  example,see the below Employee Entity sample code configured for sequence generation. EMPLOYEE_ID is the primary key and is configured for auto generation of sequence numbers. EMPLOYEE_SEQ is the sequence object exist in database.This sequence is configured for generating the sequence numbers and assign the value as primary key to Employee_id column in Employee table. @SequenceGenerator(name="InvSeq", sequenceName = "EMPLOYEE_SEQ")   @Entity public class Employee implements Serializable {    @Id    @Column(name="EMPLOYEE_ID", nullable = false)    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator="InvSeq")   private Long employeeId; }   @SequenceGenerator @GeneratedValue @SequenceGenerator - will define the sequence generator based on a  database sequence object Usage: @SequenceGenerator(name="SequenceGenerator", sequenceName = "EMPLOYEE_SEQ") @GeneratedValue - Will define the generation strategy and refers the sequence generator  Usage:     @GeneratedValue(strategy = GenerationType.SEQUENCE, generator="name of the Sequence generator defined in @SequenceGenerator")

    Read the article

  • Need help deciding if Joomla! experience as a good metric for hiring a particular prospective employee.

    - by Stephen
    My company has been looking to hire a PHP developer. Some of the requirements for the job include: an understanding of design patterns, particularly MVC. some knowledge of PHP 5.3's new features. experience working with a PHP framework (it doesn't matter which one). I interviewed a man today who's primary work experience involved working with Joomla!. As an employee, he will be required to work on existing and new web applications that use Zend Framework, CakePHP and/or CodeIgniter. It is my opinion that we shouldn't dismiss hiring a developer just because he has not used the same technologies that he'll be using on the job. So, I'd like to know about the kind of coding experience working with Joomla! can provide. I've never bothered to take more than a brief look (if that) at the Joomla! package, so I'm hoping to lean on the knowledge of my peers. Would you consider Joomla! to contain a professional code-base? Is the package well organized, and/or OO in general, or is it more like WordPress where logic and presentation are commingled? When working with Joomla!, is the developer encouraged to use best practices? In your opinion, would experience working with Joomla! garner the skills needed to get up to speed with Zend or CakePHP quickly, or will there be a steep learning curve ahead of the developer? I'm not saying that Joomla! is a bad technology, or even that it is lower on the totem pole when compared to the frameworks I've mentioned. Maybe it's awesome, I dunno. I simply have no idea!

    Read the article

  • Json.Net Issues: StackOverflowException is thrown when serialising circular dependent ISerializable object with ReferenceLoopHandling.Ignore

    - by keyr
    I have a legacy application that used binary serialisation to persist the data. Now we wanted to use Json.net 4.5 to serialise the data without much changes to the existing classes. Things were working nice till we hit a circular dependent class. Is there any workaround to solve this problem? Sample code as shown below [Serializable] class Department : ISerializable { public Employee Manager { get; set; } public string Name { get; set; } public Department() { } public Department( SerializationInfo info, StreamingContext context ) { Manager = ( Employee )info.GetValue( "Manager", typeof( Employee ) ); Name = ( string )info.GetValue( "Name", typeof( string ) ); } public void GetObjectData( SerializationInfo info, StreamingContext context ) { info.AddValue( "Manager", Manager ); info.AddValue( "Name", Name ); } } [Serializable] class Employee : ISerializable { [NonSerialized] //This does not work [XmlIgnore]//This does not work private Department mDepartment; public Department Department { get { return mDepartment; } set { mDepartment = value; } } public string Name { get; set; } public Employee() { } public Employee( SerializationInfo info, StreamingContext context ) { Department = ( Department )info.GetValue( "Department", typeof( Department ) ); Name = ( string )info.GetValue( "Name", typeof( string ) ); } public void GetObjectData( SerializationInfo info, StreamingContext context ) { info.AddValue( "Department", Department ); info.AddValue( "Name", Name ); } } And the test code Department department = new Department(); department.Name = "Dept1"; Employee emp1 = new Employee { Name = "Emp1", Department = department }; department.Manager = emp1; Employee emp2 = new Employee() { Name = "Emp2", Department = department }; IList<Employee> employees = new List<Employee>(); employees.Add( emp1 ); employees.Add( emp2 ); var memoryStream = new MemoryStream(); var formatter = new BinaryFormatter(); formatter.Serialize( memoryStream, employees ); memoryStream.Seek( 0, SeekOrigin.Begin ); IList<Employee> deserialisedEmployees = formatter.Deserialize( memoryStream ) as IList<Employee>; //Works nicely JsonSerializerSettings jsonSS= new JsonSerializerSettings(); jsonSS.TypeNameHandling = TypeNameHandling.Objects; jsonSS.TypeNameAssemblyFormat = FormatterAssemblyStyle.Full; jsonSS.Formatting = Formatting.Indented; jsonSS.ReferenceLoopHandling = ReferenceLoopHandling.Ignore; //This is not working!! //jsonSS.ReferenceLoopHandling = ReferenceLoopHandling.Serialize; //This is also not working!! jsonSS.PreserveReferencesHandling = PreserveReferencesHandling.All; string jsonAll = JsonConvert.SerializeObject( employees, jsonSS ); //Throws stackoverflow exception Edit1: The issue has been reported to Json (http://json.codeplex.com/workitem/23668)

    Read the article

  • DataContractSerializer and XSLT not Serializing Class Properties

    - by Russ Clark
    I've written a simple Employee class that I'm trying to serialize to an XDocument and then use XSLT to transform the document to a page that displays both the properties (Name and ID) from the Employee class, and an html form with 2 radio buttons (Approve and Reject) and a submit button. Here is the Employee class: [Serializable, DataContract(Namespace="XSLT_MVC.Controllers/")] public class Employee { [DataMember] public string Name { get; set; } [DataMember] public int ID { get; set; } public Employee() { } public Employee(string name, int id) { Name = name; ID = id; } public XDocument GetDoc() { XDocument doc = new XDocument(); var serializer = new DataContractSerializer(typeof(Employee)); using (var writer = doc.CreateWriter()) { serializer.WriteObject(writer, this); writer.Close(); } return doc; } } And here is the XSLT file: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:output method="html" indent="yes"/> <xsl:template match="/"> <html> <body> <xsl:value-of select="Employee/Name"/> <br /> <xsl:value-of select="Employee/ID"/> <br /> <form method="post" action="/Home/ProcessRequest?id={Employee/ID}"> <input id="Action" name="Action" type="radio" value="Approved"></input> Approved <br /> <input id="Action" name="Action" type="radio" value="Rejected"></input> Rejected <br /> <input type="submit" value="Submit"></input> </form> </body> </html> </xsl:template> </xsl:stylesheet> When I run this, all I get is the html form with the 2 radio buttons and the submit button, but not the properties from the Employee class. I saw a separate StackOverflow post that said I need to change the <xsl:template match="/"> to match on the namespace of my Employee class like this: <xsl:template match="/XSLT_MVC.Controllers"> but when I do that, now all I get are the Employee properties, and not the html form with the 2 radio buttons and the submit button. Does anyone know what needs to be done so that my transform will select and display both the Employee properties and the html form?

    Read the article

  • How to use second level cache for lazy loaded collections in Hibernate?

    - by Chandru
    Let's say I have two entities, Employee and Skill. Every employee has a set of skills. Now when I load the skills lazily through the Employee instances the cache is not used for skills in different instances of Employee. Let's Consider the following data set. Employee - 1 : Java, PHP Employee - 2 : Java, PHP When I load Employee - 2 after Employee - 1, I do not want hibernate to hit the database to get the skills and instead use the Skill instances already available in cache. Is this possible? If so how? Hibernate Configuration <session-factory> <property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property> <property name="hibernate.connection.password">pass</property> <property name="hibernate.connection.url">jdbc:mysql://localhost/cache</property> <property name="hibernate.connection.username">root</property> <property name="hibernate.dialect">org.hibernate.dialect.MySQLInnoDBDialect</property> <property name="hibernate.cache.use_second_level_cache">true</property> <property name="hibernate.cache.use_query_cache">true</property> <property name="hibernate.cache.provider_class">net.sf.ehcache.hibernate.EhCacheProvider</property> <property name="hibernate.hbm2ddl.auto">update</property> <property name="hibernate.show_sql">true</property> <mapping class="org.cache.models.Employee" /> <mapping class="org.cache.models.Skill" /> </session-factory> The Entities with imports, getters and setters Removed @Entity @Table(name = "employee") @Cache(usage = CacheConcurrencyStrategy.READ_WRITE) public class Employee { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private int id; private String name; public Employee() { } @ManyToMany @JoinTable(name = "employee_skills", joinColumns = @JoinColumn(name = "employee_id"), inverseJoinColumns = @JoinColumn(name = "skill_id")) @Cache(usage = CacheConcurrencyStrategy.READ_WRITE) private List<Skill> skills; } @Entity @Table(name = "skill") @Cache(usage = CacheConcurrencyStrategy.READ_WRITE) public class Skill { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private int id; private String name; } SQL for Loading the Second Employee and his Skills Hibernate: select employee0_.id as id0_0_, employee0_.name as name0_0_ from employee employee0_ where employee0_.id=? Hibernate: select skills0_.employee_id as employee1_1_, skills0_.skill_id as skill2_1_, skill1_.id as id1_0_, skill1_.name as name1_0_ from employee_skills skills0_ left outer join skill skill1_ on skills0_.skill_id=skill1_.id where skills0_.employee_id=? In that I specifically want to avoid the second query as the first one is unavoidable anyway.

    Read the article

  • Normalization of database for timesheet tool and ensure data integrity

    - by fireeyedboy
    I'm creating a timesheet application. I have the following entities (amongst others): Company Employee = an employee associated with a company Client = a client associated with a company So far I have the following (abbreviated) database setup: Company - id - name Employee - id - companyId (FK to Company.id) - name Client - id - companyId (FK to Company.id) - name Now, I want an employee to be associated with a client, but only if that client is associated with the company the employee works for. How would you guarantee this data integrity on a database level? Or should I just depend on the application to guarantee this data integrity? I thought about creating a many to many table like this: EmployeeClient - employeeId (FK to Employee.id) - companyId \ (combined FK to Client.companyId, Client.id) - clientId / Thus, when I insert a client for an employee along with the employee's company id, the database should prevent this when the client is not associated with the employee's company id. Does this make sense? Because this still doesn't guarantee the employee is associated with the company. How do you deal with these things? UPDATE The scenario is as followed: A company has multiple employees. Employees will only be linked to one company. A company has multiple clients also. Clients will only be linked to one company. (Company is a sandbox, so to speak). An employee of a company can be linked to a client of it's company, but only if the client is part of the company's clientele. In other words: The application will allow a company to create/add employees and create/add clients (hence the companyId FK in the Employee and Client tables). Next, the company will be allowed to assign certain clients to certain of it's employees (EmployeeClient table). Imagine an employee working on projects for a few clients for which s/he can write billable hours, but the employee must not be allowed to write billable hours for clients they are not assigned to by their employer (the company). So, employees will not automatically have access to all their company's clients, but only to those that the company has selected for them. Hopefully this has shed some more light on the matter.

    Read the article

  • DataContractSerializer and XSLT

    - by Russ Clark
    I've got a simple Employee class that I'm trying to serialize to an XDocument and then use XSLT to transform the document to a page that displays both the properties (Name and ID) from the Employee class, and an html form with 2 radio buttons (Approve and Reject) and a submit button. Here is the Employee class: [Serializable, DataContract(Namespace="XSLT_MVC.Controllers/")] public class Employee { [DataMember] public string Name { get; set; } [DataMember] public int ID { get; set; } public Employee() { } public Employee(string name, int id) { Name = name; ID = id; } public XDocument GetDoc() { XDocument doc = new XDocument(); var serializer = new DataContractSerializer(typeof(Employee)); using (var writer = doc.CreateWriter()) { serializer.WriteObject(writer, this); writer.Close(); } return doc; } } And here is the XSLT file: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:output method="html" indent="yes"/> <xsl:template match="/"> <html> <body> <xsl:value-of select="Employee/Name"/> <br /> <xsl:value-of select="Employee/ID"/> <br /> <form method="post" action="/Home/ProcessRequest?id={Employee/ID}"> <input id="Action" name="Action" type="radio" value="Approved"></input> Approved <br /> <input id="Action" name="Action" type="radio" value="Rejected"></input> Rejected <br /> <input type="submit" value="Submit"></input> </form> </body> </html> </xsl:template> </xsl:stylesheet> When I run this, all I get is the html form with the 2 radio buttons and the submit button, but not the properties from the Employee class. I saw a separate StackOverflow post that said I need to change the <xsl:template match="/"> to match on the namespace of my Employee class like this: <xsl:template match="/XSLT_MVC.Controllers">, but when I do that, now all I get are the Employee properties, and not the html form with the 2 radio buttons and the submit button. Does anyone know what needs to be done so that my transform will select and display both the Employee properties and the html form?

    Read the article

< Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >