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  • Most optimal order (of joins) for left join

    - by Ram
    I have 3 tables Table1 (with 1020690 records), Table2(with 289425 records), Table 3(with 83692 records).I have something like this SELECT * FROM Table1 T1 /* OK fine select * is bad when not all columns are needed, this is just an example*/ LEFT JOIN Table2 T2 ON T1.id=T2.id LEFT JOIN Table3 T3 ON T1.id=T3.id and a query like this SELECT * FROM Table1 T1 LEFT JOIN Table3 T3 ON T1.id=T3.id LEFT JOIN Table2 T2 ON T1.id=T2.id The query plan shows me that it uses 2 Merge Join for both the joins. For the first query, the first merge is with T1 and T2 and then with T3. For the second query, the first merge is with T1 and T3 and then with T2. Both these queries take about the same time(40 seconds approx.) or sometimes Query1 takes couple of seconds longer. So my question is, does the join order matter ?

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  • MySQL LEFT OUTER JOIN virtual table

    - by user1707323
    I am working on a pretty complicated query let me try to explain it to you. Here is the tables that I have in my MySQL database: students Table --- `students` --- student_id first_name last_name current_status status_change_date ------------ ------------ ----------- ---------------- -------------------- 1 John Doe Active NULL 2 Jane Doe Retread 2012-02-01 students_have_courses Table --- `students_have_courses` --- students_student_id courses_course_id s_date e_date int_date --------------------- ------------------- ---------- ---------- ----------- 1 1 2012-01-01 2012-01-04 2012-01-05 1 2 2012-01-05 NULL NULL 2 1 2012-01-10 2012-01-11 NULL students_have_optional_courses Table --- `students_have_optional_courses` --- students_student_id optional_courses_opcourse_id s_date e_date --------------------- ------------------------------ ---------- ---------- 1 1 2012-01-02 2012-01-03 1 1 2012-01-06 NULL 1 5 2012-01-07 NULL Here is my query so far SELECT `students_and_courses`.student_id, `students_and_courses`.first_name, `students_and_courses`.last_name, `students_and_courses`.courses_course_id, `students_and_courses`.s_date, `students_and_courses`.e_date, `students_and_courses`.int_date, `students_have_optional_courses`.optional_courses_opcourse_id, `students_have_optional_courses`.s_date, `students_have_optional_courses`.e_date FROM ( SELECT `c_s_a_s`.student_id, `c_s_a_s`.first_name, `c_s_a_s`.last_name, `c_s_a_s`.courses_course_id, `c_s_a_s`.s_date, `c_s_a_s`.e_date, `c_s_a_s`.int_date FROM ( SELECT `students`.student_id, `students`.first_name, `students`.last_name, `students_have_courses`.courses_course_id, `students_have_courses`.s_date, `students_have_courses`.e_date, `students_have_courses`.int_date FROM `students` LEFT OUTER JOIN `students_have_courses` ON ( `students_have_courses`.`students_student_id` = `students`.`student_id` AND (( `students_have_courses`.`s_date` >= `students`.`status_change_date` AND `students`.current_status = 'Retread' ) OR `students`.current_status = 'Active') ) WHERE `students`.current_status = 'Active' OR `students`.current_status = 'Retread' ) `c_s_a_s` ORDER BY `c_s_a_s`.`courses_course_id` DESC ) `students_and_courses` LEFT OUTER JOIN `students_have_optional_courses` ON ( `students_have_optional_courses`.students_student_id = `students_and_courses`.student_id AND `students_have_optional_courses`.s_date >= `students_and_courses`.s_date AND `students_have_optional_courses`.e_date IS NULL ) GROUP BY `students_and_courses`.student_id; What I want to be returned is the student_id, first_name, and last_name for all Active or Retread students and then LEFT JOIN the highest course_id, s_date, e_date, and int_date for the those students where the s_date is since the status_change_date if status is 'Retread'. Then LEFT JOIN the highest optional_courses_opcourse_id, s_date, and e_date from the students_have_optional_courses TABLE where the students_have_optional_courses.s_date is greater or equal to the students_have_courses.s_date and the students_have_optional_courses.e_date IS NULL Here is what is being returned: student_id first_name last_name courses_course_id s_date e_date int_date optional_courses_opcourse_id s_date_1 e_date_1 ------------ ------------ ----------- ------------------- ---------- ---------- ------------ ------------------------------ ---------- ---------- 1 John Doe 2 2012-01-05 NULL NULL 1 2012-01-06 NULL 2 Jane Doe NULL NULL NULL NULL NULL NULL NULL Here is what I want being returned: student_id first_name last_name courses_course_id s_date e_date int_date optional_courses_opcourse_id s_date_1 e_date_1 ------------ ------------ ----------- ------------------- ---------- ---------- ------------ ------------------------------ ---------- ---------- 1 John Doe 2 2012-01-05 NULL NULL 5 2012-01-07 NULL 2 Jane Doe NULL NULL NULL NULL NULL NULL NULL Everything is working except one thing, I cannot seem to get the highest students_have_optional_courses.optional_courses_opcourse_id no matter how I form the query Sorry, I just solved this myself after writing this all out I think it helped me think of the solution. Here is the solution query: SELECT `students_and_courses`.student_id, `students_and_courses`.first_name, `students_and_courses`.last_name, `students_and_courses`.courses_course_id, `students_and_courses`.s_date, `students_and_courses`.e_date, `students_and_courses`.int_date, `students_optional_courses`.optional_courses_opcourse_id, `students_optional_courses`.s_date, `students_optional_courses`.e_date FROM ( SELECT `c_s_a_s`.student_id, `c_s_a_s`.first_name, `c_s_a_s`.last_name, `c_s_a_s`.courses_course_id, `c_s_a_s`.s_date, `c_s_a_s`.e_date, `c_s_a_s`.int_date FROM ( SELECT `students`.student_id, `students`.first_name, `students`.last_name, `students_have_courses`.courses_course_id, `students_have_courses`.s_date, `students_have_courses`.e_date, `students_have_courses`.int_date FROM `students` LEFT OUTER JOIN `students_have_courses` ON ( `students_have_courses`.`students_student_id` = `students`.`student_id` AND (( `students_have_courses`.`s_date` >= `students`.`status_change_date` AND `students`.current_status = 'Retread' ) OR `students`.current_status = 'Active') ) WHERE `students`.current_status = 'Active' OR `students`.current_status = 'Retread' ) `c_s_a_s` ORDER BY `c_s_a_s`.`courses_course_id` DESC ) `students_and_courses` LEFT OUTER JOIN ( SELECT * FROM `students_have_optional_courses` ORDER BY `students_have_optional_courses`.optional_courses_opcourse_id DESC ) `students_optional_courses` ON ( `students_optional_courses`.students_student_id = `students_and_courses`.student_id AND `students_optional_courses`.s_date >= `students_and_courses`.s_date AND `students_optional_courses`.e_date IS NULL ) GROUP BY `students_and_courses`.student_id;

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  • Android -- SDK/IDE Layout Bug (w/Custom Layouts)??

    - by borg17of20
    Hello all, Can someone tell me if this is a bug in the SDK/IDE: Any custom or extended layout I add to my layout XML causes the IDE to ignore the fact that there are any child views of that layout (they just disappear from the outline view/window), thus making them uneditable via the properties view/window. (I need to extend a layout to make onSetAlpha() public) FYI: I'm developing for Android 1.5 and up, using all the latest plug-ins/updates in Eclipse Here is a simple example of a layout XML and the extended Layout that causes this error. [Extended Layout] package com.test; public class CustomLinearLayout extends LinearLayout { public CustomLinearLayout(Context context, AttributeSet attrs) { super(context, attrs); } public CustomLinearLayout(Context context) { super(context); } } [Simple layout XML] <?xml version="1.0" encoding="utf-8"?> <com.test.CustomLinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="wrap_content" android:layout_height="wrap_content"> <ImageView android:id="@+id/ImageView01" android:layout_width="wrap_content" android:layout_height="wrap_content"></ImageView> </com.test.CustomLinearLayout> ImageView01 is not visible or editable in the properties or outline views/windows. Thanks.

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  • Remote Desktop to home server: From mac gives english keyboard layout, from pc gives norwegian layou

    - by format71
    I'm trying to connect to my home server from my mac, but struggle with typing the password, which contains a plus sign. I have a norwegian keyboard layout, and when I log in from windows (via wmware), I get a norwegian keyboard at the logon screen, but when I connect directly from the mac, I get a english keyboard layout, which makes it impossible to type my password... Why does it give me a different layout for the mac? How can I type a plus sign? The key that should give me a plus sign if the keyboard was english, is the key that contains the ´ and `, and using this button doesn't give me anything in the login prompt... regards, -Vegar

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  • CSS layout problem on Firefox with filling space between end of left column and footer

    - by Jean
    Basically, the left column is supposed to extend to the footer with the continuous red color. However, in Firefox on pages with lots of text, the column does not extend to the footer and leaves a large white gap--see site: http://library.luhs.org/JHSII/about.html I've tried readjusting the heights, creating the sticky footer, and other things I've read about on this site. So I admit that I'm stumped, and what's really odd is that the layout seems to work in IE as there is no white space! I didn't create the site, but I recently inherited it and trying to work through the mess Any help is much appreciated, here's the CSS #html,body{ margin:0; padding:0; border:0; height:100%; } #body{ background:#ffffff; min-width:965px; text-align:center; width: 600px; font: Geneva, Arial, Helvetica, sans-serif; } #.style7{ clear:both; height:1px; overflow:hidden; line-height:1%; font-size:0px; margin-bottom:-1px; } #fullheightcontainer{ margin-left:auto; margin-right:auto; text-align:left; position:relative; width:965px; height:100%; } #wrapper{ min-height:100%; height:100%; background:#660000; background-color: #660000; background-repeat: repeat; } #wrapp\65 r{ height:auto; } # html wrapper{ height:100%; } #outer{ z-index:1; position:relative; margin-left:150px; width:815px; background:#FFFFFF; height:100%; background-color: #FFFFFF; } #left{ width:151px; float:left; display:inline; position:relative; margin-left:-150px; } padding: 20px; border: 0; margin: 0 0 0 240px *>html #left{width:150px;} #container-left{ width:150px; color: #CCCCCC; } * html #left{margin-right:-3px;} #center{ width:800px; float:right; display:inline; margin-left:-1px; } #clearheadercenter{ height:125px; overflow:hidden; } #clearfootercenter{ height:50px; overflow:hidden; } #footer{ z-index:1; position:relative; clear: both; width:965px; height:50px; overflow:hidden; margin-top:-50px; background-color: #660000; } #subfooter1{ background:#FFFFCC; text-align:left; margin-left:150px; height:50px; } #header{ z-index:1; position:absolute; top:0px; width:815px; margin-left:150px; height:100px; overflow:hidden; background-color: #660000; } #subheader1{ background:#FFFFCC; text-align:center; height:70px; } #gfx_bg_middle{ top:0px; position:absolute; height:100%; overflow:hidden; width:815px; margin-left:150px; background:#FFFFFF; } # html #gfx_bg_middle{ display:none; } #floatingnav { margin: 5px 10px 5px 5px; padding: 0px 5px 5px; float: right; font: .75em/1.35em Geneva, Arial, Helvetica, sans-serif; height: 600px; width: 300px; } #floatingnav a { color: #630; } #floatingnav ul { margin-top: -5; } #.floatright { float: right; margin: 0 0 10px 10px; border: 1px solid #666; padding: 2px; } #outer{ word-wrap:break-word; } #table.s1 { border-width: medium; border-spacing: 2px; border-style: none; border-color: rgb(85, 0, 0); border-collapse: collapse; background-color: white; } #table.s1 th { border-width: medium; padding: 2px; border-style: groove; border-color: red; background-color: white; -moz-border-radius: 0px 0px 0px 0px; } #table.s1 td { border-width: medium; padding: 2px; border-style: groove; border-color: #660000; background-color: #FFFFFF; -moz-border-radius: 0px 0px 0px 0px; } #a:link { color: #000066; } #a:visited { color: #000066; } #p.sample { font-family: serif; font-style: normal; font-variant: normal; font-weight: normal; font-size: medium; line-height: 100%; word-spacing: normal; letter-spacing: normal; text-decoration: none; text-transform: none; text-align: left; text-indent: 0ex; }

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  • Linear Layout Issue at Runtime

    - by George
    Hi all, I am trying to build a layout dynamically which display some text and image for the most part, but has a series of buttons placed next to each other in the bottom. I have a linear layout that carries the text, another linear layout that carries the image. And yet another linear layout that carries the buttons that get created in a for loop. I have a main layout aligned vertical that adds the text, image and buttons layout, in that order. To finally generate something like this: Text .... Image ... Button1 Button2 Button3.... The problem is the number of buttons get decided at runtime, so if there are more than 4 buttons, the 5th button gets displayed really tiny. Also, when I tilt the phone, I get only the text and image showing, but no buttons coz the image covers the entire screen. Layoutting seems to be pretty complicated to me, any help is appreciated! Thanks George

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  • SQL Oracle LEFT JOIN and SUBQUERY error: ORA-00905: missing keyword

    - by Curro
    Hello everyone. Asking for your help on this Oracle query. It's giving me the error 2 "ORA-00905: missing keyword". It was working fine before I added the LEFT JOIN statement. Obviously it won't deliver the information as we need it without the LEFT JOIN statement. Please provide any help to know which keyword is missing in this query Thanks a lot!: DB Tables: DW.TICKETS DW.TICKET_ACTLOG Subquery table: TABLE_RESOLVERS SELECT TO_CHAR(DW.TICKETS.RESOLVED_TIMESTAMP,'YYYY-MM-DD HH24:MI:SS') AS RESOLVED_DATE, DW.TICKETS.SUBJECT, DW.TICKETS.OWNER_CORE_ID, DW.TICKETS.TICKET_NUMBER, TABLE_RESOLVERS.SUBMITTER AS RESOLVER_CORE_ID FROM DW.TICKETS LEFT JOIN (SELECT TICKET_NUMBER, SUBMITTER FROM DW.TICKET_ACTLOG WHERE TYPE = 'Final Resolution' AND (SUBMITTER = 'B02666' OR SUBMITTER = 'R66604') ORDER BY CREATE_TIMESTAMP DESC ) AS TABLE_RESOLVERS ON DW.TICKETS.TICKET_NUMBER = TABLE_RESOLVERS.TICKET_NUMBER WHERE DW.TICKETS.RESOLVED_TIMESTAMP >= to_date('05-03-2010','dd-mm-yyyy') AND DW.TICKETS.RESOLVED_TIMESTAMP < to_date('8-03-2010','dd-mm-yyyy') AND DW.TICKETS.TICKET_NUMBER LIKE 'TCK%' AND DW.TICKETS.TICKET_NUMBER IN (SELECT TICKET_NUMBER FROM DW.TICKET_ACTLOG WHERE (SUBMITTER = 'B02666' OR SUBMITTER = 'R66604') ) ORDER BY DW.TICKETS.CREATE_TIMESTAMP ASC

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  • Remove Duplicates from LEFT OUTER JOIN

    - by Kaushik Gopal
    Hey folk my question is quite similar to http://stackoverflow.com/questions/757957/restricting-a-left-join I have a variation in that request though and the comment didn't allow too many characters hence posting as a new question. I hope this doesn't go against the posting rules/etiquette. Assuming i have a table SHOP and another table LOCATION. Location is a sort of child table of table SHOP, that has two columns of interest, one is a Division Key (calling it just KEY) and a "SHOP" number. This matches to the Number "NO" in table SHOP. I tried this left outer join: SELECT S.NO, L.KEY FROM SHOP S LEFT OUTER JOIN LOCATN L ON S.NO = L.SHOP But i'm getting a lot of duplicates since there are many locations that belong to a single shop. I want to eliminate them and just get a list of "shop, key" entries without duplicates. any ideas how? (edit: ORACLE 10g Database)

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  • "SELECT TOP", "LEFT OUTER JOIN", "ORDER BY" gives extra rows

    - by Codesleuth
    I have the following Access query I'm running through OLE DB in .NET: SELECT TOP 25 tblClient.ClientCode, tblRegion.Region FROM (tblClient LEFT OUTER JOIN tblRegion ON tblClient.RegionCode = tblRegion.RegionCode) ORDER BY tblRegion.Region There are 431 records within tblClient that have RegionCode set to NULL. For some reason, the query above returns all these 431 records instead of the first 25. If I change the query to ORDER BY tblClient.Client (the name of the client) like so: SELECT TOP 25 tblClient.ClientCode, tblRegion.Region FROM (tblClient LEFT OUTER JOIN tblRegion ON tblClient.RegionCode = tblRegion.RegionCode) ORDER BY tblClient.Client I get the expected result set of 25 records, showing a mixture of region names and NULL values. Why is it that ordering by a field retrieved through a LEFT OUTER JOIN will the TOP clause not work?

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  • CSS Problem, fixed contentarea with left and right sidebar?

    - by mathiregister
    Hey guys, i really need your help with a CSS-Layout. I tried a few time, however i've no chance (and actually no idea how) to solve it. Moreover I don't even know if it's possible the way I want it! The #mainContent should always be centered horizontally in the browserwindow. It should be 1024px in width and a 100% of the windowheight. Now the difficult part. I need two divs, one on the left side, one on the right side of the #mainContent. Both should be 100% in height, but should ALWAYS have the rest of the browserwindow. If the browserwindow has only 1024px in width #navLeft and #navRight are invisible. Is that even possible, if so, HOW? thank you

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  • Left Join Returning Extra Rows T-SQL?

    - by davemackey
    I have the following query: select * from ACADEMIC a left join RESIDENCY r on a.PEOPLE_CODE_ID = r.PEOPLE_CODE_ID where a.ACADEMIC_TERM='Fall' and r.ACADEMIC_TERM='Fall' and a.ACADEMIC_SESSION='' and a.ACADEMIC_YEAR = (Select Year(GetDate())) and r.ACADEMIC_YEAR = (Select Year(GetDate())) and (CLASS_LEVEL LIKE 'FR%' OR a.CLASS_LEVEL LIKE 'SO' OR a.CLASS_LEVEL LIKE 'JR' OR a.CLASS_LEVEL LIKE 'SR%') and r.RESIDENT_COMMUTER='R' For each person in the database it returns two rows with identical information. Yet, when I do the same query without the left join: select * from ACADEMIC a where a.ACADEMIC_TERM='Fall' and a.ACADEMIC_SESSION='' and a.ACADEMIC_YEAR = (Select Year(GetDate())) and (CLASS_LEVEL LIKE 'FR%' OR a.CLASS_LEVEL LIKE 'SO' OR a.CLASS_LEVEL LIKE 'JR' OR a.CLASS_LEVEL LIKE 'SR%') ORDER BY PEOPLE_ID It returns only one row for each person. I'm doing a left join - why is it adding an extra row? Shouldn't it only do that if I add a right join?

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  • Why is my left join not returning nulls?

    - by Griz
    In sql server 2008, I have the following query: select c.title as categorytitle, s.title as subcategorytitle, i.title as itemtitle from categories c join subcategories s on c.categoryid = s.categoryid left join itemcategories ic on s.subcategoryid = ic.subcategoryid left join items i on ic.itemid = i.itemid where (ic.isactive = 1 or ic.isactive is null) and i.siteid = 132 order by c.title, s.title I am trying to get items in their subcategories, but I still want to return a record if there are no items in the category or subcategory. Subcategories that have no items are never returned. What am I doing wrong? Thank you EDIT Modified query with a second left join and where clause, but it's still not returning nulls. :/

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  • MySQL LEFT JOIN issue with three WHERE statements

    - by jhat
    I am building a note taking app for myself with tag filtering functions, but am having an issue when trying to grab notes with the tags. The tag filter needs to use AND not IN, because it will help better narrow down what I am looking for. My tables are configured like this: + notes note_id | note_title | note_uid + tags tag_id | tag_title + notes_tags nt_id | nt_note_id | nt_tag_id The notes_tags table keeps track of all notes' tags. I am not worried about returning any information about tags, so here is an example LEFT JOIN I am using currently to only get notes with only 1 tag. SELECT * FROM notes_tags LEFT JOIN notes ON note_id = nt_note_id WHERE note_uid IN ( 1 ) AND nt_tag_id = 10 This query runs perfect, it grabs all of the notes with that single tag. However, I am having issues "pinpointing" my notes using a query like this: SELECT * FROM notes_tags LEFT JOIN notes ON note_id = nt_note_id WHERE note_uid IN ( 1 ) AND nt_tag_id = 10 AND nt_tag_id = 11 What am I doing wrong with the syntax?

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  • Linq, double left join and double count

    - by Fabian Vilers
    Hi! I'm looking to translate this SQL statement to a well working & performant LINQ command. I've managed to have the first count working using the grouping count and key members, but don't know how to get the second count. select main.title, count(details.id) as details, count(messages.id) as messages from main left outer join details on main.id = details.mainid left outer join messages on details.id = messages.detailid group by main.title Any advice is welcome! Fabian

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  • NHibernate Left Outer Join

    - by Matthew
    I'm looking to create a Left outer join Nhibernate query with multiple on statements akin to this: SELECT * FROM [Database].[dbo].[Posts] p LEFT JOIN [Database].[dbo].[PostInteractions] i ON p.PostId = i.PostID_TargetPost And i.UserID_ActingUser = 202 I've been fooling around with the critera and aliases, but I haven't had any luck figuring out how do to this. Any suggestions?

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  • linq to entites left outer join

    - by parminder
    I am struggling linq to entities left outer join. I have two entities (tables): Listings { ListingID, MakeID (nullable) } Makes { MakeID, Description } I want to write something like this in LINQ: select listings.listingID ,listings.makeid , IsNull(makes.Description, 'NA') from listings left outer join makes on listings.makeid = makes.makeid

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  • LINQ 2 SQL:Left outer join for my SQL statement

    - by Shyju
    Can any one tell me the LINQ 2 SQL version (in vb.net) of the below Left outer join query.I am trying to get all Employees with name "Shyju" and their address line 1 if it exist in the address table SELECT E.EMPLOYEE_NAME, E.AGE,A.ADRESS_LINE1 FROM EMPLOYEE_MASTER E LEFT OUTER JOIN ADDRESS_MASTER A ON E.ID=A.EMPLOYEE_ID WHERE E.EMPLOYEE_NAME='Shyju' Thanks in advance

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  • Android: Adding extended GLSurfaceView to a Layout don't show 3d stuff

    - by Santiago
    I make a game extending the class GLSurfaceView, if I apply SetContentView directly to that class, the 3d stuff and input works great. Now I want to show some items over 3d stuff, so I create a XML with a layout and some objects, and I try to add my class manually to the layout. I'm not getting errors but the 3d stuff is not shown but I can view the objects from XML layout. source: @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); LayoutInflater inflater = (LayoutInflater) getSystemService(LAYOUT_INFLATER_SERVICE); layout = (RelativeLayout) inflater.inflate(R.layout.testlayout, null); //Create an Instance with this Activity my3dstuff = new myGLSurfaceViewClass(this); layout.addView(my3dstuff,4); setContentView(R.layout.testlayout); } And testlayout have: <?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="wrap_content" android:layout_height="wrap_content" android:id="@+id/Pantalla"> <ImageView android:id="@+id/zoom_less" android:layout_width="wrap_content" android:layout_height="wrap_content" android:src="@drawable/zoom_less"></ImageView> <ImageView android:id="@+id/zoom_more" android:layout_width="wrap_content" android:src="@drawable/zoom_more" android:layout_height="wrap_content" android:layout_alignParentRight="true"></ImageView> <ImageView android:id="@+id/zoom_normal" android:layout_width="wrap_content" android:layout_height="wrap_content" android:src="@drawable/zoom_normal" android:layout_centerHorizontal="true"></ImageView> <ImageView android:id="@+id/stop" android:layout_width="wrap_content" android:layout_height="wrap_content" android:src="@drawable/stop" android:layout_centerInParent="true" android:layout_alignParentBottom="true"></ImageView> </RelativeLayout> I also tried to add my class to XML but the Activity hangs up. <com.mygame.myGLSurfaceViewClass android:id="@+id/my3dstuff" android:layout_width="fill_parent" android:layout_height="fill_parent"></com.mygame.myGLSurfaceViewClass> and this don't works: <View class="com.mygame.myGLSurfaceViewClass" android:id="@+id/my3dstuff" android:layout_width="fill_parent" android:layout_height="fill_parent"></View> Any Idea? Thanks

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  • An Ideal Keyboard Layout for Programming

    - by Jon Purdy
    I often hear complaints that programming languages that make heavy use of symbols for brevity, most notably C and C++ (I'm not going to touch APL), are difficult to type because they require frequent use of the shift key. A year or two ago, I got tired of it myself, downloaded Microsoft's Keyboard Layout Creator, made a few changes to my layout, and have not once looked back. The speed difference is astounding; with these few simple changes I am able to type C++ code around 30% faster, depending of course on how hairy it is; best of all, my typing speed in ordinary running text is not compromised. My questions are these: what alternate keyboard layouts have existed for programming, which have gained popularity, are any of them still in modern use, do you personally use any altered layout, and how can my layout be further optimised? I made the following changes to a standard QWERTY layout. (I don't use Dvorak, but there is a programmer Dvorak layout worth mentioning.) Swap numbers with symbols in the top row, because long or repeated literal numbers are typically replaced with named constants; Swap backquote with tilde, because backquotes are rare in many languages but destructors are common in C++; Swap minus with underscore, because underscores are common in identifiers; Swap curly braces with square brackets, because blocks are more common than subscripts; and Swap double quote with single quote, because strings are more common than character literals. I suspect this last is probably going to be the most controversial, as it interferes the most with running text by requiring use of shift to type common contractions. This layout has significantly increased my typing speed in C++, C, Java, and Perl, and somewhat increased it in LISP and Python.

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  • Cannot right click desktop windows xp

    - by Robert Harvey
    This occurred after a Trojan incident. We managed to get the Trojan cleaned off the computer, but now we can't Right click the desktop. We have tried changing HKCU/software/microsoft/windows/current version/policies/explorer/noviewcontextmenu in the registry, and group policy user configuration/administrative templates/windows explorer/remove windows explorers default context menu, but neither worked. How do we reenable the right-click menu for the desktop? (it works everywhere else)

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  • Right Clicking error in windows 7 windows explorer

    - by Domenik VanBuskirk
    Whenever I right-click something in windows explorer other than favorites, libraries, computer, or network (the main headings in the left pane), the drop-down menu does not appear and an error pops up "windows explorer has stopped working" - "windows explorer is restarting". Once those both close the icons on the desktop and taskbar itself blink off and back on again. Is there any way of finding out what is going on when I right click and this problem ensues?

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  • Linq, Left Join and Dates...

    - by BitFiddler
    So my situation is that I have a linq-to-sql model that does not allow dates to be null in one of my tables. This is intended, because the database does not allow nulls in that field. My problem, is that when I try to write a Linq query with this model, I cannot do a left join with that table anymore because the date is not a 'nullable' field and so I can't compare it to "Nothing". Example: There is a Movie table, {ID,MovieTitle}, and a Showings table, {ID,MovieID,ShowingTime,Location} Now I am trying to write a statement that will return all those movies that have no showings. In T.SQL this would look like: Select m.* From Movies m Left Join Showings s On m.ID = s.MovieID Where s.ShowingTime is Null Now in this situation I could test for Null on the 'Location' field but this is not what I have in reality (just a simplified example). All I have are non-null dates. I am trying to write in Linq: From m In dbContext.Movies _ Group Join s In Showings on m.ID Equals s.MovieID into MovieShowings = Group _ From ms In MovieShowings.DefaultIfEmpty _ Where ms.ShowingTime is Nothing _ Select ms However I am getting an error saying 'Is' operator does not accept operands of type 'Date'. Operands must be reference or nullable types. Is there any way around this? The model is correct, there should never be a null in the Showings:ShowTime table. But if you do a left join, and there are no show times for a particular movie, then ShowTime SHOULD be Nothing for that movie... Thanks everyone for your help.

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  • Display a ranking grid for game : optimization of left outer join and find a player

    - by Jerome C.
    Hello, I want to do a ranking grid. I have a table with different values indexed by a key: Table SimpleValue : key varchar, value int, playerId int I have a player which have several SimpleValue. Table Player: id int, nickname varchar Now imagine these records: SimpleValue: Key value playerId for 1 1 int 2 1 agi 2 1 lvl 5 1 for 6 2 int 3 2 agi 1 2 lvl 4 2 Player: id nickname 1 Bob 2 John I want to display a rank of these players on various SimpleValue. Something like: nickname for lvl Bob 1 5 John 6 4 For the moment I generate an sql query based on which SimpleValue key you want to display and on which SimpleValue key you want to order players. eg: I want to display 'lvl' and 'for' of each player and order them on the 'lvl' The generated query is: SELECT p.nickname as nickname, v1.value as lvl, v2.value as for FROM Player p LEFT OUTER JOIN SimpleValue v1 ON p.id=v1.playerId and v1.key = 'lvl' LEFT OUTER JOIN SimpleValue v2 ON p.id=v2.playerId and v2.key = 'for' ORDER BY v1.value This query runs perfectly. BUT if I want to display 10 different values, it generates 10 'left outer join'. Is there a way to simplify this query ? I've got a second question: Is there a way to display a portion of this ranking. Imagine I've 1000 players and I want to display TOP 10, I use the LIMIT keyword. Now I want to display the rank of the player Bob which is 326/1000 and I want to display 5 rank player above and below (so from 321 to 331 position). How can I achieve it ? thanks.

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  • How can I automatically change the system keyboard layout when plugging in an external keyboard?

    - by Andrew Bolster
    I have a US-Style laptop, which is fine, but I also have a UK-style Ergonomic USB keyboard. As such I usually have the US key layout set, but when I settle in at my desk and use the UK USB keyboard I find myself making stupid mistakes on symbols (normally a pretty good touch typist on either ergo or standard kbd). Can anyone think of a clean way of setting the keyboard layout based on the inferred layout/USBID of any plugged in Keyboard? Even having a custom setting such as adding a specific USB ID to a runtime script that checks if its plugged in or not. Can this be done without the user having to logout/in? I remember doing something similar with xorg.conf, but that required logout.

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