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  • visual studio Regex Find/Replace error

    - by rockinthesixstring
    I'm working on using Find/Replace to change a bunch of labels to DataBound text. Here's my regex <asp:Label ID="lbl{\d*}" runat="server" /> Here's my replace <%# Eval("\1")%> Here's my Error Unknown argument for ':' operator. Complete Regular Expression required in the search string. How would I resolve this?

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  • String Seach Replace AS3

    - by Ross
    I have a bit of text "this is the text want I want to do is replace the text, I have just added another is for good measure" This is stored as a standard string but I want to turn this into html and add css classes like, in this example wrapping around the word "is"; "this is the text want I want to do is replace the text, I have just added another is for good measure" Any ideas how I can do this in as3?

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  • vbscript multiple replace regex

    - by George
    How do you match more than one pattern in vbscript? Set regEx = New RegExp regEx.Pattern = "[?&]cat=[\w-]+" & "[?&]subcat=[\w-]+" // tried this regEx.Pattern = "([?&]cat=[\w-]+)([?&]subcat=[\w-]+)" // and this param = regEx.Replace(param, "") I want to replace any parameter called cat or subcat in a string called param with nothing. For instance string?cat=meow&subcat=purr or string?cat=meow&dog=bark&subcat=purr I would want to remove cat=meow and subcat=purr from each string.

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  • Regexp: Replace only in specific context

    - by blinry
    In a text, I would like to replace all occurrences of $word by [$word]($word) (to create a link in Markdown), but only if it is not already in a link. Example: [$word homepage](http://w00tw00t.org) should not become [[$word]($word) homepage](http://w00tw00t.org). Thus, I need to check whether $word is somewhere between [ and ] and only replace if it's not the case. Can you think of a preg_replace command for this?

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  • Need to replace HTML single-quote entity in MySQL

    - by modulaaron
    Hi, I currently have the following MySQL statement to replace the HTML entity for a single quote with an actual single quote: update photo_galleries replace(title, '&#39;', '\''); This statement returns an error. I have tried adding additional backslashes, but this does not help at all. I want to run this command using pure SQL (no PHP, etc.). Any suggestions are welcome and appreciated. Thanks.

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  • How to sed search and replace without changing ownership

    - by Ian
    I found this command line search and replace example: find . -type f -print0 | xargs -0 sed -i 's/find/replace/g' It worked fine except it changed the date and file ownership on EVERY file it searched through, even those that did not contain the search text. What's a better solution to this task? Thanks.

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  • Replace text in file with Python

    - by Aaron Hoffman
    I'm trying to replace some text in a file with a value. Everything works fine but when I look at the file after its completed there is a new (blank) line after each line in the file. Is there something I can do to prevent this from happening. Here is the code as I have it: import fileinput for line in fileinput.FileInput("testfile.txt",inplace=1): line = line.replace("newhost",host) print line Thank you, Aaron

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  • Replace occurences of NSString - iPhone

    - by ncohen
    Hi everyone, I have a long NSString in which I m trying to replace special characters. Part of my string looks like this: "veau (c\u00f4telette)","veau (filet)","agneau (gigot)","agneau (c\u00f4telette)","b*\u0153*uf (hach\u00e9)","porc (hach\u00e9)" I would like to replace all the \u0153 with "oe". I ve tried: [response stringByReplacingOccurrencesOfString:@"\u0153" withString:@"oe"]; but it doesn't work.... I don't understand why! Thanks

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  • JavaScript replace()

    - by d3020
    I'm trying to use the replace function in JavaScript and have a question. strNewDdlVolCannRegion = strNewDdlVolCannRegion.replace(/_existing_0/gi, "existing" + "newCounter"); That works. But I need to have the "0" be a variable. I've tried: _ + myVariable +/gi and also tried _ + 'myVariable' + /gi Could someone lend a hand with the syntax for this, please. Thank you.

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  • Replace method doesn't work properly

    - by John Smith
    Hello I have a string and when i try to use replace method in for loop it doesn't work String phrase="hello friend"; String[] wordds=phrase.split(" "); String newPhrase="sup friendhello weirdo"; for (int g=0;g<2;g++) { finalPhrase+=newPhrase.replace(wordds[g],"");} } System.out.println(finalPhrase) It prints out "sup hello weirdo" and i expect it to print "sup weirdo". What am i doing wrong?

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  • Problem with RegEx.Replace and trying to change a filename

    - by fraXis
    Hello, I am having a strange problem and I can't seem to figure it out. My filename is something like this: DER 1513016-3.020F.NCF. I want to be able to change it to: DER 1513016-3.020H.NCF Sometimes the filename can be this as well: DER 1513016-3.020F_NEW.NCF which would change to: DER 1513016-3.020H_NEW.NCF This is my code to do this: OpenFileDialog fDialog = new OpenFileDialog(); fDialog.Title = "Open"; fDialog.Filter = "NCF files (*.ncf)|*.ncf|All files (*.*)|*.*"; fDialog.InitialDirectory = @"C:\Program Files\"; if (fDialog.ShowDialog() == DialogResult.OK) { string newfilename; string fileext = Path.GetExtension(fDialog.FileName); newfilename = Regex.Replace(fDialog.FileName, "F.NCF", "H.NCF"); newfilename = Regex.Replace(fDialog.FileName, "F_NEW.NCF", "H_NEW.NCF"); } This is where things get wierd. The way the code works now, it will NOT change the filename to DER 1513016-3.020H.NCF If I comment out this line of code: //newfilename = Regex.Replace(fDialog.FileName, "F_NEW.NCF", "H_NEW.NCF"); it will work fine and the file will now become: DER 1513016-3.020H.NCF However, if I uncomment that line of code, the filename will not change to DER 1513016-3.020H.NCF. It will stay as DER 1513016-3.020F.NCF. Why is that line of code causing the routine to not change the filename? Thanks,

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  • VS2008 - Find and Replace - Searches too many files.

    - by Pam Bullock
    I've used VS2008 a lot and have never had this problem. However, I started a new job and am using a new machine. Ever since I've gotten here the VS Find feature has been acting funny. I first noticed it when I did a replace all for "All Open Files". The project wouldn't build because the values had actually been replaced in other files within the solution that were not open and didn't even open after I pressed replace all. I have found that I can never use replace all on this machine because I never know what it is going to do. Even if I just do a find on "Current Document", once it's done with the document and I should get that message that says "No more matches found" it actually OPENS another random file from my solution where there is a match and keeps on going. It seems to never make any difference what "Look in" option I've chosen. My coworker has an install off the same disk and claims to not be experiencing this. We're in the middle of a stressful, huge project with a close deadline so I know my boss won't let me do a reinstall. Has anyone else ever had this happen? Anyone know a fix?? Thanks, Pam

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  • Replace apostrophe in json string with empty string

    - by user572844
    Hi, I have problem with deserialization of json string, because string is bad format. For example json object consist string property statusMessage with value "Hello "dog" ". The correct format should be "Hello \" dog \" " . I would like remove apostrophes from this property. Something Like this. "Hello "dog" ". - "Hello dog ". Here is it original json string which I work. "{\"jancl\":{\"idUser\":18438201,\"nick\":\"JANCl\",\"photo\":\"1\",\"sex\":1,\"photoAlbums\":1,\"videoAlbums\":0,\"sefNick\":\"jancl\",\"profilPercent\":75,\"emphasis\":false,\"age\":\"-\",\"isBlocked\":false,\"PHOTO\":{\"normal\":\"http://u.aimg.sk/fotky/1843/82/n_18438201.jpg?v=1\",\"medium\":\"http://u.aimg.sk/fotky/1843/82/m_18438201.jpg?v=1\",\"24x24\":\"http://u.aimg.sk/fotky/1843/82/s_18438201.jpg?v=1\"},\"PLUS\":{\"active\":false,\"activeTo\":\"0000-00-00\"},\"LOCATION\":{\"idRegion\":\"6\",\"regionName\":\"Trenciansky kraj\",\"idCity\":\"138\",\"cityName\":\"Trencianske Teplice\"},\"STATUS\":{\"isLoged\":true,\"isChating\":false,\"idChat\":0,\"roomName\":\"\",\"lastLogin\":1294925369},\"PROJECT_STATUS\":{\"photoAlbums\":1,\"photoAlbumsFavs\":0,\"videoAlbums\":0,\"videoAlbumsFavs\":0,\"videoAlbumsExts\":0,\"blogPosts\":0,\"emailNew\":0,\"postaNew\":0,\"clubInvitations\":0,\"dashboardItems\":1},\"STATUS_MESSAGE\":{\"statusMessage\":\"\"Status\"\",\"addTime\":\"1294872330\"},\"isFriend\":false,\"isIamFriend\":false}}" Problem is here, json string consist this object: "STATUS_MESSAGE": {"statusMessage":" "some "bad" value" ", "addTime" :"1294872330"} Condition of string which I want modified: string start with "statusMessage":" string can has any *lenght from 0 -N * string end with ", "addTime So I try write pattern for string which start with "statusMessage":", has any lenght and is ended with ", "addTime. Here is it: const string pattern = " \" statusMessage \" : \" .*? \",\"addTime\" "; var regex = new Regex(pattern, RegexOptions.IgnoreCase); //here i would replace " with empty string string result = regex.Replace(jsonString, match => ???); But I think pattern is wrong, also I don’t know how replace apostrophe with empty string (remove apostrophne). My goal is : "statusMessage":" "some "bad" value" to "statusMessage":" "some bad value" Thank for advice

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  • C# String.Replace with a start/index (Added my (slow) implementation)

    - by Chris T
    I'd like an efficient method that would work something like this EDIT: Sorry I didn't put what I'd tried before. I updated the example now. // Method signature, Only replaces first instance or how many are specified in max public int MyReplace(ref string source,string org, string replace, int start, int max) { int ret = 0; int len = replace.Length; int olen = org.Length; for(int i = 0; i < max; i++) { // Find the next instance of the search string int x = source.IndexOf(org, ret + olen); if(x > ret) ret = x; else break; // Insert the replacement source = source.Insert(x, replace); // And remove the original source = source.Remove(x + len, olen); // removes original string } return ret; } string source = "The cat can fly but only if he is the cat in the hat"; int i = MyReplace(ref source,"cat", "giraffe", 8, 1); // Results in the string "The cat can fly but only if he is the giraffe in the hat" // i contains the index of the first letter of "giraffe" in the new string The only reason I'm asking is because my implementation I'd imagine getting slow with 1,000s of replaces.

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  • File.Replace throwing IOException

    - by WebDevHobo
    I have an app that can make modify images. In some cases, this makes the filesize smaller, in some cases bigger. The program doesn't have an option to "not replace the file if result has a bigger filesize". So I wrote a little C# app to try and solve this. Instead of overwriting the files, I make the app write the result to a folder under the current one and name that folder Test. The C# app I wrote compares grabs the contents of both folders and puts the full path to the file(s) in two List objects. I then compare and replace. The replacing isn't working however. I get the following IOException: Unable to remove the file to be replaced The location is on an external hard-drive, on which I have full rights. Now, I know I can just do File.Delete and File.Move in that order, but this exception has gotten me interested in why this particular setup wont work. Here's the source code: http://pastebin.com/4Vq82Umu And yes, the file specified as last argument of the Replace function does exist.

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  • using replace to produce javascript code, django

    - by durdenk
    I want to use highcharts with my django site but it requires a comlex javascript code such as below. So I wanted to get this script in my python code and replace apropriate portions then write it in my template, first question is, is this a dump way to do that for a person not knowing javascript. I can read it tough. Second question is, Why I cant replace this string. Lets say this string is a variable like this. lineChartsTemplate = """ ... ... """ if I try and do lineChartsTemplate .replace('dataCategory', dataCategory) it basically suppossed to change dataCategory text with my dataCategory variable, but no such luck. I need guidance here. thx. $(function () { var chart = new Highcharts.Chart({ chart: { renderTo: 'container', type: 'bar' }, xAxis: { categories: dataCategory }, yAxis: { }, legend: { layout: 'vertical', floating: true, backgroundColor: '#FFFFFF', align: 'right', verticalAlign: 'top', y: 60, x: -60 }, tooltip: { formatter: function() { return '<b>'+ this.series.name +'</b><br/>'+ this.x +': '+ this.y; } }, plotOptions: { }, series: [{ data: dataList , name : 'Satislar'}] }); });

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  • String replacement on a whole text file in Python 3.x?

    - by SkippyFire
    How can I replace a string with another string, within a given text file. Do I just loop through readline() and run the replacement while saving out to a new file? Or is there a better way? I'm thinking that I could read the whole thing into memory, but I'm looking for a more elegant solution... Thanks in advance

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  • Advanced Regex: Smart auto detect and replace URLs with anchor tags

    - by Robert Koritnik
    I've written a regular expression that automatically detects URLs in free text that users enter. This is not such a simple task as it may seem at first. Jeff Atwood writes about it in his post. His regular expression works, but needs extra code after detection is done. I've managed to write a regular expression that does everything in a single go. This is how it looks like (I've broken it down into separate lines to make it more understandable what it does): 1 (?<outer>\()? 2 (?<scheme>http(?<secure>s)?://)? 3 (?<url> 4 (?(scheme) 5 (?:www\.)? 6 | 7 www\. 8 ) 9 [a-z0-9] 10 (?(outer) 11 [-a-z0-9/+&@#/%?=~_()|!:,.;cšžcd]+(?=\)) 12 | 13 [-a-z0-9/+&@#/%?=~_()|!:,.;cšžcd]+ 14 ) 15 ) 16 (?<ending>(?(outer)\))) As you may see, I'm using named capture groups (used later in Regex.Replace()) and I've also included some local characters (cšžcd), that allow our localised URLs to be parsed as well. You can easily omit them if you'd like. Anyway. Here's what it does (referring to line numbers): 1 - detects if URL starts with open braces (is contained inside braces) and stores it in "outer" named capture group 2 - checks if it starts with URL scheme also detecting whether scheme is SSL or not 3 - start parsing URL itself (will store it in "url" named capture group) 4-8 - if statement that says: if "sheme" was present then www. part is optional, otherwise mandatory for a string to be a link (so this regular expression detects all strings that start with either http or www) 9 - first character after http:// or www. should be either a letter or a number (this can be extended if you'd like to cover even more links, but I've decided not to because I can't think of a link that would start with some obscure character) 10-14 - if statement that says: if "outer" (braces) was present capture everything up to the last closing braces otherwise capture all 15 - closes the named capture group for URL 16 - if open braces were present, capture closing braces as well and store it in "ending" named capture group First and last line used to have \s* in them as well, so user could also write open braces and put a space inside before pasting link. Anyway. My code that does link replacement with actual anchor HTML elements looks exactly like this: value = Regex.Replace( value, @"(?<outer>\()?(?<scheme>http(?<secure>s)?://)?(?<url>(?(scheme)(?:www\.)?|www\.)[a-z0-9](?(outer)[-a-z0-9/+&@#/%?=~_()|!:,.;cšžcd]+(?=\))|[-a-z0-9/+&@#/%?=~_()|!:,.;cšžcd]+))(?<ending>(?(outer)\)))", "${outer}<a href=\"http${secure}://${url}\">http${secure}://${url}</a>${ending}", RegexOptions.Compiled | RegexOptions.CultureInvariant | RegexOptions.IgnoreCase); As you can see I'm using named capture groups to replace link with an Anchor tag: "${outer}<a href=\"http${secure}://${url}\">http${secure}://${url}</a>${ending}" I could as well omit the http(s) part in anchor display to make links look friendlier, but for now I decided not to. Question I would like my links to be replaced with shortenings as well. So when user copies a very long link (for instance if they would copy a link from google maps that usually generates long links) I would like to shorten the visible part of the anchor tag. Link would work, but visible part of an anchor tag would be shortened to some number of characters. I could as well append ellipsis at the end of at all possible (and make things even more perfect). Does Regex.Replace() method support replacement notations so that I can still use a single call? Something similar as string.Format() method does when you'd like to format values in string format (decimals, dates etc...).

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