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  • Getting the last User ID in Zend Framework

    - by Ryan Murphy
    Using MySQL query browser, I manually made a table called users and input some date in the fields. I set the primary key to id and set it to auto increment. There are 3 rows, the highest id is 3. I then made the following class in the method directory to call upon the data in the table etc. class Application_Model_DbTable_User extends Zend_Db_Table_Abstract { protected $_name = 'user'; public function getLatestUserId() { $id = $this->getAdapter()->lastInsertId(); return $id; } } In the controller I do the following which gets the value generated by the method and lets the view access it: $usersDbModel = new Application_Model_DbTable_User(); $lastUserId = $usersDbModel->getLatestUserId(); $this->view->lastUserId = $lastUserId; In the view I then echo it to display it to the user: echo $this->lastUserId; However, even though my last id in the users table is 3. It displays 0. I have also tried: public function getLatestUserId() { $sql = 'SELECT max(id) FROM user'; $query = $this->query($sql); $result = $query->fetchAll(); return $result; } But this just throws out a server error. What have I done wrong? Am I missing something? Is there another way of doing this?

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  • Merge computed data from two tables back into one of them

    - by Tyler McHenry
    I have the following situation (as a reduced example). Two tables, Measures1 and Measures2, each of which store an ID, a Weight in grams, and optionally a Volume in fluid onces. (In reality, Measures1 has a good deal of other data that is irrelevant here) Contents of Measures1: +----+----------+--------+ | ID | Weight | Volume | +----+----------+--------+ | 1 | 100.0000 | NULL | | 2 | 200.0000 | NULL | | 3 | 150.0000 | NULL | | 4 | 325.0000 | NULL | +----+----------+--------+ Contents of Measures2: +----+----------+----------+ | ID | Weight | Volume | +----+----------+----------+ | 1 | 75.0000 | 10.0000 | | 2 | 400.0000 | 64.0000 | | 3 | 100.0000 | 22.0000 | | 4 | 500.0000 | 100.0000 | +----+----------+----------+ These tables describe equivalent weights and volumes of a substance. E.g. 10 fluid ounces of substance 1 weighs 75 grams. The IDs are related: ID 1 in Measures1 is the same substance as ID 1 in Measures2. What I want to do is fill in the NULL volumes in Measures1 using the information in Measures2, but keeping the weights from Measures1 (then, ultimately, I can drop the Measures2 table, as it will be redundant). For the sake of simplicity, assume that all volumes in Measures1 are NULL and all volumes in Measures2 are not. I can compute the volumes I want to fill in with the following query: SELECT Measures1.ID, Measures1.Weight, (Measures2.Volume * (Measures1.Weight / Measures2.Weight)) AS DesiredVolume FROM Measures1 JOIN Measures2 ON Measures1.ID = Measures2.ID; Producing: +----+----------+-----------------+ | ID | Weight | DesiredVolume | +----+----------+-----------------+ | 4 | 325.0000 | 65.000000000000 | | 3 | 150.0000 | 33.000000000000 | | 2 | 200.0000 | 32.000000000000 | | 1 | 100.0000 | 13.333333333333 | +----+----------+-----------------+ But I am at a loss for how to actually insert these computed values into the Measures1 table. Preferably, I would like to be able to do it with a single query, rather than writing a script or stored procedure that iterates through every ID in Measures1. But even then I am worried that this might not be possible because the MySQL documentation says that you can't use a table in an UPDATE query and a SELECT subquery at the same time, and I think any solution would need to do that. I know that one workaround might be to create a new table with the results of the above query (also selecting all of the other non-Volume fields in Measures1) and then drop both tables and replace Measures1 with the newly-created table, but I was wondering if there was any better way to do it that I am missing.

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  • Table not created by Hibernate

    - by User1
    I annotated a bunch of POJO's so JPA can use them to create tables in Hibernate. It appears that all of the tables are created except one very central table called "Revision". The Revision class has an @Entity(name="RevisionT") annotation so it will be renamed to RevisionT so there is not a conflict with any reserved words in MySQL (the target database). I delete the entire database, recreate it and basically open and close a JPA session. All the tables seem to get recreated without a problem. Why would a single table be missing from the created schema? What instrumentation can be used to see what Hibernate is producing and which errors? Thanks. UPDATE: I tried to create as a Derby DB and it was successful. However, one of the fields has a a name of "index". I use @org.hibernate.annotations.IndexColumn to specify the name to something other than a reserved word. However, the column is always called "index" when it is created. Here's a sample of the suspect annotations. @ManyToOne @JoinColumn(name="MasterTopID") @IndexColumn(name="Cx3tHApe") protected MasterTop masterTop; Instead of creating MasterTop.Cx3tHApe as a field, it creates MasterTop.Index. Why is the name ignored?

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  • Problem with checkboxes, sql select statements & php

    - by smokey20
    I am trying to display some rows from a database table based on choices submitted by the user. Here is my form code <form action="choice.php" method="POST" > <input type="checkbox" name="variable[]" value="Apple">Apple <input type="checkbox" name="variable[]" value="Banana">Banana <input type="checkbox" name="variable[]" value="Orange">Orange <input type="checkbox" name="variable[]" value="Melon">Melon <input type="checkbox" name="variable[]" value="Blackberry">Blackberry From what I understand I am placing the values of these into an array called variable. Two of my columns are called receipe name and ingredients(each field under ingredients can store a number of fruits). What I would like to do is, if a number of checkboxes are selected then the receipe name/s is displayed. Here is my php code. <?php // Make a MySQL Connection mysql_connect("localhost", "*****", "*****") or die(mysql_error()); mysql_select_db("****") or die(mysql_error()); $variable=$_POST['variable']; foreach ($variable as $variablename) { echo "$variablename is checked"; } $query = "SELECT receipename FROM fruit WHERE $variable like ingredients"; $row = mysql_fetch_assoc($result); foreach ($_POST['variabble'] as $ingredients) echo $row[$ingredients] . '<br/>'; ?> I am very new to php and just wish to display the data, I do not need to perform any actions on it. I have tried many select statements but I cannot get any results to display. My db connection is fine and it does print out what variables are checked. Many thanks in advance.

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  • a reusable query with modifications?

    - by fusion
    i'm using this mysql query alongwith php to search for multiple keywords: $query = "SELECT cQuotes, vAuthor, cArabic, vReference FROM ".$table." WHERE ("; $countFields = count($arrayFields); while ($a < $countFields) { while ($b < $countSearch) { $query = $query."$arrayFields[$a] LIKE '%$arraySearch[$b]%'"; $b++; if ($b < $countSearch) { $query = $query." AND "; } } $b = 0; $a++; if ($a < $countFields) { $query = $query.") OR ("; } } $query = $query.")"; $result = mysql_query($query, $conn) i'd like to reuse this query with a few modifications to it (for instance, the WHERE clause remains the same, while i query the number of rows using COUNT), but it doesn't seem practical to repeat the code again for a few additions. any suggestions?

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  • #1146 - Table 'phpmyadmin.pma_recent' doesn't exist

    - by Mumin Ali
    Solution Guys... FYI i am using xampp to use phpmyadmin. and this error happens during the process of creating a database on localhost. Below is the code for config.inc file under phpmyadmin directory: <?php /* * This is needed for cookie based authentication to encrypt password in * cookie */ $cfg['blowfish_secret'] = 'xampp'; /* YOU SHOULD CHANGE THIS FOR A MORE SECURE COOKIE AUTH! */ /* * Servers configuration */ $i = 0; /* * First server */ $i++; /* Authentication type and info */ $cfg['Servers'][$i]['auth_type'] = 'HTTP'; $cfg['Servers'][$i]['user'] = 'root'; $cfg['Servers'][$i]['password'] = 'password'; $cfg['Servers'][$i]['extension'] = 'mysql'; $cfg['Servers'][$i]['AllowNoPassword'] = true; $cfg['Lang'] = ''; /* Bind to the localhost ipv4 address and tcp */ $cfg['Servers'][$i]['host'] = 'localhost'; $cfg['Servers'][$i]['connect_type'] = 'tcp'; /* User for advanced features */ $cfg['Servers'][$i]['controluser'] = 'pma'; $cfg['Servers'][$i]['controlpass'] = ''; /* Advanced phpMyAdmin features */ $cfg['Servers'][$i]['pmadb'] = 'phpmyadmin'; $cfg['Servers'][$i]['bookmarktable'] = 'pma_bookmark'; $cfg['Servers'][$i]['relation'] = 'pma_relation'; $cfg['Servers'][$i]['table_info'] = 'pma_table_info'; $cfg['Servers'][$i]['table_coords'] = 'pma_table_coords'; $cfg['Servers'][$i]['pdf_pages'] = 'pma_pdf_pages'; $cfg['Servers'][$i]['column_info'] = 'pma_column_info'; $cfg['Servers'][$i]['history'] = 'pma_history'; $cfg['Servers'][$i]['designer_coords'] = 'pma_designer_coords'; $cfg['Servers'][$i]['tracking'] = 'pma_tracking'; $cfg['Servers'][$i]['userconfig'] = 'pma_userconfig'; $cfg['Servers'][$i]['recent'] = 'pma_recent'; $cfg['Servers'][$i]['table_uiprefs'] = 'pma_table_uiprefs'; /* * End of servers configuration */ ?>

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  • How to display multiple categories and products underneath each category?

    - by shin
    Generally there is a category menu and each link to a category page where shows all the items under that category. Now I need to show all the categories and products underneath with PHP/MySQL in the same page. So it will be like this. Category 1 description of category 1 item 1 item 2 .. Category 2 description of category 2 item 5 item 6 .. Category 3 description of category 3 item 8 item 9 ... ... I have category and product table in my database. But I am not sure how to proceed. CREATE TABLE IF NOT EXISTS `omc_product` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL, `shortdesc` varchar(255) NOT NULL, `longdesc` text NOT NULL, `thumbnail` varchar(255) NOT NULL, `image` varchar(255) NOT NULL, `product_order` int(11) DEFAULT NULL, `class` varchar(255) DEFAULT NULL, `grouping` varchar(16) DEFAULT NULL, `status` enum('active','inactive') NOT NULL, `category_id` int(11) NOT NULL, `featured` enum('none','front','webshop') NOT NULL, `other_feature` enum('none','most sold','new product') NOT NULL, `price` float(7,2) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=2 ; CREATE TABLE IF NOT EXISTS `omc_category` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL, `shortdesc` varchar(255) NOT NULL, `longdesc` text NOT NULL, `status` enum('active','inactive') NOT NULL, `parentid` int(11) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=2 ; I will appreciate your help. Thanks in advance.

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  • PHP DELETE immediately after select

    - by teehoo
    I have a PHP server script that SELECTs some data from a MySQL database. As soon as I have the result from mysql_query and mysql_fetch_assoc stored in my own local variables, I want to delete the row I just selected. The problem with this approach is that it seems that PHP has done pass-by-reference to my local variables instead of pass-by-value, and my local variables become undefined after the delete command. Is there anyway to get around this? Here is my code: $query="SELECT id, peerID, name FROM names WHERE peer = $userID AND docID = '$docID' AND seqNo = $nid"; $result = mysql_query($query); if (!$result) self::logError("FAIL:1 getUsersNamesUpdate() query: ".$query."\n"); if (mysql_num_rows($result) == 0) return array(); $row = mysql_fetch_assoc($result); $result = array(); $result["id"] = $row["id"]; $result["peerID"] = $row["peerID"]; $result["name"] = $row["name"]; $query="DELETE FROM names WHERE id = $result[id];"; $result = mysql_query($query); if (!$result) self::logError("FAIL:2 getUsersNamesUpdate() query: ".$query."\n"); return $result;

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  • Most watched videos this week

    - by Jan Hancic
    I have a youtube like web-page where users upload&watch videos. I would like to add a "most watched videos this week" list of videos to my page. But this list should not contain just the videos that ware uploaded in the previous week, but all videos. I'm currently recording views in a column, so I have no information on when a video was watched. So now I'm searching for a solution to how to record this data. The first is the most obvious (and the correct one, as far as I know): have a separate table in which you insert a new line every time you want to record a new view (storing the ID of the video and the timestamp). I'm worried that I would quickly get huge amounts of data in this table, and queries using this table would be extremely slow (we get about 3 million views a month). The second solution isn't as flexible but is more easy on the database. I would add 7 columns to the "videos" table (one for each day of the week): views_monday, views_tuesday , views_wednesday, ... And increment the value in the correct column based on the day it is. And I would reset the current day's column to 0 at midnight. I could then easily get the most watched videos of the week by summing this 7 columns. What do you think, should I bother with the first solution or will the second one suffice for my case? If you have a better solution please share! Oh, I'm using MySQL.

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  • What's the best way to "shuffle" a table of database records?

    - by Darth
    Say that I have a table with a bunch of records, which I want to randomly present to users. I also want users to be able to paginate back and forth, so I have to perserve some sort of order, at least for a while. The application is basically only AJAX and it uses cache for already visited pages, so even if I always served random results, when the user tries to go back, he will get the previous page, because it will load from the local cache. The problem is, that if I return only random results, there might be some duplicates. Each page contains 6 results, so to prevent this, I'd have to do something like WHERE id NOT IN (1,2,3,4 ...) where I'd put all the previously loaded IDs. Huge downside of that solution is that it won't be possible to cache anything on the server side, as every user will request different data. Alternate solution might be to create another column for ordering the records, and shuffle it every insert time unit here. The problem here is, I'd need to set random number out of a sequence to every record in the table, which would take as many queries as there are records. I'm using Rails and MySQL if that's of any relevance.

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  • Website. VoteUp or VoteDown Videos. How to restrict users voting multiple times?

    - by DJDonaL3000
    Im working on a website (html,css,javascript, ajax, php,mysql), and I want to restrict the number of times a particular user votes for a particular video. Its similar to the YouTube system where you can voteUp or voteDown a particular video. Each vote involves adding a row to the video.votes table, which logs the time, vote direction(up or down), the client IPaddress( using PHP: $ip = $_SERVER['REMOTE_ADDR']; ), and of course the ID of the video in question. Adding votes is as simple as; (pseudocode): Javascript:onClick( vote( a,b,c,d ) ), which passes variables to PHP insertion script via ajax, and finally we replace the voteing buttons with a "Thank You For Voting" message. THE PROBLEM: If you reload/refresh the page after voting, you can vote again, and again, and again, you get the point. MY QUESTION: How do you limit the amount of times a particular user votes for a particular video?? MY THOUGHTS: Do you use cookies, and add a new cookie with the id of the video. And check for a cookie before you insert a new vote.? OR Before you insert the vote, do you use the IPaddress and the videoID to see if this same user(IP) has voted for this same video(vidID) in the past 24hrs(mktime), and either allow or dissallow the voteInsertion based on this query? OR Do you just not care? Take the assumption that most users are sane, and have better things to do than refresh pages and vote repeatedly.?? Any suggestions or ideas welcome.

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  • DBIx::Class base result class

    - by Rob
    Hi there, I am trying to create a model for Catalyst by using DBIx::Class::Schema::Loader. I want the result classes to have a base class I can add methods to. So MyTable.pm inherits from Base.pm which inherits from DBIx::Class::core (default). Somehow I cannot figure out how to do this. my create script is below, can anyone tell me what I am doing wrong? The script creates my model ok, but all resultset classes just directly inherit from DBIx::Class::core without my Base class in between. #!/usr/bin/perl use DBIx::Class::Schema::Loader qw/ make_schema_at /; #specifically for the entities many-2-many relation $ENV{DBIC_OVERWRITE_HELPER_METHODS_OK} = 1; make_schema_at( 'MyApp::Schema', { dump_directory => '/tmp', debug => 1, overwrite_modifications => 1, components => ['EncodedColumn'], #encoded password column use_namespaces => 1, default_resultset_class => 'Base' }, [ 'DBI:mysql:database=mydb;host=localhost;port=3306','rob', '******' ], );

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  • can this problem be solved with a single SQL query?

    - by PierrOz
    I have the two following tables (with some sample datas) LOGS: ID | SETID | DATE ======================== 1 | 1 | 2010-02-25 2 | 2 | 2010-02-25 3 | 1 | 2010-02-26 4 | 2 | 2010-02-26 5 | 1 | 2010-02-27 6 | 2 | 2010-02-27 7 | 1 | 2010-02-28 8 | 2 | 2010-02-28 9 | 1 | 2010-03-01 STATS: ID | OBJECTID | FREQUENCY | STARTID | ENDID ============================================= 1 | 1 | 0.5 | 1 | 5 2 | 2 | 0.6 | 1 | 5 3 | 3 | 0.02 | 1 | 5 4 | 4 | 0.6 | 2 | 6 5 | 5 | 0.6 | 2 | 6 6 | 6 | 0.4 | 2 | 6 7 | 1 | 0.35 | 3 | 7 8 | 2 | 0.6 | 3 | 7 9 | 3 | 0.03 | 3 | 7 10 | 4 | 0.6 | 4 | 8 11 | 5 | 0.6 | 4 | 8 7 | 1 | 0.45 | 5 | 9 8 | 2 | 0.6 | 5 | 9 9 | 3 | 0.02 | 5 | 9 Every day new logs are analyzed on different sets of objects and stored in table LOGS. Among other processes, some statistics are computed on the objects contained into these sets and the result are stored in table STATS. These statistic are computed through several logs (identified by the STARTID and ENDID columns). So, what could be the SQL query that would give me the latest computed stats for all the objects with the corresponding log dates. In the given example, the result rows would be: OBJECTID | SETID | FREQUENCY | STARTDATE | ENDDATE ====================================================== 1 | 1 | 0.45 | 2010-02-27 | 2010-03-01 2 | 1 | 0.6 | 2010-02-27 | 2010-03-01 3 | 1 | 0.02 | 2010-02-27 | 2010-03-01 4 | 2 | 0.6 | 2010-02-26 | 2010-02-28 5 | 2 | 0.6 | 2010-02-26 | 2010-02-28 So, the most recent stats for set 1 are computed with logs from feb 27 to march 1 whereas stats for set 2 are computed from feb 26 to feb 28. object 6 is not in the results rows as there is no stat on it within the last period of time. Last thing, I use MySQL. Any Idea ?

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  • Symfony generating database from model

    - by Sergej Jevsejev
    Hello, I am having troubles generating a simple database form model. I am using: Doctrine on Symfony 1.4.4 MySQL Workbench 5.2.16 with Doctrine Export 0.4.2dev So my ERL Model is: http://img708.imageshack.us/img708/1716/tmg.png Genereted YAML file: --- detect_relations: true options: collate: utf8_unicode_ci charset: utf8 type: InnoDB Course: columns: id: type: integer(4) primary: true notnull: true autoincrement: true name: type: string(255) notnull: true keywords: type: string(255) notnull: true summary: type: clob(65535) notnull: true Lecture: columns: id: type: integer(4) primary: true notnull: true autoincrement: true course_id: type: integer(4) primary: true notnull: true name: type: string(255) notnull: true description: type: string(255) notnull: true url: type: string(255) relations: Course: class: Course local: course_id foreign: id foreignAlias: Lectures foreignType: many owningSide: true User: columns: id: type: integer(4) primary: true unique: true notnull: true autoincrement: true firstName: type: string(255) notnull: true lastName: type: string(255) notnull: true email: type: string(255) unique: true notnull: true designation: type: string(1024) personalHeadline: type: string(1024) shortBio: type: clob(65535) UserCourse: tableName: user_has_course columns: user_id: type: integer(4) primary: true notnull: true course_id: type: integer(4) primary: true notnull: true relations: User: class: User local: user_id foreign: id foreignAlias: UserCourses foreignType: many owningSide: true Course: class: Course local: course_id foreign: id foreignAlias: UserCourses foreignType: many owningSide: true And no matter what I try this error occurs after: symfony doctrine:build --all --no-confirmation SQLSTATE[42000]: Syntax error or access violation: 1072 Key column 'user_userid' doesn't exist in table. Failing Query: "ALTER TABLE user_has_course ADD CONSTRAINT user_has_course_user_userid_user_id FOREIGN KEY (user_userid) REFERENCES user(id)". Failing Query: ALTER TABLE user_has_course ADD CONSTRAINT user_has_cou rse_user_userid_user_id FOREIGN KEY (user_userid) REFERENCES user(id) Currently I am studying Symfony, and stuck with this error. Please help.

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  • Getting the number of posts a user has by the number of rows returned?

    - by transparent
    So I have a question. I have chatting/IM website that I am working on and I was making a user profile page. I wanted to show how many posts that user had. Another issue I had earlier was that when I called a certain value it would return a 'Resource #1' type string. But I got that working by using $totalposts=mysql_query("SELECT * FROM `posts` WHERE Username='" . $username . "'"); $totalposts = mysql_fetch_row($totalposts); $totalposts = $totalposts[0]; But that just returns the last postID of the most recent post. I thought that mysql_num_rows would work. But this code returns an error (example with numbers): 29: $totalposts=mysql_query("SELECT * FROM `posts` WHERE Username='" . $username . "'"); 30: $totalposts = mysql_num_rows($totalposts); 31: $totalposts =mysql_fetch_row($totalposts); 32: $totalposts = $totalposts[0]; That returns this error: Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in /home/a9091503/public_html/im/user.php on line 31 Thanks guys. :) I hope you can figure this out. :D

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  • SQL trigger to delete rows from database

    - by wpearse
    I have an industrial system that logs alarms to a remotely hosted MySQL database. The industrial system inserts a new row whenever a property of the alarm changes (such as the time the alarm was activated, acknowledged or switched off) into a table named 'alarms'. I don't want multiple records for each alarm, so I have set up two database triggers. The first trigger mirrors each new record to a second table, creating/updating rows as required: CREATE TRIGGER `mirror_alarms` BEFORE INSERT ON `alarms` FOR EACH ROW INSERT INTO `alarm_display` (Tag,...,OffTime) VALUES (new.Tag,...,new.OffTime) ON DUPLICATE KEY UPDATE OnDate=new.OnDate,...,OffTime=new.OffTime The second trigger should execute after the first and (ideally) delete all rows from the alarms table. (I used the Tag property of the alarm because the Tag property never changes, although I suspect I could just use a 'DELETE FROM alarms WHERE 1' statement to the same effect). CREATE TRIGGER `remove_alarms` AFTER INSERT ON `alarms` FOR EACH ROW DELETE FROM alarms WHERE Tag=new.Tag My problem is that the second trigger doesn't appear to run, or if it does, the second trigger doesn't delete any rows from the database. So here's the question: why does my second trigger not do what I expect it to do?

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  • PHP active page code - I can't figure out parse error

    - by dmschenk
    I'm trying to build an active page menu with PHP and MySQL and am having a difficult time fixing the error. In the while statement I have an if statement that is giving me fits. Basically I think I'm saying that "thispage" is equal to the "title" based on pageID and as the menu is looped through if "thispage" is equal to "title" then echo id="active". Thanks <?php mysql_select_db($database_db_connection, $db_connection); $query_rsDaTa = "SELECT * FROM pages WHERE pagesID = 4"; $rsDaTa = mysql_query($query_rsDaTa, $db_connection) or die(mysql_error()); $row_rsDaTa = mysql_fetch_assoc($rsDaTa); $totalRows_rsDaTa = mysql_num_rows($rsDaTa); $query_rsMenu = "SELECT * FROM menu WHERE online = 1 ORDER BY menuPos ASC"; $rsMenu = mysql_query($query_rsMenu, $db_connection) or die(mysql_error()); $thisPage = ($row_rsDaTa['title']); ?> <link href="../css/MainStyle.css" rel="stylesheet" type="text/css" /> <h2><?php echo $thisPage; ?></h2> <div id="footcontainer"> <ul id="footlist"> <?php while($row_rsMenu = mysql_fetch_assoc($rsMenu)) { echo (" <li" . <?php if ($thisPage==$row_rsDaTa['title']) echo id="active"; ?> . "<a href=\"../" . $row_rsMenu['menuURL'] . "\">" . $row_rsMenu['menuName'] . "</a></li>\n"); } echo "</ul>\n"; ?> </div> <?php mysql_free_result($rsMenu); mysql_free_result($rsDaTa); ?>

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  • Viewing recently edited etherpads (note new 'etherpad' tag for open sourced etherpad code!)

    - by dreeves
    Prescript: The amazing etherpad was recently open sourced. Get it here: http://code.google.com/p/etherpad. This is the first question that I know of on StackOverflow about the etherpad code. If you're part of the etherpad open source community, you might want to subscribe to the RSS feed for questions tagged 'etherpad' just in case this catches on! My actual question, which assumes you have etherpad installed on your own server: First, here's a query to view recently edited pads: SELECT id,lastWriteTime,creationTime,headRev FROM PAD_SQLMETA ORDER BY lastWriteTime, headRev; Or, if you want to run it from a unix prompt: mysql -u root -pPASSWD etherpad -e "select id,lastWriteTime,creationTime,headRev from PAD_SQLMETA order by lastWriteTime, headRev" That's handy, however lastWriteTime actually gets updated every time someone so much as views a pad in their browser. I'd rather sort the pads by when they were actually last edited. There's probably a fancy SQL query involving a join with another table that would show actual last edit time. Does anyone know what that is? Alternatively, you could have a script that notices when headRev changes but that doesn't seem like the cleanest way to do it.

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  • How can several different datatypes be saved in one table

    - by poseidon
    This is my situation: I am constructing an ad-like application in Django and Mysql. I am using a flexible-ad approach where we have: a table with ad categories (several categories such as home, furniture, cars, etc.) id_category name a table with details for the ad categories (home: area, squared meters. car: seats, color.) id_detail id_category (the categ the detail describes) name type (boolean, char, int, long, etc.) the ad table (i am selling a house. i am selling a car.) id_ad id_category text date a table where i plan to consolidate the details of the ads (home: A-area, 500 sq-meters. car: 5 seats, red.) id_detail_ad id_ad id_detail value Is this possible? Can I have a table of details for all the ads, even if details include numbers, texts, booleans, etc? Or would I have to save them all as text and then interpret them via code accordingly? Please express your opinions. Thank you.

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  • Join with Three Tables

    - by John
    Hello, In MySQL, I am using the following three tables (their fields are listed after their titles): comment: commentid loginid submissionid comment datecommented login: loginid username password email actcode disabled activated created points submission: submissionid loginid title url displayurl datesubmitted I would like to display "datecommented" and "comment" for a given "username," where "username" equals a variable called $profile. I would also like to make the "comment" a hyperlink to http://www...com/.../comments/index.php?submission='.$rowc["title"].'&submissionid='.$rowc["submissionid"].'&url='.$rowc["url"].'&countcomments='.$rowc["countComments"].'&submittor='.$rowc["username"].'&submissiondate='.$rowc["datesubmitted"].'&dispurl='.$rowc["displayurl"].' where countComments equals COUNT(c.commentid) and $rowc is part of the query listed below. I tried using the code below to do what I want, but it didn't work. How could I change it to make it do what I want? Thanks in advance, John $sqlStrc = "SELECT s.loginid ,s.title ,s.url ,s.displayurl ,s.datesubmitted ,l.username ,l.loginid ,s.title ,s.submissionid ,c.comment ,c.datecommented ,COUNT(c.commentid) countComments FROM submission s INNER JOIN login l ON s.loginid = l.loginid LEFT OUTER JOIN comment c ON c.loginid = l.loginid WHERE l.username = '$profile' GROUP BY c.loginid ORDER BY s.datecommented DESC LIMIT 10"; $resultc = mysql_query($sqlStrc); $arrc = array(); echo "<table class=\"samplesrec1c\">"; while ($rowc = mysql_fetch_array($resultc)) { $dtc = new DateTime($rowc["datecommented"], $tzFromc); $dtc->setTimezone($tzToc); echo '<tr>'; echo '<td class="sitename3c">'.$dtc->format('F j, Y &\nb\sp &\nb\sp g:i a').'</a></td>'; echo '<td class="sitename1c"><a href="http://www...com/.../comments/index.php?submission='.$rowc["title"].'&submissionid='.$rowc["submissionid"].'&url='.$rowc["url"].'&countcomments='.$rowc["countComments"].'&submittor='.$rowc["username"].'&submissiondate='.$rowc["datesubmitted"].'&dispurl='.$rowc["displayurl"].'">'.stripslashes($rowc["comment"]).'</a></td>'; echo '</tr>'; } echo "</table>";

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  • Avoiding repeated subqueries when 'WITH' is unavailable

    - by EloquentGeek
    MySQL v5.0.58. Tables, with foreign key constraints etc and other non-relevant details omitted for brevity: CREATE TABLE `fixture` ( `id` int(11) NOT NULL auto_increment, `competition_id` int(11) NOT NULL, `name` varchar(50) NOT NULL, `scheduled` datetime default NULL, `played` datetime default NULL, PRIMARY KEY (`id`) ); CREATE TABLE `result` ( `id` int(11) NOT NULL auto_increment, `fixture_id` int(11) NOT NULL, `team_id` int(11) NOT NULL, `score` int(11) NOT NULL, `place` int(11) NOT NULL, PRIMARY KEY (`id`) ); CREATE TABLE `team` ( `id` int(11) NOT NULL auto_increment, `name` varchar(50) NOT NULL, PRIMARY KEY (`id`) ); Where: A draw will set result.place to 0 result.place will otherwise contain an integer representing first place, second place, and so on The task is to return a string describing the most recently played result in a given competition for a given team. The format should be "def Team X,Team Y" if the given team was victorious, "lost to Team X" if the given team lost, and "drew with Team X" if there was a draw. And yes, in theory there could be more than two teams per fixture (though 1 v 1 will be the most common case). This works, but feels really inefficient: SELECT CONCAT( (SELECT CASE `result`.`place` WHEN 0 THEN "drew with" WHEN 1 THEN "def" ELSE "lost to" END FROM `result` WHERE `result`.`fixture_id` = (SELECT `fixture`.`id` FROM `fixture` LEFT JOIN `result` ON `result`.`fixture_id` = `fixture`.`id` WHERE `fixture`.`competition_id` = 2 AND `result`.`team_id` = 1 ORDER BY `fixture`.`played` DESC LIMIT 1) AND `result`.`team_id` = 1), ' ', (SELECT GROUP_CONCAT(`team`.`name`) FROM `fixture` LEFT JOIN `result` ON `result`.`fixture_id` = `fixture`.`id` LEFT JOIN `team` ON `result`.`team_id` = `team`.`id` WHERE `fixture`.`id` = (SELECT `fixture`.`id` FROM `fixture` LEFT JOIN `result` ON `result`.`fixture_id` = `fixture`.`id` WHERE `fixture`.`competition_id` = 2 AND `result`.`team_id` = 1 ORDER BY `fixture`.`played` DESC LIMIT 1) AND `team`.`id` != 1) ) Have I missed something really obvious, or should I simply not try to do this in one query? Or does the current difficulty reflect a poor table design?

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  • Guidance required: FIrst time gonna work with real high end database (size = 50GB).

    - by claws
    I got a project of designing a Database. This is going to be my first big scale project. Good thing about it is information is mostly organized & currently stored in text files. The size of this information is 50GB. There are going to be few millions of records in each Table. Its going to have around 50 tables. I need to provide a web interface for searching & browsing. I'm going to use MySQL DBMS. I've never worked with a database more than 200MB before. So, speed & performance was never a concern but I followed things like normalization & Indexes. I never used any kind of testing/benchmarking/queryOptimization/whatever because I never had to care about them. But here the purpose of creating a database is to make it quickly searchable. So, I need to consider all possible aspects in design. I was browsing archives & found: http://stackoverflow.com/questions/1981526/what-should-every-developer-know-about-databases http://stackoverflow.com/questions/621884/database-development-mistakes-made-by-app-developers I'm gonna keep the points mentioned in above answers in mind. What else should I know? What else should I keep in mind?

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  • @ManyToMany Duplicate Entry Exception

    - by zp26
    I have mapped a bidirectional many-to-many exception between the entities Course and Trainee in the following manner: Course { ... private Collection<Trainee> students; ... @ManyToMany(targetEntity = lesson.domain.Trainee.class, cascade = {CascadeType.All}, fetch = {FetchType.EAGER}) @Jointable(name="COURSE_TRAINEE", joincolumns = @JoinColumn(name="COURSE_ID"), inverseJoinColumns = @JoinColumn(name = "TRAINEE_ID")) @CollectionOfElements public Collection<Trainee> getStudents() { return students; } ... } Trainee { ... private Collection<Course> authCourses; ... @ManyToMany(cascade = {CascadeType.All}, fetch = {FetchType.EAGER}, mappedBy = "students", targetEntity = lesson.domain.Course.class) @CollectionOfElements public Collection<Course> getAuthCourses() { return authCourses; } ... } Instead of creating a table where the Primary Key is made of the two foreign keys (imported from the table of the related two entities), the system generates the table "COURSE_TRAINEE" with the following schema: I am working on MySQL 5.1 and my App. Server is JBoss 5.1. Does anyone guess why?

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  • Exporting database from external server (without SSH access)

    - by Derek Carlisle
    Our current website is hosted by the design agency who originally built the website, however we are bringing the development of the website in house therefore need to export the database from their server and import it to ours. We have FTP and phpMyAdmin access but don't have SSH access to the server. I was hoping to run a PHP script that would mysql dump the database, compress it and then copy it across to our server using scp: $backupFile = $_SERVER['DOCUMENT_ROOT'].'/backup' . date("Y-m-d-H-i-s") . '.gz'; system("mysqldump -h DB_HOST -u DB_USER -pDB_PASS DB_NAME | gzip > $backupFile"); exec("sshpass -p PASSWORD scp -r -P PORT_NUMBER $backupFile [email protected]:/path/to/directory/"); I have ran this locally from the command line and it worked fine, although I had to install sshpass (the hosting server might not have this installed). Also, I was hoping to run it from the browser as I don't have command line access on the hosting server, however it didn't work, no errors produced though. Can you anyone recommend how I can export from the server that I don't have SSH access to and import to my server? Thanks

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  • MediaWiki: how to hide users from the user list?

    - by Dave Everitt
    I've set up Mediawiki 1.15.1 for a client who has added two users by mistake. They now want to hide these users from the user list. It seems this is done via the $wgGroupPermissions array with $wgGroupPermissions['suppress']['hideuser'] = true;, but it isn't at all clear what entry this needs for the hiding to work, or whether a new group ('hidden' or whatever) has to be created first with $wgAddGroups['bureaucrat'] = true;. For now, I've added the two users to be hidden to the 'Oversight' group which explains 'Block a username, hiding it from the public (hideuser)', but they still appear on the Special:ListUsers page. At a loss as to how the MediWiki arrays alter options displayed in the interface, so far I've added this to LocalSettings.php: $wgGroupPermissions['suppress']['hideuser'] = true; $wgAddGroups['supress'] = true; Or - since they haven't actually added anything to the wiki - could they simply be removed from the MySQL users table - although MediaWiki warns against this? Has anyone else done this successfully? Update - this is a hole in MediaWiki admin (although there are workarounds). See this thread on MediaWIki Users and the note to the reply below.

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