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  • Change master table PK and update related table FK (changing PK from Autoincrement to UUID on Mysql)

    - by eleonzx
    I have two related tables: Groups and Clients. Clients belongs to Groups so I have a foreign key "group_id" that references the group a client belongs to. I'm changing the Group id from an autoincrement to a UUID. So what I need is to generate a UUID for each Group and update the Clients table at once to reflect the changes and keep the records related. Is there a way to do this with multiple-table update on MySQL? Adding tables definitions for clarification. CREATE TABLE `groups` ( `id` char(36) NOT NULL, `name` varchar(255) DEFAULT NULL, `created` datetime DEFAULT NULL, `modified` datetime DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8$$ CREATE TABLE `clients` ( `id` char(36) NOT NULL, `name` varchar(255) NOT NULL, `group_id` char(36) DEFAULT NULL, `active` tinyint(1) DEFAULT '1' PRIMARY KEY (`id`), KEY `fkgp` (`group_id`), CONSTRAINT `fkgp` FOREIGN KEY (`group_id`) REFERENCES `groups` (`id`) ON DELETE NO ACTION ON UPDATE CASCADE ) ENGINE=InnoDB DEFAULT CHARSET=utf8$$

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  • Way to check for foreign key references before deleting in MySQL?

    - by Chad Johnson
    I'm working with a content management system, and users are prompted with a confirmation screen before deleting records. Some records are foreign key referenced in other tables, and therefore they cannot be deleted. I would like to display a message beside a given record if it has foreign key references. To know whether I should display the message for a record, I could just query the referencing table and see if there are references. But the problem is, there are about a dozen tables with records potentially referencing this record, and a lookup could take a "long" time. Is there an easy way to tell whether the record is delete-ready (ie. has no foreign key references)?

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  • PHP IF statement not taking variable into account!

    - by Jess
    I have a tabled view in a while loop, where a user can view information on books. For example, book ISBN, book name, read status... Basically, when the user sets their 'readstatus' to 'complete' I want that specific table row to become grey! The logic is very straight forward, however I can't get my IF statement to recognise this: $readstatus = $_GET['readstatus']; if ($readstatus == 'complete') { echo '<tr class="completed">'; } else if ($readstatus != 'complete') { echo '<tr class="reading">'; } I'm obviously doing something wrong here, but all I need is the CSS class of the table row to change if the value of 'readstatus' = 'complete', if not, then output the default CSS table row color ('reading') Should I be putting $result as the variable or something? I have this coming just before my nested IF statement: $result = mysql_query($sql, $connection) or die ("Couldn't perform query $sql <br />".mysql_error()); while($row = mysql_fetch_array($result)) { ?>

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  • Best way to order by columns in relationships?

    - by Timmy
    im using sqlalchemy, and i have a few polymorphic tables, and i want to sort by a column in one of the relationship. i have tables a,b,c,d, with relationship a to b, b to c, c to d. a to b is one-to-many b to c and c to d are one-to-one, but polymorphic. given an item in table a, i will have a list of items b, c, d (all one to one). how do i use sqlalchemy to sort them by a column in table d?

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  • Visual Studio 2010 deploys views too late in deploy process

    - by Markus
    I have a database project in my VS2010 solution. I recently changed a view and and changed a number of functions to use this view instead of going directly against a table. But now when I deploy I get errors on most of these functions because the column asked for does not exists in the view yet. The update of the view happends later than the update of UDF's. Is there any way to change this behaviour? Wouldn't the best thing be if the deploy script updated in this order: tables, views, SP and UDF. It seems like tables is updated first, but the views are just thrown in somewhere in the middle of the deploy script.

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  • Jquery Mobile splitview like Android Gmail app [closed]

    - by JDev
    Since I don't know much about jquery mobile, CSS, i don't know what we call this. I want to create a splitview like Android gmail app (image attached). but i am not sure how to create arrow cut on the active (clicked) listview only (like shown in the image) and other listview are normal. Can someone guide me how to approach it. Sorry for confusing everyone. Updated the image with black circle. the nice inward arrow (shown under black circle) is what i am looking for. As you see this inward arrow will appear only for the active left side listview only and others will have a straight line, also left side has a distinct appearance. I want to know the approach for these using jquery mobile, jquery, css etc.

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  • jQuery Mobile button js control

    - by David
    I have a button that is not triggering event in jQuery mobile. It was working but I had to remove the css. It was screwing up my all my ul lists. Any help would greatly appreciated Here is the code for the button at the bottom of the form : <div class="next"> <a class="btnNext">Next &gt;&gt;</a> </div> Which is supposed to do this on a separate js file: init: function(){ $('.btnNext').onclick(function(){ if ($('input[type=radio]:checked:visible').length == 0) { return false; } $(this).parents('.questionContainer').fadeOut(500, function(){ Here is the css I removed: a { border: 1px solid #000; padding: 2px 5px; font-weight: bold; font-size: 10px; background: #FFF; cursor: pointer; } a:hover { background: none; }

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  • jquery change element to element

    - by Isis
    Hello <div class="leftlink" id="mcontacts"> <img src="test.gif" class="arrowred"/> <a href="/contacts/" class="u">????????</a> </div> if(window.location == 'http://my.site.com/contacts/') { $('.menuwelcome').css('display', 'block'); $('.leftlink').find('????????').css('font-weight', 'bold'); $('#mcontacts').find('a').html('<b>????????</b>').remove(); } How do remove tag "a" html, and change his for '<b>????????</b>' ? =) Than you, sorry for bad english

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  • Get information from a higher class?

    - by Clint Davis
    I don't know really how to word the question so please bear with me... I have 3 classes: Server, Database, and Table. Each class has a "Name" property. How I want it to work is that each server can have multiple databases and each database can have multiple tables. So in the Server class I have this property. Private _databases As List(Of Database) Public Property Databases() As List(Of Database) Get Return _databases End Get Set(ByVal value As List(Of Database)) _databases = value End Set End Property And I have something similar in the Database class for the tables. This works fine now because I can do something like this to get all the databases in the server. For Each db In s.Databases 's being the server object Debug.Print(db.Name) Next I would like to expand these classes. I want the server class to handle all the connection information and I would like the other classes to use the server class's connection information in them. For example, I setup a server class and set the connection string to the server. Then I want the database class to use serverclass.connectionstring property to connect to the server and get a list of all the databases. But I want to keep that code in the database class. How can I do this? I've attached some code of what I want to do. Public Class Server Private _name As String Public Property Name() As String Get Return _name End Get Set(ByVal value As String) _name = value End Set End Property Private _databases As List(Of Database) Public Property Databases() As List(Of Database) Get Return _databases End Get Set(ByVal value As List(Of Database)) _databases = value End Set End Property End Class '-----New class Public Class Database Private _name As String Public Property Name() As String Get Return _name End Get Set(ByVal value As String) _name = value End Set End Property Private _tables As List(Of Table) Public Property Tables() As List(Of Table) Get Return _tables End Get Set(ByVal value As List(Of Table)) _tables = value End Set End Property 'This is where I need help! Private Sub LoadTables () dim connectionstring as string = server.connectionstring 'Possible? 'Do database stuff End Class Thanks for reading!

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  • What table is affected by delete when form based on query?

    - by webworm
    In MS Access 2003 I have a form whose record source is equal to a query that involves an INNER JOIN. The join is between a location table and a container table. Containers are objects that are stored in specific locations each location and container are specified by ID values. SELECT DISTINCTROW Container.Container_ID, Location.Location_ID FROM Location INNER JOIN Container ON Location.[Location_ID] = Container.[Location_ID] What I am trying to figure out is this …. When I delete a record (using the form navigation controls) in the form based on the above query which tables are affected? Are records in the Container and Location tables deleted or is it just in the location table? Thanks!

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  • Are these 2 sql queries equivalent in all respects (e.g. estimated and actual execution plan)?

    - by Xerion
    Are query 1) == 2) in terms of estimated query plan AND actual plan? (can statistics affect the actual plan here, ever?) declare @cat int -- input param from prc ... 1) select * from A as a join B as b on b.id = a.id on b.cat = @cat join C as c on c.fid = b.fid on c.cat = @cat where a.cat = @cat 2) select * from A as a join B as b on b.id = a.id on b.cat = a.cat join C as c on c.fid = b.fid on c.cat = b.cat where a.cat = @cat It seems to me that these should logically be equivalent and the execution plan should always be the same regardless of actual difference in tables. And adding more conditions either in join, or where, or add more tables to join shouldn't change this. Are there cases this is not true?

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  • SQLiteOpenHelper problem

    - by Harsha M V
    I have created SQLiteOpenHelper class to help me open write the database. but i am not able to invoke it from the main.java activity I have created an Class which extends the Database Helper which is stored at /Messaging/src/com/v3/messaging/DatabaseHelper.java Code: http://pastebin.com/Z5qp32xu now i have this class called Main.java which will be the first activity on the launch of the application. But how can i make the DatabaseHelper.java run just to create the database but still be at the Main.java file. The database should be created with the tables only when the db or the tables dont exist. Main.java code: http://pastebin.com/LVFVuhA0 Now when i run the program. the database is not being created :( I am trying to learn Android. So please excuse me if i forgot to tell something.

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  • Export XML with only one MySQL request ?

    - by mere-teresa
    I want to export in XML format some data from 7 tables (MySQL database), and then I want to import in another database. And I have a update or insert rule for data. I already have a SQL query retrieving all data, with JOINs on my 7 tables. But...when I try to put data in XML format, I reach a limit. My PHP loop can catch each row, but I would like to benefit from hierachical structure of the XML, and all I have are rows with the same data repeated. It is better to query once and to construct the XML tree in PHP or to query each time I want access to a lower level ?

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  • Customers and suppliers database design issue

    - by hectorsq
    I am developing a web application in which I will have customers and suppliers. Initially I thought on using a Customers table and a Suppliers table. Then when I was thinking on bank transactions, I noticed that each transaction needs to refer to a customer or a supplier, so I thought on using a single table named Business in which I will save both customers and suppliers. If I use Customers and Suppliers tables when I want to list the bank transactions I will have to search in both tables to get the company name. If I use a Businesses table I will have to use a business type column, and have the union of possible fields for all businesses types. Any suggestions on the design?

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  • Will a source-removal sort always return a maximal cycle?

    - by Jason Baker
    I wrote a source-removal algorithm to sort some dependencies between tables in our database, and it turns out we have a cycle. For simplicity, let's say we have tables A, B, C, and D. The edges are like this: (A, B) (B, A) (B, C) (C, D) (D, A) As you can see, there are two cycles here. One is between A and B and another is between all four of them. Will this type of sort always choke on the largest cycle? Or is that not necessarily the case?

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  • Can somebody tell me why this Jquery tooltip is not showing up?

    - by alex
    <link rel="stylesheet" type="text/css" href="jquery-tooltip/jquery.tooltip.css"/> <script type="text/javascript" src="jquery-tooltip/jquery.tooltip.js"></script> <div id="baby" title="My tootip">The text</div> <script type="text/javascript"> $(function(){ $('#baby').tooltip({ track: true, delay: 0, showURL: false, showBody: " - ", extraClass: "pretty", fixPNG: true, opacity: 0.95, left: -120 }); }); </script> The files are found, and they are not 404.

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  • SQL Server 2008 - Get Latest Record from Joined Table

    - by user336786
    Hello, I have a SQL Server 2008 database. This database has two tables called Customer and Order. These tables are defined as follows: Customer -------- ID, First Name, Last Name Order ----- ID, CustomerID, Date, Description I am trying to write a query that returns all of the customers in my database. If the user has placed at least one order, I want to return the information associated with the most recent order placed. Currently, I have the following: SELECT * FROM Customer c LEFT OUTER JOIN Order o ON c.[ID]=o.[CustomerID] As you can imagine, this will return all of the orders associated with a customer. In reality though, I only want the most recent one. How do I do this in SQL? Thank you!

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  • MySQL AND alternative for eatch table in a join

    - by Scott
    I have a simple join in a query however I need to have a condition on both of the tables "confirmed='yes'" but if one of the tables doesn't have any that match the query returns with no rows. Database: .----------parties----------. | id - party_id - confirmed | |---------------------------| | 1 1 yes | | 1 2 no | | 1 3 no | +---------------------------+ .-----------events----------. | id - event_id - confirmed | |---------------------------| | 1 1 no | +---------------------------+ Query: SELECT p.party_id, e.event_id FROM parties p LEFT JOIN events e ON p.id=e.id WHERE p.id = '1' AND p.party_id IN (1,2,3) AND e.event_id IN (1) AND p.confirmed='yes' AND e.confirmed='yes' It returns nothing but I want it to return party_id 1 with a empty event_id. I hope this make sense and I not missing anything, Thanks for your help!

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  • mysql select multiple rows in join

    - by julio
    Hi-- I have a simple mySQL problem-- I have two tables, one is a user's table, and one is a photos table (each user can upload multiple photos). I'd like to write a query to join these tables, so I can pull all photos associated with a user (up to a certain limit). However, when I do something obvious like this: SELECT *.a, *.b FROM user_table a JOIN photos_table b ON a.id = b.userid it returns a.id, a.name, a.email, a.address, b.id, b.userid, b.photo_title, b.location but it only returns a single photo. Is there a way to return something like: a.id, a.name, a.email, a.address, b.id, b.userid, b.photo_title, b.location, b.id2, b.photo_title2, b.location2 etc. . . for a given LIMIT of photos? Thanks for any ideas.

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  • How to properly design a simple favorites and blocked table?

    - by Nils Riedemann
    Hey, i am currently writing a webapp in rails where users can mark items as favorites and also block them. I came up two ways and wondered which one is more common/better way. 1. Separate join tables Would it be wise to have 2 tables for this? Like: users_favorites - user_id - item_id users_blocked - user_id - item_id 2. single table users_marks (or so) - users_id - item_id - type (["fav", "blk"]) Both ways seem to have advantages. Which one would you use and why?

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  • looking for RTF template system with simple DSL

    - by 01
    Is there any framework that fills up rtf document with data? The idea is to make business people/testers change the document in MsWord and than generate reports from that. The problem is with tables, Id need to create some special DSL for handling tables and showing hidding text/page parts. Id rather not do that and use some existing solution. I tried to search for something, but I only found frameworks that can produce rtf output from xml input and i want to use rtf as input and output.

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  • jQuery UI 1.8.13 sudden error

    - by user837306
    We have been using Jquery from this link http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.13/jquery-ui.min.js for drag and drop. Suddenly we notice it is not working now and there is no code change done our side. We notice the error is pointing to these line and error is TypeError: a.curCSS is not a function? What will be solution to this problem? e&&e.call(i)},g)}):this._focus.apply(this,arguments)},scrollParent:function(){var g;g=a.browser.msie&&/(static|relative)/.test(this.css("position"))||/absolute/.test(this.css("position"))?this.parents().filter

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  • MySQL: Query to obtain recipes using all given ingredients.

    - by John_A
    hi I have the following simplified tables: CREATE TABLE recipe(id int, name varchar(25)); CREATE TABLE ingredient(name varchar(25)); CREATE TABLE uses_ingredient(recipe_id int, name varchar(25)); I want to make a query that returns all id's of recipes that contain both Chicken and Cream. I have tried SELECT recipe_id FROM uses_ingredient INNER JOIN (SELECT * FROM ingredient WHERE name="Chicken" OR name="Cream") USING (name) GROUP BY recipe_id HAVING COUNT(recipe_id) >= (SELECT COUNT(*) FROM theme); which gives me :"ERROR 1248 (42000): Every derived table must have its own alias" and is probably wrong too. Next I tried SELECT recipe_id FROM (SELECT * FROM ingredient WHERE name="Chicken" OR name="Cream") AS t INNER JOIN uses_ingredient USING (name) GROUP BY recipe_id HAVING COUNT(recipe_id)>= (SELECT COUNT(*) FROM t); which gives "ERROR 1146 (42S02): Table 'recipedb.t' doesn't exist" I want to avoid creating temporary tables including using ENGINE=MEMORY.

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  • need help in positioning

    - by teki
    i am using "beassistance validation" for my form and using tooltip plugin and it work fine except that positioning. please have a look at this link and i upload my form to get an idea what i am talking about. what i want is: if my validation fails i want to display the message after the tooltip icon, but its displaying the message before the tooltip icon. please see here here is the .css i am using: validation .css #aspnetForm { width: 670px; } #aspnetForm label.error { margin-left: 10px; width: auto; display: inline; } form.cmxform { width: 50em; } em.error { background: url("Images/unchecked.gif") no-repeat 0px 0px; padding-left: 16px; } em.success { background: url("Images/checked.gif") no-repeat 0px 0px; padding-left: 16px; } form.cmxform label.error { margin-left: auto; width: 250px; } #aspnetForm label.error { background: url("Images/unchecked.gif") no-repeat 0px 0px; padding-left: 16px; padding-bottom: 2px; font-weight: bold; color: #EA5200; } #aspnetForm label.checked { background: url("Images/checked.gif") no-repeat 0px 0px; } em.error { color: black; } #warning { display: none; } <asp:Label runat="server" ID='Label8' >Start Date:</asp:Label> <asp:TextBox ID="txtStartDate" runat='server' ></asp:TextBox> <a style="cursor: hand" class="tooltip" title="Select the starting date of a visit, example 05/05/2010 (MM/DD/YYYY)!"> <img alt="" src="Scripts/JQuery/Tooltip/icon_tooltip.gif" style="width: 11px; height: 11px" /></a> <p> </p> <asp:Label runat="server" ID='Label9' >End Date:</asp:Label> <asp:TextBox ID="txtEndDate" runat='server' ></asp:TextBox> <a style="cursor: hand" class="tooltip" title="Select the end date of a visit, example 05/06/2010 (MM/DD/YYYY)!"> <img alt="" src="Scripts/JQuery/Tooltip/icon_tooltip.gif" style="width: 11px; height: 11px" /></a> tooltip.css #tooltip{ position:absolute; border:1px solid #333; background:#f7f5d1; padding:2px 5px; color:#333; display:none; }

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