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  • Best way to convert a Unicode URL to ASCII (UTF-8 percent-escaped) in Python?

    - by benhoyt
    I'm wondering what's the best way -- or if there's a simple way with the standard library -- to convert a URL with Unicode chars in the domain name and path to the equivalent ASCII URL, encoded with domain as IDNA and the path %-encoded, as per RFC 3986. I get from the user a URL in UTF-8. So if they've typed in http://?.ws/? I get 'http://\xe2\x9e\xa1.ws/\xe2\x99\xa5' in Python. And what I want out is the ASCII version: 'http://xn--hgi.ws/%E2%99%A5'. What I do at the moment is split the URL up into parts via a regex, and then manually IDNA-encode the domain, and separately encode the path and query string with different urllib.quote() calls. # url is UTF-8 here, eg: url = u'http://?.ws/?'.encode('utf-8') match = re.match(r'([a-z]{3,5})://(.+\.[a-z0-9]{1,6})' r'(:\d{1,5})?(/.*?)(\?.*)?$', url, flags=re.I) if not match: raise BadURLException(url) protocol, domain, port, path, query = match.groups() try: domain = unicode(domain, 'utf-8') except UnicodeDecodeError: return '' # bad UTF-8 chars in domain domain = domain.encode('idna') if port is None: port = '' path = urllib.quote(path) if query is None: query = '' else: query = urllib.quote(query, safe='=&?/') url = protocol + '://' + domain + port + path + query # url is ASCII here, eg: url = 'http://xn--hgi.ws/%E3%89%8C' Is this correct? Any better suggestions? Is there a simple standard-library function to do this?

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  • Can PuTTY be configured to display the following UTF-8 characters?

    - by Stuart Powers
    I'd like to be able to render the characters as seen in this tweet: I saved the tweet's JSON data and wrote a one-liner python script for testing. python -c 'import json,urllib; print json.load(urllib.urlopen("http://c.sente.cc/BUCq/tweet.json"))["text"]' This next image shows the output of this command on two different putty sessions, one with Bitstream Vera Sans Mono font and the other is using Courier New: Next is an example of correct output (I wasn't using PuTTY): The original JSON is at this link using Twitter's API. How can I get PuTTY to display those characters?

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  • Extracting an attribute value with beautifulsoup

    - by Barnabe
    I am trying to extract the content of a single "value" attribute in a specific "input" tag on a webpage. I use the following code: import urllib f = urllib.urlopen("http://58.68.130.147") s = f.read() f.close() from BeautifulSoup import BeautifulStoneSoup soup = BeautifulStoneSoup(s) inputTag = soup.findAll(attrs={"name" : "stainfo"}) output = inputTag['value'] print str(output) I get a TypeError: list indices must be integers, not str even though from the Beautifulsoup documentation i understand that strings should not be a problem here... but i a no specialist and i may have misunderstood. Any suggestion is greatly appreciated! Thanks in advance.

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  • python coockie,request another page

    - by polovinamozga
    #!/usr/bin/python # -*- coding: utf-8 -*- import urllib2 import urllib import httplib import Cookie import cookielib Login = 'user' Password = 'password' Domain = 'inbox.ru' Auth = 'https://auth.mail.ru/cgi-bin/auth' cj = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(cj)) login_data = urllib.urlencode({'Login' : Login, 'Domain' :Domain, 'Password' : Password }) opener.open('https://auth.mail.ru/cgi-bin/auth', login_data) resp = opener.open('https://auth.mail.ru/cgi-bin/auth').read() print resp.decode('cp1251') #output page in cp1251 When script sucessfully executed i see in print resp.decode('cp1251') my page with auth. But when a try to request another page for example http://my.mail.ru i see autorization request. How i can use cookie with another page?

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  • encryption decryption function in php

    - by parthav
    import gnupg, urllib retk = urllib.urlopen("http://keyserver.pramberger.at/pks/" "lookup?op=get&search=userid for the key is required") pub_key = retk.read() #print pub_key gpg = gnupg.GPG(gnupghome="/tmp/foldername", verbose=True) print "Import the Key :", gpg.import_keys(pub_key).summary() print "Encrypt the Message:" msg = "Hellllllllllo" uid = "userid that has the key on public key server" enc = gpg.encrypt(msg, uid,always_trust=True) print "*The enc content***************************== ", enc this function written in python gives me encrypted message.The encryption is done using the public key which i am getting from public key server(pramberger.at). Now how can i implement the same functionality (getting the key from any public key server and using that key encrypt the message) in php

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  • Facebook publish HTTP Error 400 : bad request

    - by Abhishek
    Hey I am trying to publish a score to Facebook through python's urllib2 library. import urllib2,urllib url = "https://graph.facebook.com/USER_ID/scores" data = {} data['score']=SCORE data['access_token']='APP_ACCESS_TOKEN' data_encode = urllib.urlencode(data) request = urllib2.Request(url, data_encode) response = urllib2.urlopen(request) responseAsString = response.read() I am getting this error: response = urllib2.urlopen(request) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 124, in urlopen return _opener.open(url, data, timeout) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 389, in open response = meth(req, response) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 502, in http_response 'http', request, response, code, msg, hdrs) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 427, in error return self._call_chain(*args) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 361, in _call_chain result = func(*args) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 510, in http_error_default raise HTTPError(req.get_full_url(), code, msg, hdrs, fp) urllib2.HTTPError: HTTP Error 400: Bad Request Not sure if this is relating to Facebook's Open Graph or improper urllib2 API use.

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  • pycurl script can't login to website

    - by The Jug
    I'm currently trying to get a grasp on pycurl. I'm attempting to login to my own website. After logging into the site it should redirect to the main page. However when trying this script it just gets returned to the login page. What might I be doing wrong? import pycurl import urllib import StringIO import pycurl pf = {'username' : 'user', 'password' : 'pass' } fields = urllib.urlencode(pf) pageContents = StringIO.StringIO() p = pycurl.Curl() p.setopt(pycurl.FOLLOWLOCATION, 1) p.setopt(pycurl.COOKIEFILE, './cookie_test.txt') p.setopt(pycurl.COOKIEJAR, './cookie_test.txt') p.setopt(pycurl.POST, 1) p.setopt(pycurl.POSTFIELDS, fields) p.setopt(pycurl.WRITEFUNCTION, pageContents.write) p.setopt(pycurl.URL, 'http://localhost') p.perform() pageContents.seek(0) print pageContents.readlines()

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  • PIL saves image colour wrong

    - by Tom Viner
    I have an image. I want to resize it using PIL, but it come out like this. Even without a resize it still messes up the colour. Minimal code: from PIL import Image import os import urllib import webbrowser orig_url = 'http://mercedesclub.org.uk/images/stackoverflow-question/least-popular-colours-_-500-x-500.jpg' temp_fn, _ = urllib.urlretrieve(orig_url) im = Image.open(temp_fn) fn = os.tempnam() + '.jpg' im.save(fn) webbrowser.open(fn) I've tried Image.open(temp_fn).convert(format) with 'RGB', 'CMYK' and 'L' as formats, but still get weirdly coloured or grey results. When I load the image from my hard drive and I can see: >>>im.info {'adobe': 100, 'progression': 1, 'exif': 'Exif\x00\x00MM\x00*...\x7f\xff\xd9', 'adobe_transform': 100} >>>im.format 'JPEG' >>>im.mode 'CMYK' >>> im._getexif() {40961: 65535, 40962: 500, 40963: 500, 296: 2, 34665: 164, 274: 1, 305: 'Adobe Photoshop CS Macintosh', 306: '2010:02:26 12:46:54', 282: (300, 1), 283: (300, 1)} Thanks and let me know if you need any more data.

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  • gae error when i login.

    - by zjm1126
    i am using http://code.google.com/p/gaema/source/browse/#hg/demos/webapp, and this is my traceback: Traceback (most recent call last): File "D:\Program Files\Google\google_appengine\google\appengine\ext\webapp\__init__.py", line 510, in __call__ handler.get(*groups) File "D:\gaema\demos\webapp\main.py", line 31, in get google_auth.get_authenticated_user(self._on_auth) File "D:\gaema\demos\webapp\gaema\auth.py", line 641, in get_authenticated_user OpenIdMixin.get_authenticated_user(self, callback) File "D:\gaema\demos\webapp\gaema\auth.py", line 83, in get_authenticated_user url = self._OPENID_ENDPOINT + "?" + urllib.urlencode(args) File "D:\Python25\lib\urllib.py", line 1250, in urlencode v = quote_plus(str(v)) UnicodeEncodeError: 'ascii' codec can't encode characters in position 0-1: ordinal not in range(128) how to do this thanks ??????????????? ???????? ??????????? ?????????????? ???????

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  • Parsing JSON file with Python -> google map api

    - by Hannes
    Hi all, I am trying to get started with JSON in Python, but it seems that I misunderstand something in the JSON concept. I followed the google api example, which works fine. But when I change the code to a lower level in the JSON response (as shown below, where I try to get access to the location), I get the following error message for code below: Traceback (most recent call last): File "geoCode.py", line 11, in test = json.dumps([s['location'] for s in jsonResponse['results']], indent=3) KeyError: 'location' How can I get access to lower information level in the JSON file in python? Do I have to go to a higher level and search the result string? That seems very weird to me? Here is the code I have tried to run: import urllib, json URL2 = "http://maps.googleapis.com/maps/api/geocode/json?address=1600+Amphitheatre+Parkway,+Mountain+View,+CA&sensor=false" googleResponse = urllib.urlopen(URL2); jsonResponse = json.loads(googleResponse.read()) test = json.dumps([s['location'] for s in jsonResponse['results']], indent=3) print test Thank you for your responses.

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  • Play Shoutcast MP3 radio stream with Python?

    - by Zachary Brown
    I have managed to create an online radio station using Shoutcast and Sam Broadcaster. Now, I am wanting to build my own player for that radio station. I am not sure where to begin, I have googled, but no luck. I am using Python 2.6 on Microsoft Windows. I have managed to capture the stream and save it as an MP# on the hard disk, just not sure what to do with it next. I tried playback of the file, but it always pulls up errors. This is the code I have so far: import urllib target = open("broadcast.mp3") conn = urllib.urlopen("http://78.159.104.175:80") while True: target.write(con.read(5200)) Any help would be greatly appreciated!

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  • float change from python 3.0.1 to 3.1.2

    - by Jeremy
    Im trying to learn python. I am using 3.1.2 and the o'reilly book is using 3.0.1 here is my code import urllib.request price = (99.99) while price 4.74: page = urllib.request.urlopen ("http://www.beans-r-us.biz/prices-loyalty.html") text = page.read().decode("utf8") where = text.find('>$') start_of_price = where + 2 end_of_price = start_of_price + 6 price = float(text[start_of_price:end_of_price]) print ("Buy!") - here is my error Traceback (most recent call last): File "/Users/odin/Desktop/Coffe.py", line 14, in price = float(text[start_of_price:end_of_price]) ValueError: invalid literal for float(): 4.59 what is wrong? please help!!

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  • Url open encoding

    - by badc0re
    I have the following code for urllib and BeautifulSoup: getSite = urllib.urlopen(pageName) # open current site getSitesoup = BeautifulSoup(getSite.read()) # reading the site content print getSitesoup.originalEncoding for value in getSitesoup.find_all('link'): # extract all <a> tags defLinks.append(value.get('href')) The result of it: /usr/lib/python2.6/site-packages/bs4/dammit.py:231: UnicodeWarning: Some characters could not be decoded, and were replaced with REPLACEMENT CHARACTER. "Some characters could not be decoded, and were " And when i try to read the site i get: ?7?e????0*"I??G?H????F??????9-??????;??E?YÞBs????????????4i???)?????^W?????`w?Ke??%??*9?.'OQB???V??@?????]???(P??^??q?$?S5???tT*?Z

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  • How to login with python and save cookie, then use that info to view page for member only

    - by patcsong
    I am quite new in python and trying to write a script to login to the page at http://ryushare.com/login.python. I have try many attempt, but it fails to login and i have no idea why. After login to the page, I wish to get the return of http://ryushare.com/file-manager.python Here's the code I try to attempt by reading the example from others. import urllib, urllib2, cookielib username = 'myusername' password = 'mypassword' cj = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(cj)) login_data = urllib.urlencode({'login' : username, 'password' : password}) opener.open('http://www.ryushare.com/login.python', login_data) resp = opener.open('http://ryushare.com/file-manager.python') print resp.read() I check the source code of the login page, it said the username and password value is "login and password" so i change it. I have try some other example which can be found here like google news feed, It also can not able to login : (

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  • Télécharger un fichier du Web avec PyQt4 et QThread, un article de Jean-Paul Vidal

    Bonjour, Je vous informe d'un nouveau tuto sur developpez : comment télécharger un fichier sur le Web avec PyQt4. Le code utilise QThread (le thread de Qt4) et, pour le téléchargement, le module urllib. Il permet de montrer comment les threads peuvent communiquer par messages avec l'interface graphique afin de mettre à jour une barre de progression du téléchargement. Il a été développé suite au fil de discussion http://www.developpez.net/forums/d10...s-urlretrieve/. Tyrtamos...

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  • ImportError: No module named _socket? WSGI Deployment into Apache

    - by Sxkaur
    I am using WSGI 3.3 for python 2.7.3 (32bit) for Apache 2.2. I got the binary WSGI from http://code.google.com/p/modwsgi/downloads/detail?name=mod_wsgi-win32-ap22py27-3.3.so. I have been trying to deploy an application but keep on receiving the ImportError: no module named _socket. I have included my wsgi and error logs. APACHE config: #LoadModule vhost_alias_module modules/mod_vhost_alias.so LoadModule wsgi_module modules/mod_wsgi.so <Directory C:/Users/xxxxd/Documents/cahd> AllowOverride None Options None Order deny,allow Allow from all </Directory> WSGIScriptAlias / C:/Users/xxxxd/Documents/cahd/cahd/django.wsgi import os, sys sys.path.append('C:/Users/xxxxd/Documents) sys.path.append('C:/Users/xxxxd/Documents/cahd/') os.environ['DJANGO_SETTINGS_MODULE'] = 'cahd.settings' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() The error was: [Mon Nov 19 09:44:17 2012] [error] [client 127.0.0.1] Traceback (most recent call last): [Mon Nov 19 09:44:17 2012] [error] [client 127.0.0.1 ]File "C:/Users/xxxxd/Documents/cahd/django.wsgi", line 10, in <module> [Mon Nov 19 09:44:17 2012] [error] [client 127.0.0.1] import django.core.handlers.wsgi [Mon Nov 19 09:44:17 2012] [error] [client 127.0.0.1] File "C:\\django\\Django-1.4.1\\django\\core\\handlers\\wsgi.py", line 8, in <module> [Mon Nov 19 09:44:17 2012] [error] [client 127.0.0.1] from django import http [Mon Nov 19 09:44:17 2012] [error] [client 127.0.0.1] File "C:\\django\\Django-1.4.1\\django\\http\\__init__.py", line 11, in <module> [Mon Nov 19 09:44:17 2012] [error] [client 127.0.0.1] from urllib import urlencode, quote [Mon Nov 19 09:44:17 2012] [error] [client 127.0.0.1] File "C:\\Python27\\Lib\\urllib.py", line 26, in <module> [Mon Nov 19 09:44:17 2012] [error] [client 127.0.0.1] import socket [Mon Nov 19 09:44:17 2012] [error] [client 127.0.0.1] File "C:\\Python27\\Lib\\socket.py", line 47, in <module> [Mon Nov 19 09:44:17 2012] [error] [client 127.0.0.1] import _socket [Mon Nov 19 09:44:17 2012] [error] [client 127.0.0.1] ImportError: No module named _socket

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  • python mechanize.browser submit() related problem

    - by paul
    Hello All im making some script with mechanize.browser module. one of problem is all other thing is ok, but when submit() form,it not working, so i was found some suspicion source part. in the html source i was found such like following. <form method="post" onsubmit="return loginCheck(this)" name="FRMLOGIN"/> im thinking, loginCheck(this) making problem when submit form. but how to handle this kind of javascript function with mechanize module ,so i can successfully submit form and can receive result? folloing is my current script source. if anyone can help me ..much appreciate!! # -*- coding: cp949-*- import sys,os import mechanize, urllib import cookielib from BeautifulSoup import BeautifulSoup,BeautifulStoneSoup,Tag import datetime, time, socket import re,sys,os,mechanize,urllib,time br = mechanize.Browser() cj = cookielib.LWPCookieJar() br.set_cookiejar(cj) # Browser options br.set_handle_equiv(True) br.set_handle_gzip(True) br.set_handle_redirect(True) br.set_handle_referer(True) br.set_handle_robots(False) # Follows refresh 0 but not hangs on refresh > 0 br.set_handle_refresh(mechanize._http.HTTPRefreshProcessor(), max_time=1) # Want debugging messages? br.set_debug_http(True) br.set_debug_redirects(True) br.set_debug_responses(True) # User-Agent (this is cheating, ok?) br.addheaders = [('User-agent', 'Mozilla/5.0 (Windows; U; Windows NT 6.0; en-US; rv:1.9.0.6')] br.open('http://user.buddybuddy.co.kr/Login/LoginForm.asp?URL=') html = br.response().read() print html br.select_form(name='FRMLOGIN') print br.viewing_html() br.form['ID']='zero1zero2' br.form['PWD']='012045' br.submit() print br.response().read()

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  • File Uploading In Google Application Engine Using Django

    - by Ayush
    I am using gae with django. I have an project named MusicSite with following url mapping- urls.py from django.conf.urls.defaults import * from MusicSite.views import MainHandler from MusicSite.views import UploadHandler from MusicSite.views import ServeHandler urlpatterns = patterns('',(r'^start/', MainHandler), (r'^upload/', UploadHandler), (r'^/serve/([^/]+)?', ServeHandler), ) There is an application MusicSite inside MusicFun with the following codes- views.py import os import urllib from google.appengine.ext import blobstore from google.appengine.ext import webapp from google.appengine.ext.webapp import blobstore_handlers from google.appengine.ext.webapp import template from google.appengine.ext.webapp.util import run_wsgi_app def MainHandler(request): response=HttpResponse() upload_url = blobstore.create_upload_url('http://localhost: 8000/upload/') response.write('') response.write('' % upload_url) response.write("""Upload File: """) return HttpResponse(response) def UploadHandler(request): upload_files=request.FILES['file'] blob_info = upload_files[0] response.redirect('http://localhost:8000/serve/%s' % blob_info.key()) class ServeHandler(blobstore_handlers.BlobstoreDownloadHandler): def get(self, resource): resource = str(urllib.unquote(resource)) blob_info = blobstore.BlobInfo.get(resource) self.send_blob(blob_info) now whenever a upload a file using /start and click Submit i am taken to a blank page with the following url- localhost:8000/_ah/upload/ahhnb29nbGUtYXBwLWVuZ2luZS1kamFuZ29yGwsSFV9fQmxvYlVwbG9hZFNlc3Npb25fXxgHDA These random alphabets keep varying but the result is same. A blank page after every upload. Somebody please help. The server responses are as below- INFO:root:"GET /start/ HTTP/1.1" 200 - INFO:root:"GET /favicon.ico HTTP/1.1" 404 - INFO:root:Internal redirection to http://localhost:8000/upload/ INFO:root:Upload handler returned 500 ERROR:root:Invalid upload handler response. Only 301, 302 and 303 statuses are permitted and it may not have a content body. INFO:root:"POST /_ah/upload/ ahhnb29nbGUtYXBwLWVuZ2luZS1kamFuZ29yGwsSFV9fQmxvYlVwbG9hZFNlc3Npb25fXxgCDA HTTP/1.1" 500 - INFO:root:"GET /favicon.ico HTTP/1.1" 404 -

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  • how python http request and response works

    - by Apache
    hi expert, i'm newbie for python, i use to learn using sample, i use python to scan wifi to get ssid, and now i want to send the data to the server, then i did as follow import httplib,urllib params = urllib.urlencode({"ssid":"guest"}) headers = {"Content-type":"application/x-www-form-urlencoded","Accept":"text/plain"} conn=httplib.HTTPConnection("http://223.56.124.58:8080/wireless") conn.request("POST","data",params,headers) response = conn.getresponse() print "Response" print response.status print "-----" print response.reason data = response.read() print data conn.close() but when execute the code i'm getting as follow root@dave-laptop:~# python http.py Traceback (most recent call last): File "http.py", line 9, in conn.request("POST","http://202.45.139.58:8080/ppod-web",params,headers) File "/usr/lib/python2.6/httplib.py", line 898, in request self._send_request(method, url, body, headers) File "/usr/lib/python2.6/httplib.py", line 935, in _send_request self.endheaders() File "/usr/lib/python2.6/httplib.py", line 892, in endheaders self._send_output() File "/usr/lib/python2.6/httplib.py", line 764, in _send_output self.send(msg) File "/usr/lib/python2.6/httplib.py", line 723, in send self.connect() File "/usr/lib/python2.6/httplib.py", line 704, in connect self.timeout) File "/usr/lib/python2.6/socket.py", line 500, in create_connection for res in getaddrinfo(host, port, 0, SOCK_STREAM): socket.gaierror: [Errno -2] Name or service not known can anyone help me the code should be like this when rum in the url http://223.56.124.58:8080/wireless?data={"wifi":{"ssid":"guest","rssi","80"}} how to set like this or other way to do this to send to the server thanks

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  • youtube python api gdata.service. requesterror

    - by nashr rafeeg
    i have the following code which is trying to add a set of videos into a youtube play list import urllib,re import gdata.youtube import gdata.youtube.service class reddit(): def __init__(self, rssurl ='http://www.reddit.com/r/chillmusic.rss' ): self.URL = rssurl self._downloadrss() def _downloadrss(self): if self.URL.endswith('.rss'): # Downloadd the RSS feed of the subreddit - save as "feed.rss" try: print "Downloading rss from reddit..." urllib.urlretrieve (URL, "feed.rss") except Exception as e: print e def clean(self): playList = open("feed.rss").read() links = re.findall(r'(http?://www.youtube.com\S+)', playList) for link in links: firstPass = link.replace('&quot;&gt;[link]&lt;/a&gt;', '') secondPass = firstPass.replace('&amp;amp;fmt=18', '') thirdpass = secondPass.replace('&amp;amp;feature=related', '') finalPass = thirdpass.replace('http://www.youtube.com/watch?v=', '') print thirdpass, "\t Extracted: ", finalPass return finalPass class google(): def __init__(self, username, password): self.Username = username self.password = password #do not change any of the following self.key = 'AI39si5DDjGYhG_1W-8n_amjgEjbOU27sa0aw2RQI5gOaoK5KqCD2Fzffbkh8oqGu7CqFQLLQ7N7wK0gz7lrTQbd70srC72Niw' self.appname = 'Reddit playlist maker' self.service = gdata.youtube.service.YouTubeService() def authenticate(self): self.service.email = self.Username self.service.password = self.password self.service.developer_key = self.key self.service.client_id = self.appname self.service.source = self.appname self.service.ssl = False self.service.ProgrammaticLogin() def get_playlists(self): y_playlist = self.service.GetYouTubePlaylistFeed(username='default') l = [] k = [] for p in y_playlist.entry: k=[] k=[p.link[1].href, p.title.text] l.append(k) return l def get_playlist_id_from_url(self, href): #quick and dirty method to get the playList id's return href.replace('http://www.youtube.com/view_play_list?p=','') def creat_playlist(self, name="Reddit list", disc ="videos from reddit"): playlistentry = self.service.AddPlaylist(name, disc) if isinstance(playlistentry, gdata.youtube.YouTubePlaylistEntry): print 'New playlist added' return playlistentry.link[1].href def add_video_to_playlist(self,playlist_uri,video): video_entry = self.service.AddPlaylistVideoEntryToPlaylist( playlist_uri, video) if isinstance(video_entry, gdata.youtube.YouTubePlaylistVideoEntry): print 'Video added' URL = "http://www.reddit.com/r/chillmusic.rss" r = reddit(URL) g = google('[email protected]', 'xxxx') g.authenticate() def search_playlist(playlist="Reddit list3"): pl_id = None for pl in g.get_playlists(): if pl[1] == playlist: pl_id = pl[0] print pl_id break if pl_id == None: pl_id = g.creat_playlist(name=playlist) return pl_id pls = search_playlist() for video_id in r.clean(): g.add_video_to_playlist(pls, video_id) when i run the code i am geting the following error message gdata.service.RequestError: {'status': 303, 'body': '', 'reason': 'See Other'} any one have any idea why i am getting this error cheers Nash

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  • What is the proper way to URL encode Unicode characters?

    - by Josh Gibson
    I know of the non-standard %uxxxx scheme but that doesn't seem like a wise choice since the scheme has been rejected by the W3C. Some interesting examples: The heart character. If I type this into my browser: http://www.google.com/search?q=? Then copy and paste it, I see this URL http://www.google.com/search?q=%E2%99%A5 which makes it seem like Firefox (or Safari) is doing this. urllib.quote_plus(x.encode("latin-1")) '%E2%99%A5' which makes sense, except for things that can't be encoded in Latin-1, like the triple dot character. … If I type the URL http://www.google.com/search?q=… into my browser then copy and paste, I get http://www.google.com/search?q=%E2%80%A6 back. Which seems to be the result of doing urllib.quote_plus(x.encode("utf-8")) which makes sense since … can't be encoded with Latin-1. But then its not clear to me how the browser knows whether to decode with UTF-8 or Latin-1. Since this seems to be ambiguous: In [67]: u"…".encode('utf-8').decode('latin-1') Out[67]: u'\xc3\xa2\xc2\x80\xc2\xa6' works, so I don't know how the browser figures out whether to decode that with UTF-8 or Latin-1. What's the right thing to be doing with the special characters I need to deal with?

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  • Python - Open default mail client using mailto, with multiple recipients

    - by victorhooi
    Hi, I'm attempting to write a Python function to send an email to a list of users, using the default installed mail client. I want to open the email client, and give the user the opportunity to edit the list of users or the email body. I did some searching, and according to here: http://www.sightspecific.com/~mosh/WWW_FAQ/multrec.html It's apparently against the RFC spec to put multiple comma-delimited recipients in a mailto link. However, that's the way everybody else seems to be doing it. What exactly is the modern stance on this? Anyhow, I found the following two sites: http://2ality.blogspot.com/2009/02/generate-emails-with-mailto-urls-and.html http://www.megasolutions.net/python/invoke-users-standard-mail-client-64348.aspx which seem to suggest solutions using urllib.parse (url.parse.quote for me), and webbrowser.open. I tried the sample code from the first link (2ality.blogspot.com), and that worked fine, and opened my default mail client. However, when I try to use the code in my own module, it seems to open up my default browser, for some weird reason. No funny text in the address bar, it just opens up the browser. The email_incorrect_phone_numbers() function is in the Employees class, which contains a dictionary (employee_dict) of Employee objects, which themselves have a number of employee attributes (sn, givenName, mail etc.). Full code is actually here (http://stackoverflow.com/questions/2963975/python-converting-csv-to-objects-code-design) from urllib.parse import quote import webbrowser .... def email_incorrect_phone_numbers(self): email_list = [] for employee in self.employee_dict.values(): if not PhoneNumberFormats.standard_format.search(employee.telephoneNumber): print(employee.telephoneNumber, employee.sn, employee.givenName, employee.mail) email_list.append(employee.mail) recipients = ', '.join(email_list) webbrowser.open("mailto:%s?subject=%s&body=%s" % (recipients, quote("testing"), quote('testing')) ) Any suggestions? Cheers, Victor

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  • Python 4 step setup with progressBars

    - by Samuel Taylor
    I'm having a problem with the code below. When I run it the progress bar will pulse for around 10 secs as meant to and then move on to downloading and will show the progress but when finished it will not move on to the next step it just locks up. import sys import time import pygtk import gtk import gobject import threading import urllib import urlparse class WorkerThread(threading.Thread): def __init__ (self, function, parent, arg = None): threading.Thread.__init__(self) self.function = function self.parent = parent self.arg = arg self.parent.still_working = True def run(self): # when does "run" get executed? self.parent.still_working = True if self.arg == None: self.function() else: self.function(self.arg) self.parent.still_working = False def stop(self): self = None class MainWindow: def __init__(self): gtk.gdk.threads_init() self.wTree = gtk.Builder() self.wTree.add_from_file("gui.glade") self.mainWindows() def mainWindows(self): self.mainWindow = self.wTree.get_object("frmMain") dic = { "on_btnNext_clicked" : self.mainWindowNext, } self.wTree.connect_signals(dic) self.mainWindow.show() self.installerStep = 0 # 0 = none, 1 = preinstall, 2 = download, 3 = install info, 4 = install #gtk.main() self.mainWindowNext() def pulse(self): self.wTree.get_object("progress").pulse() if self.still_working == False: self.mainWindowNext() return self.still_working def preinstallStep(self): self.wTree.get_object("progress").set_fraction(0) self.wTree.get_object("btnNext").set_sensitive(0) self.wTree.get_object("notebook1").set_current_page(0) self.installerStep = 1 WT = WorkerThread(self.heavyWork, self) #Would do a heavy function here like setup some thing WT.start() gobject.timeout_add(75, self.pulse) def downloadStep(self): self.wTree.get_object("progress").set_fraction(0) self.wTree.get_object("btnNext").set_sensitive(0) self.wTree.get_object("notebook1").set_current_page(0) self.installerStep = 2 urllib.urlretrieve('http://mozilla.mirrors.evolva.ro//firefox/releases/3.6.3/win32/en-US/Firefox%20Setup%203.6.3.exe', '/tmp/firefox.exe', self.updateHook) self.mainWindowNext() def updateHook(self, blocks, blockSize, totalSize): percentage = float ( blocks * blockSize ) / totalSize if percentage > 1: percentage = 1 self.wTree.get_object("progress").set_fraction(percentage) while gtk.events_pending(): gtk.main_iteration() def installInfoStep(self): self.wTree.get_object("btnNext").set_sensitive(1) self.wTree.get_object("notebook1").set_current_page(1) self.installerStep = 3 def installStep(self): self.wTree.get_object("progress").set_fraction(0) self.wTree.get_object("btnNext").set_sensitive(0) self.wTree.get_object("notebook1").set_current_page(0) self.installerStep = 4 WT = WorkerThread(self.heavyWork, self) #Would do a heavy function here like setup some thing WT.start() gobject.timeout_add(75, self.pulse) def mainWindowNext(self, widget = None): if self.installerStep == 0: self.preinstallStep() elif self.installerStep == 1: self.downloadStep() elif self.installerStep == 2: self.installInfoStep() elif self.installerStep == 3: self.installStep() elif self.installerStep == 4: sys.exit(0) def heavyWork(self): time.sleep(10) if __name__ == '__main__': MainWindow() gtk.main()

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  • urllib2.Request() with data returns empty url

    - by Mr. Polywhirl
    My main concern is the function: getUrlAndHtml() If I manually build and append the query to the end of the uri, I can get the response.url(), but if I pass a dictionary as the request data, the url does not come back. Is there anyway to guarantee the redirected url? In my example below, if thisWorks = True I get back a url, but the returned url is the request url as opposed to a redirect link. On a sidenote, the encoding for .E2.80.93 does not translate to - for some reason? #!/usr/bin/python import pprint import urllib import urllib2 from bs4 import BeautifulSoup from sys import argv URL = 'http://en.wikipedia.org/w/index.php?' def yesOrNo(boolVal): return 'yes' if boolVal else 'no' def getTitleFromRaw(page): return page.strip().replace(' ', '_') def getUrlAndHtml(title, printable=False): thisWorks = False if thisWorks: query = 'title={:s}&printable={:s}'.format(title, yesOrNo(printable)) opener = urllib2.build_opener() opener.addheaders = [('User-agent', 'Mozilla/5.0')] response = opener.open(URL + query) else: params = {'title':title,'printable':yesOrNo(printable)} data = urllib.urlencode(params) headers = {'User-agent':'Mozilla/5.0'}; request = urllib2.Request(URL, data, headers) response = urllib2.urlopen(request) return response.geturl(), response.read() def getSoup(html, name=None, attrs=None): soup = BeautifulSoup(html) if name is None: return None return soup.find(name, attrs) def setTitle(soup, newTitle): title = soup.find('div', {'id':'toctitle'}) h2 = title.find('h2') h2.contents[0].replaceWith('{:s} for {:s}'.format(h2.getText(), newTitle)) def updateLinks(soup, url): fragment = '#' for a in soup.findAll('a', href=True): a['href'] = a['href'].replace(fragment, url + fragment) def writeToFile(soup, filename='out.html', indentLevel=2): with open(filename, 'wt') as out: pp = pprint.PrettyPrinter(indent=indentLevel, stream=out) pp.pprint(soup) print('Wrote {:s} successfully.'.format(filename)) if __name__ == '__main__': def exitPgrm(): print('usage: {:s} "<PAGE>" <FILE>'.format(argv[0])) exit(0) if len(argv) == 2: help = argv[1] if help == '-h' or help == '--help': exitPgrm() if False:''' if not len(argv) == 3: exitPgrm() ''' page = 'Led Zeppelin' # argv[1] filename = 'test.html' # argv[2] title = getTitleFromRaw(page) url, html = getUrlAndHtml(title) soup = getSoup(html, 'div', {'id':'toc'}) setTitle(soup, page) updateLinks(soup, url) writeToFile(soup, filename)

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