Search Results

Search found 15224 results on 609 pages for 'parallel python'.

Page 408/609 | < Previous Page | 404 405 406 407 408 409 410 411 412 413 414 415  | Next Page >

  • Django: Extending User Model - Inline User fields in UserProfile

    - by Jack Sparrow
    Is there a way to display User fields under a form that adds/edits a UserProfile model? I am extending default Django User model like this: class UserProfile(models.Model): user = models.OneToOneField(User, unique=True) about = models.TextField(blank=True) I know that it is possible to make a: class UserProfileInlineAdmin(admin.TabularInline): and then inline this in User ModelAdmin but I want to achieve the opposite effect, something like inverse inlining, displaying the fields of the model pointed by the OneToOne Relationship (User) in the page of the model defining the relationship (UserProfile). I don't care if it would be in the admin or in a custom view/template. I just need to know how to achieve this. I've been struggling with ModelForms and Formsets, I know the answer is somewhere there, but my little experience in Django doesn't allow me to come up with the solution yet. A little example would be really helpful!

    Read the article

  • I Made Simple Generator,, Is there any faster way ??

    - by Rami Jarrar
    Hi, i do like this: import time f = open('wl4.txt', 'w') hh = 0 ###################################### for n in range(1,5): for l in range(33,127): if n==1: b = chr(l) + '\n' f.write(b) hh += 1 elif n==2: for s0 in range(33, 127): b = chr(l) + chr(s0) + '\n' f.write(b) hh += 1 elif n==3: for s0 in range(33, 127): for s1 in range(33, 127): b = chr(l) + chr(s0) + chr(s1) + '\n' f.write(b) hh += 1 elif n==4: for s0 in range(33, 127): for s1 in range(33, 127): for s2 in range(33,127): b = chr(l) + chr(s0) + chr(s1) + chr(s2) + '\n' f.write(b) hh += 1 ###################################### print "We Made %d Words." %(hh) ###################################### f.close() So, is there any faster method to make it faster,,

    Read the article

  • How to achieve interaction between GUI class with logic class

    - by volting
    Im new to GUI programming, and haven't done much OOP. Im working on a basic calculator app to help me learn GUI design and to brush up on OOP. I understand that anything GUI related should be kept seperate from the logic, but Im unsure how to implement interaction between logic an GUI classes when needed i.e. basically passing variables back and forth... Im using TKinter and when I pass a tkinter variable to my logic it only seems to hold the string PY_VAR0. def on_equal_btn_click(self): self.entryVariable.set(self.entryVariable.get() + "=") calculator = Calc(self.entryVariable) self.entryVariable.set(calculator.calculate()) Im sure that im probably doing something fundamentally wrong and probabaly really stupid, I spent a considerable amount of time experimenting (and searching for answers online) but Im getting no where. Any help would be appreciated. Thanks, V The Full Program (well just enough to show the structure..) import Tkinter class Gui(Tkinter.Tk): def __init__(self,parent): Tkinter.Tk.__init__(self,parent) self.parent = parent self.initialize() def initialize(self): self.grid() self.create_widgets() """ grid config """ #self.grid_columnconfigure(0,weight=1,pad=0) self.resizable(False, False) def create_widgets(self): """row 0 of grid""" """Create Text Entry Box""" self.entryVariable = Tkinter.StringVar() self.entry = Tkinter.Entry(self,width=30,textvariable=self.entryVariable) self.entry.grid(column=0,row=0, columnspan = 3 ) self.entry.bind("<Return>", self.on_press_enter) """create equal button""" equal_btn = Tkinter.Button(self,text="=",width=4,command=self.on_equal_btn_click) equal_btn.grid(column=3, row=0) """row 1 of grid""" """create number 1 button""" number1_btn = Tkinter.Button(self,text="1",width=8,command=self.on_number1_btn_click) number1_btn.grid(column=0, row=1) . . . def on_equal_btn_click(self): self.entryVariable.set(self.entryVariable.get() + "=") calculator = Calc(self.entryVariable) self.entryVariable.set(calculator.calculate()) class Calc(): def __init__(self, equation): self.equation = equation def calculate(self): #TODO: parse string and calculate... return self.equation if __name__ == "__main__": app = Gui(None) app.title('Calculator') app.mainloop()

    Read the article

  • Problem with SQLite executemany

    - by Strider1066
    I can't find my error in the following code. When it is run a type error is given for line: cur.executemany(sql % itr.next()) = 'function takes exactly 2 arguments (1 given), import sqlite3 con = sqlite3.connect('test.sqlite') cur = con.cursor() cur.execute("create table IF NOT EXISTS fred (dat)") def newSave(className, fields, objData): sets = [] itr = iter(objData) if len(fields) == 1: sets.append( ':' + fields[0]) else: for name in fields: sets.append( ':' + name) if len(sets)== 1: colNames = sets[0] else: colNames = ', '.join(sets) sql = " '''insert into %s (%s) values(%%s)'''," % (className, colNames) print itr.next() cur.executemany(sql % itr.next()) con.commit() if __name__=='__main__': newSave('fred', ['dat'], [{'dat':1}, {'dat':2}, { 'dat':3}, {'dat':4}]) I would appreciate your thoughts.

    Read the article

  • Use Twisted's getPage as urlopen?

    - by RadiantHex
    Hi folks, I would like to use Twisted non-blocking getPage method within a webapp, but it feels quite complicated to use such function compared to urlopen. This is an example of what I'm trying to achive: def web_request(request): response = urllib.urlopen('http://www.example.org') return HttpResponse(len(response.read())) Is it so hard to have something similar with getPage?

    Read the article

  • How to slice a list of objects in association of the object attributes

    - by gizgok
    I have a list of fixtures.Each fixture has a home club and a away club attribute.I want to slice the list in association of its home club and away club.The sliced list should be of homeclub items and awayclub items. Easier way to implement this is to first slice a list of fixtures.Then make a new list of the corresponding Home Clubs and Away Clubs.I wanted to know if we can do this one step.

    Read the article

  • Interesting task using random numbers only

    - by psihodelia
    Given any number of the random real numbers from the interval [0,1] is there exist any method to construct a floating point number with zero decimal part? Your algorithm can use only random() function calls and no variables or constants. No constants and variables are allowed, no type casting is allowed. You can use for/while, if/else or any other programming language operands.

    Read the article

  • How do I make BeautifulSoup parse the contents of textarea tags as HTML?

    - by brofield
    Before 3.0.5, BeautifulSoup used to treat the contents of <textarea as HTML. It now treats it as text. The document I am parsing has HTML inside the textarea tags, and I am trying to process it. I've tried: for textarea in soup.findAll('textarea'): contents = BeautifulSoup.BeautifulSoup(textarea.contents) textarea.replaceWith(contents.html(text=True)) But I'm getting errors. I can't find this in the documentation, and the alternative parsers aren't helping. Anyone know how I can parse the textareas as HTML?

    Read the article

  • how to create a theme with QT

    - by Moayyad Yaghi
    hello im looking for a way to make my pyqt interface look nicer by adding a theme to it. im new to Qt and i still have no idea how to add a custom theme for widgets.. so how is that possible ? and is it possible through qt designer ? sorry for my bad english , its my third language. i hope the idea is clear enough . please let me know if something was unclear .. thanks in advace

    Read the article

  • Empty dict-like collection problem in SQLAlchemy

    - by maksymko
    I have a mapping in SQLAlchemy that looks like this: t_property_value = sa.Table('property_value', MetaData, autoload = True, autoload_with = engine) orm.mapper(PropertyValue, t_property_value) t_estate = sa.Table('estate', MetaData, autoload = True, autoload_with = engine) orm.mapper(Estate, t_estate, properties = dict( property_hash = orm.relation(PropertyValue, collection_class = column_mapped_collection(t_property_value.c.property_id)) )) Now, everything seems to be fine, when I load the Estate object and it has some relations to PropertyValue objects. However, when it does not, then property_hash attribute is None, instead of being something dict-like, so I can not add new relations like this: estate.property_hash[prop_id] = PropertyValue(...) because I get the "'NoneType' object does not support item assignment" error. So, is there any way to force SQLAlchemy to create proper empty collection?

    Read the article

  • standard geographic tilizing/binning method?

    - by monkut
    I'm trying to learn and understand more about mapping and displaying values on a map. (GIS) At the moment I'M looking to take some values and apply those values to a tile or bin on a map. Ideally I'd like the tile sizes to be uniform, like 100 meters, 500 meters, etc. Is there a standard method for creating uniform tile sizes? Or Are what are common accepted method to deal with this kind of data display? (Currently I'm using geodjango and it's related toolset geos, proj4, etc)

    Read the article

  • What is an efficient way to erase substrings?

    - by Legend
    I have a long string and a set of <end-index, string> list like the following: long_sentence = "This is a long long long long sentence" indices = [[6, "is"], [8, "is a"], [18, "long"], [23, "long"]] An element 6, "is" indicates that 6 is the end index of the word "is" in the string. I want to get the following string in the end: >> print long_sentence This .... long ......... long sentence" I tried an approach like this: temp = long_sentence for i in indices: temp = temp[:int(i[0]) - len(i[1])] + '.'*(len(i[1])+1) + temp[i[0]+1:] While this seems to be working, it is taking exceptionally long time (more than 6 hours on 5000 strings inside a 300 MB file). Is there a way to speed this up?

    Read the article

  • list comprehension example

    - by self
    can we use elif in list comprehension? example : l = [1, 2, 3, 4, 5] for values in l: if values==1: print 'yes' elif values==2: print 'no' else: print 'idle' can we use list comprehension for such 2 if conditions and one else condition? foe example answer like : ['yes', 'no', 'idle', 'idle', 'idle'] I have done till now only if else in list comprehension.

    Read the article

  • Get the path to Django itself

    - by andybak
    I've got some code that runs on every (nearly) every admin request but doesn't have access to the 'request' object. I need to find the path to Django installation. I could do: import django django_path = django.__file__ but that seems rather wasteful in the middle of a request. Does putting the import at the start of the module waste memory? I'm fairly sure I'm missing an obvious trick here.

    Read the article

  • How to sort a Pandas DataFrame according to multiple criteria?

    - by user1715271
    I have the following DataFrame containing song names, their peak chart positions and the number of weeks they spent at position no 1: Song Peak Weeks 76 Paperback Writer 1 16 117 Lady Madonna 1 9 118 Hey Jude 1 27 22 Can't Buy Me Love 1 17 29 A Hard Day's Night 1 14 48 Ticket To Ride 1 14 56 Help! 1 17 109 All You Need Is Love 1 16 173 The Ballad Of John And Yoko 1 13 85 Eleanor Rigby 1 14 87 Yellow Submarine 1 14 20 I Want To Hold Your Hand 1 24 45 I Feel Fine 1 15 60 Day Tripper 1 12 61 We Can Work It Out 1 12 10 She Loves You 1 36 155 Get Back 1 6 8 From Me To You 1 7 115 Hello Goodbye 1 7 2 Please Please Me 2 20 92 Strawberry Fields Forever 2 12 93 Penny Lane 2 13 107 Magical Mystery Tour 2 16 176 Let It Be 2 14 0 Love Me Do 4 26 157 Something 4 9 166 Come Together 4 10 58 Yesterday 8 21 135 Back In The U.S.S.R. 19 3 164 Here Comes The Sun 58 19 96 Sgt. Pepper's Lonely Hearts Club Band 63 12 105 With A Little Help From My Friends 63 7 I'd like to rank these songs in order of popularity, so I'd like to sort them according to the following criteria: songs that reached the highest position come first, but if there is a tie, the songs that remained in the charts for the longest come first. I can't seem to figure out how to do this in Pandas.

    Read the article

  • HTML5 -- server side

    - by Joe Cannatti
    How much does it matter what server side language is used for building a web app to take advantage of HTML 5? It seems to me that the ruby community will probably have the fastest uptake, and as a result the most support. Does that seem right? If I want to make a serious investment in HTML5, what server side language should I use?

    Read the article

  • PyGTK "assertion GTK_IS_WINDOW failed

    - by iAndr0idOs
    I'm trying to build a web browser using PyGTK and PyWebKit However, I'm pretty sure my question only concerns PyGTK I have a custom gtk.Notebook class, with an "add tab" button as the last tab. When I click it, it gives me the error /home/ruiqimao/workspace/PyBrowser/src/browser/__init__.py:161: GtkWarning: IA__gdk_window_get_cursor: assertion `GDK_IS_WINDOW (window)' failed gtk.main() twice. And then, my new tab won't show up. I have no idea what is going on, so here is my whole code If any of you could help me, that would be great! Thanks! [EDIT]: Just found out that the problem lies in the w.show_all() line What could this mean?

    Read the article

  • Adding a child node to a JSON node dynamically

    - by Sai
    I have to create a nested multi level json depending on the resultset that I get from MYSQL. I created a json object initially. Now I want to add child nodes to the already child nodes in the object. d = collections.OrderedDict() jsonobj = {"test": dict(updated_at="today", ID="ID", ads=[])} for rows1 in rs: jsonobj['list']["ads"].append(dict(unit = "1", type ="ad_type", id ="123", updated_at="today", x_id="111", x_name="test")) cur.execute("SELECT * from f_test") rs1 = cur.fetchall() for rows2 in rs1: propertiesObj = [] d["name"]="propName" d["type"]="TypeName" d["value"]="Value1" propertiesObj.append(d) jsonobj['play_list']["ads"].append() Here in the above line I want to add another child node to [play_list].[ads] which is a array list again. the output should look like the following [list].[ads].[preferences].

    Read the article

< Previous Page | 404 405 406 407 408 409 410 411 412 413 414 415  | Next Page >