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  • How do I display each view once as they are loaded, in Android?

    - by Joe Masilotti
    I have an Android application that works off of a smaller database, around 300 entries. To view the database, I have created a custom view that contains individual rows of data. Then I query the database, and add each line to a newly created custom view. The problem is that it takes a little white for all of this to be created/loaded, so when you open the application, it sits for a few seconds. How can I load one line of data, then display it, then the next, append it, etc.?

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  • Problems with 'while' loop and 'for' loop when reading through file

    - by David Beckham
    I wasted plenty of hours trying to figure out the problem but no luck. Tried asking the TA at my school, but he was useless. I am a beginner and I know there are a lot of mistakes in it, so it would be great if I can get some detail explanation as well. Anyways, basically what I am trying to do with the following function is: Use while loop to check and see if random_string is in TEXT, if not return NoneType if yes, then use a for loop to read lines from that TEXT and put it in list, l1. then, write an if statement to see if random_string is in l1. if it is, then do some calculations. else read the next line Finally, return the calculations as a whole. TEXT = open('randomfile.txt') def random (TEXT, random_string): while random_string in TEXT: for lines in TEXT: l1=TEXT.readline().rsplit() if random_string in l1: ''' do some calculations ''' else: TEXT.readline() #read next line??? return #calculations return None

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  • Permission error while trying to access an (server) program started by a Java program.

    - by Zardoz
    I am starting a server application (normally to be started from the Unix command line) by using Runtime.getRuntime().exec("path/mmserver"). My problem is now that as long as my Java program, which started that server runs, the server is correctly accessible (from command line and other programs). But when my Java program exits the sever is not accessible anymore (the process of the server is still running). I just get such a error message when trying to access the server: "Error: permission_error(flush_output(user_output),write,stream,user_output,errno(32))". The server is a blackbox for me. I am just looking for other ways to start a new process. And maybe someone has a hint why I get that permission error (even if one doesn't know what that server exactly is ... you rather won't know it).

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  • Saving substrings using Regular Expressions

    - by user362971
    I'm new to regular expressions in Java (or any language, for that matter) and I'm wanting to do a find using them. The tricky part that I don't understand how to do is replace something inside the string that matches. For example, if the line I'm looking for is Person item6 [can {item thing [wrap]}] I'm able to write a regex that finds that line, but finding what the word "thing" is (as it may differ among different lines) is my problem. I may want to either replace that word with something else or save it in a variable for later. Is there any easy way to do this using Java's regex engine?

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  • WAMP & WordPress - Having issues after installing plugins

    - by user1786083
    I am using WAMP (Apache 2.2.17, PHP 5.4.3) & WordPress 3.4.2. Everything was fine until I started to add and activate plugins now I get different sort of errors on the front-end/Admin e.g. "Notice: Undefined index: plugin_version in C:\repo\wpdev\wp-content\plugins\wp-rss-multi-importer\inc\upgrade.php on line 11" And "Warning: Illegal string offset 'feedslug' in C:\repo\wpdev\wp-content\plugins\wp-rss-multi-importer\inc\rss_feed.php on line 21." IF I deactivate the plugins everything seems to be fine. I have installed WAMP & WP 2X. The plugins work fine on MediaTemple. The error messages vary depending on the plugins. Search Google and came up empty. Thanks in advance.

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  • Is it more secure to run a desktop app in a applet?

    - by Tom Brito
    Fist of all, when I say "run a desktop app in a applet" I mean do a Applet application that runs off-line, instead of a Desktop application that runs inside a JFrame. The little I know about applets (and maybe something I say is wrong, please correct me) is that applets have all permitions not granted by default. Also, the applets run inside a Sandbox, that does not allow information in or out without explicity permition. So, if I am focused on security in my application, its best to run it inside an applet (off-line, for a desktop application) then inside a JFrame. Is it right?

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  • Error when creating database in MySQL using Netbeans 6.8

    - by nix
    I am trying to create a database using MySQL statements in NetBeans 6.8. However, I keep getting Error code 1064. I don't know what the problem is really since the same statements work in NetBeans 6.0. Here is the error: Error code 1064, SQL state 42000: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '; /*!40000 ALTER TABLE students ENABLE KEYS */; -- -- Definition of table `w' at line 1016 Line 46, column 1

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  • GitHub: searching through older versions of files

    - by normski
    I know that using GitHub I can search through all the current versions of my files in a repo. However, I would also like to search through the older versions of my repo files. For example, say, I used to have a function called get_info() in my code, but deleted it several versions ago, is it possible to search for get_info and find the code. If it is not possible using GitHub, is it possible from the git command line? EDIT Thanks to @Mark Longair for showing how this can be done from the git command line. If it's not possible in GitHub it would be a great feature to have.

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  • joomla's hwdvideoshare module help

    - by Sam
    hi! i using hwdvideoshare module in joomla and i can't use the Method 1 for Direct Video Conversions. it requires the following things to be done: * The exec() function need to be enabled in PHP. * safe_mode must be set to Off. You can check that at Joomla Help -> System Info -> PHP Information) * php-cli (Command Line Interface to PHP) must be installed in the server and its path set in Server Settings * safe_mode must be set to Off for php-cli. You can check that executing php -i | grep safe_mode from the command line i've checked the first two settings. i don't know whether php-cli is enabled or not..i'm using php5..how do i enable it, without messing with other php packages?

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  • Add button to a layout programmatically

    - by mmmbaileys
    I'm having trouble adding a button to a layout that I've created in XML. Here's what I want to achieve: //some class else { startActivity(new Intent(StatisticsScreen.this, ScreenTemperature.class)); } //// //ScreenTemperatureClass @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); //this is where I call another class that //displays a nice graph setContentView(new GraphTemperature(getApplicationContext())); } I want to add a Button to this new screen so that it'll appear below the graph. I've tried creating a LinearLayout view, then create a Button and add it to this view but I just get NullPointerExceptions.. Any help would be appreciated. Thanks EDIT#1 Here's what I've tried using that created a NullPointerException and 'force close': Button buybutton; LinearLayout layout; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(new GraphTemperature(getApplicationContext())); layout = (LinearLayout) findViewById(R.id.statsviewlayout); Button buyButton = new Button(this); buyButton.setText(R.string.button_back); buyButton.setLayoutParams(new LayoutParams( ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT)); layout.addView(buyButton); } And here's the logcat error: ERROR/AndroidRuntime(293): java.lang.RuntimeException: Unable to start activity ComponentInfo{com.weatherapp/com.weatherapp.ScreenTemperature}: java.lang.NullPointerException ERROR/AndroidRuntime(293): at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2663) ERROR/AndroidRuntime(293): at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2679) ERROR/AndroidRuntime(293): at android.app.ActivityThread.access$2300(ActivityThread.java:125) ERROR/AndroidRuntime(293): at android.app.ActivityThread$H.handleMessage(ActivityThread.java:2033) theres abviously more lines to do with this error in logcat, not sure if you want it? EDIT#2 So i tried bhups method: @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); GraphTemperature GT = new GraphTemperature(getApplicationContext()); layout = (LinearLayout) findViewById(R.id.statsviewlayout); Button buyButton = new Button(this); buyButton.setText(R.string.button_back); buyButton.setLayoutParams(new LayoutParams( ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT)); layout.addView(GT); // line 27 layout.addView(buyButton); setContentView(layout); } This method produced the same logcat error as above, NullPointerException, indicating it was something to do with line no. 27 which is the layout.addView line of code. Any ideas? Thanks again

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  • C++ STL: Trouble with string iterators

    - by Rosarch
    I'm making a simple command line Hangman game. void Hangman::printStatus() { cout << "Lives remaining: " << livesRemaining << endl; cout << getFormattedAnswer() << endl; } string Hangman::getFormattedAnswer() { return getFormattedAnswerFrom(correctAnswer.begin(), correctAnswer.end()); } string Hangman::getFormattedAnswerFrom(string::const_iterator begin, string::const_iterator end) { return begin == end? "" : displayChar(*begin) + getFormattedAnswerFrom(++begin, end); } char Hangman::displayChar(const char c) { return c; } (Eventually, I'll change this so displayChar() displays a - or a character if the user has guessed it, but for simplicity now I'm just returning everything.) When I build and run this from VS 2010, I get a popup box: Debug Assertion Failed! xstring Line: 78 Expression: string iterator not dereferenceable What am I doing wrong?

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  • Java PreparedStatement Throws MySQLSyntaxErrorException

    - by sqlBugs
    I have the following Java code: String query = "Select 1 from myTable where name = ? and age = ?"; PreparedStatement stmt = conn.prepareStatement(query); stmt.setString(1, name); stmt.setInt(2, age); ResultSet rs = stmt.executeQuery(); Whenever I run the above code, it throws an exception on line 2 (where the PreparedStatement is declared): Error 0221202: SQLException = com.mysql.jdbc.exceptions.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '? AND age = ?' at line 1 Does anyone have any suggestions about what I am doing wrong? Thanks!

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  • what is wrong with my create table SQL?

    - by George2
    Hello everyone, I am using SQL Server 2008 management studio to execute the following SQL statements, and here is the related error message from SQL Server management studio. Any ideas what is wrong? SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO Create TABLE [dbo].[BatchStatus]( [BatchID] [uniqueidentifier] NOT NULL CONSTRAINT [PK_BatchStatus_ID], [BatchStatus] [int] NULL, CONSTRAINT [PK_BatchStatus_ID] PRIMARY KEY CLUSTERED ( [BatchID] ASC )WITH (IGNORE_DUP_KEY = OFF) ON [PRIMARY] ) ON [PRIMARY] GO Msg 102, Level 15, State 1, Line 3 Incorrect syntax near ','. Msg 319, Level 15, State 1, Line 8 Incorrect syntax near the keyword 'with'. If this statement is a common table expression, an xmlnamespaces clause or a change tracking context clause, the previous statement must be terminated with a semicolon. thanks in advance, George

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  • What does it mean when a Perl method returns a "hashref"?

    - by Uri
    I'm trying to decrypt a Perl code which I'm not familiar with, somehow related to HashRef. I'm using Amazon::S3, but my question is a general Perl question. See the code below: use Amazon::S3; my $s3 = Amazon::S3->new( ... ); my $response = $s3->buckets; Documentation (here) sais, about s3-buckets: Returns undef on error, else HASHREF of results The following line is working for me, but I don't understand why: for $b in ( @ { $response->{buckets} } ) { print "bucket: " . $b->bucket . "\n"; } I'm Puzzled by each operator on the first line. What type exactly are $response, $respone->{bucket}. Looks like the expression within the for is an array, but I don't understand this syntax: @{ ... }?

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  • Export CSV from Mysql

    - by ss888
    Hi, I'm having a bit of trouble exporting a csv file that is created from one of my mysql tables using php. The code I'm using prints the correct data, but I can't see how to download this data in a csv file, providing a download link to the created file. I thought the browser was supposed to automatically provide the file for download, but it doesn't. (Could it be because the below code is called using ajax?) Any help greatly appreciated - code below, S. include('../config/config.php'); //db connection settings $query = "SELECT * FROM isregistered"; $export = mysql_query ($query ) or die ( "Sql error : " . mysql_error( ) ); $fields = mysql_num_fields ( $export ); for ( $i = 0; $i < $fields; $i++ ) { $header .= mysql_field_name( $export , $i ) . "\t"; } while( $row = mysql_fetch_row( $export ) ) { $line = ''; foreach( $row as $value ) { if ( ( !isset( $value ) ) || ( $value == "" ) ) { $value = "\t"; } else { $value = str_replace( '"' , '""' , $value ); $value = '"' . $value . '"' . "\t"; } $line .= $value; } $data .= trim( $line ) . "\n"; } $data = str_replace( "\r" , "" , $data ); if ( $data == "" ) { $data = "\n(0) Records Found!\n"; } //header("Content-type: application/octet-stream"); //have tried all of these at sometime //header("Content-type: text/x-csv"); header("Content-type: text/csv"); //header("Content-type: application/csv"); header("Content-Disposition: attachment; filename=export.csv"); //header("Content-Disposition: attachment; filename=export.xls"); header("Pragma: no-cache"); header("Expires: 0"); echo '<a href="">Download Exported Data</a>'; //want my link to go in here... print "$header\n$data";

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  • Last element not getting insert in Tree

    - by rdk1992
    So I was asked to make a Binary Tree in Haskell taking as input a list of Integers. Below is my code. My problem is that the last element of the list is not getting inserted in the Tree. For example [1,2,3,4] it only inserts to the tree until "3" and 4 is not inserted in the Tree. data ArbolBinario a = Node a (ArbolBinario a) (ArbolBinario a) | EmptyNode deriving(Show) insert(x) EmptyNode= insert(tail x) (Node (head x) EmptyNode EmptyNode) insert(x) (Node e izq der) |x == [] = EmptyNode --I added this line to fix the Prelude.Head Empty List error, after I added this line the last element started to be ignored and not inserted in the tree |head x == e = (Node e izq der) |head x < e = (Node e (insert x izq) der) |head x > e = (Node e izq (insert x der)) Any ideas on whats going on here? Help is much appreciated

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  • Faster s3 bucket duplication

    - by Sean McCleary
    I have been trying to find a better command line tool for duplicating buckets than s3cmd. s3cmd can duplicate buckets without having to download and upload each file. The command I normally run to duplicate buckets using s3cmd is: s3cmd cp -r --acl-public s3://bucket1 s3://bucket2 This works, but it is very slow as copies each file via the API one at a time. If s3cmd could run in parallel mode, I'd be very happy. Are there other options available as a command line tools or code that people use to duplicate buckets that are faster than s3cmd?

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  • How to identify/handle text file newlines in Java?

    - by rafrafUk
    Hi Everyone! I get files in different formats coming from different systems that I need to import into our database. Part of the import process it to check the line length to make sure the format is correct. We seem to be having issues with files coming from UNIX systems where one character is added. I suspect this is due to the return carriage being encoded differently on UNIX and windows platform. Is there a way to detect on which file system a file was created, other than checking the last character on the line? Or maybe a way of reading the files as text and not binary which I suspect is the issue? Thanks Guys !

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  • closing sockets on linux and windows

    - by robUK
    Hello, gcc 4.4.4 c89 Visual Studio VC++ 2008 I am writing a cross platform client server application. It will run on both linux and windows. However, I am just wondering what I have done for closing the sockets is correct. I close the file descriptor. However, if there is a problem with closing it. What is the best way to handle this. Maybe some data is still being sent or received? Many thanks for any advice, if(close(sockfd) == -1) { #if defined ( _WIN32 ) fprintf(stderr, "[ %d ] [ %s ] [ %s ] [ %d ]\n", WSAGetLastError(), strerror(errno), __func__, __LINE__); #elif( __linux__ ) fprintf(stderr, "[ %s ] [ %s ] [ %d ]\n", strerror(errno), __func__, __LINE__); #endif return CS_FAILURE; }

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  • How can I check if a value is in a list in Perl?

    - by ablimit
    I have a file in which every line is an integer which represents an id. What I want to do is just check whether some specific ids are in this list. But the code didn't work. It never tells me it exists even if 123 is a line in that file. I don't know why? Help appreciated. open (FILE, "list.txt") or die ("unable to open !"); my @data=<FILE>; my %lookup =map {chop($_) => undef} @data; my $element= '123'; if (exists $lookup{$element}) { print "Exists"; } Thanks in advance.

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  • How do I erase printed characters in a console application(Linux)?

    - by Binny V A
    Hi all, I am creating a small console app that needs a progress bar. Something like... Conversion: 175/348 Seconds |========== | 50% My question is, how do you erase characters already printed to the console? When I reach the 51st percentage, I have to erase this line from the console and insert a new line. In my current solution, this is what happens... Conversion: 175/348 Seconds |========== | 50% Conversion: 179/348 Seconds |========== | 52% Conversion: 183/348 Seconds |========== | 54% Conversion: 187/348 Seconds |=========== | 56% Code I use is... print "Conversion: $converted_seconds/$total_time Seconds $progress_bar $converted_percentage%\n"; I am doing this in Linux using PHP(only I will use the app - so please excuse the language choice). So, the solution should work on the Linux platform - but if you have a solution that's cross platform, that would be preferable.

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  • Numeric GUI bottleneck

    - by Physic
    Hi all, I've made a GUI to set up and start a numerical integrator using PyQT4, Wing, QT, and Python 2.6.6, on my Mac. The thing is, when I run the integrator form the GUI, it takes very many times longer than when I crudely run the integrator from the command line. As an example, a 1000 year integration took 98 seconds on the command line and ~570 seconds from the GUI. In the GUI, the integration runs from a thread and then returns. It uses a a queue to communicate back to the GUI. Does anyone have any ideas as to where the bottleneck is? I suspect that others may be experiencing something like this just on a smaller scale. t = threading.Thread( target=self.threadsafe_start_thread, args=( self.queue, self.selected ) ) t.start() Thanks!

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  • Connecting to the database in a Created Library - CodeIgniter

    - by Brogrammer
    I have a little issue right now and its bugging me, hopefully one of you guys will be able to help me out. Basically I'm creating a library to use in CodeIgniter and I'm getting this error: A PHP Error was encountered Severity: Notice Message: Undefined property: Functions::$db Filename: libraries/Functions.php Line Number: 11 The Database library is already on autoload aswell as my functions library: $autoload['libraries'] = array('database','session','encrypt','functions'); The Functions.php file is located in the application/libraries folder accordingly. Line number 11 consists of this: $this->db->where('username', $data); Not sure as to why the db is an undefined property?

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  • Python change the working directory for an exe opened with startfile

    - by Saulpila
    In python i'm using the os.startfile command to start a windows executable that does especific stuff in its own folder, the python code is running from another folder, so when I start the file, it starts in the python script's working directory, but it has to start in its own directory. I've tried to use os.chdir(path) to change the working directory, but it fails, the file still not runs in it's own folder. I thought maybe there is a command like shortcut's "Start in" line. I've searched everywere, but not success. The only solution comes to my mind is to create a shortcut and add the "start in" line, then launch the shortcut, but that is very impractical.

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