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  • What do ptLineDist and relativeCCW do?

    - by Fasih Khatib
    I saw these methods in the Line2D Java Docs but did not understand what they do? Javadoc for ptLineDist says: Returns the distance from a point to this line. The distance measured is the distance between the specified point and the closest point on the infinitely-extended line defined by this Line2D. If the specified point intersects the line, this method returns 0.0 Doc for relativeCCW says: Returns an indicator of where the specified point (PX, PY) lies with respect to the line segment from (X1, Y1) to (X2, Y2). The return value can be either 1, -1, or 0 and indicates in which direction the specified line must pivot around its first endpoint, (X1, Y1), in order to point at the specified point (PX, PY). A return value of 1 indicates that the line segment must turn in the direction that takes the positive X axis towards the negative Y axis. In the default coordinate system used by Java 2D, this direction is counterclockwise. A return value of -1 indicates that the line segment must turn in the direction that takes the positive X axis towards the positive Y axis. In the default coordinate system, this direction is clockwise. A return value of 0 indicates that the point lies exactly on the line segment. Note that an indicator value of 0 is rare and not useful for determining colinearity because of floating point rounding issues. If the point is colinear with the line segment, but not between the endpoints, then the value will be -1 if the point lies "beyond (X1, Y1)" or 1 if the point lies "beyond (X2, Y2)".

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  • C++ OOP - Can you 'overload a cast' <- hard to explain in 1 sentence

    - by Brandon Miller
    Well, the WinAPI has a POINT struct, but I am trying to make an alternative class to this so you can set the values of x and y from a constructor. /** * X-Y coordinates */ class Point { public: int X, Y; Point(void) : X(0), Y(0) {} Point(int x, int y) : X(x), Y(y) {} Point(const POINT& pt) : X(pt.x), Y(pt.y) {} Point& operator= (const POINT& other) { X = other.x; Y = other.y; } }; // I have an assignment operator and copy constructor. Point myPtA(3,7); Point myPtB(8,5); POINT pt; pt.x = 9; pt.y = 2; // I can assign a 'POINT' to a 'Point' myPtA = pt; // But I also want to be able to assign a 'Point' to a 'POINT' pt = myPtB; Is it possible to overload operator= in a way so that I can assign a Point to a POINT? Or maybe some other method to achieve this? Thanks in advance.

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  • Why does SFINAE not apply to this?

    - by Simon Buchan
    I'm writing some simple point code while trying out Visual Studio 10 (Beta 2), and I've hit this code where I would expect SFINAE to kick in, but it seems not to: template<typename T> struct point { T x, y; point(T x, T y) : x(x), y(y) {} }; template<typename T, typename U> struct op_div { typedef decltype(T() / U()) type; }; template<typename T, typename U> point<typename op_div<T, U>::type> operator/(point<T> const& l, point<U> const& r) { return point<typename op_div<T, U>::type>(l.x / r.x, l.y / r.y); } template<typename T, typename U> point<typename op_div<T, U>::type> operator/(point<T> const& l, U const& r) { return point<typename op_div<T, U>::type>(l.x / r, l.y / r); } int main() { point<int>(0, 1) / point<float>(2, 3); } This gives error C2512: 'point<T>::point' : no appropriate default constructor available Given that it is a beta, I did a quick sanity check with the online comeau compiler, and it agrees with an identical error, so it seems this behavior is correct, but I can't see why. In this case some workarounds are to simply inline the decltype(T() / U()), to give the point class a default constructor, or to use decltype on the full result expression, but I got this error while trying to simplify an error I was getting with a version of op_div that did not require a default constructor*, so I would rather fix my understanding of C++ rather than to just do what works. Thanks! *: the original: template<typename T, typename U> struct op_div { static T t(); static U u(); typedef decltype(t() / u()) type; }; Which gives error C2784: 'point<op_div<T,U>::type> operator /(const point<T> &,const U &)' : could not deduce template argument for 'const point<T> &' from 'int', and also for the point<T> / point<U> overload.

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  • What's the use of Ant's extension-point if/unless attributes?

    - by Robert Menteer
    When you define an extension-point in an Ant build file you can have it conditional by using the if or unless attribute. On a target the if/unless prevent it's tasks from being run. But an extension-point doesn't have any tasks to conditionally run, so what does the condition do? My thought (which proved to be incorrect in Ant 1.8.0) is it would prevent any tasks that extend the extension-point from being run. Here is an example build script showing the problem: <project name = "ext-test" default = "main"> <property name = "do.it" value = "false" /> <extension-point name = "init"/> <extension-point name = "doit" depends = "init" if = "${do.it}" /> <target name = "extend-init" extensionOf = "init"> <echo message = "Doing extend-init." /> </target> <target name = "extend-doit" extensionOf = "doit"> <echo message = "Do It! (${do.it})" /> </target> <target name = "main" depends = "doit"> <echo message = "Doing main." /> </target> </project> Using the command: ant -v Relults in: Apache Ant version 1.8.0 compiled on February 1 2010 Trying the default build file: build.xml Buildfile: /Users/bob/build.xml Detected Java version: 1.6 in: /System/Library/Frameworks/JavaVM.framework/Versions/1.6.0/Home Detected OS: Mac OS X parsing buildfile /Users/bob/build.xml with URI = file:/Users/bob/build.xml Project base dir set to: /Users/bob parsing buildfile jar:file:/Users/bob/Documents/Development/3P-Tools/apache-ant-1.8.0/lib/ant.jar!/org/apache/tools/ant/antlib.xml with URI = jar:file:/Users/bob/Documents/Development/3P-Tools/apache-ant-1.8.0/lib/ant.jar!/org/apache/tools/ant/antlib.xml from a zip file Build sequence for target(s) `main' is [extend-init, init, extend-doit, doit, main] Complete build sequence is [extend-init, init, extend-doit, doit, main, ] extend-init: [echo] Doing extend-init. init: extend-doit: [echo] Do It! (false) doit: Skipped because property 'false' not set. main: [echo] Doing main. BUILD SUCCESSFUL Total time: 0 seconds You will notice the target extend-doit is executed but the extention-point itself is skipped. Since an extention-point doesn't have any tasks exactly what has been skipped? Any targets that depend on the extention-point still get executed since a skipped target is a successful target. What is the value of the if/unless attributes on an extention-point?

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  • How do I set the current point in a CG graphics context?

    - by Joe
    When running the code below in the iphone simulator I get the error : CGContextClosePath: no current point. Why is the current point not being set? Or is the context not set to the correct state? CGContextBeginPath(ctx); CGMutablePathRef pathHolder; pathHolder = CGPathCreateMutable(); //move to point for the initial point NSLog(@"Drawing a state point %f, %f", [[holder.points objectAtIndex:0] floatValue], [[holder.points objectAtIndex:1] floatValue]); CGPathMoveToPoint(pathHolder, NULL, [[holder.points objectAtIndex:0] floatValue], [[holder.points objectAtIndex:1] floatValue]); for(int x = 2; x < [holder.points count] - 1; x += 2) { NSLog(@"Drawing a state point %f, %f", [[holder.points objectAtIndex:x] floatValue], [[holder.points objectAtIndex:(x+1)] floatValue]); CGPathAddLineToPoint(pathHolder, NULL, [[holder.points objectAtIndex:x] floatValue], [[holder.points objectAtIndex:(x+1)] floatValue]); } CGContextClosePath(ctx); CGContextFillPath(ctx);

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  • How do I point a new domain to start on a page that's not index.html on separate hosting? [closed]

    - by Owen Campbell-Moore
    Possible Duplicate: How do I point a new domain to start on a page that's not index.html on separate hosting? I'm using a service called SquareSpace to host my site, and today I'm registering the domain for it. Basically, how do I make it so when somebody types www.tedxoxford.com it points at http://www.tedxoxford.com/landing (currently http://tedxoxford.squarespace.com/landing) instead of the default index? Is this possible? Squarespace is quite a restricted CMS and means that your logos etc all point to the index so I don't want people ending up on my landing/splash page every time they want the home page, only on the first time they type in the URL. A dirty hack would be to check the refferer and redirect anyone hitting the index to the landing page, but that's a lot of loading overhead I'd rather avoid...

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  • Le monde sur le point de se « noyer dans les données » selon le président d'Oracle qui prédit une crise du stockage et du traitement

    Le monde sur le point de se « noyer dans les données » Selon le président d'Oracle qui prédit une crise du stockage et de traitement Dans une déclaration au Times de Londres, le coprésident d'Oracle Mark Hurd a évoqué le sujet de « la croissance exponentielle » des données. Il prédit que celle-ci soit sur le point de déclencher un problème majeur dans les opérations de stockage, de traitement et d'analyse en temps réel. [IMG]http://idelways.developpez.com/news/images/oracle-marc-hurd.jpg[/IMG] Mark Hurd Selon Hurd, le nombre de dispositifs connectés à internet et fournissant des données pour les entreprises va croître po...

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  • Turn your laptop into a wireless Access Point with Windows 7!

    - by David Nudelman
    Windows 7 offers a very cool feature where you can connect multiple devices to any wired and wireless network connection (hotel, cable, 3G, UMTS, EDGE, WIFI, RJ45, Ethernet, etc.) by turning your own laptop into a wireless AP (Access Point) to relay those devices not directly connected to the internet. For this just enter these two commands to an elevated (right click on CMD.EXE, run as administrator): netsh wlan set hostednetwork mode=allow ssid=YOURFRIENDLYSSID key=SOMEPASSWORD netsh wlan start hostednetwork At this point, if Internet Connection Sharing (ICS) is setup, anyone can connect to your SoftAP (if they know the PWD of course) and the traffic will be sent through whatever adapter you want. You can actually bridge it across an entirely different adapter... or the same on a different Wifi LAN. A GUI to set this up can be downloaded for free here: http://www.connectify.me/

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  • Auto-mount CD/DVD drive to single, specific mount point every time?

    - by Christopher Parker
    Currently, whenever I insert a CD or DVD into my DVD drive, it mounts to a location such as /media/<LABEL>, where <LABEL> is the arbitrary label assigned to the optical disc. I remember, once upon a time, CD and DVD media being reliably located at /media/cdrom0 or something similar. Why was this changed? And how do I get this old behavior back for this drive? I can understand this behavior for USB sticks. It makes sense for those. But not for CD/DVD media, in my opinion. For example, because of this, I have no way to configure Wine to point to my DVD drive, as the mount point changes with every single CD I insert. TL;DR: How do I make CD/DVD media always mount to /media/cdrom0?

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  • Applications: The mathematics of movement, Part 1

    - by TechTwaddle
    Before you continue reading this post, a suggestion; if you haven’t read “Programming Windows Phone 7 Series” by Charles Petzold, go read it. Now. If you find 150+ pages a little too long, at least go through Chapter 5, Principles of Movement, especially the section “A Brief Review of Vectors”. This post is largely inspired from this chapter. At this point I assume you know what vectors are, how they are represented using the pair (x, y), what a unit vector is, and given a vector how you would normalize the vector to get a unit vector. Our task in this post is simple, a marble is drawn at a point on the screen, the user clicks at a random point on the device, say (destX, destY), and our program makes the marble move towards that point and stop when it is reached. The tricky part of this task is the word “towards”, it adds a direction to our problem. Making a marble bounce around the screen is simple, all you have to do is keep incrementing the X and Y co-ordinates by a certain amount and handle the boundary conditions. Here, however, we need to find out exactly how to increment the X and Y values, so that the marble appears to move towards the point where the user clicked. And this is where vectors can be so helpful. The code I’ll show you here is not ideal, we’ll be working with C# on Windows Mobile 6.x, so there is no built-in vector class that I can use, though I could have written one and done all the math inside the class. I think it is trivial to the actual problem that we are trying to solve and can be done pretty easily once you know what’s going on behind the scenes. In other words, this is an excuse for me being lazy. The first approach, uses the function Atan2() to solve the “towards” part of the problem. Atan2() takes a point (x, y) as input, Atan2(y, x), note that y goes first, and then it returns an angle in radians. What angle you ask. Imagine a line from the origin (0, 0), to the point (x, y). The angle which Atan2 returns is the angle the positive X-axis makes with that line, measured clockwise. The figure below makes it clear, wiki has good details about Atan2(), give it a read. The pair (x, y) also denotes a vector. A vector whose magnitude is the length of that line, which is Sqrt(x*x + y*y), and a direction ?, as measured from positive X axis clockwise. If you’ve read that chapter from Charles Petzold’s book, this much should be clear. Now Sine and Cosine of the angle ? are special. Cosine(?) divides x by the vectors length (adjacent by hypotenuse), thus giving us a unit vector along the X direction. And Sine(?) divides y by the vectors length (opposite by hypotenuse), thus giving us a unit vector along the Y direction. Therefore the vector represented by the pair (cos(?), sin(?)), is the unit vector (or normalization) of the vector (x, y). This unit vector has a length of 1 (remember sin2(?) + cos2(?) = 1 ?), and a direction which is the same as vector (x, y). Now if I multiply this unit vector by some amount, then I will always get a point which is a certain distance away from the origin, but, more importantly, the point will always be on that line. For example, if I multiply the unit vector with the length of the line, I get the point (x, y). Thus, all we have to do to move the marble towards our destination point, is to multiply the unit vector by a certain amount each time and draw the marble, and the marble will magically move towards the click point. Now time for some code. The application, uses a timer based frame draw method to draw the marble on the screen. The timer is disabled initially and whenever the user clicks on the screen, the timer is enabled. The callback function for the timer follows the standard Update and Draw cycle. private double totLenToTravelSqrd = 0; private double startPosX = 0, startPosY = 0; private double destX = 0, destY = 0; private void Form1_MouseUp(object sender, MouseEventArgs e) {     destX = e.X;     destY = e.Y;     double x = marble1.x - destX;     double y = marble1.y - destY;     //calculate the total length to be travelled     totLenToTravelSqrd = x * x + y * y;     //store the start position of the marble     startPosX = marble1.x;     startPosY = marble1.y;     timer1.Enabled = true; } private void timer1_Tick(object sender, EventArgs e) {     UpdatePosition();     DrawMarble(); } Form1_MouseUp() method is called when ever the user touches and releases the screen. In this function we save the click point in destX and destY, this is the destination point for the marble and we also enable the timer. We store a few more values which we will use in the UpdatePosition() method to detect when the marble has reached the destination and stop the timer. So we store the start position of the marble and the square of the total length to be travelled. I’ll leave out the term ‘sqrd’ when speaking of lengths from now on. The time out interval of the timer is set to 40ms, thus giving us a frame rate of about ~25fps. In the timer callback, we update the marble position and draw the marble. We know what DrawMarble() does, so here, we’ll only look at how UpdatePosition() is implemented; private void UpdatePosition() {     //the vector (x, y)     double x = destX - marble1.x;     double y = destY - marble1.y;     double incrX=0, incrY=0;     double distanceSqrd=0;     double speed = 6;     //distance between destination and current position, before updating marble position     distanceSqrd = x * x + y * y;     double angle = Math.Atan2(y, x);     //Cos and Sin give us the unit vector, 6 is the value we use to magnify the unit vector along the same direction     incrX = speed * Math.Cos(angle);     incrY = speed * Math.Sin(angle);     marble1.x += incrX;     marble1.y += incrY;     //check for bounds     if ((int)marble1.x < MinX + marbleWidth / 2)     {         marble1.x = MinX + marbleWidth / 2;     }     else if ((int)marble1.x > (MaxX - marbleWidth / 2))     {         marble1.x = MaxX - marbleWidth / 2;     }     if ((int)marble1.y < MinY + marbleHeight / 2)     {         marble1.y = MinY + marbleHeight / 2;     }     else if ((int)marble1.y > (MaxY - marbleHeight / 2))     {         marble1.y = MaxY - marbleHeight / 2;     }     //distance between destination and current point, after updating marble position     x = destX - marble1.x;     y = destY - marble1.y;     double newDistanceSqrd = x * x + y * y;     //length from start point to current marble position     x = startPosX - (marble1.x);     y = startPosY - (marble1.y);     double lenTraveledSqrd = x * x + y * y;     //check for end conditions     if ((int)lenTraveledSqrd >= (int)totLenToTravelSqrd)     {         System.Console.WriteLine("Stopping because destination reached");         timer1.Enabled = false;     }     else if (Math.Abs((int)distanceSqrd - (int)newDistanceSqrd) < 4)     {         System.Console.WriteLine("Stopping because no change in Old and New position");         timer1.Enabled = false;     } } Ok, so in this function, first we subtract the current marble position from the destination point to give us a vector. The first three lines of the function construct this vector (x, y). The vector (x, y) has the same length as the line from (marble1.x, marble1.y) to (destX, destY) and is in the direction pointing from (marble1.x, marble1.y) to (destX, destY). Note that marble1.x and marble1.y denote the center point of the marble. Then we use Atan2() to get the angle which this vector makes with the positive X axis and use Cosine() and Sine() of that angle to get the unit vector along that same direction. We multiply this unit vector with 6, to get the values which the position of the marble should be incremented by. This variable, speed, can be experimented with and determines how fast the marble moves towards the destination. After this, we check for bounds to make sure that the marble stays within the screen limits and finally we check for the end condition and stop the timer. The end condition has two parts to it. The first case is the normal case, where the user clicks well inside the screen. Here, we stop when the total length travelled by the marble is greater than or equal to the total length to be travelled. Simple enough. The second case is when the user clicks on the very corners of the screen. Like I said before, the values marble1.x and marble1.y denote the center point of the marble. When the user clicks on the corner, the marble moves towards the point, and after some time tries to go outside of the screen, this is when the bounds checking comes into play and corrects the marble position so that the marble stays inside the screen. In this case the marble will never travel a distance of totLenToTravelSqrd, because of the correction is its position. So here we detect the end condition when there is not much change in marbles position. I use the value 4 in the second condition above. After experimenting with a few values, 4 seemed to work okay. There is a small thing missing in the code above. In the normal case, case 1, when the update method runs for the last time, marble position over shoots the destination point. This happens because the position is incremented in steps (which are not small enough), so in this case too, we should have corrected the marble position, so that the center point of the marble sits exactly on top of the destination point. I’ll add this later and update the post. This has been a pretty long post already, so I’ll leave you with a video of how this program looks while running. Notice in the video that the marble moves like a bot, without any grace what so ever. And that is because the speed of the marble is fixed at 6. In the next post we will see how to make the marble move a little more elegantly. And also, if Atan2(), Sine() and Cosine() are a little too much to digest, we’ll see how to achieve the same effect without using them, in the next to next post maybe. Ciao!

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  • How can I test if a point lies between two parallel lines?

    - by Harold
    In the game I'm designing there is a blast that shoots out from an origin point towards the direction of the mouse. The width of this blast is always going to be the same. Along the bottom of the screen (what's currently) squares move about which should be effected by the blast that the player controls. Currently I am trying to work out a way to discover if the corners of these squares are within the blast's two bounding lines. I thought the best way to do this would be to rotate the corners of the square around an origin point as if the blast were completely horizontal and see if the Y values of the corners were less than or equal to the width of the blast which would mean that they lie within the effected region, but I can't work out

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  • Wavefront mesh: determine which face a point belongs to?

    - by Mina Samy
    I have a 3D mesh Wavefront .obj file. Is there any algorithm that takes an arbitrary point coordinates as input and determines which face of the mesh that point belongs to ?? The mesh is rendered on the screen, then the user clicks on it, I want to determine which part of the mesh the user has clicked on ? Here's the code using LibGDX: Vector3 intersection=new Vector3(); Ray ray=camera.getPickRay(x, y); //vertices is an array that hold the coordinates of the mesh boolean ok=Intersector.intersectRayTriangles(ray, vertices, intersection); Thanks

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  • How do I find the closest points(thereby forming a polygon) enclosing a particular point?(see image)

    - by nilspin
    I am working with a game engine, and my task is to add code for simulating fracture of rigid meshes. Right now I'm only working on breaking a cube. I am using Voronoi's algorithm to make a (realistic)fractured shard and I am using the half-plane method to generate a voronoi cell. Now the way I do this is for every seed point, I make planes that are perpendicular bisector planes(the straight black lines in the image) with rest of the seed points and I calculate the intersections of all these planes to give me distinct points(all the orange dots). I've gotten this far. Out of all these calculated intersection points, I only need the ones that are closest and enclosing the seed point(the points encircled in red) and I need to discard all the rest. Information that I have : 1) Plane equations of all planes(defined by normalized normal vectors and their distance from origin) 2) Points of intersection(that I've calculated) Can anybody help me find out how I can find the points encircled in red? Thanks.

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  • How do I optimize searching for the nearest point?

    - by Rootosaurus
    For a little project of mine I'm trying to implement a space colonization algorithm in order to grow trees. The current implementation of this algorithm works fine. But I have to optimize the whole thing in order to make it generate faster. I work with 1 to 300K of random attraction points to generate one tree, and it takes a lot of time to compute and compare distances between attraction points and tree node in order to keep only the closest treenode for an attraction point. So I was wondering if some solutions exist (I know they must exist) in order to avoid the time loss looping on each tree node for each attraction point to find the closest... and so on until the tree is finished.

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  • How to get distance from point to line with distinction between side of line?

    - by tesselode
    I'm making a 2d racing game. I'm taking the nice standard approach of having a set of points defining the center of the track and detecting whether the car is off the track by detecting its distance from the nearest point. The nicest way I've found of doing this is using the formula: d = |Am + Bn + C| / sqrt(A^2 + B^2) Unfortunately, to have proper collision resolution, I need to know which side of the line the car is hitting, but I can't do that with this formula because it only returns positive numbers. So my question is: is there a formula that will give me positive or negative numbers based on which side of the line the point is on? Can I just get rid of the absolute value in the formula or do I need to do something else?

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  • BonitaSoft dépasse le million et demi de téléchargements, le point après la tournée du leader mondial français du BPM open-source

    BonitaSoft : le point sur la tournée mondiale du leader du BPM open-source Sa solution Gestion des Processus Métier dépasse le million et demi de téléchargements BonitaSoft propose une solution de Gestion des Processus Métier open-source qui se veut à la fois puissante, facile à intégrer et « conviviale pour tous types d'organisation ou secteur d'activité ». Nous ne jugerons pas de cette simplicité auto-proclamée. En revanche, la tournée mondiale « Process Efficiency 2012 » organisée par l'éditeur était l'occasion de faire le point sur les chiffres autour d'une solution qui prend de plus en plus d'importance dans le paysage des applications d'entreprise. Principal en...

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  • "Light Field" : prendre une photo puis faire le point, la technologie est-elle la prochaine révolution du traitement informatique de l'image ?

    Lytro : prendre une photo puis faire le point La technologie "Light Field" est-elle la prochaine révolution du traitement informatique de l'image ? Depuis quelques années, différents centres de recherche étudient une méthode de prise de vue nommée "light field". Le but est de remplacer la capture d'une image par la capture du flux de lumière de la scène. Il est alors possible de générer une image en modifiant le point de netteté. Après, une exploitation industrielle par la société RayTrix, une solution pour les smartphone par la société Pelican Imagine, c'est au tour de

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  • Point domain to new host - changed nameservers, now what?

    - by Larry
    This is driving me nuts, because I know I'm missing something simple. I've read numerous articles/posts about how to point (not transfer) your domain to a new web host. They all say to change the name server settings at your old host, so here is what I did: On old host (1and1.com) changed the name server settings to those of my new host (inmotionhosting.com) like below: Domain name : mydomain.com Name server 1: ns.inmotionhosting.com Name server 2: ns2.inmotionhosting.com ... and confirmed this is active (did it a couple days ago) This is where every post/article I've found stops. They imply this is all that needs to be done. But how does the new host know to point the domain to my account, and the directory in my account I want it work from?? There's go to be something else to be done - just pointing to the generic name servers of the new host can't be all there is to it. Thanks in advance...I'm bewildered...

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  • Help: Android paint/canvas issue; drawing smooth curves

    - by Wrapper
    How do I get smooth curves instead of dots or circles, when I draw with my finger on the touch screen, in Android? I am using the following code- public class DrawView extends View implements OnTouchListener { private static final String TAG = "DrawView"; List<Point> points = new ArrayList<Point>(); Paint paint = new Paint(); public DrawView(Context context) { super(context); setFocusable(true); setFocusableInTouchMode(true); this.setOnTouchListener(this); paint.setColor(Color.WHITE); paint.setAntiAlias(true); } @Override public void onDraw(Canvas canvas) { for (Point point : points) { canvas.drawCircle(point.x, point.y, 5, paint); // Log.d(TAG, "Painting: "+point); } } public boolean onTouch(View view, MotionEvent event) { // if(event.getAction() != MotionEvent.ACTION_DOWN) // return super.onTouchEvent(event); Point point = new Point(); point.x = event.getX(); point.y = event.getY(); points.add(point); invalidate(); Log.d(TAG, "point: " + point); return true; } } class Point { float x, y; @Override public String toString() { return x + ", " + y; } }

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  • Can I make my Linksys WAG200G as an access point?

    - by Adnan Badar
    I have two routers one is dsl router (connected through my fone line) second is Linksys WAG200G, i want to use this router as an access point to increase the signal strength in my neighborhood can anyone please guide me step by step as i am not that good in networking i need to know both ways one by connecting a cable from the first router to the second and then make access point to the second one. second by connecting wireless from the first router to the second and then make access point to the second one. Thanks. Adnan

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  • Connect wired-only devices to a remote wireless access point?

    - by billpg
    Hi everyone. In building A, I have a Netgear wireless access point using WPA2. Works great, no problems. In building B, I have some devices that only have wired Ethernet ports. They can't see my access point. What I need is a gizmo that connects over-the-air to my access point in building A, talks WPA2, and converts the packets to and from a wired Ethernet port. Netgear-access-point in building A      (WPA2 WiFi) Wireless bridge device          <-- Looking for this.      (Cat5 ethernet) My devices in building B. I've looked for devices on Amazon, but the descriptions are infuriatingly unclear. It says it supports WPA2, but does it support it as a client? Grrr... Any recommendations please?

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  • Is it possible to mount a TrueCrypt volume to a NTFS mount point?

    - by Anthony
    The question is simple really. Under Linux etc.. you can mount TrueCrypt volumes, files or partitions, to any mount point of your choosing whereas in Windows the interface only shows drive letters. I'm wondering if I can mount the volume, a partition in this case, un-encrypted to a NTFS mount point, or folder, instead of using drive letters. The reason I ask is I am running out of letters :(. I'm using Server 2008 with the latest TrueCrypt install. Note: I know how to mount a volume directly to an NTFS folder mount point but doing so, and navigating to the mount point, prompts a notice saying the volume is not formatted - to be expected as the volume is not un-encrypted at this stage.

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  • Problem with truncation of floating point values in DBSlayer.

    - by chrisdew
    When I run a query through DBslayer http://code.nytimes.com/projects/dbslayer the floating point results are truncated to a total of six digits (plus decimal point and negative sign when needed). { ... "lat":52.2228,"lng":-2.19906, ... } When I run the same query in MySQL, the results are as expected. | 52.22280884 | -2.19906425 | Firstly, am I correct in identifying DBSlayer as the cause of this effect? (Or the JSON library it uses, etc.) Secondly, is this floating point precision configurable within DBSlayer? Thanks, Chris. P.S. Ubuntu 9.10, x86_64 Path: . URL: http://dbslayer.googlecode.com/svn/trunk Repository Root: http://dbslayer.googlecode.com/svn Repository UUID: 5df2be84-4748-0410-afd4-f777a056bd0c Revision: 65 Node Kind: directory Schedule: normal Last Changed Author: dgottfrid Last Changed Rev: 65 Last Changed Date: 2008-03-28 22:52:46 +0000 (Fri, 28 Mar 2008)

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  • Not all of your nameservers are in different subnets. Single point of failure

    - by user2118559
    Using VPS hosting and dynadot (domain registrar) DNS. Checked domain name with http://www.intodns.com and get some warnings Different subnets WARNING: Not all of your nameservers are in different subnets and Different autonomous systems WARNING: Single point of failure As understand to avoid the warning must have second Ip4 address and both the addresses must point to different servers? If both Ip addresses point to the same server, it does not help? I mean each server has own Ip address. If one server down, then visitors can access website (files) on another server? Is this the reason why need more than one Ip? Tried to point website to 2 ip addresses and after some time get warning from uptimerobot Connection Timeout

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  • Can someone confirm how Microsoft Excel 2007 internally represents numbers?

    - by Jon
    I know the IEEE 754 floating point standard by heart as I had to learn it for an exam. I know exactly how floating point numbers are used and the problems that they can have. I can manually do any operation on the binary representation of floating point numbers. However, I have not found a single source which unambiguously states that excel uses 64 bit floating point numbers to internally represent every single cell "type" in excel except for text. I have no idea whether some of the types use signed or unsigned integers and some use 64 bit floating point. I have found literally trillions of articles which 1) describe floating point numbers and then 2) talk about being careful with excel because of floating point numbers. I have not found a single statement saying "all types are 64 bit floating point numbers except text". I have not found a single statement which says "changing the type of a cell only changes its visual representation and not its internal representation, unless you change the type from text to some other type which is not text or you change some other type which is not text to text". This is literally all I want to know, and it's so simple and axiomatic that I am amazed that I can find trillions of articles and pages which talk around these statements but do not state them directly.

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