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• OutputPath ignored on projects being build by TFS 2010

  - by bovium

  I have installed TFS2010 Beta 2 with default settings and configured a CI build with a solution containing the indivial projects. My *.cspoj files could have: <OutputPath>bin\debug\</OutputPath> Or alternatively: <OutDir>bin\debug\</OutDir> When the build server is done building and running tests etc. all the assemblies are placed in the root of the build drop off folder. How do I configure the build to keep the outputpath or outdir in my projects and store the assemblies and content in the matching folder structure( builddropfolder\bin\debug\ )? I have found a number of post on this most of them relates to TFS 2008 but I have not found solutions for TFS 2010. Perhaps it is possible to solve this in the new workflow file for the buildserver?

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• Passenger problem: "no such file to load" -- /config/environment

  - by Mason Jones

  I've been researching this one and found references to similar problems here and there, but none of them has led to a solution yet. I've installed passenger (2.2.11) and nginx (0.7.64) and when I start things up and hit a Rails URL, I get an error page informing me of a load error: no such file to load -- /path/to/app/config/environment From what I've found online this appears to be some sort of a user/permissions error, but I've tried all the logical fixes: I've made sure that /config/environment.rb is not owned by root, but by a webapp user. I've tried setting passenger_default_user, I've tried setting passenger_user_switching off. I've even tried setting the nginx user, though that shouldn't matter much. I've gotten some differing results, but nothing's actually worked. I'm hoping someone may have the magical combination of settings and permissions for this. I may try backing down to an earlier version of Passenger, because I've never had this issue before; it's been a little while since I set up Passenger though. Thanks for any suggestions.

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• Good File Organization Suggestions for Developer

  - by Paul

  I am struggling a little with folder organization to organize the many projects that I work on. I work on OS X - right now I am using ~/Development/ as the root folder, and I have many types of projects. For example, I have my iPhone apps under ~/Development/Xcode I develop in many languages, from PHP, to Ruby, to Python, to Objective-C. So, for example, I might have a couple of open-source apps based on PHP where I am using the Zend framework. Some of these projects are for clients, others are tests/experiments when learning a new language or general experimenting. I am really interested in how other developers have organized code/projects and could pass along some advice to make it very easy to navigate through code/projects related to many languages and types of projects.

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• how to get dynamically created elements width and apply style to that?

  - by 3gwebtrain

  Hi, I am creating an li element dynamically like this: $(data).find('slide').each(function(numSlide){ var slideLink = $(this).attr('link'); var slideimage = $(this).children('slideimage').text(); var slidedesc = $(this).children('slidedesc').text(); $('.slider ul').append('<li><a href="'+slideLink+'"><img src="'+root+"images/top-slider-image/"+slideimage+'" alt="welcome to Burger Davis Blog" /></a><div class="note">'+slidedesc+'</div></li>'); }) But I'd like to calculate the width of the li, and I need to apply some style to it -- how can I do that? If I add styles via the css method, it does not work for dynamically created elements... Please help me to get dynamic elements' width and how to apply styles into that? I know we can use the live function, but I can't get even by that..

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• Does django take SCRIPT_NAME into account when using the default LOGIN_URL

  - by DanJ

  Hi, I'm using Django 1.0.2 and trying to figure out how to get the @login_required working correctly. When I use the built-in server it redirects to the default login_url, or my LOGIN_URL as defined in settings.py as expected. What is not clear to me is how to deploy to the server where my site is not at the root. In my templates I use the url template tag, and in the views I can access request.META['SCRIPT_NAME'], but for some reason it doesn't seem to apply to the LOGIN_URL used. What am I missing? Thanks.

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• How can I find out the original username a process was started with?

  - by szabgab

  There is a perl script that needs to run as root but the we must make sure the user who runs the script did not log-in originally as user foo as it will be removed during the script. So how can I find out if the user, who might have su-ed several times since she logged in has not impersonated 'foo' at any time in that chain? I found an interesting perl script that was calling the following two shell scripts, but I think that would only work on Solaris. my $shell_paren = `ps -ef | grep -v grep | awk \'{print \$2\" \"\$3}\' | egrep \"^@_\" | awk \'{print \$2}'`; my $parent_owner = `ps -ef | grep -v grep | awk \'{print \$1\" \"\$2}\' | grep @_ | awk \'{print \$1}\'`; This needs to work on both Linux and Solaris and I'd rather eliminate the repeated calls to he the shell and keep the whole thing in Perl.

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• ASP.Net Vertical Menu with Scroll functionality

  - by Thomas

  Referring to Menu / Scrolling Example I would like to create / find the same functionality for a vertical menu. I tried the following. <asp:Menu ID="menuAccountMembers" runat="server" StaticSubMenuIndent="16px" Visible="true" RenderingMode="Table" ScrollDownImageUrl="~/Resources/scrolldown.jpg" ScrollUpImageUrl="~/Resources/scrollup.jpg"> <Items> But it doesnt display any scrolling images. I am using .net 4.0 Tried setting menuAccountMembers.RenderingCompatibility = new Version(3, 5); as well. If there a property to only display the first 5 root menu items, then show scroll bars for the rest? It can be click-able, no need to hover over to show next item.

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• How can I use javascript to convert relative href attributes into absolute paths?

  - by jhensley2

  I have a template that gets screenscraped from an outside vendor and need to include absolute paths in the navigation so the externally hosted content will properly link back to our site. Right now the page/template is driven by a global menu app written by our back end development staff... so anyone who updates our site goes in and changes the menus and their paths... Right now all of the links are linking to relative paths back to the root. For example <a href="/">Home</a> <a href="/news/">News</a> <a href="/media/">Media</a> <a href="/other/">Other</a> I need a simple way (preferably with jquery) to prepend "http://www.domain.com" to each of those links.

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• mysql php connection problem in windows 7

  - by air

  i install windows7 ultimate and php 5.3.1 and mysql server 5.1 mysql server work fine from mysql> and if see phpinfo(); i get the following table mysql MySQL Support enabled Active Persistent Links 0 Active Links 0 Client API version mysqlnd 5.0.5-dev - 081106 - $Revision: 289630 $ Persistent cache enabled put_hits 0 put_misses 0 get_hits 0 get_misses 0 size 2000 free_items 2000 references 2 but when i connect with following php command $db_host="localhost"; $db_name="mysql"; $db_user="root"; $db_pass="*****"; $dbc=mysql_connect($db_host,$db_user,$db_pass) OR DIE (mysql_error()); $dbs=mysql_select_db($db_name) OR DIE (mysql_error()); when i run page, page take long time in loading and then return nothing. and if i pass any query it return false, i think its connection problem. Thanks

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• Understanding Nested If.. Else statements

  - by user1174762

  For some reason my PHP login script keeps returning "invalid email/password combination", yet i know I am entering the correct email and password. Does anyone see what I might be doing wrong? <?php $email= $_POST['email']; $password= $_POST['password']; if (!empty($email) && !empty($password)) { $connect= mysqli_connect("localhost", "root", "", "si") or die('error connecting with the database'); $query= "SELECT user_id, email, password FROM users WHERE email='$email' AND password='$password'"; $result= mysqli_query($connect, $query) or die('error with query'); if (mysqli_num_rows($result) == 1) { $row= mysqli_fetch_array($result); setcookie('user_id', $row['user_id']); echo "you are now logged in"; } else { echo "invalid username/password combination"; } } else { echo" you must fill out both username and password"; } ?>

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• set up way of getting mysite.$domain

  - by jose silva

  Hi I have several domains, only one website and one databse table for each domain. example: wbesite.us - data from USA goes to database table main_usa wbesite.co.uk - data form UK goes to database table main_uk Only have one database with name of the website. Having only one website structured, and having variables like $sql="select * from main_".$countrycode." where bla..bla..., and many other variables to catch the domain extension, and so on... Now, instead of having one full website for each domain, how can set a script and wher do I put it in order to detect the domain that the user uses. In my server root do I create something like website.$domain ? Something like website OLX but for different purposes. I hope I made myself clear. Thank you.

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• Doesnt the Visual Studio 2008 compiler autocast to double with sqrt in C++?

  - by Chris_45

  Shouldn't the compiler automatically cast to a double in this case at least according to Walter Savitch: #include <iostream> #include <cmath> using namespace std; int main(){ int k; for(k = 1; k <= 10; k++) cout << "The square root of i is: " << sqrt(k) << endl; return 0; }//error C2668: 'sqrt' : ambiguous call to overloaded function //Visual Studio 2008 on Win Vista

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• Whats the python way for recursively setting file permissions?

  - by Geoff

  What's the "python way" to recursively set the owner and group to files in a directory? I could just pass a 'chown -R' command to shell, but I feel like I'm missing something obvious. I'm mucking about with this: import os path = "/tmp/foo" for root, dirs, files in os.walk(path): for momo in dirs: os.chown(momo, 502, 20) This seems to work for setting the directory, but fails when applied to files. I suspect the files are not getting the whole path, so chown fails since it can't find the files. The error is: 'OSError: [Errno 2] No such file or directory: 'foo.html' What am I overlooking here?

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• Property Scope (Iphone)

  - by Hank

  Hello All. I am having trouble accessing a declared property and I think I am missing something fundamental about the nature of properties and perhaps view controllers. Here's what I'm doing so far: declaring a property "myPhone" in a root view controller called RootViewController. grabbing a phone number from a modally presented people picker setting "myPhone" to the value from the people picker (from within shouldContinueAfterSelectingPerson of ABPeoplePickerNavigationController) trying to access "myPhone" from another modally presented view controller "myPhone" continues to NSLog to null despite trying every permutation of self.myPhone, super, RootViewController, etc. to try and access the value I set. What am I missing?

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• foreach with an array of stdclass objects

  - by Jared Steffen

  So, what I want to do is quite simple in my mind. I have an array that consists solely of four objects. I want to create a loop that will echo an attribute of each object in the array. The only success I've had, however, is echoing every object and every property of the objects. I've never dealt with objects so this is probably the TRUE root of the problem. There's been a few revisions but the only thing I've really excelled at is creating error codes. Here is what I have: $categories = get_categories(array('child_of' => '8')); foreach ($categories as $cat) { echo $cat->name; };

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• Facebook, Flash and maintaining state

  - by Myk

  So here's the situation: I have a Flash application I'm deploying to facebook as a canvas app. There are various states within this app - different "pages", sort of. I want to be able to share this app with other users using Facebook's baked-in sharing mechanism. However, I want each state to have its own share button. That way when someone clicks Share on page 3 they are actually sharing page 3, not the root of the whole application. Does anyone know if Facebook exposes some mechanism by which this could be possible? It would be as simple as passing a string into the iFrame that holds the canvas app, so I could load it in as a FlashVar and work from there. I'm kind of beating my head against the wall - does this request make sense, and has anyone tackled anything like this before? Thanks!

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• How to see functions implemented in R packages

  - by rinzy kutex

  How do I see the actual code for the functions implemented in R packaged. For instance I have loaded the caret package and I would like to see the code used for the function "createMultiFolds". I have gone to where the packages are stored but can't seem to find what I am looking for. For instance folders like Meta in the root folder of the caret package have files with the .rds extension which I can read into R with the gzfile command but I can't still seem to find what I am looking for i.e. the exact for the functions e.g. creatMultifolds. I would like to adapt some of these functions specifically to my research needs by make small changes to the codes to output the results in the way that I want without having to "re-invent the wheel" I will be glad if someone can help me. Thanks.

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• How can I clean up this SELECT query?

  - by Cruachan

  I'm running PHP 5 and MySQL 5 on a dedicated server (Ubuntu Server 8.10) with full root access. I'm cleaning up some LAMP code I've inherited and I've a large number of SQL selects with this type of construct: SELECT ... FROM table WHERE LCASE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE( strSomeField, ' ', '-'), ',', ''), '/', '-'), '&', ''), '+', '') ) = $somevalue Ignoring the fact that the database should never have been constructed to require such a select in the first place, and the $somevalue field will need to be parameterised to plug the gaping security hole, what is my best option for fixing the WHERE condition into something less offensive? If I was using MSSQL or Oracle I'd simply put together a user-defined function, but my experience with MySQL is more limited and I've not constructed a UDF with it before, although I'm happy coding C. Update: For all those who've already raised their eyebrows at this in the original code, $somevalue is actually something like $GET['product']—there are a few variations on the theme. In this case the select is pulling the product back from the database by product name—after stripping out characters so it matches what could be previously passed as a URI parameter.

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• htaccess: how to prevent infinite subdirectories?

  - by Vincent Isles

  My .htaccess at the root directory contains this: Options -MultiViews +FollowSymlinks -Indexes ErrorDocument 404 /404.htm RewriteEngine On RewriteBase / followed by a bunch of RewriteRules. The .htaccess at the /forum subdirectory contains this: RewriteEngine On RewriteBase /forum RewriteRule ^index.html$ index.php [L,NE] RewriteRule ^(.*)-t-([0-9]+).html(.*)$ showthread.php?tid=$2$3 [QSA,L] RewriteRule ^(.*)-t-([0-9]+)-([0-9]+).html$ showthread.php?tid=$2&page=$3 [QSA,L] followed by other rules mapping SEO-friendly URLs to the true URLs. mydomain.com/forum/a-thread-t-1.html returns the page showthread.php?tid=1 but so does mydomain.com/forum/forum/a-thread-t-1.html, mydomain.com/forum/forum/forum/a-thread-t-1.html and so on. I don't want this behavior - I want pages accessed as /forum/forum/* to return a 404. Any hint on where I had been wrong?

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• HOw to find specific child node in XML using AS3 flash

  - by Mirage

  I have this xml var testXML:XML = <family> <father name1="tom" age="5" ><father1 name1="test1"/><father2 name1="test2"/></father> <mother name1="tomylee" age="55" ><mother1/><mother2/></mother> <sister name1="sister1" age="35" ><sister1/><sister2/></sister> </family>; I want to get the child node with name1 = test1 but i only know family so is there something like trace (testXML.children(@name1="test1"); I only know the family node , i don't know where that node is inside the father or not is there any filter can be applied on root node to find something

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• How can I generate XML application configuration using Zend_Tool?

  - by wimvds

  When creating a new project using zf create project myproject it will create a default project layout with an application.ini in the configs folder. Where can I change these default settings so that it generates (and uses) an XML file (application.xml)? I've looked at the documentation for Zend_Tool (http://framework.zend.com/manual/en/zend.tool.html), but there seems to be no information on how to do this. And suppose you'd like to use a different default folder layout (ie. use htdocs instead of public as your document root), is there a way to specify this as well? Any pointers to relevant information (btw I've looked at the Quickstart, nothing relevant is mentioned there unless I'm overlooking it)? edit I already tried creating a profile (stored in .zf/project/profiles), and used that to create a project (using zf create project myproject myprofile) but that doesn't change anything, even though the .zfproject.xml file in the root of the new project does contain the <applicationConfigFile type="xml"/> setting... The new project contains this (as you can see, it's just the default settings, only the type of applicationConfigFile has been changed) : <?xml version="1.0"?> <projectProfile type="default" version="1.10"> <projectDirectory> <projectProfileFile filesystemName=".zfproject.xml"/> <applicationDirectory classNamePrefix="Application_"> <apisDirectory enabled="false"/> <configsDirectory> <applicationConfigFile type="xml"/> </configsDirectory> <controllersDirectory> <controllerFile controllerName="Index"> <actionMethod actionName="index"/> </controllerFile> <controllerFile controllerName="Error"/> </controllersDirectory> <formsDirectory enabled="false"/> <layoutsDirectory enabled="false"/> <modelsDirectory/> <modulesDirectory enabled="false"/> <viewsDirectory> <viewScriptsDirectory> <viewControllerScriptsDirectory forControllerName="Index"> <viewScriptFile forActionName="index"/> </viewControllerScriptsDirectory> <viewControllerScriptsDirectory forControllerName="Error"> <viewScriptFile forActionName="error"/> </viewControllerScriptsDirectory> </viewScriptsDirectory> <viewHelpersDirectory/> <viewFiltersDirectory enabled="false"/> </viewsDirectory> <bootstrapFile filesystemName="Bootstrap.php"/> </applicationDirectory> <dataDirectory enabled="false"> <cacheDirectory enabled="false"/> <searchIndexesDirectory enabled="false"/> <localesDirectory enabled="false"/> <logsDirectory enabled="false"/> <sessionsDirectory enabled="false"/> <uploadsDirectory enabled="false"/> </dataDirectory> <docsDirectory> <file filesystemName="README.txt"/> </docsDirectory> <libraryDirectory> <zfStandardLibraryDirectory enabled="false"/> </libraryDirectory> <publicDirectory> <publicStylesheetsDirectory enabled="false"/> <publicScriptsDirectory enabled="false"/> <publicImagesDirectory enabled="false"/> <publicIndexFile filesystemName="index.php"/> <htaccessFile filesystemName=".htaccess"/> </publicDirectory> <projectProvidersDirectory enabled="false"/> <temporaryDirectory enabled="false"/> <testsDirectory> <testPHPUnitConfigFile filesystemName="phpunit.xml"/> <testApplicationDirectory> <testApplicationBootstrapFile filesystemName="bootstrap.php"/> </testApplicationDirectory> <testLibraryDirectory> <testLibraryBootstrapFile filesystemName="bootstrap.php"/> </testLibraryDirectory> </testsDirectory> </projectDirectory> </projectProfile>

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• Cannot use scp on Mac OS X

  - by Robert

  Hi all, when I try to copy any file with scp on Mac OS X Snow Leopard from another machine I get this error: scp [email protected]:/home/me/file.zip . Password: ... ---> Couldn't open /dev/null: Permission denied this is the output of "ls -l /dev/null": crw-rw-rw- 1 root wheel 3, 2 May 14 14:10 /dev/null I am in the group wheel, and even if I do "sudo scp..." it doesn't work. It's driving me crazy, do you have any suggestion? Thanx!

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• apache alias and .htacess willing to understand configuration?

  - by sushil bharwani

  On our local dev enviornment we had just one server and to add far future expires and cache control header to static images we kept a .htaccess file in the root of the application things worked fine. But on our prod we have multiple apache servers having aliases to a code base on a different server. Here in this case i am not sure where to keep .htacess file on. Should i be keeping it on code base or on the individual apache servers. How can i write the same stuff that i have written in .htaccess file to httpd.conf file.

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• findNode in binary search tree

  - by Weadadada Awda

  Does this look right? I mean I am trying to implement the delete function. Node* BST::findNode(int tofind) { Node* node = new Node; node = root; while (node != NULL) { if (node->val == tofind) { return node; } else if (tofind < node->val) { node = node->left; } else { node = node->right; } } } Here is the delete, it's not even close to done but, void BST::Delete(int todelete) { // bool found = false; Node* toDelete = new Node(); toDelete=findNode(todelete); if(toDelete->val!=NULL) { cout << toDelete->val << endl; } } This causes a segmentation fault just running that, any ideas?

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• Cannot move ckeditor 4 selection to beginning

  - by Gary Hillerson

  I've been exploring numerous solutions in stackoverflow and elsewhere to try to get ckeditor 4 to scroll to the top after I've programmatically added a number of pages to it, using CKEditor's InsertHtml function. After adding my html, which looks fine, I want to position the cursor at the beginning. Here's one of a variety of things I've tried without success: function MoveCaretToStart(myEditor) { var range = new CKEDITOR.dom.range( editor.document ); range.selectNodeContents(editor.document.getBody()); range.moveToElementEditStart(range.root); // also tried range.collapse(true); range.select(); } ... MoveCaretToStart(CKEDITOR.instances['myEditor']); // which already has contents in it This doesn't throw any errors, but also doesn't move the cursor position (it remains at the end of the doc). I thought this one would be easy, but it sure hasn't been. Any help appreciated.

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