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• Are hash values globally unqiue

  - by Wololo

  I want to generate a hash code for a file. Using C# I would do something like this then store the value in a database. byte[] b = File.ReadAllBytes(@"C:\image.jpg"); string hash = ComputeHash(b); Now, if i use say a Java program that implements the same hashing alogorithm (Md5), can i expect the hash values to be the equal to the value generated in C#? What if i execute the java program from different environments, Windows, Linux or Mac?

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• Forcing users to change password on first login - Windows Server 2008 R2 Remote Desktop Services

  - by George Durzi

  I'm setting up a demo lab environment in which each demo lab user is assigned 4 accounts to use in the lab. Users access the lab via Remote Desktop to the "client" machine in the lab - exposed at demolab.mydomain.com. The Client machine is a Windows 2008 Server R2 Enterprise Edition server The Remote Desktop Services role is configured on this server Remote Connection settings are configured to allow users to connect with any version of the Remote Desktop Client All accounts are members of the local Administrators and Remote Desktop Users groups All accounts are configured to be forced to change the default password after first login The user is instructed to remote into the lab with an account designated as their main account, and establish 3 more remote desktop sessions within the lab using their 3 other assigned demo lab accounts. When establishing the initial remote desktop connection to the lab using their main account, the user sees the change password dialog as expected. However, after logging in and trying to establish remote desktop connections to the server with their three other accounts, they are prompted that they need to change the password after logging in but can't continue with the login process - they don't see the expected change password experience. After logging in with a primary accounts, it doesn't make a difference if I try establishing a Remote Desktop connection to the environment using the name of the server, e.g. Client, or demolab.mydomain.com. I experimented with changing the settings for Remote Connections to require NLA but that didn't make a different. Appreciate any tips. Thanks

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• Getting prompted for password accessing page through script even when client and server are in same

  - by Munawar

  I'm trying to pull up an internal webpage in automated fashion using the methods in 'Internetexplorer.Application' using vbscript. But I'm getting prompted for password, although the client and the server both are in the same domain. Predictably when I manually try to access the web page, I don't have any problem. Only when I try using cscript.exe or iexplore.exe, I get prompted. I'm trying to automate some of the smoke test we do after a new build is deployed. But this password prompt is getting in the way. Following are the system specs Client machine - IE 7.0, OS is Windows server 2003 Server machine - Windows Server 2008 Both are in the same domain. So far I've unsuccessfully tried following to automate the password input system.diagnostics.process.start var WinHttpReq = new ActiveXObject("WinHttp.WinHttpRequest.5.1"); WinHttpReq.Open("GET", "http://website", false); WinHttpReq.SetCredentials("username", "password", 0); Nothing seems to work I checked in IIS. we have only anonymous and forms authentication enabled Is there any configuration setting in the client machine that can be tweaked to bypass this, although I'd hate to do it since you step on the toes of twenty people trying to do that. Preferable way would be to programmatically input it if its possible. Also, if you can suggest a more appropriate forum, that'd be great too. Please help.

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• Password Authentication Fails - NTLMv2

  - by JMeterX

  Environment: Windows 2000 sp4 EDIT: Domain Controller with no trust setup with the Win2008 Server Windows XP machines Windows 2008 Server Netapp NAS Problem: We have a shared folder that resides on a NAS using a Windows 2008 AD for the authentication with the proper permissions setup. When the Windows 2000 machine tries to open the share residing on the Win2008 machine, it is prompted for a username and password. Upon entering the credentials it continuously re-asks for credentials. Important Details: The Windows 2000 machine can ping both the XP machines and the Windows 2008 Server The Windows 2008 machine is mandated to only use NTLMv2 The Windows 2000 machine was originally set to NTLM but was recently switched to NTLMv2 if negotiated for the purpose of trying to connect to the share. As I am sure it will come up, we are using Windows 2000 because of contractual obligations Questions: Why is password Authentication failing in this case? After setting a GPO for the Win2000 machine for it to use NTLMv2, do we need to reboot the machine for the changes to take affect? We used SECEDIT to update the GPOs without rebooting. UPDATE We checked both of the 2008 Domain Controllers to find an error code. We received: Microsoft_Auth_Package_V1_0 0xc000006a Event ID: 4776 I know this to be an authentication error via THIS article "The value provided as the current password is not correct" We know this password to be correct, but since these two domains (Win2000 & Win2008) do not have a trust setup what authentication account needs to be used? One that resides on the Win2000 hosted domain?

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• SASL - Plaintext password not accepted - Encrypted works

  - by leviathanus

  I have a very strange issue! SASL does not work properly, as it does not accept plain-text passwords (like Outlook sends them) Oct 2 10:35:09 srf cyrus/imap[4119]: accepted connection Oct 2 10:35:09 srf cyrus/imap[4119]: badlogin: [217.XX.XXX.140] plaintext [email protected] SASL(-1): generic failure: checkpass failed Now I switch to "Encrypted password" in Thunderbird. I have the same issue as Outlook above on Thunderbird if I turn on "Plain Password"): Oct 2 10:40:40 srf cyrus/imap[14644]: accepted connection Oct 2 10:40:41 srf cyrus/imap[14622]: login: [217.XX.XXX.140] [email protected] CRAM-MD5 User logged in Same with Postfix: Without Oct 2 10:42:48 srf postfix/smtpd[17980]: connect from unknown[217.XX.XXX.140] Oct 2 10:42:48 srf postfix/smtpd[17980]: warning: SASL authentication failure: cannot connect to saslauthd server: Permission denied Oct 2 10:42:48 srf postfix/smtpd[17980]: warning: SASL authentication failure: Password verification failed Oct 2 10:42:48 srf postfix/smtpd[17980]: warning: unknown[217.XX.XXX.140]: SASL PLAIN authentication failed: generic failure With "Encrypted password": Oct 2 10:45:27 srf postfix/smtpd[21872]: connect from unknown[217.XX.XXX.140] Oct 2 10:45:28 srf postfix/smtpd[21872]: 50B3A332AAB: client=unknown[217.XX.XXX.140], sasl_method=CRAM-MD5, [email protected] Oct 2 10:45:28 srf postfix/cleanup[21899]: 50B3A332AAB: message-id=<[email protected]> Oct 2 10:45:28 srf postfix/qmgr[6181]: 50B3A332AAB: from=<[email protected]>, size=398, nrcpt=1 (queue active) Oct 2 10:45:28 srf postfix/smtpd[21872]: disconnect from unknown[217.XX.XXX.140] Config: /etc/imapd.conf:sasl_mech_list:LOGIN PLAIN CRAM-MD5 and /etc/postfix/sasl/smtpd.conf:mech_list: LOGIN PLAIN CRAM-MD5 I have no idea where to dig. Please advise.

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• For Loop help In a Hash Cracker Homework.

  - by aaron burns

  On the homework I am working on we are making a hash cracker. I am implementing it so as to have my cracker. java call worker.java. Worker.java implements Runnable. Worker is to take the start and end of a list of char, the hash it is to crack, and the max length of the password that made the hash. I know I want to do a loop in run() BUT I cannot think of how I would do it so it would go to the given max pasword length. I have posted the code I have so far. Any directions or areas I should look into.... I thought there was a way to do this with a certain way to write the loop but I don't know or can't find the correct syntax. Oh.. also. In main I divide up so x amount of threads can be chosen and I know that as of write now it only works for an even number of the 40 possible char given. package HashCracker; import java.util.*; import java.security.MessageDigest; import java.security.NoSuchAlgorithmException; public class Cracker { // Array of chars used to produce strings public static final char[] CHARS = "abcdefghijklmnopqrstuvwxyz0123456789.,-!".toCharArray(); public static final int numOfChar=40; /* Given a byte[] array, produces a hex String, such as "234a6f". with 2 chars for each byte in the array. (provided code) */ public static String hexToString(byte[] bytes) { StringBuffer buff = new StringBuffer(); for (int i=0; i<bytes.length; i++) { int val = bytes[i]; val = val & 0xff; // remove higher bits, sign if (val<16) buff.append('0'); // leading 0 buff.append(Integer.toString(val, 16)); } return buff.toString(); } /* Given a string of hex byte values such as "24a26f", creates a byte[] array of those values, one byte value -128..127 for each 2 chars. (provided code) */ public static byte[] hexToArray(String hex) { byte[] result = new byte[hex.length()/2]; for (int i=0; i<hex.length(); i+=2) { result[i/2] = (byte) Integer.parseInt(hex.substring(i, i+2), 16); } return result; } public static void main(String args[]) throws NoSuchAlgorithmException { if(args.length==1)//Hash Maker { //create a byte array , meassage digestand put password into it //and get out a hash value printed to the screen using provided methods. byte[] myByteArray=args[0].getBytes(); MessageDigest hasher=MessageDigest.getInstance("SHA-1"); hasher.update(myByteArray); byte[] digestedByte=hasher.digest(); String hashValue=Cracker.hexToString(digestedByte); System.out.println(hashValue); } else//Hash Cracker { ArrayList<Thread> myRunnables=new ArrayList<Thread>(); int numOfThreads = Integer.parseInt(args[2]); int charPerThread=Cracker.numOfChar/numOfThreads; int start=0; int end=charPerThread-1; for(int i=0; i<numOfThreads; i++) { //creates, stores and starts threads. Runnable tempWorker=new Worker(start, end, args[1], Integer.parseInt(args[1])); Thread temp=new Thread(tempWorker); myRunnables.add(temp); temp.start(); start=end+1; end=end+charPerThread; } } } import java.util.*; public class Worker implements Runnable{ private int charStart; private int charEnd; private String Hash2Crack; private int maxLength; public Worker(int start, int end, String hashValue, int maxPWlength) { charStart=start; charEnd=end; Hash2Crack=hashValue; maxLength=maxPWlength; } public void run() { byte[] myHash2Crack_=Cracker.hexToArray(Hash2Crack); for(int i=charStart; i<charEnd+1; i++) { Cracker.numOfChar[i]////// this is where I am stuck. } } }

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• Using hashing to group similar records

  - by Neil Dobson

  I work for a fulfillment company and we have to pack and ship many orders from our warehouse to customers. To improve efficiency we would like to group identical orders and pack these in the most optimum way. By identical I mean having the same number of order lines containing the same SKUs and same order quantities. To achieve this I was thinking about hashing each order. We can then group by hash to quickly see which orders are the same. We are moving from an Access database to a PostgreSQL database and we have .NET based systems for data loading and general order processing systems, so we can either do the hashing during the data loading or hand this task over to the DB. My question firstly is should the hashing be managed by DB, possibly using triggers, or should the hash be created on-the-fly using a view or something? And secondly would it be best to calculate a hash for each order line and then to combine these to find an order-level hash for grouping, or should I just use a trigger for all CRUD operations on the order lines table which re-calculates a single hash for the entire order and store the value in the orders table? TIA

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• LDAP Account Locked Out Sporadically after Password change - Finding the source of invalid attempts

  - by CityView

  On a small network of machines (<1000) we have a user whose account is being locked out after an indeterminate interval following a password change. We are having severe difficulties finding the source of the invalid logon attempts and I would appreciate it greatly if some of you could go through your thought process and the checks you would perform in order to fix the problem. All I know for sure is that the account is locked out several (5+) times a day, I can't even be sure it's due to failed login attempts as there is no record of failure until the account is locked. So far I have tried; Logging the account out of everything we can think of and back in with the new password Scanning the user's box for any non standard software which might perform an LDAP lookup Checking all installed services on our production boxes to check none are attempting to run under the account Changing the user back to their old password (Problem persists so perhaps password change is a red herring) Wireshark on a box where lots of LDAP authentication is performed - Rejects only occur after account is already locked out Clearing the credential cache in - Control Panel - User Accounts - Advanced Looking at the local I'm at a loss for what to try. I am happy to try any suggestions you have in order to diagnose the issue. I think my question boils down to a simple request; I need a technique for deriving the source (Application/Host) of the invalid login attempts which are causing the account to be locked. I'm not sure if that's even possible but I suspect there must be more I can try. Many thanks, CityView

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• Distributions and hashes

  - by Don Mackenzie

  Has anyone ever had an incidence of downloading software from a genuine site, where an MD5 or SHA series hash for the download is also supplied and then discovered that the hash calculated from the downloaded artifact doesn't match the published hash? I understand the theory but am curious how prevalent the problem is. Many software publishers seem to discount the threat.

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• Windows service fails to start with local user until password is entered again in logon tab

  - by Nick

  Basically we have a service where we use a local account as its logon. it has all the proper permissions, and everything is working fine, service starts and runs and all is good. Then one day, after rebooting, the service fails to start. Logs show incorrect password. Our technicians resolve the issue by simply retyping the password into the "Log On" tab from the services.msc. Unfortunately we have not been able to root cause. I suspect that the password that is stored for the service is lost somehow. Does anyone know where the password hash might be stored so we can check it? The only activities that seem to be possibly related are patching with Microsoft security patches, but we have multiple servers running the same service, and we have never seen more than one at a time, and its usually a different one each time when this occurrs. I believe this to be the same issue as this: Windows service fails to start with custom user until started once with local user But i was unable to add comments, and its really old.

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• Python unhash value

  - by blah01

  Hi all I am a newbie to the python. Can I unhash, or rather how can I unhash a value. I am using std hash() function. What I would like to do is to first hash a value send it somewhere and then unhash it as such: #process X hashedVal = hash(someVal) #send n receive in process Y someVal = unhash(hashedVal) #for example print it print someVal Thx in advance

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• Why does git hash-object return a different hash than openssl sha1?

  - by user657606

  Context: I downloaded a file (Audirvana 0.7.1.zip) from code.google to my Macbook Pro (Mac OS X 10.6.6). (current url: http://code.google.com/p/audirvana/downloads/detail?name=Audirvana%200.7.1.zip&can=2&q= ) I wanted to verify the checksum, which for that particular file is posted as 862456662a11e2f386ff0b24fdabcb4f6c1c446a (SHA-1). git hash-object gave me a different hash, but openssl sha1 returned the expected 862456662a11e2f386ff0b24fdabcb4f6c1c446a. The following experiment seems to rule out any possible download corruption or newline differences and to indicate that there are actually two different algorithms at play: $ echo A > foo.txt $ cat foo.txt A $ git hash-object foo.txt f70f10e4db19068f79bc43844b49f3eece45c4e8 $ openssl sha1 foo.txt SHA1(foo.txt)= 7d157d7c000ae27db146575c08ce30df893d3a64 What's going on?

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• Convert ten character classification string into four character one in C#

  - by mare

  What's the best way to convert (to hash) a string like 3800290030, which represents an id for a classification into a four character one like 3450 (I need to support at max 9999 classes). The hash needs to be unique and always the same for the same an input. If possible, the hash should also be reversible (but this is not required).

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• Rsync root files between systems without specifying password

  - by xpt

  This seems very tricky to me. I've set up my two systems so that I can rsync files between them as me, without specifying password. Now the the problem is to rsync files that belong to root. On both of my systems, there are no root passwords. The only way to become root is via sudo. So I can neither give a password for sudo rsyn local root@remote:, no use my ssh-agent to supply pass phrase. I don't want to set up a root password on any systems; and I do need the files to be owned by root on both systems. EDIT: Using the files that belong to root is just an example, I need a way for my unprivileged account to read/write system (including root-owned) files easily. One example is to copy my configured /root environment into the freshly-installed system. The two systems are actually two VMs under a single host, so it's not a big concern for me to copy root-owned files between them. EDIT 2: If I only want to copy my configured /root environment into the freshly-installed system, I can use tar: sudo tar cvzf - /root | ssh me@remote sudo tar xvzf - -C / But I do need rsync to update from time to time. Any easy way to make it happen? EDIT 3: Formally formulate the question Alright, it all began with the question, how to rsync files that belong to root between two systems as a normal unprivileged user, without specifying password, under the condition that, The root account is locked on both of systems. I.e., there are no root passwords. The only way to become root is via sudo (recommended security practice, see http://help.ubuntu.com/community/RootSudo) I don't want a completely passwordless sudo but don’t want to be typing passwords all the time either. The normal unprivileged user has entered their ssh pass phrase into the ssh agent. Thanks

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• Do I have to hash twice in C#?

  - by Joe H

  I have code like the following: class MyClass { string Name; int NewInfo; } List<MyClass> newInfo = .... // initialize list with some values Dictionary<string, int> myDict = .... // initialize dictionary with some values foreach(var item in newInfo) { if(myDict.ContainsKey(item.Name)) // 'A' I hash the first time here myDict[item.Name] += item.NewInfo // 'B' I hash the second (and third?) time here else myDict.Add(item.Name, item.NewInfo); } Is there any way to avoid doing two lookups in the Dictionary -- the first time to see if contains an entry, and the second time to update the value? There may even be two hash lookups on line 'B' -- one to get the int value and another to update it.

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• Combine MD5 hashes of multiple files

  - by user685869

  I have 7 files that I'm generating MD5 hashes for. The hashes are used to ensure that a remote copy of the data store is identical to the local copy. Unfortunately, the link between these two copies of the data is mind numbingly slow. Changes to the data are very rare but I have a requirement that the data be synchronized at all times (or as soon as possible). Rather than passing 7 different MD5 hashes across my (extremely slow) communications link, I'd like to generate the hash for each file and then combine these hashes into a single hash which I can then transfer and then re-calculate/use for comparison on the remote side. If the "combined hash" differs, then I'd start sending the 7 individual hashes to determine exactly which file(s) have been changed. For example, here are the MD5 hashes for the 7 files as of last week: 0709d609d69385255c496436eb50402c 709465a74411bd596595c7b9b158ae6a 4ab657320ef33e3d5eb498e4c13d41b7 3b49c6ab199994fd776bb63761414e72 0fc28c5a010fc3c06c0c930c88e31a15 c4ecd214662cac5aae0e53f6f252bf0e 8b086431e43148a2c2d943ba30d31cc6 I'd like to combine these hashes together such that I get a single unique value (perhaps another MD5 hash?) that I can then send to the remote system. On the remote system, I'd then perform the same calculation to determine if the data as a whole has been changed. If it has, then I'd start sending the individual hashes, etc. The most important factor is that my "combined hash" be short enough so that it uses less bandwidth than just sending all 7 hashes in the first place. I thought of writing the 7 MD5 hashes to a file and then hashing that file but is there a better way?

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• How do you embed a hash into a file recursively?

  - by oasisbob

  Simplest case: You want to make a text file which says "The MD5 hash of this file is FOOBARHASH". How do you embed the hash, knowing that the embedded hash value and the hash of the file are inter-related? eg, Cisco embeds hash values into their IOS images, which can be verified like this: cisco# verify s72033-advipservicesk9_wan-mz.122-33.SXH7.bin Embedded Hash MD5 : D2BB0668310392BAC803BE5A0BCD0C6A Computed Hash MD5 : D2BB0668310392BAC803BE5A0BCD0C6A IIRC, Ubuntu also includes a txt file in the root of their ISOs which have the hash of the entire ISO. Maybe I'm mistaken, but trying to figure out how to do this blows my mind.

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• Optimal strategy to make a C++ hash table, thread safe

  - by Ajeet

  (I am interested in design of implementation NOT a readymade construct that will do it all.) Suppose we have a class HashTable (not hash-map implemented as a tree but hash-table) and say there are eight threads. Suppose read to write ratio is about 100:1 or even better 1000:1. Case A) Only one thread is a writer and others including writer can read from HashTable(they may simply iterate over entire hash table) Case B) All threads are identical and all could read/write. Can someone suggest best strategy to make the class thread safe with following consideration 1. Top priority to least lock contention 2. Second priority to least number of locks My understanding so far is thus : One BIG reader-writer lock(semaphore). Specialize the semaphore so that there could be eight instances writer-resource for case B, where each each writer resource locks one row(or range for that matter). (so i guess 1+8 mutexes) Please let me know if I am thinking on the correct line, and how could we improve on this solution.

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• Find all duplicate files by md5 hash

  - by Jamie Curran

  I'm trying to find all duplicate files based upon md5 hash and ordered by file size. So far I have this: find . -type f -print0 | xargs -0 -I "{}" sh -c 'md5sum "{}" | cut -f1 -d " " | tr "\n" " "; du -h "{}"' | sort -h -k2 -r | uniq -w32 --all-repeated=separate The output of this is: 1832348bb0c3b0b8a637a3eaf13d9f22 4.0K ./picture.sh 1832348bb0c3b0b8a637a3eaf13d9f22 4.0K ./picture2.sh 1832348bb0c3b0b8a637a3eaf13d9f22 4.0K ./picture2.s d41d8cd98f00b204e9800998ecf8427e 0 ./test(1).log Is this the most efficient way?

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• Active Directory - Lightweight Directory Services and Domain Password Policy

  - by Craig Beuker

  Greetings all, We have an active directory domain which enforces a strict password policy. Hooray! Now, for the project we are working on, we are going to be storing users of our website Microsoft's AD-LDS service as well as using that for authentication of our web users. By default, it is my understanding that AD-LDS inherits its password policy from the domain of the machine it's installed on. Is there any way to break that link such that we can define a lighter password policy (or none if we so choose) for users in AD-LDS without affecting our domain? Note: AD-LDS is going to be hosted on a machine which is part of the domain. Thanks in advance.

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• Login failed--password of account must be changed--error 18488

  - by Bill Paetzke

  I failed to connect to a production SQL server. My administrator reset my password, and told me what it was. SQL Server Management Studio gives me this error: Login failed for user 'Bill'. Reason: The password of the account must be changed. (Microsoft SQL Server, Error: 18488) So, how can I reset my password? I tried terminaling into the server with this account, but it said that account doesn't exist. So I guess it's not a regular server account--just SQL server. (if that helps)

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• Force Capistrano to ask for password

  - by Moshe Katz

  I am deploying using Capistrano to a new server and having the following issue. Currently, I cannot add an SSH key to the server to log in with so I must use password authentication. However, I do have a key for another server saved in my local user account's .ssh directory. Here is the error I get when I try to log in: C:\Web\CampMaRabu>cap deploy:setup * executing `deploy:setup' * executing "mkdir -p /home2/webapp1 /home2/webapp1/releases /home2/webapp1/shared /home2/webapp1/shared/system /home2/webapp1/shared/log /home2/webapp1/shared/pids" servers: ["myserver.example.com"] connection failed for: myserver.example.com (OpenSSL::PKey::PKeyError: not a public key "C:/Users/MyAccount/.ssh/id_rsa.pub") How can I get Capistrano to ignore the existence of the key I have and let me log in with a password instead? I tried adding set :password, "myp@ssw0rd" to deploy.rb and it didn't help.

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• creating a new user Ubuntu

  - by Matt

  I am trying to new user that can sftp on a server....i did this ubuntu@ip-10-112-46-15:~$ sudo useradd jesse -p testPass ubuntu@ip-10-112-46-15:~$ sudo passwd jesse Enter new UNIX password: Retype new UNIX password: passwd: password updated successfully but when i try to login via sftp I cant get in....am i missing something like adding a group or something the answer was PasswordAuthentication yes

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• IIS 7 Using Domain Account for Application pool identity Invalid Password

  - by Luke Van Diest

  I have an asp.net website containing a WCF service that I am developing on a Windows 7 machine hosted with IIS 7. I am needing to connect to an instance of Reporting Services 2005 with the service, and have been getting 401 errors when trying to execute reports. So, I assume that I need to be running the IIS Application pool under a domain account. The problem is that when I try to change the identity to a domain account, I get the error message "The specified password is invalid. Type a new password." I've rechecked the password multiple times to make sure it is correct. The account I'm using has admin rights on the machine. I saw elsewhere to try running this command: aspnet_regiis.exe -GA domain\username which I did but it didn't help. What else do I need to do?

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• New Release Overview Part 2

  - by brian.harrison

  To continue our discussion of the next release of WCI, lets take a look at a few other new features that have been developed and tested. Password Management With customer implementations starting to go more external, we were finding that these customers wanted to use the native users within the portal because the customer did not want to provide an LDAP server that is externally facing. However, the portal does not provide anything close to the same level of password policy that a standard LDAP environment would provide. With that being the case, we made the decision to provide the same kind of password policies directly within WCI that a standard LDAP environment would have. Password Expiration - In how many days will a password expire which will force the user to change their password? Also, in how many days prior to expiration with the user be notified that their password is about the expire? Password Rotation - How many of your previous passwords will you not be able to use when changing your password? Password Policies - What are the requirements for the password that is being created by the user? Number of Characters Numbers Required Symbols Required Capitalization Required Easily Configurable - Configuration is handled through the Portal Settings utility within Administration. All options are available on the main page of the utility. In addition to the configuration options that were mention above, there has also been a complete rewrite of the Change Password screen to provide better information to the user when they are changing their password. The Change Password will now provide a red light/green light listing of all the policies the user must meet for the changed password to be successful. As the user is typing the password, the red lights will change to green lights as the policies as met. In addition, text will show next to the password text box stating what policy has not been met yet. NOTE: The password policy functionality is not held within the User Editor page within Administration. We did not want to remove the option for Administrators to change a user's password on the fly in the case of a password reset situation. Miscellaneous Features In addition to the Password Management feature, there are a few other features that are related to WCI that should be mentioned. Consolidated Installer - Instead of having up to 12 or 13 different installers, one for each of the main products and separate services, we are going to only provide two installers. One that will be used for Collaboration and its respective images. The second will contain WCI and all of the relevant services required for a WCI architecture as well as the IDK, .NET App Accelerator, SharePoint Console as well as all Content Web Services and Identity Services. Updated Documentation - Most of us are aware that the documentation hasn't been properly kept up to date with the last couple of releases. We are doing everything that we can to remedy this with the next release by consolidating and reviewing everything that is available. We are making sure to fill in the gaps that are already there, add in all documentation for the functionality as well as clearing anything that is no longer valid based on the newly released version. I hope that you enjoyed reading through this new release information. Next time we will start to talk about the new functionality that will be available within the next release of Collaboration. If there is anything in particular that you would like to get more detail about, then please don't hesitate to send me a comment.

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