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  • Add kilometers to a map point

    - by proveyourselfthom
    Good morning. I would like to know how do I add kilometers to a map point (latitude / longitude). For example: The city Jaraguá do Sul is in latitude -26.462049, longitude -49.059448. I want to add 100 kilometers up, down, and on the sides. I want to do a square and get the new points. How do I do that? I tried it: <?php $distance = 100; $earthRadius = 6371; $lat1 = -26.4853239150483; $lon1 = -49.075927734375; $bearing = 0; $lat2 = asin(sin($lat1) * cos($distance / $earthRadius) + cos($lat1) * sin($distance / $earthRadius) * cos($bearing)); $lon2 = $lon1 + atan2(sin($bearing) * sin($distance / $earthRadius) * cos($lat1), cos($distance / $earthRadius) - sin($lat1) * sin($lat2)); echo 'LAT: ' . $lat2 . '<br >'; echo 'LNG: ' . $lon2; ?> But it's returning wrong cordinates. Thank you! Thank you very much.

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  • Give the mount point of a path

    - by Charles Stewart
    The following, very non-robust shell code will give the mount point of $path: (for i in $(df|cut -c 63-99); do case $path in $i*) echo $i;; esac; done) | tail -n 1 Is there a better way to do this? Postscript This script is really awful, but has the redeeming quality that it Works On My Systems. Note that several mount points may be prefixes of $path. Examples On a Linux system: cas@txtproof:~$ path=/sys/block/hda1 cas@txtproof:~$ for i in $(df -a|cut -c 57-99); do case $path in $i*) echo $i;; esac; done| tail -1 /sys On a Mac osx system cas local$ path=/dev/fd/0 cas local$ for i in $(df -a|cut -c 63-99); do case $path in $i*) echo $i;; esac; done| tail -1 /dev Note the need to vary cut's parameters, because of the way df's output differs: indeed, awk is better. Answer It looks like munging tabular output is the only way within the shell, but df /dev/fd/impossible | tail -1 | awk '{ print $NF}' is a big improvement on what I had. Note two differences in semantics: firstly, df $path insists that $path names an existing file, the script I had above doesn't care; secondly, there are no worries about dereferncing symlinks. It's not difficult to write Python code to do the job.

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  • Any one point me how to customize facebook share

    - by Venkat
    I am trying to share my own custom url, image, title and description using Facebook and twitter. I am having lot of images and videos in my website. So i want to make my content viral on social websites. I am trying to keep share options for both facebook and twitter for everything individually. If some one share one image i want that image in the sharing thumbnail and url will be the page url with my own title, description. Based on the url i will point the user to that pic in my website. I tried in the below way. Facebook share: <a href="javascript:;" onclick="window.open('http://www.facebook.com/share.php?u=your_page_url','facebook share','resizable=yes,width=700,height=500,scrollbars=yes,status=yes')"><img alt="facebook" src="yourimage.jpg" /></a> Twitter share: <a href="javascript:;" onclick="window.open('https://twitter.com/share','twitter share','resizable=yes,width=700,height=500,scrollbars=yes,status=yes')"><img alt="twitter" src="yourimage.jpg" /></a>

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  • c++ floating point precision loss: 3015/0.00025298219406977296

    - by SigTerm
    The problem. Microsoft Visual C++ 2005 compiler, 32bit windows xp sp3, amd 64 x2 cpu. Code: double a = 3015.0; double b = 0.00025298219406977296; //*((unsigned __int64*)(&a)) == 0x40a78e0000000000 //*((unsigned __int64*)(&b)) == 0x3f30945640000000 double f = a/b;//3015/0.00025298219406977296; the result of calculation (i.e. "f") is 11917835.000000000 (*((unsigned __int64*)(&f)) == 0x4166bb4160000000) although it should be 11917834.814763514 (i.e. *((unsigned __int64*)(&f)) == 0x4166bb415a128aef). I.e. fractional part is lost. Unfortunately, I need fractional part to be correct. Questions: 1) Why does this happen? 2) How can I fix the problem? Additional info: 0) The result is taken directly from "watch" window (it wasn't printed, and I didn't forget to set printing precision). I also provided hex dump of floating point variable, so I'm absolutely sure about calculation result. 1) The disassembly of f = a/b is: fld qword ptr [a] fdiv qword ptr [b] fstp qword ptr [f] 2) f = 3015/0.00025298219406977296; yields correct result (f == 11917834.814763514 , *((unsigned __int64*)(&f)) == 0x4166bb415a128aef ), but it looks like in this case result is simply calculated during compile-time: fld qword ptr [__real@4166bb415a128aef (828EA0h)] fstp qword ptr [f] So, how can I fix this problem? P.S. I've found a temporary workaround (i need only fractional part of division, so I simply use f = fmod(a/b)/b at the moment), but I still would like to know how to fix this problem properly - double precision is supposed to be 16 decimal digits, so such calculation isn't supposed to cause problems.

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  • Time taken for memcpy decreases after certain point

    - by tss
    I ve a code which increases the size of the memory(identified by a pointer) exponentially. Instead of realloc, I use malloc followed by memcpy.. Something like this.. int size=5,newsize; int *c = malloc(size*sizeof(int)); int *temp; while(1) { newsize=2*size; //begin time temp=malloc(newsize*sizeof(int)); memcpy(temp,c,size*sizeof(int)); //end time //print time in mili seconds c=temp; size=newsize; } Thus the number of bytes getting copied is increasing exponentially. The time required for this task also increases almost linearly with the increase in size. However after certain point, the time taken abruptly reduces to a very small value and then remains constant. I recorded time for similar code, copyin data(Of my own type) 5 -> 10 - 2 ms 10 -> 20 - 2 ms . . 2560 -> 5120 - 5 ms . . 20480 -> 40960 - 30 ms 40960 -> 91920 - 58 ms 367680 -> 735360 - 2 ms 735360 -> 1470720 - 2 ms 1470720 -> 2941440 - 2 ms What is the reason for this drop in time ? Does a more optimal memcpy method get called when the size is large ?

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  • How to start matching and saving matched from exact point in a text

    - by yuliya
    I have a text and I write a parser for it using regular expressions and perl. I can match what I need with two empty lines (I use regexp), because there is a pattern that allows recognize blocks of text after two empty lines. But the problem is that the whole text has Introduction part and some text in the end I do not need. Here is a code which matches text when it finds two empty lines #!/usr/bin/perl use strict; use warnings; my $file = 'first'; open(my $fh, '<', $file); my $empty = 0; my $block_num = 1; open(OUT, '>', $block_num . '.txt'); while (my $line = <$fh>) { chomp ($line); if ($line =~ /^\s*$/) { $empty++; } elsif ($empty == 2) { close(OUT); open(OUT, '>', ++$block_num . '.txt'); $empty = 0; } else { $empty = 0;} print OUT "$line\n"; } close(OUT); This is example of the text I need (it's really small :)) this is file example I think that I need to iterate over the text till the moment it will find the word LOREM IPSUM with regexps this kind "/^LOREM IPSUM/", because it is the point from which needed text starts(and save the text in one file when i reach the word). And I need to finish iterating over the text when INDEX word is fount or save the text in separate file. How could I implement it. Should I use next function to proceed with lines or what? BR, Yuliya

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  • Android designing an app to keep me logged into a wifi access point

    - by MrGibbage
    At the gym where I work out, they have an open wifi access point. The way it is set up, once you "connect", you have to navigate to a web page (it is a 1.1.X.X ip address) and click the "I agree" button, after presumably reading the user agreement. The problem is, they have it set up to log you out once an hour, which always happens in the middle of my workout. I have the SSID remembered, so it connects automatically when I come in range, but I get an android notification that further action is needed to fully connect. What I was wondering is if there a work around so that I don't have to click-through every hour? I was thinking of writing an app that could detect when I was in range, or when "half-connected", and then have it somehow complete the registration process. Perhaps this will have to be done by loading the web page in memory and then somehow clicking the "I agree" button. What I would like help with is: 1) what is the terminology involved here? What state is the connection in when I am connected, but I haven't clicked through? What other connection states may apply? If I knew that, I might just be able to research this and come up with a solution. Are these different states "detectable"? It seems like it is since I get a notification that I need to complete the registration process when I am "half-connected". 2) I know there are plugins for desktop browsers that can click buttons (like the keepass plugins, which will log you into a site). How could I replicate this in Android? Ideally I would like to do it internally, in memory, rather than firing up a browser. Possible? Comments? Is my understanding and thought process sound here, or am I overlooking something?

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  • The sign of zero with float2

    - by JackOLantern
    Consider the following code performing operations on complex numbers with C/C++'s float: float real_part = log(3.f); float imag_part = 0.f; float real_part2 = (imag_part)*(imag_part)-(real_part*real_part); float imag_part2 = (imag_part)*(real_part)+(real_part*imag_part); The result will be real_part2= -1.20695 imag_part2= 0 angle= 3.14159 where angle is the phase of the complex number and, in this case, is pi. Now consider the following code: float real_part = log(3.f); float imag_part = 0.f; float real_part2 = (-imag_part)*(-imag_part)-(real_part)*(real_part); float imag_part2 = (-imag_part)*(real_part)+(real_part)*(-imag_part); The result will be real_part2= -1.20695 imag_part2= 0 angle= -3.14159 The imaginary part of the result is -0 which makes the phase of the result be -pi. Although still accomplishing with the principal argument of a complex number and with the signed property of floating point's 0, this changes is a problem when one is defining functions of complex numbers. For example, if one is defining sqrt of a complex number by the de Moivre formula, this will change the sign of the imaginary part of the result to a wrong value. How to deal with this effect?

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  • why Floating point exception?

    - by livio8495
    I have a floating point exception, and I don't know why. the code is this: void calcola_fitness(){ vector<double> fitness; int n=nodes.size(); int e=edges.size(); int dim=feasibility.size(); int feas=(feasibility[dim-1])*100; int narchi=numarchicoll[dim-1]/e; int numero_nodi=freePathNode.size()/n; double dist_start_goal=node_dist(0,1); int i,f,t; double pathlenght=0; int siize=freePathNode.size(); for(i=0;i!=siize-1; i++){ f=freePathNode[i].getIndex(); i++; t=freePathNode[i].getIndex(); i--; pathlenght=pathlenght+node_dist(f,t); } double pathlenghtnorm=pathlenght/10*dist_start_goal; double fit=((double)numero_nodi+pathlenghtnorm+(double)narchi)*((double)feas); fitness.push_back(fit); } Could anybody help me? What's the problem? I could I solve this? thank you very much

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  • Zoom in on a point (using scale and translate)

    - by csiz
    I want to be able to zoom in on the point under the mouse in canvas with the mouse whell, like when zooming on maps.google. I'd like straight code as I've been working on this for 5h+ Something to start with: <canvas id="canvas" width="800" height="600"></canvas> <script type="text/javascript"> var canvas = document.getElementById("canvas"); var context = canvas.getContext("2d"); var scale = 1; var originx = 0; var originy = 0; function draw(){ context.fillStyle = "white"; context.fillRect(originx,originy,800/scale,600/scale); context.fillStyle = "black"; context.fillRect(50,50,100,100); } setInterval(draw,100); canvas.onmousewheel = function (event){ var mousex = event.clientX - canvas.offsetLeft; var mousey = event.clientY - canvas.offsetTop; var wheel = event.wheelDelta/120;//n or -n var zoom = 1 + wheel/2; scale *= zoom; originx += 0;//??? originy += 0;//??? context.scale(zoom,zoom); context.translate(0,0);//??? } </script>

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  • iPhone Objective C - error: pointer value used where a floating point value was expected

    - by Mausimo
    I do not understand why i am getting this error. Here is the related code: Photo.h #import <CoreData/CoreData.h> @class Person; @interface Photo : NSManagedObject { } @property (nonatomic, retain) NSData * imageData; @property (nonatomic, retain) NSNumber * Latitude; @property (nonatomic, retain) NSString * ImageName; @property (nonatomic, retain) NSString * ImagePath; @property (nonatomic, retain) NSNumber * Longitude; @property (nonatomic, retain) Person * PhotoToPerson; @end Photo.m #import "Photo.h" #import "Person.h" @implementation Photo @dynamic imageData; @dynamic Latitude; @dynamic ImageName; @dynamic ImagePath; @dynamic Longitude; @dynamic PhotoToPerson; @end This is a mapViewController.m class i have created. If i run this, the CLLocationDegrees CLLat and CLLong lines: CLLocationDegrees CLLat = (CLLocationDegrees)photo.Latitude; CLLocationDegrees CLLong = (CLLocationDegrees)photo.Longitude; give me the error : pointer value used where a floating point value was expected. for(int i = 0; i < iPerson; i++) { //get the person that corresponds to the row indexPath that is currently being rendered and set the text Person * person = (Person *)[myArrayPerson objectAtIndex:i]; //get the photos associated with the person NSArray * PhotoArray = [person.PersonToPhoto allObjects]; int iPhoto = [PhotoArray count]; for(int j = 0; j < iPhoto; j++) { //get the first photo (all people will have atleast 1 photo, else they will not exist). Set the image Photo * photo = (Photo *)[PhotoArray objectAtIndex:j]; if(photo.Latitude != nil && photo.Longitude != nil) { MyAnnotation *ann = [[MyAnnotation alloc] init]; ann.title = photo.ImageName; ann.subtitle = photo.ImageName; CLLocationCoordinate2D cord; CLLocationDegrees CLLat = (CLLocationDegrees)photo.Latitude; CLLocationDegrees CLLong = (CLLocationDegrees)photo.Longitude; cord.latitude = CLLat; cord.longitude = CLLong; ann.coordinate = cord; [mkMapView addAnnotation:ann]; } } }

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  • point light illumination using Phong model

    - by Myx
    Hello: I wish to render a scene that contains one box and a point light source using the Phong illumination scheme. The following are the relevant code snippets for my calculation: R3Rgb Phong(R3Scene *scene, R3Ray *ray, R3Intersection *intersection) { R3Rgb radiance; if(intersection->hit == 0) { radiance = scene->background; return radiance; } ... // obtain ambient term ... // this is zero for my test // obtain emissive term ... // this is also zero for my test // for each light in the scene, obtain calculate the diffuse and specular terms R3Rgb intensity_diffuse(0,0,0,1); R3Rgb intensity_specular(0,0,0,1); for(unsigned int i = 0; i < scene->lights.size(); i++) { R3Light *light = scene->Light(i); R3Rgb light_color = LightIntensity(scene->Light(i), intersection->position); R3Vector light_vector = -LightDirection(scene->Light(i), intersection->position); // check if the light is "behind" the surface normal if(normal.Dot(light_vector)<=0) continue; // calculate diffuse reflection if(!Kd.IsBlack()) intensity_diffuse += Kd*normal.Dot(light_vector)*light_color; if(Ks.IsBlack()) continue; // calculate specular reflection ... // this I believe to be irrelevant for the particular test I'm doing } radiance = intensity_diffuse; return radiance; } R3Rgb LightIntensity(R3Light *light, R3Point position) { R3Rgb light_intensity; double distance; double denominator; if(light->type != R3_DIRECTIONAL_LIGHT) { distance = (position-light->position).Length(); denominator = light->constant_attenuation + (light->linear_attenuation*distance) + (light->quadratic_attenuation*distance*distance); } switch(light->type) { ... case R3_POINT_LIGHT: light_intensity = light->color/denominator; break; ... } return light_intensity; } R3Vector LightDirection(R3Light *light, R3Point position) { R3Vector light_direction; switch(light->type) { ... case R3_POINT_LIGHT: light_direction = position - light->position; break; ... } light_direction.Normalize(); return light_direction; } I believe that the error must be somewhere in either LightDirection(...) or LightIntensity(...) functions because when I run my code using a directional light source, I obtain the desired rendered image (thus this leads me to believe that the Phong illumination equation is correct). Also, in Phong(...), when I computed the intensity_diffuse and while debugging, I divided light_color by 10, I was obtaining a resulting image that looked more like what I need. Am I calculating the light_color correctly? Thanks.

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  • Counting point size based on chart area during zooming/unzoomin

    - by Gacek
    Hi folks. I heave a quite simple task. I know (I suppose) it should be easy, but from the reasons I cannot understand, I try to solve it since 2 days and I don't know where I'm making the mistake. So, the problem is as follows: - we have a chart with some points - The chart starts with some known area and points have known size - we would like to "emulate" the zooming effect. So when we zoom to some part of the chart, the size of points is getting proportionally bigger. In other words, the smaller part of the chart we select, the bigger the point should get. So, we have something like that. We know this two parameters: initialArea; // Initial area - area of the whole chart, counted as width*height initialSize; // initial size of the points Now lets assume we are handling some kind of OnZoom event. We selected some part of the chart and would like to count the current size of the points float CountSizeOnZoom() { float currentArea = CountArea(...); // the area is counted for us. float currentSize = initialSize * initialArea / currentArea; return currentSize; } And it works. But the rate of change is too fast. In other words, the points are getting really big too soon. So I would like the currentSize to be invertly proportional to currentArea, but with some scaling coefficient. So I created the second function: float CountSizeOnZoom() { float currentArea = CountArea(...); % the area is counted for us. // Lets assume we want the size of points to change ten times slower, than area of the chart changed. float currentSize = initialSize + 0.1f* initialSize * ((initialArea / currentArea) -1); return currentSize; } Lets do some calculations in mind. if currentArea is smaller than initialArea, initialArea/currentArea > 1 and then we add "something" small and postive to initialSize. Checked, it works. Lets check what happens if we would un-zoom. currentArea will be equal to initialArea, so we would have 0 at the right side (1-1), so new size should be equal to initialSize. Right? Yeah. So lets check it... and it doesn't work. My question is: where is the mistake? Or maybe you have any ideas how to count this scaled size depending on current area in some other way?

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  • How to manually (bitwise) perform (float)x? (homework)

    - by Silver
    Now, here is the function header of the function I'm supposed to implement: /* * float_from_int - Return bit-level equivalent of expression (float) x * Result is returned as unsigned int, but * it is to be interpreted as the bit-level representation of a * single-precision floating point values. * Legal ops: Any integer/unsigned operations incl. ||, &&. also if, while * Max ops: 30 * Rating: 4 */ unsigned float_from_int(int x) { ... } We aren't allowed to do float operations, or any kind of casting. Now I tried to implement the first algorithm given at this site: http://locklessinc.com/articles/i2f/ Here's my code: unsigned float_from_int(int x) { // grab sign bit int xIsNegative = 0; int absValOfX = x; if(x < 0){ xIsNegative = 1; absValOfX = -x; } // zero case if(x == 0){ return 0; } //int shiftsNeeded = 0; /*while(){ shiftsNeeded++; }*/ unsigned I2F_MAX_BITS = 15; unsigned I2F_MAX_INPUT = ((1 << I2F_MAX_BITS) - 1); unsigned I2F_SHIFT = (24 - I2F_MAX_BITS); unsigned result, i, exponent, fraction; if ((absValOfX & I2F_MAX_INPUT) == 0) result = 0; else { exponent = 126 + I2F_MAX_BITS; fraction = (absValOfX & I2F_MAX_INPUT) << I2F_SHIFT; i = 0; while(i < I2F_MAX_BITS) { if (fraction & 0x800000) break; else { fraction = fraction << 1; exponent = exponent - 1; } i++; } result = (xIsNegative << 31) | exponent << 23 | (fraction & 0x7fffff); } return result; } But it didn't work (see test error below): Test float_from_int(-2147483648[0x80000000]) failed... ...Gives 0[0x0]. Should be -822083584[0xcf000000] 4 4 0 float_times_four I don't know where to go from here. How should I go about parsing the float from this int?

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  • Round-twice error in .NET's Double.ToString method

    - by Jeppe Stig Nielsen
    Mathematically, consider for this question the rational number 8725724278030350 / 2**48 where ** in the denominator denotes exponentiation, i.e. the denominator is 2 to the 48th power. (The fraction is not in lowest terms, reducible by 2.) This number is exactly representable as a System.Double. Its decimal expansion is 31.0000000000000'49'73799150320701301097869873046875 (exact) where the apostrophes do not represent missing digits but merely mark the boudaries where rounding to 15 resp. 17 digits is to be performed. Note the following: If this number is rounded to 15 digits, the result will be 31 (followed by thirteen 0s) because the next digits (49...) begin with a 4 (meaning round down). But if the number is first rounded to 17 digits and then rounded to 15 digits, the result could be 31.0000000000001. This is because the first rounding rounds up by increasing the 49... digits to 50 (terminates) (next digits were 73...), and the second rounding might then round up again (when the midpoint-rounding rule says "round away from zero"). (There are many more numbers with the above characteristics, of course.) Now, it turns out that .NET's standard string representation of this number is "31.0000000000001". The question: Isn't this a bug? By standard string representation we mean the String produced by the parameterles Double.ToString() instance method which is of course identical to what is produced by ToString("G"). An interesting thing to note is that if you cast the above number to System.Decimal then you get a decimal that is 31 exactly! See this Stack Overflow question for a discussion of the surprising fact that casting a Double to Decimal involves first rounding to 15 digits. This means that casting to Decimal makes a correct round to 15 digits, whereas calling ToSting() makes an incorrect one. To sum up, we have a floating-point number that, when output to the user, is 31.0000000000001, but when converted to Decimal (where 29 digits are available), becomes 31 exactly. This is unfortunate. Here's some C# code for you to verify the problem: static void Main() { const double evil = 31.0000000000000497; string exactString = DoubleConverter.ToExactString(evil); // Jon Skeet, http://csharpindepth.com/Articles/General/FloatingPoint.aspx Console.WriteLine("Exact value (Jon Skeet): {0}", exactString); // writes 31.00000000000004973799150320701301097869873046875 Console.WriteLine("General format (G): {0}", evil); // writes 31.0000000000001 Console.WriteLine("Round-trip format (R): {0:R}", evil); // writes 31.00000000000005 Console.WriteLine(); Console.WriteLine("Binary repr.: {0}", String.Join(", ", BitConverter.GetBytes(evil).Select(b => "0x" + b.ToString("X2")))); Console.WriteLine(); decimal converted = (decimal)evil; Console.WriteLine("Decimal version: {0}", converted); // writes 31 decimal preciseDecimal = decimal.Parse(exactString, CultureInfo.InvariantCulture); Console.WriteLine("Better decimal: {0}", preciseDecimal); // writes 31.000000000000049737991503207 } The above code uses Skeet's ToExactString method. If you don't want to use his stuff (can be found through the URL), just delete the code lines above dependent on exactString. You can still see how the Double in question (evil) is rounded and cast.

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  • Anything wrong with this function for comparing floats?

    - by Michael Borgwardt
    When my Floating-Point Guide was yesterday published on slashdot, I got a lot of flak for my suggested comparison function, which was indeed inadequate. So I finally did the sensible thing and wrote a test suite to see whether I could get them all to pass. Here is my result so far. And I wonder if this is really as good as one can get with a generic (i.e. not application specific) float comparison function, or whether I still missed some edge cases. import static org.junit.Assert.assertFalse; import static org.junit.Assert.assertTrue; import org.junit.Test; public class NearlyEqualsTest { public static boolean nearlyEqual(float a, float b) { final float epsilon = 0.000001f; final float absA = Math.abs(a); final float absB = Math.abs(b); final float diff = Math.abs(a-b); if (a*b==0) { // a or b or both are zero // relative error is not meaningful here return diff < Float.MIN_VALUE / epsilon; } else { // use relative error return diff / (absA+absB) < epsilon; } } /** Regular large numbers - generally not problematic */ @Test public void big() { assertTrue(nearlyEqual(1000000f, 1000001f)); assertTrue(nearlyEqual(1000001f, 1000000f)); assertFalse(nearlyEqual(10000f, 10001f)); assertFalse(nearlyEqual(10001f, 10000f)); } /** Negative large numbers */ @Test public void bigNeg() { assertTrue(nearlyEqual(-1000000f, -1000001f)); assertTrue(nearlyEqual(-1000001f, -1000000f)); assertFalse(nearlyEqual(-10000f, -10001f)); assertFalse(nearlyEqual(-10001f, -10000f)); } /** Numbers around 1 */ @Test public void mid() { assertTrue(nearlyEqual(1.0000001f, 1.0000002f)); assertTrue(nearlyEqual(1.0000002f, 1.0000001f)); assertFalse(nearlyEqual(1.0002f, 1.0001f)); assertFalse(nearlyEqual(1.0001f, 1.0002f)); } /** Numbers around -1 */ @Test public void midNeg() { assertTrue(nearlyEqual(-1.000001f, -1.000002f)); assertTrue(nearlyEqual(-1.000002f, -1.000001f)); assertFalse(nearlyEqual(-1.0001f, -1.0002f)); assertFalse(nearlyEqual(-1.0002f, -1.0001f)); } /** Numbers between 1 and 0 */ @Test public void small() { assertTrue(nearlyEqual(0.000000001000001f, 0.000000001000002f)); assertTrue(nearlyEqual(0.000000001000002f, 0.000000001000001f)); assertFalse(nearlyEqual(0.000000000001002f, 0.000000000001001f)); assertFalse(nearlyEqual(0.000000000001001f, 0.000000000001002f)); } /** Numbers between -1 and 0 */ @Test public void smallNeg() { assertTrue(nearlyEqual(-0.000000001000001f, -0.000000001000002f)); assertTrue(nearlyEqual(-0.000000001000002f, -0.000000001000001f)); assertFalse(nearlyEqual(-0.000000000001002f, -0.000000000001001f)); assertFalse(nearlyEqual(-0.000000000001001f, -0.000000000001002f)); } /** Comparisons involving zero */ @Test public void zero() { assertTrue(nearlyEqual(0.0f, 0.0f)); assertFalse(nearlyEqual(0.00000001f, 0.0f)); assertFalse(nearlyEqual(0.0f, 0.00000001f)); } /** Comparisons of numbers on opposite sides of 0 */ @Test public void opposite() { assertFalse(nearlyEqual(1.000000001f, -1.0f)); assertFalse(nearlyEqual(-1.0f, 1.000000001f)); assertFalse(nearlyEqual(-1.000000001f, 1.0f)); assertFalse(nearlyEqual(1.0f, -1.000000001f)); assertTrue(nearlyEqual(10000f*Float.MIN_VALUE, -10000f*Float.MIN_VALUE)); } /** * The really tricky part - comparisons of numbers * very close to zero. */ @Test public void ulp() { assertTrue(nearlyEqual(Float.MIN_VALUE, -Float.MIN_VALUE)); assertTrue(nearlyEqual(-Float.MIN_VALUE, Float.MIN_VALUE)); assertTrue(nearlyEqual(Float.MIN_VALUE, 0)); assertTrue(nearlyEqual(0, Float.MIN_VALUE)); assertTrue(nearlyEqual(-Float.MIN_VALUE, 0)); assertTrue(nearlyEqual(0, -Float.MIN_VALUE)); assertFalse(nearlyEqual(0.000000001f, -Float.MIN_VALUE)); assertFalse(nearlyEqual(0.000000001f, Float.MIN_VALUE)); assertFalse(nearlyEqual(Float.MIN_VALUE, 0.000000001f)); assertFalse(nearlyEqual(-Float.MIN_VALUE, 0.000000001f)); assertFalse(nearlyEqual(1e20f*Float.MIN_VALUE, 0.0f)); assertFalse(nearlyEqual(0.0f, 1e20f*Float.MIN_VALUE)); assertFalse(nearlyEqual(1e20f*Float.MIN_VALUE, -1e20f*Float.MIN_VALUE)); } }

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  • not able to make entry of ubuntu 10.04 grub.cfg into redhat 5.1 menu.lst file to run 2 linux os and

    - by Deepak Narwal
    Hello friend... In my computer there are three operating systems.. First i installed Windows 7 then i installed ubuntu 10.04 and in last i installed redhat 5.1 NOw i know one thing as i installed redhat then grub installed by ubuntu will be overwritten by redhat grub..and i know that to see all three operating syetm at the startup i have to make entry of /boot/grub/cfg into /boot/grub/menu.lst file.. Now the problem is like this In te previous version it was very easy to play with ubuntu grub file but now this file is modified..NOw i dont know what is to be picked up from ubuntu /grub/grub.cfg file so that i can make entry in redhat /boot/grub/menu.lst file.. In short i am not able to put entry of grub.cfg file into redhat menu.lst file.. will u help me plz i want to work on these thre eOS..

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  • Task Management - How important it is for a entry level developer?

    - by Naveen Kumar
    I hold masters in CS & now I'm mobile apps developer (Entry Level) , I always start to plan things when starting or doing any project both at work & projects i do at Home (for passion) - as I can deliver the project on time but sometimes i m running out of time like 10 tasks a day vs my time forecast will take 2 on that day? As I'm beginner level, I want your suggestions on How important is Task Management for a person like me & for achieving my goals? My target for the next 3 year will be a Project Manager or Similiar Role - i belive which these time managing skills will be a needed quality.

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  • Des chercheurs en sécurité découvrent Dexter, un malware qui cible essentiellement les systèmes de point de vente

    Des chercheurs en sécurité découvrent Dexter un malware qui cible essentiellement les systèmes de point de vente Les pirates pour voler les données des cartes de crédit ont trouvé un moyen d'insérer un malware directement dans les systèmes de point de vente (POS). La firme de sécurité Seculert vient d'identifier un programme malveillant spécialement conçu pour attaquer les systèmes de point de vente. Le logiciel malveillant baptisé Dexter, aurait déjà infecté des systèmes POS dans près de 40 pays au cours des deux derniers mois. Les pays anglo-saxons semblent être les cibles favorites du malware, avec 30% d'attaque aux USA, 19% en Grande-Bretagne et 9% au Canada. L...

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  • Will grub overwrite EasyBCD entry if I already have Windows 7 and Windows XP installed?

    - by Sachin
    Installing Ubuntu on EEE PC which already has Windows 7 and Windows XP in dual boot using Easy BCD I have an ASUS EEE PC 1015PEM with Windows 7 starter and Windows XP in dual boot configuration on separate partitions. Now I want to replace my Windows XP with Ubuntu 11. Earlier after installing XP on my system it failed to boot in Windows 7, which I restored easily using EasyBCD. If I install Ubuntu 11 will I be able to boot my Windows 7 also? Will grub overwrite the EasyBCD entry for XP?

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  • How do I count Internal Logical Files (ILF) and External Inputs (EI) for a dynamic form entry page?

    - by DmytroL
    Assuming I have an applicant information entry screen, the number and types of fields on which can be defined by the system administrator, how do I go about counting the number of Internal Logical Files (ILFs) and Data Element Types (DETs) for the related data functions? So far I have come up with something like this: ILF #1 (control information): Field Metadata, 1 RET, ~3 DET (name, type, mandatory) ILF #2 (business data): Applicant Data, most likely 1 RET, but how many DET? Of course I could count it as 2 DET (Field ref, Value), but I am not sure that would be correct And when it comes to an External Input (EI), say, "Add New Applicant", things become even more complicated, because the number of DET corresponding to the user-editable fields is totally dependent on the control information in ILF #1, and I am out of ideas here... Anyone fancy to help with that? Thanks in advance!

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  • Good source for interview-style coding problems for entry/intermediate developers?

    - by soster
    I have taught myself to code over the past few years and do not have a computer science degree. As a result, I lack experience from many things, such as the basic homework/test questions many CS graduates take for granted. I recently had a tech screen interview where I fumbled and struggled to finish a (relatively) common question, I believe due to this inexperience. My question to all of you is this: do you know a good source for a bunch of these problems that includes answers, for an entry/intermediate developer who is trying to gain coding problem solving experience? The ones I've been able to find on the internet are for coding teams, so they're a bit too complicated for me. Thanks so much in advance.

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  • Epson OPOS ADK for .NET drivers for windows 7

    - by Xience
    Has anyone used Epson OPOS ADK for .NET for windows 7. i tried to install windows vista drivers on windows 7, since there are none available for windows 7, but it did not work. Please share any suggestions or ideas that might have worked for you. I am using a TM-88IV receipt printer

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  • MS cash drawer with epson TM-IV88 Status API

    - by Xience
    Does anyone know how to monitor cash drawer's open/close state using Advanced Printer Driver's Status API for Epson TM-88IV thermal printer. I wish i could use OPOS for ADK .Net, but haven't had luck setting it up on windows 7. Does anyone know how to be a part of epson developer network. I have gone through the information available at www.epson-pos.com but there is no information available on POS/ESC codes. Please help...........

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  • Read half precision float (float16 IEEE 754r) binary data in matlab

    - by Michael
    you have been a great help last time, i hope you can give me some advise this time, too. I read a binary file into matlab with bit16 (format = bitn) and i get a string of ones and zeros. bin = '1 00011 1111111111' (16 bits: 1. sign, 2-6. exponent, 7-16. mantissa) According to ftp://www.fox-toolkit.org/pub/fasthalffloatconversion.pdf it can be 'converted' like out = (-1)^bin(1) * 2^(bin(2:6)-15) * 1.bin(7:16) [are exponent and mantissa still binary?] Can someone help me out and tell me how to deal with the 'eeeee' and '1.mmmmmmmmmm' as mentioned in the pdf, please. Thanks a lot! Michael

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