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  • Formal separation marker of syslog events?

    - by Server Horror
    I've been looking at RFC5424 to find the formally specified marker that will end a syslog event. Unfortunately I couldn't find it. So If I wanted to implement some small syslog server that reacts on certain messages what is the marker that ends a message (yes commonly an event is a single line, but I just couldn't find it in the specification) Clarification: I call it event because I associate a message with a single line. An event could possibly be some thing like Type: foo Source: webservers whereas a message to me is this: Type: foo Source: webservers http://tools.ietf.org/html/rfc5424#section-6 defines: SYSLOG-MSG = HEADER SP STRUCTURED-DATA [SP MSG] neither STRUCTURED-DATA nor MSG tell me how these fields end. Especially MSG is defined as as MSG-ANY / MSG-UTF8 which expands to virtually anything. There's nothing that says a newline marks the end (or an 8 or an a for that matter). Given the example messages (section 6.5): This is one valid message, or 2 valid messages depending on wether you say that a HEADER element must never occur in any MSG element: literal whitespace <34>1 2003-10-11T22:14:15.003Z mymachine.example.com su - ID47 - <34>1 2003-10-11T22:14:15.003Z mymachine.example.com su - ID47 | is this an end marker? \t stands for a tab <34>1 2003-10-11T22:14:15.003Z mymachine.example.com su - ID47 -\t<34>1 2003-10-11T22:14:15.003Z mymachine.example.com su - ID47 | is this an end marker? \n stands for a newline <34>1 2003-10-11T22:14:15.003Z mymachine.example.com su - ID47 -\n<34>1 2003-10-11T22:14:15.003Z mymachine.example.com su - ID47 | is this an end marker? Either I'm misreading the RFC or there just isn't any mention. The sizes specified in the RFC just say what the minimum length is expected that I can work with...

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  • 3D Sphereical Terrain with an 8 mesh sphere. The edges of the mesh are obvioulsy seen and I'm not su

    - by Justin808
    Hi :) I'm working in Unity3D, but my issue is with 3D meshes. I'm hoping someone here can help or point me in the right direction. I have 2 version of code, http://www.pasteit4me.com/695002 (old) and http://www.pasteit4me.com/690003 (new). The old code, makes a single mesh sphere and creates a terrain on it. The new code makes an 8 mesh sphere and creates a terrain on it. On the new version the edges of the meshes are obviously seen and I'm not sure why. It looks like the edges are adjusted no much, almost 2-3 times more than they should have been. GenerateB() in the old code and Generate() in the new code creates the sphere. MakeTerrain() in both create the terrain. If I dont run the MakeTerrain() function the new sphere looks like a solid mesh. I'm not sure where to start looking in the MakeTerrain() function in the new code to solve the issue :-/ Any ideas? An image of the issue is at http://img28.imageshack.us/img28/3784/screenshot20100611at850.png.

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  • Invitación a evento de Oracle sobre Transformación del CPD

    - by Eloy M. Rodríguez
    Ahora que se acaba el año y se van dejando atrás los últimos empujones a los temas que hay que cerrar, es un buen momento para hacer un pequeño alto en el camino y asistir a este evento que organiza Oracle y reflexionar sobre los enfoques innovadores que se plantean ya que la actual situación reclama actuaciones diferentes y, a veces, el árbol tapa al bosque. Adjunto la invitación oficial, con la agenda y acceso al registro automático.. Oracle Transformación del Centro de Datos: Acelerando la adopción eficaz de la Cloud Transformación del Centro de Datos: Acelerando la adopción eficaz de la Cloud Únase a nosotros en el evento Transformación del Centro de Datos y descubra cómo implementar un centro de datos que esté diseñado para promover la innovación, ofreciendo un mayor rendimiento y fiabilidad, simplificando la gestión y reduciendo significativamente los costes. Venga a conocer los últimas novedades tecnológicas aplicables a su negocio que Oracle acaba de anunciar en Oracle Open World, su conferencia mundial por excelencia, como el Supercluster, el nuevo procesador T4 y las soluciones de Storage Pillar. Sólo Oracle diseña hardware y software, para que estos trabajen conjuntamente desde las aplicaciones al disco, lo que permite reducir la complejidad, impulsar la productividad en toda la empresa y acelerar la innovación empresarial. Únase a nosotros para descubrir cómo transformar su centro de datos para maximizar la eficacia y restablecer IT como una ventaja competitiva del negocio de su empresa. Comparta ideas y experiencias con los mejores expertos y ejecutivos y descubra como: Acelerar la transformación del centro de datos a través de la tecnología que proporciona un rendimiento espectacular y una mayor eficiencia Reducir costes, acelerar y simplificar el despliegue y la consolidación de bases de datos y aplicaciones Optimizar el rendimiento a través de la utilización de los productos Oracle con la tecnología de virtualización incorporada sin coste adicional Minimizar el riesgo durante los despliegues de cloud empresarial con el apoyo de los productos líderes del mercado en materia de seguridad Aumentar la productividad y responder rápidamente a los cambios del mercado con las soluciones optimizadas de Oracle Transforme su centro de datos para optimizar el rendimiento, incrementar la agilidad de su negocio y maximizar sus inversiones en IT. No deje pasar esta oportunidad e inscríbase hoy mismo a este evento que tendrá lugar el próximo 14 de diciembre en Madrid. Inscríbase hoy mismo Para más información, contacte con [email protected] Inscríbase ahora 14 de diciembre de 2011 09:00 - 16:00 CÍRCULO DE BELLAS ARTES DE MADRID C/ Alcalá, 42 28014 MadridEntrada por c/ Marqués de Casa Riera Programa 09:00 Registro 09:30 Bienvenida e IntroducciónJoão Taron, Vice-President & Hardware Leader, Oracle Iberia 09:45 Estrategia OracleGerhard Schlabschi, Business Development Director, Oracle Systems EMEA 10:20 Como transformar su centro de datos eficazmente Manuel Vidal, Director Systems Presales, Oracle Iberia 10:45 Caso de Éxito 11:15 Café 11:45 Consolidacion en Private Cloud Rendimiento extremo con Oracle Exalogic Elastic Cloud & Exadata Lisa Martinez,Business Development Manager, Oracle  Aceleración de las aplicaciones empresariales con SPARC SuperClusters y servidores empresariales T4                                     Carlos Soler Ibanez, Principal Sales Consultant, Oracle 13:15 Almuerzo 14:15 Optimización del Centro de Datos Cómo maximizar el potencial de su infrastructura con sistemas virtualizados de Oracle Javier Cerrada, Senior Sales Consultant, Oracle Optimización de los recursos de almacenamiento con Data Tiering Miguel Angel Borrega, Storage Architect, Oracle 15:00 Gestión del Centro de Datos Oracle Solaris 11                                                                             Javier Cerrada, Senior Sales Consultant, Oracle Enterprise Manager 12c                                                                     Jesus Robles, Master Principal Sales Consultant, Oracle 15:45 Preguntas & respuestas 16:00 Conversaciones con sus interlocutores de Oracle & sorteo de iPAD If you are an employee or official of a government organization, please click here for important ethics information regarding this event. Copyright © 2011, Oracle and/or its affiliates. All rights reserved. Contacte con nosotros | Notas Legales y | Política de Privacidad

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  • Python 3 - Module: subprocess

    - by Rhys
    Hi Stack Overflow users, I've encountered a frustrating problem, can't find the answer to it. Yesterday I was trying to find a way to HIDE a subprocess.Popen. So for example, if i was opening the cmd. I would like it to be hidden, permanently. I found this code: kwargs = {} if subprocess.mswindows: su = subprocess.STARTUPINFO() su.dwFlags |= subprocess.STARTF_USESHOWWINDOW su.wShowWindow = subprocess.SW_HIDE kwargs['startupinfo'] = su subprocess.Popen("cmd.exe", **kwargs) It worked like a charm! But today, for reasons I don't need to get into, I had to reinstall python 3 (32bit) Now, when I run my program I get this error: Traceback (most recent call last): File "C:\Python31\hello.py", line 7, in <module> su.dwFlags |= subprocess.STARTF_USESHOWWINDOW AttributeError: 'module' object has no attribute 'STARTF_USESHOWWINDOW' I'm using 32bit, python3.1.3 ... just like before. If you have any clues/alternatives PLEASE post, thanks. NOTE: I am looking for a SHORT method to hide the app, not like two pages of code please

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  • Announcing the latest update to Oracle VM Server for x86 2.2 Release

    - by Honglin Su
    More and more customers have discovered that Oracle delivers more value with Oracle VM compared with other server virtualization solutions, and we've seen the momentum that customers succeed with Oracle VM and leading partners support Oracle VM. Recently, Oracle VM server for x86 with Windows PV Drivers passed Microsoft SVVP requirements for Windows servers, which provides customers more confidence to deploy Microsoft Windows guest OS onto Oracle VM server for x86. Today I'm pleased to announce the Oracle VM server for x86 2.2.2 release. See the new features introduced in the 2.2.2 release. Expand the guest OS support to include Oracle Linux 6.x and Oracle Solaris 11 Express OS. For a complete list of guest OS support, please refer to the Oracle VM server x86 release note. The VMPInfo system information and cluster troubleshooting utility is provided with this release. Additional information on VMPInfo is also available in the following My Oracle Support Notes: 1263293.1 Post-installation check list for new Oracle VM Server 1290587.1 Performing Site Reviews and Cluster Troubleshooting with VMPInfo A new storage repository option to provide NFS mount options when creating a storage repository. For more information on this new parameter, see Oracle VM Server User Guide "Adding a Storage Repository". Updated OCFS2 cluster file system, libdhcp, device drivers. See details and additional enhancements at Oracle VM Server User Guide: New Features in Release 2.2.2. The Oracle VM Server for x86 ISO image is available for download at Oracle's E-Delivery site. If you've subscribed to Oracle's Unbreakable Linux Network (ULN), you can simply run up2date command to update the server. Please refer to Oracle VM Upgrade Guide: Upgrading Oracle VM Server. There's no change to Oracle VM Manager, which remains at 2.2.0 with the patch 2.2-16. If you have any questions about Oracle VM Serer for x86, you may post your questions at OTN discussion forum; or purchase support for Oracle Unbreakable Linux and Oracle VM. For Oracle's x86 systems, Oracle VM support as well Oracle Linux and Oracle Solaris support are included in the Oracle Premier Support for Systems. For more information about Oracle's virtualization, visit oracle.com/virtualization.

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  • Keep Oracle VM 3 Up to Date

    - by Honglin Su
    More and more customers turn to Oracle VM 3 to virtualize their enterprise applications. Oracle VM support subscription is an integrated part of their successes. Customers enjoy the benefit of the industry-leading global support 24x7 for their server virtualization implementation, and receive access to patches, fixes, and updates via Unbreakable Linux Network (ULN). For customers running Oracle systems, Oracle VM support is included in Oracle Premium Support for Systems at no extra cost, and customers receive comprehensive systems coverage that includes single point accountability for Oracle server and storage hardware; integrated software (for example, firmware); and operating system software (Oracle Solaris, Oracle Linux, and Oracle VM). To run a successful virtualization infrastructure, it's important to keep Oracle VM 3 environment up to date by leveraging Oracle VM support resources.  Oracle VM Server Updates: You can easily upgrade Oracle VM Server using a Yum repository. You can download the latest server patch updates from ULN. To receive notification on the software update delivered to Oracle ULN for Oracle VM, you can sign up here. For information on setting up an Oracle VM Server Yum repository and using Oracle VM Manager to perform the upgrade of Oracle VM Servers, see Updating and Upgrading Oracle VM Servers in the Oracle VM User's Guide .  Oracle VM Manager Updates: Get the download instructions at OTN, and apply latest Oracle VM Manager patch. Be sure to review the patch README before you apply the patches. Support customers have access to extremely valuable knowledge notes from My Oracle Support. They are the first to receive useful tips to help address issues in Oracle VM deployments. For example, Upgrade to Oracle VM 3.1.1 using Yum Repository may cause network configuration scripts to be renamed causing network failure after reboot (Doc ID 1464126.1) Oracle VM server reboots after network becomes unresponsive due to deep C-State power management setting (Doc ID 1440197.1) For more information about Oracle's virtualization, visit oracle.com/virtualization.

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  • Get the latest Oracle VM updates

    - by Honglin Su
    We have released the latest Oracle VM updates for both x86 and SPARC.  For Oracle VM Server for SPARC: Oracle Solaris 11 SRU8.5 includes Oracle VM server for SPARC 2.2 so if you're already running a Solaris 11 as the control domain. All you need do is a 'pkg update' to get the latest 2.2 bits. Learn more how to upgrade to the latest Oracle VM Server for SPARC 2.2 release on Solaris 11 here and consult the documentation for further details. For Oracle VM Server for x86:  Download Oracle VM Manager 3.1.1 Patch Update from My Oracle Support, patch ID 14227416. With the latest Oracle VM Manager 3.1.1 build 365, you can explore Oracle VM Manager 3 Command Line Interface (CLI). Download Oracle VM Server Update from Oracle Unbreakable Linux Network. To receive notification on the software update delivered to Oracle ULN for Oracle VM, you can sign up here. For information on setting up an Oracle VM Server Yum repository and using Oracle VM Manager to perform the upgrade of Oracle VM Servers, see Updating and Upgrading Oracle VM Servers in the Oracle VM User's Guide For more information about Oracle's virtualization, visit oracle.com/virtualization.

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  • Installing Oracle 11gR2 on RHEL 6.2

    - by Chris
    Hello all I'm having some difficulty installing Oracle 11gR2 on RHEL 6.2 I have compiled a giant list of every single step I have taken so far I installed RHEL 6.2 on VMWARE it did it's easy install automatically I Selected 4gb of memory Selected max size of 80Gb Selected 2 processors Sorry for the bad styling copy paste isn't working correctly The version of oracle i downloaded is Linux x86-64 11.2.0.1 I am installing this on a local machine NOT a remote machine I followed the following documentation http://docs.oracle.com/cd/E11882_01/install.112/e24326/toc.htm I bolded the steps which I was least sure about from my research Easy installed with RHEL 6.2 for VMWARE Registered with red hat so I can get updates Reinstalled vmware-tools by pressing enter at every choice Sudo yum update at the end something about GPG key selected y then y Checked Memory Requirements grep MemTotal /proc/meminfo MemTotal: 3921368 kb uname -m x86_64 grep SwapTotal /proc/meminfo SwapTotal: 6160376 kb free total used free shared buffers cached Mem: 3921368 2032012 1889356 0 76216 1533268 -/+ buffers/cache: 422528 3498840 Swap: 6160376 0 6160376 df -h /dev/shm Filesystem Size Used Avail Use% Mounted on tmpfs 1.9G 276K 1.9G 1% /dev/shm df -h /tmp Filesystem Size Used Avail Use% Mounted on /dev/sda2 73G 2.7G 67G 4% / df -h Filesystem Size Used Avail Use% Mounted on /dev/sda2 73G 2.7G 67G 4% / tmpfs 1.9G 276K 1.9G 1% /dev/shm /dev/sda1 291M 58M 219M 21% /boot All looked fine to me except maybe for swap? Software Requirements cat /proc/version Linux version 2.6.32-220.el6.x86_64 ([email protected]) (gcc version 4.4.5 20110214 (Red Hat 4.4.5-6) (GCC) ) #1 SMP Wed Nov 9 08:03:13 EST 2011 uname -r 2.6.32-220.el6.x86_64 (same as above but whatever) According to the tutorial should be On Red Hat Enterprise Linux 6 2.6.32-71.el6.x86_64 or later These are the versions of software I have installed binutils-2.20.51.0.2-5.28.el6.x86_64 compat-libcap1-1.10-1.x86_64 compat-libstdc++-33-3.2.3-69.el6.x86_64 compat-libstdc++-33.i686 0:3.2.3-69.el6 gcc-4.4.6-3.el6.x86_64 gcc-c++.x86_64 0:4.4.6-3.el6 glibc-2.12-1.47.el6_2.12.x86_64 glibc-2.12-1.47.el6_2.12.i686 glibc-devel-2.12-1.47.el6_2.12.x86_64 glibc-devel.i686 0:2.12-1.47.el6_2.12 ksh.x86_64 0:20100621-12.el6_2.1 libgcc-4.4.6-3.el6.x86_64 libgcc-4.4.6-3.el6.i686 libstdc++-4.4.6-3.el6.x86_64 libstdc++.i686 0:4.4.6-3.el6 libstdc++-devel.i686 0:4.4.6-3.el6 libstdc++-devel-4.4.6-3.el6.x86_64 libaio-0.3.107-10.el6.x86_64 libaio-0.3.107-10.el6.i686 libaio-devel-0.3.107-10.el6.x86_64 libaio-devel-0.3.107-10.el6.i686 make-3.81-19.el6.x86_64 sysstat-9.0.4-18.el6.x86_64 unixODBC-2.2.14-11.el6.x86_64 unixODBC-devel-2.2.14-11.el6.x86_64 unixODBC-devel-2.2.14-11.el6.i686 unixODBC-2.2.14-11.el6.i686 8. Probably screwed up here or step 9 /usr/sbin/groupadd oinstall /usr/sbin/groupadd dba(not sure why this isn't in the tutorial) /usr/sbin/useradd -g oinstall -G dba oracle passwd oracle /sbin/sysctl -a | grep sem Xkernel.sem = 250 32000 32 128 /sbin/sysctl -a | grep shm kernel.shmmax = 68719476736 kernel.shmall = 4294967296 kernel.shmmni = 4096 vm.hugetlb_shm_group = 0 /sbin/sysctl -a | grep file-max Xfs.file-max = 384629 /sbin/sysctl -a | grep ip_local_port_range Xnet.ipv4.ip_local_port_range = 32768 61000 /sbin/sysctl -a | grep rmem_default Xnet.core.rmem_default = 124928 /sbin/sysctl -a | grep rmem_max Xnet.core.rmem_max = 131071 /sbin/sysctl -a | grep wmem_max Xnet.core.wmem_max = 131071 /sbin/sysctl -a | grep wmem_default Xnet.core.wmem_default = 124928 Here is my sysctl.conf file I only added the items that were bigger: Kernel sysctl configuration file for Red Hat Linux # For binary values, 0 is disabled, 1 is enabled. See sysctl(8) and sysctl.conf(5) for more details. Controls IP packet forwarding net.ipv4.ip_forward = 0 Controls source route verification net.ipv4.conf.default.rp_filter = 1 Do not accept source routing net.ipv4.conf.default.accept_source_route = 0 Controls the System Request debugging functionality of the kernel kernel.sysrq = 0 Controls whether core dumps will append the PID to the core filename. Useful for debugging multi-threaded applications. kernel.core_uses_pid = 1 Controls the use of TCP syncookies net.ipv4.tcp_syncookies = 1 Disable netfilter on bridges. net.bridge.bridge-nf-call-ip6tables = 0 net.bridge.bridge-nf-call-iptables = 0 net.bridge.bridge-nf-call-arptables = 0 Controls the maximum size of a message, in bytes kernel.msgmnb = 65536 Controls the default maxmimum size of a mesage queue kernel.msgmax = 65536 Controls the maximum shared segment size, in bytes kernel.shmmax = 68719476736 Controls the maximum number of shared memory segments, in pages kernel.shmall = 4294967296 fs.aio-max-nr = 1048576 fs.file-max = 6815744 kernel.sem = 250 32000 100 128 net.ipv4.ip_local_port_range = 9000 65500 net.core.rmem_default = 262144 net.core.rmem_max = 4194304 net.core.wmem_default = 262144 net.core.wmem_max = 1048576 /sbin/sysctl -p net.ipv4.ip_forward = 0 net.ipv4.conf.default.rp_filter = 1 net.ipv4.conf.default.accept_source_route = 0 kernel.sysrq = 0 kernel.core_uses_pid = 1 net.ipv4.tcp_syncookies = 1 error: "net.bridge.bridge-nf-call-ip6tables" is an unknown key error: "net.bridge.bridge-nf-call-iptables" is an unknown key error: "net.bridge.bridge-nf-call-arptables" is an unknown key kernel.msgmnb = 65536 kernel.msgmax = 65536 kernel.shmmax = 68719476736 kernel.shmall = 4294967296 fs.aio-max-nr = 1048576 fs.file-max = 6815744 kernel.sem = 250 32000 100 128 net.ipv4.ip_local_port_range = 9000 65500 net.core.rmem_default = 262144 net.core.rmem_max = 4194304 net.core.wmem_default = 262144 net.core.wmem_max = 1048576 su - oracle ulimit -Sn 1024 ulimit -Hn 1024 ulimit -Su 1024 ulimit -Hu 30482 ulimit -Su 1024 ulimit -Ss 10240 ulimit -Hs unlimited su - nano /etc/security/limits.conf *added to the end of the file * oracle soft nproc 2047 oracle hard nproc 16384 oracle soft nofile 1024 oracle hard nofile 65536 oracle soft stack 10240 exit exit su - mkdir -p /app/ chown -R oracle:oinstall /app/ chmod -R 775 /app/ 9. THIS IS PROBABLY WHERE I MESSED UP I then exited out of the root account so now I'm back in my account chris then I su - oracle echo $SHELL /bin/bash umask 0022 (so it should be set already to what is neccesary) Also from what I have read I do not need to set the DISPLAY variable because I'm installing this on the localhost I then opened the .bash_profile of the oracle and changed it to the following .bash_profile Get the aliases and functions if [ -f ~/.bashrc ]; then . ~/.bashrc fi User specific environment and startup programs PATH=$PATH:$HOME/bin; export PATH ORACLE_BASE=/app/oracle ORACLE_SID=orcl export ORACLE_BASE ORACLE_SID I then shutdown the virtual machine shared my desktop folder from my windows 7 then turned back on the virtual machine logged in as chris opened up a terminal then: su - for some reason the shared folder didn't appear so I reinstalled vmware tools again and restarted then same as before su - cp -R linux_oracle/database /db; chown -R oracle:oinstall /db; chmod -R 775 /db; ll /db drwxrwxr-x. 8 oracle oinstall 4096 Jun 5 06:20 database exit su - oracle cd /db/database ./runInstaller AND FINALLY THE INFAMOUS JAVA:132 ERROR MESSAGE Starting Oracle Universal Installer... Checking Temp space: must be greater than 80 MB. Actual 65646 MB Passed Checking swap space: must be greater than 150 MB. Actual 6015 MB Passed Checking monitor: must be configured to display at least 256 colors. Actual 16777216 Passed Preparing to launch Oracle Universal Installer from /tmp/OraInstall2012-06-05_06-47-12AM. Please wait ...[oracle@localhost database]$ Exception in thread "main" java.lang.UnsatisfiedLinkError: /tmp/OraInstall2012-06-05_06-47-12AM/jdk/jre/lib/i386/xawt/libmawt.so: libXext.so.6: cannot open shared object file: No such file or directory at java.lang.ClassLoader$NativeLibrary.load(Native Method) at java.lang.ClassLoader.loadLibrary0(ClassLoader.java:1751) at java.lang.ClassLoader.loadLibrary(ClassLoader.java:1647) at java.lang.Runtime.load0(Runtime.java:769) at java.lang.System.load(System.java:968) at java.lang.ClassLoader$NativeLibrary.load(Native Method) at java.lang.ClassLoader.loadLibrary0(ClassLoader.java:1751) at java.lang.ClassLoader.loadLibrary(ClassLoader.java:1668) at java.lang.Runtime.loadLibrary0(Runtime.java:822) at java.lang.System.loadLibrary(System.java:993) at sun.security.action.LoadLibraryAction.run(LoadLibraryAction.java:50) at java.security.AccessController.doPrivileged(Native Method) at java.awt.Toolkit.loadLibraries(Toolkit.java:1509) at java.awt.Toolkit.(Toolkit.java:1530) at com.jgoodies.looks.LookUtils.isLowResolution(Unknown Source) at com.jgoodies.looks.LookUtils.(Unknown Source) at com.jgoodies.looks.plastic.PlasticLookAndFeel.(PlasticLookAndFeel.java:122) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Class.java:242) at javax.swing.SwingUtilities.loadSystemClass(SwingUtilities.java:1783) at javax.swing.UIManager.setLookAndFeel(UIManager.java:480) at oracle.install.commons.util.Application.startup(Application.java:758) at oracle.install.commons.flow.FlowApplication.startup(FlowApplication.java:164) at oracle.install.commons.flow.FlowApplication.startup(FlowApplication.java:181) at oracle.install.commons.base.driver.common.Installer.startup(Installer.java:265) at oracle.install.ivw.db.driver.DBInstaller.startup(DBInstaller.java:114) at oracle.install.ivw.db.driver.DBInstaller.main(DBInstaller.java:132)

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  • Best Practices to Accelerate Oracle VM Server Deployments

    - by Honglin Su
    IOUG (Independent Oracle User Group) Virtualization SIG is hosting the webcast on the best practices of Oracle VM server virtualization. July 11, 2012 - Best Practices to Accelerate Oracle VM Server on SPARC Deployments. Register here. To learn the best practices on Oracle VM Server for x86,  watch the session replay here. For more white paper about best practices, visit Oracle VM OTN page here.

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  • Download the latest Oracle VM 3.1.1 Update

    - by Honglin Su
    We have released the latest patch update for Oracle VM Manager 3.1.1 and Oracle VM Server for x86 3.1.1. Oracle VM Manager 3.1.1-478 has been validated in combination with Oracle VM Server 3.1.1-485. The download instructions are available at OTN. Download Oracle VM Manager 3.1.1 Patch Update from My Oracle Support, patch ID 14227416 Download Oracle VM Server 3.1.1 ISO Update from My Oracle Support, patch ID 14775391.  Download Oracle VM Server Update from Oracle Unbreakable Linux Network and Oracle's Public Yum Repository Please be sure to read the README files of the above patches. Customers are recommended to schedule a maintenance window and apply the above patch updates to their Oracle VM 3.1.1 environment. To receive notification on the software update delivered to Oracle Unbreakable Linux Network (ULN, http://linux.oracle.com) for Oracle VM, you can sign up here http://oss.oracle.com/mailman/listinfo/oraclevm-errata. For more information about Oracle's virtualization, visit oracle.com/virtualization.

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  • Best Practices to Accelerate Oracle VM Server Deployments

    - by Honglin Su
    IOUG (Independent Oracle User Group) Virtualization SIG is hosting the webcast on the best practices of Oracle VM server virtualization. The upcoming event is scheduled on July 11 with the focus on Oracle VM Server on SPARC. Register here. Areas addressed will include recommended practices for installation, maintenance, performance, and reliability.  Topics will include sizing, resource allocation, multiple I/O domain configurations for availability, secure live migration, selection of I/O backends, and I/O virtualization.  To learn the best practices on Oracle VM Server for x86,  watch the session replay here.

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  • Power Management with Oracle VM Server for SPARC

    - by Honglin Su
    With the introduction of Oracle VM Server for SPARC 2.2, it includes power management features which can be set via the service processor (ILOM) of the supported SPARC T-Series systems. Watch this video to learn about the hardware power savings capabilities available on SPARC T4 systems, and how Oracle VM Server for SPARC makes use of them. The video will show you how to choose a power management policy and set a power cap. For more information, read the OTN technical article "How to Use the Power Management Controls on SPARC Servers".

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  • Incompatible group permissions in Linux - Is it a bug?

    - by Sachin
    I am on Ubuntu 11.04. I am creating another user and placing an existing user in the group of other user, hoping to write in the home directory of other user. # uname -a Linux vini 2.6.38-11-generic #50-Ubuntu SMP Mon Sep 12 21:18:14 UTC 2011 i686 athlon i386 GNU/Linux # whoami sachin # su root # useradd -m -U foo // create user foo # usermod -a -G foo sachin // add user `sachin' to group `foo' # chmod 770 /home/foo/ # exit # whoami sachin # cd /home/foo/ bash: cd: /home/foo/: Permission denied # groups sachin sachin : sachin foo This is totally weird. Though user sachin is in group foo, and group bits for /home/foo/ is set to rwx, sachin can't chdir to /home/foo/. I am not able to understand this. But, if at the exit step, I switch to sachin user from root, this is what happens: # uname -a Linux vini 2.6.38-11-generic #50-Ubuntu SMP Mon Sep 12 21:18:14 UTC 2011 i686 athlon i386 GNU/Linux # whoami sachin # su root # useradd -m -U foo // create user foo # usermod -a -G foo sachin // add user `sachin' to group `foo' # chmod 770 /home/foo/ # su sachin # whoami sachin # cd /home/foo/ # ls examples.desktop Now, whatever is happening here is totally incomprehensible. Does su sachin inherits some permissions from the root user at this step? Any explanations would be much appreciated.

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  • LDAP authentication ... Log in fail on the LDAP client

    - by billyduc
    I can get the password and group from the LDAP client getent passwd getent group work sucessfully But when I try 'su USERNAME' the name from the LDAP server or 'ssh USERNAME@localhost' it prompt me a user password, I typed exactly the USERNAME password but it return "su : Authentication Failure" or "Permission denied, Please try again". I don't know why? it only work when I was at root at the client and "su USERNAME"

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  • Init.d script gets return code 1 when calling itself, how can I get output?

    - by Per
    My question is, how can I modify the script so that it will tell me what goes wrong? The scenario is this: I'm trying to get Sonatype Nexus to start as a service in Ubuntu 10.04, and it just will not work. (I'm not looking for help on how to run Nexus, but on how to get some useful output from a script) It works when invoking it with sudo /etc/init.d/nexus start but fails when using sudo service nexus start I have run the update-rc.d command on it, and done everything according to instructions. The nexus init.d-script has a point where it calls itself when it detects that it should run as another user ('nexus'): su -m $RUN_AS_USER -c "\"$REALPATH\" $2" which expands to su -m nexus -c '"/opt/nexus-2.0.2/bin/jsw/linux-x86-64/nexus" start' when adding the -x debug flag to the script. This command results in return code 1. It never executes - I've set -x debug flag on the script, placed echo commands with redirect to file at the start of script to trace, etc. I cannot get any output telling me why the command will not execute. I've tried appending redirect to file after the above script line, inside the quotes, outside, any way I could imagine. All info I can get is by inserting a line echo $? after the su line, which outputs '1'. Is there a way I can see what happens when the su command runs?

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  • Run preseed commands as specific user / switching users

    - by pduersteler
    Beside the usual setup where I create a normal user foo, I want to run a few d-i preseed/late_command commands as that foo user. My initial thought was to simply call those commands with sudo, e.g: d-i preseed/late_command in-target echo "<pwd>" | sudo -Si <command>. This works for some sort of commands. However the problem is that some of the commands load up shell scripts which require to not be run with sudo. Issuing a su -c "<command>" would be an alternative, but su does not offer the possibility to read the password from stdin. Is it safe to jump around between the users using su (And if yes, how do I provide the stdin? and does it work or just result in a su: must be run from a terminal) or would this cause issues?

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  • which graphics driver will solve my laptop screen display problem?

    - by vi.su.
    which graphics driver will solve my laptop screen display problem? Recently installed Ubuntu 10.04.4 LTS on my laptop and upgraded it to 12.10, through 12.04.1 LTS. I am not able to get the display right, from the beginning. During boot laptop screen is all green, and images / videos are not getting displayed properly when logged in. Actual problem started last week, when this laptop was with Windows Vista (preloaded), and I tried to update Nvidia graphics drivers. something went wrong and I couldn't find a way to fix, so decided to install Ubuntu. Over last week, installed / re-installed Ubuntu many times with various drivers with no success. Laptop : Dell Inspiron 1420 Installed OS : ubuntu 10.04 LTS (Current, Ubuntu 12.10) Nvidia driver : GeForce 8400M GS (tried in previous installations; not installed now) Print-screen was not able to catch this issue as mentioned in the comment, so I am posting screen photos.

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  • Basics of Join Factorization

    - by Hong Su
    We continue our series on optimizer transformations with a post that describes the Join Factorization transformation. The Join Factorization transformation was introduced in Oracle 11g Release 2 and applies to UNION ALL queries. Union all queries are commonly used in database applications, especially in data integration applications. In many scenarios the branches in a UNION All query share a common processing, i.e, refer to the same tables. In the current Oracle execution strategy, each branch of a UNION ALL query is evaluated independently, which leads to repetitive processing, including data access and join. The join factorization transformation offers an opportunity to share the common computations across the UNION ALL branches. Currently, join factorization only factorizes common references to base tables only, i.e, not views. Consider a simple example of query Q1. Q1:    select t1.c1, t2.c2    from t1, t2, t3    where t1.c1 = t2.c1 and t1.c1 > 1 and t2.c2 = 2 and t2.c2 = t3.c2   union all    select t1.c1, t2.c2    from t1, t2, t4    where t1.c1 = t2.c1 and t1.c1 > 1 and t2.c3 = t4.c3; Table t1 appears in both the branches. As does the filter predicates on t1 (t1.c1 > 1) and the join predicates involving t1 (t1.c1 = t2.c1). Nevertheless, without any transformation, the scan (and the filtering) on t1 has to be done twice, once per branch. Such a query may benefit from join factorization which can transform Q1 into Q2 as follows: Q2:    select t1.c1, VW_JF_1.item_2    from t1, (select t2.c1 item_1, t2.c2 item_2                   from t2, t3                    where t2.c2 = t3.c2 and t2.c2 = 2                                  union all                   select t2.c1 item_1, t2.c2 item_2                   from t2, t4                    where t2.c3 = t4.c3) VW_JF_1    where t1.c1 = VW_JF_1.item_1 and t1.c1 > 1; In Q2, t1 is "factorized" and thus the table scan and the filtering on t1 is done only once (it's shared). If t1 is large, then avoiding one extra scan of t1 can lead to a huge performance improvement. Another benefit of join factorization is that it can open up more join orders. Let's look at query Q3. Q3:    select *    from t5, (select t1.c1, t2.c2                  from t1, t2, t3                  where t1.c1 = t2.c1 and t1.c1 > 1 and t2.c2 = 2 and t2.c2 = t3.c2                 union all                  select t1.c1, t2.c2                  from t1, t2, t4                  where t1.c1 = t2.c1 and t1.c1 > 1 and t2.c3 = t4.c3) V;   where t5.c1 = V.c1 In Q3, view V is same as Q1. Before join factorization, t1, t2 and t3 must be joined first before they can be joined with t5. But if join factorization factorizes t1 from view V, t1 can then be joined with t5. This opens up new join orders. That being said, join factorization imposes certain join orders. For example, in Q2, t2 and t3 appear in the first branch of the UNION ALL query in view VW_JF_1. T2 must be joined with t3 before it can be joined with t1 which is outside of the VW_JF_1 view. The imposed join order may not necessarily be the best join order. For this reason, join factorization is performed under cost-based transformation framework; this means that we cost the plans with and without join factorization and choose the cheapest plan. Note that if the branches in UNION ALL have DISTINCT clauses, join factorization is not valid. For example, Q4 is NOT semantically equivalent to Q5.   Q4:     select distinct t1.*      from t1, t2      where t1.c1 = t2.c1  union all      select distinct t1.*      from t1, t2      where t1.c1 = t2.c1 Q5:    select distinct t1.*     from t1, (select t2.c1 item_1                   from t2                union all                   select t2.c1 item_1                  from t2) VW_JF_1     where t1.c1 = VW_JF_1.item_1 Q4 might return more rows than Q5. Q5's results are guaranteed to be duplicate free because of the DISTINCT key word at the top level while Q4's results might contain duplicates.   The examples given so far involve inner joins only. Join factorization is also supported in outer join, anti join and semi join. But only the right tables of outer join, anti join and semi joins can be factorized. It is not semantically correct to factorize the left table of outer join, anti join or semi join. For example, Q6 is NOT semantically equivalent to Q7. Q6:     select t1.c1, t2.c2    from t1, t2    where t1.c1 = t2.c1(+) and t2.c2 (+) = 2  union all    select t1.c1, t2.c2    from t1, t2      where t1.c1 = t2.c1(+) and t2.c2 (+) = 3 Q7:     select t1.c1, VW_JF_1.item_2    from t1, (select t2.c1 item_1, t2.c2 item_2                  from t2                  where t2.c2 = 2                union all                  select t2.c1 item_1, t2.c2 item_2                  from t2                                                                                                    where t2.c2 = 3) VW_JF_1       where t1.c1 = VW_JF_1.item_1(+)                                                                  However, the right side of an outer join can be factorized. For example, join factorization can transform Q8 to Q9 by factorizing t2, which is the right table of an outer join. Q8:    select t1.c2, t2.c2    from t1, t2      where t1.c1 = t2.c1 (+) and t1.c1 = 1 union all    select t1.c2, t2.c2    from t1, t2    where t1.c1 = t2.c1(+) and t1.c1 = 2 Q9:   select VW_JF_1.item_2, t2.c2   from t2,             (select t1.c1 item_1, t1.c2 item_2            from t1            where t1.c1 = 1           union all            select t1.c1 item_1, t1.c2 item_2            from t1            where t1.c1 = 2) VW_JF_1   where VW_JF_1.item_1 = t2.c1(+) All of the examples in this blog show factorizing a single table from two branches. This is just for ease of illustration. Join factorization can factorize multiple tables and from more than two UNION ALL branches.  SummaryJoin factorization is a cost-based transformation. It can factorize common computations from branches in a UNION ALL query which can lead to huge performance improvement. 

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  • Unisciti alla Customer Experience Revolution! 27 settembre 2012, Milano

    - by antonella.buonagurio
    Si tiene giovedì 27 settembre a Milano Oracle Customer Experience Briefing, un evento pensato per riflettere sulla Customer Experience vista come strategia per dare vita a processi più completi ed innovativi per generare e gestire l’interazione con i consumatori, su tutti i canali. I lavori si terranno in particolare dalle 10.30 alle 13.00 presso Casa dell’Energia (Piazza Po 3). Enrico Finzi, Sociologo e Presidente di AstraRicerche, condividerà la propria visione sul tema e ne discuterà insieme agli esperti di Accenture e Oracle. L'incontro, rivolto in particolare alle aziende dei settori Retail e Beni di Consumo, consentirà dunque di comprendere perché la Customer Experience sia diventata la componente più importante e strategica del business delle imprese e di scoprire come essa accelleri l’acquisizione di nuovi clienti, incrementi la fidelizzazione ad un brand/prodotto/servizio, migliori l’efficienza operativa e sostenga le vendite. L’evento darà inoltre la possibilità di capire come le soluzioni di Customer Experience possono aiutare le aziende a far vivere questa esperienza ai clienti in modo coerente e personalizzato, attraverso tutti i canali e su tutti i dispositivi, ottenendo risultati misurabili.La partecipazione è gratuita su invito ed è riservata alle aziende finali. Per registrarsi all’evento è possibile collegarsi a questo link.

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  • What factors help in getting a site indexed by Google fast?

    - by ekaj
    What should I do to get a site indexed on Google, fast? Taking example of Super User I just did a quick Google for a question that was 20 minutes old, to look for an answer, and it was already on Google Search - how is this possible? I glanced over this article which seems to suggest that SU has added RSS feeds (which SU has, but when I opened the feed the article says last posted 6 minutes ago, but when Googled it is 11 hours old) - which leads me to think (Based on that article, I don't know much about search indexing but I am reading at the moment) that most of this indexing is done thanks to the sitemap. is there anything else I am unaware of that helps SU questions get on Google so fast?

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  • How can I get stats for what 3rd-party sites have embedded our iframe widget?

    - by Su'
    Say we've produced a widget for other sites to use, like so: <iframe src="http://example.com/whatever.php" frameBorder="0" width="200px" height="300px" scrolling="no"></iframe> The client would like to be able to see within GA who has embedded the thing. Is there some referer information automatically passed that I can look for, or do I need to add something? whatever.php is already loading the analytics Javascript(we're also tracking clicks on an outbound link). [EDIT] Looking around a bit more, I found what seems to be a similar question on SO with an answer saying this can be found, automatically, but I still can't seem to find the information. The question's also old enough the respondent is probably referring to the old interface, though. Maybe someone could explain getting to it in the new look. (I won't likely be able to train this client to switch, deal with the old look, etc.)

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  • Why won't Webmaster Tools let me set a preferred domain? (says to verify, but it should already be)

    - by Su'
    I've got a domain that I apparently forgot to set a preferred domain for, so I just tried to do it. Webmaster Tools instead popped up a little box: Part of the process of setting a preferred domain is to verify that you own http://www.example.com/. Please verify http://www.example.com/. I'm running into some problems following these instructions: As far as I can tell I already did verify sometime in the past. There's a TXT DNS record with the gibberish Google tells you to set for it that I couldn't have come up with myself. …and nothing is telling me this information is bad. So let's assume the site is somehow not actually verified. All the various methods' instructions start with "click the Manage Site button next to the site you want, and then click Verify this site." That button doesn't even exist on my screens. (It presumably goes away when you successfully verify?) Those instructions were all updated pretty recently, and the DNS one in particular just a couple weeks ago so it seems a bit unlikely they're inaccurate. I am not using Apps, and won't be, so can't try out the verification through there. Note that I also have another domain that I have not done any verification for which is showing the same behavior(no such button, being told to verify when it seems impossible etc.) so something appears to just be broken. I already have a no-www process in place server-side, so we can skip that. I'm just trying to get the box checked off in GWT. If I don't get any resolution, I'll eventually scrap the TXT record and see if the site gets un-verified(or whatever since it thinks it isn't), and see if I can just restart the process. It's not urgent so I'm just trying to figure out if I've gone blind to something or what. Did the button move?

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  • Frameworks cual recomiendan

    - by chechar11
    hola actualmente estoy conociendo sobre los frameworks Turbine,cocoon, Struts, webwork, pero quisiera saber cual de estos 4 frames, es mejor o cual recomendarian para su uso, o posiblemente cual es su escalabilidad, la mantenibilidad , su robustez, cosas asi que ayuden a decidirme por alguno de ellos Grax

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  • How do I output Unicode characters as a pair of ASCII characters?

    - by ChrisF
    How do I convert (as an example): Señor Coconut Y Su Conjunto - Introducciõn to: Señor Coconut Y Su Conjunto - Introducciõn I've got an app that creates m3u playlists, but when the track filename, artist or title contains non ASCII characters it doesn't get read properly by the music player so the track doesn't get played. I've discovered that if I write the track out as: #EXTINFUTF8:76,Señor Coconut Y Su Conjunto - Introducciõn #EXTINF:76,Señor Coconut Y Su Conjunto - Introducciõn #UTF8:01-Introducciõn.mp3 01-Introducciõn.mp3 Then the music player will read it correctly and play the track. My problem is that I can't find the information I need to be able to do the conversion properly.

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