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  • Help understand difference in sql query

    - by Anil Namde
    Select user_name [User Name], first_name [First Name], last_name [Last Name] Form tab_user ORDER BY user_name Select user_name [User Name], first_name [First Name], last_name [Last Name] Form tab_user ORDER BY User Name Above are the two queries, Is there any difference because of the user_name used instead of User Name Is there something that should be taken care/worried when using something like this.

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  • Error in inserting data into data using JPA in netbeans

    - by sandeep
    SEVERE: Local Exception Stack: Exception [EclipseLink-7092] (Eclipse Persistence Services - 2.0.0.v20091127-r5931): org.eclipse.persistence.exceptions.ValidationException Exception Description: Cannot add a query whose types conflict with an existing query. Query To Be Added: [ReadAllQuery(name="Voter.findAll" referenceClass=Voter jpql="SELECT v FROM Voter v")] is named: [Voter.findAll] with arguments [[]].The existing conflicting query: [ReadAllQuery(name="Voter.findAll" referenceClass=Voter jpql="SELECT v FROM Voter v")] is named: [Voter.findAll] with arguments: [[]].

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  • Explain this SQL query in plain English.

    - by Kevinniceguy
    Please explain, in plain English, what question this SQL query answers: SELECT SUM(price) FROM Room r, Hotel h WHERE r.hotelNo = h.hotelNo and hotelName = 'Paris Hilton' and roomNo NOT IN (SELECT roomNo FROM Booking b, Hotel h WHERE (dateFrom <= CURRENT_DATE AND dateTo >= CURRENT_DATE) AND b.hotelNo = h.hotelNo AND hotelName = 'Paris Hilton');

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  • Mysql Avg function for recent 15 records by date (order date desc) in every symbol

    - by venkatesh
    i am trying to create a statement in sql (for a table which holds stock symbols and price on specified date) with avg of 5 day price and avg of 15 days price for each symbol. table description: symbol open high close date the average price is calculated from last 5 days and last 15 days. i tried this for getting 1 symbol: SELECT avg(close), avg(`trd_qty`) FROM (select * from cashmarket WHERE symbol = \'hdil\' order by `M_day` desc limit 0,15 ) s ...but I couldn't get the desired the list for showing avg values for all symbols.

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  • Drop Down list in PHP

    - by ajithperuva
    In my application am submiting my form by using post for a php page. <form method="post"> <select name="txtplace"> <option value="1">ajith</option> </select> </form> here when i am try to get the value of my dropdown its only getting 1.How can i get ajith

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  • Have I to count transactions before rollback one in catch block in T-SQL?

    - by abatishchev
    I have next block in the end of each my stored procedure for SQL Server 2008 BEGIN TRY BEGIN TRAN -- my code COMMIT END TRY BEGIN CATCH IF (@@trancount > 0) BEGIN ROLLBACK DECLARE @message NVARCHAR(MAX) DECLARE @state INT SELECT @message = ERROR_MESSAGE(), @state = ERROR_STATE() RAISERROR (@message, 11, @state) END END CATCH Is it possible to switch CATCH-block to BEGIN CATCH ROLLBACK DECLARE @message NVARCHAR(MAX) DECLARE @state INT SELECT @message = ERROR_MESSAGE(), @state = ERROR_STATE() RAISERROR (@message, 11, @state) END CATCH or just BEGIN CATCH ROLLBACK END CATCH ?

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  • Emacs 23: Selection not highlighted

    - by phimuemue
    I installed Ubuntu 10.04, and with it came Emacs 23. If I want to select text in Emacs, that works perfectly fine except the fact that the region is not highlighted. However, this only happens, if I try to make a region using the keyboard. If I select something with the mouse, it is highlighted as usual. Does anybody know, why the region is not highlighted and how to fix that?

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  • How do I remove elements from a jQuery wrapped set

    - by Bungle
    I'm a little confused about which jQuery method and/or selectors to use when trying to select an element, and then remove certain descendant elements from the wrapped set. For example, given the following HTML: <div id="article"> <div id="inset"> <ul> <li>This is bullet point #1.</li> <li>This is bullet point #2.</li> <li>This is bullet point #3.</li> </ul> </div> <p>This is the first paragraph of the article</p> <p>This is the second paragraph of the article</p> <p>This is the third paragraph of the article</p> </div> I want to select the article: var $article = $('#article'); but then remove <div id="inset"></div> and its descendants from the wrapped set. I tried the following: var $article = $('#article').not('#inset'); but that didn't work, and in retrospect, I think I can see why. I also tried using remove() unsuccessfully. What would be the correct way to do this? Ultimately, I need to set this up in such a way that I can define a configuration array, such as: var selectors = [ { select: '#article', exclude: ['#inset'] } ]; where select defines a single element that contains text content, and exclude is an optional array that defines one or more selectors to disregard text content from. Given the final wrapped set with the excluded elements removed, I would like to be able to call jQuery's text() method to end up with the following text: This is the first paragraph of the article.This is the second paragraph of the article.This is the third paragraph of the article. The configuration array doesn't need to work exactly like that, but it should provide roughly equivalent configuration potential. Thanks for any help you can provide!

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  • Can I make this two LINQ queries into one query only?

    - by Holli
    From a List of builtAgents I need all items with OptimPriority == 1 and only 5 items with OptimPriority == 0. I do this with two seperate queries but I wonder if I could make this with only one query. IEnumerable<Agent> priorityAgents = from pri in builtAgents where pri.OptimPriority == 1 select pri; IEnumerable<Agent> otherAgents = (from oth in builtAgents where oth.OptimPriority == 0 select oth).Take(5);

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  • More efficient left join of big table

    - by Zeus
    Hello, I have the following (simplified) query select P.peopleID, P.peopleName, ED.DataNumber from peopleTable P left outer join ( select PE.peopleID, PE.DataNumber from formElements FE inner join peopleExtra PE on PE.ElementID = FE.FormElementID where FE.FormComponentID = 42 ) ED on ED.peopleID = P.peopleID Without the sub-query this procedure takes ~7 seconds, but with it, it takes about 3minutes. Given that table peopleExtra is rather large, is there a more efficient way to do that join (short of restructuring the DB) ?

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  • JSP to Bean to Java class Validation

    - by littlevahn
    I have a rather simple form in JSP that looks like this: <form action="response.jsp" method="POST"> <label>First Name:</label><input type="text" name="firstName" /><br> <label>Last Name:</label><input type="text" name="lastName" /><br> <label>Email:</label><input type="text" name="email" /><br> <label>Re-enter Email:</label><input type="text" name="emailRe" /><br> <label>Address:</label><input type="text" name="address" /><br> <label>Address 2:</label><input type="text" name="address2" /><br> <label>City:</label><input type="text" name="city" /><br> <label>Country:</label> <select name="country"> <option value="0">--Country--</option> <option value="1">United States</option> <option value="2">Canada</option> <option value="3">Mexico</option> </select><br> <label>Phone:</label><input type="text" name="phone" /><br> <label>Alt Phone:</label><input type="text" name="phoneAlt" /><br> <input type="submit" value="submit" /> </form> But when I try and access the value of the select box in my Java class I get null. Ive tried reading it in as a String and an Array of strings neither though seems to be grabbing the right value. The response.jsp looks like this: <%@ page language="java" %> <%@ page import="java.util.*" %> <%@page contentType="text/html" pageEncoding="UTF-8"%> <%! %> <jsp:useBean id="formHandler" class="validation.RegHandler" scope="request"> <jsp:setProperty name="formHandler" property="*" /> </jsp:useBean> <% if (formHandler.validate()) { %> <jsp:forward page="success.jsp"/> <% } else { %> <jsp:forward page="retryReg.jsp"/> <% } %> I already have Java script validation in place but I wanted to make sure I covered validation and checking for non-JS users. The RegHandler just uses the name field to refer to the value in the form. Any Idea how I could access the select box's value?

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  • .NET Extension Objects with XSLT -- how to iterate over a collection?

    - by Pandincus
    Help me, Stackoverflow! I have a simple .NET 3.5 console app that reads some data and sends emails. I'm representing the email format in an XSLT stylesheet so that we can easily change the wording of the email without needing to recompile the app. We're using Extension Objects to pass data to the XSLT when we apply the transformation: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl" xmlns:EmailNotification="ext:EmailNotification"> -- this way, we can have statements like: <p> Dear <xsl:value-of select="EmailNotification:get_FullName()" />: </p> The above works fine. I pass the object via code like this (some irrelevant code omitted for brevity): // purely an example structure public struct EmailNotification { public string FullName { get; set; } } // Somewhere in some method ... var notification = new Notification("John Smith"); // ... XsltArgumentList xslArgs = new XsltArgumentList(); xslArgs.AddExtensionObject("ext:EmailNotification", notification); // ... // The part where it breaks! (This is where we do the transformation) xslt.Transform(fakeXMLDocument.CreateNavigator(), xslArgs, XmlWriter.Create(transformedXMLString)); So, all of the above code works. However, I wanted to get a little fancy (always my downfall) and pass a collection, so that I could do something like this: <p>The following accounts need to be verified:</p> <xsl:for-each select="EmailNotification:get_SomeCollection()"> <ul> <li> <xsl:value-of select="@SomeAttribute" /> </li> </ul> <xsl:for-each> When I pass the collection in the extension object and attempt to transform, I get the following error: "Extension function parameters or return values which have Clr type 'String[]' are not supported." or List, or IEnumerable, or whatever I try to pass in. So, my questions are: How can I pass in a collection to my XSLT? What do I put for the xsl:value-of select="" inside the xsl:for-each ? Is what I am trying to do impossible?

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  • How to make a nested query with an Entity that doesn't really exist (many-to-many)

    - by Calou
    Hi everyone, I'm new with Doctrine2 so my question can be easy to answer (I hope so). First of all, here the SQL query that I'd want : SELECT * FROM Document WHERE id NOT IN (SELECT document_id FROM Documents_Folders) Pretty simple isn't it ? The porblem is that my table 'Documents_Folders' is not an entity. In fact, it was create because I have a many-to-many relation between my entities 'Document' and 'Folder'. I tried several queries, but none worked. Thanks.

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  • SQL Server: How to get a subitem of sp_helplanguage ?

    - by Quandary
    Question: I can get the SQL Server database language by querying: SELECT @@language And I can get further info via EXEC sp_helplanguage How can I query for a column of sp_helplanguage where name= @@language I do SELECT * FROM sp_helplanguage WHERE name='DEUTSCH' but that obviously doesn't work. What's the correct way to query it ?

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  • T-SQL generated from LINQ to SQL is missing a where clause

    - by Jimmy W
    I have extended some functionality to a DataContext object (called "CodeLookupAccessDataContext") such that the object exposes some methods to return results of LINQ to SQL queries. Here are the methods I have defined: public List<CompositeSIDMap> lookupCompositeSIDMap(int regionId, int marketId) { var sidGroupId = CompositeSIDGroupMaps.Where(x => x.RegionID.Equals(regionId) && x.MarketID.Equals(marketId)) .Select(x => x.CompositeSIDGroup); IEnumerator<int> sidGroupIdEnum = sidGroupId.GetEnumerator(); if (sidGroupIdEnum.MoveNext()) return lookupCodeInfo<CompositeSIDMap, CompositeSIDMap>(x => x.CompositeSIDGroup.Equals(sidGroupIdEnum.Current), x => x); else return null; } private List<TResult> lookupCodeInfo<T, TResult>(Func<T, bool> compLambda, Func<T, TResult> selectLambda) where T : class { System.Data.Linq.Table<T> dataTable = this.GetTable<T>(); var codeQueryResult = dataTable.Where(compLambda) .Select(selectLambda); List<TResult> codeList = new List<TResult>(); foreach (TResult row in codeQueryResult) codeList.Add(row); return codeList; } CompositeSIDGroupMap and CompositeSIDMap are both tables in our database that are represented as objects in my DataContext object. I wrote the following code to call these methods and display the T-SQL generated after calling these methods: using (CodeLookupAccessDataContext codeLookup = new CodeLookupAccessDataContext()) { codeLookup.Log = Console.Out; List<CompositeSIDMap> compList = codeLookup.lookupCompositeSIDMap(5, 3); } I got the following results in my log after invoking this code: SELECT [t0].[CompositeSIDGroup] FROM [dbo].[CompositeSIDGroupMap] AS [t0] WHERE ([t0].[RegionID] = @p0) AND ([t0].[MarketID] = @p1) -- @p0: Input Int (Size = 0; Prec = 0; Scale = 0) [5] -- @p1: Input Int (Size = 0; Prec = 0; Scale = 0) [3] -- Context: SqlProvider(Sql2005) Model: AttributedMetaModel Build: 3.5.30729.1 SELECT [t0].[PK_CSM], [t0].[CompositeSIDGroup], [t0].[InputSID], [t0].[TargetSID], [t0].[StartOffset], [t0].[EndOffset], [t0].[Scale] FROM [dbo].[CompositeSIDMap] AS [t0] -- Context: SqlProvider(Sql2005) Model: AttributedMetaModel Build: 3.5.30729.1 The first T-SQL statement contains a where clause as specified and returns one column as expected. However, the second statement is missing a where clause and returns all columns, even though I did specify which rows I wanted to view and which columns were of interest. Why is the second T-SQL statement generated the way it is, and what should I do to ensure that I filter out the data according to specifications via the T-SQL? Also note that I would prefer to keep lookupCodeInfo() and especially am interested in keeping it enabled to accept lambda functions for specifying which rows/columns to return.

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  • how do i get the sum of the 4th column

    - by every_answer_gets_a_point
    this statement will generate a 4 column table: SELECT shipped.badguy AS badguy, shipped.sdate AS LineDate, 'Delivery' AS Legend, -price*quantity AS amount FROM product JOIN shipped ON (product.id = shipped.product) UNION SELECT receipt.badguy, receipt.rdate,notes, amount FROM how do i get the total sum of the 4th of column of what the above generates?

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  • How do I use "Into" LINQ expression in VB.NET?

    - by SLC
    I'm converting from C# this LINQ expression. However, it does not seem to work. C# return (from w in fishSticks group w by w.FishQty into g orderby g.Key descending select g).First().First(); VB Return (From w In fishSticks Group w By w.FishQty Into g() Order By g.Key Descending Select g).First().First() Visual Studio turns g into g() itself and then gives me this error: Definition of method 'g' is not accessible in this context. Any ideas?

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  • Define keys in temporary table creation

    - by imperium2335
    How do I define the keys for a temporary table that is being created from a SELECT statement? I have: CREATE temporary TABLE _temp_unique_parts_trading engine=memory AS (SELECT parts_trading.enquiryref, sellingcurrency, jobs.id AS jobID FROM parts_trading, jobs WHERE jobs.enquiryref = parts_trading.enquiryref GROUP BY parts_trading.enquiryref) But where do I define the keys?

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  • How can i get the seed value of an identity column in MySql

    - by mmcdonald
    To get the seed and step values of an identity column in sql server i can use this syntax SELECT ColumnName = name, Seed = seed_value, Step = increment_value FROM sys.identity_columns So far in MySql i have found that if i use this syntax SELECT * FROM INFORMATION_SCHEMA.TABLES WHERE auto_increment IS NOT NULL I can at least find out which columns are an identity... The question being how can i get the SEED and STEP values of the identity column from the MySQL Schema.

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  • How can you access two identically-named columns in a MySQL LEFT JOIN query?

    - by George Edison
    I have two tables. table_x: id INT(11) tag INT(11) table_tags: id INT(11) name VARCHAR(255) Then I use PHP to perform the following query: SELECT * FROM table_x LEFT JOIN table_tags ON table_x.tag = table_tags.id The only problem is: how do I access table_x.id and table_tags.id in the results? Here is the PHP code: $query = "SELECT * FROM table_x LEFT JOIN table_tags ON table_x.tag = table_tags.id"; $results = mysql_query($query); while($row = mysql_fetch_array($results)) { // how do I now access table_x.id and table_tags.id ??? }

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