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  • Best way to manually sort random text files?

    - by Jane
    I have about 1000 text files and I need to view each, and move it to a folder if it's the correct one. I can only do basic sorting by length/size, and I can't grep because the text is random. How can I do this besides manually openiing + saving each in gedit. I'm on Ubuntu Linux. Thanks

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  • My PC becomes very slow after changing page file in XP.

    - by Jane
    Hello there, I have 5 partitions in my computer (C, D, E, F, G), and C: is the system partition. Recently I changed the page file setting to use 768-768 MB from the G:, without changing the C: default value (256-512 MB). Everything runs fine until I rebooted my PC. I unset the G:'s page file before I rebooted my PC. Well, after I rebooted my PC, my XP becomes VERY slow. damn slow. I don't know how long I wasted to wait for the boot screen to disappear. (Well, maybe about 1-3 mins. Normally it is under 10 secs) and when I tried to enter the desktop, it just like using a computer without a VGA card, or VGA driver installed. Very slow. Any suggestions to fix this problem? Because I hate to repair-install my XP =\ Thanks.

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  • maintaing a sorted list that is bigger than memory

    - by tcurdt
    I have a list of tuples. [ "Bob": 3, "Alice: 2, "Jane": 1, ] When incrementing the counts "Alice" += 2 the order should be maintained: [ "Alice: 4, "Bob": 3, "Jane": 1, ] When all is in memory there rather simple ways (some more or some less) to efficiently implement this. (using an index, insert-sort etc) The question though is: What's the most promising approach when the list does not fit into memory. Bonus question: What if not even the index fits into memory? How would you approach this?

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  • Allowing the specific format of email address in MVC input

    - by user219315
    Hi I have a page in MVC where i want to take the email adddress as the input which can be of format like:"Jone Davi" <[email protected]>, "Ben Miller" <[email protected]>, "Jane Ton" <[email protected]>, Then from this I want to parse the valid emailaddress.But on click of the submit button getting error message" A potentially dangerous Request.Form value was detected from the client " Thus is there any way to take the input of email address in above format and bypass the security error for that specific page. Thanks in advance.

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  • split sting in xsl for content with /

    - by kristina
    I have some content being pulled in from an external xml with xsl. in the xml the title is merged with the author with a backslash seperating them. How do I seperate the title and author in xsl so I can have them with differnt tags The Maze / Jane Evans to be The Maze Jane Evans Thanks

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  • Fix static ip address problems in Ubuntu 10.04

    - by jane
    I used Network Manager in Ubuntu 10.04 to set a static ip address and assigned one that was already in use. Now my computer will not boot (nfs crashes). I booted from a live cd to change the configuration on the file system in /etc/network/interfaces but the file looks to be the default. Where does the network manager (the gui from system- preferences) store it's configuration so I can overwrite it and enter the correct ip addresss and have a happy working computer again. thanks!!

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  • I can't open a Word file because it's too large

    - by Jane
    I was creating a file with MS Word 2007 where I included a number of images. I didn't compress them as I was putting them into the file. I managed to save the file, but have not been able to reopen it ever since, as it says that I have exceeded the 32 MB limit. I am working on an old Macbook (OS X 10.4.11). I have tried to open the file in both OpenOffice and LibreOffice, but it just causes those programs to crash. Is there any way of reducing the file size without opening the document?

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  • C# lost local variable window from debug (f11 step by step)

    - by Jane
    I was running my code (visual studio 2010) and I accidentally closed the window that shows the state of variables step by step. I think it was called locals but I can't find it on any of the menu option. Would appreciate any help on this, I didn't realize how handy it was until now - The following link is what my local window looks like when selecting debug/start debugging/selecting breakpoints, which I'm don't find helpful. This is what my window used to look like: http://www.google.co.nz/imgresum=1&hl=en&sa=N&biw=1600&bih=761&tbm=isch&tbnid=Sa5AmVW5BxxakM:&imgrefurl=http://www.codeproject.com/Articles/79508/Mastering-Debugging-in-Visual-Studio-2010-A-Beginn&docid=4Iskh8P-E7oVSM&imgurl=http://www.codeproject.com/KB/cs/MasteringInDebugging/debug30_small.png&w=640&h=228&ei=TjKBUKGwKcXVsgauvIGYDQ&zoom=1&iact=hc&vpx=1119&vpy=441&dur=1559&hovh=134&hovw=376&tx=219&ty=79&sig=104270260849502265426&page=1&tbnh=91&tbnw=256&start=0&ndsp=22&ved=1t:429,r:0,s:20,i:134 It's probably a mode/option within debugging I need to select but I can't figure out how to get it back to the nice and simple variable state display..

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  • How can I make Mac OS X Address Book display a person’s home address from an LDAP server?

    - by Arcturus
    Hi, (I've posted this question on Stack Overflow first, but someone told me it belonged here.) I have a custom LDAP server, which I can customize to generate whichever object class and attributes I need. I'm trying to display people from that server in the Mac OS X address book. Names and organizations display correctly, as well as work-related phone and address. However, I've never been able to have a home address displayed in the address book. This is an example of output from running a ldapsearch: # extended LDIF # # LDAPv3 # base <dc=example,dc=com> with scope subtree # filter: (givenName=Joh*) # requesting: ALL # # 10041, example.com dn: uid=10041,dc=example,dc=com objectclass: top objectclass: person objectclass: organizationalPerson objectclass: inetOrgPerson objectclass: mozillaOrgPerson uid: 10041 cn: John Doe givenName: John sn: Doe o: Acme telephoneNumber: 500 00 00 mobile: 500 00 00 mail: [email protected] street: Baker St postalCode: 10098 l: New York c: US homePostalAddress: White St mozillaHomePostalCode: 10098 mozillaHomeLocalityName: New York mozillaHomeCountryName: US # search result search: 2 result: 0 Success # numResponses: 2 # numEntries: 1 Every piece of information shows up in the address book up to here: homePostalAddress: White St mozillaHomePostalCode: 10098 mozillaHomeLocalityName: New York mozillaHomeCountryName: US Which object class or attribute name should I use to have the home address show up in the Mac OS X address book?

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  • Retrieve a user's Exchange database in powershell

    - by Paul
    Hey Everyone, I've scoured the interwebs for a few days now off and on to find this. I am creating a powershell script for email-enabling new user's(Exchange 2007). To give you a little background when we have a new hire, their AD account is created at our off-site helpdesk, but they don't create their email account. I'm trying to automate the process of mail-enabling the user which involves putting them in the same database as an existing user, disable imap pop activesync, and lastly email the requester of the ticket. I would like to just get prompted for the New User's name, User to Replicate(mailbox, storage group, database), and the person to email after it's been created. So if someone could just help with a command to Retrieve a user's Exchange database in powershell that would be great, but if people also want to help with my hacked up script please do so as well!!! Here is what I have so far: Write-output “ENTER THE FOLLOWING DETAILS” $DName = Read-Host “User Diplay Name" $RUser = Read-Host "Replicate User(Database Grab)" ***$RData = #get the Replicate user's mailbox database here*** $REmail = #either just use a Read-Host “Requester's Email address" or ask for Requester's name and pipe through their email address by digging for it w/ powershell Enable-Mailbox -Identity "$DName" -Database "$RData" Send-MailMessage -From "John Doe <[email protected]>" -To (put $REmail here which is the Requester's email) -Subject "Test Person's email account" -Body "Test Person's email account has been setup.`n`n`nJohn Doe`nGeneric Company`nSystems Administrator`nOffice: 123.456.7890`[email protected]" -SmtpServer genericexchange.exchange.com

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  • linux: automount internal hard drive during boot?

    - by John Doe
    i try to create my own NAS and i need to automount the internal sata disks during boot i know i could do using fstab but im searching for a more easy/generalized way so its easier to scale with less handwork needed for every hard drive attached (or every mainboard added to the cluster) so anyone knows how to automount internal disks without using fstab like ubuntu does for usb drives? im using ubuntu server 9.10 thx all

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  • Can't get MultiViews to work on Apache 2.2 - negotiation problem

    - by Doe
    Hi I can't get MultiViews to set up properly on my Apache 2.2. When I go to filtered.com/something, I expect it to execute something.pl but it doesn't. I get a Error 404 page. In my error logs it says: " [Fri Apr 16 13:04:20 2010] [error] [client 78.85.152.94] Negotiation: discovere\ d file(s) matching request: /var/www/html/filtered.net/translate-english (None could be negotiated)., referer: http://filtered.net/" Would anyone kindly help me so that MultiViews is properly installed on my server? ServerAdmin [email protected] ServerAlias *.filtered.net DocumentRoot /var/www/html/filtered.net ServerName filtered.net ErrorLog logs/filtered.net-error_log CustomLog logs/filtered.net-access_log common Options ExecCGI +Indexes +IncludesNoExec +MultiViews +ExecCGI AllowOverride None Order allow,deny Allow from all <IfModule mod_dir.c> DirectoryIndex index.php index.html index.pl </IfModule> </Directory> </VirtualHost>

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  • linux kernel option to set sata disk to udma/133 1.5gbps

    - by John Doe
    hi, i try to speed up boot time of my linux server box which uses removable HDD rack's the current boot time is around 2 min's but if i connect the hdd's directly to the mainboard its about 2 sec's the problem is that ahci's kernel implementation causes a timeout of around 30 seconds for each disk during boot which originates from the hdd-rack after the timeout the kernel prints that the disk is limited with speed to 1.5gbps and udma/133 is used so the question i have is: how can i set this in grub as a boot option so the kernel doesnt have to wait for a timeout and just hardcoded limits the speed of the disks? i read about a few options like pci=nomsi or such, which dont work thats why im asking for limiting precisely the disks during boot thx

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  • Download resume support blocked by isp?

    - by John Doe
    Can ISP block resume support for downloads ? I'm using IDM (internet download manager) to download of the internet from resume supported websites, yet I am unable to resume downloads. I tried different computers with the same result. Turned off firewall, didn't have any effect i was able to download with no issues until a couple of days ago. Another thing i noticed is that before IDM used to try to connect to several connections to speed up my download, but now it can only connect to one connection. Also i tried to download using my vpn, and i was able to download and resume downloads with no problem.

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  • Simple way to encode a string according to a password?

    - by RexE
    Does Python have a built-in, simple way of encoding/decoding strings using a password? Something like this: >>> encode('John Doe', password = 'mypass') 'sjkl28cn2sx0' >>> decode('sjkl28cn2sx0', password = 'mypass') 'John Doe' I would like to use these encrypted strings as URL parameters. My goal is obfuscation, not strong security. I realize I could use a database table to store keys and values, but am trying to be minimalist.

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  • Need help with SQL Query

    - by StackOverflowNewbie
    Say I have 2 tables: Person - Id - Name PersonAttribute - Id - PersonId - Name - Value Further, let's say that each person had 2 attributes (say, gender and age). A sample record would be like this: Person->Id = 1 Person->Name = 'John Doe' PersonAttribute->Id = 1 PersonAttribute->PersonId = 1 PersonAttribute->Name = 'Gender' PersonAttribute->Value = 'Male' PersonAttribute->Id = 2 PersonAttribute->PersonId = 1 PersonAttribute->Name = 'Age' PersonAttribute->Value = '30' Question: how do I query this such that I get a result like this: 'John Doe', 'Male', '30'

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  • SQL Server, how to join a table in a "rotated" format (returning columns instead of rows)?

    - by Joshua Carmody
    Sorry for the lame title, my descriptive skills are poor today. In a nutshell, I have a query similar to the following: SELECT P.LAST_NAME, P.FIRST_NAME, D.DEMO_GROUP FROM PERSON P JOIN PERSON_DEMOGRAPHIC PD ON PD.PERSON_ID = P.PERSON_ID JOIN DEMOGRAPHIC D ON D.DEMOGRAPHIC_ID = PD.DEMOGRAPHIC_ID This returns output like this: LAST_NAME FIRST_NAME DEMO_GROUP --------------------------------------------- Johnson Bob Male Smith Jane Female Smith Jane Teacher Beeblebrox Zaphod Male Beeblebrox Zaphod Alien Beeblebrox Zaphid Politician I would prefer the output be similar to the following: LAST_NAME FIRST_NAME Male Female Teacher Alien Politician --------------------------------------------------------------------------------------------------------- Johnson Bob 1 0 0 0 0 Smith Jane 0 1 1 0 0 Beeblebrox Zaphod 1 0 0 1 1 The number of rows in the DEMOGRAPHIC table varies, so I can't say with certainty how many columns I need. The query needs to be flexible. Yes, it would be trivial to do this in code. But this query is one piece of a complicated set of stored procedures, views, and reporting services, many of which are outside my sphere of influence. I need to produce this output inside the database to avoid breaking the system. Any ideas? This is MS SQL Server 2005, by the way. Thanks.

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  • Filter entities that match all pairs

    - by Jon
    I have an entity (let's say Person) with a set of arbitrary attributes with a known subset of values. I need to search for all of these entities that match all my filter conditions. For example, my table structures look like this: Person: id | name 1 | John Doe 2 | Jane Roe 3 | John Smith Attribute: id | attr_name 1 | Sex 2 | Eye Color ValidValue: id | attr_id | value_name 1 | 1 | Male 2 | 1 | Female 3 | 2 | Blue 4 | 2 | Green 5 | 2 | Brown PersonAttributes id | person_id | attr_id | value_id 1 | 1 | 1 | 1 2 | 1 | 2 | 3 3 | 2 | 1 | 2 4 | 2 | 2 | 4 5 | 3 | 1 | 1 6 | 3 | 2 | 4 In JPA, I have entities built for all of these tables. What I'd like to do is perform a search for all entities matching a given set of attribute-value pairs. For instance, I'd like to be able to find all males (John Doe and John Smith), all people with green eyes (Jane Roe or John Smith), or all females with green eyes (Jane Roe). I see that I can already take advantage of the fact that I only really need to match on value_id, since that's already unique and tied to the attr_id. But where can I go from there?

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  • How can I get a distinct list of elements in a hierarchical query?

    - by RenderIn
    I have a database table, with people identified by a name, a job and a city. I have a second table that contains a hierarchical representation of every job in the company in every city. Suppose I have 3 people in the people table: [name(PK),title,city] Jim, Salesman, Houston Jane, Associate Marketer, Chicago Bill, Cashier, New York And I have thousands of job type/location combinations in the job table, a sample of which follow. You can see the hierarchical relationship since parent_title is a foreign key to title: [title,city,pay,parent_title] Salesman, Houston, $50000, CEO Cashier, Houston, $25000 CEO, USA, $1000000 Associate Marketer, Chicago, $75000 Senior Marketer, Chicago, $125000 ..... The problem I'm having is that my Person table is a composite key, so I don't know how to structure the start with part of my query so that it starts with each of the three jobs in the cities I specified. I can execute three separate queries to get what I want, but this doesn't scale well. e.g.: select * from jobs start with city = (select city from people where name = 'Bill') and title = (select title from people where name = 'Bill') connect by prior parent_title = title UNION select * from jobs start with city = (select city from people where name = 'Jim') and title = (select title from people where name = 'Jim') connect by prior parent_title = title UNION select * from jobs start with city = (select city from people where name = 'Jane') and title = (select title from people where name = 'Jane') connect by prior parent_title = title How else can I get a distinct list (or I could wrap it with a distinct if not possible) of all the jobs which are above the three people I specified?

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  • sqlite3 JOIN, GROUP_CONCAT using distinct with custom separator

    - by aiwilliams
    Given a table of "events" where each event may be associated with zero or more "speakers" and zero or more "terms", those records associated with the events through join tables, I need to produce a table of all events with a column in each row which represents the list of "speaker_names" and "term_names" associated with each event. However, when I run my query, I have duplication in the speaker_names and term_names values, since the join tables produce a row per association for each of the speakers and terms of the events: 1|Soccer|Bobby|Ball 2|Baseball|Bobby - Bobby - Bobby|Ball - Bat - Helmets 3|Football|Bobby - Jane - Bobby - Jane|Ball - Ball - Helmets - Helmets The group_concat aggregate function has the ability to use 'distinct', which removes the duplication, though sadly it does not support that alongside the custom separator, which I really need. I am left with these results: 1|Soccer|Bobby|Ball 2|Baseball|Bobby|Ball,Bat,Helmets 3|Football|Bobby,Jane|Ball,Helmets My question is this: Is there a way I can form the query or change the data structures in order to get my desired results? Keep in mind this is a sqlite3 query I need, and I cannot add custom C aggregate functions, as this is for an Android deployment. I have created a gist which makes it easy for you to test a possible solution: https://gist.github.com/4072840

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  • Match entities fulfilling filter (strict superset of search)

    - by Jon
    I have an entity (let's say Person) with a set of arbitrary attributes with a known subset of values. I need to search for all of these entities that match all my filter conditions. That is, given a set of Attributes A, I need to find all people that have a set of Attributes that are a superset of A. For example, my table structures look like this: Person: id | name 1 | John Doe 2 | Jane Roe 3 | John Smith Attribute: id | attr_name 1 | Sex 2 | Eye Color ValidValue: id | attr_id | value_name 1 | 1 | Male 2 | 1 | Female 3 | 2 | Blue 4 | 2 | Green 5 | 2 | Brown PersonAttributes id | person_id | attr_id | value_id 1 | 1 | 1 | 1 2 | 1 | 2 | 3 3 | 2 | 1 | 2 4 | 2 | 2 | 4 5 | 3 | 1 | 1 6 | 3 | 2 | 4 In JPA, I have entities built for all of these tables. What I'd like to do is perform a search for all entities matching a given set of attribute-value pairs. For instance, I'd like to be able to find all males (John Doe and John Smith), all people with green eyes (Jane Roe or John Smith), or all females with green eyes (Jane Roe). I see that I can already take advantage of the fact that I only really need to match on value_id, since that's already unique and tied to the attr_id. But where can I go from there? I've been trying to do something like the following, given that the ValidValue is unique in all cases: select distinct p from Person p join p.personAttributes a where a.value IN (:values) Then I've tried putting my set of required values in as "values", but that gives me errors no matter how I try to structure that. I also have to get a little more complicated, as follows, but at this point I'd be happy with solving the first problem cleanly. However, if it's possible, the Attribute table actually has a field for default value: id | attr_name | default_value 1 | Sex | 1 2 | Eye Color | 5 If the value you're searching on happens to be the default value, I want it to return any people that have no explicit value set for that attribute, because in the application logic, that means they inherit the default value. Again, I'm more concerned about the primary question, but if someone who can help with that also has some idea of how to do this one, I'd be extremely grateful.

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  • Formatting the parent and child nodes of a Treeview that is populated by a XML file

    - by Marina
    Hello Everyone, I'm very new to xml so I hope I'm not asking any silly question here. I'm currently working on populating a treeview from an XML file that is not hierarchically structured. In the xml file that I was given the child and parent nodes are defined within the attributes of the item element. How would I be able to utilize the attributes in order for the treeview to populate in the right hierarchical order. (Example Mary Jane should be a child node of Peter Smith). At present all names are under one another. root <item parent_id="0" id="1"><content><name>Peter Smith</name></content></item> <item parent_id="1" id="2"><content><name>Mary Jane</name></content></item> <item parent_id="1" id="7"><content><name>Lucy Lu</name></content></item> <item parent_id="2" id="3"><content><name>Informatics Team</name></content></item> <item parent_id="3" id="4"><content><name>Sandy Chu</name></content></item> <item parent_id="4" id="5"><content><name>John Smith</name></content></item> <item parent_id="5" id="6"><content><name>Jane Smith</name></content></item> /root Thank you for all of your help, Marina

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  • Updating a specific key/value inside of an array field with MongoDB

    - by Jesta
    As a preface, I've been working with MongoDB for about a week now, so this may turn out to be a pretty simple answer. I have data already stored in my collection, we will call this collection content, as it contains articles, news, etc. Each of these articles contains another array called author which has all of the author's information (Address, Phone, Title, etc). The Goal - I am trying to create a query that will update the author's address on every article that the specific author exists in, and only the specified author block (not others that exist within the array). Sort of a "Global Update" to a specific article that affects his/her information on every piece of content that exists. Here is an example of what the content with the author looks like. { "_id" : ObjectId("4c1a5a948ead0e4d09010000"), "authors" : [ { "user_id" : null, "slug" : "joe-somebody", "display_name" : "Joe Somebody", "display_title" : "Contributing Writer", "display_company_name" : null, "email" : null, "phone" : null, "fax" : null, "address" : null, "address2" : null, "city" : null, "state" : null, "zip" : null, "country" : null, "image" : null, "url" : null, "blurb" : null }, { "user_id" : null, "slug" : "jane-somebody", "display_name" : "Jane Somebody", "display_title" : "Editor", "display_company_name" : null, "email" : null, "phone" : null, "fax" : null, "address" : null, "address2" : null, "city" : null, "state" : null, "zip" : null, "country" : null, "image" : null, "url" : null, "blurb" : null }, ], "tags" : [ "tag1", "tag2", "tag3" ], "title" : "Title of the Article" } I can find every article that this author has created by running the following command: db.content.find({authors: {$elemMatch: {slug: 'joe-somebody'}}}); So theoretically I should be able to update the authors record for the slug joe-somebody but not jane-somebody (the 2nd author), I am just unsure exactly how you reach in and update every record for that author. I thought I was on the right track, and here's what I've tried. b.content.update( {authors: {$elemMatch: {slug: 'joe-somebody'} } }, {$set: {address: '1234 Avenue Rd.'} }, false, true ); I just believe there's something I am missing in the $set statement to specify the correct author and point inside of the correct array. Any ideas? **Update** I've also tried this now: b.content.update( {authors: {$elemMatch: {slug: 'joe-somebody'} } }, {$set: {'authors.$.address': '1234 Avenue Rd.'} }, false, true );

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  • Basic PHP OOPS Query

    - by appu
    Ok. I am starting out OOPS in PHP. Created a couple of classes: customer(parent) and sales(child) class that inherits from parent class. Created another testcustomer.php in which a new sales object is created however the salesprint() function defined in the sales class does not echo out customer's name though it is set to be "Jane" in the class.customer.php(parent). My thinking is that when sales class extends customer class PHP automatically includes all the code from class.customer.php to sales.customer.php and therefore the constructor in parent class set $name to "Jane". Here is the code: class.customer.php <?php class customer{ private $name; private $cust_no; public function __construct($customerid) { $this->name = 'Jane'; $this->cust_no = $customerid; } } ?> class.sales.php <?php require_once('class.customer.php'); class sales extends customer{ public function salesprint($customerid) { echo "Hello $this->name this is a print of your purchased products"; } } ?> testcustomer.php require_once('class.sales.php'); $objsales = new sales(17); $objsales->salesprint(17); ?> The Output I get Hello this is a print of your purchased products. What am i doing wrong ? thanks romesh

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