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  • How exactly is an Abstract Syntax Tree created?

    - by Howcan
    I think I understand the goal of an AST, and I've build a couple of tree structures before, but never an AST. I'm mostly confused because the nodes are text and not number, so I can't think of a nice way to input a token/string as I'm parsing some code. For example, when I looked at diagrams of AST's, the variable and its value were leaf nodes to an equal sign. This makes perfect sense to me, but how would I go about implementing this? I guess I can do it case by case, so that when I stumble upon an "=" I use that as a node, and add the value parsed before the "=" as the leaf. It just seems wrong, because I'd probably have to make cases for tons and tons of things, depending on the syntax. And then I came upon another problem, how is the tree traversed? Do I go all the way down the height, and go back up a node when I hit the bottom, and do the same for it's neighbor? I've seen tons of diagrams on ASTs, but I couldn't find a fairly simple example of one in code, which would probably help.

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  • Dynamic quadrees

    - by paul424
    recently I come out writing Quadtree for creatures culling in Opendungeons game. Thing is those are moving points and bounding hierarchy will quickly get lost if the quadtree is not rebuild very often. I have several variants, first is to upgrade the leaf position , every time creature move is requested. ( note if I would need collision detection anyway, so this might be necessery anyway). Second would be making leafs enough large , that the creature would sure stay inside it's bounding box ( due to its speed limit). The partition of a plane in quadtree is always fixed ( modulo the hierarchical unions of some parts) . For creatures close to the center of the plane , there would be no way of keeping it but inside one big leaf, besides this brokes the invariant that each point can be put into any small area as desired. So on the second thought could I use several quadrees ? Each would have its "coordinate axis XY" somwhere shifted ? Before I start playing with this maybe some other space diving structure would suit me better, unfortunetly wiki does not compare it's execution time : http://en.wikipedia.org/wiki/Grid_%28spatial_index%29#See_also

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  • Minimax algorithm: Cost/evaluation function?

    - by Dave
    Hi guys, A school project has me writing a Date game in C++ (example at http://www.cut-the-knot.org/Curriculum/Games/Date.shtml) where the computer player must implement a Minimax algorithm with alpha-beta pruning. Thus far, I understand what the goal is behind the algorithm in terms of maximizing potential gains while assuming the opponent will minify them. However, none of the resources I read helped me understand how to design the evaluation function the minimax bases all it's decisions on. All the examples have had arbitrary numbers assigned to the leaf nodes, however, I need to actually assign meaningful values to those nodes. Intuition tells me it'd be something like +1 for a win leaf node, and -1 for a loss, but how do intermediate nodes evaluate? Any help would be most appreciated.

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  • ExtJs: Tree: how download then select using AJAX calls ?

    - by Olivier Pons
    Hi, Here's my goal : - open a tree - download the root nodes - expand automatically one specific node using AJAX (and loop n times here) until i find a leaf then select the leaf Here's the function that works when I declare the Tree : listeners: { load: function(n) { console.log('load(n)'); n.eachChild( function(n) { if ((n.id=='lys/2007') || (n.id=='lys/2007/08') || (n.id=='lys/2007/08/29')) { n.expand(false,false); } }); } } But if I don't know how to make it more "generic" (almost exactly like the ExtJs documentation). But they don't jump automatically to a specific node (i.e. I want no user interaction). Any idea / advice how to do this? Don't hesitate to edit my post to make it proper English :)

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  • Problem understanding treesort in Haskell

    - by Jerry
    I am trying to figure out how exactly does treesort from here work (I understand flatten, insert and foldr). I suppose what's being done in treesort is applying insert for each element on the list thus generating a tree and then flattening it. The only problem I can't overcome here is where the list (that is the argument of the function) is hiding (because it is not written anywhere as an argument except for the function type declaration). One more thing: since dot operator is function composition, why is it an error when I change: treesort = flatten . foldr insert Leaf to treesort = flatten( foldr insert Leaf )?

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  • Nicely printing/showing a binary tree in Haskell

    - by nicole
    I have a tree data type: data Tree a b = Branch b (Tree a b) (Tree a b) | Leaf a ...and I need to make it an instance of Show, without using deriving. I have found that nicely displaying a little branch with two leaves is easy: instance (Show a, Show b) => Show (Tree a b) where show (Leaf x) = show x show (Branch val l r) = " " ++ show val ++ "\n" ++ show l ++ " " ++ show r But how can I extend a nice structure to a tree of arbitrary size? It seems like determining the spacing would require me to know just how many leaves will be at the very bottom (or maybe just how many leaves there are in total) so that I can allocate all the space I need there and just work 'up.' I would probably need to call a size function. I can see this being workable, but is that making it harder than it is?

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  • How to find longest common substring using trees?

    - by user384706
    The longest common substring problem according to wiki can be solved using a suffix tree. From wiki: The longest common substrings of a set of strings can be found by building a generalised suffix tree for the strings, and then finding the deepest internal nodes which have leaf nodes from all the strings in the subtree below it I don't get this. Example: if I have: ABCDE and XABCZ then the suffix tree is (some branches from XABCZ omitted due to space): The longest common substring is ABC but it is not I can not see how the description of wiki helps here. ABC is not the deepest internal nodes with leaf nodes. Any help to understand how this works?

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  • Constructing a tree using Python

    - by stealthspy
    I am trying to implement a unranked boolean retrieval. For this, I need to construct a tree and perform a DFS to retrieve documents. I have the leaf nodes but I am having difficulty to construct the tree. Eg: query = OR ( AND (maria sharapova) tennis) Result: OR | | AND tennis | | maria sharapova I traverse the tree using DFS and calculate the boolean equivalent of certain document ids to identify the required document from the corpus. Can someone help me with the design of this using python? I have parsed the query and retrieved the leaf nodes for now.

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  • Composite pattern in C++ problem

    - by annouk
    Hello! I have to work with an application in C++ similar to a phone book: the class Agenda with an STL list of Contacts.Regarding the contacts hierarchy,there is a base-class named Contact(an abstract one),and the derived classes Friend and Acquaintance(the types of contact). These classes have,for instance, a virtual method called getName,which returns the name of the contact. Now I must implement the Composite pattern by adding another type of contact,Company(being derived from Contact),which also contains a collection of Contacts(an STL list as well),that can be either of the "leaf" type(Friends or Acquaintances),or they can be Companies as well. Therefore,Company is the Compound type. The question is: how and where can I implement an STL find_if to search the contact with a given name(via getName function or suggest me smth else) both among the "leaf"-type Contact and inside the Company collection? In other words,how do I traverse the tree in order to find possible matches there too,using an uniform function definition? I hope I was pretty clear...

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  • Are there any good Java/JVM libraries for my Expression Tree architecture?

    - by Snuggy
    My team and I are developing an enterprise-level application and I have devised an architecture for it that's best described as an "Expression Tree". The basic idea is that the leaf nodes of the tree are very simple expressions (perhaps simple values or strings). Nodes closer to the trunk will get more and more complex, taking the simpler nodes as their inputs and returning more complex results for their parents. Looking at it the other way, the application performs some task, and for this it creates a root expression. The root expression divides its input into smaller units and creates child expressions, which when evaluated it can use to build it's own result. The subdividing process continues until the simplest leaf nodes. There are two very important aspects of this architecture: It must be possible to manipulate nodes of the tree after it is built. The nodes may be given new input values to work with and any change in result for that node needs to be propagated back up the tree to the root node. The application must make best use of available processors and ultimately be scalable to other computers in a grid or in the cloud. Nodes in the tree will often be updating concurrently and notifying other interested nodes in the tree when they get a new value. Unfortunately, I'm not at liberty to discuss my actual application, but to aid understanding a little bit, you might imagine a kind of spreadsheet application being implemented with a similar architecture, where changes to cells in the table are propagated all over the place to other cells that need the result. The spreadsheet could get so massive that applying multi-core multi-computer distributed system to solve it would be of benefit. I've got my prototype "Expression Engine" working nicely on a single multi-core PC but I've started to run into a few concurrency issues (as expected because I haven't been taking too much care so far) so it's now time to start thinking about migrating the Engine to a more robust library, and that leads to a number of related questions: Is there any precedent for my "Expression Tree" architecture that I could research? What programming concepts should I consider. I realise this approach has many similarities to a functional programming style, and I'm already aware of the concepts of using futures and actors. Are there any others? Are there any languages or libraries that I should study? This question is inspired by my accidental discovery of Scala and the Akka library (which has good support for Actors, Futures, Distributed workloads etc.) and I'm wondering if there is anything else I should be looking at as well?

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  • Testing for disk write

    - by Montecristo
    I'm writing an application for storing lots of images (size <5MB) on an ext3 filesystem, this is what I have for now. After some searching here on serverfault I have decided for a structure of directories like this: 000/000/000000001.jpg ... 236/519/236519107.jpg This structure will allow me to save up to 1'000'000'000 images as I'll store a max of 1'000 images in each leaf. I've created it, from a theoretical point of view seems ok to me (though I've no experience on this), but I want to find out what will happen when there will be directories full of files in there. A question about creating this structure: is it better to create it all in one go (takes approx 50 minutes on my pc) or should I create directories as they are needed? From a developer point of view I think the first option is better (no extra waiting time for the user), but from a sysadmin point of view, is this ok? I've thought I could do as if the filesystem is already under the running application, I'll make a script that will save images as fast as it can, monitoring things as follows: how much time does it take for an image to be saved when there is no or little space used? how does this change when the space starts to be used up? how much time does it take for an image to be read from a random leaf? Does this change a lot when there are lots of files? Does launching this command sync; echo 3 | sudo tee /proc/sys/vm/drop_caches has any sense at all? Is this the only thing I have to do to have a clean start if I want to start over again with my tests? Do you have any suggestions or corrections?

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  • Anyone know a good mind mapper that works with a scheduler?

    - by GLycan
    TL;DR: Mind mapping tasks to be processed into a schedule based on task metadata. I have all sorts of ideas about what to invest resources (mainly time) in, but when I actually have time to do something I useually end up browsing reddit for not knowing what do to, and the frequancy with which I forget deadlines scares me. I'd love to bring order and structure into my mind, and always know what to do next. So, I want a mind mapping app, where I'd give each branch (types and subtypes of things I want to do) a importance score (if there were two branches, and one had 60 while the other 40, they would respectivily get 60% and 40% of the parent's importance, with the root being 100) and a how soon that branch should be revised/updated (an hobby I want to try out might be checked, say, once a week, while a school subject should be checked once a day) and give each leaf (something I want/need to do) how much time it takes, deadline (if any), and optionally an absolute importance, reoccurrence (guitar practice might repeat once a week), and prerequisites (reading something requires that book (although that could be brought somewhere), coding requires a box, jogging requires being outside) and maybe some other flags, like if it's enjoyable or not. It should either be packaged or working with a schedular app, to which I'd say, look, my day works this way (completely busy from 8 to 9:15, then 15 minutes of being inside with nothing, ..., two hours with box and possibility to go outside, etc), saying that such-and-such pattern is school and happens ever weekday except such-and-such days. The output should be of the form of a schedule, fit for printing or, when I finally get an android, mobile viewing, that schedules tasks with regards to availability of resources and importance (importance being derived from the leaf-task's parent branches), and the set of flags (all work and no play makes me a dull boy). One of these tasks should be reviewing anything that should be updated on that day, including future day layouts (e.g, if the time slots of future days have changed. This should be done every day.) Does anyone know some collection of preferably open-source (or free, or pirateable) tools, or better yet a single one, that accomplishes this task? I know python pretty well, and should be able to write any necessary glue.

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  • Treeview - Hierarchical Data Template - Binding does not update on source change?

    - by ClearsTheScreen
    Greetings! I ran into this problem in my project (Silverlight 3 with C#): I have a TreeView which is data bound to, well, a tree. This TreeView has a HierarchicalDataTamplate in a resource dictionary, that defines various controls. Now I want to hide (Visibility.Collapse) some items depending on wether a node has children or not. Other items shall be visible under the same condition. It works like charm when I first bind the source tree to the TreeView, but when I change the source tree, the visibility in the treeview does not change. XAML - page: <controls:TreeView x:Name="SankeyTreeView" ItemContainerStyle="{StaticResource expandedTreeViewItemStyle}" ItemTemplate="{StaticResource SankeyTreeTemplate}"> <controls:TreeViewItem IsExpanded="True"> <controls:TreeViewItem.HeaderTemplate> <DataTemplate> <TextBlock Text="This is just for loading and will be replaced directly after the data becomes available..."/> </DataTemplate> </controls:TreeViewItem.HeaderTemplate> </controls:TreeViewItem> </controls:TreeView> XAML - ResourceDictionary <!-- Each node in the tree is structurally identical, hence only one Hierarchical Data Template that'll use itself on the children. --> <Data:HierarchicalDataTemplate x:Key="SankeyTreeTemplate" ItemsSource="{Binding Children}"> <Grid Height="24"> <TextBlock x:Name="TextBlockName" Text="{Binding Path=Value.name, Mode=TwoWay}" VerticalAlignment="Center" Foreground="Black"/> <TextBox x:Name="TextBoxFlow" Text="{Binding Path=Value.flow, Mode=TwoWay}" Grid.Column="1" Visibility="{Binding Children, Converter={StaticResource BoxConverter}, ConverterParameter=\{box\}}"/> <TextBlock x:Name="TextBlockThroughput" Text="{Binding Path=Value.throughput, Mode=TwoWay}" Grid.Column="1" Visibility="{Binding Children, Converter={StaticResource BoxConverter}, ConverterParameter=\{block\}}"/> <Button x:Name="ButtonAddNode"/> <Button x:Name="ButtonDeleteNode"/> <Button x:Name="ButtonEditNode"/> </Grid> </Data:HierarchicalDataTemplate> Now, as you can see, the TextBoxFlow and the TextBlockThroughput share the same space. What I aim at: The "Throughput" value of a node is how much of something 'flows' through this node from its children. It can't be changed directly, so I want to display a text block. Only leaf nodes have a TextBox to let someone enter the 'flow' that is generated in this leaf node. (I.E.: Node.Throughput = Node.Flow + Sum(Children.Throughput), where Node.Flow = 0 for each non-leaf.) What the BoxConverter (silly name -.-) does: public object Convert(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture) { if ((value as NodeList<TreeItem>).Count > 1) // Node has Children? { if ((parameter as String) == "{box}") { return Visibility.Collapsed; } else ((parameter as String) == "{block}") { return Visibility.Visible; } } else { /* * As above, just with Collapsed and Visible switched */ } } The structure of the tree that is bound to the TreeView is essentially stolen from Dan Vanderboom (a bit too much to dump the whole code here), except that I here of course use an ObservableCollection for the children and the value items implement INotifyPropertyChanged. I would be very grateful if someone could explain to me, why inserting items into the underlying tree does not update the visibility for box and block. Thank you in advance!

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  • Something for the weekend - Whats the most complex query?

    - by simonsabin
    Whenever I teach about SQL Server performance tuning I try can get across the message that there is no such thing as a table. Does that sound odd, well it isn't, trust me. Rather than tables you need to consider structures. You have 1. Heaps 2. Indexes (b-trees) Some people split indexes in two, clustered and non-clustered, this I feel confuses the situation as people associate clustered indexes with sorting, but don't associate non clustered indexes with sorting, this is wrong. Clustered and non-clustered indexes are the same b-tree structure(and even more so with SQL 2005) with the leaf pages sorted in a linked list according to the keys of the index.. The difference is that non clustered indexes include in their structure either, the clustered key(s), or the row identifier for the row in the table (see http://sqlblog.com/blogs/kalen_delaney/archive/2008/03/16/nonclustered-index-keys.aspx for more details). Beyond that they are the same, they have key columns which are stored on the root and intermediary pages, and included columns which are on the leaf level. The reason this is important is that this is how the optimiser sees the world, this means it can use any of these structures to resolve your query. Even if your query only accesses one table, the optimiser can access multiple structures to get your results. One commonly sees this with a non-clustered index scan and then a key lookup (clustered index seek), but importantly it's not restricted to just using one non-clustered index and the clustered index or heap, and that's the challenge for the weekend. So the challenge for the weekend is to produce the most complex single table query. For those clever bods amongst you that are thinking, great I will just use lots of xquery functions, sorry these are the rules. 1. You have to use a table from AdventureWorks (2005 or 2008) 2. You can add whatever indexes you like, but you must document these 3. You cannot use XQuery, Spatial, HierarchyId, Full Text or any open rowset function. 4. You can only reference your table once, i..e a FROM clause with ONE table and no JOINs 5. No Sub queries. The aim of this is to show how the optimiser can use multiple structures to build the results of a query and to also highlight why the optimiser is doing that. How many structures can you get the optimiser to use? As an example create these two indexes on AdventureWorks2008 create index IX_Person_Person on Person.Person (lastName, FirstName,NameStyle,PersonType) create index IX_Person_Person on Person.Person(BusinessentityId,ModifiedDate)with drop_existing    select lastName, ModifiedDate   from Person.Person  where LastName = 'Smith' You will see that the optimiser has decided to not access the underlying clustered index of the table but to use two indexes above to resolve the query. This highlights how the optimiser considers all storage structures, clustered indexes, non clustered indexes and heaps when trying to resolve a query. So are you up to the challenge for the weekend to produce the most complex single table query? The prize is a pdf version of a popular SQL Server book, or a physical book if you live in the UK.  

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  • Build Explorer version 1.1 for Visual Studio Team Explorer is released

    - by terje
    Our free extension to Visual Studio , the folder based Build Explorer Version 1.1 has now been released, and uploaded to the Visual Studio Gallery and Codeplex. We have collected up a few changes and some bugs, as follows: Changes: Queue Default Builds can now be optionally fully enabled, fully disabled or enabled just for leaf nodes (=disabled for folders).  If you got a large number of builds it was pretty scary to be able to launch all of them with just one click.  However, it is nice to avoid having the dialog box up when you want to just run off a single build.  That’s the reasoning between the 3rd choice here. Auto fill-in of the builds at start up and refresh  This was a request that came up a lot, and which was also irritating to us.  When the Team Project is opened, the Build explorer will start by itself and fill up it’s tree. So you don’t need to click the node anymore. There was also quite a bit of flashing when the tree filled up, this has been reduced to just a single top level fill before it collapses the node. The speed of the buildup of the tree has also been increased. The “All Build Definitions” node is now shown on top of the list Login box appeared in certain cross domain situations. This was a fix for the TF30063 authentication problem we had in the beginning.  Hopefully the new code has that fixed properly so that both the login box and the TF30063 are gone forever.  Our testing so far seems to indicate it works.  If anyone gets a real problem here there are two workarounds: 1) Turn off the auto refresh to reduce the issue. If this doesn’t fix it, then 2) please reinstall the former version (go to the codeplex download site if you don’t have it anymore)  Write a comment to this blog post with a description of what happens, and I will send a temporary fix asap. Bug fixes: The folder name matching was case sensitive, so “Application.CI” and “application.CI” created two different folders.  View all builds not shown for leaf odes, and view builds didn’t work in all cases.  There was some inconsistencies here which have been fixed. Partly fixed:  The context menu to queue a new build for disabled builds should be removed, but that was a difficult one, and is still on the list, but the command will not do anything for a disabled build. Using the Queue Default Builds on a folder, and if it had some disabled builds below an error box appeared and ruined the whole experience. As a result of these fixes there has been introduced some new options, as shown below:   The two first settings, the Separator symbol and the options for how to handle Queuing of default builds are set per Team Project, and is stored in the TFS source control under the BuildProcessTemplates folder, with the name Inmeta.VisualStudio.BuildExplorer.Settings.xml The next two settings need some explanations.  They handle the behavior for the auto update of the build folders.  First, these are stored in the local registry per user, at the key HKEY_CURRENT_USER/Software\Inmeta\BuildExplorer. The first option Use Timed Refresh at Startup, if turned off, you will need to click the node as it is done in Version 1.0.  The second option is a timed value, the time after the Build explorer node is created and until the scanning of the Build folders start.  It is assumed that this is enough, and the tests so far indicates this.  If you have very many builds and you see that the explorer don’t get them all, try to increase this value, and of course, notify me of your case, either here or on the Visual Gallery site.

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  • July, the 31 Days of SQL Server DMO’s – Day 22 (sys.dm_db_index_physical_stats)

    - by Tamarick Hill
    The sys.dm_db_index_physical_stats Dynamic Management Function is used to return information about the fragmentation levels, page counts, depth, number of levels, record counts, etc. about the indexes on your database instance. One row is returned for each level in a given index, which we will discuss more later. The function takes a total of 5 input parameters which are (1) database_id, (2) object_id, (3) index_id, (4) partition_number, and (5) the mode of the scan level that you would like to run. Let’s use this function with our AdventureWorks2012 database to better illustrate the information it provides. SELECT * FROM sys.dm_db_index_physical_stats(db_id('AdventureWorks2012'), NULL, NULL, NULL, NULL) As you can see from the result set, there is a lot of beneficial information returned from this DMF. The first couple of columns in the result set (database_id, object_id, index_id, partition_number, index_type_desc, alloc_unit_type_desc) are either self-explanatory or have been explained in our previous blog sessions so I will not go into detail about these at this time. The next column in the result set is the index_depth which represents how deep the index goes. For example, If we have a large index that contains 1 root page, 3 intermediate levels, and 1 leaf level, our index depth would be 5. The next column is the index_level which refers to what level (of the depth) a particular row is referring to. Next is probably one of the most beneficial columns in this result set, which is the avg_fragmentation_in_percent. This column shows you how fragmented a particular level of an index may be. Many people use this column within their index maintenance jobs to dynamically determine whether they should do REORG’s or full REBUILD’s of a given index. The fragment count represents the number of fragments in a leaf level while the avg_fragment_size_in_pages represents the number of pages in a fragment. The page_count column tells you how many pages are in a particular index level. From my result set above, you see the the remaining columns all have NULL values. This is because I did not specify a ‘mode’ in my query and as a result it used the ‘LIMITED’ mode by default. The LIMITED mode is meant to be lightweight so it does collect information for every column in the result set. I will re-run my query again using the ‘DETAILED’ mode and you will see we now have results for these rows. SELECT * FROM sys.dm_db_index_physical_stats(db_id('AdventureWorks2012'), NULL, NULL, NULL, ‘DETAILED’)   From the remaining columns, you see we get even more detailed information such as how many records are in a particular index level (record_count). We have a column for ghost_record_count which represents the number of records that have been marked for deletion, but have not physically been removed by the background ghost cleanup process. We later see information on the MIN, MAX, and AVG record size in bytes. The forwarded_record_count column refers to records that have been updated and now no longer fit within the row on the page anymore and thus have to be moved. A forwarded record is left in the original location with a pointer to the new location. The last column in the result set is the compressed_page_count column which tells you how many pages in your index have been compressed. This is a very powerful DMF that returns good information about the current indexes in your system. However, based on the mode you select, it could be a very resource intensive function so be careful with how you use it. For more information on this Dynamic Management Function, please see the below Books Online link: http://msdn.microsoft.com/en-us/library/ms188917.aspx Follow me on Twitter @PrimeTimeDBA

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  • Drupal6: How to programmatically style a block?

    - by Fronker
    In Drupal6, I basically have a block (a hierarchical menu structure) that turns out like this in HTML: <div class="block block-menu_block" id="block-menu_block-1"> <div class="content"> <div class="menu-block-1 menu-name-menu-navigation parent-mlid-0 menu-level-1"> <ul class="menu"> <li class="leaf first menu-mlid-248 active active-trail"><a class="active-trail active" title="" href="/">Start</a></li> <li class="expanded menu-mlid-249 active"><a class="active" title="" href="/">Aktuell</a> <ul class="menu"> <li class="leaf first menu-mlid-259"> <a title="News und Presse" href="/news-und-presse">News and Press</a> </li>... What I would like to get is actually a lot simpler: <div id="topmenu"> <ul class="one"> <li>some main entry <ul> <li> some sub entry ... or maybe: <div id="topmenu"> <h2>some main entry</h2> <h3><a href="#">some sub entry</a></h3> <h3><a href="#">another sub entry</a></h3> <h2>another main entry</h2> So, keeping the structure, but being able to use simpler, even completely different tags, if and when needed. I think I understand from the drupal docs, that I am (maybe) looking at <div class="block block-menu_block" id="block-menu_block-1" ==> module := menu_block delta := 1 (?) regrettably, none of the suggested * block-[module]-[delta].tpl.php * block-[module].tpl.php * block-[region].tpl.php placed next to page.tpl.php has any impact (yes, I did clear the cache).

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  • How to define trees with more than one type in ML programing language

    - by user550413
    Well, I am asked to do the next thing: To define a binary tree which can contain 2 different types: ('a,'b) abtree and these are the requirements: Any inner vertex (not a leaf) must be of the type 'a or 'b and the leafs have no value. For every path in the tree all 'a values must appear before the 'b value: examples of paths: 'a->'a->'a-'b (legal) 'a->'b->'b (legal) 'a->'a->'a (legal) 'b->'b->'b (legal) 'a->'b->'a (ILLEGAL) and also I need to define another tree which is like the one described above but now I have got also 'c and in the second requirement it says that for every path I 'a values appear before the 'b values and all the 'b values appear before the 'c values. First, I am not sure how to define binary trees to have more than 1 type in them. I mean the simplest binary tree is: datatype 'a tree = leaf | br of 'a * 'a tree * 'a tree; And also how I can define a tree to have these requirements. Any help will be appreciated. Thanks.

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  • Problem in setting backgound color to my TreeCellRenderer

    - by Sunil Kumar Sahoo
    Hi I have cretaed my own renderer. I want the back ground should be blue. I have set background color as blue also. But I donot know what is tha problem that the background color of my renderer always seems to be white. I have post the code. please help where I am wrong so that the background color becomes white. class CheckTreeCellRenderer extends JPanel implements TreeCellRenderer { private CheckTreeSelectionModel selectionModel; private MyRenderer delegate; private TristateCheckBox checkBox = new TristateCheckBox("", null, true); public static final State NOT_SELECTED = new State(); public static final State SELECTED = new State(); public static final State DONT_CARE = new State(); public CheckTreeCellRenderer(MyRenderer delegate, CheckTreeSelectionModel selectionModel) { this.delegate = delegate; this.selectionModel = selectionModel; setLayout(new BorderLayout()); setOpaque(true); setBackground(new Color(207, 219, 234)); checkBox.setState(Boolean.TRUE); checkBox.setOpaque(true); checkBox.setBackground(new Color(207, 219, 234)); } public Component getTreeCellRendererComponent(JTree tree, Object value, boolean selected, boolean expanded, boolean leaf, int row, boolean hasFocus) { Component renderer = delegate.getTreeCellRendererComponent(tree, value, selected, expanded, leaf, row, hasFocus); TreePath path = tree.getPathForRow(row); if (path != null) { if (selectionModel.isPathSelected(path, true)) { checkBox.setState(Boolean.TRUE); } else { checkBox.setState(selectionModel.isPartiallySelected(path) ? null : Boolean.FALSE); } } renderer.setBackground(new Color(207, 219, 234)); tree.setOpaque(true); tree.setBackground(new Color(207, 219, 234)); this.setOpaque(true); this.setBackground(new Color(207, 219, 234)); add(checkBox, BorderLayout.WEST); add(renderer, BorderLayout.CENTER); return this; } }

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  • Permuting a binary tree without the use of lists

    - by Banang
    I need to find an algorithm for generating every possible permutation of a binary tree, and need to do so without using lists (this is because the tree itself carries semantics and restraints that cannot be translated into lists). I've found an algorithm that works for trees with the height of three or less, but whenever I get to greater hights, I loose one set of possible permutations per height added. Each node carries information about its original state, so that one node can determine if all possible permutations have been tried for that node. Also, the node carries information on weather or not it's been 'swapped', i.e. if it has seen all possible permutations of it's subtree. The tree is left-centered, meaning that the right node should always (except in some cases that I don't need to cover for this algorithm) be a leaf node, while the left node is always either a leaf or a branch. The algorithm I'm using at the moment can be described sort of like this: if the left child node has been swapped swap my right node with the left child nodes right node set the left child node as 'unswapped' if the current node is back to its original state swap my right node with the lowest left nodes' right node swap the lowest left nodes two childnodes set my left node as 'unswapped' set my left chilnode to use this as it's original state set this node as swapped return null return this; else if the left child has not been swapped if the result of trying to permute left child is null return the permutation of this node else return the permutation of the left child node if this node has a left node and a right node that are both leaves swap them set this node to be 'swapped' The desired behaviour of the algoritm would be something like this: branch / | branch 3 / | branch 2 / | 0 1 branch / | branch 3 / | branch 2 / | 1 0 <-- first swap branch / | branch 3 / | branch 1 <-- second swap / | 2 0 branch / | branch 3 / | branch 1 / | 0 2 <-- third swap branch / | branch 3 / | branch 0 <-- fourth swap / | 1 2 and so on... Sorry for the ridiculisly long and waddly explanation, would really, really apreciate any sort of help you guys could offer me. Thanks a bunch!

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  • New record may be written twice in clusterd index structure

    - by Cupidvogel
    As per the article at Microsoft, under the Test 1: INSERT Performance section, it is written that For the table with the clustered index, only a single write operation is required since the leaf nodes of the clustered index are data pages (as explained in the section Clustered Indexes and Heaps), whereas for the table with the nonclustered index, two write operations are required—one for the entry into the index B-tree and another for the insert of the data itself. I don't think that is necessarily true. Clustered Indexes are implemented through B+ tree structures, right? If you look at at this article, which gives a simple example of inserting into a B+ tree, we can see that when 8 is initially inserted, it is written only once, but then when 5 comes in, it is written to the root node as well (thus written twice, albeit not initially at the time of insertion). Also when 8 comes in next, it is written twice, once at the root and then at the leaf. So won't it be correct to say, that the number of rewrites in case of a clustered index is much less compared to a NIC structure (where it must occur every time), instead of saying that rewrite doesn't occur in CI at all?

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  • TreeView Control Problem

    - by ProgNet
    Hi all, I have a public folder on the server that contains recursively nested sub folders. In the various Leaf folders contains Images. I wanted to create a server side file browser that will display the Images to the user. I am using the ASP.NET TreeView Control. I create the tree nodes using PopulateOnDemand. If the user click on a leaf directory I want the images in that folder to be displayed in a DataList Control. The problem is that when I click on a sub tree node (after I expanded it parent node) All the expanded sub tree disappears and only the parent node is showed with no + sign next to it !! ( I have set the TreeView's PopulateNodesFromClient property to true ) Can someone tell me what is the problem ?? Thanks Here is the code : <asp:TreeView ID="TreeView1" runat="server" AutoGenerateDataBindings="False" onselectednodechanged="TreeView1_SelectedNodeChanged" ontreenodepopulate="TreeView1_TreeNodePopulate"> </asp:TreeView> protected void Page_Load(object sender, EventArgs e) { if (!Page.IsPostBack) { string path = Server.MapPath("."); PopulateTopNodes(path); } } private void PopulateTopNodes(string pathToRootFolder) { DirectoryInfo dirInfo = new DirectoryInfo(pathToRootFolder); DirectoryInfo[] dirs = dirInfo.GetDirectories(); foreach (DirectoryInfo dir in dirs) { TreeNode folderNode = new TreeNode(dir.Name,dir.FullName); if (dir.GetDirectories().Length > 0) { folderNode.PopulateOnDemand = true; folderNode.Collapse(); } TreeView1.Nodes.Add(folderNode); } } protected void TreeView1_TreeNodePopulate(object sender, TreeNodeEventArgs e) { if (IsCallback == true) { if (e.Node.ChildNodes.Count == 0) { LoadChildNode(e.Node); } } } private void LoadChildNode(TreeNode treeNode) { DirectoryInfo dirInfo = new DirectoryInfo(treeNode.Value); DirectoryInfo[] dirs = dirInfo.GetDirectories(); foreach (DirectoryInfo dir in dirs) { TreeNode folderNode = new TreeNode(dir.Name, dir.FullName); if(dir.GetDirectories().Length>0){ folderNode.PopulateOnDemand = true; folderNode.Collapse(); } treeNode.ChildNodes.Add(folderNode); } } protected void TreeView1_SelectedNodeChanged(object sender, EventArgs e) { // Retrieve the images here }

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  • Using classes for the first time,help in debugging

    - by kaushik
    here is post my code:this is no the entire code but enough to explain my doubt.please discard any code line which u find irrelavent enter code here saving_tree={} isLeaf=False class tree: global saving_tree rootNode=None lispTree=None def __init__(self,x): file=x string=file.readlines() #print string self.lispTree=S_expression(string) self.rootNode=BinaryDecisionNode(0,'Root',self.lispTree) class BinaryDecisionNode: global saving_tree def __init__(self,ind,name,lispTree,parent=None): self.parent=parent nodes=lispTree.getNodes(ind) print nodes self.isLeaf=(nodes[0]==1) nodes=nodes[1]#Nodes are stored self.name=name self.children=[] if self.isLeaf: #Leaf Node print nodes #Set the leaf data self.attribute=nodes print "LeafNode is ",nodes else: #Set the question self.attribute=lispTree.getString(nodes[0]) self.attribute=self.attribute.split() print "Question: ",self.attribute,self.name tree={} tree={str(self.name):self.attribute} saving_tree=tree #Add the children for i in range(1,len(nodes)):#Since node 0 is a question # print "Adding child ",nodes[i]," who has ",len(nodes)-1," siblings" self.children.append(BinaryDecisionNode(nodes[i],self.name+str(i),lispTree,self)) print saving_tree i wanted to save some data in saving_tree{},which i have declared previously and want to use that saving tree in the another function outside the class.when i asked to print saving_tree it printing but,only for that instance.i want the saving_tree{} to have the data to store data of all instance and access it outside. when i asked for print saving_tree outside the class it prints empty{}.. please tell me the required modification to get my required output and use saving_tree{} outside the class..

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  • Multiple Components in a JTree Node Renderer & Node Editor

    - by Samad Lotia
    I am attempting to create a JTree where a node has several components: a JPanel that holds a JCheckBox, followed by a JLabel, then a JComboBox. I have attached the code at the bottom if one wishes to run it. Fortunately the JTree correctly renders the components. However when I click on the JComboBox, the node disappears; if I click on the JCheckBox, it works fine. It seems that I am doing something wrong with how the TreeCellEditor is being set up. How could I resolve this issue? Am I going beyond the capabilities of JTree? Here's a quick overview of the code I have posted below. The class EntityListDialog merely creates the user interface. It is not useful to understand it other than the createTree method. Node is the data structure that holds information about each node in the JTree. All Nodes have a name, but samples may be null or an empty array. This should be evident by looking at EntityListDialog's createTree method. The name is used as the text of the JCheckBox. If samples is non-empty, it is used as the contents of the JCheckBox. NodeWithSamplesRenderer renders Nodes whose samples are non-empty. It creates the complicated user interface with the JPanel consisting of the JCheckBox and the JComboBox. NodeWithoutSamplesRenderer creates just a JCheckBox when samples is empty. RendererDispatcher decides whether to use a NodeWithSamplesRenderer or a NodeWithoutSamplesRenderer. This entirely depends on whether Node has a non-empty samples member or not. It essentially functions as a means for the NodeWith*SamplesRenderer to plug into the JTree. Code listing: import java.awt.*; import java.awt.event.*; import java.util.*; import javax.swing.*; import javax.swing.tree.*; public class EntityListDialog { final JDialog dialog; final JTree entitiesTree; public EntityListDialog() { dialog = new JDialog((Frame) null, "Test"); entitiesTree = createTree(); JScrollPane entitiesTreeScrollPane = new JScrollPane(entitiesTree); JCheckBox pathwaysCheckBox = new JCheckBox("Do additional searches"); JButton sendButton = new JButton("Send"); JButton cancelButton = new JButton("Cancel"); JButton selectAllButton = new JButton("All"); JButton deselectAllButton = new JButton("None"); dialog.getContentPane().setLayout(new GridBagLayout()); GridBagConstraints c = new GridBagConstraints(); JPanel selectPanel = new JPanel(new FlowLayout(FlowLayout.LEFT)); selectPanel.add(new JLabel("Select: ")); selectPanel.add(selectAllButton); selectPanel.add(deselectAllButton); c.gridx = 0; c.gridy = 0; c.weightx = 1.0; c.weighty = 0.0; c.fill = GridBagConstraints.HORIZONTAL; dialog.getContentPane().add(selectPanel, c); c.gridx = 0; c.gridy = 1; c.weightx = 1.0; c.weighty = 1.0; c.fill = GridBagConstraints.BOTH; c.insets = new Insets(0, 5, 0, 5); dialog.getContentPane().add(entitiesTreeScrollPane, c); c.gridx = 0; c.gridy = 2; c.weightx = 1.0; c.weighty = 0.0; c.insets = new Insets(0, 0, 0, 0); c.fill = GridBagConstraints.HORIZONTAL; dialog.getContentPane().add(pathwaysCheckBox, c); JPanel buttonsPanel = new JPanel(new FlowLayout(FlowLayout.RIGHT)); buttonsPanel.add(sendButton); buttonsPanel.add(cancelButton); c.gridx = 0; c.gridy = 3; c.weightx = 1.0; c.weighty = 0.0; c.fill = GridBagConstraints.HORIZONTAL; dialog.getContentPane().add(buttonsPanel, c); dialog.pack(); dialog.setVisible(true); } public static void main(String[] args) { EntityListDialog dialog = new EntityListDialog(); } private static JTree createTree() { DefaultMutableTreeNode root = new DefaultMutableTreeNode( new Node("All Entities")); root.add(new DefaultMutableTreeNode( new Node("Entity 1", "Sample A", "Sample B", "Sample C"))); root.add(new DefaultMutableTreeNode( new Node("Entity 2", "Sample D", "Sample E", "Sample F"))); root.add(new DefaultMutableTreeNode( new Node("Entity 3", "Sample G", "Sample H", "Sample I"))); JTree tree = new JTree(root); RendererDispatcher rendererDispatcher = new RendererDispatcher(tree); tree.setCellRenderer(rendererDispatcher); tree.setCellEditor(rendererDispatcher); tree.setEditable(true); return tree; } } class Node { final String name; final String[] samples; boolean selected; int selectedSampleIndex; public Node(String name, String... samples) { this.name = name; this.selected = false; this.samples = samples; if (samples == null) { this.selectedSampleIndex = -1; } else { this.selectedSampleIndex = 0; } } public boolean isSelected() { return selected; } public void setSelected(boolean selected) { this.selected = selected; } public String toString() { return name; } public int getSelectedSampleIndex() { return selectedSampleIndex; } public void setSelectedSampleIndex(int selectedSampleIndex) { this.selectedSampleIndex = selectedSampleIndex; } public String[] getSamples() { return samples; } } interface Renderer { public void setForeground(final Color foreground); public void setBackground(final Color background); public void setFont(final Font font); public void setEnabled(final boolean enabled); public Component getComponent(); public Object getContents(); } class NodeWithSamplesRenderer implements Renderer { final DefaultComboBoxModel comboBoxModel = new DefaultComboBoxModel(); final JPanel panel = new JPanel(); final JCheckBox checkBox = new JCheckBox(); final JLabel label = new JLabel(" Samples: "); final JComboBox comboBox = new JComboBox(comboBoxModel); final JComponent components[] = {panel, checkBox, comboBox, label}; public NodeWithSamplesRenderer() { Boolean drawFocus = (Boolean) UIManager.get("Tree.drawsFocusBorderAroundIcon"); if (drawFocus != null) { checkBox.setFocusPainted(drawFocus.booleanValue()); } for (int i = 0; i < components.length; i++) { components[i].setOpaque(true); } panel.add(checkBox); panel.add(label); panel.add(comboBox); } public void setForeground(final Color foreground) { for (int i = 0; i < components.length; i++) { components[i].setForeground(foreground); } } public void setBackground(final Color background) { for (int i = 0; i < components.length; i++) { components[i].setBackground(background); } } public void setFont(final Font font) { for (int i = 0; i < components.length; i++) { components[i].setFont(font); } } public void setEnabled(final boolean enabled) { for (int i = 0; i < components.length; i++) { components[i].setEnabled(enabled); } } public void setContents(Node node) { checkBox.setText(node.toString()); comboBoxModel.removeAllElements(); for (int i = 0; i < node.getSamples().length; i++) { comboBoxModel.addElement(node.getSamples()[i]); } } public Object getContents() { String title = checkBox.getText(); String[] samples = new String[comboBoxModel.getSize()]; for (int i = 0; i < comboBoxModel.getSize(); i++) { samples[i] = comboBoxModel.getElementAt(i).toString(); } Node node = new Node(title, samples); node.setSelected(checkBox.isSelected()); node.setSelectedSampleIndex(comboBoxModel.getIndexOf(comboBoxModel.getSelectedItem())); return node; } public Component getComponent() { return panel; } } class NodeWithoutSamplesRenderer implements Renderer { final JCheckBox checkBox = new JCheckBox(); public NodeWithoutSamplesRenderer() { Boolean drawFocus = (Boolean) UIManager.get("Tree.drawsFocusBorderAroundIcon"); if (drawFocus != null) { checkBox.setFocusPainted(drawFocus.booleanValue()); } } public void setForeground(final Color foreground) { checkBox.setForeground(foreground); } public void setBackground(final Color background) { checkBox.setBackground(background); } public void setFont(final Font font) { checkBox.setFont(font); } public void setEnabled(final boolean enabled) { checkBox.setEnabled(enabled); } public void setContents(Node node) { checkBox.setText(node.toString()); } public Object getContents() { String title = checkBox.getText(); Node node = new Node(title); node.setSelected(checkBox.isSelected()); return node; } public Component getComponent() { return checkBox; } } class NoNodeRenderer implements Renderer { final JLabel label = new JLabel(); public void setForeground(final Color foreground) { label.setForeground(foreground); } public void setBackground(final Color background) { label.setBackground(background); } public void setFont(final Font font) { label.setFont(font); } public void setEnabled(final boolean enabled) { label.setEnabled(enabled); } public void setContents(String text) { label.setText(text); } public Object getContents() { return label.getText(); } public Component getComponent() { return label; } } class RendererDispatcher extends AbstractCellEditor implements TreeCellRenderer, TreeCellEditor { final static Color selectionForeground = UIManager.getColor("Tree.selectionForeground"); final static Color selectionBackground = UIManager.getColor("Tree.selectionBackground"); final static Color textForeground = UIManager.getColor("Tree.textForeground"); final static Color textBackground = UIManager.getColor("Tree.textBackground"); final JTree tree; final NodeWithSamplesRenderer nodeWithSamplesRenderer = new NodeWithSamplesRenderer(); final NodeWithoutSamplesRenderer nodeWithoutSamplesRenderer = new NodeWithoutSamplesRenderer(); final NoNodeRenderer noNodeRenderer = new NoNodeRenderer(); final Renderer[] renderers = { nodeWithSamplesRenderer, nodeWithoutSamplesRenderer, noNodeRenderer }; Renderer renderer = null; public RendererDispatcher(JTree tree) { this.tree = tree; Font font = UIManager.getFont("Tree.font"); if (font != null) { for (int i = 0; i < renderers.length; i++) { renderers[i].setFont(font); } } } public Component getTreeCellRendererComponent(JTree tree, Object value, boolean selected, boolean expanded, boolean leaf, int row, boolean hasFocus) { final Node node = extractNode(value); if (node == null) { renderer = noNodeRenderer; noNodeRenderer.setContents(tree.convertValueToText( value, selected, expanded, leaf, row, false)); } else { if (node.getSamples() == null || node.getSamples().length == 0) { renderer = nodeWithoutSamplesRenderer; nodeWithoutSamplesRenderer.setContents(node); } else { renderer = nodeWithSamplesRenderer; nodeWithSamplesRenderer.setContents(node); } } renderer.setEnabled(tree.isEnabled()); if (selected) { renderer.setForeground(selectionForeground); renderer.setBackground(selectionBackground); } else { renderer.setForeground(textForeground); renderer.setBackground(textBackground); } renderer.getComponent().repaint(); renderer.getComponent().invalidate(); renderer.getComponent().validate(); return renderer.getComponent(); } public Component getTreeCellEditorComponent( JTree tree, Object value, boolean selected, boolean expanded, boolean leaf, int row) { return getTreeCellRendererComponent( tree, value, true, expanded, leaf, row, true); } public Object getCellEditorValue() { return renderer.getContents(); } public boolean isCellEditable(final EventObject event) { if (!(event instanceof MouseEvent)) { return false; } final MouseEvent mouseEvent = (MouseEvent) event; final TreePath path = tree.getPathForLocation( mouseEvent.getX(), mouseEvent.getY()); if (path == null) { return false; } Object node = path.getLastPathComponent(); if (node == null || (!(node instanceof DefaultMutableTreeNode))) { return false; } DefaultMutableTreeNode treeNode = (DefaultMutableTreeNode) node; Object userObject = treeNode.getUserObject(); return (userObject instanceof Node); } private static Node extractNode(Object value) { if ((value != null) && (value instanceof DefaultMutableTreeNode)) { DefaultMutableTreeNode node = (DefaultMutableTreeNode) value; Object userObject = node.getUserObject(); if ((userObject != null) && (userObject instanceof Node)) { return (Node) userObject; } } return null; } }

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  • iPack -The iOS Application Packager

    - by user13277780
    iOS applications are distributed in .ipa archive files. These files are regular zip files which contain application resources and executable-s. To protect them from unauthorized modifications and to provide identification of their sources, the content of the archives is signed. The signature is included in the application executable of an.ipa archive and protects the executable file itself and the associated resource files. Apple provides native Mac OS tools for signing iOS executable-s (which are actually generic Mach-O code signing tools), but these tools are not generally available on other platforms. To provide a multi-platform development environment for JavaFX based iOS applications, we ported iOS signing and packaging to Java and created a dedicated ipack tool for it. The iPack tool can be used as a last step of creating .ipa package on various operating systems. Prototype has been tested by creating a final distributable for JavaFX application that runs on iPad, all done on Windows 7. Source Code The source code of iPac tool is in OpenJFX project repository. You can find it in: <openjfx root>/rt/tools/ios/Maven/ipack To build the iPack tool use: rt/tools/ios/Maven/ipack$ mvn package After building, you can run the tool: java -jar <path to ipack.jar> <arguments>  Signing keystore The tool uses a java key store to read the signing certificate and the associated private key. To prepare such keystore users can use keytool from JDK. One possible scenario is to import an existing private key and the certificate from a key store used on Mac OS: To list the content of an existing key store and identify the source alias: keytool -list -keystore <src keystore>.p12 -storetype pkcs12 -storepass <src keystore password> To create Java key store and import the private key with its certificate to the keys store: keytool -importkeystore \ -destkeystore <dst keystore> -deststorepass <dst keystore password> \ -srckeystore <src keystore>.p12 -srcstorepass <src keystore password> -srcstoretype pkcs12 \ -srcalias <src alias> -destalias <dst alias> -destkeypass <dst key password> Another scenario would be to generate a private / public key pair directly in a Java key store and create a certificate request from it. After sending the request to Apple one can then import the certificate response back to the Java key store and complete the signing certificate entry. In both scenarios the resulting alias in the Java key store will contain only a single (leaf) certificate. This can be verified with the following command: keytool -list -v -keystore <ipack keystore> -storepass <keystore password> When looking at the Certificate chain length entry, the number next to it is 1. When an executable file is signed on Mac OS, the resulting signature (in CMS format) includes the whole certificate chain up to the Apple Root CA. The ipack tool includes only the chain which is stored under the alias specified on the command line. So to have the whole chain in the signature we need to replace the single certificate entry under the alias with the corresponding full certificate chain. To do that we need first to create the chain in a separate file. It is easy to create such chain when working with certificates in Base-64 encoded PEM format. A certificate chain can be created by concatenating PEM certificates, which should form the chain, into a single file. For iOS signing we need the following certificates in our chain: Apple Root CA Apple Worldwide Developer Relations CA Our signing leaf certificate To convert a certificate from the binary DER format (.der, .cer) to PEM format: keytool -importcert -noprompt -keystore temp.ks -storepass temppwd -alias tempcert -file <certificate>.cer keytool -exportcert -keystore temp.ks -storepass temppwd -alias tempcert -rfc -file <certificate>.pem To export the signing certificate into PEM format: keytool -exportcert -keystore <ipack keystore> -storepass <keystore password> -alias <signing alias> -rfc -file SigningCert.pem After constructing a chain from AppleIncRootCertificate.pem, AppleWWDRCA.pem andSigningCert.pem, it can be imported back into the keystore with: keytool -importcert -noprompt -keystore <ipack keystore> -storepass <keystore password> -alias <signing alias> -keypass <key password> -file SigningCertChain.pem To summarize, the following example shows the full certificate chain replacement process: keytool -importcert -noprompt -keystore temp.ks -storepass temppwd -alias tempcert1 -file AppleIncRootCertificate.cer keytool -exportcert -keystore temp.ks -storepass temppwd -alias tempcert1 -rfc -file AppleIncRootCertificate.pem keytool -importcert -noprompt -keystore temp.ks -storepass temppwd -alias tempcert2 -file AppleWWDRCA.cer keytool -exportcert -keystore temp.ks -storepass temppwd -alias tempcert2 -rfc -file AppleWWDRCA.pem keytool -exportcert -keystore ipack.ks -storepass keystorepwd -alias mycert -rfc -file SigningCert.pem cat SigningCert.pem AppleWWDRCA.pem AppleIncRootCertificate.pem >SigningCertChain.pem keytool -importcert -noprompt -keystore ipack.ks -storepass keystorepwd -alias mycert -keypass keypwd -file SigningCertChain.pem keytool -list -v -keystore ipack.ks -storepass keystorepwd Usage When the ipack tool is started with no arguments it prints the following usage information: -appname MyApplication -appid com.myorg.MyApplication     Usage: ipack <archive> <signing opts> <application opts> [ <application opts> ... ] Signing options: -keystore <keystore> keystore to use for signing -storepass <password> keystore password -alias <alias> alias for the signing certificate chain and the associated private key -keypass <password> password for the private key Application options: -basedir <directory> base directory from which to derive relative paths -appdir <directory> directory with the application executable and resources -appname <file> name of the application executable -appid <id> application identifier Example: ipack MyApplication.ipa -keystore ipack.ks -storepass keystorepwd -alias mycert -keypass keypwd -basedir mysources/MyApplication/dist -appdir Payload/MyApplication.app -appname MyApplication -appid com.myorg.MyApplication    

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